Integrand size = 23, antiderivative size = 121 \[ \int \frac {1}{\sqrt [4]{a+b x^2} \left (2 a+b x^2\right )} \, dx=\frac {\arctan \left (\frac {b^{3/2} x \sqrt [4]{a+b x^2}}{a^{3/4} \left (b+\frac {b \sqrt {a+b x^2}}{\sqrt {a}}\right )}\right )}{2 a^{3/4} \sqrt {b}}-\frac {\text {arctanh}\left (\frac {a^{3/4} \left (1-\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{\sqrt {b} x \sqrt [4]{a+b x^2}}\right )}{2 a^{3/4} \sqrt {b}} \] Output:
1/2*arctan(b^(3/2)*x*(b*x^2+a)^(1/4)/a^(3/4)/(b+b*(b*x^2+a)^(1/2)/a^(1/2)) )/a^(3/4)/b^(1/2)-1/2*arctanh(a^(3/4)*(1-(b*x^2+a)^(1/2)/a^(1/2))/b^(1/2)/ x/(b*x^2+a)^(1/4))/a^(3/4)/b^(1/2)
Time = 0.21 (sec) , antiderivative size = 119, normalized size of antiderivative = 0.98 \[ \int \frac {1}{\sqrt [4]{a+b x^2} \left (2 a+b x^2\right )} \, dx=\frac {\arctan \left (\frac {b x^2-2 \sqrt {a} \sqrt {a+b x^2}}{2 \sqrt [4]{a} \sqrt {b} x \sqrt [4]{a+b x^2}}\right )+\text {arctanh}\left (\frac {2 \sqrt [4]{a} \sqrt {b} x \sqrt [4]{a+b x^2}}{b x^2+2 \sqrt {a} \sqrt {a+b x^2}}\right )}{4 a^{3/4} \sqrt {b}} \] Input:
Integrate[1/((a + b*x^2)^(1/4)*(2*a + b*x^2)),x]
Output:
(ArcTan[(b*x^2 - 2*Sqrt[a]*Sqrt[a + b*x^2])/(2*a^(1/4)*Sqrt[b]*x*(a + b*x^ 2)^(1/4))] + ArcTanh[(2*a^(1/4)*Sqrt[b]*x*(a + b*x^2)^(1/4))/(b*x^2 + 2*Sq rt[a]*Sqrt[a + b*x^2])])/(4*a^(3/4)*Sqrt[b])
Time = 0.19 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.99, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.043, Rules used = {308}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{\sqrt [4]{a+b x^2} \left (2 a+b x^2\right )} \, dx\) |
\(\Big \downarrow \) 308 |
\(\displaystyle -\frac {\arctan \left (\frac {a^{3/4} \left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}+1\right )}{\sqrt {b} x \sqrt [4]{a+b x^2}}\right )}{2 a^{3/4} \sqrt {b}}-\frac {\text {arctanh}\left (\frac {a^{3/4} \left (1-\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{\sqrt {b} x \sqrt [4]{a+b x^2}}\right )}{2 a^{3/4} \sqrt {b}}\) |
Input:
Int[1/((a + b*x^2)^(1/4)*(2*a + b*x^2)),x]
Output:
-1/2*ArcTan[(a^(3/4)*(1 + Sqrt[a + b*x^2]/Sqrt[a]))/(Sqrt[b]*x*(a + b*x^2) ^(1/4))]/(a^(3/4)*Sqrt[b]) - ArcTanh[(a^(3/4)*(1 - Sqrt[a + b*x^2]/Sqrt[a] ))/(Sqrt[b]*x*(a + b*x^2)^(1/4))]/(2*a^(3/4)*Sqrt[b])
Int[1/(((a_) + (b_.)*(x_)^2)^(1/4)*((c_) + (d_.)*(x_)^2)), x_Symbol] :> Wit h[{q = Rt[b^2/a, 4]}, Simp[(-b/(2*a*d*q))*ArcTan[(b + q^2*Sqrt[a + b*x^2])/ (q^3*x*(a + b*x^2)^(1/4))], x] - Simp[(b/(2*a*d*q))*ArcTanh[(b - q^2*Sqrt[a + b*x^2])/(q^3*x*(a + b*x^2)^(1/4))], x]] /; FreeQ[{a, b, c, d}, x] && EqQ [b*c - 2*a*d, 0] && PosQ[b^2/a]
\[\int \frac {1}{\left (b \,x^{2}+a \right )^{\frac {1}{4}} \left (b \,x^{2}+2 a \right )}d x\]
Input:
int(1/(b*x^2+a)^(1/4)/(b*x^2+2*a),x)
Output:
int(1/(b*x^2+a)^(1/4)/(b*x^2+2*a),x)
Result contains complex when optimal does not.
Time = 23.94 (sec) , antiderivative size = 451, normalized size of antiderivative = 3.73 \[ \int \frac {1}{\sqrt [4]{a+b x^2} \left (2 a+b x^2\right )} \, dx =\text {Too large to display} \] Input:
integrate(1/(b*x^2+a)^(1/4)/(b*x^2+2*a),x, algorithm="fricas")
Output:
-1/4*(1/4)^(1/4)*(-1/(a^3*b^2))^(1/4)*log((2*(1/4)^(3/4)*sqrt(b*x^2 + a)*a ^2*b^2*x*(-1/(a^3*b^2))^(3/4) + (b*x^2 + a)^(1/4)*a^2*b*sqrt(-1/(a^3*b^2)) - (1/4)^(1/4)*a*b*x*(-1/(a^3*b^2))^(1/4) + (b*x^2 + a)^(3/4))/(b*x^2 + 2* a)) + 1/4*(1/4)^(1/4)*(-1/(a^3*b^2))^(1/4)*log(-(2*(1/4)^(3/4)*sqrt(b*x^2 + a)*a^2*b^2*x*(-1/(a^3*b^2))^(3/4) - (b*x^2 + a)^(1/4)*a^2*b*sqrt(-1/(a^3 *b^2)) - (1/4)^(1/4)*a*b*x*(-1/(a^3*b^2))^(1/4) - (b*x^2 + a)^(3/4))/(b*x^ 2 + 2*a)) + 1/4*I*(1/4)^(1/4)*(-1/(a^3*b^2))^(1/4)*log((2*I*(1/4)^(3/4)*sq rt(b*x^2 + a)*a^2*b^2*x*(-1/(a^3*b^2))^(3/4) - (b*x^2 + a)^(1/4)*a^2*b*sqr t(-1/(a^3*b^2)) + I*(1/4)^(1/4)*a*b*x*(-1/(a^3*b^2))^(1/4) + (b*x^2 + a)^( 3/4))/(b*x^2 + 2*a)) - 1/4*I*(1/4)^(1/4)*(-1/(a^3*b^2))^(1/4)*log((-2*I*(1 /4)^(3/4)*sqrt(b*x^2 + a)*a^2*b^2*x*(-1/(a^3*b^2))^(3/4) - (b*x^2 + a)^(1/ 4)*a^2*b*sqrt(-1/(a^3*b^2)) - I*(1/4)^(1/4)*a*b*x*(-1/(a^3*b^2))^(1/4) + ( b*x^2 + a)^(3/4))/(b*x^2 + 2*a))
\[ \int \frac {1}{\sqrt [4]{a+b x^2} \left (2 a+b x^2\right )} \, dx=\int \frac {1}{\sqrt [4]{a + b x^{2}} \cdot \left (2 a + b x^{2}\right )}\, dx \] Input:
integrate(1/(b*x**2+a)**(1/4)/(b*x**2+2*a),x)
Output:
Integral(1/((a + b*x**2)**(1/4)*(2*a + b*x**2)), x)
\[ \int \frac {1}{\sqrt [4]{a+b x^2} \left (2 a+b x^2\right )} \, dx=\int { \frac {1}{{\left (b x^{2} + 2 \, a\right )} {\left (b x^{2} + a\right )}^{\frac {1}{4}}} \,d x } \] Input:
integrate(1/(b*x^2+a)^(1/4)/(b*x^2+2*a),x, algorithm="maxima")
Output:
integrate(1/((b*x^2 + 2*a)*(b*x^2 + a)^(1/4)), x)
\[ \int \frac {1}{\sqrt [4]{a+b x^2} \left (2 a+b x^2\right )} \, dx=\int { \frac {1}{{\left (b x^{2} + 2 \, a\right )} {\left (b x^{2} + a\right )}^{\frac {1}{4}}} \,d x } \] Input:
integrate(1/(b*x^2+a)^(1/4)/(b*x^2+2*a),x, algorithm="giac")
Output:
integrate(1/((b*x^2 + 2*a)*(b*x^2 + a)^(1/4)), x)
Timed out. \[ \int \frac {1}{\sqrt [4]{a+b x^2} \left (2 a+b x^2\right )} \, dx=\int \frac {1}{{\left (b\,x^2+a\right )}^{1/4}\,\left (b\,x^2+2\,a\right )} \,d x \] Input:
int(1/((a + b*x^2)^(1/4)*(2*a + b*x^2)),x)
Output:
int(1/((a + b*x^2)^(1/4)*(2*a + b*x^2)), x)
\[ \int \frac {1}{\sqrt [4]{a+b x^2} \left (2 a+b x^2\right )} \, dx=\int \frac {1}{2 \left (b \,x^{2}+a \right )^{\frac {1}{4}} a +\left (b \,x^{2}+a \right )^{\frac {1}{4}} b \,x^{2}}d x \] Input:
int(1/(b*x^2+a)^(1/4)/(b*x^2+2*a),x)
Output:
int(1/(2*(a + b*x**2)**(1/4)*a + (a + b*x**2)**(1/4)*b*x**2),x)