Integrand size = 22, antiderivative size = 149 \[ \int \frac {x^4 \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx=-\frac {4 a (9 b c-10 a d) x}{15 b^3 \sqrt [4]{a+b x^2}}+\frac {2 (9 b c-10 a d) x^3}{45 b^2 \sqrt [4]{a+b x^2}}+\frac {2 d x^5}{9 b \sqrt [4]{a+b x^2}}+\frac {8 a^{3/2} (9 b c-10 a d) \sqrt [4]{1+\frac {b x^2}{a}} E\left (\left .\frac {1}{2} \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )\right |2\right )}{15 b^{7/2} \sqrt [4]{a+b x^2}} \] Output:
-4/15*a*(-10*a*d+9*b*c)*x/b^3/(b*x^2+a)^(1/4)+2/45*(-10*a*d+9*b*c)*x^3/b^2 /(b*x^2+a)^(1/4)+2/9*d*x^5/b/(b*x^2+a)^(1/4)+8/15*a^(3/2)*(-10*a*d+9*b*c)* (1+b*x^2/a)^(1/4)*EllipticE(sin(1/2*arctan(b^(1/2)*x/a^(1/2))),2^(1/2))/b^ (7/2)/(b*x^2+a)^(1/4)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.06 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.68 \[ \int \frac {x^4 \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx=\frac {2 x \left (-60 a^2 d+2 a b \left (27 c-5 d x^2\right )+b^2 x^2 \left (9 c+5 d x^2\right )+6 a (-9 b c+10 a d) \sqrt [4]{1+\frac {b x^2}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {3}{2},-\frac {b x^2}{a}\right )\right )}{45 b^3 \sqrt [4]{a+b x^2}} \] Input:
Integrate[(x^4*(c + d*x^2))/(a + b*x^2)^(5/4),x]
Output:
(2*x*(-60*a^2*d + 2*a*b*(27*c - 5*d*x^2) + b^2*x^2*(9*c + 5*d*x^2) + 6*a*( -9*b*c + 10*a*d)*(1 + (b*x^2)/a)^(1/4)*Hypergeometric2F1[1/4, 1/2, 3/2, -( (b*x^2)/a)]))/(45*b^3*(a + b*x^2)^(1/4))
Time = 0.23 (sec) , antiderivative size = 143, normalized size of antiderivative = 0.96, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {363, 250, 250, 213, 212}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^4 \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx\) |
\(\Big \downarrow \) 363 |
\(\displaystyle \frac {(9 b c-10 a d) \int \frac {x^4}{\left (b x^2+a\right )^{5/4}}dx}{9 b}+\frac {2 d x^5}{9 b \sqrt [4]{a+b x^2}}\) |
\(\Big \downarrow \) 250 |
\(\displaystyle \frac {(9 b c-10 a d) \left (\frac {2 x^3}{5 b \sqrt [4]{a+b x^2}}-\frac {6 a \int \frac {x^2}{\left (b x^2+a\right )^{5/4}}dx}{5 b}\right )}{9 b}+\frac {2 d x^5}{9 b \sqrt [4]{a+b x^2}}\) |
\(\Big \downarrow \) 250 |
\(\displaystyle \frac {(9 b c-10 a d) \left (\frac {2 x^3}{5 b \sqrt [4]{a+b x^2}}-\frac {6 a \left (\frac {2 x}{b \sqrt [4]{a+b x^2}}-\frac {2 a \int \frac {1}{\left (b x^2+a\right )^{5/4}}dx}{b}\right )}{5 b}\right )}{9 b}+\frac {2 d x^5}{9 b \sqrt [4]{a+b x^2}}\) |
\(\Big \downarrow \) 213 |
\(\displaystyle \frac {(9 b c-10 a d) \left (\frac {2 x^3}{5 b \sqrt [4]{a+b x^2}}-\frac {6 a \left (\frac {2 x}{b \sqrt [4]{a+b x^2}}-\frac {2 \sqrt [4]{\frac {b x^2}{a}+1} \int \frac {1}{\left (\frac {b x^2}{a}+1\right )^{5/4}}dx}{b \sqrt [4]{a+b x^2}}\right )}{5 b}\right )}{9 b}+\frac {2 d x^5}{9 b \sqrt [4]{a+b x^2}}\) |
\(\Big \downarrow \) 212 |
\(\displaystyle \frac {(9 b c-10 a d) \left (\frac {2 x^3}{5 b \sqrt [4]{a+b x^2}}-\frac {6 a \left (\frac {2 x}{b \sqrt [4]{a+b x^2}}-\frac {4 \sqrt {a} \sqrt [4]{\frac {b x^2}{a}+1} E\left (\left .\frac {1}{2} \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )\right |2\right )}{b^{3/2} \sqrt [4]{a+b x^2}}\right )}{5 b}\right )}{9 b}+\frac {2 d x^5}{9 b \sqrt [4]{a+b x^2}}\) |
Input:
Int[(x^4*(c + d*x^2))/(a + b*x^2)^(5/4),x]
Output:
(2*d*x^5)/(9*b*(a + b*x^2)^(1/4)) + ((9*b*c - 10*a*d)*((2*x^3)/(5*b*(a + b *x^2)^(1/4)) - (6*a*((2*x)/(b*(a + b*x^2)^(1/4)) - (4*Sqrt[a]*(1 + (b*x^2) /a)^(1/4)*EllipticE[ArcTan[(Sqrt[b]*x)/Sqrt[a]]/2, 2])/(b^(3/2)*(a + b*x^2 )^(1/4))))/(5*b)))/(9*b)
Int[((a_) + (b_.)*(x_)^2)^(-5/4), x_Symbol] :> Simp[(2/(a^(5/4)*Rt[b/a, 2]) )*EllipticE[(1/2)*ArcTan[Rt[b/a, 2]*x], 2], x] /; FreeQ[{a, b}, x] && GtQ[a , 0] && PosQ[b/a]
Int[((a_) + (b_.)*(x_)^2)^(-5/4), x_Symbol] :> Simp[(1 + b*(x^2/a))^(1/4)/( a*(a + b*x^2)^(1/4)) Int[1/(1 + b*(x^2/a))^(5/4), x], x] /; FreeQ[{a, b}, x] && PosQ[a] && PosQ[b/a]
Int[((c_.)*(x_))^(m_)/((a_) + (b_.)*(x_)^2)^(5/4), x_Symbol] :> Simp[2*c*(( c*x)^(m - 1)/(b*(2*m - 3)*(a + b*x^2)^(1/4))), x] - Simp[2*a*c^2*((m - 1)/( b*(2*m - 3))) Int[(c*x)^(m - 2)/(a + b*x^2)^(5/4), x], x] /; FreeQ[{a, b, c}, x] && PosQ[b/a] && IntegerQ[2*m] && GtQ[m, 3/2]
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2), x _Symbol] :> Simp[d*(e*x)^(m + 1)*((a + b*x^2)^(p + 1)/(b*e*(m + 2*p + 3))), x] - Simp[(a*d*(m + 1) - b*c*(m + 2*p + 3))/(b*(m + 2*p + 3)) Int[(e*x)^ m*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b*c - a*d , 0] && NeQ[m + 2*p + 3, 0]
\[\int \frac {x^{4} \left (x^{2} d +c \right )}{\left (b \,x^{2}+a \right )^{\frac {5}{4}}}d x\]
Input:
int(x^4*(d*x^2+c)/(b*x^2+a)^(5/4),x)
Output:
int(x^4*(d*x^2+c)/(b*x^2+a)^(5/4),x)
\[ \int \frac {x^4 \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx=\int { \frac {{\left (d x^{2} + c\right )} x^{4}}{{\left (b x^{2} + a\right )}^{\frac {5}{4}}} \,d x } \] Input:
integrate(x^4*(d*x^2+c)/(b*x^2+a)^(5/4),x, algorithm="fricas")
Output:
integral((d*x^6 + c*x^4)*(b*x^2 + a)^(3/4)/(b^2*x^4 + 2*a*b*x^2 + a^2), x)
Result contains complex when optimal does not.
Time = 2.11 (sec) , antiderivative size = 60, normalized size of antiderivative = 0.40 \[ \int \frac {x^4 \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx=\frac {c x^{5} {{}_{2}F_{1}\left (\begin {matrix} \frac {5}{4}, \frac {5}{2} \\ \frac {7}{2} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{5 a^{\frac {5}{4}}} + \frac {d x^{7} {{}_{2}F_{1}\left (\begin {matrix} \frac {5}{4}, \frac {7}{2} \\ \frac {9}{2} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{7 a^{\frac {5}{4}}} \] Input:
integrate(x**4*(d*x**2+c)/(b*x**2+a)**(5/4),x)
Output:
c*x**5*hyper((5/4, 5/2), (7/2,), b*x**2*exp_polar(I*pi)/a)/(5*a**(5/4)) + d*x**7*hyper((5/4, 7/2), (9/2,), b*x**2*exp_polar(I*pi)/a)/(7*a**(5/4))
\[ \int \frac {x^4 \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx=\int { \frac {{\left (d x^{2} + c\right )} x^{4}}{{\left (b x^{2} + a\right )}^{\frac {5}{4}}} \,d x } \] Input:
integrate(x^4*(d*x^2+c)/(b*x^2+a)^(5/4),x, algorithm="maxima")
Output:
integrate((d*x^2 + c)*x^4/(b*x^2 + a)^(5/4), x)
\[ \int \frac {x^4 \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx=\int { \frac {{\left (d x^{2} + c\right )} x^{4}}{{\left (b x^{2} + a\right )}^{\frac {5}{4}}} \,d x } \] Input:
integrate(x^4*(d*x^2+c)/(b*x^2+a)^(5/4),x, algorithm="giac")
Output:
integrate((d*x^2 + c)*x^4/(b*x^2 + a)^(5/4), x)
Timed out. \[ \int \frac {x^4 \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx=\int \frac {x^4\,\left (d\,x^2+c\right )}{{\left (b\,x^2+a\right )}^{5/4}} \,d x \] Input:
int((x^4*(c + d*x^2))/(a + b*x^2)^(5/4),x)
Output:
int((x^4*(c + d*x^2))/(a + b*x^2)^(5/4), x)
\[ \int \frac {x^4 \left (c+d x^2\right )}{\left (a+b x^2\right )^{5/4}} \, dx=\left (\int \frac {x^{6}}{\left (b \,x^{2}+a \right )^{\frac {1}{4}} a +\left (b \,x^{2}+a \right )^{\frac {1}{4}} b \,x^{2}}d x \right ) d +\left (\int \frac {x^{4}}{\left (b \,x^{2}+a \right )^{\frac {1}{4}} a +\left (b \,x^{2}+a \right )^{\frac {1}{4}} b \,x^{2}}d x \right ) c \] Input:
int(x^4*(d*x^2+c)/(b*x^2+a)^(5/4),x)
Output:
int(x**6/((a + b*x**2)**(1/4)*a + (a + b*x**2)**(1/4)*b*x**2),x)*d + int(x **4/((a + b*x**2)**(1/4)*a + (a + b*x**2)**(1/4)*b*x**2),x)*c