Integrand size = 34, antiderivative size = 590 \[ \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx=\frac {\left (\frac {a}{c}-\frac {b}{d}\right ) x \sqrt {a+b x^2} \sqrt {e+f x^2}}{3 \left (c+d x^2\right )^{3/2}}+\frac {\sqrt {e} (b c (2 d e-3 c f)+a d (2 d e-c f)) \sqrt {a+b x^2} \sqrt {\frac {c \left (e+f x^2\right )}{e \left (c+d x^2\right )}} E\left (\arcsin \left (\frac {\sqrt {d e-c f} x}{\sqrt {e} \sqrt {c+d x^2}}\right )|-\frac {(b c-a d) e}{a (d e-c f)}\right )}{3 c^2 d^2 \sqrt {d e-c f} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}} \sqrt {e+f x^2}}-\frac {\sqrt {e} \left (3 b^2 c^2 f-a^2 d^2 f+a b d (d e-3 c f)\right ) \sqrt {a+b x^2} \sqrt {\frac {c \left (e+f x^2\right )}{e \left (c+d x^2\right )}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {d e-c f} x}{\sqrt {e} \sqrt {c+d x^2}}\right ),-\frac {(b c-a d) e}{a (d e-c f)}\right )}{3 a c d^3 \sqrt {d e-c f} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}} \sqrt {e+f x^2}}+\frac {b^2 c \sqrt {e} f \sqrt {a+b x^2} \sqrt {\frac {c \left (e+f x^2\right )}{e \left (c+d x^2\right )}} \operatorname {EllipticPi}\left (\frac {d e}{d e-c f},\arcsin \left (\frac {\sqrt {d e-c f} x}{\sqrt {e} \sqrt {c+d x^2}}\right ),-\frac {(b c-a d) e}{a (d e-c f)}\right )}{a d^3 \sqrt {d e-c f} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}} \sqrt {e+f x^2}} \] Output:
1/3*(a/c-b/d)*x*(b*x^2+a)^(1/2)*(f*x^2+e)^(1/2)/(d*x^2+c)^(3/2)+1/3*e^(1/2 )*(b*c*(-3*c*f+2*d*e)+a*d*(-c*f+2*d*e))*(b*x^2+a)^(1/2)*(c*(f*x^2+e)/e/(d* x^2+c))^(1/2)*EllipticE((-c*f+d*e)^(1/2)*x/e^(1/2)/(d*x^2+c)^(1/2),(-(-a*d +b*c)*e/a/(-c*f+d*e))^(1/2))/c^2/d^2/(-c*f+d*e)^(1/2)/(c*(b*x^2+a)/a/(d*x^ 2+c))^(1/2)/(f*x^2+e)^(1/2)-1/3*e^(1/2)*(3*b^2*c^2*f-a^2*d^2*f+a*b*d*(-3*c *f+d*e))*(b*x^2+a)^(1/2)*(c*(f*x^2+e)/e/(d*x^2+c))^(1/2)*EllipticF((-c*f+d *e)^(1/2)*x/e^(1/2)/(d*x^2+c)^(1/2),(-(-a*d+b*c)*e/a/(-c*f+d*e))^(1/2))/a/ c/d^3/(-c*f+d*e)^(1/2)/(c*(b*x^2+a)/a/(d*x^2+c))^(1/2)/(f*x^2+e)^(1/2)+b^2 *c*e^(1/2)*f*(b*x^2+a)^(1/2)*(c*(f*x^2+e)/e/(d*x^2+c))^(1/2)*EllipticPi((- c*f+d*e)^(1/2)*x/e^(1/2)/(d*x^2+c)^(1/2),d*e/(-c*f+d*e),(-(-a*d+b*c)*e/a/( -c*f+d*e))^(1/2))/a/d^3/(-c*f+d*e)^(1/2)/(c*(b*x^2+a)/a/(d*x^2+c))^(1/2)/( f*x^2+e)^(1/2)
\[ \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx \] Input:
Integrate[((a + b*x^2)^(3/2)*Sqrt[e + f*x^2])/(c + d*x^2)^(5/2),x]
Output:
Integrate[((a + b*x^2)^(3/2)*Sqrt[e + f*x^2])/(c + d*x^2)^(5/2), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx\) |
\(\Big \downarrow \) 434 |
\(\displaystyle \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}}dx\) |
Input:
Int[((a + b*x^2)^(3/2)*Sqrt[e + f*x^2])/(c + d*x^2)^(5/2),x]
Output:
$Aborted
Int[((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2)^(q_.)*((e_) + (f_.)*( x_)^2)^(r_.), x_Symbol] :> Unintegrable[(a + b*x^2)^p*(c + d*x^2)^q*(e + f* x^2)^r, x] /; FreeQ[{a, b, c, d, e, f, p, q, r}, x]
\[\int \frac {\left (b \,x^{2}+a \right )^{\frac {3}{2}} \sqrt {f \,x^{2}+e}}{\left (x^{2} d +c \right )^{\frac {5}{2}}}d x\]
Input:
int((b*x^2+a)^(3/2)*(f*x^2+e)^(1/2)/(d*x^2+c)^(5/2),x)
Output:
int((b*x^2+a)^(3/2)*(f*x^2+e)^(1/2)/(d*x^2+c)^(5/2),x)
\[ \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{\frac {3}{2}} \sqrt {f x^{2} + e}}{{\left (d x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \] Input:
integrate((b*x^2+a)^(3/2)*(f*x^2+e)^(1/2)/(d*x^2+c)^(5/2),x, algorithm="fr icas")
Output:
integral((b*x^2 + a)^(3/2)*sqrt(d*x^2 + c)*sqrt(f*x^2 + e)/(d^3*x^6 + 3*c* d^2*x^4 + 3*c^2*d*x^2 + c^3), x)
\[ \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int \frac {\left (a + b x^{2}\right )^{\frac {3}{2}} \sqrt {e + f x^{2}}}{\left (c + d x^{2}\right )^{\frac {5}{2}}}\, dx \] Input:
integrate((b*x**2+a)**(3/2)*(f*x**2+e)**(1/2)/(d*x**2+c)**(5/2),x)
Output:
Integral((a + b*x**2)**(3/2)*sqrt(e + f*x**2)/(c + d*x**2)**(5/2), x)
\[ \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{\frac {3}{2}} \sqrt {f x^{2} + e}}{{\left (d x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \] Input:
integrate((b*x^2+a)^(3/2)*(f*x^2+e)^(1/2)/(d*x^2+c)^(5/2),x, algorithm="ma xima")
Output:
integrate((b*x^2 + a)^(3/2)*sqrt(f*x^2 + e)/(d*x^2 + c)^(5/2), x)
\[ \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{\frac {3}{2}} \sqrt {f x^{2} + e}}{{\left (d x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \] Input:
integrate((b*x^2+a)^(3/2)*(f*x^2+e)^(1/2)/(d*x^2+c)^(5/2),x, algorithm="gi ac")
Output:
integrate((b*x^2 + a)^(3/2)*sqrt(f*x^2 + e)/(d*x^2 + c)^(5/2), x)
Timed out. \[ \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int \frac {{\left (b\,x^2+a\right )}^{3/2}\,\sqrt {f\,x^2+e}}{{\left (d\,x^2+c\right )}^{5/2}} \,d x \] Input:
int(((a + b*x^2)^(3/2)*(e + f*x^2)^(1/2))/(c + d*x^2)^(5/2),x)
Output:
int(((a + b*x^2)^(3/2)*(e + f*x^2)^(1/2))/(c + d*x^2)^(5/2), x)
\[ \int \frac {\left (a+b x^2\right )^{3/2} \sqrt {e+f x^2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int \frac {\left (b \,x^{2}+a \right )^{\frac {3}{2}} \sqrt {f \,x^{2}+e}}{\left (d \,x^{2}+c \right )^{\frac {5}{2}}}d x \] Input:
int((b*x^2+a)^(3/2)*(f*x^2+e)^(1/2)/(d*x^2+c)^(5/2),x)
Output:
int((b*x^2+a)^(3/2)*(f*x^2+e)^(1/2)/(d*x^2+c)^(5/2),x)