Integrand size = 34, antiderivative size = 635 \[ \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx=\frac {(d e-c f) x \sqrt {a+b x^2} \sqrt {e+f x^2}}{3 c d \left (c+d x^2\right )^{3/2}}-\frac {\sqrt {e} \sqrt {d e-c f} (2 a d (d e+c f)-b c (d e+3 c f)) \sqrt {a+b x^2} \sqrt {\frac {c \left (e+f x^2\right )}{e \left (c+d x^2\right )}} E\left (\arcsin \left (\frac {\sqrt {d e-c f} x}{\sqrt {e} \sqrt {c+d x^2}}\right )|-\frac {(b c-a d) e}{a (d e-c f)}\right )}{3 c^2 d^2 (b c-a d) \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}} \sqrt {e+f x^2}}-\frac {\sqrt {e} \left (3 b^2 c^3 f^2+a^2 d^2 f (d e+2 c f)-a b d \left (d^2 e^2-c d e f+6 c^2 f^2\right )\right ) \sqrt {a+b x^2} \sqrt {\frac {c \left (e+f x^2\right )}{e \left (c+d x^2\right )}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {d e-c f} x}{\sqrt {e} \sqrt {c+d x^2}}\right ),-\frac {(b c-a d) e}{a (d e-c f)}\right )}{3 a c d^3 (b c-a d) \sqrt {d e-c f} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}} \sqrt {e+f x^2}}+\frac {b c \sqrt {e} f^2 \sqrt {a+b x^2} \sqrt {\frac {c \left (e+f x^2\right )}{e \left (c+d x^2\right )}} \operatorname {EllipticPi}\left (\frac {d e}{d e-c f},\arcsin \left (\frac {\sqrt {d e-c f} x}{\sqrt {e} \sqrt {c+d x^2}}\right ),-\frac {(b c-a d) e}{a (d e-c f)}\right )}{a d^3 \sqrt {d e-c f} \sqrt {\frac {c \left (a+b x^2\right )}{a \left (c+d x^2\right )}} \sqrt {e+f x^2}} \] Output:
1/3*(-c*f+d*e)*x*(b*x^2+a)^(1/2)*(f*x^2+e)^(1/2)/c/d/(d*x^2+c)^(3/2)-1/3*e ^(1/2)*(-c*f+d*e)^(1/2)*(2*a*d*(c*f+d*e)-b*c*(3*c*f+d*e))*(b*x^2+a)^(1/2)* (c*(f*x^2+e)/e/(d*x^2+c))^(1/2)*EllipticE((-c*f+d*e)^(1/2)*x/e^(1/2)/(d*x^ 2+c)^(1/2),(-(-a*d+b*c)*e/a/(-c*f+d*e))^(1/2))/c^2/d^2/(-a*d+b*c)/(c*(b*x^ 2+a)/a/(d*x^2+c))^(1/2)/(f*x^2+e)^(1/2)-1/3*e^(1/2)*(3*b^2*c^3*f^2+a^2*d^2 *f*(2*c*f+d*e)-a*b*d*(6*c^2*f^2-c*d*e*f+d^2*e^2))*(b*x^2+a)^(1/2)*(c*(f*x^ 2+e)/e/(d*x^2+c))^(1/2)*EllipticF((-c*f+d*e)^(1/2)*x/e^(1/2)/(d*x^2+c)^(1/ 2),(-(-a*d+b*c)*e/a/(-c*f+d*e))^(1/2))/a/c/d^3/(-a*d+b*c)/(-c*f+d*e)^(1/2) /(c*(b*x^2+a)/a/(d*x^2+c))^(1/2)/(f*x^2+e)^(1/2)+b*c*e^(1/2)*f^2*(b*x^2+a) ^(1/2)*(c*(f*x^2+e)/e/(d*x^2+c))^(1/2)*EllipticPi((-c*f+d*e)^(1/2)*x/e^(1/ 2)/(d*x^2+c)^(1/2),d*e/(-c*f+d*e),(-(-a*d+b*c)*e/a/(-c*f+d*e))^(1/2))/a/d^ 3/(-c*f+d*e)^(1/2)/(c*(b*x^2+a)/a/(d*x^2+c))^(1/2)/(f*x^2+e)^(1/2)
\[ \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx \] Input:
Integrate[(Sqrt[a + b*x^2]*(e + f*x^2)^(3/2))/(c + d*x^2)^(5/2),x]
Output:
Integrate[(Sqrt[a + b*x^2]*(e + f*x^2)^(3/2))/(c + d*x^2)^(5/2), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx\) |
\(\Big \downarrow \) 434 |
\(\displaystyle \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}}dx\) |
Input:
Int[(Sqrt[a + b*x^2]*(e + f*x^2)^(3/2))/(c + d*x^2)^(5/2),x]
Output:
$Aborted
Int[((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2)^(q_.)*((e_) + (f_.)*( x_)^2)^(r_.), x_Symbol] :> Unintegrable[(a + b*x^2)^p*(c + d*x^2)^q*(e + f* x^2)^r, x] /; FreeQ[{a, b, c, d, e, f, p, q, r}, x]
\[\int \frac {\sqrt {b \,x^{2}+a}\, \left (f \,x^{2}+e \right )^{\frac {3}{2}}}{\left (x^{2} d +c \right )^{\frac {5}{2}}}d x\]
Input:
int((b*x^2+a)^(1/2)*(f*x^2+e)^(3/2)/(d*x^2+c)^(5/2),x)
Output:
int((b*x^2+a)^(1/2)*(f*x^2+e)^(3/2)/(d*x^2+c)^(5/2),x)
Timed out. \[ \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx=\text {Timed out} \] Input:
integrate((b*x^2+a)^(1/2)*(f*x^2+e)^(3/2)/(d*x^2+c)^(5/2),x, algorithm="fr icas")
Output:
Timed out
\[ \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int \frac {\sqrt {a + b x^{2}} \left (e + f x^{2}\right )^{\frac {3}{2}}}{\left (c + d x^{2}\right )^{\frac {5}{2}}}\, dx \] Input:
integrate((b*x**2+a)**(1/2)*(f*x**2+e)**(3/2)/(d*x**2+c)**(5/2),x)
Output:
Integral(sqrt(a + b*x**2)*(e + f*x**2)**(3/2)/(c + d*x**2)**(5/2), x)
\[ \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int { \frac {\sqrt {b x^{2} + a} {\left (f x^{2} + e\right )}^{\frac {3}{2}}}{{\left (d x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \] Input:
integrate((b*x^2+a)^(1/2)*(f*x^2+e)^(3/2)/(d*x^2+c)^(5/2),x, algorithm="ma xima")
Output:
integrate(sqrt(b*x^2 + a)*(f*x^2 + e)^(3/2)/(d*x^2 + c)^(5/2), x)
\[ \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int { \frac {\sqrt {b x^{2} + a} {\left (f x^{2} + e\right )}^{\frac {3}{2}}}{{\left (d x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \] Input:
integrate((b*x^2+a)^(1/2)*(f*x^2+e)^(3/2)/(d*x^2+c)^(5/2),x, algorithm="gi ac")
Output:
integrate(sqrt(b*x^2 + a)*(f*x^2 + e)^(3/2)/(d*x^2 + c)^(5/2), x)
Timed out. \[ \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int \frac {\sqrt {b\,x^2+a}\,{\left (f\,x^2+e\right )}^{3/2}}{{\left (d\,x^2+c\right )}^{5/2}} \,d x \] Input:
int(((a + b*x^2)^(1/2)*(e + f*x^2)^(3/2))/(c + d*x^2)^(5/2),x)
Output:
int(((a + b*x^2)^(1/2)*(e + f*x^2)^(3/2))/(c + d*x^2)^(5/2), x)
\[ \int \frac {\sqrt {a+b x^2} \left (e+f x^2\right )^{3/2}}{\left (c+d x^2\right )^{5/2}} \, dx=\int \frac {\sqrt {b \,x^{2}+a}\, \left (f \,x^{2}+e \right )^{\frac {3}{2}}}{\left (d \,x^{2}+c \right )^{\frac {5}{2}}}d x \] Input:
int((b*x^2+a)^(1/2)*(f*x^2+e)^(3/2)/(d*x^2+c)^(5/2),x)
Output:
int((b*x^2+a)^(1/2)*(f*x^2+e)^(3/2)/(d*x^2+c)^(5/2),x)