Integrand size = 34, antiderivative size = 700 \[ \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx=-\frac {b (5 b d e-b c f-9 a d f) x \sqrt {a+b x^2} \sqrt {c+d x^2}}{8 d f^2 \sqrt {e+f x^2}}+\frac {b^2 x^3 \sqrt {a+b x^2} \sqrt {c+d x^2}}{4 f \sqrt {e+f x^2}}-\frac {c \sqrt {-b e+a f} \left (25 a b d e f-8 a^2 d f^2-b^2 e (15 d e-c f)\right ) \sqrt {a+b x^2} \sqrt {\frac {e \left (c+d x^2\right )}{c \left (e+f x^2\right )}} E\left (\arcsin \left (\frac {\sqrt {-b e+a f} x}{\sqrt {a} \sqrt {e+f x^2}}\right )|\frac {a (d e-c f)}{c (b e-a f)}\right )}{8 \sqrt {a} d e f^3 \sqrt {c+d x^2} \sqrt {\frac {e \left (a+b x^2\right )}{a \left (e+f x^2\right )}}}-\frac {3 b \sqrt {-b e+a f} (a f (5 d e-8 c f)-b e (5 d e-7 c f)) \sqrt {a+b x^2} \sqrt {\frac {e \left (c+d x^2\right )}{c \left (e+f x^2\right )}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {-b e+a f} x}{\sqrt {a} \sqrt {e+f x^2}}\right ),\frac {a (d e-c f)}{c (b e-a f)}\right )}{8 \sqrt {a} f^4 \sqrt {c+d x^2} \sqrt {\frac {e \left (a+b x^2\right )}{a \left (e+f x^2\right )}}}+\frac {b e \left (15 a^2 d^2 f^2-10 a b d f (3 d e-c f)+b^2 \left (15 d^2 e^2-6 c d e f-c^2 f^2\right )\right ) \sqrt {a+b x^2} \sqrt {\frac {e \left (c+d x^2\right )}{c \left (e+f x^2\right )}} \operatorname {EllipticPi}\left (-\frac {a f}{b e-a f},\arcsin \left (\frac {\sqrt {-b e+a f} x}{\sqrt {a} \sqrt {e+f x^2}}\right ),\frac {a (d e-c f)}{c (b e-a f)}\right )}{8 \sqrt {a} d f^4 \sqrt {-b e+a f} \sqrt {c+d x^2} \sqrt {\frac {e \left (a+b x^2\right )}{a \left (e+f x^2\right )}}} \] Output:
-1/8*b*(-9*a*d*f-b*c*f+5*b*d*e)*x*(b*x^2+a)^(1/2)*(d*x^2+c)^(1/2)/d/f^2/(f *x^2+e)^(1/2)+1/4*b^2*x^3*(b*x^2+a)^(1/2)*(d*x^2+c)^(1/2)/f/(f*x^2+e)^(1/2 )-1/8*c*(a*f-b*e)^(1/2)*(25*a*b*d*e*f-8*a^2*d*f^2-b^2*e*(-c*f+15*d*e))*(b* x^2+a)^(1/2)*(e*(d*x^2+c)/c/(f*x^2+e))^(1/2)*EllipticE((a*f-b*e)^(1/2)*x/a ^(1/2)/(f*x^2+e)^(1/2),(a*(-c*f+d*e)/c/(-a*f+b*e))^(1/2))/a^(1/2)/d/e/f^3/ (d*x^2+c)^(1/2)/(e*(b*x^2+a)/a/(f*x^2+e))^(1/2)-3/8*b*(a*f-b*e)^(1/2)*(a*f *(-8*c*f+5*d*e)-b*e*(-7*c*f+5*d*e))*(b*x^2+a)^(1/2)*(e*(d*x^2+c)/c/(f*x^2+ e))^(1/2)*EllipticF((a*f-b*e)^(1/2)*x/a^(1/2)/(f*x^2+e)^(1/2),(a*(-c*f+d*e )/c/(-a*f+b*e))^(1/2))/a^(1/2)/f^4/(d*x^2+c)^(1/2)/(e*(b*x^2+a)/a/(f*x^2+e ))^(1/2)+1/8*b*e*(15*a^2*d^2*f^2-10*a*b*d*f*(-c*f+3*d*e)+b^2*(-c^2*f^2-6*c *d*e*f+15*d^2*e^2))*(b*x^2+a)^(1/2)*(e*(d*x^2+c)/c/(f*x^2+e))^(1/2)*Ellipt icPi((a*f-b*e)^(1/2)*x/a^(1/2)/(f*x^2+e)^(1/2),-a*f/(-a*f+b*e),(a*(-c*f+d* e)/c/(-a*f+b*e))^(1/2))/a^(1/2)/d/f^4/(a*f-b*e)^(1/2)/(d*x^2+c)^(1/2)/(e*( b*x^2+a)/a/(f*x^2+e))^(1/2)
\[ \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx=\int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx \] Input:
Integrate[((a + b*x^2)^(5/2)*Sqrt[c + d*x^2])/(e + f*x^2)^(3/2),x]
Output:
Integrate[((a + b*x^2)^(5/2)*Sqrt[c + d*x^2])/(e + f*x^2)^(3/2), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx\) |
\(\Big \downarrow \) 434 |
\(\displaystyle \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}}dx\) |
Input:
Int[((a + b*x^2)^(5/2)*Sqrt[c + d*x^2])/(e + f*x^2)^(3/2),x]
Output:
$Aborted
Int[((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2)^(q_.)*((e_) + (f_.)*( x_)^2)^(r_.), x_Symbol] :> Unintegrable[(a + b*x^2)^p*(c + d*x^2)^q*(e + f* x^2)^r, x] /; FreeQ[{a, b, c, d, e, f, p, q, r}, x]
\[\int \frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}} \sqrt {x^{2} d +c}}{\left (f \,x^{2}+e \right )^{\frac {3}{2}}}d x\]
Input:
int((b*x^2+a)^(5/2)*(d*x^2+c)^(1/2)/(f*x^2+e)^(3/2),x)
Output:
int((b*x^2+a)^(5/2)*(d*x^2+c)^(1/2)/(f*x^2+e)^(3/2),x)
Timed out. \[ \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx=\text {Timed out} \] Input:
integrate((b*x^2+a)^(5/2)*(d*x^2+c)^(1/2)/(f*x^2+e)^(3/2),x, algorithm="fr icas")
Output:
Timed out
\[ \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx=\int \frac {\left (a + b x^{2}\right )^{\frac {5}{2}} \sqrt {c + d x^{2}}}{\left (e + f x^{2}\right )^{\frac {3}{2}}}\, dx \] Input:
integrate((b*x**2+a)**(5/2)*(d*x**2+c)**(1/2)/(f*x**2+e)**(3/2),x)
Output:
Integral((a + b*x**2)**(5/2)*sqrt(c + d*x**2)/(e + f*x**2)**(3/2), x)
\[ \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} \sqrt {d x^{2} + c}}{{\left (f x^{2} + e\right )}^{\frac {3}{2}}} \,d x } \] Input:
integrate((b*x^2+a)^(5/2)*(d*x^2+c)^(1/2)/(f*x^2+e)^(3/2),x, algorithm="ma xima")
Output:
integrate((b*x^2 + a)^(5/2)*sqrt(d*x^2 + c)/(f*x^2 + e)^(3/2), x)
\[ \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} \sqrt {d x^{2} + c}}{{\left (f x^{2} + e\right )}^{\frac {3}{2}}} \,d x } \] Input:
integrate((b*x^2+a)^(5/2)*(d*x^2+c)^(1/2)/(f*x^2+e)^(3/2),x, algorithm="gi ac")
Output:
integrate((b*x^2 + a)^(5/2)*sqrt(d*x^2 + c)/(f*x^2 + e)^(3/2), x)
Timed out. \[ \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx=\int \frac {{\left (b\,x^2+a\right )}^{5/2}\,\sqrt {d\,x^2+c}}{{\left (f\,x^2+e\right )}^{3/2}} \,d x \] Input:
int(((a + b*x^2)^(5/2)*(c + d*x^2)^(1/2))/(e + f*x^2)^(3/2),x)
Output:
int(((a + b*x^2)^(5/2)*(c + d*x^2)^(1/2))/(e + f*x^2)^(3/2), x)
\[ \int \frac {\left (a+b x^2\right )^{5/2} \sqrt {c+d x^2}}{\left (e+f x^2\right )^{3/2}} \, dx=\int \frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}} \sqrt {d \,x^{2}+c}}{\left (f \,x^{2}+e \right )^{\frac {3}{2}}}d x \] Input:
int((b*x^2+a)^(5/2)*(d*x^2+c)^(1/2)/(f*x^2+e)^(3/2),x)
Output:
int((b*x^2+a)^(5/2)*(d*x^2+c)^(1/2)/(f*x^2+e)^(3/2),x)