\(\int \frac {1}{(a+b x^2)^{5/2} (c+d x^2)^{3/2} (e+f x^2)^{3/2}} \, dx\) [534]

Optimal result

Integrand size = 34, antiderivative size = 946 \[ \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx=\frac {b^2 x}{3 a (b c-a d) (b e-a f) \left (a+b x^2\right )^{3/2} \sqrt {c+d x^2} \sqrt {e+f x^2}}+\frac {2 b^2 \left (b^2 c e+5 a^2 d f-3 a b (d e+c f)\right ) x}{3 a^2 (b c-a d)^2 (b e-a f)^2 \sqrt {a+b x^2} \sqrt {c+d x^2} \sqrt {e+f x^2}}+\frac {d \left (6 a^3 b d^3 e f-3 a^4 d^3 f^2+2 b^4 c^2 e (d e-c f)-a b^3 c \left (7 d^2 e^2-c d e f-6 c^2 f^2\right )-a^2 b^2 d \left (3 d^2 e^2-11 c d e f+11 c^2 f^2\right )\right ) x \sqrt {a+b x^2}}{3 a^2 c (b c-a d)^3 (b e-a f)^2 (d e-c f) \sqrt {c+d x^2} \sqrt {e+f x^2}}-\frac {\left (2 b^5 c^2 e^2 (d e-c f)^2+3 a^5 d^3 f^3 (d e+c f)-7 a b^4 c e (d e-c f)^2 (d e+c f)-9 a^4 b d^2 f^2 \left (d^2 e^2+c^2 f^2\right )+9 a^3 b^2 d f \left (d^3 e^3+c^3 f^3\right )-3 a^2 b^3 \left (d^4 e^4-4 c d^3 e^3 f+8 c^2 d^2 e^2 f^2-4 c^3 d e f^3+c^4 f^4\right )\right ) \sqrt {a+b x^2} \sqrt {\frac {e \left (c+d x^2\right )}{c \left (e+f x^2\right )}} E\left (\arcsin \left (\frac {\sqrt {-b e+a f} x}{\sqrt {a} \sqrt {e+f x^2}}\right )|\frac {a (d e-c f)}{c (b e-a f)}\right )}{3 a^{5/2} (b c-a d)^3 e (-b e+a f)^{5/2} (d e-c f)^2 \sqrt {c+d x^2} \sqrt {\frac {e \left (a+b x^2\right )}{a \left (e+f x^2\right )}}}-\frac {2 \left (3 a^4 d^3 f^3-b^4 c e (d e-c f)^2-3 a^3 b d^2 f^2 (d e+c f)+3 a b^3 (d e-c f)^2 (d e+c f)-3 a^2 b^2 d f \left (d^2 e^2-3 c d e f+c^2 f^2\right )\right ) \sqrt {a+b x^2} \sqrt {\frac {e \left (c+d x^2\right )}{c \left (e+f x^2\right )}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {-b e+a f} x}{\sqrt {a} \sqrt {e+f x^2}}\right ),\frac {a (d e-c f)}{c (b e-a f)}\right )}{3 a^{5/2} (b c-a d)^2 (-b e+a f)^{5/2} (d e-c f)^2 \sqrt {c+d x^2} \sqrt {\frac {e \left (a+b x^2\right )}{a \left (e+f x^2\right )}}} \] Output:

1/3*b^2*x/a/(-a*d+b*c)/(-a*f+b*e)/(b*x^2+a)^(3/2)/(d*x^2+c)^(1/2)/(f*x^2+e 
)^(1/2)+2/3*b^2*(b^2*c*e+5*a^2*d*f-3*a*b*(c*f+d*e))*x/a^2/(-a*d+b*c)^2/(-a 
*f+b*e)^2/(b*x^2+a)^(1/2)/(d*x^2+c)^(1/2)/(f*x^2+e)^(1/2)+1/3*d*(6*a^3*b*d 
^3*e*f-3*a^4*d^3*f^2+2*b^4*c^2*e*(-c*f+d*e)-a*b^3*c*(-6*c^2*f^2-c*d*e*f+7* 
d^2*e^2)-a^2*b^2*d*(11*c^2*f^2-11*c*d*e*f+3*d^2*e^2))*x*(b*x^2+a)^(1/2)/a^ 
2/c/(-a*d+b*c)^3/(-a*f+b*e)^2/(-c*f+d*e)/(d*x^2+c)^(1/2)/(f*x^2+e)^(1/2)-1 
/3*(2*b^5*c^2*e^2*(-c*f+d*e)^2+3*a^5*d^3*f^3*(c*f+d*e)-7*a*b^4*c*e*(-c*f+d 
*e)^2*(c*f+d*e)-9*a^4*b*d^2*f^2*(c^2*f^2+d^2*e^2)+9*a^3*b^2*d*f*(c^3*f^3+d 
^3*e^3)-3*a^2*b^3*(c^4*f^4-4*c^3*d*e*f^3+8*c^2*d^2*e^2*f^2-4*c*d^3*e^3*f+d 
^4*e^4))*(b*x^2+a)^(1/2)*(e*(d*x^2+c)/c/(f*x^2+e))^(1/2)*EllipticE((a*f-b* 
e)^(1/2)*x/a^(1/2)/(f*x^2+e)^(1/2),(a*(-c*f+d*e)/c/(-a*f+b*e))^(1/2))/a^(5 
/2)/(-a*d+b*c)^3/e/(a*f-b*e)^(5/2)/(-c*f+d*e)^2/(d*x^2+c)^(1/2)/(e*(b*x^2+ 
a)/a/(f*x^2+e))^(1/2)-2/3*(3*a^4*d^3*f^3-b^4*c*e*(-c*f+d*e)^2-3*a^3*b*d^2* 
f^2*(c*f+d*e)+3*a*b^3*(-c*f+d*e)^2*(c*f+d*e)-3*a^2*b^2*d*f*(c^2*f^2-3*c*d* 
e*f+d^2*e^2))*(b*x^2+a)^(1/2)*(e*(d*x^2+c)/c/(f*x^2+e))^(1/2)*EllipticF((a 
*f-b*e)^(1/2)*x/a^(1/2)/(f*x^2+e)^(1/2),(a*(-c*f+d*e)/c/(-a*f+b*e))^(1/2)) 
/a^(5/2)/(-a*d+b*c)^2/(a*f-b*e)^(5/2)/(-c*f+d*e)^2/(d*x^2+c)^(1/2)/(e*(b*x 
^2+a)/a/(f*x^2+e))^(1/2)
 

Mathematica [F]

\[ \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx=\int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx \] Input:

Integrate[1/((a + b*x^2)^(5/2)*(c + d*x^2)^(3/2)*(e + f*x^2)^(3/2)),x]
 

Output:

Integrate[1/((a + b*x^2)^(5/2)*(c + d*x^2)^(3/2)*(e + f*x^2)^(3/2)), x]
 

Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx\)

\(\Big \downarrow \) 434

\(\displaystyle \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}}dx\)

Input:

Int[1/((a + b*x^2)^(5/2)*(c + d*x^2)^(3/2)*(e + f*x^2)^(3/2)),x]
 

Output:

$Aborted
 

Defintions of rubi rules used

rule 434

Int[((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2)^(q_.)*((e_) + (f_.)*( 
x_)^2)^(r_.), x_Symbol] :> Unintegrable[(a + b*x^2)^p*(c + d*x^2)^q*(e + f* 
x^2)^r, x] /; FreeQ[{a, b, c, d, e, f, p, q, r}, x]
 

Maple [F]

\[\int \frac {1}{\left (b \,x^{2}+a \right )^{\frac {5}{2}} \left (x^{2} d +c \right )^{\frac {3}{2}} \left (f \,x^{2}+e \right )^{\frac {3}{2}}}d x\]

Input:

int(1/(b*x^2+a)^(5/2)/(d*x^2+c)^(3/2)/(f*x^2+e)^(3/2),x)
 

Output:

int(1/(b*x^2+a)^(5/2)/(d*x^2+c)^(3/2)/(f*x^2+e)^(3/2),x)
 

Fricas [F]

\[ \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx=\int { \frac {1}{{\left (b x^{2} + a\right )}^{\frac {5}{2}} {\left (d x^{2} + c\right )}^{\frac {3}{2}} {\left (f x^{2} + e\right )}^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/(b*x^2+a)^(5/2)/(d*x^2+c)^(3/2)/(f*x^2+e)^(3/2),x, algorithm=" 
fricas")
 

Output:

integral(sqrt(b*x^2 + a)*sqrt(d*x^2 + c)*sqrt(f*x^2 + e)/(b^3*d^2*f^2*x^14 
 + (2*b^3*d^2*e*f + (2*b^3*c*d + 3*a*b^2*d^2)*f^2)*x^12 + (b^3*d^2*e^2 + 2 
*(2*b^3*c*d + 3*a*b^2*d^2)*e*f + (b^3*c^2 + 6*a*b^2*c*d + 3*a^2*b*d^2)*f^2 
)*x^10 + ((2*b^3*c*d + 3*a*b^2*d^2)*e^2 + 2*(b^3*c^2 + 6*a*b^2*c*d + 3*a^2 
*b*d^2)*e*f + (3*a*b^2*c^2 + 6*a^2*b*c*d + a^3*d^2)*f^2)*x^8 + a^3*c^2*e^2 
 + ((b^3*c^2 + 6*a*b^2*c*d + 3*a^2*b*d^2)*e^2 + 2*(3*a*b^2*c^2 + 6*a^2*b*c 
*d + a^3*d^2)*e*f + (3*a^2*b*c^2 + 2*a^3*c*d)*f^2)*x^6 + (a^3*c^2*f^2 + (3 
*a*b^2*c^2 + 6*a^2*b*c*d + a^3*d^2)*e^2 + 2*(3*a^2*b*c^2 + 2*a^3*c*d)*e*f) 
*x^4 + (2*a^3*c^2*e*f + (3*a^2*b*c^2 + 2*a^3*c*d)*e^2)*x^2), x)
 

Sympy [F(-1)]

Timed out. \[ \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx=\text {Timed out} \] Input:

integrate(1/(b*x**2+a)**(5/2)/(d*x**2+c)**(3/2)/(f*x**2+e)**(3/2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx=\int { \frac {1}{{\left (b x^{2} + a\right )}^{\frac {5}{2}} {\left (d x^{2} + c\right )}^{\frac {3}{2}} {\left (f x^{2} + e\right )}^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/(b*x^2+a)^(5/2)/(d*x^2+c)^(3/2)/(f*x^2+e)^(3/2),x, algorithm=" 
maxima")
 

Output:

integrate(1/((b*x^2 + a)^(5/2)*(d*x^2 + c)^(3/2)*(f*x^2 + e)^(3/2)), x)
 

Giac [F]

\[ \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx=\int { \frac {1}{{\left (b x^{2} + a\right )}^{\frac {5}{2}} {\left (d x^{2} + c\right )}^{\frac {3}{2}} {\left (f x^{2} + e\right )}^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/(b*x^2+a)^(5/2)/(d*x^2+c)^(3/2)/(f*x^2+e)^(3/2),x, algorithm=" 
giac")
 

Output:

integrate(1/((b*x^2 + a)^(5/2)*(d*x^2 + c)^(3/2)*(f*x^2 + e)^(3/2)), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx=\int \frac {1}{{\left (b\,x^2+a\right )}^{5/2}\,{\left (d\,x^2+c\right )}^{3/2}\,{\left (f\,x^2+e\right )}^{3/2}} \,d x \] Input:

int(1/((a + b*x^2)^(5/2)*(c + d*x^2)^(3/2)*(e + f*x^2)^(3/2)),x)
 

Output:

int(1/((a + b*x^2)^(5/2)*(c + d*x^2)^(3/2)*(e + f*x^2)^(3/2)), x)
 

Reduce [F]

\[ \int \frac {1}{\left (a+b x^2\right )^{5/2} \left (c+d x^2\right )^{3/2} \left (e+f x^2\right )^{3/2}} \, dx=\int \frac {1}{\left (b \,x^{2}+a \right )^{\frac {5}{2}} \left (d \,x^{2}+c \right )^{\frac {3}{2}} \left (f \,x^{2}+e \right )^{\frac {3}{2}}}d x \] Input:

int(1/(b*x^2+a)^(5/2)/(d*x^2+c)^(3/2)/(f*x^2+e)^(3/2),x)
 

Output:

int(1/(b*x^2+a)^(5/2)/(d*x^2+c)^(3/2)/(f*x^2+e)^(3/2),x)