\(\int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx\) [20]

Optimal result

Integrand size = 17, antiderivative size = 551 \[ \int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx=\frac {3 B \left (a+b x^2\right )^{2/3}}{4 b}-\frac {3 A x}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}+\frac {3 \sqrt [4]{3} \sqrt {2+\sqrt {3}} \sqrt [3]{a} A \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} E\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}\right )|-7+4 \sqrt {3}\right )}{2 b x \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}-\frac {\sqrt {2} 3^{3/4} \sqrt [3]{a} A \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}\right ),-7+4 \sqrt {3}\right )}{b x \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}} \] Output:

3/4*B*(b*x^2+a)^(2/3)/b-3*A*x/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))+3/2*3^ 
(1/4)*(1/2*6^(1/2)+1/2*2^(1/2))*a^(1/3)*A*(a^(1/3)-(b*x^2+a)^(1/3))*((a^(2 
/3)+a^(1/3)*(b*x^2+a)^(1/3)+(b*x^2+a)^(2/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a 
)^(1/3))^2)^(1/2)*EllipticE(((1+3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))/((1-3^(1 
/2))*a^(1/3)-(b*x^2+a)^(1/3)),2*I-I*3^(1/2))/b/x/(-a^(1/3)*(a^(1/3)-(b*x^2 
+a)^(1/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))^2)^(1/2)-2^(1/2)*3^(3/4)* 
a^(1/3)*A*(a^(1/3)-(b*x^2+a)^(1/3))*((a^(2/3)+a^(1/3)*(b*x^2+a)^(1/3)+(b*x 
^2+a)^(2/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))^2)^(1/2)*EllipticF(((1+ 
3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3)),2* 
I-I*3^(1/2))/b/x/(-a^(1/3)*(a^(1/3)-(b*x^2+a)^(1/3))/((1-3^(1/2))*a^(1/3)- 
(b*x^2+a)^(1/3))^2)^(1/2)
                                                                                    
                                                                                    
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 8.42 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.12 \[ \int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx=\frac {3 B \left (a+b x^2\right )^{2/3}}{4 b}+\frac {A x \sqrt [3]{\frac {a+b x^2}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{3},\frac {1}{2},\frac {3}{2},-\frac {b x^2}{a}\right )}{\sqrt [3]{a+b x^2}} \] Input:

Integrate[(A + B*x)/(a + b*x^2)^(1/3),x]
 

Output:

(3*B*(a + b*x^2)^(2/3))/(4*b) + (A*x*((a + b*x^2)/a)^(1/3)*Hypergeometric2 
F1[1/3, 1/2, 3/2, -((b*x^2)/a)])/(a + b*x^2)^(1/3)
 

Rubi [A] (warning: unable to verify)

Time = 0.49 (sec) , antiderivative size = 595, normalized size of antiderivative = 1.08, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.294, Rules used = {455, 233, 833, 760, 2418}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx\)

\(\Big \downarrow \) 455

\(\displaystyle A \int \frac {1}{\sqrt [3]{b x^2+a}}dx+\frac {3 B \left (a+b x^2\right )^{2/3}}{4 b}\)

\(\Big \downarrow \) 233

\(\displaystyle \frac {3 A \sqrt {b x^2} \int \frac {\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}}{2 b x}+\frac {3 B \left (a+b x^2\right )^{2/3}}{4 b}\)

\(\Big \downarrow \) 833

\(\displaystyle \frac {3 A \sqrt {b x^2} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a} \int \frac {1}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}-\int \frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}\right )}{2 b x}+\frac {3 B \left (a+b x^2\right )^{2/3}}{4 b}\)

\(\Big \downarrow \) 760

\(\displaystyle \frac {3 A \sqrt {b x^2} \left (-\int \frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}-\frac {2 \sqrt {2-\sqrt {3}} \left (1+\sqrt {3}\right ) \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}\right )}{2 b x}+\frac {3 B \left (a+b x^2\right )^{2/3}}{4 b}\)

\(\Big \downarrow \) 2418

\(\displaystyle \frac {3 A \sqrt {b x^2} \left (-\frac {2 \sqrt {2-\sqrt {3}} \left (1+\sqrt {3}\right ) \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}+\frac {\sqrt [4]{3} \sqrt {2+\sqrt {3}} \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} E\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right )|-7+4 \sqrt {3}\right )}{\sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}-\frac {2 \sqrt {b x^2}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}\right )}{2 b x}+\frac {3 B \left (a+b x^2\right )^{2/3}}{4 b}\)

Input:

Int[(A + B*x)/(a + b*x^2)^(1/3),x]
 

Output:

(3*B*(a + b*x^2)^(2/3))/(4*b) + (3*A*Sqrt[b*x^2]*((-2*Sqrt[b*x^2])/((1 - S 
qrt[3])*a^(1/3) - (a + b*x^2)^(1/3)) + (3^(1/4)*Sqrt[2 + Sqrt[3]]*a^(1/3)* 
(a^(1/3) - (a + b*x^2)^(1/3))*Sqrt[(a^(2/3) + a^(1/3)*(a + b*x^2)^(1/3) + 
(a + b*x^2)^(2/3))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))^2]*Elliptic 
E[ArcSin[((1 + Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))/((1 - Sqrt[3])*a^(1/3 
) - (a + b*x^2)^(1/3))], -7 + 4*Sqrt[3]])/(Sqrt[b*x^2]*Sqrt[-((a^(1/3)*(a^ 
(1/3) - (a + b*x^2)^(1/3)))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))^2) 
]) - (2*Sqrt[2 - Sqrt[3]]*(1 + Sqrt[3])*a^(1/3)*(a^(1/3) - (a + b*x^2)^(1/ 
3))*Sqrt[(a^(2/3) + a^(1/3)*(a + b*x^2)^(1/3) + (a + b*x^2)^(2/3))/((1 - S 
qrt[3])*a^(1/3) - (a + b*x^2)^(1/3))^2]*EllipticF[ArcSin[((1 + Sqrt[3])*a^ 
(1/3) - (a + b*x^2)^(1/3))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))], - 
7 + 4*Sqrt[3]])/(3^(1/4)*Sqrt[b*x^2]*Sqrt[-((a^(1/3)*(a^(1/3) - (a + b*x^2 
)^(1/3)))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))^2)])))/(2*b*x)
 

Defintions of rubi rules used

rule 233

Int[((a_) + (b_.)*(x_)^2)^(-1/3), x_Symbol] :> Simp[3*(Sqrt[b*x^2]/(2*b*x)) 
   Subst[Int[x/Sqrt[-a + x^3], x], x, (a + b*x^2)^(1/3)], x] /; FreeQ[{a, b 
}, x]
 

rule 455

Int[((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[d*(( 
a + b*x^2)^(p + 1)/(2*b*(p + 1))), x] + Simp[c   Int[(a + b*x^2)^p, x], x] 
/; FreeQ[{a, b, c, d, p}, x] &&  !LeQ[p, -1]
 

rule 760

Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], 
s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt[2 - Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s 
*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[(- 
s)*((s + r*x)/((1 - Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 + Sqrt[3]) 
*s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x 
] && NegQ[a]
 

rule 833

Int[(x_)/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3] 
], s = Denom[Rt[b/a, 3]]}, Simp[(-(1 + Sqrt[3]))*(s/r)   Int[1/Sqrt[a + b*x 
^3], x], x] + Simp[1/r   Int[((1 + Sqrt[3])*s + r*x)/Sqrt[a + b*x^3], x], x 
]] /; FreeQ[{a, b}, x] && NegQ[a]
 

rule 2418

Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = N 
umer[Simplify[(1 + Sqrt[3])*(d/c)]], s = Denom[Simplify[(1 + Sqrt[3])*(d/c) 
]]}, Simp[2*d*s^3*(Sqrt[a + b*x^3]/(a*r^2*((1 - Sqrt[3])*s + r*x))), x] + S 
imp[3^(1/4)*Sqrt[2 + Sqrt[3]]*d*s*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/( 
(1 - Sqrt[3])*s + r*x)^2]/(r^2*Sqrt[a + b*x^3]*Sqrt[(-s)*((s + r*x)/((1 - S 
qrt[3])*s + r*x)^2)]))*EllipticE[ArcSin[((1 + Sqrt[3])*s + r*x)/((1 - Sqrt[ 
3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b, c, d}, x] && NegQ[a] && 
 EqQ[b*c^3 - 2*(5 + 3*Sqrt[3])*a*d^3, 0]
 

Maple [F]

\[\int \frac {B x +A}{\left (b \,x^{2}+a \right )^{\frac {1}{3}}}d x\]

Input:

int((B*x+A)/(b*x^2+a)^(1/3),x)
 

Output:

int((B*x+A)/(b*x^2+a)^(1/3),x)
 

Fricas [F]

\[ \int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx=\int { \frac {B x + A}{{\left (b x^{2} + a\right )}^{\frac {1}{3}}} \,d x } \] Input:

integrate((B*x+A)/(b*x^2+a)^(1/3),x, algorithm="fricas")
 

Output:

integral((B*x + A)/(b*x^2 + a)^(1/3), x)
 

Sympy [A] (verification not implemented)

Time = 0.75 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.10 \[ \int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx=\frac {A x {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{3}, \frac {1}{2} \\ \frac {3}{2} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{\sqrt [3]{a}} + B \left (\begin {cases} \frac {x^{2}}{2 \sqrt [3]{a}} & \text {for}\: b = 0 \\\frac {3 \left (a + b x^{2}\right )^{\frac {2}{3}}}{4 b} & \text {otherwise} \end {cases}\right ) \] Input:

integrate((B*x+A)/(b*x**2+a)**(1/3),x)
 

Output:

A*x*hyper((1/3, 1/2), (3/2,), b*x**2*exp_polar(I*pi)/a)/a**(1/3) + B*Piece 
wise((x**2/(2*a**(1/3)), Eq(b, 0)), (3*(a + b*x**2)**(2/3)/(4*b), True))
 

Maxima [F]

\[ \int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx=\int { \frac {B x + A}{{\left (b x^{2} + a\right )}^{\frac {1}{3}}} \,d x } \] Input:

integrate((B*x+A)/(b*x^2+a)^(1/3),x, algorithm="maxima")
 

Output:

integrate((B*x + A)/(b*x^2 + a)^(1/3), x)
 

Giac [F]

\[ \int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx=\int { \frac {B x + A}{{\left (b x^{2} + a\right )}^{\frac {1}{3}}} \,d x } \] Input:

integrate((B*x+A)/(b*x^2+a)^(1/3),x, algorithm="giac")
 

Output:

integrate((B*x + A)/(b*x^2 + a)^(1/3), x)
 

Mupad [B] (verification not implemented)

Time = 0.49 (sec) , antiderivative size = 54, normalized size of antiderivative = 0.10 \[ \int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx=\frac {3\,B\,{\left (b\,x^2+a\right )}^{2/3}}{4\,b}+\frac {A\,x\,{\left (\frac {b\,x^2}{a}+1\right )}^{1/3}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{3},\frac {1}{2};\ \frac {3}{2};\ -\frac {b\,x^2}{a}\right )}{{\left (b\,x^2+a\right )}^{1/3}} \] Input:

int((A + B*x)/(a + b*x^2)^(1/3),x)
 

Output:

(3*B*(a + b*x^2)^(2/3))/(4*b) + (A*x*((b*x^2)/a + 1)^(1/3)*hypergeom([1/3, 
 1/2], 3/2, -(b*x^2)/a))/(a + b*x^2)^(1/3)
 

Reduce [F]

\[ \int \frac {A+B x}{\sqrt [3]{a+b x^2}} \, dx=\left (\int \frac {x}{\left (b \,x^{2}+a \right )^{\frac {1}{3}}}d x \right ) b +\left (\int \frac {1}{\left (b \,x^{2}+a \right )^{\frac {1}{3}}}d x \right ) a \] Input:

int((B*x+A)/(b*x^2+a)^(1/3),x)
 

Output:

int(x/(a + b*x**2)**(1/3),x)*b + int(1/(a + b*x**2)**(1/3),x)*a