\(\int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx\) [68]

Optimal result
Mathematica [C] (verified)
Rubi [A] (warning: unable to verify)
Maple [F]
Fricas [F]
Sympy [A] (verification not implemented)
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 27, antiderivative size = 628 \[ \int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx=\frac {3 (b B-a D) \left (a+b x^2\right )^{2/3}}{4 b^2}+\frac {3 C x \left (a+b x^2\right )^{2/3}}{7 b}+\frac {3 D \left (a+b x^2\right )^{5/3}}{10 b^2}-\frac {3 (7 A b-3 a C) x}{7 b \left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}+\frac {3 \sqrt [4]{3} \sqrt {2+\sqrt {3}} \sqrt [3]{a} (7 A b-3 a C) \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} E\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}\right )|-7+4 \sqrt {3}\right )}{14 b^2 x \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}-\frac {\sqrt {2} 3^{3/4} \sqrt [3]{a} (7 A b-3 a C) \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}\right ),-7+4 \sqrt {3}\right )}{7 b^2 x \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}} \] Output:

3/4*(B*b-D*a)*(b*x^2+a)^(2/3)/b^2+3/7*C*x*(b*x^2+a)^(2/3)/b+3/10*D*(b*x^2+ 
a)^(5/3)/b^2-3/7*(7*A*b-3*C*a)*x/b/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))+3 
/14*3^(1/4)*(1/2*6^(1/2)+1/2*2^(1/2))*a^(1/3)*(7*A*b-3*C*a)*(a^(1/3)-(b*x^ 
2+a)^(1/3))*((a^(2/3)+a^(1/3)*(b*x^2+a)^(1/3)+(b*x^2+a)^(2/3))/((1-3^(1/2) 
)*a^(1/3)-(b*x^2+a)^(1/3))^2)^(1/2)*EllipticE(((1+3^(1/2))*a^(1/3)-(b*x^2+ 
a)^(1/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3)),2*I-I*3^(1/2))/b^2/x/(-a^( 
1/3)*(a^(1/3)-(b*x^2+a)^(1/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))^2)^(1 
/2)-1/7*2^(1/2)*3^(3/4)*a^(1/3)*(7*A*b-3*C*a)*(a^(1/3)-(b*x^2+a)^(1/3))*(( 
a^(2/3)+a^(1/3)*(b*x^2+a)^(1/3)+(b*x^2+a)^(2/3))/((1-3^(1/2))*a^(1/3)-(b*x 
^2+a)^(1/3))^2)^(1/2)*EllipticF(((1+3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))/((1- 
3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3)),2*I-I*3^(1/2))/b^2/x/(-a^(1/3)*(a^(1/3)- 
(b*x^2+a)^(1/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))^2)^(1/2)
                                                                                    
                                                                                    
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 5.06 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.15 \[ \int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx=\frac {-3 \left (a+b x^2\right ) (-35 b B+21 a D-2 b x (10 C+7 D x))+20 b (7 A b-3 a C) x \sqrt [3]{1+\frac {b x^2}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{3},\frac {1}{2},\frac {3}{2},-\frac {b x^2}{a}\right )}{140 b^2 \sqrt [3]{a+b x^2}} \] Input:

Integrate[(A + B*x + C*x^2 + D*x^3)/(a + b*x^2)^(1/3),x]
 

Output:

(-3*(a + b*x^2)*(-35*b*B + 21*a*D - 2*b*x*(10*C + 7*D*x)) + 20*b*(7*A*b - 
3*a*C)*x*(1 + (b*x^2)/a)^(1/3)*Hypergeometric2F1[1/3, 1/2, 3/2, -((b*x^2)/ 
a)])/(140*b^2*(a + b*x^2)^(1/3))
 

Rubi [A] (warning: unable to verify)

Time = 0.63 (sec) , antiderivative size = 663, normalized size of antiderivative = 1.06, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2346, 27, 2346, 27, 455, 233, 833, 760, 2418}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx\)

\(\Big \downarrow \) 2346

\(\displaystyle \frac {3 \int \frac {2 \left (5 b C x^2+(5 b B-3 a D) x+5 A b\right )}{3 \sqrt [3]{b x^2+a}}dx}{10 b}+\frac {3 D x^2 \left (a+b x^2\right )^{2/3}}{10 b}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {5 b C x^2+(5 b B-3 a D) x+5 A b}{\sqrt [3]{b x^2+a}}dx}{5 b}+\frac {3 D x^2 \left (a+b x^2\right )^{2/3}}{10 b}\)

\(\Big \downarrow \) 2346

\(\displaystyle \frac {\frac {3 \int \frac {b (5 (7 A b-3 a C)+7 (5 b B-3 a D) x)}{3 \sqrt [3]{b x^2+a}}dx}{7 b}+\frac {15}{7} C x \left (a+b x^2\right )^{2/3}}{5 b}+\frac {3 D x^2 \left (a+b x^2\right )^{2/3}}{10 b}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {1}{7} \int \frac {5 (7 A b-3 a C)+7 (5 b B-3 a D) x}{\sqrt [3]{b x^2+a}}dx+\frac {15}{7} C x \left (a+b x^2\right )^{2/3}}{5 b}+\frac {3 D x^2 \left (a+b x^2\right )^{2/3}}{10 b}\)

\(\Big \downarrow \) 455

\(\displaystyle \frac {\frac {1}{7} \left (5 (7 A b-3 a C) \int \frac {1}{\sqrt [3]{b x^2+a}}dx+\frac {21 \left (a+b x^2\right )^{2/3} (5 b B-3 a D)}{4 b}\right )+\frac {15}{7} C x \left (a+b x^2\right )^{2/3}}{5 b}+\frac {3 D x^2 \left (a+b x^2\right )^{2/3}}{10 b}\)

\(\Big \downarrow \) 233

\(\displaystyle \frac {\frac {1}{7} \left (\frac {15 \sqrt {b x^2} (7 A b-3 a C) \int \frac {\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}}{2 b x}+\frac {21 \left (a+b x^2\right )^{2/3} (5 b B-3 a D)}{4 b}\right )+\frac {15}{7} C x \left (a+b x^2\right )^{2/3}}{5 b}+\frac {3 D x^2 \left (a+b x^2\right )^{2/3}}{10 b}\)

\(\Big \downarrow \) 833

\(\displaystyle \frac {\frac {1}{7} \left (\frac {15 \sqrt {b x^2} (7 A b-3 a C) \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a} \int \frac {1}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}-\int \frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}\right )}{2 b x}+\frac {21 \left (a+b x^2\right )^{2/3} (5 b B-3 a D)}{4 b}\right )+\frac {15}{7} C x \left (a+b x^2\right )^{2/3}}{5 b}+\frac {3 D x^2 \left (a+b x^2\right )^{2/3}}{10 b}\)

\(\Big \downarrow \) 760

\(\displaystyle \frac {\frac {1}{7} \left (\frac {15 \sqrt {b x^2} (7 A b-3 a C) \left (-\int \frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}-\frac {2 \sqrt {2-\sqrt {3}} \left (1+\sqrt {3}\right ) \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}\right )}{2 b x}+\frac {21 \left (a+b x^2\right )^{2/3} (5 b B-3 a D)}{4 b}\right )+\frac {15}{7} C x \left (a+b x^2\right )^{2/3}}{5 b}+\frac {3 D x^2 \left (a+b x^2\right )^{2/3}}{10 b}\)

\(\Big \downarrow \) 2418

\(\displaystyle \frac {\frac {1}{7} \left (\frac {15 \sqrt {b x^2} (7 A b-3 a C) \left (-\frac {2 \sqrt {2-\sqrt {3}} \left (1+\sqrt {3}\right ) \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}+\frac {\sqrt [4]{3} \sqrt {2+\sqrt {3}} \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} E\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right )|-7+4 \sqrt {3}\right )}{\sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}-\frac {2 \sqrt {b x^2}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}\right )}{2 b x}+\frac {21 \left (a+b x^2\right )^{2/3} (5 b B-3 a D)}{4 b}\right )+\frac {15}{7} C x \left (a+b x^2\right )^{2/3}}{5 b}+\frac {3 D x^2 \left (a+b x^2\right )^{2/3}}{10 b}\)

Input:

Int[(A + B*x + C*x^2 + D*x^3)/(a + b*x^2)^(1/3),x]
 

Output:

(3*D*x^2*(a + b*x^2)^(2/3))/(10*b) + ((15*C*x*(a + b*x^2)^(2/3))/7 + ((21* 
(5*b*B - 3*a*D)*(a + b*x^2)^(2/3))/(4*b) + (15*(7*A*b - 3*a*C)*Sqrt[b*x^2] 
*((-2*Sqrt[b*x^2])/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3)) + (3^(1/4)* 
Sqrt[2 + Sqrt[3]]*a^(1/3)*(a^(1/3) - (a + b*x^2)^(1/3))*Sqrt[(a^(2/3) + a^ 
(1/3)*(a + b*x^2)^(1/3) + (a + b*x^2)^(2/3))/((1 - Sqrt[3])*a^(1/3) - (a + 
 b*x^2)^(1/3))^2]*EllipticE[ArcSin[((1 + Sqrt[3])*a^(1/3) - (a + b*x^2)^(1 
/3))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))], -7 + 4*Sqrt[3]])/(Sqrt[ 
b*x^2]*Sqrt[-((a^(1/3)*(a^(1/3) - (a + b*x^2)^(1/3)))/((1 - Sqrt[3])*a^(1/ 
3) - (a + b*x^2)^(1/3))^2)]) - (2*Sqrt[2 - Sqrt[3]]*(1 + Sqrt[3])*a^(1/3)* 
(a^(1/3) - (a + b*x^2)^(1/3))*Sqrt[(a^(2/3) + a^(1/3)*(a + b*x^2)^(1/3) + 
(a + b*x^2)^(2/3))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))^2]*Elliptic 
F[ArcSin[((1 + Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))/((1 - Sqrt[3])*a^(1/3 
) - (a + b*x^2)^(1/3))], -7 + 4*Sqrt[3]])/(3^(1/4)*Sqrt[b*x^2]*Sqrt[-((a^( 
1/3)*(a^(1/3) - (a + b*x^2)^(1/3)))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^( 
1/3))^2)])))/(2*b*x))/7)/(5*b)
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 233
Int[((a_) + (b_.)*(x_)^2)^(-1/3), x_Symbol] :> Simp[3*(Sqrt[b*x^2]/(2*b*x)) 
   Subst[Int[x/Sqrt[-a + x^3], x], x, (a + b*x^2)^(1/3)], x] /; FreeQ[{a, b 
}, x]
 

rule 455
Int[((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[d*(( 
a + b*x^2)^(p + 1)/(2*b*(p + 1))), x] + Simp[c   Int[(a + b*x^2)^p, x], x] 
/; FreeQ[{a, b, c, d, p}, x] &&  !LeQ[p, -1]
 

rule 760
Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], 
s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt[2 - Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s 
*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[(- 
s)*((s + r*x)/((1 - Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 + Sqrt[3]) 
*s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x 
] && NegQ[a]
 

rule 833
Int[(x_)/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3] 
], s = Denom[Rt[b/a, 3]]}, Simp[(-(1 + Sqrt[3]))*(s/r)   Int[1/Sqrt[a + b*x 
^3], x], x] + Simp[1/r   Int[((1 + Sqrt[3])*s + r*x)/Sqrt[a + b*x^3], x], x 
]] /; FreeQ[{a, b}, x] && NegQ[a]
 

rule 2346
Int[(Pq_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{q = Expon[Pq, x], 
e = Coeff[Pq, x, Expon[Pq, x]]}, Simp[e*x^(q - 1)*((a + b*x^2)^(p + 1)/(b*( 
q + 2*p + 1))), x] + Simp[1/(b*(q + 2*p + 1))   Int[(a + b*x^2)^p*ExpandToS 
um[b*(q + 2*p + 1)*Pq - a*e*(q - 1)*x^(q - 2) - b*e*(q + 2*p + 1)*x^q, x], 
x], x]] /; FreeQ[{a, b, p}, x] && PolyQ[Pq, x] &&  !LeQ[p, -1]
 

rule 2418
Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = N 
umer[Simplify[(1 + Sqrt[3])*(d/c)]], s = Denom[Simplify[(1 + Sqrt[3])*(d/c) 
]]}, Simp[2*d*s^3*(Sqrt[a + b*x^3]/(a*r^2*((1 - Sqrt[3])*s + r*x))), x] + S 
imp[3^(1/4)*Sqrt[2 + Sqrt[3]]*d*s*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/( 
(1 - Sqrt[3])*s + r*x)^2]/(r^2*Sqrt[a + b*x^3]*Sqrt[(-s)*((s + r*x)/((1 - S 
qrt[3])*s + r*x)^2)]))*EllipticE[ArcSin[((1 + Sqrt[3])*s + r*x)/((1 - Sqrt[ 
3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b, c, d}, x] && NegQ[a] && 
 EqQ[b*c^3 - 2*(5 + 3*Sqrt[3])*a*d^3, 0]
 
Maple [F]

\[\int \frac {D x^{3}+C \,x^{2}+B x +A}{\left (b \,x^{2}+a \right )^{\frac {1}{3}}}d x\]

Input:

int((D*x^3+C*x^2+B*x+A)/(b*x^2+a)^(1/3),x)
 

Output:

int((D*x^3+C*x^2+B*x+A)/(b*x^2+a)^(1/3),x)
 

Fricas [F]

\[ \int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx=\int { \frac {D x^{3} + C x^{2} + B x + A}{{\left (b x^{2} + a\right )}^{\frac {1}{3}}} \,d x } \] Input:

integrate((D*x^3+C*x^2+B*x+A)/(b*x^2+a)^(1/3),x, algorithm="fricas")
 

Output:

integral((D*x^3 + C*x^2 + B*x + A)/(b*x^2 + a)^(1/3), x)
 

Sympy [A] (verification not implemented)

Time = 1.40 (sec) , antiderivative size = 272, normalized size of antiderivative = 0.43 \[ \int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx=\frac {A x {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{3}, \frac {1}{2} \\ \frac {3}{2} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{\sqrt [3]{a}} + B \left (\begin {cases} \frac {x^{2}}{2 \sqrt [3]{a}} & \text {for}\: b = 0 \\\frac {3 \left (a + b x^{2}\right )^{\frac {2}{3}}}{4 b} & \text {otherwise} \end {cases}\right ) + \frac {C x^{3} {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{3}, \frac {3}{2} \\ \frac {5}{2} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{3 \sqrt [3]{a}} - \frac {9 D a^{\frac {11}{3}} \left (1 + \frac {b x^{2}}{a}\right )^{\frac {2}{3}}}{20 a^{2} b^{2} + 20 a b^{3} x^{2}} + \frac {9 D a^{\frac {11}{3}}}{20 a^{2} b^{2} + 20 a b^{3} x^{2}} - \frac {3 D a^{\frac {8}{3}} b x^{2} \left (1 + \frac {b x^{2}}{a}\right )^{\frac {2}{3}}}{20 a^{2} b^{2} + 20 a b^{3} x^{2}} + \frac {9 D a^{\frac {8}{3}} b x^{2}}{20 a^{2} b^{2} + 20 a b^{3} x^{2}} + \frac {6 D a^{\frac {5}{3}} b^{2} x^{4} \left (1 + \frac {b x^{2}}{a}\right )^{\frac {2}{3}}}{20 a^{2} b^{2} + 20 a b^{3} x^{2}} \] Input:

integrate((D*x**3+C*x**2+B*x+A)/(b*x**2+a)**(1/3),x)
 

Output:

A*x*hyper((1/3, 1/2), (3/2,), b*x**2*exp_polar(I*pi)/a)/a**(1/3) + B*Piece 
wise((x**2/(2*a**(1/3)), Eq(b, 0)), (3*(a + b*x**2)**(2/3)/(4*b), True)) + 
 C*x**3*hyper((1/3, 3/2), (5/2,), b*x**2*exp_polar(I*pi)/a)/(3*a**(1/3)) - 
 9*D*a**(11/3)*(1 + b*x**2/a)**(2/3)/(20*a**2*b**2 + 20*a*b**3*x**2) + 9*D 
*a**(11/3)/(20*a**2*b**2 + 20*a*b**3*x**2) - 3*D*a**(8/3)*b*x**2*(1 + b*x* 
*2/a)**(2/3)/(20*a**2*b**2 + 20*a*b**3*x**2) + 9*D*a**(8/3)*b*x**2/(20*a** 
2*b**2 + 20*a*b**3*x**2) + 6*D*a**(5/3)*b**2*x**4*(1 + b*x**2/a)**(2/3)/(2 
0*a**2*b**2 + 20*a*b**3*x**2)
 

Maxima [F]

\[ \int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx=\int { \frac {D x^{3} + C x^{2} + B x + A}{{\left (b x^{2} + a\right )}^{\frac {1}{3}}} \,d x } \] Input:

integrate((D*x^3+C*x^2+B*x+A)/(b*x^2+a)^(1/3),x, algorithm="maxima")
 

Output:

integrate((D*x^3 + C*x^2 + B*x + A)/(b*x^2 + a)^(1/3), x)
 

Giac [F]

\[ \int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx=\int { \frac {D x^{3} + C x^{2} + B x + A}{{\left (b x^{2} + a\right )}^{\frac {1}{3}}} \,d x } \] Input:

integrate((D*x^3+C*x^2+B*x+A)/(b*x^2+a)^(1/3),x, algorithm="giac")
 

Output:

integrate((D*x^3 + C*x^2 + B*x + A)/(b*x^2 + a)^(1/3), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx=\int \frac {A+B\,x+C\,x^2+x^3\,D}{{\left (b\,x^2+a\right )}^{1/3}} \,d x \] Input:

int((A + B*x + C*x^2 + x^3*D)/(a + b*x^2)^(1/3),x)
 

Output:

int((A + B*x + C*x^2 + x^3*D)/(a + b*x^2)^(1/3), x)
 

Reduce [F]

\[ \int \frac {A+B x+C x^2+D x^3}{\sqrt [3]{a+b x^2}} \, dx=\left (\int \frac {x^{3}}{\left (b \,x^{2}+a \right )^{\frac {1}{3}}}d x \right ) d +\left (\int \frac {x^{2}}{\left (b \,x^{2}+a \right )^{\frac {1}{3}}}d x \right ) c +\left (\int \frac {x}{\left (b \,x^{2}+a \right )^{\frac {1}{3}}}d x \right ) b +\left (\int \frac {1}{\left (b \,x^{2}+a \right )^{\frac {1}{3}}}d x \right ) a \] Input:

int((D*x^3+C*x^2+B*x+A)/(b*x^2+a)^(1/3),x)
 

Output:

int(x**3/(a + b*x**2)**(1/3),x)*d + int(x**2/(a + b*x**2)**(1/3),x)*c + in 
t(x/(a + b*x**2)**(1/3),x)*b + int(1/(a + b*x**2)**(1/3),x)*a