Integrand size = 16, antiderivative size = 133 \[ \int \frac {x^{13}}{\sqrt [4]{a-b x^4}} \, dx=-\frac {4 a^2 x^2 \left (a-b x^4\right )^{3/4}}{39 b^3}-\frac {10 a x^6 \left (a-b x^4\right )^{3/4}}{117 b^2}-\frac {x^{10} \left (a-b x^4\right )^{3/4}}{13 b}+\frac {8 a^{7/2} \sqrt [4]{1-\frac {b x^4}{a}} E\left (\left .\frac {1}{2} \arcsin \left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{39 b^{7/2} \sqrt [4]{a-b x^4}} \] Output:
-4/39*a^2*x^2*(-b*x^4+a)^(3/4)/b^3-10/117*a*x^6*(-b*x^4+a)^(3/4)/b^2-1/13* x^10*(-b*x^4+a)^(3/4)/b+8/39*a^(7/2)*(1-b*x^4/a)^(1/4)*EllipticE(sin(1/2*a rcsin(b^(1/2)*x^2/a^(1/2))),2^(1/2))/b^(7/2)/(-b*x^4+a)^(1/4)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 6.61 (sec) , antiderivative size = 91, normalized size of antiderivative = 0.68 \[ \int \frac {x^{13}}{\sqrt [4]{a-b x^4}} \, dx=\frac {x^2 \left (-12 a^3+2 a^2 b x^4+a b^2 x^8+9 b^3 x^{12}+12 a^3 \sqrt [4]{1-\frac {b x^4}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {3}{2},\frac {b x^4}{a}\right )\right )}{117 b^3 \sqrt [4]{a-b x^4}} \] Input:
Integrate[x^13/(a - b*x^4)^(1/4),x]
Output:
(x^2*(-12*a^3 + 2*a^2*b*x^4 + a*b^2*x^8 + 9*b^3*x^12 + 12*a^3*(1 - (b*x^4) /a)^(1/4)*Hypergeometric2F1[1/4, 1/2, 3/2, (b*x^4)/a]))/(117*b^3*(a - b*x^ 4)^(1/4))
Time = 0.24 (sec) , antiderivative size = 151, normalized size of antiderivative = 1.14, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {807, 262, 262, 262, 227, 226}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^{13}}{\sqrt [4]{a-b x^4}} \, dx\) |
\(\Big \downarrow \) 807 |
\(\displaystyle \frac {1}{2} \int \frac {x^{12}}{\sqrt [4]{a-b x^4}}dx^2\) |
\(\Big \downarrow \) 262 |
\(\displaystyle \frac {1}{2} \left (\frac {10 a \int \frac {x^8}{\sqrt [4]{a-b x^4}}dx^2}{13 b}-\frac {2 x^{10} \left (a-b x^4\right )^{3/4}}{13 b}\right )\) |
\(\Big \downarrow \) 262 |
\(\displaystyle \frac {1}{2} \left (\frac {10 a \left (\frac {2 a \int \frac {x^4}{\sqrt [4]{a-b x^4}}dx^2}{3 b}-\frac {2 x^6 \left (a-b x^4\right )^{3/4}}{9 b}\right )}{13 b}-\frac {2 x^{10} \left (a-b x^4\right )^{3/4}}{13 b}\right )\) |
\(\Big \downarrow \) 262 |
\(\displaystyle \frac {1}{2} \left (\frac {10 a \left (\frac {2 a \left (\frac {2 a \int \frac {1}{\sqrt [4]{a-b x^4}}dx^2}{5 b}-\frac {2 x^2 \left (a-b x^4\right )^{3/4}}{5 b}\right )}{3 b}-\frac {2 x^6 \left (a-b x^4\right )^{3/4}}{9 b}\right )}{13 b}-\frac {2 x^{10} \left (a-b x^4\right )^{3/4}}{13 b}\right )\) |
\(\Big \downarrow \) 227 |
\(\displaystyle \frac {1}{2} \left (\frac {10 a \left (\frac {2 a \left (\frac {2 a \sqrt [4]{1-\frac {b x^4}{a}} \int \frac {1}{\sqrt [4]{1-\frac {b x^4}{a}}}dx^2}{5 b \sqrt [4]{a-b x^4}}-\frac {2 x^2 \left (a-b x^4\right )^{3/4}}{5 b}\right )}{3 b}-\frac {2 x^6 \left (a-b x^4\right )^{3/4}}{9 b}\right )}{13 b}-\frac {2 x^{10} \left (a-b x^4\right )^{3/4}}{13 b}\right )\) |
\(\Big \downarrow \) 226 |
\(\displaystyle \frac {1}{2} \left (\frac {10 a \left (\frac {2 a \left (\frac {4 a^{3/2} \sqrt [4]{1-\frac {b x^4}{a}} E\left (\left .\frac {1}{2} \arcsin \left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{5 b^{3/2} \sqrt [4]{a-b x^4}}-\frac {2 x^2 \left (a-b x^4\right )^{3/4}}{5 b}\right )}{3 b}-\frac {2 x^6 \left (a-b x^4\right )^{3/4}}{9 b}\right )}{13 b}-\frac {2 x^{10} \left (a-b x^4\right )^{3/4}}{13 b}\right )\) |
Input:
Int[x^13/(a - b*x^4)^(1/4),x]
Output:
((-2*x^10*(a - b*x^4)^(3/4))/(13*b) + (10*a*((-2*x^6*(a - b*x^4)^(3/4))/(9 *b) + (2*a*((-2*x^2*(a - b*x^4)^(3/4))/(5*b) + (4*a^(3/2)*(1 - (b*x^4)/a)^ (1/4)*EllipticE[ArcSin[(Sqrt[b]*x^2)/Sqrt[a]]/2, 2])/(5*b^(3/2)*(a - b*x^4 )^(1/4))))/(3*b)))/(13*b))/2
Int[((a_) + (b_.)*(x_)^2)^(-1/4), x_Symbol] :> Simp[(2/(a^(1/4)*Rt[-b/a, 2] ))*EllipticE[(1/2)*ArcSin[Rt[-b/a, 2]*x], 2], x] /; FreeQ[{a, b}, x] && GtQ [a, 0] && NegQ[b/a]
Int[((a_) + (b_.)*(x_)^2)^(-1/4), x_Symbol] :> Simp[(1 + b*(x^2/a))^(1/4)/( a + b*x^2)^(1/4) Int[1/(1 + b*(x^2/a))^(1/4), x], x] /; FreeQ[{a, b}, x] && PosQ[a]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[c*(c*x) ^(m - 1)*((a + b*x^2)^(p + 1)/(b*(m + 2*p + 1))), x] - Simp[a*c^2*((m - 1)/ (b*(m + 2*p + 1))) Int[(c*x)^(m - 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b , c, p}, x] && GtQ[m, 2 - 1] && NeQ[m + 2*p + 1, 0] && IntBinomialQ[a, b, c , 2, m, p, x]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Simp[1/k Subst[Int[x^((m + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]
\[\int \frac {x^{13}}{\left (-b \,x^{4}+a \right )^{\frac {1}{4}}}d x\]
Input:
int(x^13/(-b*x^4+a)^(1/4),x)
Output:
int(x^13/(-b*x^4+a)^(1/4),x)
\[ \int \frac {x^{13}}{\sqrt [4]{a-b x^4}} \, dx=\int { \frac {x^{13}}{{\left (-b x^{4} + a\right )}^{\frac {1}{4}}} \,d x } \] Input:
integrate(x^13/(-b*x^4+a)^(1/4),x, algorithm="fricas")
Output:
integral(-(-b*x^4 + a)^(3/4)*x^13/(b*x^4 - a), x)
Result contains complex when optimal does not.
Time = 0.74 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.22 \[ \int \frac {x^{13}}{\sqrt [4]{a-b x^4}} \, dx=\frac {x^{14} {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {7}{2} \\ \frac {9}{2} \end {matrix}\middle | {\frac {b x^{4} e^{2 i \pi }}{a}} \right )}}{14 \sqrt [4]{a}} \] Input:
integrate(x**13/(-b*x**4+a)**(1/4),x)
Output:
x**14*hyper((1/4, 7/2), (9/2,), b*x**4*exp_polar(2*I*pi)/a)/(14*a**(1/4))
\[ \int \frac {x^{13}}{\sqrt [4]{a-b x^4}} \, dx=\int { \frac {x^{13}}{{\left (-b x^{4} + a\right )}^{\frac {1}{4}}} \,d x } \] Input:
integrate(x^13/(-b*x^4+a)^(1/4),x, algorithm="maxima")
Output:
integrate(x^13/(-b*x^4 + a)^(1/4), x)
\[ \int \frac {x^{13}}{\sqrt [4]{a-b x^4}} \, dx=\int { \frac {x^{13}}{{\left (-b x^{4} + a\right )}^{\frac {1}{4}}} \,d x } \] Input:
integrate(x^13/(-b*x^4+a)^(1/4),x, algorithm="giac")
Output:
integrate(x^13/(-b*x^4 + a)^(1/4), x)
Timed out. \[ \int \frac {x^{13}}{\sqrt [4]{a-b x^4}} \, dx=\int \frac {x^{13}}{{\left (a-b\,x^4\right )}^{1/4}} \,d x \] Input:
int(x^13/(a - b*x^4)^(1/4),x)
Output:
int(x^13/(a - b*x^4)^(1/4), x)
\[ \int \frac {x^{13}}{\sqrt [4]{a-b x^4}} \, dx=\int \frac {x^{13}}{\left (-b \,x^{4}+a \right )^{\frac {1}{4}}}d x \] Input:
int(x^13/(-b*x^4+a)^(1/4),x)
Output:
int(x**13/(a - b*x**4)**(1/4),x)