Integrand size = 13, antiderivative size = 99 \[ \int \frac {x^4}{\left (a+\frac {b}{x}\right )^3} \, dx=\frac {15 b^4 x}{a^7}-\frac {5 b^3 x^2}{a^6}+\frac {2 b^2 x^3}{a^5}-\frac {3 b x^4}{4 a^4}+\frac {x^5}{5 a^3}+\frac {b^7}{2 a^8 (b+a x)^2}-\frac {7 b^6}{a^8 (b+a x)}-\frac {21 b^5 \log (b+a x)}{a^8} \] Output:
15*b^4*x/a^7-5*b^3*x^2/a^6+2*b^2*x^3/a^5-3/4*b*x^4/a^4+1/5*x^5/a^3+1/2*b^7 /a^8/(a*x+b)^2-7*b^6/a^8/(a*x+b)-21*b^5*ln(a*x+b)/a^8
Time = 0.05 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.86 \[ \int \frac {x^4}{\left (a+\frac {b}{x}\right )^3} \, dx=\frac {300 a b^4 x-100 a^2 b^3 x^2+40 a^3 b^2 x^3-15 a^4 b x^4+4 a^5 x^5-\frac {10 b^6 (13 b+14 a x)}{(b+a x)^2}-420 b^5 \log (b+a x)}{20 a^8} \] Input:
Integrate[x^4/(a + b/x)^3,x]
Output:
(300*a*b^4*x - 100*a^2*b^3*x^2 + 40*a^3*b^2*x^3 - 15*a^4*b*x^4 + 4*a^5*x^5 - (10*b^6*(13*b + 14*a*x))/(b + a*x)^2 - 420*b^5*Log[b + a*x])/(20*a^8)
Time = 0.40 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {795, 49, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^4}{\left (a+\frac {b}{x}\right )^3} \, dx\) |
\(\Big \downarrow \) 795 |
\(\displaystyle \int \frac {x^7}{(a x+b)^3}dx\) |
\(\Big \downarrow \) 49 |
\(\displaystyle \int \left (-\frac {b^7}{a^7 (a x+b)^3}+\frac {7 b^6}{a^7 (a x+b)^2}-\frac {21 b^5}{a^7 (a x+b)}+\frac {15 b^4}{a^7}-\frac {10 b^3 x}{a^6}+\frac {6 b^2 x^2}{a^5}-\frac {3 b x^3}{a^4}+\frac {x^4}{a^3}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {b^7}{2 a^8 (a x+b)^2}-\frac {7 b^6}{a^8 (a x+b)}-\frac {21 b^5 \log (a x+b)}{a^8}+\frac {15 b^4 x}{a^7}-\frac {5 b^3 x^2}{a^6}+\frac {2 b^2 x^3}{a^5}-\frac {3 b x^4}{4 a^4}+\frac {x^5}{5 a^3}\) |
Input:
Int[x^4/(a + b/x)^3,x]
Output:
(15*b^4*x)/a^7 - (5*b^3*x^2)/a^6 + (2*b^2*x^3)/a^5 - (3*b*x^4)/(4*a^4) + x ^5/(5*a^3) + b^7/(2*a^8*(b + a*x)^2) - (7*b^6)/(a^8*(b + a*x)) - (21*b^5*L og[b + a*x])/a^8
Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int [ExpandIntegrand[(a + b*x)^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && IGtQ[m, 0] && IGtQ[m + n + 2, 0]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[x^(m + n*p)* (b + a/x^n)^p, x] /; FreeQ[{a, b, m, n}, x] && IntegerQ[p] && NegQ[n]
Time = 0.06 (sec) , antiderivative size = 90, normalized size of antiderivative = 0.91
method | result | size |
risch | \(\frac {x^{5}}{5 a^{3}}-\frac {3 b \,x^{4}}{4 a^{4}}+\frac {2 b^{2} x^{3}}{a^{5}}-\frac {5 b^{3} x^{2}}{a^{6}}+\frac {15 b^{4} x}{a^{7}}+\frac {-7 b^{6} x -\frac {13 b^{7}}{2 a}}{a^{7} \left (a x +b \right )^{2}}-\frac {21 b^{5} \ln \left (a x +b \right )}{a^{8}}\) | \(90\) |
norman | \(\frac {\frac {x^{7}}{5 a}-\frac {7 b \,x^{6}}{20 a^{2}}+\frac {7 b^{2} x^{5}}{10 a^{3}}-\frac {63 b^{7}}{2 a^{8}}-\frac {7 b^{3} x^{4}}{4 a^{4}}+\frac {7 b^{4} x^{3}}{a^{5}}-\frac {42 b^{6} x}{a^{7}}}{\left (a x +b \right )^{2}}-\frac {21 b^{5} \ln \left (a x +b \right )}{a^{8}}\) | \(92\) |
default | \(\frac {\frac {1}{5} a^{4} x^{5}-\frac {3}{4} a^{3} b \,x^{4}+2 a^{2} b^{2} x^{3}-5 a \,b^{3} x^{2}+15 b^{4} x}{a^{7}}-\frac {7 b^{6}}{a^{8} \left (a x +b \right )}-\frac {21 b^{5} \ln \left (a x +b \right )}{a^{8}}+\frac {b^{7}}{2 a^{8} \left (a x +b \right )^{2}}\) | \(94\) |
parallelrisch | \(-\frac {-4 a^{7} x^{7}+7 a^{6} b \,x^{6}-14 a^{5} b^{2} x^{5}+35 a^{4} b^{3} x^{4}+420 \ln \left (a x +b \right ) x^{2} a^{2} b^{5}-140 b^{4} x^{3} a^{3}+840 \ln \left (a x +b \right ) x a \,b^{6}+420 \ln \left (a x +b \right ) b^{7}+840 b^{6} x a +630 b^{7}}{20 a^{8} \left (a x +b \right )^{2}}\) | \(117\) |
Input:
int(x^4/(a+b/x)^3,x,method=_RETURNVERBOSE)
Output:
1/5/a^3*x^5-3/4*b*x^4/a^4+2*b^2*x^3/a^5-5/a^6*b^3*x^2+15*b^4*x/a^7+(-7*b^6 *x-13/2*b^7/a)/a^7/(a*x+b)^2-21*b^5*ln(a*x+b)/a^8
Time = 0.07 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.30 \[ \int \frac {x^4}{\left (a+\frac {b}{x}\right )^3} \, dx=\frac {4 \, a^{7} x^{7} - 7 \, a^{6} b x^{6} + 14 \, a^{5} b^{2} x^{5} - 35 \, a^{4} b^{3} x^{4} + 140 \, a^{3} b^{4} x^{3} + 500 \, a^{2} b^{5} x^{2} + 160 \, a b^{6} x - 130 \, b^{7} - 420 \, {\left (a^{2} b^{5} x^{2} + 2 \, a b^{6} x + b^{7}\right )} \log \left (a x + b\right )}{20 \, {\left (a^{10} x^{2} + 2 \, a^{9} b x + a^{8} b^{2}\right )}} \] Input:
integrate(x^4/(a+b/x)^3,x, algorithm="fricas")
Output:
1/20*(4*a^7*x^7 - 7*a^6*b*x^6 + 14*a^5*b^2*x^5 - 35*a^4*b^3*x^4 + 140*a^3* b^4*x^3 + 500*a^2*b^5*x^2 + 160*a*b^6*x - 130*b^7 - 420*(a^2*b^5*x^2 + 2*a *b^6*x + b^7)*log(a*x + b))/(a^10*x^2 + 2*a^9*b*x + a^8*b^2)
Time = 0.18 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.10 \[ \int \frac {x^4}{\left (a+\frac {b}{x}\right )^3} \, dx=\frac {- 14 a b^{6} x - 13 b^{7}}{2 a^{10} x^{2} + 4 a^{9} b x + 2 a^{8} b^{2}} + \frac {x^{5}}{5 a^{3}} - \frac {3 b x^{4}}{4 a^{4}} + \frac {2 b^{2} x^{3}}{a^{5}} - \frac {5 b^{3} x^{2}}{a^{6}} + \frac {15 b^{4} x}{a^{7}} - \frac {21 b^{5} \log {\left (a x + b \right )}}{a^{8}} \] Input:
integrate(x**4/(a+b/x)**3,x)
Output:
(-14*a*b**6*x - 13*b**7)/(2*a**10*x**2 + 4*a**9*b*x + 2*a**8*b**2) + x**5/ (5*a**3) - 3*b*x**4/(4*a**4) + 2*b**2*x**3/a**5 - 5*b**3*x**2/a**6 + 15*b* *4*x/a**7 - 21*b**5*log(a*x + b)/a**8
Time = 0.03 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.04 \[ \int \frac {x^4}{\left (a+\frac {b}{x}\right )^3} \, dx=-\frac {14 \, a b^{6} x + 13 \, b^{7}}{2 \, {\left (a^{10} x^{2} + 2 \, a^{9} b x + a^{8} b^{2}\right )}} - \frac {21 \, b^{5} \log \left (a x + b\right )}{a^{8}} + \frac {4 \, a^{4} x^{5} - 15 \, a^{3} b x^{4} + 40 \, a^{2} b^{2} x^{3} - 100 \, a b^{3} x^{2} + 300 \, b^{4} x}{20 \, a^{7}} \] Input:
integrate(x^4/(a+b/x)^3,x, algorithm="maxima")
Output:
-1/2*(14*a*b^6*x + 13*b^7)/(a^10*x^2 + 2*a^9*b*x + a^8*b^2) - 21*b^5*log(a *x + b)/a^8 + 1/20*(4*a^4*x^5 - 15*a^3*b*x^4 + 40*a^2*b^2*x^3 - 100*a*b^3* x^2 + 300*b^4*x)/a^7
Time = 0.12 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.96 \[ \int \frac {x^4}{\left (a+\frac {b}{x}\right )^3} \, dx=-\frac {21 \, b^{5} \log \left ({\left | a x + b \right |}\right )}{a^{8}} - \frac {14 \, a b^{6} x + 13 \, b^{7}}{2 \, {\left (a x + b\right )}^{2} a^{8}} + \frac {4 \, a^{12} x^{5} - 15 \, a^{11} b x^{4} + 40 \, a^{10} b^{2} x^{3} - 100 \, a^{9} b^{3} x^{2} + 300 \, a^{8} b^{4} x}{20 \, a^{15}} \] Input:
integrate(x^4/(a+b/x)^3,x, algorithm="giac")
Output:
-21*b^5*log(abs(a*x + b))/a^8 - 1/2*(14*a*b^6*x + 13*b^7)/((a*x + b)^2*a^8 ) + 1/20*(4*a^12*x^5 - 15*a^11*b*x^4 + 40*a^10*b^2*x^3 - 100*a^9*b^3*x^2 + 300*a^8*b^4*x)/a^15
Time = 0.25 (sec) , antiderivative size = 104, normalized size of antiderivative = 1.05 \[ \int \frac {x^4}{\left (a+\frac {b}{x}\right )^3} \, dx=\frac {x^5}{5\,a^3}-\frac {7\,b^6\,x+\frac {13\,b^7}{2\,a}}{a^9\,x^2+2\,a^8\,b\,x+a^7\,b^2}-\frac {21\,b^5\,\ln \left (b+a\,x\right )}{a^8}-\frac {3\,b\,x^4}{4\,a^4}+\frac {15\,b^4\,x}{a^7}+\frac {2\,b^2\,x^3}{a^5}-\frac {5\,b^3\,x^2}{a^6} \] Input:
int(x^4/(a + b/x)^3,x)
Output:
x^5/(5*a^3) - (7*b^6*x + (13*b^7)/(2*a))/(a^7*b^2 + a^9*x^2 + 2*a^8*b*x) - (21*b^5*log(b + a*x))/a^8 - (3*b*x^4)/(4*a^4) + (15*b^4*x)/a^7 + (2*b^2*x ^3)/a^5 - (5*b^3*x^2)/a^6
Time = 0.21 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.32 \[ \int \frac {x^4}{\left (a+\frac {b}{x}\right )^3} \, dx=\frac {-420 \,\mathrm {log}\left (a x +b \right ) a^{2} b^{5} x^{2}-840 \,\mathrm {log}\left (a x +b \right ) a \,b^{6} x -420 \,\mathrm {log}\left (a x +b \right ) b^{7}+4 a^{7} x^{7}-7 a^{6} b \,x^{6}+14 a^{5} b^{2} x^{5}-35 a^{4} b^{3} x^{4}+140 a^{3} b^{4} x^{3}+420 a^{2} b^{5} x^{2}-210 b^{7}}{20 a^{8} \left (a^{2} x^{2}+2 a b x +b^{2}\right )} \] Input:
int(x^4/(a+b/x)^3,x)
Output:
( - 420*log(a*x + b)*a**2*b**5*x**2 - 840*log(a*x + b)*a*b**6*x - 420*log( a*x + b)*b**7 + 4*a**7*x**7 - 7*a**6*b*x**6 + 14*a**5*b**2*x**5 - 35*a**4* b**3*x**4 + 140*a**3*b**4*x**3 + 420*a**2*b**5*x**2 - 210*b**7)/(20*a**8*( a**2*x**2 + 2*a*b*x + b**2))