Integrand size = 15, antiderivative size = 291 \[ \int \sqrt {a+\frac {b}{x^3}} x^7 \, dx=-\frac {21 b^2 \sqrt {a+\frac {b}{x^3}} x^2}{320 a^2}+\frac {3 b \sqrt {a+\frac {b}{x^3}} x^5}{80 a}+\frac {1}{8} \sqrt {a+\frac {b}{x^3}} x^8-\frac {7\ 3^{3/4} \sqrt {2+\sqrt {3}} b^{8/3} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right ) \sqrt {\frac {a^{2/3}+\frac {b^{2/3}}{x^2}-\frac {\sqrt [3]{a} \sqrt [3]{b}}{x}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}\right ),-7-4 \sqrt {3}\right )}{320 a^2 \sqrt {a+\frac {b}{x^3}} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}}} \] Output:
-21/320*b^2*(a+b/x^3)^(1/2)*x^2/a^2+3/80*b*(a+b/x^3)^(1/2)*x^5/a+1/8*(a+b/ x^3)^(1/2)*x^8-7/320*3^(3/4)*(1/2*6^(1/2)+1/2*2^(1/2))*b^(8/3)*(a^(1/3)+b^ (1/3)/x)*((a^(2/3)+b^(2/3)/x^2-a^(1/3)*b^(1/3)/x)/((1+3^(1/2))*a^(1/3)+b^( 1/3)/x)^2)^(1/2)*EllipticF(((1-3^(1/2))*a^(1/3)+b^(1/3)/x)/((1+3^(1/2))*a^ (1/3)+b^(1/3)/x),I*3^(1/2)+2*I)/a^2/(a+b/x^3)^(1/2)/(a^(1/3)*(a^(1/3)+b^(1 /3)/x)/((1+3^(1/2))*a^(1/3)+b^(1/3)/x)^2)^(1/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.06 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.33 \[ \int \sqrt {a+\frac {b}{x^3}} x^7 \, dx=\frac {\sqrt {a+\frac {b}{x^3}} x^2 \left (\sqrt {1+\frac {a x^3}{b}} \left (-7 b^2+3 a b x^3+10 a^2 x^6\right )+7 b^2 \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1}{6},\frac {7}{6},-\frac {a x^3}{b}\right )\right )}{80 a^2 \sqrt {1+\frac {a x^3}{b}}} \] Input:
Integrate[Sqrt[a + b/x^3]*x^7,x]
Output:
(Sqrt[a + b/x^3]*x^2*(Sqrt[1 + (a*x^3)/b]*(-7*b^2 + 3*a*b*x^3 + 10*a^2*x^6 ) + 7*b^2*Hypergeometric2F1[-1/2, 1/6, 7/6, -((a*x^3)/b)]))/(80*a^2*Sqrt[1 + (a*x^3)/b])
Time = 0.56 (sec) , antiderivative size = 302, normalized size of antiderivative = 1.04, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {858, 809, 847, 847, 759}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int x^7 \sqrt {a+\frac {b}{x^3}} \, dx\) |
| \(\Big \downarrow \) 858 |
| \(\displaystyle -\int \sqrt {a+\frac {b}{x^3}} x^9d\frac {1}{x}\) |
| \(\Big \downarrow \) 809 |
| \(\displaystyle \frac {1}{8} x^8 \sqrt {a+\frac {b}{x^3}}-\frac {3}{16} b \int \frac {x^6}{\sqrt {a+\frac {b}{x^3}}}d\frac {1}{x}\) |
| \(\Big \downarrow \) 847 |
| \(\displaystyle \frac {1}{8} x^8 \sqrt {a+\frac {b}{x^3}}-\frac {3}{16} b \left (-\frac {7 b \int \frac {x^3}{\sqrt {a+\frac {b}{x^3}}}d\frac {1}{x}}{10 a}-\frac {x^5 \sqrt {a+\frac {b}{x^3}}}{5 a}\right )\) |
| \(\Big \downarrow \) 847 |
| \(\displaystyle \frac {1}{8} x^8 \sqrt {a+\frac {b}{x^3}}-\frac {3}{16} b \left (-\frac {7 b \left (-\frac {b \int \frac {1}{\sqrt {a+\frac {b}{x^3}}}d\frac {1}{x}}{4 a}-\frac {x^2 \sqrt {a+\frac {b}{x^3}}}{2 a}\right )}{10 a}-\frac {x^5 \sqrt {a+\frac {b}{x^3}}}{5 a}\right )\) |
| \(\Big \downarrow \) 759 |
| \(\displaystyle \frac {1}{8} x^8 \sqrt {a+\frac {b}{x^3}}-\frac {3}{16} b \left (-\frac {7 b \left (-\frac {\sqrt {2+\sqrt {3}} b^{2/3} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right ) \sqrt {\frac {a^{2/3}-\frac {\sqrt [3]{a} \sqrt [3]{b}}{x}+\frac {b^{2/3}}{x^2}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}}\right ),-7-4 \sqrt {3}\right )}{2 \sqrt [4]{3} a \sqrt {a+\frac {b}{x^3}} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b}}{x}\right )^2}}}-\frac {x^2 \sqrt {a+\frac {b}{x^3}}}{2 a}\right )}{10 a}-\frac {x^5 \sqrt {a+\frac {b}{x^3}}}{5 a}\right )\) |
Input:
Int[Sqrt[a + b/x^3]*x^7,x]
Output:
(Sqrt[a + b/x^3]*x^8)/8 - (3*b*(-1/5*(Sqrt[a + b/x^3]*x^5)/a - (7*b*(-1/2* (Sqrt[a + b/x^3]*x^2)/a - (Sqrt[2 + Sqrt[3]]*b^(2/3)*(a^(1/3) + b^(1/3)/x) *Sqrt[(a^(2/3) + b^(2/3)/x^2 - (a^(1/3)*b^(1/3))/x)/((1 + Sqrt[3])*a^(1/3) + b^(1/3)/x)^2]*EllipticF[ArcSin[((1 - Sqrt[3])*a^(1/3) + b^(1/3)/x)/((1 + Sqrt[3])*a^(1/3) + b^(1/3)/x)], -7 - 4*Sqrt[3]])/(2*3^(1/4)*a*Sqrt[a + b /x^3]*Sqrt[(a^(1/3)*(a^(1/3) + b^(1/3)/x))/((1 + Sqrt[3])*a^(1/3) + b^(1/3 )/x)^2])))/(10*a)))/16
Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt[2 + Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s *x + r^2*x^2)/((1 + Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[s* ((s + r*x)/((1 + Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 - Sqrt[3])*s + r*x)/((1 + Sqrt[3])*s + r*x)], -7 - 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x] & & PosQ[a]
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c* x)^(m + 1)*((a + b*x^n)^p/(c*(m + 1))), x] - Simp[b*n*(p/(c^n*(m + 1))) I nt[(c*x)^(m + n)*(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c}, x] && IGtQ [n, 0] && GtQ[p, 0] && LtQ[m, -1] && !ILtQ[(m + n*p + n + 1)/n, 0] && IntB inomialQ[a, b, c, n, m, p, x]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c*x )^(m + 1)*((a + b*x^n)^(p + 1)/(a*c*(m + 1))), x] - Simp[b*((m + n*(p + 1) + 1)/(a*c^n*(m + 1))) Int[(c*x)^(m + n)*(a + b*x^n)^p, x], x] /; FreeQ[{a , b, c, p}, x] && IGtQ[n, 0] && LtQ[m, -1] && IntBinomialQ[a, b, c, n, m, p , x]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Subst[Int[(a + b/x^n)^p/x^(m + 2), x], x, 1/x] /; FreeQ[{a, b, p}, x] && ILtQ[n, 0] && Int egerQ[m]
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 752 vs. \(2 (224 ) = 448\).
Time = 1.57 (sec) , antiderivative size = 753, normalized size of antiderivative = 2.59
| method | result | size |
| risch | \(\frac {\left (40 a^{2} x^{6}+12 a b \,x^{3}-21 b^{2}\right ) x^{2} \sqrt {\frac {a \,x^{3}+b}{x^{3}}}}{320 a^{2}}+\frac {21 b^{3} \left (\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}-\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) \sqrt {\frac {\left (-\frac {3 \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) x}{\left (-\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) \left (x -\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{a}\right )}}\, {\left (x -\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{a}\right )}^{2} \sqrt {\frac {\left (-a^{2} b \right )^{\frac {1}{3}} \left (x +\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right )}{a \left (-\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}-\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) \left (x -\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{a}\right )}}\, \sqrt {\frac {\left (-a^{2} b \right )^{\frac {1}{3}} \left (x +\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}-\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right )}{a \left (-\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) \left (x -\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{a}\right )}}\, \operatorname {EllipticF}\left (\sqrt {\frac {\left (-\frac {3 \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) x}{\left (-\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) \left (x -\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{a}\right )}}, \sqrt {\frac {\left (\frac {3 \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) \left (\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}-\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right )}{\left (\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) \left (\frac {3 \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}-\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right )}}\right ) \sqrt {\frac {a \,x^{3}+b}{x^{3}}}\, x \sqrt {x \left (a \,x^{3}+b \right )}}{320 a \left (-\frac {3 \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) \left (-a^{2} b \right )^{\frac {1}{3}} \sqrt {a x \left (x -\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{a}\right ) \left (x +\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}+\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right ) \left (x +\frac {\left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}-\frac {i \sqrt {3}\, \left (-a^{2} b \right )^{\frac {1}{3}}}{2 a}\right )}\, \left (a \,x^{3}+b \right )}\) | \(753\) |
| default | \(\text {Expression too large to display}\) | \(2226\) |
Input:
int((a+b/x^3)^(1/2)*x^7,x,method=_RETURNVERBOSE)
Output:
1/320*(40*a^2*x^6+12*a*b*x^3-21*b^2)/a^2*x^2*((a*x^3+b)/x^3)^(1/2)+21/320/ a*b^3*(1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*((-3/2/a*(-a^2 *b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*x/(-1/2/a*(-a^2*b)^(1/3)+1/2*I*3 ^(1/2)/a*(-a^2*b)^(1/3))/(x-1/a*(-a^2*b)^(1/3)))^(1/2)*(x-1/a*(-a^2*b)^(1/ 3))^2*(1/a*(-a^2*b)^(1/3)*(x+1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b) ^(1/3))/(-1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(x-1/a*(-a^ 2*b)^(1/3)))^(1/2)*(1/a*(-a^2*b)^(1/3)*(x+1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/ 2)/a*(-a^2*b)^(1/3))/(-1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3) )/(x-1/a*(-a^2*b)^(1/3)))^(1/2)/(-3/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a ^2*b)^(1/3))/(-a^2*b)^(1/3)/(a*x*(x-1/a*(-a^2*b)^(1/3))*(x+1/2/a*(-a^2*b)^ (1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))*(x+1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2 )/a*(-a^2*b)^(1/3)))^(1/2)*EllipticF(((-3/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2) /a*(-a^2*b)^(1/3))*x/(-1/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3) )/(x-1/a*(-a^2*b)^(1/3)))^(1/2),((3/2/a*(-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a ^2*b)^(1/3))*(1/2/a*(-a^2*b)^(1/3)-1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(1/2/a* (-a^2*b)^(1/3)+1/2*I*3^(1/2)/a*(-a^2*b)^(1/3))/(3/2/a*(-a^2*b)^(1/3)-1/2*I *3^(1/2)/a*(-a^2*b)^(1/3)))^(1/2))*((a*x^3+b)/x^3)^(1/2)*x*(x*(a*x^3+b))^( 1/2)/(a*x^3+b)
\[ \int \sqrt {a+\frac {b}{x^3}} x^7 \, dx=\int { \sqrt {a + \frac {b}{x^{3}}} x^{7} \,d x } \] Input:
integrate((a+b/x^3)^(1/2)*x^7,x, algorithm="fricas")
Output:
integral(x^7*sqrt((a*x^3 + b)/x^3), x)
Time = 0.89 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.16 \[ \int \sqrt {a+\frac {b}{x^3}} x^7 \, dx=- \frac {\sqrt {a} x^{8} \Gamma \left (- \frac {8}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {8}{3}, - \frac {1}{2} \\ - \frac {5}{3} \end {matrix}\middle | {\frac {b e^{i \pi }}{a x^{3}}} \right )}}{3 \Gamma \left (- \frac {5}{3}\right )} \] Input:
integrate((a+b/x**3)**(1/2)*x**7,x)
Output:
-sqrt(a)*x**8*gamma(-8/3)*hyper((-8/3, -1/2), (-5/3,), b*exp_polar(I*pi)/( a*x**3))/(3*gamma(-5/3))
\[ \int \sqrt {a+\frac {b}{x^3}} x^7 \, dx=\int { \sqrt {a + \frac {b}{x^{3}}} x^{7} \,d x } \] Input:
integrate((a+b/x^3)^(1/2)*x^7,x, algorithm="maxima")
Output:
integrate(sqrt(a + b/x^3)*x^7, x)
\[ \int \sqrt {a+\frac {b}{x^3}} x^7 \, dx=\int { \sqrt {a + \frac {b}{x^{3}}} x^{7} \,d x } \] Input:
integrate((a+b/x^3)^(1/2)*x^7,x, algorithm="giac")
Output:
integrate(sqrt(a + b/x^3)*x^7, x)
Timed out. \[ \int \sqrt {a+\frac {b}{x^3}} x^7 \, dx=\int x^7\,\sqrt {a+\frac {b}{x^3}} \,d x \] Input:
int(x^7*(a + b/x^3)^(1/2),x)
Output:
int(x^7*(a + b/x^3)^(1/2), x)
\[ \int \sqrt {a+\frac {b}{x^3}} x^7 \, dx=\frac {80 \sqrt {x}\, \sqrt {a \,x^{3}+b}\, a^{2} x^{6}+24 \sqrt {x}\, \sqrt {a \,x^{3}+b}\, a b \,x^{3}-42 \sqrt {x}\, \sqrt {a \,x^{3}+b}\, b^{2}+21 \left (\int \frac {\sqrt {x}\, \sqrt {a \,x^{3}+b}}{a \,x^{4}+b x}d x \right ) b^{3}}{640 a^{2}} \] Input:
int((a+b/x^3)^(1/2)*x^7,x)
Output:
(80*sqrt(x)*sqrt(a*x**3 + b)*a**2*x**6 + 24*sqrt(x)*sqrt(a*x**3 + b)*a*b*x **3 - 42*sqrt(x)*sqrt(a*x**3 + b)*b**2 + 21*int((sqrt(x)*sqrt(a*x**3 + b)) /(a*x**4 + b*x),x)*b**3)/(640*a**2)