\(\int \frac {(c x)^{-1-\frac {2 n}{3}}}{a+b x^n} \, dx\) [659]

Optimal result
Mathematica [C] (verified)
Rubi [A] (verified)
Maple [F]
Fricas [A] (verification not implemented)
Sympy [C] (verification not implemented)
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 21, antiderivative size = 222 \[ \int \frac {(c x)^{-1-\frac {2 n}{3}}}{a+b x^n} \, dx=-\frac {3 (c x)^{-2 n/3}}{2 a c n}+\frac {\sqrt {3} b^{2/3} x^{2 n/3} (c x)^{-2 n/3} \arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x^{n/3}}{\sqrt {3} \sqrt [3]{a}}\right )}{a^{5/3} c n}-\frac {b^{2/3} x^{2 n/3} (c x)^{-2 n/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x^{n/3}\right )}{a^{5/3} c n}+\frac {b^{2/3} x^{2 n/3} (c x)^{-2 n/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}\right )}{2 a^{5/3} c n} \] Output:

-3/2/a/c/n/((c*x)^(2/3*n))+3^(1/2)*b^(2/3)*x^(2/3*n)*arctan(1/3*(a^(1/3)-2 
*b^(1/3)*x^(1/3*n))*3^(1/2)/a^(1/3))/a^(5/3)/c/n/((c*x)^(2/3*n))-b^(2/3)*x 
^(2/3*n)*ln(a^(1/3)+b^(1/3)*x^(1/3*n))/a^(5/3)/c/n/((c*x)^(2/3*n))+1/2*b^( 
2/3)*x^(2/3*n)*ln(a^(2/3)-a^(1/3)*b^(1/3)*x^(1/3*n)+b^(2/3)*x^(2/3*n))/a^( 
5/3)/c/n/((c*x)^(2/3*n))
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.01 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.18 \[ \int \frac {(c x)^{-1-\frac {2 n}{3}}}{a+b x^n} \, dx=-\frac {3 x (c x)^{-1-\frac {2 n}{3}} \operatorname {Hypergeometric2F1}\left (-\frac {2}{3},1,\frac {1}{3},-\frac {b x^n}{a}\right )}{2 a n} \] Input:

Integrate[(c*x)^(-1 - (2*n)/3)/(a + b*x^n),x]
 

Output:

(-3*x*(c*x)^(-1 - (2*n)/3)*Hypergeometric2F1[-2/3, 1, 1/3, -((b*x^n)/a)])/ 
(2*a*n)
 

Rubi [A] (verified)

Time = 0.59 (sec) , antiderivative size = 180, normalized size of antiderivative = 0.81, number of steps used = 12, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.524, Rules used = {887, 886, 868, 750, 16, 1142, 25, 27, 1082, 217, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(c x)^{-\frac {2 n}{3}-1}}{a+b x^n} \, dx\)

\(\Big \downarrow \) 887

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \int \frac {x^{-\frac {2 n}{3}-1}}{b x^n+a}dx}{c}\)

\(\Big \downarrow \) 886

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {b \int \frac {x^{\frac {n-3}{3}}}{b x^n+a}dx}{a}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

\(\Big \downarrow \) 868

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {3 b \int \frac {1}{b x^n+a}dx^{n/3}}{a n}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

\(\Big \downarrow \) 750

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {3 b \left (\frac {\int \frac {2 \sqrt [3]{a}-\sqrt [3]{b} x^{n/3}}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}}{3 a^{2/3}}+\frac {\int \frac {1}{\sqrt [3]{b} x^{n/3}+\sqrt [3]{a}}dx^{n/3}}{3 a^{2/3}}\right )}{a n}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

\(\Big \downarrow \) 16

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {3 b \left (\frac {\int \frac {2 \sqrt [3]{a}-\sqrt [3]{b} x^{n/3}}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}}{3 a^{2/3}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x^{n/3}\right )}{3 a^{2/3} \sqrt [3]{b}}\right )}{a n}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

\(\Big \downarrow \) 1142

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {3 b \left (\frac {\frac {3}{2} \sqrt [3]{a} \int \frac {1}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}-\frac {\int -\frac {\sqrt [3]{b} \left (\sqrt [3]{a}-2 \sqrt [3]{b} x^{n/3}\right )}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}}{2 \sqrt [3]{b}}}{3 a^{2/3}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x^{n/3}\right )}{3 a^{2/3} \sqrt [3]{b}}\right )}{a n}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {3 b \left (\frac {\frac {3}{2} \sqrt [3]{a} \int \frac {1}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}+\frac {\int \frac {\sqrt [3]{b} \left (\sqrt [3]{a}-2 \sqrt [3]{b} x^{n/3}\right )}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}}{2 \sqrt [3]{b}}}{3 a^{2/3}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x^{n/3}\right )}{3 a^{2/3} \sqrt [3]{b}}\right )}{a n}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {3 b \left (\frac {\frac {3}{2} \sqrt [3]{a} \int \frac {1}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}+\frac {1}{2} \int \frac {\sqrt [3]{a}-2 \sqrt [3]{b} x^{n/3}}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}}{3 a^{2/3}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x^{n/3}\right )}{3 a^{2/3} \sqrt [3]{b}}\right )}{a n}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

\(\Big \downarrow \) 1082

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {3 b \left (\frac {\frac {1}{2} \int \frac {\sqrt [3]{a}-2 \sqrt [3]{b} x^{n/3}}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}+\frac {3 \int \frac {1}{-x^{2 n/3}-3}d\left (1-\frac {2 \sqrt [3]{b} x^{n/3}}{\sqrt [3]{a}}\right )}{\sqrt [3]{b}}}{3 a^{2/3}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x^{n/3}\right )}{3 a^{2/3} \sqrt [3]{b}}\right )}{a n}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {3 b \left (\frac {\frac {1}{2} \int \frac {\sqrt [3]{a}-2 \sqrt [3]{b} x^{n/3}}{-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}+a^{2/3}}dx^{n/3}-\frac {\sqrt {3} \arctan \left (\frac {1-\frac {2 \sqrt [3]{b} x^{n/3}}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{\sqrt [3]{b}}}{3 a^{2/3}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x^{n/3}\right )}{3 a^{2/3} \sqrt [3]{b}}\right )}{a n}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {x^{2 n/3} (c x)^{-2 n/3} \left (-\frac {3 b \left (\frac {-\frac {\log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x^{n/3}+b^{2/3} x^{2 n/3}\right )}{2 \sqrt [3]{b}}-\frac {\sqrt {3} \arctan \left (\frac {1-\frac {2 \sqrt [3]{b} x^{n/3}}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{\sqrt [3]{b}}}{3 a^{2/3}}+\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x^{n/3}\right )}{3 a^{2/3} \sqrt [3]{b}}\right )}{a n}-\frac {3 x^{-2 n/3}}{2 a n}\right )}{c}\)

Input:

Int[(c*x)^(-1 - (2*n)/3)/(a + b*x^n),x]
 

Output:

(x^((2*n)/3)*(-3/(2*a*n*x^((2*n)/3)) - (3*b*(Log[a^(1/3) + b^(1/3)*x^(n/3) 
]/(3*a^(2/3)*b^(1/3)) + (-((Sqrt[3]*ArcTan[(1 - (2*b^(1/3)*x^(n/3))/a^(1/3 
))/Sqrt[3]])/b^(1/3)) - Log[a^(2/3) - a^(1/3)*b^(1/3)*x^(n/3) + b^(2/3)*x^ 
((2*n)/3)]/(2*b^(1/3)))/(3*a^(2/3))))/(a*n)))/(c*(c*x)^((2*n)/3))
 

Defintions of rubi rules used

rule 16
Int[(c_.)/((a_.) + (b_.)*(x_)), x_Symbol] :> Simp[c*(Log[RemoveContent[a + 
b*x, x]]/b), x] /; FreeQ[{a, b, c}, x]
 

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 750
Int[((a_) + (b_.)*(x_)^3)^(-1), x_Symbol] :> Simp[1/(3*Rt[a, 3]^2)   Int[1/ 
(Rt[a, 3] + Rt[b, 3]*x), x], x] + Simp[1/(3*Rt[a, 3]^2)   Int[(2*Rt[a, 3] - 
 Rt[b, 3]*x)/(Rt[a, 3]^2 - Rt[a, 3]*Rt[b, 3]*x + Rt[b, 3]^2*x^2), x], x] /; 
 FreeQ[{a, b}, x]
 

rule 868
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[1/(m + 1) 
 Subst[Int[(a + b*x^Simplify[n/(m + 1)])^p, x], x, x^(m + 1)], x] /; FreeQ[ 
{a, b, m, n, p}, x] && IntegerQ[Simplify[n/(m + 1)]] &&  !IntegerQ[n]
 

rule 886
Int[(x_)^(m_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[x^(m + 1)/(a*(m + 
 1)), x] - Simp[b/a   Int[x^Simplify[m + n]/(a + b*x^n), x], x] /; FreeQ[{a 
, b, m, n}, x] && FractionQ[Simplify[(m + 1)/n]] && SumSimplerQ[m, n]
 

rule 887
Int[((c_)*(x_))^(m_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[c^IntPart[ 
m]*((c*x)^FracPart[m]/x^FracPart[m])   Int[x^m/(a + b*x^n), x], x] /; FreeQ 
[{a, b, c, m, n}, x] && FractionQ[Simplify[(m + 1)/n]] && (SumSimplerQ[m, n 
] || SumSimplerQ[m, -n])
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1142
Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[(2*c*d - b*e)/(2*c)   Int[1/(a + b*x + c*x^2), x], x] + Simp[e/(2*c) 
Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x]
 
Maple [F]

\[\int \frac {\left (c x \right )^{-1-\frac {2 n}{3}}}{a +b \,x^{n}}d x\]

Input:

int((c*x)^(-1-2/3*n)/(a+b*x^n),x)
 

Output:

int((c*x)^(-1-2/3*n)/(a+b*x^n),x)
 

Fricas [A] (verification not implemented)

Time = 0.28 (sec) , antiderivative size = 329, normalized size of antiderivative = 1.48 \[ \int \frac {(c x)^{-1-\frac {2 n}{3}}}{a+b x^n} \, dx=-\frac {3 \, x e^{\left (-\frac {1}{3} \, {\left (2 \, n + 3\right )} \log \left (c\right ) - \frac {1}{3} \, {\left (2 \, n + 3\right )} \log \left (x\right )\right )} - 2 \, \sqrt {3} \left (-\frac {b^{2} c^{-2 \, n - 3}}{a^{2}}\right )^{\frac {1}{3}} \arctan \left (\frac {2 \, \sqrt {3} a \left (-\frac {b^{2} c^{-2 \, n - 3}}{a^{2}}\right )^{\frac {1}{3}} \sqrt {x} e^{\left (-\frac {1}{6} \, {\left (2 \, n + 3\right )} \log \left (c\right ) - \frac {1}{6} \, {\left (2 \, n + 3\right )} \log \left (x\right )\right )} + \sqrt {3} b c^{-n - \frac {3}{2}}}{3 \, b c^{-n - \frac {3}{2}}}\right ) - 2 \, \left (-\frac {b^{2} c^{-2 \, n - 3}}{a^{2}}\right )^{\frac {1}{3}} \log \left (\frac {b c^{-n - \frac {3}{2}} x e^{\left (-\frac {1}{6} \, {\left (2 \, n + 3\right )} \log \left (c\right ) - \frac {1}{6} \, {\left (2 \, n + 3\right )} \log \left (x\right )\right )} + a \left (-\frac {b^{2} c^{-2 \, n - 3}}{a^{2}}\right )^{\frac {2}{3}} \sqrt {x}}{x}\right ) + \left (-\frac {b^{2} c^{-2 \, n - 3}}{a^{2}}\right )^{\frac {1}{3}} \log \left (\frac {b c^{-n - \frac {3}{2}} x e^{\left (-\frac {1}{3} \, {\left (2 \, n + 3\right )} \log \left (c\right ) - \frac {1}{3} \, {\left (2 \, n + 3\right )} \log \left (x\right )\right )} - a \left (-\frac {b^{2} c^{-2 \, n - 3}}{a^{2}}\right )^{\frac {2}{3}} \sqrt {x} e^{\left (-\frac {1}{6} \, {\left (2 \, n + 3\right )} \log \left (c\right ) - \frac {1}{6} \, {\left (2 \, n + 3\right )} \log \left (x\right )\right )} - b c^{-n - \frac {3}{2}} \left (-\frac {b^{2} c^{-2 \, n - 3}}{a^{2}}\right )^{\frac {1}{3}}}{x}\right )}{2 \, a n} \] Input:

integrate((c*x)^(-1-2/3*n)/(a+b*x^n),x, algorithm="fricas")
 

Output:

-1/2*(3*x*e^(-1/3*(2*n + 3)*log(c) - 1/3*(2*n + 3)*log(x)) - 2*sqrt(3)*(-b 
^2*c^(-2*n - 3)/a^2)^(1/3)*arctan(1/3*(2*sqrt(3)*a*(-b^2*c^(-2*n - 3)/a^2) 
^(1/3)*sqrt(x)*e^(-1/6*(2*n + 3)*log(c) - 1/6*(2*n + 3)*log(x)) + sqrt(3)* 
b*c^(-n - 3/2))/(b*c^(-n - 3/2))) - 2*(-b^2*c^(-2*n - 3)/a^2)^(1/3)*log((b 
*c^(-n - 3/2)*x*e^(-1/6*(2*n + 3)*log(c) - 1/6*(2*n + 3)*log(x)) + a*(-b^2 
*c^(-2*n - 3)/a^2)^(2/3)*sqrt(x))/x) + (-b^2*c^(-2*n - 3)/a^2)^(1/3)*log(( 
b*c^(-n - 3/2)*x*e^(-1/3*(2*n + 3)*log(c) - 1/3*(2*n + 3)*log(x)) - a*(-b^ 
2*c^(-2*n - 3)/a^2)^(2/3)*sqrt(x)*e^(-1/6*(2*n + 3)*log(c) - 1/6*(2*n + 3) 
*log(x)) - b*c^(-n - 3/2)*(-b^2*c^(-2*n - 3)/a^2)^(1/3))/x))/(a*n)
 

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 1.21 (sec) , antiderivative size = 233, normalized size of antiderivative = 1.05 \[ \int \frac {(c x)^{-1-\frac {2 n}{3}}}{a+b x^n} \, dx=\frac {c^{- \frac {2 n}{3} - 1} x^{- \frac {2 n}{3}} \Gamma \left (- \frac {2}{3}\right )}{a n \Gamma \left (\frac {1}{3}\right )} - \frac {2 b^{\frac {2}{3}} c^{- \frac {2 n}{3} - 1} e^{- \frac {i \pi }{3}} \log {\left (1 - \frac {\sqrt [3]{b} x^{\frac {n}{3}} e^{\frac {i \pi }{3}}}{\sqrt [3]{a}} \right )} \Gamma \left (- \frac {2}{3}\right )}{3 a^{\frac {5}{3}} n \Gamma \left (\frac {1}{3}\right )} + \frac {2 b^{\frac {2}{3}} c^{- \frac {2 n}{3} - 1} \log {\left (1 - \frac {\sqrt [3]{b} x^{\frac {n}{3}} e^{i \pi }}{\sqrt [3]{a}} \right )} \Gamma \left (- \frac {2}{3}\right )}{3 a^{\frac {5}{3}} n \Gamma \left (\frac {1}{3}\right )} - \frac {2 b^{\frac {2}{3}} c^{- \frac {2 n}{3} - 1} e^{\frac {i \pi }{3}} \log {\left (1 - \frac {\sqrt [3]{b} x^{\frac {n}{3}} e^{\frac {5 i \pi }{3}}}{\sqrt [3]{a}} \right )} \Gamma \left (- \frac {2}{3}\right )}{3 a^{\frac {5}{3}} n \Gamma \left (\frac {1}{3}\right )} \] Input:

integrate((c*x)**(-1-2/3*n)/(a+b*x**n),x)
 

Output:

c**(-2*n/3 - 1)*gamma(-2/3)/(a*n*x**(2*n/3)*gamma(1/3)) - 2*b**(2/3)*c**(- 
2*n/3 - 1)*exp(-I*pi/3)*log(1 - b**(1/3)*x**(n/3)*exp_polar(I*pi/3)/a**(1/ 
3))*gamma(-2/3)/(3*a**(5/3)*n*gamma(1/3)) + 2*b**(2/3)*c**(-2*n/3 - 1)*log 
(1 - b**(1/3)*x**(n/3)*exp_polar(I*pi)/a**(1/3))*gamma(-2/3)/(3*a**(5/3)*n 
*gamma(1/3)) - 2*b**(2/3)*c**(-2*n/3 - 1)*exp(I*pi/3)*log(1 - b**(1/3)*x** 
(n/3)*exp_polar(5*I*pi/3)/a**(1/3))*gamma(-2/3)/(3*a**(5/3)*n*gamma(1/3))
                                                                                    
                                                                                    
 

Maxima [F]

\[ \int \frac {(c x)^{-1-\frac {2 n}{3}}}{a+b x^n} \, dx=\int { \frac {\left (c x\right )^{-\frac {2}{3} \, n - 1}}{b x^{n} + a} \,d x } \] Input:

integrate((c*x)^(-1-2/3*n)/(a+b*x^n),x, algorithm="maxima")
 

Output:

-b*integrate(x^(1/3*n)/(a*b*c^(2/3*n + 1)*x*x^n + a^2*c^(2/3*n + 1)*x), x) 
 - 3/2*c^(-2/3*n - 1)/(a*n*x^(2/3*n))
 

Giac [F]

\[ \int \frac {(c x)^{-1-\frac {2 n}{3}}}{a+b x^n} \, dx=\int { \frac {\left (c x\right )^{-\frac {2}{3} \, n - 1}}{b x^{n} + a} \,d x } \] Input:

integrate((c*x)^(-1-2/3*n)/(a+b*x^n),x, algorithm="giac")
 

Output:

integrate((c*x)^(-2/3*n - 1)/(b*x^n + a), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {(c x)^{-1-\frac {2 n}{3}}}{a+b x^n} \, dx=\int \frac {1}{{\left (c\,x\right )}^{\frac {2\,n}{3}+1}\,\left (a+b\,x^n\right )} \,d x \] Input:

int(1/((c*x)^((2*n)/3 + 1)*(a + b*x^n)),x)
 

Output:

int(1/((c*x)^((2*n)/3 + 1)*(a + b*x^n)), x)
 

Reduce [F]

\[ \int \frac {(c x)^{-1-\frac {2 n}{3}}}{a+b x^n} \, dx=\frac {\int \frac {1}{x^{\frac {5 n}{3}} b x +x^{\frac {2 n}{3}} a x}d x}{c^{\frac {2 n}{3}} c} \] Input:

int((c*x)^(-1-2/3*n)/(a+b*x^n),x)
 

Output:

int(1/(x**((5*n)/3)*b*x + x**((2*n)/3)*a*x),x)/(c**((2*n)/3)*c)