\(\int (e x)^{3/2} (a+b x^3)^{5/2} (A+B x^3) \, dx\) [259]

Optimal result
Mathematica [C] (verified)
Rubi [A] (verified)
Maple [C] (verified)
Fricas [F]
Sympy [C] (verification not implemented)
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 26, antiderivative size = 661 \[ \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx=\frac {27 a^2 (26 A b-5 a B) (e x)^{5/2} \sqrt {a+b x^3}}{5824 b e}+\frac {81 \left (1+\sqrt {3}\right ) a^3 (26 A b-5 a B) e \sqrt {e x} \sqrt {a+b x^3}}{11648 b^{5/3} \left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )}+\frac {3 a (26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{3/2}}{728 b e}+\frac {(26 A b-5 a B) (e x)^{5/2} \left (a+b x^3\right )^{5/2}}{260 b e}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}-\frac {81 \sqrt [4]{3} a^{10/3} (26 A b-5 a B) e \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} E\left (\arccos \left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{11648 b^{5/3} \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {27\ 3^{3/4} \left (1-\sqrt {3}\right ) a^{10/3} (26 A b-5 a B) e \sqrt {e x} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{23296 b^{5/3} \sqrt {\frac {\sqrt [3]{b} x \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}} \] Output:

27/5824*a^2*(26*A*b-5*B*a)*(e*x)^(5/2)*(b*x^3+a)^(1/2)/b/e+81/11648*(1+3^( 
1/2))*a^3*(26*A*b-5*B*a)*e*(e*x)^(1/2)*(b*x^3+a)^(1/2)/b^(5/3)/(a^(1/3)+(1 
+3^(1/2))*b^(1/3)*x)+3/728*a*(26*A*b-5*B*a)*(e*x)^(5/2)*(b*x^3+a)^(3/2)/b/ 
e+1/260*(26*A*b-5*B*a)*(e*x)^(5/2)*(b*x^3+a)^(5/2)/b/e+1/13*B*(e*x)^(5/2)* 
(b*x^3+a)^(7/2)/b/e-81/11648*3^(1/4)*a^(10/3)*(26*A*b-5*B*a)*e*(e*x)^(1/2) 
*(a^(1/3)+b^(1/3)*x)*((a^(2/3)-a^(1/3)*b^(1/3)*x+b^(2/3)*x^2)/(a^(1/3)+(1+ 
3^(1/2))*b^(1/3)*x)^2)^(1/2)*EllipticE((1-(a^(1/3)+(1-3^(1/2))*b^(1/3)*x)^ 
2/(a^(1/3)+(1+3^(1/2))*b^(1/3)*x)^2)^(1/2),1/4*6^(1/2)+1/4*2^(1/2))/b^(5/3 
)/(b^(1/3)*x*(a^(1/3)+b^(1/3)*x)/(a^(1/3)+(1+3^(1/2))*b^(1/3)*x)^2)^(1/2)/ 
(b*x^3+a)^(1/2)-27/23296*3^(3/4)*(1-3^(1/2))*a^(10/3)*(26*A*b-5*B*a)*e*(e* 
x)^(1/2)*(a^(1/3)+b^(1/3)*x)*((a^(2/3)-a^(1/3)*b^(1/3)*x+b^(2/3)*x^2)/(a^( 
1/3)+(1+3^(1/2))*b^(1/3)*x)^2)^(1/2)*InverseJacobiAM(arccos((a^(1/3)+(1-3^ 
(1/2))*b^(1/3)*x)/(a^(1/3)+(1+3^(1/2))*b^(1/3)*x)),1/4*6^(1/2)+1/4*2^(1/2) 
)/b^(5/3)/(b^(1/3)*x*(a^(1/3)+b^(1/3)*x)/(a^(1/3)+(1+3^(1/2))*b^(1/3)*x)^2 
)^(1/2)/(b*x^3+a)^(1/2)
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.17 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.15 \[ \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx=\frac {x (e x)^{3/2} \sqrt {a+b x^3} \left (5 B \left (a+b x^3\right )^3 \sqrt {1+\frac {b x^3}{a}}+a^2 (26 A b-5 a B) \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},\frac {5}{6},\frac {11}{6},-\frac {b x^3}{a}\right )\right )}{65 b \sqrt {1+\frac {b x^3}{a}}} \] Input:

Integrate[(e*x)^(3/2)*(a + b*x^3)^(5/2)*(A + B*x^3),x]
 

Output:

(x*(e*x)^(3/2)*Sqrt[a + b*x^3]*(5*B*(a + b*x^3)^3*Sqrt[1 + (b*x^3)/a] + a^ 
2*(26*A*b - 5*a*B)*Hypergeometric2F1[-5/2, 5/6, 11/6, -((b*x^3)/a)]))/(65* 
b*Sqrt[1 + (b*x^3)/a])
 

Rubi [A] (verified)

Time = 1.29 (sec) , antiderivative size = 687, normalized size of antiderivative = 1.04, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.346, Rules used = {959, 811, 811, 811, 851, 837, 25, 766, 2420}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx\)

\(\Big \downarrow \) 959

\(\displaystyle \frac {(26 A b-5 a B) \int (e x)^{3/2} \left (b x^3+a\right )^{5/2}dx}{26 b}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}\)

\(\Big \downarrow \) 811

\(\displaystyle \frac {(26 A b-5 a B) \left (\frac {3}{4} a \int (e x)^{3/2} \left (b x^3+a\right )^{3/2}dx+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{26 b}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}\)

\(\Big \downarrow \) 811

\(\displaystyle \frac {(26 A b-5 a B) \left (\frac {3}{4} a \left (\frac {9}{14} a \int (e x)^{3/2} \sqrt {b x^3+a}dx+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{26 b}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}\)

\(\Big \downarrow \) 811

\(\displaystyle \frac {(26 A b-5 a B) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3}{8} a \int \frac {(e x)^{3/2}}{\sqrt {b x^3+a}}dx+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{26 b}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}\)

\(\Big \downarrow \) 851

\(\displaystyle \frac {(26 A b-5 a B) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \int \frac {e^2 x^2}{\sqrt {b x^3+a}}d\sqrt {e x}}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{26 b}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}\)

\(\Big \downarrow \) 837

\(\displaystyle \frac {(26 A b-5 a B) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \left (-\frac {\left (1-\sqrt {3}\right ) a^{2/3} e^2 \int \frac {1}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}-\frac {\int -\frac {2 b^{2/3} x^2 e^2+\left (1-\sqrt {3}\right ) a^{2/3} e^2}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}\right )}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{26 b}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {(26 A b-5 a B) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \left (\frac {\int \frac {2 b^{2/3} x^2 e^2+\left (1-\sqrt {3}\right ) a^{2/3} e^2}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}-\frac {\left (1-\sqrt {3}\right ) a^{2/3} e^2 \int \frac {1}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}\right )}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{26 b}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}\)

\(\Big \downarrow \) 766

\(\displaystyle \frac {(26 A b-5 a B) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \left (\frac {\int \frac {2 b^{2/3} x^2 e^2+\left (1-\sqrt {3}\right ) a^{2/3} e^2}{\sqrt {b x^3+a}}d\sqrt {e x}}{2 b^{2/3}}-\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a} e \sqrt {e x} \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right ) \sqrt {\frac {a^{2/3} e^2-\sqrt [3]{a} \sqrt [3]{b} e^2 x+b^{2/3} e^2 x^2}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{4 \sqrt [4]{3} b^{2/3} \sqrt {a+b x^3} \sqrt {\frac {\sqrt [3]{b} e x \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right )}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}}}\right )}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{26 b}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}\)

\(\Big \downarrow \) 2420

\(\displaystyle \frac {(26 A b-5 a B) \left (\frac {3}{4} a \left (\frac {9}{14} a \left (\frac {3 a \left (\frac {\frac {\left (1+\sqrt {3}\right ) e^3 \sqrt {e x} \sqrt {a+b x^3}}{\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x}-\frac {\sqrt [4]{3} \sqrt [3]{a} e \sqrt {e x} \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right ) \sqrt {\frac {a^{2/3} e^2-\sqrt [3]{a} \sqrt [3]{b} e^2 x+b^{2/3} e^2 x^2}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}} E\left (\arccos \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{\sqrt {a+b x^3} \sqrt {\frac {\sqrt [3]{b} e x \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right )}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}}}}{2 b^{2/3}}-\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a} e \sqrt {e x} \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right ) \sqrt {\frac {a^{2/3} e^2-\sqrt [3]{a} \sqrt [3]{b} e^2 x+b^{2/3} e^2 x^2}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x e+\sqrt [3]{a} e}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{4 \sqrt [4]{3} b^{2/3} \sqrt {a+b x^3} \sqrt {\frac {\sqrt [3]{b} e x \left (\sqrt [3]{a} e+\sqrt [3]{b} e x\right )}{\left (\sqrt [3]{a} e+\left (1+\sqrt {3}\right ) \sqrt [3]{b} e x\right )^2}}}\right )}{4 e}+\frac {(e x)^{5/2} \sqrt {a+b x^3}}{4 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{3/2}}{7 e}\right )+\frac {(e x)^{5/2} \left (a+b x^3\right )^{5/2}}{10 e}\right )}{26 b}+\frac {B (e x)^{5/2} \left (a+b x^3\right )^{7/2}}{13 b e}\)

Input:

Int[(e*x)^(3/2)*(a + b*x^3)^(5/2)*(A + B*x^3),x]
 

Output:

(B*(e*x)^(5/2)*(a + b*x^3)^(7/2))/(13*b*e) + ((26*A*b - 5*a*B)*(((e*x)^(5/ 
2)*(a + b*x^3)^(5/2))/(10*e) + (3*a*(((e*x)^(5/2)*(a + b*x^3)^(3/2))/(7*e) 
 + (9*a*(((e*x)^(5/2)*Sqrt[a + b*x^3])/(4*e) + (3*a*((((1 + Sqrt[3])*e^3*S 
qrt[e*x]*Sqrt[a + b*x^3])/(a^(1/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x) - (3^(1/ 
4)*a^(1/3)*e*Sqrt[e*x]*(a^(1/3)*e + b^(1/3)*e*x)*Sqrt[(a^(2/3)*e^2 - a^(1/ 
3)*b^(1/3)*e^2*x + b^(2/3)*e^2*x^2)/(a^(1/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x 
)^2]*EllipticE[ArcCos[(a^(1/3)*e + (1 - Sqrt[3])*b^(1/3)*e*x)/(a^(1/3)*e + 
 (1 + Sqrt[3])*b^(1/3)*e*x)], (2 + Sqrt[3])/4])/(Sqrt[(b^(1/3)*e*x*(a^(1/3 
)*e + b^(1/3)*e*x))/(a^(1/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x)^2]*Sqrt[a + b* 
x^3]))/(2*b^(2/3)) - ((1 - Sqrt[3])*a^(1/3)*e*Sqrt[e*x]*(a^(1/3)*e + b^(1/ 
3)*e*x)*Sqrt[(a^(2/3)*e^2 - a^(1/3)*b^(1/3)*e^2*x + b^(2/3)*e^2*x^2)/(a^(1 
/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x)^2]*EllipticF[ArcCos[(a^(1/3)*e + (1 - S 
qrt[3])*b^(1/3)*e*x)/(a^(1/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x)], (2 + Sqrt[3 
])/4])/(4*3^(1/4)*b^(2/3)*Sqrt[(b^(1/3)*e*x*(a^(1/3)*e + b^(1/3)*e*x))/(a^ 
(1/3)*e + (1 + Sqrt[3])*b^(1/3)*e*x)^2]*Sqrt[a + b*x^3])))/(4*e)))/14))/4) 
)/(26*b)
 

Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 766
Int[1/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], 
s = Denom[Rt[b/a, 3]]}, Simp[x*(s + r*x^2)*(Sqrt[(s^2 - r*s*x^2 + r^2*x^4)/ 
(s + (1 + Sqrt[3])*r*x^2)^2]/(2*3^(1/4)*s*Sqrt[a + b*x^6]*Sqrt[r*x^2*((s + 
r*x^2)/(s + (1 + Sqrt[3])*r*x^2)^2)]))*EllipticF[ArcCos[(s + (1 - Sqrt[3])* 
r*x^2)/(s + (1 + Sqrt[3])*r*x^2)], (2 + Sqrt[3])/4], x]] /; FreeQ[{a, b}, x 
]
 

rule 811
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c* 
x)^(m + 1)*((a + b*x^n)^p/(c*(m + n*p + 1))), x] + Simp[a*n*(p/(m + n*p + 1 
))   Int[(c*x)^m*(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c, m}, x] && I 
GtQ[n, 0] && GtQ[p, 0] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b, c, n, m 
, p, x]
 

rule 837
Int[(x_)^4/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = Numer[Rt[b/a, 
3]], s = Denom[Rt[b/a, 3]]}, Simp[(Sqrt[3] - 1)*(s^2/(2*r^2))   Int[1/Sqrt[ 
a + b*x^6], x], x] - Simp[1/(2*r^2)   Int[((Sqrt[3] - 1)*s^2 - 2*r^2*x^4)/S 
qrt[a + b*x^6], x], x]] /; FreeQ[{a, b}, x]
 

rule 851
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = 
 Denominator[m]}, Simp[k/c   Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(k*n)/c^ 
n))^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && 
FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]
 

rule 959
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n 
_)), x_Symbol] :> Simp[d*(e*x)^(m + 1)*((a + b*x^n)^(p + 1)/(b*e*(m + n*(p 
+ 1) + 1))), x] - Simp[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(b*(m + n*(p 
 + 1) + 1))   Int[(e*x)^m*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, m, 
 n, p}, x] && NeQ[b*c - a*d, 0] && NeQ[m + n*(p + 1) + 1, 0]
 

rule 2420
Int[((c_) + (d_.)*(x_)^4)/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = 
 Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[(1 + Sqrt[3])*d*s^3*x*(Sqr 
t[a + b*x^6]/(2*a*r^2*(s + (1 + Sqrt[3])*r*x^2))), x] - Simp[3^(1/4)*d*s*x* 
(s + r*x^2)*(Sqrt[(s^2 - r*s*x^2 + r^2*x^4)/(s + (1 + Sqrt[3])*r*x^2)^2]/(2 
*r^2*Sqrt[(r*x^2*(s + r*x^2))/(s + (1 + Sqrt[3])*r*x^2)^2]*Sqrt[a + b*x^6]) 
)*EllipticE[ArcCos[(s + (1 - Sqrt[3])*r*x^2)/(s + (1 + Sqrt[3])*r*x^2)], (2 
 + Sqrt[3])/4], x]] /; FreeQ[{a, b, c, d}, x] && EqQ[2*Rt[b/a, 3]^2*c - (1 
- Sqrt[3])*d, 0]
 
Maple [C] (verified)

Result contains complex when optimal does not.

Time = 6.38 (sec) , antiderivative size = 1188, normalized size of antiderivative = 1.80

method result size
risch \(\text {Expression too large to display}\) \(1188\)
elliptic \(\text {Expression too large to display}\) \(1410\)
default \(\text {Expression too large to display}\) \(6202\)

Input:

int((e*x)^(3/2)*(b*x^3+a)^(5/2)*(B*x^3+A),x,method=_RETURNVERBOSE)
 

Output:

1/29120/b*x^3*(2240*B*b^3*x^9+2912*A*b^3*x^6+6160*B*a*b^2*x^6+8944*A*a*b^2 
*x^3+5000*B*a^2*b*x^3+9542*A*a^2*b+405*B*a^3)*(b*x^3+a)^(1/2)*e^2/(e*x)^(1 
/2)+81/11648*a^3/b*(26*A*b-5*B*a)*(x*(x+1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2) 
/b*(-a*b^2)^(1/3))*(x+1/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3)) 
+(1/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*((-3/2/b*(-a*b^2)^( 
1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*x/(-1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2 
)/b*(-a*b^2)^(1/3))/(x-1/b*(-a*b^2)^(1/3)))^(1/2)*(x-1/b*(-a*b^2)^(1/3))^2 
*(1/b*(-a*b^2)^(1/3)*(x+1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3 
))/(-1/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(x-1/b*(-a*b^2)^ 
(1/3)))^(1/2)*(1/b*(-a*b^2)^(1/3)*(x+1/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b* 
(-a*b^2)^(1/3))/(-1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(x- 
1/b*(-a*b^2)^(1/3)))^(1/2)*(((-1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^ 
2)^(1/3))/b*(-a*b^2)^(1/3)+1/b^2*(-a*b^2)^(2/3))/(-3/2/b*(-a*b^2)^(1/3)+1/ 
2*I*3^(1/2)/b*(-a*b^2)^(1/3))*b/(-a*b^2)^(1/3)*EllipticF(((-3/2/b*(-a*b^2) 
^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*x/(-1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1 
/2)/b*(-a*b^2)^(1/3))/(x-1/b*(-a*b^2)^(1/3)))^(1/2),((3/2/b*(-a*b^2)^(1/3) 
+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*(1/2/b*(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a 
*b^2)^(1/3))/(1/2/b*(-a*b^2)^(1/3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))/(3/2/b* 
(-a*b^2)^(1/3)-1/2*I*3^(1/2)/b*(-a*b^2)^(1/3)))^(1/2))+(1/2/b*(-a*b^2)^(1/ 
3)+1/2*I*3^(1/2)/b*(-a*b^2)^(1/3))*EllipticE(((-3/2/b*(-a*b^2)^(1/3)+1/...
 

Fricas [F]

\[ \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx=\int { {\left (B x^{3} + A\right )} {\left (b x^{3} + a\right )}^{\frac {5}{2}} \left (e x\right )^{\frac {3}{2}} \,d x } \] Input:

integrate((e*x)^(3/2)*(b*x^3+a)^(5/2)*(B*x^3+A),x, algorithm="fricas")
 

Output:

integral((B*b^2*e*x^10 + (2*B*a*b + A*b^2)*e*x^7 + (B*a^2 + 2*A*a*b)*e*x^4 
 + A*a^2*e*x)*sqrt(b*x^3 + a)*sqrt(e*x), x)
 

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 54.81 (sec) , antiderivative size = 308, normalized size of antiderivative = 0.47 \[ \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx=\frac {A a^{\frac {5}{2}} e^{\frac {3}{2}} x^{\frac {5}{2}} \Gamma \left (\frac {5}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {5}{6} \\ \frac {11}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {11}{6}\right )} + \frac {2 A a^{\frac {3}{2}} b e^{\frac {3}{2}} x^{\frac {11}{2}} \Gamma \left (\frac {11}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {11}{6} \\ \frac {17}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {17}{6}\right )} + \frac {A \sqrt {a} b^{2} e^{\frac {3}{2}} x^{\frac {17}{2}} \Gamma \left (\frac {17}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {17}{6} \\ \frac {23}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {23}{6}\right )} + \frac {B a^{\frac {5}{2}} e^{\frac {3}{2}} x^{\frac {11}{2}} \Gamma \left (\frac {11}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {11}{6} \\ \frac {17}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {17}{6}\right )} + \frac {2 B a^{\frac {3}{2}} b e^{\frac {3}{2}} x^{\frac {17}{2}} \Gamma \left (\frac {17}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {17}{6} \\ \frac {23}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {23}{6}\right )} + \frac {B \sqrt {a} b^{2} e^{\frac {3}{2}} x^{\frac {23}{2}} \Gamma \left (\frac {23}{6}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {23}{6} \\ \frac {29}{6} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {29}{6}\right )} \] Input:

integrate((e*x)**(3/2)*(b*x**3+a)**(5/2)*(B*x**3+A),x)
 

Output:

A*a**(5/2)*e**(3/2)*x**(5/2)*gamma(5/6)*hyper((-1/2, 5/6), (11/6,), b*x**3 
*exp_polar(I*pi)/a)/(3*gamma(11/6)) + 2*A*a**(3/2)*b*e**(3/2)*x**(11/2)*ga 
mma(11/6)*hyper((-1/2, 11/6), (17/6,), b*x**3*exp_polar(I*pi)/a)/(3*gamma( 
17/6)) + A*sqrt(a)*b**2*e**(3/2)*x**(17/2)*gamma(17/6)*hyper((-1/2, 17/6), 
 (23/6,), b*x**3*exp_polar(I*pi)/a)/(3*gamma(23/6)) + B*a**(5/2)*e**(3/2)* 
x**(11/2)*gamma(11/6)*hyper((-1/2, 11/6), (17/6,), b*x**3*exp_polar(I*pi)/ 
a)/(3*gamma(17/6)) + 2*B*a**(3/2)*b*e**(3/2)*x**(17/2)*gamma(17/6)*hyper(( 
-1/2, 17/6), (23/6,), b*x**3*exp_polar(I*pi)/a)/(3*gamma(23/6)) + B*sqrt(a 
)*b**2*e**(3/2)*x**(23/2)*gamma(23/6)*hyper((-1/2, 23/6), (29/6,), b*x**3* 
exp_polar(I*pi)/a)/(3*gamma(29/6))
 

Maxima [F]

\[ \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx=\int { {\left (B x^{3} + A\right )} {\left (b x^{3} + a\right )}^{\frac {5}{2}} \left (e x\right )^{\frac {3}{2}} \,d x } \] Input:

integrate((e*x)^(3/2)*(b*x^3+a)^(5/2)*(B*x^3+A),x, algorithm="maxima")
 

Output:

integrate((B*x^3 + A)*(b*x^3 + a)^(5/2)*(e*x)^(3/2), x)
 

Giac [F]

\[ \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx=\int { {\left (B x^{3} + A\right )} {\left (b x^{3} + a\right )}^{\frac {5}{2}} \left (e x\right )^{\frac {3}{2}} \,d x } \] Input:

integrate((e*x)^(3/2)*(b*x^3+a)^(5/2)*(B*x^3+A),x, algorithm="giac")
 

Output:

integrate((B*x^3 + A)*(b*x^3 + a)^(5/2)*(e*x)^(3/2), x)
 

Mupad [F(-1)]

Timed out. \[ \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx=\int \left (B\,x^3+A\right )\,{\left (e\,x\right )}^{3/2}\,{\left (b\,x^3+a\right )}^{5/2} \,d x \] Input:

int((A + B*x^3)*(e*x)^(3/2)*(a + b*x^3)^(5/2),x)
                                                                                    
                                                                                    
 

Output:

int((A + B*x^3)*(e*x)^(3/2)*(a + b*x^3)^(5/2), x)
 

Reduce [F]

\[ \int (e x)^{3/2} \left (a+b x^3\right )^{5/2} \left (A+B x^3\right ) \, dx=\frac {\sqrt {e}\, e \left (2842 \sqrt {x}\, \sqrt {b \,x^{3}+a}\, a^{3} x^{2}+3984 \sqrt {x}\, \sqrt {b \,x^{3}+a}\, a^{2} b \,x^{5}+2592 \sqrt {x}\, \sqrt {b \,x^{3}+a}\, a \,b^{2} x^{8}+640 \sqrt {x}\, \sqrt {b \,x^{3}+a}\, b^{3} x^{11}+1215 \left (\int \frac {\sqrt {x}\, \sqrt {b \,x^{3}+a}\, x}{b \,x^{3}+a}d x \right ) a^{4}\right )}{8320} \] Input:

int((e*x)^(3/2)*(b*x^3+a)^(5/2)*(B*x^3+A),x)
 

Output:

(sqrt(e)*e*(2842*sqrt(x)*sqrt(a + b*x**3)*a**3*x**2 + 3984*sqrt(x)*sqrt(a 
+ b*x**3)*a**2*b*x**5 + 2592*sqrt(x)*sqrt(a + b*x**3)*a*b**2*x**8 + 640*sq 
rt(x)*sqrt(a + b*x**3)*b**3*x**11 + 1215*int((sqrt(x)*sqrt(a + b*x**3)*x)/ 
(a + b*x**3),x)*a**4))/8320