Integrand size = 20, antiderivative size = 113 \[ \int \frac {\left (a+b x^3\right )^5 \left (A+B x^3\right )}{x^9} \, dx=-\frac {a^5 A}{8 x^8}-\frac {a^4 (5 A b+a B)}{5 x^5}-\frac {5 a^3 b (2 A b+a B)}{2 x^2}+10 a^2 b^2 (A b+a B) x+\frac {5}{4} a b^3 (A b+2 a B) x^4+\frac {1}{7} b^4 (A b+5 a B) x^7+\frac {1}{10} b^5 B x^{10} \] Output:
-1/8*a^5*A/x^8-1/5*a^4*(5*A*b+B*a)/x^5-5/2*a^3*b*(2*A*b+B*a)/x^2+10*a^2*b^ 2*(A*b+B*a)*x+5/4*a*b^3*(A*b+2*B*a)*x^4+1/7*b^4*(A*b+5*B*a)*x^7+1/10*b^5*B *x^10
Time = 0.04 (sec) , antiderivative size = 113, normalized size of antiderivative = 1.00 \[ \int \frac {\left (a+b x^3\right )^5 \left (A+B x^3\right )}{x^9} \, dx=-\frac {a^5 A}{8 x^8}-\frac {a^4 (5 A b+a B)}{5 x^5}-\frac {5 a^3 b (2 A b+a B)}{2 x^2}+10 a^2 b^2 (A b+a B) x+\frac {5}{4} a b^3 (A b+2 a B) x^4+\frac {1}{7} b^4 (A b+5 a B) x^7+\frac {1}{10} b^5 B x^{10} \] Input:
Integrate[((a + b*x^3)^5*(A + B*x^3))/x^9,x]
Output:
-1/8*(a^5*A)/x^8 - (a^4*(5*A*b + a*B))/(5*x^5) - (5*a^3*b*(2*A*b + a*B))/( 2*x^2) + 10*a^2*b^2*(A*b + a*B)*x + (5*a*b^3*(A*b + 2*a*B)*x^4)/4 + (b^4*( A*b + 5*a*B)*x^7)/7 + (b^5*B*x^10)/10
Time = 0.42 (sec) , antiderivative size = 113, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {950, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\left (a+b x^3\right )^5 \left (A+B x^3\right )}{x^9} \, dx\) |
\(\Big \downarrow \) 950 |
\(\displaystyle \int \left (\frac {a^5 A}{x^9}+\frac {a^4 (a B+5 A b)}{x^6}+\frac {5 a^3 b (a B+2 A b)}{x^3}+10 a^2 b^2 (a B+A b)+b^4 x^6 (5 a B+A b)+5 a b^3 x^3 (2 a B+A b)+b^5 B x^9\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -\frac {a^5 A}{8 x^8}-\frac {a^4 (a B+5 A b)}{5 x^5}-\frac {5 a^3 b (a B+2 A b)}{2 x^2}+10 a^2 b^2 x (a B+A b)+\frac {1}{7} b^4 x^7 (5 a B+A b)+\frac {5}{4} a b^3 x^4 (2 a B+A b)+\frac {1}{10} b^5 B x^{10}\) |
Input:
Int[((a + b*x^3)^5*(A + B*x^3))/x^9,x]
Output:
-1/8*(a^5*A)/x^8 - (a^4*(5*A*b + a*B))/(5*x^5) - (5*a^3*b*(2*A*b + a*B))/( 2*x^2) + 10*a^2*b^2*(A*b + a*B)*x + (5*a*b^3*(A*b + 2*a*B)*x^4)/4 + (b^4*( A*b + 5*a*B)*x^7)/7 + (b^5*B*x^10)/10
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n _))^(q_.), x_Symbol] :> Int[ExpandIntegrand[(e*x)^m*(a + b*x^n)^p*(c + d*x^ n)^q, x], x] /; FreeQ[{a, b, c, d, e, m, n}, x] && NeQ[b*c - a*d, 0] && IGt Q[p, 0] && IGtQ[q, 0]
Time = 0.57 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.01
method | result | size |
default | \(\frac {b^{5} B \,x^{10}}{10}+\frac {A \,b^{5} x^{7}}{7}+\frac {5 B a \,b^{4} x^{7}}{7}+\frac {5 a A \,b^{4} x^{4}}{4}+\frac {5 B \,a^{2} b^{3} x^{4}}{2}+10 A \,a^{2} b^{3} x +10 B \,a^{3} b^{2} x -\frac {a^{4} \left (5 A b +B a \right )}{5 x^{5}}-\frac {5 a^{3} b \left (2 A b +B a \right )}{2 x^{2}}-\frac {a^{5} A}{8 x^{8}}\) | \(114\) |
norman | \(\frac {-\frac {a^{5} A}{8}+\left (-a^{4} b A -\frac {1}{5} a^{5} B \right ) x^{3}+\left (-5 a^{3} b^{2} A -\frac {5}{2} a^{4} b B \right ) x^{6}+\left (10 a^{2} b^{3} A +10 a^{3} b^{2} B \right ) x^{9}+\left (\frac {5}{4} a \,b^{4} A +\frac {5}{2} a^{2} b^{3} B \right ) x^{12}+\left (\frac {1}{7} b^{5} A +\frac {5}{7} a \,b^{4} B \right ) x^{15}+\frac {b^{5} B \,x^{18}}{10}}{x^{8}}\) | \(122\) |
risch | \(\frac {b^{5} B \,x^{10}}{10}+\frac {A \,b^{5} x^{7}}{7}+\frac {5 B a \,b^{4} x^{7}}{7}+\frac {5 a A \,b^{4} x^{4}}{4}+\frac {5 B \,a^{2} b^{3} x^{4}}{2}+10 A \,a^{2} b^{3} x +10 B \,a^{3} b^{2} x +\frac {\left (-5 a^{3} b^{2} A -\frac {5}{2} a^{4} b B \right ) x^{6}+\left (-a^{4} b A -\frac {1}{5} a^{5} B \right ) x^{3}-\frac {a^{5} A}{8}}{x^{8}}\) | \(122\) |
gosper | \(-\frac {-28 b^{5} B \,x^{18}-40 A \,b^{5} x^{15}-200 B a \,b^{4} x^{15}-350 a A \,b^{4} x^{12}-700 B \,a^{2} b^{3} x^{12}-2800 a^{2} A \,b^{3} x^{9}-2800 B \,a^{3} b^{2} x^{9}+1400 a^{3} A \,b^{2} x^{6}+700 B \,a^{4} b \,x^{6}+280 a^{4} A b \,x^{3}+56 B \,a^{5} x^{3}+35 a^{5} A}{280 x^{8}}\) | \(128\) |
parallelrisch | \(\frac {28 b^{5} B \,x^{18}+40 A \,b^{5} x^{15}+200 B a \,b^{4} x^{15}+350 a A \,b^{4} x^{12}+700 B \,a^{2} b^{3} x^{12}+2800 a^{2} A \,b^{3} x^{9}+2800 B \,a^{3} b^{2} x^{9}-1400 a^{3} A \,b^{2} x^{6}-700 B \,a^{4} b \,x^{6}-280 a^{4} A b \,x^{3}-56 B \,a^{5} x^{3}-35 a^{5} A}{280 x^{8}}\) | \(128\) |
orering | \(-\frac {-28 b^{5} B \,x^{18}-40 A \,b^{5} x^{15}-200 B a \,b^{4} x^{15}-350 a A \,b^{4} x^{12}-700 B \,a^{2} b^{3} x^{12}-2800 a^{2} A \,b^{3} x^{9}-2800 B \,a^{3} b^{2} x^{9}+1400 a^{3} A \,b^{2} x^{6}+700 B \,a^{4} b \,x^{6}+280 a^{4} A b \,x^{3}+56 B \,a^{5} x^{3}+35 a^{5} A}{280 x^{8}}\) | \(128\) |
Input:
int((b*x^3+a)^5*(B*x^3+A)/x^9,x,method=_RETURNVERBOSE)
Output:
1/10*b^5*B*x^10+1/7*A*b^5*x^7+5/7*B*a*b^4*x^7+5/4*a*A*b^4*x^4+5/2*B*a^2*b^ 3*x^4+10*A*a^2*b^3*x+10*B*a^3*b^2*x-1/5*a^4*(5*A*b+B*a)/x^5-5/2*a^3*b*(2*A *b+B*a)/x^2-1/8*a^5*A/x^8
Time = 0.08 (sec) , antiderivative size = 121, normalized size of antiderivative = 1.07 \[ \int \frac {\left (a+b x^3\right )^5 \left (A+B x^3\right )}{x^9} \, dx=\frac {28 \, B b^{5} x^{18} + 40 \, {\left (5 \, B a b^{4} + A b^{5}\right )} x^{15} + 350 \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x^{12} + 2800 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} x^{9} - 700 \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{6} - 35 \, A a^{5} - 56 \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x^{3}}{280 \, x^{8}} \] Input:
integrate((b*x^3+a)^5*(B*x^3+A)/x^9,x, algorithm="fricas")
Output:
1/280*(28*B*b^5*x^18 + 40*(5*B*a*b^4 + A*b^5)*x^15 + 350*(2*B*a^2*b^3 + A* a*b^4)*x^12 + 2800*(B*a^3*b^2 + A*a^2*b^3)*x^9 - 700*(B*a^4*b + 2*A*a^3*b^ 2)*x^6 - 35*A*a^5 - 56*(B*a^5 + 5*A*a^4*b)*x^3)/x^8
Time = 0.64 (sec) , antiderivative size = 133, normalized size of antiderivative = 1.18 \[ \int \frac {\left (a+b x^3\right )^5 \left (A+B x^3\right )}{x^9} \, dx=\frac {B b^{5} x^{10}}{10} + x^{7} \left (\frac {A b^{5}}{7} + \frac {5 B a b^{4}}{7}\right ) + x^{4} \cdot \left (\frac {5 A a b^{4}}{4} + \frac {5 B a^{2} b^{3}}{2}\right ) + x \left (10 A a^{2} b^{3} + 10 B a^{3} b^{2}\right ) + \frac {- 5 A a^{5} + x^{6} \left (- 200 A a^{3} b^{2} - 100 B a^{4} b\right ) + x^{3} \left (- 40 A a^{4} b - 8 B a^{5}\right )}{40 x^{8}} \] Input:
integrate((b*x**3+a)**5*(B*x**3+A)/x**9,x)
Output:
B*b**5*x**10/10 + x**7*(A*b**5/7 + 5*B*a*b**4/7) + x**4*(5*A*a*b**4/4 + 5* B*a**2*b**3/2) + x*(10*A*a**2*b**3 + 10*B*a**3*b**2) + (-5*A*a**5 + x**6*( -200*A*a**3*b**2 - 100*B*a**4*b) + x**3*(-40*A*a**4*b - 8*B*a**5))/(40*x** 8)
Time = 0.03 (sec) , antiderivative size = 120, normalized size of antiderivative = 1.06 \[ \int \frac {\left (a+b x^3\right )^5 \left (A+B x^3\right )}{x^9} \, dx=\frac {1}{10} \, B b^{5} x^{10} + \frac {1}{7} \, {\left (5 \, B a b^{4} + A b^{5}\right )} x^{7} + \frac {5}{4} \, {\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x^{4} + 10 \, {\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} x - \frac {100 \, {\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{6} + 5 \, A a^{5} + 8 \, {\left (B a^{5} + 5 \, A a^{4} b\right )} x^{3}}{40 \, x^{8}} \] Input:
integrate((b*x^3+a)^5*(B*x^3+A)/x^9,x, algorithm="maxima")
Output:
1/10*B*b^5*x^10 + 1/7*(5*B*a*b^4 + A*b^5)*x^7 + 5/4*(2*B*a^2*b^3 + A*a*b^4 )*x^4 + 10*(B*a^3*b^2 + A*a^2*b^3)*x - 1/40*(100*(B*a^4*b + 2*A*a^3*b^2)*x ^6 + 5*A*a^5 + 8*(B*a^5 + 5*A*a^4*b)*x^3)/x^8
Time = 0.12 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.10 \[ \int \frac {\left (a+b x^3\right )^5 \left (A+B x^3\right )}{x^9} \, dx=\frac {1}{10} \, B b^{5} x^{10} + \frac {5}{7} \, B a b^{4} x^{7} + \frac {1}{7} \, A b^{5} x^{7} + \frac {5}{2} \, B a^{2} b^{3} x^{4} + \frac {5}{4} \, A a b^{4} x^{4} + 10 \, B a^{3} b^{2} x + 10 \, A a^{2} b^{3} x - \frac {100 \, B a^{4} b x^{6} + 200 \, A a^{3} b^{2} x^{6} + 8 \, B a^{5} x^{3} + 40 \, A a^{4} b x^{3} + 5 \, A a^{5}}{40 \, x^{8}} \] Input:
integrate((b*x^3+a)^5*(B*x^3+A)/x^9,x, algorithm="giac")
Output:
1/10*B*b^5*x^10 + 5/7*B*a*b^4*x^7 + 1/7*A*b^5*x^7 + 5/2*B*a^2*b^3*x^4 + 5/ 4*A*a*b^4*x^4 + 10*B*a^3*b^2*x + 10*A*a^2*b^3*x - 1/40*(100*B*a^4*b*x^6 + 200*A*a^3*b^2*x^6 + 8*B*a^5*x^3 + 40*A*a^4*b*x^3 + 5*A*a^5)/x^8
Time = 0.05 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.98 \[ \int \frac {\left (a+b x^3\right )^5 \left (A+B x^3\right )}{x^9} \, dx=x^7\,\left (\frac {A\,b^5}{7}+\frac {5\,B\,a\,b^4}{7}\right )-\frac {\frac {A\,a^5}{8}+x^6\,\left (\frac {5\,B\,a^4\,b}{2}+5\,A\,a^3\,b^2\right )+x^3\,\left (\frac {B\,a^5}{5}+A\,b\,a^4\right )}{x^8}+\frac {B\,b^5\,x^{10}}{10}+10\,a^2\,b^2\,x\,\left (A\,b+B\,a\right )+\frac {5\,a\,b^3\,x^4\,\left (A\,b+2\,B\,a\right )}{4} \] Input:
int(((A + B*x^3)*(a + b*x^3)^5)/x^9,x)
Output:
x^7*((A*b^5)/7 + (5*B*a*b^4)/7) - ((A*a^5)/8 + x^6*(5*A*a^3*b^2 + (5*B*a^4 *b)/2) + x^3*((B*a^5)/5 + A*a^4*b))/x^8 + (B*b^5*x^10)/10 + 10*a^2*b^2*x*( A*b + B*a) + (5*a*b^3*x^4*(A*b + 2*B*a))/4
Time = 0.22 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.62 \[ \int \frac {\left (a+b x^3\right )^5 \left (A+B x^3\right )}{x^9} \, dx=\frac {28 b^{6} x^{18}+240 a \,b^{5} x^{15}+1050 a^{2} b^{4} x^{12}+5600 a^{3} b^{3} x^{9}-2100 a^{4} b^{2} x^{6}-336 a^{5} b \,x^{3}-35 a^{6}}{280 x^{8}} \] Input:
int((b*x^3+a)^5*(B*x^3+A)/x^9,x)
Output:
( - 35*a**6 - 336*a**5*b*x**3 - 2100*a**4*b**2*x**6 + 5600*a**3*b**3*x**9 + 1050*a**2*b**4*x**12 + 240*a*b**5*x**15 + 28*b**6*x**18)/(280*x**8)