Integrand size = 26, antiderivative size = 88 \[ \int \frac {x^3}{\sqrt {a+b x^3} \sqrt {c+d x^3}} \, dx=\frac {x^4 \sqrt {1+\frac {b x^3}{a}} \sqrt {1+\frac {d x^3}{c}} \operatorname {AppellF1}\left (\frac {4}{3},\frac {1}{2},\frac {1}{2},\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )}{4 \sqrt {a+b x^3} \sqrt {c+d x^3}} \] Output:
1/4*x^4*(1+b*x^3/a)^(1/2)*(1+d*x^3/c)^(1/2)*AppellF1(4/3,1/2,1/2,7/3,-b*x^ 3/a,-d*x^3/c)/(b*x^3+a)^(1/2)/(d*x^3+c)^(1/2)
Time = 1.82 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.02 \[ \int \frac {x^3}{\sqrt {a+b x^3} \sqrt {c+d x^3}} \, dx=\frac {x^4 \sqrt {\frac {a+b x^3}{a}} \sqrt {\frac {c+d x^3}{c}} \operatorname {AppellF1}\left (\frac {4}{3},\frac {1}{2},\frac {1}{2},\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )}{4 \sqrt {a+b x^3} \sqrt {c+d x^3}} \] Input:
Integrate[x^3/(Sqrt[a + b*x^3]*Sqrt[c + d*x^3]),x]
Output:
(x^4*Sqrt[(a + b*x^3)/a]*Sqrt[(c + d*x^3)/c]*AppellF1[4/3, 1/2, 1/2, 7/3, -((b*x^3)/a), -((d*x^3)/c)])/(4*Sqrt[a + b*x^3]*Sqrt[c + d*x^3])
Time = 0.43 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {1013, 1013, 1012}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^3}{\sqrt {a+b x^3} \sqrt {c+d x^3}} \, dx\) |
\(\Big \downarrow \) 1013 |
\(\displaystyle \frac {\sqrt {\frac {b x^3}{a}+1} \int \frac {x^3}{\sqrt {\frac {b x^3}{a}+1} \sqrt {d x^3+c}}dx}{\sqrt {a+b x^3}}\) |
\(\Big \downarrow \) 1013 |
\(\displaystyle \frac {\sqrt {\frac {b x^3}{a}+1} \sqrt {\frac {d x^3}{c}+1} \int \frac {x^3}{\sqrt {\frac {b x^3}{a}+1} \sqrt {\frac {d x^3}{c}+1}}dx}{\sqrt {a+b x^3} \sqrt {c+d x^3}}\) |
\(\Big \downarrow \) 1012 |
\(\displaystyle \frac {x^4 \sqrt {\frac {b x^3}{a}+1} \sqrt {\frac {d x^3}{c}+1} \operatorname {AppellF1}\left (\frac {4}{3},\frac {1}{2},\frac {1}{2},\frac {7}{3},-\frac {b x^3}{a},-\frac {d x^3}{c}\right )}{4 \sqrt {a+b x^3} \sqrt {c+d x^3}}\) |
Input:
Int[x^3/(Sqrt[a + b*x^3]*Sqrt[c + d*x^3]),x]
Output:
(x^4*Sqrt[1 + (b*x^3)/a]*Sqrt[1 + (d*x^3)/c]*AppellF1[4/3, 1/2, 1/2, 7/3, -((b*x^3)/a), -((d*x^3)/c)])/(4*Sqrt[a + b*x^3]*Sqrt[c + d*x^3])
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ ))^(q_), x_Symbol] :> Simp[a^p*c^q*((e*x)^(m + 1)/(e*(m + 1)))*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, (-b)*(x^n/a), (-d)*(x^n/c)], x] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_ ))^(q_), x_Symbol] :> Simp[a^IntPart[p]*((a + b*x^n)^FracPart[p]/(1 + b*(x^ n/a))^FracPart[p]) Int[(e*x)^m*(1 + b*(x^n/a))^p*(c + d*x^n)^q, x], x] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] & & NeQ[m, n - 1] && !(IntegerQ[p] || GtQ[a, 0])
\[\int \frac {x^{3}}{\sqrt {b \,x^{3}+a}\, \sqrt {d \,x^{3}+c}}d x\]
Input:
int(x^3/(b*x^3+a)^(1/2)/(d*x^3+c)^(1/2),x)
Output:
int(x^3/(b*x^3+a)^(1/2)/(d*x^3+c)^(1/2),x)
\[ \int \frac {x^3}{\sqrt {a+b x^3} \sqrt {c+d x^3}} \, dx=\int { \frac {x^{3}}{\sqrt {b x^{3} + a} \sqrt {d x^{3} + c}} \,d x } \] Input:
integrate(x^3/(b*x^3+a)^(1/2)/(d*x^3+c)^(1/2),x, algorithm="fricas")
Output:
integral(sqrt(b*x^3 + a)*sqrt(d*x^3 + c)*x^3/(b*d*x^6 + (b*c + a*d)*x^3 + a*c), x)
\[ \int \frac {x^3}{\sqrt {a+b x^3} \sqrt {c+d x^3}} \, dx=\int \frac {x^{3}}{\sqrt {a + b x^{3}} \sqrt {c + d x^{3}}}\, dx \] Input:
integrate(x**3/(b*x**3+a)**(1/2)/(d*x**3+c)**(1/2),x)
Output:
Integral(x**3/(sqrt(a + b*x**3)*sqrt(c + d*x**3)), x)
\[ \int \frac {x^3}{\sqrt {a+b x^3} \sqrt {c+d x^3}} \, dx=\int { \frac {x^{3}}{\sqrt {b x^{3} + a} \sqrt {d x^{3} + c}} \,d x } \] Input:
integrate(x^3/(b*x^3+a)^(1/2)/(d*x^3+c)^(1/2),x, algorithm="maxima")
Output:
integrate(x^3/(sqrt(b*x^3 + a)*sqrt(d*x^3 + c)), x)
\[ \int \frac {x^3}{\sqrt {a+b x^3} \sqrt {c+d x^3}} \, dx=\int { \frac {x^{3}}{\sqrt {b x^{3} + a} \sqrt {d x^{3} + c}} \,d x } \] Input:
integrate(x^3/(b*x^3+a)^(1/2)/(d*x^3+c)^(1/2),x, algorithm="giac")
Output:
integrate(x^3/(sqrt(b*x^3 + a)*sqrt(d*x^3 + c)), x)
Timed out. \[ \int \frac {x^3}{\sqrt {a+b x^3} \sqrt {c+d x^3}} \, dx=\int \frac {x^3}{\sqrt {b\,x^3+a}\,\sqrt {d\,x^3+c}} \,d x \] Input:
int(x^3/((a + b*x^3)^(1/2)*(c + d*x^3)^(1/2)),x)
Output:
int(x^3/((a + b*x^3)^(1/2)*(c + d*x^3)^(1/2)), x)
\[ \int \frac {x^3}{\sqrt {a+b x^3} \sqrt {c+d x^3}} \, dx=\int \frac {\sqrt {d \,x^{3}+c}\, \sqrt {b \,x^{3}+a}\, x^{3}}{b d \,x^{6}+a d \,x^{3}+b c \,x^{3}+a c}d x \] Input:
int(x^3/(b*x^3+a)^(1/2)/(d*x^3+c)^(1/2),x)
Output:
int((sqrt(c + d*x**3)*sqrt(a + b*x**3)*x**3)/(a*c + a*d*x**3 + b*c*x**3 + b*d*x**6),x)