\(\int \frac {1}{x^9 (a+b x^8)^2 \sqrt {c+d x^8}} \, dx\) [117]

Optimal result

Integrand size = 24, antiderivative size = 185 \[ \int \frac {1}{x^9 \left (a+b x^8\right )^2 \sqrt {c+d x^8}} \, dx=-\frac {b (2 b c-a d) \sqrt {c+d x^8}}{8 a^2 c (b c-a d) \left (a+b x^8\right )}-\frac {\sqrt {c+d x^8}}{8 a c x^8 \left (a+b x^8\right )}+\frac {(4 b c+a d) \text {arctanh}\left (\frac {\sqrt {c+d x^8}}{\sqrt {c}}\right )}{8 a^3 c^{3/2}}-\frac {b^{3/2} (4 b c-5 a d) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x^8}}{\sqrt {b c-a d}}\right )}{8 a^3 (b c-a d)^{3/2}} \] Output:

-1/8*b*(-a*d+2*b*c)*(d*x^8+c)^(1/2)/a^2/c/(-a*d+b*c)/(b*x^8+a)-1/8*(d*x^8+ 
c)^(1/2)/a/c/x^8/(b*x^8+a)+1/8*(a*d+4*b*c)*arctanh((d*x^8+c)^(1/2)/c^(1/2) 
)/a^3/c^(3/2)-1/8*b^(3/2)*(-5*a*d+4*b*c)*arctanh(b^(1/2)*(d*x^8+c)^(1/2)/( 
-a*d+b*c)^(1/2))/a^3/(-a*d+b*c)^(3/2)
 

Mathematica [A] (verified)

Time = 0.71 (sec) , antiderivative size = 163, normalized size of antiderivative = 0.88 \[ \int \frac {1}{x^9 \left (a+b x^8\right )^2 \sqrt {c+d x^8}} \, dx=\frac {\frac {a \sqrt {c+d x^8} \left (-a^2 d+2 b^2 c x^8+a b \left (c-d x^8\right )\right )}{c (-b c+a d) x^8 \left (a+b x^8\right )}-\frac {b^{3/2} (4 b c-5 a d) \arctan \left (\frac {\sqrt {b} \sqrt {c+d x^8}}{\sqrt {-b c+a d}}\right )}{(-b c+a d)^{3/2}}+\frac {(4 b c+a d) \text {arctanh}\left (\frac {\sqrt {c+d x^8}}{\sqrt {c}}\right )}{c^{3/2}}}{8 a^3} \] Input:

Integrate[1/(x^9*(a + b*x^8)^2*Sqrt[c + d*x^8]),x]
 

Output:

((a*Sqrt[c + d*x^8]*(-(a^2*d) + 2*b^2*c*x^8 + a*b*(c - d*x^8)))/(c*(-(b*c) 
 + a*d)*x^8*(a + b*x^8)) - (b^(3/2)*(4*b*c - 5*a*d)*ArcTan[(Sqrt[b]*Sqrt[c 
 + d*x^8])/Sqrt[-(b*c) + a*d]])/(-(b*c) + a*d)^(3/2) + ((4*b*c + a*d)*ArcT 
anh[Sqrt[c + d*x^8]/Sqrt[c]])/c^(3/2))/(8*a^3)
 

Rubi [A] (verified)

Time = 0.60 (sec) , antiderivative size = 213, normalized size of antiderivative = 1.15, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.292, Rules used = {948, 114, 27, 168, 174, 73, 221}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{x^9 \left (a+b x^8\right )^2 \sqrt {c+d x^8}} \, dx\)

\(\Big \downarrow \) 948

\(\displaystyle \frac {1}{8} \int \frac {1}{x^{16} \left (b x^8+a\right )^2 \sqrt {d x^8+c}}dx^8\)

\(\Big \downarrow \) 114

\(\displaystyle \frac {1}{8} \left (-\frac {\int \frac {3 b d x^8+4 b c+a d}{2 x^8 \left (b x^8+a\right )^2 \sqrt {d x^8+c}}dx^8}{a c}-\frac {\sqrt {c+d x^8}}{a c x^8 \left (a+b x^8\right )}\right )\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{8} \left (-\frac {\int \frac {3 b d x^8+4 b c+a d}{x^8 \left (b x^8+a\right )^2 \sqrt {d x^8+c}}dx^8}{2 a c}-\frac {\sqrt {c+d x^8}}{a c x^8 \left (a+b x^8\right )}\right )\)

\(\Big \downarrow \) 168

\(\displaystyle \frac {1}{8} \left (-\frac {\frac {\int \frac {b d (2 b c-a d) x^8+(b c-a d) (4 b c+a d)}{x^8 \left (b x^8+a\right ) \sqrt {d x^8+c}}dx^8}{a (b c-a d)}+\frac {2 b \sqrt {c+d x^8} (2 b c-a d)}{a \left (a+b x^8\right ) (b c-a d)}}{2 a c}-\frac {\sqrt {c+d x^8}}{a c x^8 \left (a+b x^8\right )}\right )\)

\(\Big \downarrow \) 174

\(\displaystyle \frac {1}{8} \left (-\frac {\frac {\frac {(b c-a d) (a d+4 b c) \int \frac {1}{x^8 \sqrt {d x^8+c}}dx^8}{a}-\frac {b^2 c (4 b c-5 a d) \int \frac {1}{\left (b x^8+a\right ) \sqrt {d x^8+c}}dx^8}{a}}{a (b c-a d)}+\frac {2 b \sqrt {c+d x^8} (2 b c-a d)}{a \left (a+b x^8\right ) (b c-a d)}}{2 a c}-\frac {\sqrt {c+d x^8}}{a c x^8 \left (a+b x^8\right )}\right )\)

\(\Big \downarrow \) 73

\(\displaystyle \frac {1}{8} \left (-\frac {\frac {\frac {2 (b c-a d) (a d+4 b c) \int \frac {1}{\frac {x^{16}}{d}-\frac {c}{d}}d\sqrt {d x^8+c}}{a d}-\frac {2 b^2 c (4 b c-5 a d) \int \frac {1}{\frac {b x^{16}}{d}+a-\frac {b c}{d}}d\sqrt {d x^8+c}}{a d}}{a (b c-a d)}+\frac {2 b \sqrt {c+d x^8} (2 b c-a d)}{a \left (a+b x^8\right ) (b c-a d)}}{2 a c}-\frac {\sqrt {c+d x^8}}{a c x^8 \left (a+b x^8\right )}\right )\)

\(\Big \downarrow \) 221

\(\displaystyle \frac {1}{8} \left (-\frac {\frac {\frac {2 b^{3/2} c (4 b c-5 a d) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x^8}}{\sqrt {b c-a d}}\right )}{a \sqrt {b c-a d}}-\frac {2 (b c-a d) (a d+4 b c) \text {arctanh}\left (\frac {\sqrt {c+d x^8}}{\sqrt {c}}\right )}{a \sqrt {c}}}{a (b c-a d)}+\frac {2 b \sqrt {c+d x^8} (2 b c-a d)}{a \left (a+b x^8\right ) (b c-a d)}}{2 a c}-\frac {\sqrt {c+d x^8}}{a c x^8 \left (a+b x^8\right )}\right )\)

Input:

Int[1/(x^9*(a + b*x^8)^2*Sqrt[c + d*x^8]),x]
 

Output:

(-(Sqrt[c + d*x^8]/(a*c*x^8*(a + b*x^8))) - ((2*b*(2*b*c - a*d)*Sqrt[c + d 
*x^8])/(a*(b*c - a*d)*(a + b*x^8)) + ((-2*(b*c - a*d)*(4*b*c + a*d)*ArcTan 
h[Sqrt[c + d*x^8]/Sqrt[c]])/(a*Sqrt[c]) + (2*b^(3/2)*c*(4*b*c - 5*a*d)*Arc 
Tanh[(Sqrt[b]*Sqrt[c + d*x^8])/Sqrt[b*c - a*d]])/(a*Sqrt[b*c - a*d]))/(a*( 
b*c - a*d)))/(2*a*c))/8
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 73

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 114

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Simp[b*(a + b*x)^(m + 1)*(c + d*x)^(n + 1)*((e + f*x)^(p + 1 
)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + Simp[1/((m + 1)*(b*c - a*d)*(b*e 
 - a*f))   Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*(m + 1) 
 - b*(d*e*(m + n + 2) + c*f*(m + p + 2)) - b*d*f*(m + n + p + 3)*x, x], x], 
 x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && ILtQ[m, -1] && (IntegerQ[n] || 
 IntegersQ[2*n, 2*p] || ILtQ[m + n + p + 3, 0])
 

rule 168

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + 
 d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + S 
imp[1/((m + 1)*(b*c - a*d)*(b*e - a*f))   Int[(a + b*x)^(m + 1)*(c + d*x)^n 
*(e + f*x)^p*Simp[(a*d*f*g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a* 
h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p + 3)*x, x], x], 
 x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && ILtQ[m, -1]
 

rule 174

Int[(((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/(((a_.) + (b_.)*(x_))* 
((c_.) + (d_.)*(x_))), x_] :> Simp[(b*g - a*h)/(b*c - a*d)   Int[(e + f*x)^ 
p/(a + b*x), x], x] - Simp[(d*g - c*h)/(b*c - a*d)   Int[(e + f*x)^p/(c + d 
*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x]
 

rule 221

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 948

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_. 
), x_Symbol] :> Simp[1/n   Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^ 
p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] && NeQ 
[b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]
 

Maple [A] (verified)

Time = 0.64 (sec) , antiderivative size = 191, normalized size of antiderivative = 1.03

method	result	size
pseudoelliptic	\(\frac {-4 \left (b \,x^{8}+a \right ) \left (c b -\frac {5 a d}{4}\right ) c^{\frac {5}{2}} b^{2} x^{8} \arctan \left (\frac {\sqrt {d \,x^{8}+c}\, b}{\sqrt {\left (a d -c b \right ) b}}\right )+\sqrt {\left (a d -c b \right ) b}\, \left (c \,x^{8} \left (b \,x^{8}+a \right ) \left (a d +4 c b \right ) \left (a d -c b \right ) \operatorname {arctanh}\left (\frac {\sqrt {d \,x^{8}+c}}{\sqrt {c}}\right )+c^{\frac {3}{2}} \sqrt {d \,x^{8}+c}\, a \left (2 b^{2} c \,x^{8}+a \left (-d \,x^{8}+c \right ) b -a^{2} d \right )\right )}{8 \sqrt {\left (a d -c b \right ) b}\, c^{\frac {5}{2}} x^{8} a^{3} \left (a d -c b \right ) \left (b \,x^{8}+a \right )}\)	\(191\)

Input:

int(1/x^9/(b*x^8+a)^2/(d*x^8+c)^(1/2),x,method=_RETURNVERBOSE)
 

Output:

1/8*(-4*(b*x^8+a)*(c*b-5/4*a*d)*c^(5/2)*b^2*x^8*arctan((d*x^8+c)^(1/2)*b/( 
(a*d-b*c)*b)^(1/2))+((a*d-b*c)*b)^(1/2)*(c*x^8*(b*x^8+a)*(a*d+4*b*c)*(a*d- 
b*c)*arctanh((d*x^8+c)^(1/2)/c^(1/2))+c^(3/2)*(d*x^8+c)^(1/2)*a*(2*b^2*c*x 
^8+a*(-d*x^8+c)*b-a^2*d)))/((a*d-b*c)*b)^(1/2)/c^(5/2)/x^8/a^3/(a*d-b*c)/( 
b*x^8+a)
 

Fricas [A] (verification not implemented)

Time = 0.22 (sec) , antiderivative size = 1189, normalized size of antiderivative = 6.43 \[ \int \frac {1}{x^9 \left (a+b x^8\right )^2 \sqrt {c+d x^8}} \, dx=\text {Too large to display} \] Input:

integrate(1/x^9/(b*x^8+a)^2/(d*x^8+c)^(1/2),x, algorithm="fricas")
 

Output:

[1/16*(((4*b^3*c^3 - 5*a*b^2*c^2*d)*x^16 + (4*a*b^2*c^3 - 5*a^2*b*c^2*d)*x 
^8)*sqrt(b/(b*c - a*d))*log((b*d*x^8 + 2*b*c - a*d - 2*sqrt(d*x^8 + c)*(b* 
c - a*d)*sqrt(b/(b*c - a*d)))/(b*x^8 + a)) + ((4*b^3*c^2 - 3*a*b^2*c*d - a 
^2*b*d^2)*x^16 + (4*a*b^2*c^2 - 3*a^2*b*c*d - a^3*d^2)*x^8)*sqrt(c)*log((d 
*x^8 + 2*sqrt(d*x^8 + c)*sqrt(c) + 2*c)/x^8) - 2*((2*a*b^2*c^2 - a^2*b*c*d 
)*x^8 + a^2*b*c^2 - a^3*c*d)*sqrt(d*x^8 + c))/((a^3*b^2*c^3 - a^4*b*c^2*d) 
*x^16 + (a^4*b*c^3 - a^5*c^2*d)*x^8), 1/16*(2*((4*b^3*c^3 - 5*a*b^2*c^2*d) 
*x^16 + (4*a*b^2*c^3 - 5*a^2*b*c^2*d)*x^8)*sqrt(-b/(b*c - a*d))*arctan(sqr 
t(d*x^8 + c)*sqrt(-b/(b*c - a*d))) + ((4*b^3*c^2 - 3*a*b^2*c*d - a^2*b*d^2 
)*x^16 + (4*a*b^2*c^2 - 3*a^2*b*c*d - a^3*d^2)*x^8)*sqrt(c)*log((d*x^8 + 2 
*sqrt(d*x^8 + c)*sqrt(c) + 2*c)/x^8) - 2*((2*a*b^2*c^2 - a^2*b*c*d)*x^8 + 
a^2*b*c^2 - a^3*c*d)*sqrt(d*x^8 + c))/((a^3*b^2*c^3 - a^4*b*c^2*d)*x^16 + 
(a^4*b*c^3 - a^5*c^2*d)*x^8), -1/16*(2*((4*b^3*c^2 - 3*a*b^2*c*d - a^2*b*d 
^2)*x^16 + (4*a*b^2*c^2 - 3*a^2*b*c*d - a^3*d^2)*x^8)*sqrt(-c)*arctan(sqrt 
(-c)/sqrt(d*x^8 + c)) - ((4*b^3*c^3 - 5*a*b^2*c^2*d)*x^16 + (4*a*b^2*c^3 - 
 5*a^2*b*c^2*d)*x^8)*sqrt(b/(b*c - a*d))*log((b*d*x^8 + 2*b*c - a*d - 2*sq 
rt(d*x^8 + c)*(b*c - a*d)*sqrt(b/(b*c - a*d)))/(b*x^8 + a)) + 2*((2*a*b^2* 
c^2 - a^2*b*c*d)*x^8 + a^2*b*c^2 - a^3*c*d)*sqrt(d*x^8 + c))/((a^3*b^2*c^3 
 - a^4*b*c^2*d)*x^16 + (a^4*b*c^3 - a^5*c^2*d)*x^8), 1/8*(((4*b^3*c^3 - 5* 
a*b^2*c^2*d)*x^16 + (4*a*b^2*c^3 - 5*a^2*b*c^2*d)*x^8)*sqrt(-b/(b*c - a...
 

Sympy [F]

\[ \int \frac {1}{x^9 \left (a+b x^8\right )^2 \sqrt {c+d x^8}} \, dx=\int \frac {1}{x^{9} \left (a + b x^{8}\right )^{2} \sqrt {c + d x^{8}}}\, dx \] Input:

integrate(1/x**9/(b*x**8+a)**2/(d*x**8+c)**(1/2),x)
 

Output:

Integral(1/(x**9*(a + b*x**8)**2*sqrt(c + d*x**8)), x)
 

Maxima [F]

\[ \int \frac {1}{x^9 \left (a+b x^8\right )^2 \sqrt {c+d x^8}} \, dx=\int { \frac {1}{{\left (b x^{8} + a\right )}^{2} \sqrt {d x^{8} + c} x^{9}} \,d x } \] Input:

integrate(1/x^9/(b*x^8+a)^2/(d*x^8+c)^(1/2),x, algorithm="maxima")
 

Output:

integrate(1/((b*x^8 + a)^2*sqrt(d*x^8 + c)*x^9), x)
 

Giac [A] (verification not implemented)

Time = 0.12 (sec) , antiderivative size = 257, normalized size of antiderivative = 1.39 \[ \int \frac {1}{x^9 \left (a+b x^8\right )^2 \sqrt {c+d x^8}} \, dx=\frac {{\left (4 \, b^{3} c - 5 \, a b^{2} d\right )} \arctan \left (\frac {\sqrt {d x^{8} + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{8 \, {\left (a^{3} b c - a^{4} d\right )} \sqrt {-b^{2} c + a b d}} - \frac {2 \, {\left (d x^{8} + c\right )}^{\frac {3}{2}} b^{2} c d - 2 \, \sqrt {d x^{8} + c} b^{2} c^{2} d - {\left (d x^{8} + c\right )}^{\frac {3}{2}} a b d^{2} + 2 \, \sqrt {d x^{8} + c} a b c d^{2} - \sqrt {d x^{8} + c} a^{2} d^{3}}{8 \, {\left (a^{2} b c^{2} - a^{3} c d\right )} {\left ({\left (d x^{8} + c\right )}^{2} b - 2 \, {\left (d x^{8} + c\right )} b c + b c^{2} + {\left (d x^{8} + c\right )} a d - a c d\right )}} - \frac {{\left (4 \, b c + a d\right )} \arctan \left (\frac {\sqrt {d x^{8} + c}}{\sqrt {-c}}\right )}{8 \, a^{3} \sqrt {-c} c} \] Input:

integrate(1/x^9/(b*x^8+a)^2/(d*x^8+c)^(1/2),x, algorithm="giac")
 

Output:

1/8*(4*b^3*c - 5*a*b^2*d)*arctan(sqrt(d*x^8 + c)*b/sqrt(-b^2*c + a*b*d))/( 
(a^3*b*c - a^4*d)*sqrt(-b^2*c + a*b*d)) - 1/8*(2*(d*x^8 + c)^(3/2)*b^2*c*d 
 - 2*sqrt(d*x^8 + c)*b^2*c^2*d - (d*x^8 + c)^(3/2)*a*b*d^2 + 2*sqrt(d*x^8 
+ c)*a*b*c*d^2 - sqrt(d*x^8 + c)*a^2*d^3)/((a^2*b*c^2 - a^3*c*d)*((d*x^8 + 
 c)^2*b - 2*(d*x^8 + c)*b*c + b*c^2 + (d*x^8 + c)*a*d - a*c*d)) - 1/8*(4*b 
*c + a*d)*arctan(sqrt(d*x^8 + c)/sqrt(-c))/(a^3*sqrt(-c)*c)
 

Mupad [B] (verification not implemented)

Time = 7.07 (sec) , antiderivative size = 3832, normalized size of antiderivative = 20.71 \[ \int \frac {1}{x^9 \left (a+b x^8\right )^2 \sqrt {c+d x^8}} \, dx=\text {Too large to display} \] Input:

int(1/(x^9*(a + b*x^8)^2*(c + d*x^8)^(1/2)),x)
 

Output:

(((c + d*x^8)^(1/2)*(a^2*d^3 + 2*b^2*c^2*d - 2*a*b*c*d^2))/(2*a^2*(b*c^2 - 
 a*c*d)) + (b*(c + d*x^8)^(3/2)*(a*d^2 - 2*b*c*d))/(2*a^2*(b*c^2 - a*c*d)) 
)/((c + d*x^8)*(4*a*d - 8*b*c) + 4*b*(c + d*x^8)^2 + 4*b*c^2 - 4*a*c*d) + 
(atan((((-b^3*(a*d - b*c)^3)^(1/2)*(5*a*d - 4*b*c)*(((c + d*x^8)^(1/2)*(a^ 
4*b^3*d^6 + 32*b^7*c^4*d^2 - 64*a*b^6*c^3*d^3 + 6*a^3*b^4*c*d^5 + 26*a^2*b 
^5*c^2*d^4))/(32*(a^4*b^2*c^4 + a^6*c^2*d^2 - 2*a^5*b*c^3*d)) + ((-b^3*(a* 
d - b*c)^3)^(1/2)*(5*a*d - 4*b*c)*(((a^9*b^2*c*d^6)/2 + a^6*b^5*c^4*d^3 - 
2*a^7*b^4*c^3*d^4 + (a^8*b^3*c^2*d^5)/2)/(a^6*b^2*c^4 + a^8*c^2*d^2 - 2*a^ 
7*b*c^3*d) - ((-b^3*(a*d - b*c)^3)^(1/2)*(c + d*x^8)^(1/2)*(5*a*d - 4*b*c) 
*(512*a^6*b^5*c^5*d^2 - 1280*a^7*b^4*c^4*d^3 + 1024*a^8*b^3*c^3*d^4 - 256* 
a^9*b^2*c^2*d^5))/(512*(a^4*b^2*c^4 + a^6*c^2*d^2 - 2*a^5*b*c^3*d)*(a^6*d^ 
3 - a^3*b^3*c^3 + 3*a^4*b^2*c^2*d - 3*a^5*b*c*d^2))))/(16*(a^6*d^3 - a^3*b 
^3*c^3 + 3*a^4*b^2*c^2*d - 3*a^5*b*c*d^2)))*1i)/(16*(a^6*d^3 - a^3*b^3*c^3 
 + 3*a^4*b^2*c^2*d - 3*a^5*b*c*d^2)) + ((-b^3*(a*d - b*c)^3)^(1/2)*(5*a*d 
- 4*b*c)*(((c + d*x^8)^(1/2)*(a^4*b^3*d^6 + 32*b^7*c^4*d^2 - 64*a*b^6*c^3* 
d^3 + 6*a^3*b^4*c*d^5 + 26*a^2*b^5*c^2*d^4))/(32*(a^4*b^2*c^4 + a^6*c^2*d^ 
2 - 2*a^5*b*c^3*d)) - ((-b^3*(a*d - b*c)^3)^(1/2)*(5*a*d - 4*b*c)*(((a^9*b 
^2*c*d^6)/2 + a^6*b^5*c^4*d^3 - 2*a^7*b^4*c^3*d^4 + (a^8*b^3*c^2*d^5)/2)/( 
a^6*b^2*c^4 + a^8*c^2*d^2 - 2*a^7*b*c^3*d) + ((-b^3*(a*d - b*c)^3)^(1/2)*( 
c + d*x^8)^(1/2)*(5*a*d - 4*b*c)*(512*a^6*b^5*c^5*d^2 - 1280*a^7*b^4*c^...
 

Reduce [F]

\[ \int \frac {1}{x^9 \left (a+b x^8\right )^2 \sqrt {c+d x^8}} \, dx=\int \frac {1}{x^{9} \left (b \,x^{8}+a \right )^{2} \sqrt {d \,x^{8}+c}}d x \] Input:

int(1/x^9/(b*x^8+a)^2/(d*x^8+c)^(1/2),x)
 

Output:

int(1/x^9/(b*x^8+a)^2/(d*x^8+c)^(1/2),x)