Integrand size = 22, antiderivative size = 105 \[ \int \frac {\left (a+b x^n\right )^{5/2} \left (A+B x^n\right )}{x^2} \, dx=-\frac {2 B \left (a+b x^n\right )^{7/2}}{b (2-7 n) x}-\frac {a^2 \left (A-\frac {2 a B}{2 b-7 b n}\right ) \sqrt {a+b x^n} \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},-\frac {1}{n},-\frac {1-n}{n},-\frac {b x^n}{a}\right )}{x \sqrt {1+\frac {b x^n}{a}}} \] Output:
-2*B*(a+b*x^n)^(7/2)/b/(2-7*n)/x-a^2*(A-2*a*B/(-7*b*n+2*b))*(a+b*x^n)^(1/2 )*hypergeom([-5/2, -1/n],[-(1-n)/n],-b*x^n/a)/x/(1+b*x^n/a)^(1/2)
Time = 0.13 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.97 \[ \int \frac {\left (a+b x^n\right )^{5/2} \left (A+B x^n\right )}{x^2} \, dx=\frac {a^2 \sqrt {a+b x^n} \left ((A-A n) \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},-\frac {1}{n},\frac {-1+n}{n},-\frac {b x^n}{a}\right )+B x^n \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},\frac {-1+n}{n},2-\frac {1}{n},-\frac {b x^n}{a}\right )\right )}{(-1+n) x \sqrt {1+\frac {b x^n}{a}}} \] Input:
Integrate[((a + b*x^n)^(5/2)*(A + B*x^n))/x^2,x]
Output:
(a^2*Sqrt[a + b*x^n]*((A - A*n)*Hypergeometric2F1[-5/2, -n^(-1), (-1 + n)/ n, -((b*x^n)/a)] + B*x^n*Hypergeometric2F1[-5/2, (-1 + n)/n, 2 - n^(-1), - ((b*x^n)/a)]))/((-1 + n)*x*Sqrt[1 + (b*x^n)/a])
Time = 0.41 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {959, 889, 888}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\left (a+b x^n\right )^{5/2} \left (A+B x^n\right )}{x^2} \, dx\) |
\(\Big \downarrow \) 959 |
\(\displaystyle \left (A-\frac {2 a B}{2 b-7 b n}\right ) \int \frac {\left (b x^n+a\right )^{5/2}}{x^2}dx-\frac {2 B \left (a+b x^n\right )^{7/2}}{b (2-7 n) x}\) |
\(\Big \downarrow \) 889 |
\(\displaystyle \frac {a^2 \sqrt {a+b x^n} \left (A-\frac {2 a B}{2 b-7 b n}\right ) \int \frac {\left (\frac {b x^n}{a}+1\right )^{5/2}}{x^2}dx}{\sqrt {\frac {b x^n}{a}+1}}-\frac {2 B \left (a+b x^n\right )^{7/2}}{b (2-7 n) x}\) |
\(\Big \downarrow \) 888 |
\(\displaystyle -\frac {a^2 \sqrt {a+b x^n} \left (A-\frac {2 a B}{2 b-7 b n}\right ) \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},-\frac {1}{n},-\frac {1-n}{n},-\frac {b x^n}{a}\right )}{x \sqrt {\frac {b x^n}{a}+1}}-\frac {2 B \left (a+b x^n\right )^{7/2}}{b (2-7 n) x}\) |
Input:
Int[((a + b*x^n)^(5/2)*(A + B*x^n))/x^2,x]
Output:
(-2*B*(a + b*x^n)^(7/2))/(b*(2 - 7*n)*x) - (a^2*(A - (2*a*B)/(2*b - 7*b*n) )*Sqrt[a + b*x^n]*Hypergeometric2F1[-5/2, -n^(-1), -((1 - n)/n), -((b*x^n) /a)])/(x*Sqrt[1 + (b*x^n)/a])
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p *((c*x)^(m + 1)/(c*(m + 1)))*Hypergeometric2F1[-p, (m + 1)/n, (m + 1)/n + 1 , (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] && !IGtQ[p, 0] && (ILt Q[p, 0] || GtQ[a, 0])
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^I ntPart[p]*((a + b*x^n)^FracPart[p]/(1 + b*(x^n/a))^FracPart[p]) Int[(c*x) ^m*(1 + b*(x^n/a))^p, x], x] /; FreeQ[{a, b, c, m, n, p}, x] && !IGtQ[p, 0 ] && !(ILtQ[p, 0] || GtQ[a, 0])
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n _)), x_Symbol] :> Simp[d*(e*x)^(m + 1)*((a + b*x^n)^(p + 1)/(b*e*(m + n*(p + 1) + 1))), x] - Simp[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(b*(m + n*(p + 1) + 1)) Int[(e*x)^m*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0] && NeQ[m + n*(p + 1) + 1, 0]
\[\int \frac {\left (a +b \,x^{n}\right )^{\frac {5}{2}} \left (A +B \,x^{n}\right )}{x^{2}}d x\]
Input:
int((a+b*x^n)^(5/2)*(A+B*x^n)/x^2,x)
Output:
int((a+b*x^n)^(5/2)*(A+B*x^n)/x^2,x)
Exception generated. \[ \int \frac {\left (a+b x^n\right )^{5/2} \left (A+B x^n\right )}{x^2} \, dx=\text {Exception raised: TypeError} \] Input:
integrate((a+b*x^n)^(5/2)*(A+B*x^n)/x^2,x, algorithm="fricas")
Output:
Exception raised: TypeError >> Error detected within library code: inte grate: implementation incomplete (has polynomial part)
Result contains complex when optimal does not.
Time = 8.64 (sec) , antiderivative size = 389, normalized size of antiderivative = 3.70 \[ \int \frac {\left (a+b x^n\right )^{5/2} \left (A+B x^n\right )}{x^2} \, dx=\frac {A a^{2} a^{- \frac {1}{n}} a^{\frac {1}{2} + \frac {1}{n}} \Gamma \left (- \frac {1}{n}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, - \frac {1}{n} \\ 1 - \frac {1}{n} \end {matrix}\middle | {\frac {b x^{n} e^{i \pi }}{a}} \right )}}{n x \Gamma \left (1 - \frac {1}{n}\right )} + \frac {2 A a a^{- \frac {1}{2} + \frac {1}{n}} a^{1 - \frac {1}{n}} b x^{n - 1} \Gamma \left (1 - \frac {1}{n}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, 1 - \frac {1}{n} \\ 2 - \frac {1}{n} \end {matrix}\middle | {\frac {b x^{n} e^{i \pi }}{a}} \right )}}{n \Gamma \left (2 - \frac {1}{n}\right )} + \frac {A a^{- \frac {3}{2} + \frac {1}{n}} a^{2 - \frac {1}{n}} b^{2} x^{2 n - 1} \Gamma \left (2 - \frac {1}{n}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, 2 - \frac {1}{n} \\ 3 - \frac {1}{n} \end {matrix}\middle | {\frac {b x^{n} e^{i \pi }}{a}} \right )}}{n \Gamma \left (3 - \frac {1}{n}\right )} + \frac {B a^{2} a^{- \frac {1}{2} + \frac {1}{n}} a^{1 - \frac {1}{n}} x^{n - 1} \Gamma \left (1 - \frac {1}{n}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, 1 - \frac {1}{n} \\ 2 - \frac {1}{n} \end {matrix}\middle | {\frac {b x^{n} e^{i \pi }}{a}} \right )}}{n \Gamma \left (2 - \frac {1}{n}\right )} + \frac {2 B a a^{- \frac {3}{2} + \frac {1}{n}} a^{2 - \frac {1}{n}} b x^{2 n - 1} \Gamma \left (2 - \frac {1}{n}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, 2 - \frac {1}{n} \\ 3 - \frac {1}{n} \end {matrix}\middle | {\frac {b x^{n} e^{i \pi }}{a}} \right )}}{n \Gamma \left (3 - \frac {1}{n}\right )} + \frac {B a^{- \frac {5}{2} + \frac {1}{n}} a^{3 - \frac {1}{n}} b^{2} x^{3 n - 1} \Gamma \left (3 - \frac {1}{n}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, 3 - \frac {1}{n} \\ 4 - \frac {1}{n} \end {matrix}\middle | {\frac {b x^{n} e^{i \pi }}{a}} \right )}}{n \Gamma \left (4 - \frac {1}{n}\right )} \] Input:
integrate((a+b*x**n)**(5/2)*(A+B*x**n)/x**2,x)
Output:
A*a**2*a**(1/2 + 1/n)*gamma(-1/n)*hyper((-1/2, -1/n), (1 - 1/n,), b*x**n*e xp_polar(I*pi)/a)/(a**(1/n)*n*x*gamma(1 - 1/n)) + 2*A*a*a**(-1/2 + 1/n)*a* *(1 - 1/n)*b*x**(n - 1)*gamma(1 - 1/n)*hyper((-1/2, 1 - 1/n), (2 - 1/n,), b*x**n*exp_polar(I*pi)/a)/(n*gamma(2 - 1/n)) + A*a**(-3/2 + 1/n)*a**(2 - 1 /n)*b**2*x**(2*n - 1)*gamma(2 - 1/n)*hyper((-1/2, 2 - 1/n), (3 - 1/n,), b* x**n*exp_polar(I*pi)/a)/(n*gamma(3 - 1/n)) + B*a**2*a**(-1/2 + 1/n)*a**(1 - 1/n)*x**(n - 1)*gamma(1 - 1/n)*hyper((-1/2, 1 - 1/n), (2 - 1/n,), b*x**n *exp_polar(I*pi)/a)/(n*gamma(2 - 1/n)) + 2*B*a*a**(-3/2 + 1/n)*a**(2 - 1/n )*b*x**(2*n - 1)*gamma(2 - 1/n)*hyper((-1/2, 2 - 1/n), (3 - 1/n,), b*x**n* exp_polar(I*pi)/a)/(n*gamma(3 - 1/n)) + B*a**(-5/2 + 1/n)*a**(3 - 1/n)*b** 2*x**(3*n - 1)*gamma(3 - 1/n)*hyper((-1/2, 3 - 1/n), (4 - 1/n,), b*x**n*ex p_polar(I*pi)/a)/(n*gamma(4 - 1/n))
\[ \int \frac {\left (a+b x^n\right )^{5/2} \left (A+B x^n\right )}{x^2} \, dx=\int { \frac {{\left (B x^{n} + A\right )} {\left (b x^{n} + a\right )}^{\frac {5}{2}}}{x^{2}} \,d x } \] Input:
integrate((a+b*x^n)^(5/2)*(A+B*x^n)/x^2,x, algorithm="maxima")
Output:
integrate((B*x^n + A)*(b*x^n + a)^(5/2)/x^2, x)
\[ \int \frac {\left (a+b x^n\right )^{5/2} \left (A+B x^n\right )}{x^2} \, dx=\int { \frac {{\left (B x^{n} + A\right )} {\left (b x^{n} + a\right )}^{\frac {5}{2}}}{x^{2}} \,d x } \] Input:
integrate((a+b*x^n)^(5/2)*(A+B*x^n)/x^2,x, algorithm="giac")
Output:
integrate((B*x^n + A)*(b*x^n + a)^(5/2)/x^2, x)
Timed out. \[ \int \frac {\left (a+b x^n\right )^{5/2} \left (A+B x^n\right )}{x^2} \, dx=\int \frac {\left (A+B\,x^n\right )\,{\left (a+b\,x^n\right )}^{5/2}}{x^2} \,d x \] Input:
int(((A + B*x^n)*(a + b*x^n)^(5/2))/x^2,x)
Output:
int(((A + B*x^n)*(a + b*x^n)^(5/2))/x^2, x)
\[ \int \frac {\left (a+b x^n\right )^{5/2} \left (A+B x^n\right )}{x^2} \, dx =\text {Too large to display} \] Input:
int((a+b*x^n)^(5/2)*(A+B*x^n)/x^2,x)
Output:
(30*x**(3*n)*sqrt(x**n*b + a)*b**3*n**3 - 92*x**(3*n)*sqrt(x**n*b + a)*b** 3*n**2 + 72*x**(3*n)*sqrt(x**n*b + a)*b**3*n - 16*x**(3*n)*sqrt(x**n*b + a )*b**3 + 132*x**(2*n)*sqrt(x**n*b + a)*a*b**2*n**3 - 388*x**(2*n)*sqrt(x** n*b + a)*a*b**2*n**2 + 272*x**(2*n)*sqrt(x**n*b + a)*a*b**2*n - 48*x**(2*n )*sqrt(x**n*b + a)*a*b**2 + 244*x**n*sqrt(x**n*b + a)*a**2*b*n**3 - 640*x* *n*sqrt(x**n*b + a)*a**2*b*n**2 + 328*x**n*sqrt(x**n*b + a)*a**2*b*n - 48* x**n*sqrt(x**n*b + a)*a**2*b + 352*sqrt(x**n*b + a)*a**3*n**3 - 344*sqrt(x **n*b + a)*a**3*n**2 + 128*sqrt(x**n*b + a)*a**3*n - 16*sqrt(x**n*b + a)*a **3 + 11025*int(sqrt(x**n*b + a)/(105*x**n*b*n**4*x**2 - 352*x**n*b*n**3*x **2 + 344*x**n*b*n**2*x**2 - 128*x**n*b*n*x**2 + 16*x**n*b*x**2 + 105*a*n* *4*x**2 - 352*a*n**3*x**2 + 344*a*n**2*x**2 - 128*a*n*x**2 + 16*a*x**2),x) *a**4*n**8*x - 36960*int(sqrt(x**n*b + a)/(105*x**n*b*n**4*x**2 - 352*x**n *b*n**3*x**2 + 344*x**n*b*n**2*x**2 - 128*x**n*b*n*x**2 + 16*x**n*b*x**2 + 105*a*n**4*x**2 - 352*a*n**3*x**2 + 344*a*n**2*x**2 - 128*a*n*x**2 + 16*a *x**2),x)*a**4*n**7*x + 36120*int(sqrt(x**n*b + a)/(105*x**n*b*n**4*x**2 - 352*x**n*b*n**3*x**2 + 344*x**n*b*n**2*x**2 - 128*x**n*b*n*x**2 + 16*x**n *b*x**2 + 105*a*n**4*x**2 - 352*a*n**3*x**2 + 344*a*n**2*x**2 - 128*a*n*x* *2 + 16*a*x**2),x)*a**4*n**6*x - 13440*int(sqrt(x**n*b + a)/(105*x**n*b*n* *4*x**2 - 352*x**n*b*n**3*x**2 + 344*x**n*b*n**2*x**2 - 128*x**n*b*n*x**2 + 16*x**n*b*x**2 + 105*a*n**4*x**2 - 352*a*n**3*x**2 + 344*a*n**2*x**2 ...