Integrand size = 22, antiderivative size = 576 \[ \int \frac {x^9 \left (c+d x^6\right )}{\left (a+b x^6\right )^{3/2}} \, dx=-\frac {(b c-a d) x^4}{3 b^2 \sqrt {a+b x^6}}+\frac {d x^4 \sqrt {a+b x^6}}{7 b^2}+\frac {4 (7 b c-10 a d) \sqrt {a+b x^6}}{21 b^{8/3} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )}-\frac {2 \sqrt {2-\sqrt {3}} \sqrt [3]{a} (7 b c-10 a d) \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x^2+b^{2/3} x^4}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} E\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2}\right )|-7-4 \sqrt {3}\right )}{7\ 3^{3/4} b^{8/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} \sqrt {a+b x^6}}+\frac {4 \sqrt {2} \sqrt [3]{a} (7 b c-10 a d) \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x^2+b^{2/3} x^4}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2}\right ),-7-4 \sqrt {3}\right )}{21 \sqrt [4]{3} b^{8/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} \sqrt {a+b x^6}} \] Output:
-1/3*(-a*d+b*c)*x^4/b^2/(b*x^6+a)^(1/2)+1/7*d*x^4*(b*x^6+a)^(1/2)/b^2+4/21 *(-10*a*d+7*b*c)*(b*x^6+a)^(1/2)/b^(8/3)/((1+3^(1/2))*a^(1/3)+b^(1/3)*x^2) -2/21*(1/2*6^(1/2)-1/2*2^(1/2))*a^(1/3)*(-10*a*d+7*b*c)*(a^(1/3)+b^(1/3)*x ^2)*((a^(2/3)-a^(1/3)*b^(1/3)*x^2+b^(2/3)*x^4)/((1+3^(1/2))*a^(1/3)+b^(1/3 )*x^2)^2)^(1/2)*EllipticE(((1-3^(1/2))*a^(1/3)+b^(1/3)*x^2)/((1+3^(1/2))*a ^(1/3)+b^(1/3)*x^2),I*3^(1/2)+2*I)*3^(1/4)/b^(8/3)/(a^(1/3)*(a^(1/3)+b^(1/ 3)*x^2)/((1+3^(1/2))*a^(1/3)+b^(1/3)*x^2)^2)^(1/2)/(b*x^6+a)^(1/2)+4/63*2^ (1/2)*a^(1/3)*(-10*a*d+7*b*c)*(a^(1/3)+b^(1/3)*x^2)*((a^(2/3)-a^(1/3)*b^(1 /3)*x^2+b^(2/3)*x^4)/((1+3^(1/2))*a^(1/3)+b^(1/3)*x^2)^2)^(1/2)*EllipticF( ((1-3^(1/2))*a^(1/3)+b^(1/3)*x^2)/((1+3^(1/2))*a^(1/3)+b^(1/3)*x^2),I*3^(1 /2)+2*I)*3^(3/4)/b^(8/3)/(a^(1/3)*(a^(1/3)+b^(1/3)*x^2)/((1+3^(1/2))*a^(1/ 3)+b^(1/3)*x^2)^2)^(1/2)/(b*x^6+a)^(1/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.08 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.14 \[ \int \frac {x^9 \left (c+d x^6\right )}{\left (a+b x^6\right )^{3/2}} \, dx=\frac {x^4 \left (7 b c-10 a d+b d x^6+(-7 b c+10 a d) \sqrt {1+\frac {b x^6}{a}} \operatorname {Hypergeometric2F1}\left (\frac {2}{3},\frac {3}{2},\frac {5}{3},-\frac {b x^6}{a}\right )\right )}{7 b^2 \sqrt {a+b x^6}} \] Input:
Integrate[(x^9*(c + d*x^6))/(a + b*x^6)^(3/2),x]
Output:
(x^4*(7*b*c - 10*a*d + b*d*x^6 + (-7*b*c + 10*a*d)*Sqrt[1 + (b*x^6)/a]*Hyp ergeometric2F1[2/3, 3/2, 5/3, -((b*x^6)/a)]))/(7*b^2*Sqrt[a + b*x^6])
Time = 0.98 (sec) , antiderivative size = 582, normalized size of antiderivative = 1.01, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {959, 807, 817, 832, 759, 2416}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^9 \left (c+d x^6\right )}{\left (a+b x^6\right )^{3/2}} \, dx\) |
\(\Big \downarrow \) 959 |
\(\displaystyle \frac {(7 b c-10 a d) \int \frac {x^9}{\left (b x^6+a\right )^{3/2}}dx}{7 b}+\frac {d x^{10}}{7 b \sqrt {a+b x^6}}\) |
\(\Big \downarrow \) 807 |
\(\displaystyle \frac {(7 b c-10 a d) \int \frac {x^8}{\left (b x^6+a\right )^{3/2}}dx^2}{14 b}+\frac {d x^{10}}{7 b \sqrt {a+b x^6}}\) |
\(\Big \downarrow \) 817 |
\(\displaystyle \frac {(7 b c-10 a d) \left (\frac {4 \int \frac {x^2}{\sqrt {b x^6+a}}dx^2}{3 b}-\frac {2 x^4}{3 b \sqrt {a+b x^6}}\right )}{14 b}+\frac {d x^{10}}{7 b \sqrt {a+b x^6}}\) |
\(\Big \downarrow \) 832 |
\(\displaystyle \frac {(7 b c-10 a d) \left (\frac {4 \left (\frac {\int \frac {\sqrt [3]{b} x^2+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt {b x^6+a}}dx^2}{\sqrt [3]{b}}-\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a} \int \frac {1}{\sqrt {b x^6+a}}dx^2}{\sqrt [3]{b}}\right )}{3 b}-\frac {2 x^4}{3 b \sqrt {a+b x^6}}\right )}{14 b}+\frac {d x^{10}}{7 b \sqrt {a+b x^6}}\) |
\(\Big \downarrow \) 759 |
\(\displaystyle \frac {(7 b c-10 a d) \left (\frac {4 \left (\frac {\int \frac {\sqrt [3]{b} x^2+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt {b x^6+a}}dx^2}{\sqrt [3]{b}}-\frac {2 \left (1-\sqrt {3}\right ) \sqrt {2+\sqrt {3}} \sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x^2+b^{2/3} x^4}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [3]{b} x^2+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x^2+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right ),-7-4 \sqrt {3}\right )}{\sqrt [4]{3} b^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} \sqrt {a+b x^6}}\right )}{3 b}-\frac {2 x^4}{3 b \sqrt {a+b x^6}}\right )}{14 b}+\frac {d x^{10}}{7 b \sqrt {a+b x^6}}\) |
\(\Big \downarrow \) 2416 |
\(\displaystyle \frac {(7 b c-10 a d) \left (\frac {4 \left (\frac {\frac {2 \sqrt {a+b x^6}}{\sqrt [3]{b} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )}-\frac {\sqrt [4]{3} \sqrt {2-\sqrt {3}} \sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x^2+b^{2/3} x^4}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} E\left (\arcsin \left (\frac {\sqrt [3]{b} x^2+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x^2+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right )|-7-4 \sqrt {3}\right )}{\sqrt [3]{b} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} \sqrt {a+b x^6}}}{\sqrt [3]{b}}-\frac {2 \left (1-\sqrt {3}\right ) \sqrt {2+\sqrt {3}} \sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x^2+b^{2/3} x^4}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [3]{b} x^2+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x^2+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right ),-7-4 \sqrt {3}\right )}{\sqrt [4]{3} b^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x^2\right )^2}} \sqrt {a+b x^6}}\right )}{3 b}-\frac {2 x^4}{3 b \sqrt {a+b x^6}}\right )}{14 b}+\frac {d x^{10}}{7 b \sqrt {a+b x^6}}\) |
Input:
Int[(x^9*(c + d*x^6))/(a + b*x^6)^(3/2),x]
Output:
(d*x^10)/(7*b*Sqrt[a + b*x^6]) + ((7*b*c - 10*a*d)*((-2*x^4)/(3*b*Sqrt[a + b*x^6]) + (4*(((2*Sqrt[a + b*x^6])/(b^(1/3)*((1 + Sqrt[3])*a^(1/3) + b^(1 /3)*x^2)) - (3^(1/4)*Sqrt[2 - Sqrt[3]]*a^(1/3)*(a^(1/3) + b^(1/3)*x^2)*Sqr t[(a^(2/3) - a^(1/3)*b^(1/3)*x^2 + b^(2/3)*x^4)/((1 + Sqrt[3])*a^(1/3) + b ^(1/3)*x^2)^2]*EllipticE[ArcSin[((1 - Sqrt[3])*a^(1/3) + b^(1/3)*x^2)/((1 + Sqrt[3])*a^(1/3) + b^(1/3)*x^2)], -7 - 4*Sqrt[3]])/(b^(1/3)*Sqrt[(a^(1/3 )*(a^(1/3) + b^(1/3)*x^2))/((1 + Sqrt[3])*a^(1/3) + b^(1/3)*x^2)^2]*Sqrt[a + b*x^6]))/b^(1/3) - (2*(1 - Sqrt[3])*Sqrt[2 + Sqrt[3]]*a^(1/3)*(a^(1/3) + b^(1/3)*x^2)*Sqrt[(a^(2/3) - a^(1/3)*b^(1/3)*x^2 + b^(2/3)*x^4)/((1 + Sq rt[3])*a^(1/3) + b^(1/3)*x^2)^2]*EllipticF[ArcSin[((1 - Sqrt[3])*a^(1/3) + b^(1/3)*x^2)/((1 + Sqrt[3])*a^(1/3) + b^(1/3)*x^2)], -7 - 4*Sqrt[3]])/(3^ (1/4)*b^(2/3)*Sqrt[(a^(1/3)*(a^(1/3) + b^(1/3)*x^2))/((1 + Sqrt[3])*a^(1/3 ) + b^(1/3)*x^2)^2]*Sqrt[a + b*x^6])))/(3*b)))/(14*b)
Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt[2 + Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s *x + r^2*x^2)/((1 + Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[s* ((s + r*x)/((1 + Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 - Sqrt[3])*s + r*x)/((1 + Sqrt[3])*s + r*x)], -7 - 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x] & & PosQ[a]
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Simp[1/k Subst[Int[x^((m + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[c^( n - 1)*(c*x)^(m - n + 1)*((a + b*x^n)^(p + 1)/(b*n*(p + 1))), x] - Simp[c^n *((m - n + 1)/(b*n*(p + 1))) Int[(c*x)^(m - n)*(a + b*x^n)^(p + 1), x], x ] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0] && LtQ[p, -1] && GtQ[m + 1, n] && ! ILtQ[(m + n*(p + 1) + 1)/n, 0] && IntBinomialQ[a, b, c, n, m, p, x]
Int[(x_)/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3] ], s = Denom[Rt[b/a, 3]]}, Simp[(-(1 - Sqrt[3]))*(s/r) Int[1/Sqrt[a + b*x ^3], x], x] + Simp[1/r Int[((1 - Sqrt[3])*s + r*x)/Sqrt[a + b*x^3], x], x ]] /; FreeQ[{a, b}, x] && PosQ[a]
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n _)), x_Symbol] :> Simp[d*(e*x)^(m + 1)*((a + b*x^n)^(p + 1)/(b*e*(m + n*(p + 1) + 1))), x] - Simp[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(b*(m + n*(p + 1) + 1)) Int[(e*x)^m*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0] && NeQ[m + n*(p + 1) + 1, 0]
Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = N umer[Simplify[(1 - Sqrt[3])*(d/c)]], s = Denom[Simplify[(1 - Sqrt[3])*(d/c) ]]}, Simp[2*d*s^3*(Sqrt[a + b*x^3]/(a*r^2*((1 + Sqrt[3])*s + r*x))), x] - S imp[3^(1/4)*Sqrt[2 - Sqrt[3]]*d*s*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/( (1 + Sqrt[3])*s + r*x)^2]/(r^2*Sqrt[a + b*x^3]*Sqrt[s*((s + r*x)/((1 + Sqrt [3])*s + r*x)^2)]))*EllipticE[ArcSin[((1 - Sqrt[3])*s + r*x)/((1 + Sqrt[3]) *s + r*x)], -7 - 4*Sqrt[3]], x]] /; FreeQ[{a, b, c, d}, x] && PosQ[a] && Eq Q[b*c^3 - 2*(5 - 3*Sqrt[3])*a*d^3, 0]
\[\int \frac {x^{9} \left (d \,x^{6}+c \right )}{\left (b \,x^{6}+a \right )^{\frac {3}{2}}}d x\]
Input:
int(x^9*(d*x^6+c)/(b*x^6+a)^(3/2),x)
Output:
int(x^9*(d*x^6+c)/(b*x^6+a)^(3/2),x)
Time = 0.08 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.19 \[ \int \frac {x^9 \left (c+d x^6\right )}{\left (a+b x^6\right )^{3/2}} \, dx=-\frac {4 \, {\left ({\left (7 \, b^{2} c - 10 \, a b d\right )} x^{6} + 7 \, a b c - 10 \, a^{2} d\right )} \sqrt {b} {\rm weierstrassZeta}\left (0, -\frac {4 \, a}{b}, {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x^{2}\right )\right ) - {\left (3 \, b^{2} d x^{10} - {\left (7 \, b^{2} c - 10 \, a b d\right )} x^{4}\right )} \sqrt {b x^{6} + a}}{21 \, {\left (b^{4} x^{6} + a b^{3}\right )}} \] Input:
integrate(x^9*(d*x^6+c)/(b*x^6+a)^(3/2),x, algorithm="fricas")
Output:
-1/21*(4*((7*b^2*c - 10*a*b*d)*x^6 + 7*a*b*c - 10*a^2*d)*sqrt(b)*weierstra ssZeta(0, -4*a/b, weierstrassPInverse(0, -4*a/b, x^2)) - (3*b^2*d*x^10 - ( 7*b^2*c - 10*a*b*d)*x^4)*sqrt(b*x^6 + a))/(b^4*x^6 + a*b^3)
Time = 17.23 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.14 \[ \int \frac {x^9 \left (c+d x^6\right )}{\left (a+b x^6\right )^{3/2}} \, dx=\frac {c x^{10} \Gamma \left (\frac {5}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{2}, \frac {5}{3} \\ \frac {8}{3} \end {matrix}\middle | {\frac {b x^{6} e^{i \pi }}{a}} \right )}}{6 a^{\frac {3}{2}} \Gamma \left (\frac {8}{3}\right )} + \frac {d x^{16} \Gamma \left (\frac {8}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{2}, \frac {8}{3} \\ \frac {11}{3} \end {matrix}\middle | {\frac {b x^{6} e^{i \pi }}{a}} \right )}}{6 a^{\frac {3}{2}} \Gamma \left (\frac {11}{3}\right )} \] Input:
integrate(x**9*(d*x**6+c)/(b*x**6+a)**(3/2),x)
Output:
c*x**10*gamma(5/3)*hyper((3/2, 5/3), (8/3,), b*x**6*exp_polar(I*pi)/a)/(6* a**(3/2)*gamma(8/3)) + d*x**16*gamma(8/3)*hyper((3/2, 8/3), (11/3,), b*x** 6*exp_polar(I*pi)/a)/(6*a**(3/2)*gamma(11/3))
\[ \int \frac {x^9 \left (c+d x^6\right )}{\left (a+b x^6\right )^{3/2}} \, dx=\int { \frac {{\left (d x^{6} + c\right )} x^{9}}{{\left (b x^{6} + a\right )}^{\frac {3}{2}}} \,d x } \] Input:
integrate(x^9*(d*x^6+c)/(b*x^6+a)^(3/2),x, algorithm="maxima")
Output:
integrate((d*x^6 + c)*x^9/(b*x^6 + a)^(3/2), x)
\[ \int \frac {x^9 \left (c+d x^6\right )}{\left (a+b x^6\right )^{3/2}} \, dx=\int { \frac {{\left (d x^{6} + c\right )} x^{9}}{{\left (b x^{6} + a\right )}^{\frac {3}{2}}} \,d x } \] Input:
integrate(x^9*(d*x^6+c)/(b*x^6+a)^(3/2),x, algorithm="giac")
Output:
integrate((d*x^6 + c)*x^9/(b*x^6 + a)^(3/2), x)
Timed out. \[ \int \frac {x^9 \left (c+d x^6\right )}{\left (a+b x^6\right )^{3/2}} \, dx=\int \frac {x^9\,\left (d\,x^6+c\right )}{{\left (b\,x^6+a\right )}^{3/2}} \,d x \] Input:
int((x^9*(c + d*x^6))/(a + b*x^6)^(3/2),x)
Output:
int((x^9*(c + d*x^6))/(a + b*x^6)^(3/2), x)
\[ \int \frac {x^9 \left (c+d x^6\right )}{\left (a+b x^6\right )^{3/2}} \, dx=\frac {-10 \sqrt {b \,x^{6}+a}\, a d \,x^{4}+7 \sqrt {b \,x^{6}+a}\, b c \,x^{4}+\sqrt {b \,x^{6}+a}\, b d \,x^{10}+40 \left (\int \frac {\sqrt {b \,x^{6}+a}\, x^{3}}{b^{2} x^{12}+2 a b \,x^{6}+a^{2}}d x \right ) a^{3} d -28 \left (\int \frac {\sqrt {b \,x^{6}+a}\, x^{3}}{b^{2} x^{12}+2 a b \,x^{6}+a^{2}}d x \right ) a^{2} b c +40 \left (\int \frac {\sqrt {b \,x^{6}+a}\, x^{3}}{b^{2} x^{12}+2 a b \,x^{6}+a^{2}}d x \right ) a^{2} b d \,x^{6}-28 \left (\int \frac {\sqrt {b \,x^{6}+a}\, x^{3}}{b^{2} x^{12}+2 a b \,x^{6}+a^{2}}d x \right ) a \,b^{2} c \,x^{6}}{7 b^{2} \left (b \,x^{6}+a \right )} \] Input:
int(x^9*(d*x^6+c)/(b*x^6+a)^(3/2),x)
Output:
( - 10*sqrt(a + b*x**6)*a*d*x**4 + 7*sqrt(a + b*x**6)*b*c*x**4 + sqrt(a + b*x**6)*b*d*x**10 + 40*int((sqrt(a + b*x**6)*x**3)/(a**2 + 2*a*b*x**6 + b* *2*x**12),x)*a**3*d - 28*int((sqrt(a + b*x**6)*x**3)/(a**2 + 2*a*b*x**6 + b**2*x**12),x)*a**2*b*c + 40*int((sqrt(a + b*x**6)*x**3)/(a**2 + 2*a*b*x** 6 + b**2*x**12),x)*a**2*b*d*x**6 - 28*int((sqrt(a + b*x**6)*x**3)/(a**2 + 2*a*b*x**6 + b**2*x**12),x)*a*b**2*c*x**6)/(7*b**2*(a + b*x**6))