Integrand size = 22, antiderivative size = 302 \[ \int \frac {c+d x^6}{x^6 \left (a+b x^6\right )^{5/2}} \, dx=-\frac {c}{5 a x^5 \left (a+b x^6\right )^{3/2}}-\frac {(14 b c-5 a d) x}{45 a^2 \left (a+b x^6\right )^{3/2}}-\frac {8 (14 b c-5 a d) x}{135 a^3 \sqrt {a+b x^6}}-\frac {8 (14 b c-5 a d) x \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x^2+b^{2/3} x^4}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x^2\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\sqrt [3]{a}+\left (1-\sqrt {3}\right ) \sqrt [3]{b} x^2}{\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x^2}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{135 \sqrt [4]{3} a^{10/3} \sqrt {\frac {\sqrt [3]{b} x^2 \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x^2\right )^2}} \sqrt {a+b x^6}} \] Output:
-1/5*c/a/x^5/(b*x^6+a)^(3/2)-1/45*(-5*a*d+14*b*c)*x/a^2/(b*x^6+a)^(3/2)-8/ 135*(-5*a*d+14*b*c)*x/a^3/(b*x^6+a)^(1/2)-8/405*(-5*a*d+14*b*c)*x*(a^(1/3) +b^(1/3)*x^2)*((a^(2/3)-a^(1/3)*b^(1/3)*x^2+b^(2/3)*x^4)/(a^(1/3)+(1+3^(1/ 2))*b^(1/3)*x^2)^2)^(1/2)*InverseJacobiAM(arccos((a^(1/3)+(1-3^(1/2))*b^(1 /3)*x^2)/(a^(1/3)+(1+3^(1/2))*b^(1/3)*x^2)),1/4*6^(1/2)+1/4*2^(1/2))*3^(3/ 4)/a^(10/3)/(b^(1/3)*x^2*(a^(1/3)+b^(1/3)*x^2)/(a^(1/3)+(1+3^(1/2))*b^(1/3 )*x^2)^2)^(1/2)/(b*x^6+a)^(1/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.07 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.38 \[ \int \frac {c+d x^6}{x^6 \left (a+b x^6\right )^{5/2}} \, dx=\frac {-112 b^2 c x^{12}+2 a b x^6 \left (-77 c+20 d x^6\right )+a^2 \left (-27 c+55 d x^6\right )+16 (-14 b c+5 a d) x^6 \left (a+b x^6\right ) \sqrt {1+\frac {b x^6}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{2},\frac {7}{6},-\frac {b x^6}{a}\right )}{135 a^3 x^5 \left (a+b x^6\right )^{3/2}} \] Input:
Integrate[(c + d*x^6)/(x^6*(a + b*x^6)^(5/2)),x]
Output:
(-112*b^2*c*x^12 + 2*a*b*x^6*(-77*c + 20*d*x^6) + a^2*(-27*c + 55*d*x^6) + 16*(-14*b*c + 5*a*d)*x^6*(a + b*x^6)*Sqrt[1 + (b*x^6)/a]*Hypergeometric2F 1[1/6, 1/2, 7/6, -((b*x^6)/a)])/(135*a^3*x^5*(a + b*x^6)^(3/2))
Time = 0.54 (sec) , antiderivative size = 300, normalized size of antiderivative = 0.99, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {955, 749, 749, 766}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {c+d x^6}{x^6 \left (a+b x^6\right )^{5/2}} \, dx\) |
\(\Big \downarrow \) 955 |
\(\displaystyle -\frac {(14 b c-5 a d) \int \frac {1}{\left (b x^6+a\right )^{5/2}}dx}{5 a}-\frac {c}{5 a x^5 \left (a+b x^6\right )^{3/2}}\) |
\(\Big \downarrow \) 749 |
\(\displaystyle -\frac {(14 b c-5 a d) \left (\frac {8 \int \frac {1}{\left (b x^6+a\right )^{3/2}}dx}{9 a}+\frac {x}{9 a \left (a+b x^6\right )^{3/2}}\right )}{5 a}-\frac {c}{5 a x^5 \left (a+b x^6\right )^{3/2}}\) |
\(\Big \downarrow \) 749 |
\(\displaystyle -\frac {(14 b c-5 a d) \left (\frac {8 \left (\frac {2 \int \frac {1}{\sqrt {b x^6+a}}dx}{3 a}+\frac {x}{3 a \sqrt {a+b x^6}}\right )}{9 a}+\frac {x}{9 a \left (a+b x^6\right )^{3/2}}\right )}{5 a}-\frac {c}{5 a x^5 \left (a+b x^6\right )^{3/2}}\) |
\(\Big \downarrow \) 766 |
\(\displaystyle -\frac {(14 b c-5 a d) \left (\frac {8 \left (\frac {x \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x^2+b^{2/3} x^4}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x^2\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{b} x^2+\sqrt [3]{a}}{\left (1+\sqrt {3}\right ) \sqrt [3]{b} x^2+\sqrt [3]{a}}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{3 \sqrt [4]{3} a^{4/3} \sqrt {\frac {\sqrt [3]{b} x^2 \left (\sqrt [3]{a}+\sqrt [3]{b} x^2\right )}{\left (\sqrt [3]{a}+\left (1+\sqrt {3}\right ) \sqrt [3]{b} x^2\right )^2}} \sqrt {a+b x^6}}+\frac {x}{3 a \sqrt {a+b x^6}}\right )}{9 a}+\frac {x}{9 a \left (a+b x^6\right )^{3/2}}\right )}{5 a}-\frac {c}{5 a x^5 \left (a+b x^6\right )^{3/2}}\) |
Input:
Int[(c + d*x^6)/(x^6*(a + b*x^6)^(5/2)),x]
Output:
-1/5*c/(a*x^5*(a + b*x^6)^(3/2)) - ((14*b*c - 5*a*d)*(x/(9*a*(a + b*x^6)^( 3/2)) + (8*(x/(3*a*Sqrt[a + b*x^6]) + (x*(a^(1/3) + b^(1/3)*x^2)*Sqrt[(a^( 2/3) - a^(1/3)*b^(1/3)*x^2 + b^(2/3)*x^4)/(a^(1/3) + (1 + Sqrt[3])*b^(1/3) *x^2)^2]*EllipticF[ArcCos[(a^(1/3) + (1 - Sqrt[3])*b^(1/3)*x^2)/(a^(1/3) + (1 + Sqrt[3])*b^(1/3)*x^2)], (2 + Sqrt[3])/4])/(3*3^(1/4)*a^(4/3)*Sqrt[(b ^(1/3)*x^2*(a^(1/3) + b^(1/3)*x^2))/(a^(1/3) + (1 + Sqrt[3])*b^(1/3)*x^2)^ 2]*Sqrt[a + b*x^6])))/(9*a)))/(5*a)
Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(-x)*((a + b*x^n)^(p + 1)/(a*n*(p + 1))), x] + Simp[(n*(p + 1) + 1)/(a*n*(p + 1)) Int[(a + b*x^ n)^(p + 1), x], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[p, -1] && (Inte gerQ[2*p] || Denominator[p + 1/n] < Denominator[p])
Int[1/Sqrt[(a_) + (b_.)*(x_)^6], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[x*(s + r*x^2)*(Sqrt[(s^2 - r*s*x^2 + r^2*x^4)/ (s + (1 + Sqrt[3])*r*x^2)^2]/(2*3^(1/4)*s*Sqrt[a + b*x^6]*Sqrt[r*x^2*((s + r*x^2)/(s + (1 + Sqrt[3])*r*x^2)^2)]))*EllipticF[ArcCos[(s + (1 - Sqrt[3])* r*x^2)/(s + (1 + Sqrt[3])*r*x^2)], (2 + Sqrt[3])/4], x]] /; FreeQ[{a, b}, x ]
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n _)), x_Symbol] :> Simp[c*(e*x)^(m + 1)*((a + b*x^n)^(p + 1)/(a*e*(m + 1))), x] + Simp[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(a*e^n*(m + 1)) Int[(e *x)^(m + n)*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[b* c - a*d, 0] && (IntegerQ[n] || GtQ[e, 0]) && ((GtQ[n, 0] && LtQ[m, -1]) || (LtQ[n, 0] && GtQ[m + n, -1])) && !ILtQ[p, -1]
\[\int \frac {d \,x^{6}+c}{x^{6} \left (b \,x^{6}+a \right )^{\frac {5}{2}}}d x\]
Input:
int((d*x^6+c)/x^6/(b*x^6+a)^(5/2),x)
Output:
int((d*x^6+c)/x^6/(b*x^6+a)^(5/2),x)
\[ \int \frac {c+d x^6}{x^6 \left (a+b x^6\right )^{5/2}} \, dx=\int { \frac {d x^{6} + c}{{\left (b x^{6} + a\right )}^{\frac {5}{2}} x^{6}} \,d x } \] Input:
integrate((d*x^6+c)/x^6/(b*x^6+a)^(5/2),x, algorithm="fricas")
Output:
integral(sqrt(b*x^6 + a)*(d*x^6 + c)/(b^3*x^24 + 3*a*b^2*x^18 + 3*a^2*b*x^ 12 + a^3*x^6), x)
Timed out. \[ \int \frac {c+d x^6}{x^6 \left (a+b x^6\right )^{5/2}} \, dx=\text {Timed out} \] Input:
integrate((d*x**6+c)/x**6/(b*x**6+a)**(5/2),x)
Output:
Timed out
\[ \int \frac {c+d x^6}{x^6 \left (a+b x^6\right )^{5/2}} \, dx=\int { \frac {d x^{6} + c}{{\left (b x^{6} + a\right )}^{\frac {5}{2}} x^{6}} \,d x } \] Input:
integrate((d*x^6+c)/x^6/(b*x^6+a)^(5/2),x, algorithm="maxima")
Output:
integrate((d*x^6 + c)/((b*x^6 + a)^(5/2)*x^6), x)
\[ \int \frac {c+d x^6}{x^6 \left (a+b x^6\right )^{5/2}} \, dx=\int { \frac {d x^{6} + c}{{\left (b x^{6} + a\right )}^{\frac {5}{2}} x^{6}} \,d x } \] Input:
integrate((d*x^6+c)/x^6/(b*x^6+a)^(5/2),x, algorithm="giac")
Output:
integrate((d*x^6 + c)/((b*x^6 + a)^(5/2)*x^6), x)
Timed out. \[ \int \frac {c+d x^6}{x^6 \left (a+b x^6\right )^{5/2}} \, dx=\int \frac {d\,x^6+c}{x^6\,{\left (b\,x^6+a\right )}^{5/2}} \,d x \] Input:
int((c + d*x^6)/(x^6*(a + b*x^6)^(5/2)),x)
Output:
int((c + d*x^6)/(x^6*(a + b*x^6)^(5/2)), x)
\[ \int \frac {c+d x^6}{x^6 \left (a+b x^6\right )^{5/2}} \, dx=\frac {-\sqrt {b \,x^{6}+a}\, d -5 \left (\int \frac {\sqrt {b \,x^{6}+a}}{b^{3} x^{24}+3 a \,b^{2} x^{18}+3 a^{2} b \,x^{12}+a^{3} x^{6}}d x \right ) a^{3} d \,x^{5}+14 \left (\int \frac {\sqrt {b \,x^{6}+a}}{b^{3} x^{24}+3 a \,b^{2} x^{18}+3 a^{2} b \,x^{12}+a^{3} x^{6}}d x \right ) a^{2} b c \,x^{5}-10 \left (\int \frac {\sqrt {b \,x^{6}+a}}{b^{3} x^{24}+3 a \,b^{2} x^{18}+3 a^{2} b \,x^{12}+a^{3} x^{6}}d x \right ) a^{2} b d \,x^{11}+28 \left (\int \frac {\sqrt {b \,x^{6}+a}}{b^{3} x^{24}+3 a \,b^{2} x^{18}+3 a^{2} b \,x^{12}+a^{3} x^{6}}d x \right ) a \,b^{2} c \,x^{11}-5 \left (\int \frac {\sqrt {b \,x^{6}+a}}{b^{3} x^{24}+3 a \,b^{2} x^{18}+3 a^{2} b \,x^{12}+a^{3} x^{6}}d x \right ) a \,b^{2} d \,x^{17}+14 \left (\int \frac {\sqrt {b \,x^{6}+a}}{b^{3} x^{24}+3 a \,b^{2} x^{18}+3 a^{2} b \,x^{12}+a^{3} x^{6}}d x \right ) b^{3} c \,x^{17}}{14 b \,x^{5} \left (b^{2} x^{12}+2 a b \,x^{6}+a^{2}\right )} \] Input:
int((d*x^6+c)/x^6/(b*x^6+a)^(5/2),x)
Output:
( - sqrt(a + b*x**6)*d - 5*int(sqrt(a + b*x**6)/(a**3*x**6 + 3*a**2*b*x**1 2 + 3*a*b**2*x**18 + b**3*x**24),x)*a**3*d*x**5 + 14*int(sqrt(a + b*x**6)/ (a**3*x**6 + 3*a**2*b*x**12 + 3*a*b**2*x**18 + b**3*x**24),x)*a**2*b*c*x** 5 - 10*int(sqrt(a + b*x**6)/(a**3*x**6 + 3*a**2*b*x**12 + 3*a*b**2*x**18 + b**3*x**24),x)*a**2*b*d*x**11 + 28*int(sqrt(a + b*x**6)/(a**3*x**6 + 3*a* *2*b*x**12 + 3*a*b**2*x**18 + b**3*x**24),x)*a*b**2*c*x**11 - 5*int(sqrt(a + b*x**6)/(a**3*x**6 + 3*a**2*b*x**12 + 3*a*b**2*x**18 + b**3*x**24),x)*a *b**2*d*x**17 + 14*int(sqrt(a + b*x**6)/(a**3*x**6 + 3*a**2*b*x**12 + 3*a* b**2*x**18 + b**3*x**24),x)*b**3*c*x**17)/(14*b*x**5*(a**2 + 2*a*b*x**6 + b**2*x**12))