Integrand size = 31, antiderivative size = 336 \[ \int (e x)^m \left (a+b x^n\right )^3 \left (A+B x^n\right ) \left (c+d x^n\right )^2 \, dx=\frac {a^3 A c^2 (e x)^{1+m}}{e (1+m)}+\frac {a^2 c (3 A b c+a B c+2 a A d) x^n (e x)^{1+m}}{e (1+m+n)}+\frac {a \left (a B c (3 b c+2 a d)+A \left (3 b^2 c^2+6 a b c d+a^2 d^2\right )\right ) x^{2 n} (e x)^{1+m}}{e (1+m+2 n)}+\frac {\left (a B \left (3 b^2 c^2+6 a b c d+a^2 d^2\right )+A b \left (b^2 c^2+6 a b c d+3 a^2 d^2\right )\right ) x^{3 n} (e x)^{1+m}}{e (1+m+3 n)}+\frac {b \left (3 a^2 B d^2+3 a b d (2 B c+A d)+b^2 c (B c+2 A d)\right ) x^{4 n} (e x)^{1+m}}{e (1+m+4 n)}+\frac {b^2 d (2 b B c+A b d+3 a B d) x^{5 n} (e x)^{1+m}}{e (1+m+5 n)}+\frac {b^3 B d^2 x^{6 n} (e x)^{1+m}}{e (1+m+6 n)} \] Output:
a^3*A*c^2*(e*x)^(1+m)/e/(1+m)+a^2*c*(2*A*a*d+3*A*b*c+B*a*c)*x^n*(e*x)^(1+m )/e/(1+m+n)+a*(a*B*c*(2*a*d+3*b*c)+A*(a^2*d^2+6*a*b*c*d+3*b^2*c^2))*x^(2*n )*(e*x)^(1+m)/e/(1+m+2*n)+(a*B*(a^2*d^2+6*a*b*c*d+3*b^2*c^2)+A*b*(3*a^2*d^ 2+6*a*b*c*d+b^2*c^2))*x^(3*n)*(e*x)^(1+m)/e/(1+m+3*n)+b*(3*a^2*B*d^2+3*a*b *d*(A*d+2*B*c)+b^2*c*(2*A*d+B*c))*x^(4*n)*(e*x)^(1+m)/e/(1+m+4*n)+b^2*d*(A *b*d+3*B*a*d+2*B*b*c)*x^(5*n)*(e*x)^(1+m)/e/(1+m+5*n)+b^3*B*d^2*x^(6*n)*(e *x)^(1+m)/e/(1+m+6*n)
Time = 1.20 (sec) , antiderivative size = 273, normalized size of antiderivative = 0.81 \[ \int (e x)^m \left (a+b x^n\right )^3 \left (A+B x^n\right ) \left (c+d x^n\right )^2 \, dx=x (e x)^m \left (\frac {a^3 A c^2}{1+m}+\frac {a^2 c (3 A b c+a B c+2 a A d) x^n}{1+m+n}+\frac {a \left (a B c (3 b c+2 a d)+A \left (3 b^2 c^2+6 a b c d+a^2 d^2\right )\right ) x^{2 n}}{1+m+2 n}+\frac {\left (a B \left (3 b^2 c^2+6 a b c d+a^2 d^2\right )+A b \left (b^2 c^2+6 a b c d+3 a^2 d^2\right )\right ) x^{3 n}}{1+m+3 n}+\frac {b \left (3 a^2 B d^2+3 a b d (2 B c+A d)+b^2 c (B c+2 A d)\right ) x^{4 n}}{1+m+4 n}+\frac {b^2 d (2 b B c+A b d+3 a B d) x^{5 n}}{1+m+5 n}+\frac {b^3 B d^2 x^{6 n}}{1+m+6 n}\right ) \] Input:
Integrate[(e*x)^m*(a + b*x^n)^3*(A + B*x^n)*(c + d*x^n)^2,x]
Output:
x*(e*x)^m*((a^3*A*c^2)/(1 + m) + (a^2*c*(3*A*b*c + a*B*c + 2*a*A*d)*x^n)/( 1 + m + n) + (a*(a*B*c*(3*b*c + 2*a*d) + A*(3*b^2*c^2 + 6*a*b*c*d + a^2*d^ 2))*x^(2*n))/(1 + m + 2*n) + ((a*B*(3*b^2*c^2 + 6*a*b*c*d + a^2*d^2) + A*b *(b^2*c^2 + 6*a*b*c*d + 3*a^2*d^2))*x^(3*n))/(1 + m + 3*n) + (b*(3*a^2*B*d ^2 + 3*a*b*d*(2*B*c + A*d) + b^2*c*(B*c + 2*A*d))*x^(4*n))/(1 + m + 4*n) + (b^2*d*(2*b*B*c + A*b*d + 3*a*B*d)*x^(5*n))/(1 + m + 5*n) + (b^3*B*d^2*x^ (6*n))/(1 + m + 6*n))
Time = 1.04 (sec) , antiderivative size = 318, normalized size of antiderivative = 0.95, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.065, Rules used = {1040, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int (e x)^m \left (a+b x^n\right )^3 \left (A+B x^n\right ) \left (c+d x^n\right )^2 \, dx\) |
\(\Big \downarrow \) 1040 |
\(\displaystyle \int \left (a^3 A c^2 (e x)^m+a x^{2 n} (e x)^m \left (A \left (a^2 d^2+6 a b c d+3 b^2 c^2\right )+a B c (2 a d+3 b c)\right )+x^{3 n} (e x)^m \left (A b \left (3 a^2 d^2+6 a b c d+b^2 c^2\right )+a B \left (a^2 d^2+6 a b c d+3 b^2 c^2\right )\right )+b x^{4 n} (e x)^m \left (3 a^2 B d^2+3 a b d (A d+2 B c)+b^2 c (2 A d+B c)\right )+a^2 c x^n (e x)^m (2 a A d+a B c+3 A b c)+b^2 d x^{5 n} (e x)^m (3 a B d+A b d+2 b B c)+b^3 B d^2 x^{6 n} (e x)^m\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {a^3 A c^2 (e x)^{m+1}}{e (m+1)}+\frac {a x^{2 n+1} (e x)^m \left (A \left (a^2 d^2+6 a b c d+3 b^2 c^2\right )+a B c (2 a d+3 b c)\right )}{m+2 n+1}+\frac {x^{3 n+1} (e x)^m \left (A b \left (3 a^2 d^2+6 a b c d+b^2 c^2\right )+a B \left (a^2 d^2+6 a b c d+3 b^2 c^2\right )\right )}{m+3 n+1}+\frac {b x^{4 n+1} (e x)^m \left (3 a^2 B d^2+3 a b d (A d+2 B c)+b^2 c (2 A d+B c)\right )}{m+4 n+1}+\frac {a^2 c x^{n+1} (e x)^m (2 a A d+a B c+3 A b c)}{m+n+1}+\frac {b^2 d x^{5 n+1} (e x)^m (3 a B d+A b d+2 b B c)}{m+5 n+1}+\frac {b^3 B d^2 x^{6 n+1} (e x)^m}{m+6 n+1}\) |
Input:
Int[(e*x)^m*(a + b*x^n)^3*(A + B*x^n)*(c + d*x^n)^2,x]
Output:
(a^2*c*(3*A*b*c + a*B*c + 2*a*A*d)*x^(1 + n)*(e*x)^m)/(1 + m + n) + (a*(a* B*c*(3*b*c + 2*a*d) + A*(3*b^2*c^2 + 6*a*b*c*d + a^2*d^2))*x^(1 + 2*n)*(e* x)^m)/(1 + m + 2*n) + ((a*B*(3*b^2*c^2 + 6*a*b*c*d + a^2*d^2) + A*b*(b^2*c ^2 + 6*a*b*c*d + 3*a^2*d^2))*x^(1 + 3*n)*(e*x)^m)/(1 + m + 3*n) + (b*(3*a^ 2*B*d^2 + 3*a*b*d*(2*B*c + A*d) + b^2*c*(B*c + 2*A*d))*x^(1 + 4*n)*(e*x)^m )/(1 + m + 4*n) + (b^2*d*(2*b*B*c + A*b*d + 3*a*B*d)*x^(1 + 5*n)*(e*x)^m)/ (1 + m + 5*n) + (b^3*B*d^2*x^(1 + 6*n)*(e*x)^m)/(1 + m + 6*n) + (a^3*A*c^2 *(e*x)^(1 + m))/(e*(1 + m))
Int[((g_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n _))^(q_.)*((e_) + (f_.)*(x_)^(n_))^(r_.), x_Symbol] :> Int[ExpandIntegrand[ (g*x)^m*(a + b*x^n)^p*(c + d*x^n)^q*(e + f*x^n)^r, x], x] /; FreeQ[{a, b, c , d, e, f, g, m, n}, x] && IGtQ[p, -2] && IGtQ[q, 0] && IGtQ[r, 0]
Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 2.72 (sec) , antiderivative size = 11356, normalized size of antiderivative = 33.80
method | result | size |
risch | \(\text {Expression too large to display}\) | \(11356\) |
parallelrisch | \(\text {Expression too large to display}\) | \(15203\) |
orering | \(\text {Expression too large to display}\) | \(23014\) |
Input:
int((e*x)^m*(a+b*x^n)^3*(A+B*x^n)*(c+d*x^n)^2,x,method=_RETURNVERBOSE)
Output:
result too large to display
Leaf count of result is larger than twice the leaf count of optimal. 6638 vs. \(2 (336) = 672\).
Time = 0.29 (sec) , antiderivative size = 6638, normalized size of antiderivative = 19.76 \[ \int (e x)^m \left (a+b x^n\right )^3 \left (A+B x^n\right ) \left (c+d x^n\right )^2 \, dx=\text {Too large to display} \] Input:
integrate((e*x)^m*(a+b*x^n)^3*(A+B*x^n)*(c+d*x^n)^2,x, algorithm="fricas")
Output:
Too large to include
Leaf count of result is larger than twice the leaf count of optimal. 168099 vs. \(2 (332) = 664\).
Time = 29.35 (sec) , antiderivative size = 168099, normalized size of antiderivative = 500.29 \[ \int (e x)^m \left (a+b x^n\right )^3 \left (A+B x^n\right ) \left (c+d x^n\right )^2 \, dx=\text {Too large to display} \] Input:
integrate((e*x)**m*(a+b*x**n)**3*(A+B*x**n)*(c+d*x**n)**2,x)
Output:
Piecewise(((A + B)*(a + b)**3*(c + d)**2*log(x)/e, Eq(m, -1) & Eq(n, 0)), ((A*a**3*c**2*log(x) + 2*A*a**3*c*d*x**n/n + A*a**3*d**2*x**(2*n)/(2*n) + 3*A*a**2*b*c**2*x**n/n + 3*A*a**2*b*c*d*x**(2*n)/n + A*a**2*b*d**2*x**(3*n )/n + 3*A*a*b**2*c**2*x**(2*n)/(2*n) + 2*A*a*b**2*c*d*x**(3*n)/n + 3*A*a*b **2*d**2*x**(4*n)/(4*n) + A*b**3*c**2*x**(3*n)/(3*n) + A*b**3*c*d*x**(4*n) /(2*n) + A*b**3*d**2*x**(5*n)/(5*n) + B*a**3*c**2*x**n/n + B*a**3*c*d*x**( 2*n)/n + B*a**3*d**2*x**(3*n)/(3*n) + 3*B*a**2*b*c**2*x**(2*n)/(2*n) + 2*B *a**2*b*c*d*x**(3*n)/n + 3*B*a**2*b*d**2*x**(4*n)/(4*n) + B*a*b**2*c**2*x* *(3*n)/n + 3*B*a*b**2*c*d*x**(4*n)/(2*n) + 3*B*a*b**2*d**2*x**(5*n)/(5*n) + B*b**3*c**2*x**(4*n)/(4*n) + 2*B*b**3*c*d*x**(5*n)/(5*n) + B*b**3*d**2*x **(6*n)/(6*n))/e, Eq(m, -1)), (A*a**3*c**2*Piecewise((0**(-6*n - 1)*x, Eq( e, 0)), (Piecewise((-1/(6*n*(e*x)**(6*n)), Ne(n, 0)), (log(e*x), True))/e, True)) + 2*A*a**3*c*d*Piecewise((-x*x**n*(e*x)**(-6*n - 1)/(5*n), Ne(n, 0 )), (x*x**n*(e*x)**(-6*n - 1)*log(x), True)) + A*a**3*d**2*Piecewise((-x*x **(2*n)*(e*x)**(-6*n - 1)/(4*n), Ne(n, 0)), (x*x**(2*n)*(e*x)**(-6*n - 1)* log(x), True)) + 3*A*a**2*b*c**2*Piecewise((-x*x**n*(e*x)**(-6*n - 1)/(5*n ), Ne(n, 0)), (x*x**n*(e*x)**(-6*n - 1)*log(x), True)) + 6*A*a**2*b*c*d*Pi ecewise((-x*x**(2*n)*(e*x)**(-6*n - 1)/(4*n), Ne(n, 0)), (x*x**(2*n)*(e*x) **(-6*n - 1)*log(x), True)) + 3*A*a**2*b*d**2*Piecewise((-x*x**(3*n)*(e*x) **(-6*n - 1)/(3*n), Ne(n, 0)), (x*x**(3*n)*(e*x)**(-6*n - 1)*log(x), Tr...
Leaf count of result is larger than twice the leaf count of optimal. 748 vs. \(2 (336) = 672\).
Time = 0.11 (sec) , antiderivative size = 748, normalized size of antiderivative = 2.23 \[ \int (e x)^m \left (a+b x^n\right )^3 \left (A+B x^n\right ) \left (c+d x^n\right )^2 \, dx =\text {Too large to display} \] Input:
integrate((e*x)^m*(a+b*x^n)^3*(A+B*x^n)*(c+d*x^n)^2,x, algorithm="maxima")
Output:
B*b^3*d^2*e^m*x*e^(m*log(x) + 6*n*log(x))/(m + 6*n + 1) + 2*B*b^3*c*d*e^m* x*e^(m*log(x) + 5*n*log(x))/(m + 5*n + 1) + 3*B*a*b^2*d^2*e^m*x*e^(m*log(x ) + 5*n*log(x))/(m + 5*n + 1) + A*b^3*d^2*e^m*x*e^(m*log(x) + 5*n*log(x))/ (m + 5*n + 1) + B*b^3*c^2*e^m*x*e^(m*log(x) + 4*n*log(x))/(m + 4*n + 1) + 6*B*a*b^2*c*d*e^m*x*e^(m*log(x) + 4*n*log(x))/(m + 4*n + 1) + 2*A*b^3*c*d* e^m*x*e^(m*log(x) + 4*n*log(x))/(m + 4*n + 1) + 3*B*a^2*b*d^2*e^m*x*e^(m*l og(x) + 4*n*log(x))/(m + 4*n + 1) + 3*A*a*b^2*d^2*e^m*x*e^(m*log(x) + 4*n* log(x))/(m + 4*n + 1) + 3*B*a*b^2*c^2*e^m*x*e^(m*log(x) + 3*n*log(x))/(m + 3*n + 1) + A*b^3*c^2*e^m*x*e^(m*log(x) + 3*n*log(x))/(m + 3*n + 1) + 6*B* a^2*b*c*d*e^m*x*e^(m*log(x) + 3*n*log(x))/(m + 3*n + 1) + 6*A*a*b^2*c*d*e^ m*x*e^(m*log(x) + 3*n*log(x))/(m + 3*n + 1) + B*a^3*d^2*e^m*x*e^(m*log(x) + 3*n*log(x))/(m + 3*n + 1) + 3*A*a^2*b*d^2*e^m*x*e^(m*log(x) + 3*n*log(x) )/(m + 3*n + 1) + 3*B*a^2*b*c^2*e^m*x*e^(m*log(x) + 2*n*log(x))/(m + 2*n + 1) + 3*A*a*b^2*c^2*e^m*x*e^(m*log(x) + 2*n*log(x))/(m + 2*n + 1) + 2*B*a^ 3*c*d*e^m*x*e^(m*log(x) + 2*n*log(x))/(m + 2*n + 1) + 6*A*a^2*b*c*d*e^m*x* e^(m*log(x) + 2*n*log(x))/(m + 2*n + 1) + A*a^3*d^2*e^m*x*e^(m*log(x) + 2* n*log(x))/(m + 2*n + 1) + B*a^3*c^2*e^m*x*e^(m*log(x) + n*log(x))/(m + n + 1) + 3*A*a^2*b*c^2*e^m*x*e^(m*log(x) + n*log(x))/(m + n + 1) + 2*A*a^3*c* d*e^m*x*e^(m*log(x) + n*log(x))/(m + n + 1) + (e*x)^(m + 1)*A*a^3*c^2/(e*( m + 1))
Leaf count of result is larger than twice the leaf count of optimal. 70422 vs. \(2 (336) = 672\).
Time = 0.65 (sec) , antiderivative size = 70422, normalized size of antiderivative = 209.59 \[ \int (e x)^m \left (a+b x^n\right )^3 \left (A+B x^n\right ) \left (c+d x^n\right )^2 \, dx=\text {Too large to display} \] Input:
integrate((e*x)^m*(a+b*x^n)^3*(A+B*x^n)*(c+d*x^n)^2,x, algorithm="giac")
Output:
(B*b^3*d^2*m^6*x*x^(6*n)*e^(m*log(e) + m*log(x)) + 15*B*b^3*d^2*m^5*n*x*x^ (6*n)*e^(m*log(e) + m*log(x)) + 85*B*b^3*d^2*m^4*n^2*x*x^(6*n)*e^(m*log(e) + m*log(x)) + 225*B*b^3*d^2*m^3*n^3*x*x^(6*n)*e^(m*log(e) + m*log(x)) + 2 74*B*b^3*d^2*m^2*n^4*x*x^(6*n)*e^(m*log(e) + m*log(x)) + 120*B*b^3*d^2*m*n ^5*x*x^(6*n)*e^(m*log(e) + m*log(x)) + 2*B*b^3*c*d*m^6*x*x^(5*n)*e^(m*log( e) + m*log(x)) + 3*B*a*b^2*d^2*m^6*x*x^(5*n)*e^(m*log(e) + m*log(x)) + A*b ^3*d^2*m^6*x*x^(5*n)*e^(m*log(e) + m*log(x)) + B*b^3*d^2*m^6*x*x^(5*n)*e^( m*log(e) + m*log(x)) + 32*B*b^3*c*d*m^5*n*x*x^(5*n)*e^(m*log(e) + m*log(x) ) + 48*B*a*b^2*d^2*m^5*n*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 16*A*b^3*d^2* m^5*n*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 15*B*b^3*d^2*m^5*n*x*x^(5*n)*e^( m*log(e) + m*log(x)) + 190*B*b^3*c*d*m^4*n^2*x*x^(5*n)*e^(m*log(e) + m*log (x)) + 285*B*a*b^2*d^2*m^4*n^2*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 95*A*b^ 3*d^2*m^4*n^2*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 85*B*b^3*d^2*m^4*n^2*x*x ^(5*n)*e^(m*log(e) + m*log(x)) + 520*B*b^3*c*d*m^3*n^3*x*x^(5*n)*e^(m*log( e) + m*log(x)) + 780*B*a*b^2*d^2*m^3*n^3*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 260*A*b^3*d^2*m^3*n^3*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 225*B*b^3*d^2 *m^3*n^3*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 648*B*b^3*c*d*m^2*n^4*x*x^(5* n)*e^(m*log(e) + m*log(x)) + 972*B*a*b^2*d^2*m^2*n^4*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 324*A*b^3*d^2*m^2*n^4*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 2 74*B*b^3*d^2*m^2*n^4*x*x^(5*n)*e^(m*log(e) + m*log(x)) + 288*B*b^3*c*d*...
Time = 6.28 (sec) , antiderivative size = 1882, normalized size of antiderivative = 5.60 \[ \int (e x)^m \left (a+b x^n\right )^3 \left (A+B x^n\right ) \left (c+d x^n\right )^2 \, dx=\text {Too large to display} \] Input:
int((e*x)^m*(A + B*x^n)*(a + b*x^n)^3*(c + d*x^n)^2,x)
Output:
(x*x^(3*n)*(e*x)^m*(A*b^3*c^2 + B*a^3*d^2 + 3*A*a^2*b*d^2 + 3*B*a*b^2*c^2 + 6*A*a*b^2*c*d + 6*B*a^2*b*c*d)*(5*m + 18*n + 72*m*n + 363*m*n^2 + 108*m^ 2*n + 744*m*n^3 + 72*m^3*n + 508*m*n^4 + 18*m^4*n + 10*m^2 + 10*m^3 + 5*m^ 4 + m^5 + 121*n^2 + 372*n^3 + 508*n^4 + 240*n^5 + 363*m^2*n^2 + 372*m^2*n^ 3 + 121*m^3*n^2 + 1))/(6*m + 21*n + 105*m*n + 700*m*n^2 + 210*m^2*n + 2205 *m*n^3 + 210*m^3*n + 3248*m*n^4 + 105*m^4*n + 1764*m*n^5 + 21*m^5*n + 15*m ^2 + 20*m^3 + 15*m^4 + 6*m^5 + m^6 + 175*n^2 + 735*n^3 + 1624*n^4 + 1764*n ^5 + 720*n^6 + 1050*m^2*n^2 + 2205*m^2*n^3 + 700*m^3*n^2 + 1624*m^2*n^4 + 735*m^3*n^3 + 175*m^4*n^2 + 1) + (A*a^3*c^2*x*(e*x)^m)/(m + 1) + (a*x*x^(2 *n)*(e*x)^m*(A*a^2*d^2 + 3*A*b^2*c^2 + 3*B*a*b*c^2 + 2*B*a^2*c*d + 6*A*a*b *c*d)*(5*m + 19*n + 76*m*n + 411*m*n^2 + 114*m^2*n + 922*m*n^3 + 76*m^3*n + 702*m*n^4 + 19*m^4*n + 10*m^2 + 10*m^3 + 5*m^4 + m^5 + 137*n^2 + 461*n^3 + 702*n^4 + 360*n^5 + 411*m^2*n^2 + 461*m^2*n^3 + 137*m^3*n^2 + 1))/(6*m + 21*n + 105*m*n + 700*m*n^2 + 210*m^2*n + 2205*m*n^3 + 210*m^3*n + 3248*m *n^4 + 105*m^4*n + 1764*m*n^5 + 21*m^5*n + 15*m^2 + 20*m^3 + 15*m^4 + 6*m^ 5 + m^6 + 175*n^2 + 735*n^3 + 1624*n^4 + 1764*n^5 + 720*n^6 + 1050*m^2*n^2 + 2205*m^2*n^3 + 700*m^3*n^2 + 1624*m^2*n^4 + 735*m^3*n^3 + 175*m^4*n^2 + 1) + (b*x*x^(4*n)*(e*x)^m*(3*B*a^2*d^2 + B*b^2*c^2 + 3*A*a*b*d^2 + 2*A*b^ 2*c*d + 6*B*a*b*c*d)*(5*m + 17*n + 68*m*n + 321*m*n^2 + 102*m^2*n + 614*m* n^3 + 68*m^3*n + 396*m*n^4 + 17*m^4*n + 10*m^2 + 10*m^3 + 5*m^4 + m^5 +...
Time = 0.28 (sec) , antiderivative size = 6996, normalized size of antiderivative = 20.82 \[ \int (e x)^m \left (a+b x^n\right )^3 \left (A+B x^n\right ) \left (c+d x^n\right )^2 \, dx =\text {Too large to display} \] Input:
int((e*x)^m*(a+b*x^n)^3*(A+B*x^n)*(c+d*x^n)^2,x)
Output:
(x**m*e**m*x*(x**(6*n)*b**4*d**2*m**6 + 15*x**(6*n)*b**4*d**2*m**5*n + 6*x **(6*n)*b**4*d**2*m**5 + 85*x**(6*n)*b**4*d**2*m**4*n**2 + 75*x**(6*n)*b** 4*d**2*m**4*n + 15*x**(6*n)*b**4*d**2*m**4 + 225*x**(6*n)*b**4*d**2*m**3*n **3 + 340*x**(6*n)*b**4*d**2*m**3*n**2 + 150*x**(6*n)*b**4*d**2*m**3*n + 2 0*x**(6*n)*b**4*d**2*m**3 + 274*x**(6*n)*b**4*d**2*m**2*n**4 + 675*x**(6*n )*b**4*d**2*m**2*n**3 + 510*x**(6*n)*b**4*d**2*m**2*n**2 + 150*x**(6*n)*b* *4*d**2*m**2*n + 15*x**(6*n)*b**4*d**2*m**2 + 120*x**(6*n)*b**4*d**2*m*n** 5 + 548*x**(6*n)*b**4*d**2*m*n**4 + 675*x**(6*n)*b**4*d**2*m*n**3 + 340*x* *(6*n)*b**4*d**2*m*n**2 + 75*x**(6*n)*b**4*d**2*m*n + 6*x**(6*n)*b**4*d**2 *m + 120*x**(6*n)*b**4*d**2*n**5 + 274*x**(6*n)*b**4*d**2*n**4 + 225*x**(6 *n)*b**4*d**2*n**3 + 85*x**(6*n)*b**4*d**2*n**2 + 15*x**(6*n)*b**4*d**2*n + x**(6*n)*b**4*d**2 + 4*x**(5*n)*a*b**3*d**2*m**6 + 64*x**(5*n)*a*b**3*d* *2*m**5*n + 24*x**(5*n)*a*b**3*d**2*m**5 + 380*x**(5*n)*a*b**3*d**2*m**4*n **2 + 320*x**(5*n)*a*b**3*d**2*m**4*n + 60*x**(5*n)*a*b**3*d**2*m**4 + 104 0*x**(5*n)*a*b**3*d**2*m**3*n**3 + 1520*x**(5*n)*a*b**3*d**2*m**3*n**2 + 6 40*x**(5*n)*a*b**3*d**2*m**3*n + 80*x**(5*n)*a*b**3*d**2*m**3 + 1296*x**(5 *n)*a*b**3*d**2*m**2*n**4 + 3120*x**(5*n)*a*b**3*d**2*m**2*n**3 + 2280*x** (5*n)*a*b**3*d**2*m**2*n**2 + 640*x**(5*n)*a*b**3*d**2*m**2*n + 60*x**(5*n )*a*b**3*d**2*m**2 + 576*x**(5*n)*a*b**3*d**2*m*n**5 + 2592*x**(5*n)*a*b** 3*d**2*m*n**4 + 3120*x**(5*n)*a*b**3*d**2*m*n**3 + 1520*x**(5*n)*a*b**3...