Integrand size = 26, antiderivative size = 221 \[ \int \frac {(e x)^{4/3}}{(c+d x)^2 \sqrt {a+b x^2}} \, dx=\frac {3 (e x)^{7/3} \sqrt {1+\frac {b x^2}{a}} \operatorname {AppellF1}\left (\frac {7}{6},\frac {1}{2},2,\frac {13}{6},-\frac {b x^2}{a},\frac {d^2 x^2}{c^2}\right )}{7 c^2 e \sqrt {a+b x^2}}-\frac {3 d (e x)^{10/3} \sqrt {1+\frac {b x^2}{a}} \operatorname {AppellF1}\left (\frac {5}{3},\frac {1}{2},2,\frac {8}{3},-\frac {b x^2}{a},\frac {d^2 x^2}{c^2}\right )}{5 c^3 e^2 \sqrt {a+b x^2}}+\frac {3 d^2 (e x)^{13/3} \sqrt {1+\frac {b x^2}{a}} \operatorname {AppellF1}\left (\frac {13}{6},\frac {1}{2},2,\frac {19}{6},-\frac {b x^2}{a},\frac {d^2 x^2}{c^2}\right )}{13 c^4 e^3 \sqrt {a+b x^2}} \] Output:
3/7*(e*x)^(7/3)*(1+b*x^2/a)^(1/2)*AppellF1(7/6,2,1/2,13/6,d^2*x^2/c^2,-b*x ^2/a)/c^2/e/(b*x^2+a)^(1/2)-3/5*d*(e*x)^(10/3)*(1+b*x^2/a)^(1/2)*AppellF1( 5/3,2,1/2,8/3,d^2*x^2/c^2,-b*x^2/a)/c^3/e^2/(b*x^2+a)^(1/2)+3/13*d^2*(e*x) ^(13/3)*(1+b*x^2/a)^(1/2)*AppellF1(13/6,2,1/2,19/6,d^2*x^2/c^2,-b*x^2/a)/c ^4/e^3/(b*x^2+a)^(1/2)
\[ \int \frac {(e x)^{4/3}}{(c+d x)^2 \sqrt {a+b x^2}} \, dx=\int \frac {(e x)^{4/3}}{(c+d x)^2 \sqrt {a+b x^2}} \, dx \] Input:
Integrate[(e*x)^(4/3)/((c + d*x)^2*Sqrt[a + b*x^2]),x]
Output:
Integrate[(e*x)^(4/3)/((c + d*x)^2*Sqrt[a + b*x^2]), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(e x)^{4/3}}{\sqrt {a+b x^2} (c+d x)^2} \, dx\) |
\(\Big \downarrow \) 616 |
\(\displaystyle \frac {3 \int \frac {e^4 x^2}{(c e+d x e)^2 \sqrt {b x^2+a}}d\sqrt [3]{e x}}{e}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle 3 e \int \frac {e^2 x^2}{(c e+d x e)^2 \sqrt {b x^2+a}}d\sqrt [3]{e x}\) |
\(\Big \downarrow \) 1888 |
\(\displaystyle 3 e \int \frac {e^2 x^2}{(c e+d x e)^2 \sqrt {b x^2+a}}d\sqrt [3]{e x}\) |
Input:
Int[(e*x)^(4/3)/((c + d*x)^2*Sqrt[a + b*x^2]),x]
Output:
$Aborted
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((e_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = Denominator[m]}, Simp[k/e Subst[Int[x^(k*(m + 1) - 1)*(c + d*(x^k/e))^n*(a + b*(x^(2*k)/e^2))^p, x], x, (e*x)^(1/k)], x]] /; FreeQ[{a, b, c, d, e, p}, x] && ILtQ[n, 0] && FractionQ[m]
Int[((f_.)*(x_))^(m_.)*((a_) + (c_.)*(x_)^(n2_.))^(p_.)*((d_) + (e_.)*(x_)^ (n_))^(q_.), x_Symbol] :> Unintegrable[(f*x)^m*(d + e*x^n)^q*(a + c*x^(2*n) )^p, x] /; FreeQ[{a, c, d, e, f, m, n, p, q}, x] && EqQ[n2, 2*n]
\[\int \frac {\left (e x \right )^{\frac {4}{3}}}{\left (d x +c \right )^{2} \sqrt {b \,x^{2}+a}}d x\]
Input:
int((e*x)^(4/3)/(d*x+c)^2/(b*x^2+a)^(1/2),x)
Output:
int((e*x)^(4/3)/(d*x+c)^2/(b*x^2+a)^(1/2),x)
Timed out. \[ \int \frac {(e x)^{4/3}}{(c+d x)^2 \sqrt {a+b x^2}} \, dx=\text {Timed out} \] Input:
integrate((e*x)^(4/3)/(d*x+c)^2/(b*x^2+a)^(1/2),x, algorithm="fricas")
Output:
Timed out
\[ \int \frac {(e x)^{4/3}}{(c+d x)^2 \sqrt {a+b x^2}} \, dx=\int \frac {\left (e x\right )^{\frac {4}{3}}}{\sqrt {a + b x^{2}} \left (c + d x\right )^{2}}\, dx \] Input:
integrate((e*x)**(4/3)/(d*x+c)**2/(b*x**2+a)**(1/2),x)
Output:
Integral((e*x)**(4/3)/(sqrt(a + b*x**2)*(c + d*x)**2), x)
\[ \int \frac {(e x)^{4/3}}{(c+d x)^2 \sqrt {a+b x^2}} \, dx=\int { \frac {\left (e x\right )^{\frac {4}{3}}}{\sqrt {b x^{2} + a} {\left (d x + c\right )}^{2}} \,d x } \] Input:
integrate((e*x)^(4/3)/(d*x+c)^2/(b*x^2+a)^(1/2),x, algorithm="maxima")
Output:
integrate((e*x)^(4/3)/(sqrt(b*x^2 + a)*(d*x + c)^2), x)
\[ \int \frac {(e x)^{4/3}}{(c+d x)^2 \sqrt {a+b x^2}} \, dx=\int { \frac {\left (e x\right )^{\frac {4}{3}}}{\sqrt {b x^{2} + a} {\left (d x + c\right )}^{2}} \,d x } \] Input:
integrate((e*x)^(4/3)/(d*x+c)^2/(b*x^2+a)^(1/2),x, algorithm="giac")
Output:
integrate((e*x)^(4/3)/(sqrt(b*x^2 + a)*(d*x + c)^2), x)
Timed out. \[ \int \frac {(e x)^{4/3}}{(c+d x)^2 \sqrt {a+b x^2}} \, dx=\int \frac {{\left (e\,x\right )}^{4/3}}{\sqrt {b\,x^2+a}\,{\left (c+d\,x\right )}^2} \,d x \] Input:
int((e*x)^(4/3)/((a + b*x^2)^(1/2)*(c + d*x)^2),x)
Output:
int((e*x)^(4/3)/((a + b*x^2)^(1/2)*(c + d*x)^2), x)
\[ \int \frac {(e x)^{4/3}}{(c+d x)^2 \sqrt {a+b x^2}} \, dx=e^{\frac {4}{3}} \left (\int \frac {x^{\frac {4}{3}} \sqrt {b \,x^{2}+a}}{b \,d^{2} x^{4}+2 b c d \,x^{3}+a \,d^{2} x^{2}+b \,c^{2} x^{2}+2 a c d x +a \,c^{2}}d x \right ) \] Input:
int((e*x)^(4/3)/(d*x+c)^2/(b*x^2+a)^(1/2),x)
Output:
e**(1/3)*int((x**(1/3)*sqrt(a + b*x**2)*x)/(a*c**2 + 2*a*c*d*x + a*d**2*x* *2 + b*c**2*x**2 + 2*b*c*d*x**3 + b*d**2*x**4),x)*e