\(\int \frac {c+d x}{x^3 (a+b x^2)^{4/3}} \, dx\) [1633]

Optimal result
Mathematica [C] (verified)
Rubi [A] (warning: unable to verify)
Maple [F]
Fricas [F(-1)]
Sympy [A] (verification not implemented)
Maxima [F]
Giac [F]
Mupad [B] (verification not implemented)
Reduce [F]

Optimal result

Integrand size = 20, antiderivative size = 685 \[ \int \frac {c+d x}{x^3 \left (a+b x^2\right )^{4/3}} \, dx=-\frac {3 b (c+d x)}{2 a^2 \sqrt [3]{a+b x^2}}-\frac {c \left (a+b x^2\right )^{2/3}}{2 a^2 x^2}-\frac {d \left (a+b x^2\right )^{2/3}}{a^2 x}-\frac {5 b d x}{2 a^2 \left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}-\frac {2 b c \arctan \left (\frac {\sqrt [3]{a}+2 \sqrt [3]{a+b x^2}}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} a^{7/3}}+\frac {5 \sqrt [4]{3} \sqrt {2+\sqrt {3}} d \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} E\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}\right )|-7+4 \sqrt {3}\right )}{4 a^{5/3} x \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}-\frac {5 d \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}\right ),-7+4 \sqrt {3}\right )}{\sqrt {2} \sqrt [4]{3} a^{5/3} x \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}+\frac {2 b c \log (x)}{3 a^{7/3}}-\frac {b c \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{a^{7/3}} \] Output:

-3/2*b*(d*x+c)/a^2/(b*x^2+a)^(1/3)-1/2*c*(b*x^2+a)^(2/3)/a^2/x^2-d*(b*x^2+ 
a)^(2/3)/a^2/x-5/2*b*d*x/a^2/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))-2/3*b*c 
*arctan(1/3*(a^(1/3)+2*(b*x^2+a)^(1/3))*3^(1/2)/a^(1/3))*3^(1/2)/a^(7/3)+5 
/4*3^(1/4)*(1/2*6^(1/2)+1/2*2^(1/2))*d*(a^(1/3)-(b*x^2+a)^(1/3))*((a^(2/3) 
+a^(1/3)*(b*x^2+a)^(1/3)+(b*x^2+a)^(2/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^( 
1/3))^2)^(1/2)*EllipticE(((1+3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))/((1-3^(1/2) 
)*a^(1/3)-(b*x^2+a)^(1/3)),2*I-I*3^(1/2))/a^(5/3)/x/(-a^(1/3)*(a^(1/3)-(b* 
x^2+a)^(1/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))^2)^(1/2)-5/6*d*(a^(1/3 
)-(b*x^2+a)^(1/3))*((a^(2/3)+a^(1/3)*(b*x^2+a)^(1/3)+(b*x^2+a)^(2/3))/((1- 
3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3))^2)^(1/2)*EllipticF(((1+3^(1/2))*a^(1/3)- 
(b*x^2+a)^(1/3))/((1-3^(1/2))*a^(1/3)-(b*x^2+a)^(1/3)),2*I-I*3^(1/2))*2^(1 
/2)*3^(3/4)/a^(5/3)/x/(-a^(1/3)*(a^(1/3)-(b*x^2+a)^(1/3))/((1-3^(1/2))*a^( 
1/3)-(b*x^2+a)^(1/3))^2)^(1/2)+2/3*b*c*ln(x)/a^(7/3)-b*c*ln(a^(1/3)-(b*x^2 
+a)^(1/3))/a^(7/3)
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.02 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.12 \[ \int \frac {c+d x}{x^3 \left (a+b x^2\right )^{4/3}} \, dx=\frac {-2 a d \sqrt [3]{1+\frac {b x^2}{a}} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {4}{3},\frac {1}{2},-\frac {b x^2}{a}\right )-3 b c x \operatorname {Hypergeometric2F1}\left (-\frac {1}{3},2,\frac {2}{3},1+\frac {b x^2}{a}\right )}{2 a^2 x \sqrt [3]{a+b x^2}} \] Input:

Integrate[(c + d*x)/(x^3*(a + b*x^2)^(4/3)),x]
 

Output:

(-2*a*d*(1 + (b*x^2)/a)^(1/3)*Hypergeometric2F1[-1/2, 4/3, 1/2, -((b*x^2)/ 
a)] - 3*b*c*x*Hypergeometric2F1[-1/3, 2, 2/3, 1 + (b*x^2)/a])/(2*a^2*x*(a 
+ b*x^2)^(1/3))
 

Rubi [A] (warning: unable to verify)

Time = 0.74 (sec) , antiderivative size = 761, normalized size of antiderivative = 1.11, number of steps used = 15, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.700, Rules used = {542, 243, 52, 61, 67, 16, 253, 264, 233, 833, 760, 1082, 217, 2418}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {c+d x}{x^3 \left (a+b x^2\right )^{4/3}} \, dx\)

\(\Big \downarrow \) 542

\(\displaystyle c \int \frac {1}{x^3 \left (b x^2+a\right )^{4/3}}dx+d \int \frac {1}{x^2 \left (b x^2+a\right )^{4/3}}dx\)

\(\Big \downarrow \) 243

\(\displaystyle \frac {1}{2} c \int \frac {1}{x^4 \left (b x^2+a\right )^{4/3}}dx^2+d \int \frac {1}{x^2 \left (b x^2+a\right )^{4/3}}dx\)

\(\Big \downarrow \) 52

\(\displaystyle \frac {1}{2} c \left (-\frac {4 b \int \frac {1}{x^2 \left (b x^2+a\right )^{4/3}}dx^2}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )+d \int \frac {1}{x^2 \left (b x^2+a\right )^{4/3}}dx\)

\(\Big \downarrow \) 61

\(\displaystyle \frac {1}{2} c \left (-\frac {4 b \left (\frac {\int \frac {1}{x^2 \sqrt [3]{b x^2+a}}dx^2}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )+d \int \frac {1}{x^2 \left (b x^2+a\right )^{4/3}}dx\)

\(\Big \downarrow \) 67

\(\displaystyle \frac {1}{2} c \left (-\frac {4 b \left (\frac {\frac {3}{2} \int \frac {1}{x^4+a^{2/3}+\sqrt [3]{a} \sqrt [3]{b x^2+a}}d\sqrt [3]{b x^2+a}-\frac {3 \int \frac {1}{\sqrt [3]{a}-\sqrt [3]{b x^2+a}}d\sqrt [3]{b x^2+a}}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )+d \int \frac {1}{x^2 \left (b x^2+a\right )^{4/3}}dx\)

\(\Big \downarrow \) 16

\(\displaystyle \frac {1}{2} c \left (-\frac {4 b \left (\frac {\frac {3}{2} \int \frac {1}{x^4+a^{2/3}+\sqrt [3]{a} \sqrt [3]{b x^2+a}}d\sqrt [3]{b x^2+a}+\frac {3 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )+d \int \frac {1}{x^2 \left (b x^2+a\right )^{4/3}}dx\)

\(\Big \downarrow \) 253

\(\displaystyle \frac {1}{2} c \left (-\frac {4 b \left (\frac {\frac {3}{2} \int \frac {1}{x^4+a^{2/3}+\sqrt [3]{a} \sqrt [3]{b x^2+a}}d\sqrt [3]{b x^2+a}+\frac {3 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )+d \left (\frac {5 \int \frac {1}{x^2 \sqrt [3]{b x^2+a}}dx}{2 a}+\frac {3}{2 a x \sqrt [3]{a+b x^2}}\right )\)

\(\Big \downarrow \) 264

\(\displaystyle \frac {1}{2} c \left (-\frac {4 b \left (\frac {\frac {3}{2} \int \frac {1}{x^4+a^{2/3}+\sqrt [3]{a} \sqrt [3]{b x^2+a}}d\sqrt [3]{b x^2+a}+\frac {3 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )+d \left (\frac {5 \left (\frac {b \int \frac {1}{\sqrt [3]{b x^2+a}}dx}{3 a}-\frac {\left (a+b x^2\right )^{2/3}}{a x}\right )}{2 a}+\frac {3}{2 a x \sqrt [3]{a+b x^2}}\right )\)

\(\Big \downarrow \) 233

\(\displaystyle \frac {1}{2} c \left (-\frac {4 b \left (\frac {\frac {3}{2} \int \frac {1}{x^4+a^{2/3}+\sqrt [3]{a} \sqrt [3]{b x^2+a}}d\sqrt [3]{b x^2+a}+\frac {3 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )+d \left (\frac {5 \left (\frac {\sqrt {b x^2} \int \frac {\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}}{2 a x}-\frac {\left (a+b x^2\right )^{2/3}}{a x}\right )}{2 a}+\frac {3}{2 a x \sqrt [3]{a+b x^2}}\right )\)

\(\Big \downarrow \) 833

\(\displaystyle \frac {1}{2} c \left (-\frac {4 b \left (\frac {\frac {3}{2} \int \frac {1}{x^4+a^{2/3}+\sqrt [3]{a} \sqrt [3]{b x^2+a}}d\sqrt [3]{b x^2+a}+\frac {3 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )+d \left (\frac {5 \left (\frac {\sqrt {b x^2} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a} \int \frac {1}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}-\int \frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}\right )}{2 a x}-\frac {\left (a+b x^2\right )^{2/3}}{a x}\right )}{2 a}+\frac {3}{2 a x \sqrt [3]{a+b x^2}}\right )\)

\(\Big \downarrow \) 760

\(\displaystyle d \left (\frac {5 \left (\frac {\sqrt {b x^2} \left (-\int \frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}-\frac {2 \sqrt {2-\sqrt {3}} \left (1+\sqrt {3}\right ) \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}\right )}{2 a x}-\frac {\left (a+b x^2\right )^{2/3}}{a x}\right )}{2 a}+\frac {3}{2 a x \sqrt [3]{a+b x^2}}\right )+\frac {1}{2} c \left (-\frac {4 b \left (\frac {\frac {3}{2} \int \frac {1}{x^4+a^{2/3}+\sqrt [3]{a} \sqrt [3]{b x^2+a}}d\sqrt [3]{b x^2+a}+\frac {3 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )\)

\(\Big \downarrow \) 1082

\(\displaystyle d \left (\frac {5 \left (\frac {\sqrt {b x^2} \left (-\int \frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}-\frac {2 \sqrt {2-\sqrt {3}} \left (1+\sqrt {3}\right ) \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}\right )}{2 a x}-\frac {\left (a+b x^2\right )^{2/3}}{a x}\right )}{2 a}+\frac {3}{2 a x \sqrt [3]{a+b x^2}}\right )+\frac {1}{2} c \left (-\frac {4 b \left (\frac {-\frac {3 \int \frac {1}{-x^4-3}d\left (\frac {2 \sqrt [3]{b x^2+a}}{\sqrt [3]{a}}+1\right )}{\sqrt [3]{a}}+\frac {3 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )\)

\(\Big \downarrow \) 217

\(\displaystyle d \left (\frac {5 \left (\frac {\sqrt {b x^2} \left (-\int \frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\sqrt {b x^2}}d\sqrt [3]{b x^2+a}-\frac {2 \sqrt {2-\sqrt {3}} \left (1+\sqrt {3}\right ) \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}\right )}{2 a x}-\frac {\left (a+b x^2\right )^{2/3}}{a x}\right )}{2 a}+\frac {3}{2 a x \sqrt [3]{a+b x^2}}\right )+\frac {1}{2} c \left (-\frac {4 b \left (\frac {\frac {\sqrt {3} \arctan \left (\frac {\frac {2 \sqrt [3]{a+b x^2}}{\sqrt [3]{a}}+1}{\sqrt {3}}\right )}{\sqrt [3]{a}}+\frac {3 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )\)

\(\Big \downarrow \) 2418

\(\displaystyle d \left (\frac {5 \left (\frac {\sqrt {b x^2} \left (-\frac {2 \sqrt {2-\sqrt {3}} \left (1+\sqrt {3}\right ) \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}+\frac {\sqrt [4]{3} \sqrt {2+\sqrt {3}} \sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right ) \sqrt {\frac {a^{2/3}+\sqrt [3]{a} \sqrt [3]{a+b x^2}+\left (a+b x^2\right )^{2/3}}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}} E\left (\arcsin \left (\frac {\left (1+\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{b x^2+a}}\right )|-7+4 \sqrt {3}\right )}{\sqrt {b x^2} \sqrt {-\frac {\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{\left (\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )^2}}}-\frac {2 \sqrt {b x^2}}{\left (1-\sqrt {3}\right ) \sqrt [3]{a}-\sqrt [3]{a+b x^2}}\right )}{2 a x}-\frac {\left (a+b x^2\right )^{2/3}}{a x}\right )}{2 a}+\frac {3}{2 a x \sqrt [3]{a+b x^2}}\right )+\frac {1}{2} c \left (-\frac {4 b \left (\frac {\frac {\sqrt {3} \arctan \left (\frac {\frac {2 \sqrt [3]{a+b x^2}}{\sqrt [3]{a}}+1}{\sqrt {3}}\right )}{\sqrt [3]{a}}+\frac {3 \log \left (\sqrt [3]{a}-\sqrt [3]{a+b x^2}\right )}{2 \sqrt [3]{a}}-\frac {\log \left (x^2\right )}{2 \sqrt [3]{a}}}{a}+\frac {3}{a \sqrt [3]{a+b x^2}}\right )}{3 a}-\frac {1}{a x^2 \sqrt [3]{a+b x^2}}\right )\)

Input:

Int[(c + d*x)/(x^3*(a + b*x^2)^(4/3)),x]
 

Output:

d*(3/(2*a*x*(a + b*x^2)^(1/3)) + (5*(-((a + b*x^2)^(2/3)/(a*x)) + (Sqrt[b* 
x^2]*((-2*Sqrt[b*x^2])/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3)) + (3^(1 
/4)*Sqrt[2 + Sqrt[3]]*a^(1/3)*(a^(1/3) - (a + b*x^2)^(1/3))*Sqrt[(a^(2/3) 
+ a^(1/3)*(a + b*x^2)^(1/3) + (a + b*x^2)^(2/3))/((1 - Sqrt[3])*a^(1/3) - 
(a + b*x^2)^(1/3))^2]*EllipticE[ArcSin[((1 + Sqrt[3])*a^(1/3) - (a + b*x^2 
)^(1/3))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))], -7 + 4*Sqrt[3]])/(S 
qrt[b*x^2]*Sqrt[-((a^(1/3)*(a^(1/3) - (a + b*x^2)^(1/3)))/((1 - Sqrt[3])*a 
^(1/3) - (a + b*x^2)^(1/3))^2)]) - (2*Sqrt[2 - Sqrt[3]]*(1 + Sqrt[3])*a^(1 
/3)*(a^(1/3) - (a + b*x^2)^(1/3))*Sqrt[(a^(2/3) + a^(1/3)*(a + b*x^2)^(1/3 
) + (a + b*x^2)^(2/3))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))^2]*Elli 
pticF[ArcSin[((1 + Sqrt[3])*a^(1/3) - (a + b*x^2)^(1/3))/((1 - Sqrt[3])*a^ 
(1/3) - (a + b*x^2)^(1/3))], -7 + 4*Sqrt[3]])/(3^(1/4)*Sqrt[b*x^2]*Sqrt[-( 
(a^(1/3)*(a^(1/3) - (a + b*x^2)^(1/3)))/((1 - Sqrt[3])*a^(1/3) - (a + b*x^ 
2)^(1/3))^2)])))/(2*a*x)))/(2*a)) + (c*(-(1/(a*x^2*(a + b*x^2)^(1/3))) - ( 
4*b*(3/(a*(a + b*x^2)^(1/3)) + ((Sqrt[3]*ArcTan[(1 + (2*(a + b*x^2)^(1/3)) 
/a^(1/3))/Sqrt[3]])/a^(1/3) - Log[x^2]/(2*a^(1/3)) + (3*Log[a^(1/3) - (a + 
 b*x^2)^(1/3)])/(2*a^(1/3)))/a))/(3*a)))/2
 

Defintions of rubi rules used

rule 16
Int[(c_.)/((a_.) + (b_.)*(x_)), x_Symbol] :> Simp[c*(Log[RemoveContent[a + 
b*x, x]]/b), x] /; FreeQ[{a, b, c}, x]
 

rule 52
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ 
(a + b*x)^(m + 1)*((c + d*x)^(n + 1)/((b*c - a*d)*(m + 1))), x] - Simp[d*(( 
m + n + 2)/((b*c - a*d)*(m + 1)))   Int[(a + b*x)^(m + 1)*(c + d*x)^n, x], 
x] /; FreeQ[{a, b, c, d, n}, x] && ILtQ[m, -1] && FractionQ[n] && LtQ[n, 0]
 

rule 61
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ 
(a + b*x)^(m + 1)*((c + d*x)^(n + 1)/((b*c - a*d)*(m + 1))), x] - Simp[d*(( 
m + n + 2)/((b*c - a*d)*(m + 1)))   Int[(a + b*x)^(m + 1)*(c + d*x)^n, x], 
x] /; FreeQ[{a, b, c, d, n}, x] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0 
] || (NeQ[c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d 
, m, n, x]
 

rule 67
Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(1/3)), x_Symbol] :> With[ 
{q = Rt[(b*c - a*d)/b, 3]}, Simp[-Log[RemoveContent[a + b*x, x]]/(2*b*q), x 
] + (Simp[3/(2*b)   Subst[Int[1/(q^2 + q*x + x^2), x], x, (c + d*x)^(1/3)], 
 x] - Simp[3/(2*b*q)   Subst[Int[1/(q - x), x], x, (c + d*x)^(1/3)], x])] / 
; FreeQ[{a, b, c, d}, x] && PosQ[(b*c - a*d)/b]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 233
Int[((a_) + (b_.)*(x_)^2)^(-1/3), x_Symbol] :> Simp[3*(Sqrt[b*x^2]/(2*b*x)) 
   Subst[Int[x/Sqrt[-a + x^3], x], x, (a + b*x^2)^(1/3)], x] /; FreeQ[{a, b 
}, x]
 

rule 243
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[1/2   Subst[In 
t[x^((m - 1)/2)*(a + b*x)^p, x], x, x^2], x] /; FreeQ[{a, b, m, p}, x] && I 
ntegerQ[(m - 1)/2]
 

rule 253
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(-(c*x 
)^(m + 1))*((a + b*x^2)^(p + 1)/(2*a*c*(p + 1))), x] + Simp[(m + 2*p + 3)/( 
2*a*(p + 1))   Int[(c*x)^m*(a + b*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, m 
}, x] && LtQ[p, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
 

rule 264
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(c*x)^( 
m + 1)*((a + b*x^2)^(p + 1)/(a*c*(m + 1))), x] - Simp[b*((m + 2*p + 3)/(a*c 
^2*(m + 1)))   Int[(c*x)^(m + 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, p 
}, x] && LtQ[m, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
 

rule 542
Int[(x_)^(m_.)*((c_) + (d_.)*(x_))*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> 
 Simp[c   Int[x^m*(a + b*x^2)^p, x], x] + Simp[d   Int[x^(m + 1)*(a + b*x^2 
)^p, x], x] /; FreeQ[{a, b, c, d, p}, x] && IntegerQ[m] &&  !IntegerQ[2*p]
 

rule 760
Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], 
s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt[2 - Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s 
*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[(- 
s)*((s + r*x)/((1 - Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 + Sqrt[3]) 
*s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x 
] && NegQ[a]
 

rule 833
Int[(x_)/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3] 
], s = Denom[Rt[b/a, 3]]}, Simp[(-(1 + Sqrt[3]))*(s/r)   Int[1/Sqrt[a + b*x 
^3], x], x] + Simp[1/r   Int[((1 + Sqrt[3])*s + r*x)/Sqrt[a + b*x^3], x], x 
]] /; FreeQ[{a, b}, x] && NegQ[a]
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 2418
Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = N 
umer[Simplify[(1 + Sqrt[3])*(d/c)]], s = Denom[Simplify[(1 + Sqrt[3])*(d/c) 
]]}, Simp[2*d*s^3*(Sqrt[a + b*x^3]/(a*r^2*((1 - Sqrt[3])*s + r*x))), x] + S 
imp[3^(1/4)*Sqrt[2 + Sqrt[3]]*d*s*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/( 
(1 - Sqrt[3])*s + r*x)^2]/(r^2*Sqrt[a + b*x^3]*Sqrt[(-s)*((s + r*x)/((1 - S 
qrt[3])*s + r*x)^2)]))*EllipticE[ArcSin[((1 + Sqrt[3])*s + r*x)/((1 - Sqrt[ 
3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b, c, d}, x] && NegQ[a] && 
 EqQ[b*c^3 - 2*(5 + 3*Sqrt[3])*a*d^3, 0]
 
Maple [F]

\[\int \frac {d x +c}{x^{3} \left (b \,x^{2}+a \right )^{\frac {4}{3}}}d x\]

Input:

int((d*x+c)/x^3/(b*x^2+a)^(4/3),x)
 

Output:

int((d*x+c)/x^3/(b*x^2+a)^(4/3),x)
 

Fricas [F(-1)]

Timed out. \[ \int \frac {c+d x}{x^3 \left (a+b x^2\right )^{4/3}} \, dx=\text {Timed out} \] Input:

integrate((d*x+c)/x^3/(b*x^2+a)^(4/3),x, algorithm="fricas")
 

Output:

Timed out
 

Sympy [A] (verification not implemented)

Time = 3.41 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.10 \[ \int \frac {c+d x}{x^3 \left (a+b x^2\right )^{4/3}} \, dx=- \frac {c \Gamma \left (\frac {7}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {4}{3}, \frac {7}{3} \\ \frac {10}{3} \end {matrix}\middle | {\frac {a e^{i \pi }}{b x^{2}}} \right )}}{2 b^{\frac {4}{3}} x^{\frac {14}{3}} \Gamma \left (\frac {10}{3}\right )} - \frac {d {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {4}{3} \\ \frac {1}{2} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{a^{\frac {4}{3}} x} \] Input:

integrate((d*x+c)/x**3/(b*x**2+a)**(4/3),x)
 

Output:

-c*gamma(7/3)*hyper((4/3, 7/3), (10/3,), a*exp_polar(I*pi)/(b*x**2))/(2*b* 
*(4/3)*x**(14/3)*gamma(10/3)) - d*hyper((-1/2, 4/3), (1/2,), b*x**2*exp_po 
lar(I*pi)/a)/(a**(4/3)*x)
 

Maxima [F]

\[ \int \frac {c+d x}{x^3 \left (a+b x^2\right )^{4/3}} \, dx=\int { \frac {d x + c}{{\left (b x^{2} + a\right )}^{\frac {4}{3}} x^{3}} \,d x } \] Input:

integrate((d*x+c)/x^3/(b*x^2+a)^(4/3),x, algorithm="maxima")
 

Output:

-1/6*c*(4*sqrt(3)*b*arctan(1/3*sqrt(3)*(2*(b*x^2 + a)^(1/3) + a^(1/3))/a^( 
1/3))/a^(7/3) + 3*(4*(b*x^2 + a)*b - 3*a*b)/((b*x^2 + a)^(4/3)*a^2 - (b*x^ 
2 + a)^(1/3)*a^3) - 2*b*log((b*x^2 + a)^(2/3) + (b*x^2 + a)^(1/3)*a^(1/3) 
+ a^(2/3))/a^(7/3) + 4*b*log((b*x^2 + a)^(1/3) - a^(1/3))/a^(7/3)) + d*int 
egrate(1/((b*x^4 + a*x^2)*(b*x^2 + a)^(1/3)), x)
 

Giac [F]

\[ \int \frac {c+d x}{x^3 \left (a+b x^2\right )^{4/3}} \, dx=\int { \frac {d x + c}{{\left (b x^{2} + a\right )}^{\frac {4}{3}} x^{3}} \,d x } \] Input:

integrate((d*x+c)/x^3/(b*x^2+a)^(4/3),x, algorithm="giac")
 

Output:

integrate((d*x + c)/((b*x^2 + a)^(4/3)*x^3), x)
 

Mupad [B] (verification not implemented)

Time = 9.81 (sec) , antiderivative size = 246, normalized size of antiderivative = 0.36 \[ \int \frac {c+d x}{x^3 \left (a+b x^2\right )^{4/3}} \, dx=-\frac {\frac {3\,b\,c}{a}-\frac {4\,b\,c\,\left (b\,x^2+a\right )}{a^2}}{2\,a\,{\left (b\,x^2+a\right )}^{1/3}-2\,{\left (b\,x^2+a\right )}^{4/3}}+\frac {\ln \left (a^{7/3}\,{\left (b\,c-\sqrt {3}\,b\,c\,1{}\mathrm {i}\right )}^2-4\,a^2\,b^2\,c^2\,{\left (b\,x^2+a\right )}^{1/3}\right )\,\left (b\,c-\sqrt {3}\,b\,c\,1{}\mathrm {i}\right )}{3\,a^{7/3}}+\frac {\ln \left (a^{7/3}\,{\left (b\,c+\sqrt {3}\,b\,c\,1{}\mathrm {i}\right )}^2-4\,a^2\,b^2\,c^2\,{\left (b\,x^2+a\right )}^{1/3}\right )\,\left (b\,c+\sqrt {3}\,b\,c\,1{}\mathrm {i}\right )}{3\,a^{7/3}}-\frac {2\,b\,c\,\ln \left (4\,a^{7/3}\,b^2\,c^2-4\,a^2\,b^2\,c^2\,{\left (b\,x^2+a\right )}^{1/3}\right )}{3\,a^{7/3}}-\frac {3\,d\,{\left (\frac {a}{b\,x^2}+1\right )}^{4/3}\,{{}}_2{\mathrm {F}}_1\left (\frac {4}{3},\frac {11}{6};\ \frac {17}{6};\ -\frac {a}{b\,x^2}\right )}{11\,x\,{\left (b\,x^2+a\right )}^{4/3}} \] Input:

int((c + d*x)/(x^3*(a + b*x^2)^(4/3)),x)
 

Output:

(log(a^(7/3)*(b*c - 3^(1/2)*b*c*1i)^2 - 4*a^2*b^2*c^2*(a + b*x^2)^(1/3))*( 
b*c - 3^(1/2)*b*c*1i))/(3*a^(7/3)) - ((3*b*c)/a - (4*b*c*(a + b*x^2))/a^2) 
/(2*a*(a + b*x^2)^(1/3) - 2*(a + b*x^2)^(4/3)) + (log(a^(7/3)*(b*c + 3^(1/ 
2)*b*c*1i)^2 - 4*a^2*b^2*c^2*(a + b*x^2)^(1/3))*(b*c + 3^(1/2)*b*c*1i))/(3 
*a^(7/3)) - (2*b*c*log(4*a^(7/3)*b^2*c^2 - 4*a^2*b^2*c^2*(a + b*x^2)^(1/3) 
))/(3*a^(7/3)) - (3*d*(a/(b*x^2) + 1)^(4/3)*hypergeom([4/3, 11/6], 17/6, - 
a/(b*x^2)))/(11*x*(a + b*x^2)^(4/3))
 

Reduce [F]

\[ \int \frac {c+d x}{x^3 \left (a+b x^2\right )^{4/3}} \, dx=\left (\int \frac {1}{\left (b \,x^{2}+a \right )^{\frac {1}{3}} a \,x^{3}+\left (b \,x^{2}+a \right )^{\frac {1}{3}} b \,x^{5}}d x \right ) c +\left (\int \frac {1}{\left (b \,x^{2}+a \right )^{\frac {1}{3}} a \,x^{2}+\left (b \,x^{2}+a \right )^{\frac {1}{3}} b \,x^{4}}d x \right ) d \] Input:

int((d*x+c)/x^3/(b*x^2+a)^(4/3),x)
 

Output:

int(1/((a + b*x**2)**(1/3)*a*x**3 + (a + b*x**2)**(1/3)*b*x**5),x)*c + int 
(1/((a + b*x**2)**(1/3)*a*x**2 + (a + b*x**2)**(1/3)*b*x**4),x)*d