\(\int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx\) [243]

Optimal result
Mathematica [F]
Rubi [A] (verified)
Maple [F]
Fricas [F]
Sympy [F(-1)]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 22, antiderivative size = 128 \[ \int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx=\frac {x^{7/2} (c+d x)^n \left (1+\frac {d x}{c}\right )^{-n} \operatorname {AppellF1}\left (\frac {7}{2},-n,1,\frac {9}{2},-\frac {d x}{c},-\frac {\sqrt {b} x}{\sqrt {-a}}\right )}{7 a}+\frac {x^{7/2} (c+d x)^n \left (1+\frac {d x}{c}\right )^{-n} \operatorname {AppellF1}\left (\frac {7}{2},-n,1,\frac {9}{2},-\frac {d x}{c},\frac {\sqrt {b} x}{\sqrt {-a}}\right )}{7 a} \] Output:

1/7*x^(7/2)*(d*x+c)^n*AppellF1(7/2,1,-n,9/2,-b^(1/2)*x/(-a)^(1/2),-d*x/c)/ 
a/((1+d*x/c)^n)+1/7*x^(7/2)*(d*x+c)^n*AppellF1(7/2,1,-n,9/2,b^(1/2)*x/(-a) 
^(1/2),-d*x/c)/a/((1+d*x/c)^n)
 

Mathematica [F]

\[ \int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx=\int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx \] Input:

Integrate[(x^(5/2)*(c + d*x)^n)/(a + b*x^2),x]
 

Output:

Integrate[(x^(5/2)*(c + d*x)^n)/(a + b*x^2), x]
 

Rubi [A] (verified)

Time = 0.41 (sec) , antiderivative size = 128, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {615, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx\)

\(\Big \downarrow \) 615

\(\displaystyle \int \left (\frac {\sqrt {-a} x^{5/2} (c+d x)^n}{2 a \left (\sqrt {-a}-\sqrt {b} x\right )}+\frac {\sqrt {-a} x^{5/2} (c+d x)^n}{2 a \left (\sqrt {-a}+\sqrt {b} x\right )}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {x^{7/2} (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} \operatorname {AppellF1}\left (\frac {7}{2},1,-n,\frac {9}{2},-\frac {\sqrt {b} x}{\sqrt {-a}},-\frac {d x}{c}\right )}{7 a}+\frac {x^{7/2} (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} \operatorname {AppellF1}\left (\frac {7}{2},1,-n,\frac {9}{2},\frac {\sqrt {b} x}{\sqrt {-a}},-\frac {d x}{c}\right )}{7 a}\)

Input:

Int[(x^(5/2)*(c + d*x)^n)/(a + b*x^2),x]
 

Output:

(x^(7/2)*(c + d*x)^n*AppellF1[7/2, 1, -n, 9/2, -((Sqrt[b]*x)/Sqrt[-a]), -( 
(d*x)/c)])/(7*a*(1 + (d*x)/c)^n) + (x^(7/2)*(c + d*x)^n*AppellF1[7/2, 1, - 
n, 9/2, (Sqrt[b]*x)/Sqrt[-a], -((d*x)/c)])/(7*a*(1 + (d*x)/c)^n)
 

Defintions of rubi rules used

rule 615
Int[((e_.)*(x_))^(m_.)*((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_), 
 x_Symbol] :> Int[ExpandIntegrand[(e*x)^m*(c + d*x)^n*(a + b*x^2)^p, x], x] 
 /; FreeQ[{a, b, c, d, e, m, n}, x] && ILtQ[p, 0]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 
Maple [F]

\[\int \frac {x^{\frac {5}{2}} \left (d x +c \right )^{n}}{b \,x^{2}+a}d x\]

Input:

int(x^(5/2)*(d*x+c)^n/(b*x^2+a),x)
 

Output:

int(x^(5/2)*(d*x+c)^n/(b*x^2+a),x)
 

Fricas [F]

\[ \int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx=\int { \frac {{\left (d x + c\right )}^{n} x^{\frac {5}{2}}}{b x^{2} + a} \,d x } \] Input:

integrate(x^(5/2)*(d*x+c)^n/(b*x^2+a),x, algorithm="fricas")
 

Output:

integral((d*x + c)^n*x^(5/2)/(b*x^2 + a), x)
 

Sympy [F(-1)]

Timed out. \[ \int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx=\text {Timed out} \] Input:

integrate(x**(5/2)*(d*x+c)**n/(b*x**2+a),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx=\int { \frac {{\left (d x + c\right )}^{n} x^{\frac {5}{2}}}{b x^{2} + a} \,d x } \] Input:

integrate(x^(5/2)*(d*x+c)^n/(b*x^2+a),x, algorithm="maxima")
 

Output:

integrate((d*x + c)^n*x^(5/2)/(b*x^2 + a), x)
 

Giac [F]

\[ \int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx=\int { \frac {{\left (d x + c\right )}^{n} x^{\frac {5}{2}}}{b x^{2} + a} \,d x } \] Input:

integrate(x^(5/2)*(d*x+c)^n/(b*x^2+a),x, algorithm="giac")
 

Output:

integrate((d*x + c)^n*x^(5/2)/(b*x^2 + a), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx=\int \frac {x^{5/2}\,{\left (c+d\,x\right )}^n}{b\,x^2+a} \,d x \] Input:

int((x^(5/2)*(c + d*x)^n)/(a + b*x^2),x)
 

Output:

int((x^(5/2)*(c + d*x)^n)/(a + b*x^2), x)
 

Reduce [F]

\[ \int \frac {x^{5/2} (c+d x)^n}{a+b x^2} \, dx =\text {Too large to display} \] Input:

int(x^(5/2)*(d*x+c)^n/(b*x^2+a),x)
 

Output:

( - 4*sqrt(x)*(c + d*x)**n*a*d*n - 6*sqrt(x)*(c + d*x)**n*a*d + 2*sqrt(x)* 
(c + d*x)**n*b*c*x + 8*int((sqrt(x)*(c + d*x)**n*x**2)/(2*a*c*n + 3*a*c + 
2*a*d*n*x + 3*a*d*x + 2*b*c*n*x**2 + 3*b*c*x**2 + 2*b*d*n*x**3 + 3*b*d*x** 
3),x)*a*b*d**2*n**3 + 28*int((sqrt(x)*(c + d*x)**n*x**2)/(2*a*c*n + 3*a*c 
+ 2*a*d*n*x + 3*a*d*x + 2*b*c*n*x**2 + 3*b*c*x**2 + 2*b*d*n*x**3 + 3*b*d*x 
**3),x)*a*b*d**2*n**2 + 30*int((sqrt(x)*(c + d*x)**n*x**2)/(2*a*c*n + 3*a* 
c + 2*a*d*n*x + 3*a*d*x + 2*b*c*n*x**2 + 3*b*c*x**2 + 2*b*d*n*x**3 + 3*b*d 
*x**3),x)*a*b*d**2*n + 9*int((sqrt(x)*(c + d*x)**n*x**2)/(2*a*c*n + 3*a*c 
+ 2*a*d*n*x + 3*a*d*x + 2*b*c*n*x**2 + 3*b*c*x**2 + 2*b*d*n*x**3 + 3*b*d*x 
**3),x)*a*b*d**2 + 4*int((sqrt(x)*(c + d*x)**n*x**2)/(2*a*c*n + 3*a*c + 2* 
a*d*n*x + 3*a*d*x + 2*b*c*n*x**2 + 3*b*c*x**2 + 2*b*d*n*x**3 + 3*b*d*x**3) 
,x)*b**2*c**2*n**2 + 6*int((sqrt(x)*(c + d*x)**n*x**2)/(2*a*c*n + 3*a*c + 
2*a*d*n*x + 3*a*d*x + 2*b*c*n*x**2 + 3*b*c*x**2 + 2*b*d*n*x**3 + 3*b*d*x** 
3),x)*b**2*c**2*n + 4*int((sqrt(x)*(c + d*x)**n)/(2*a*c*n*x + 3*a*c*x + 2* 
a*d*n*x**2 + 3*a*d*x**2 + 2*b*c*n*x**3 + 3*b*c*x**3 + 2*b*d*n*x**4 + 3*b*d 
*x**4),x)*a**2*c*d*n**2 + 12*int((sqrt(x)*(c + d*x)**n)/(2*a*c*n*x + 3*a*c 
*x + 2*a*d*n*x**2 + 3*a*d*x**2 + 2*b*c*n*x**3 + 3*b*c*x**3 + 2*b*d*n*x**4 
+ 3*b*d*x**4),x)*a**2*c*d*n + 9*int((sqrt(x)*(c + d*x)**n)/(2*a*c*n*x + 3* 
a*c*x + 2*a*d*n*x**2 + 3*a*d*x**2 + 2*b*c*n*x**3 + 3*b*c*x**3 + 2*b*d*n*x* 
*4 + 3*b*d*x**4),x)*a**2*c*d + 8*int((sqrt(x)*(c + d*x)**n)/(2*a*c*n + ...