Integrand size = 22, antiderivative size = 128 \[ \int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx=\frac {x^{3/2} (c+d x)^n \left (1+\frac {d x}{c}\right )^{-n} \operatorname {AppellF1}\left (\frac {3}{2},-n,1,\frac {5}{2},-\frac {d x}{c},-\frac {\sqrt {b} x}{\sqrt {-a}}\right )}{3 a}+\frac {x^{3/2} (c+d x)^n \left (1+\frac {d x}{c}\right )^{-n} \operatorname {AppellF1}\left (\frac {3}{2},-n,1,\frac {5}{2},-\frac {d x}{c},\frac {\sqrt {b} x}{\sqrt {-a}}\right )}{3 a} \] Output:
1/3*x^(3/2)*(d*x+c)^n*AppellF1(3/2,1,-n,5/2,-b^(1/2)*x/(-a)^(1/2),-d*x/c)/ a/((1+d*x/c)^n)+1/3*x^(3/2)*(d*x+c)^n*AppellF1(3/2,1,-n,5/2,b^(1/2)*x/(-a) ^(1/2),-d*x/c)/a/((1+d*x/c)^n)
\[ \int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx=\int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx \] Input:
Integrate[(Sqrt[x]*(c + d*x)^n)/(a + b*x^2),x]
Output:
Integrate[(Sqrt[x]*(c + d*x)^n)/(a + b*x^2), x]
Time = 0.41 (sec) , antiderivative size = 128, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {615, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx\) |
\(\Big \downarrow \) 615 |
\(\displaystyle \int \left (\frac {\sqrt {-a} \sqrt {x} (c+d x)^n}{2 a \left (\sqrt {-a}-\sqrt {b} x\right )}+\frac {\sqrt {-a} \sqrt {x} (c+d x)^n}{2 a \left (\sqrt {-a}+\sqrt {b} x\right )}\right )dx\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {x^{3/2} (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} \operatorname {AppellF1}\left (\frac {3}{2},1,-n,\frac {5}{2},-\frac {\sqrt {b} x}{\sqrt {-a}},-\frac {d x}{c}\right )}{3 a}+\frac {x^{3/2} (c+d x)^n \left (\frac {d x}{c}+1\right )^{-n} \operatorname {AppellF1}\left (\frac {3}{2},1,-n,\frac {5}{2},\frac {\sqrt {b} x}{\sqrt {-a}},-\frac {d x}{c}\right )}{3 a}\) |
Input:
Int[(Sqrt[x]*(c + d*x)^n)/(a + b*x^2),x]
Output:
(x^(3/2)*(c + d*x)^n*AppellF1[3/2, 1, -n, 5/2, -((Sqrt[b]*x)/Sqrt[-a]), -( (d*x)/c)])/(3*a*(1 + (d*x)/c)^n) + (x^(3/2)*(c + d*x)^n*AppellF1[3/2, 1, - n, 5/2, (Sqrt[b]*x)/Sqrt[-a], -((d*x)/c)])/(3*a*(1 + (d*x)/c)^n)
Int[((e_.)*(x_))^(m_.)*((c_) + (d_.)*(x_))^(n_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Int[ExpandIntegrand[(e*x)^m*(c + d*x)^n*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n}, x] && ILtQ[p, 0]
\[\int \frac {\sqrt {x}\, \left (d x +c \right )^{n}}{b \,x^{2}+a}d x\]
Input:
int(x^(1/2)*(d*x+c)^n/(b*x^2+a),x)
Output:
int(x^(1/2)*(d*x+c)^n/(b*x^2+a),x)
\[ \int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx=\int { \frac {{\left (d x + c\right )}^{n} \sqrt {x}}{b x^{2} + a} \,d x } \] Input:
integrate(x^(1/2)*(d*x+c)^n/(b*x^2+a),x, algorithm="fricas")
Output:
integral((d*x + c)^n*sqrt(x)/(b*x^2 + a), x)
Timed out. \[ \int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx=\text {Timed out} \] Input:
integrate(x**(1/2)*(d*x+c)**n/(b*x**2+a),x)
Output:
Timed out
\[ \int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx=\int { \frac {{\left (d x + c\right )}^{n} \sqrt {x}}{b x^{2} + a} \,d x } \] Input:
integrate(x^(1/2)*(d*x+c)^n/(b*x^2+a),x, algorithm="maxima")
Output:
integrate((d*x + c)^n*sqrt(x)/(b*x^2 + a), x)
\[ \int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx=\int { \frac {{\left (d x + c\right )}^{n} \sqrt {x}}{b x^{2} + a} \,d x } \] Input:
integrate(x^(1/2)*(d*x+c)^n/(b*x^2+a),x, algorithm="giac")
Output:
integrate((d*x + c)^n*sqrt(x)/(b*x^2 + a), x)
Timed out. \[ \int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx=\int \frac {\sqrt {x}\,{\left (c+d\,x\right )}^n}{b\,x^2+a} \,d x \] Input:
int((x^(1/2)*(c + d*x)^n)/(a + b*x^2),x)
Output:
int((x^(1/2)*(c + d*x)^n)/(a + b*x^2), x)
\[ \int \frac {\sqrt {x} (c+d x)^n}{a+b x^2} \, dx=\int \frac {\sqrt {x}\, \left (d x +c \right )^{n}}{b \,x^{2}+a}d x \] Input:
int(x^(1/2)*(d*x+c)^n/(b*x^2+a),x)
Output:
int((sqrt(x)*(c + d*x)**n)/(a + b*x**2),x)