Integrand size = 21, antiderivative size = 184 \[ \int x^4 \left (c+d \sqrt {a+b x^2}\right )^p \, dx=\frac {1}{5} x^5 \left (c+d \sqrt {a+b x^2}\right )^p-\frac {x^5 \left (c+d \sqrt {a+b x^2}\right )^p \operatorname {AppellF1}\left (p,-\frac {5}{2},-\frac {5}{2},1+p,\frac {c+d \sqrt {a+b x^2}}{c-\sqrt {a} d},\frac {c+d \sqrt {a+b x^2}}{c+\sqrt {a} d}\right )}{5 \left (1-\frac {c+d \sqrt {a+b x^2}}{c-\sqrt {a} d}\right )^{5/2} \left (1-\frac {c+d \sqrt {a+b x^2}}{c+\sqrt {a} d}\right )^{5/2}} \] Output:
1/5*x^5*(c+d*(b*x^2+a)^(1/2))^p-1/5*x^5*(c+d*(b*x^2+a)^(1/2))^p*AppellF1(p ,-5/2,-5/2,p+1,(c+d*(b*x^2+a)^(1/2))/(c-a^(1/2)*d),(c+d*(b*x^2+a)^(1/2))/( c+a^(1/2)*d))/(1-(c+d*(b*x^2+a)^(1/2))/(c-a^(1/2)*d))^(5/2)/(1-(c+d*(b*x^2 +a)^(1/2))/(c+a^(1/2)*d))^(5/2)
\[ \int x^4 \left (c+d \sqrt {a+b x^2}\right )^p \, dx=\int x^4 \left (c+d \sqrt {a+b x^2}\right )^p \, dx \] Input:
Integrate[x^4*(c + d*Sqrt[a + b*x^2])^p,x]
Output:
Integrate[x^4*(c + d*Sqrt[a + b*x^2])^p, x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^4 \left (d \sqrt {a+b x^2}+c\right )^p \, dx\) |
\(\Big \downarrow \) 7299 |
\(\displaystyle \int x^4 \left (d \sqrt {a+b x^2}+c\right )^pdx\) |
Input:
Int[x^4*(c + d*Sqrt[a + b*x^2])^p,x]
Output:
$Aborted
\[\int x^{4} \left (c +d \sqrt {b \,x^{2}+a}\right )^{p}d x\]
Input:
int(x^4*(c+d*(b*x^2+a)^(1/2))^p,x)
Output:
int(x^4*(c+d*(b*x^2+a)^(1/2))^p,x)
\[ \int x^4 \left (c+d \sqrt {a+b x^2}\right )^p \, dx=\int { {\left (\sqrt {b x^{2} + a} d + c\right )}^{p} x^{4} \,d x } \] Input:
integrate(x^4*(c+d*(b*x^2+a)^(1/2))^p,x, algorithm="fricas")
Output:
integral((sqrt(b*x^2 + a)*d + c)^p*x^4, x)
Exception generated. \[ \int x^4 \left (c+d \sqrt {a+b x^2}\right )^p \, dx=\text {Exception raised: HeuristicGCDFailed} \] Input:
integrate(x**4*(c+d*(b*x**2+a)**(1/2))**p,x)
Output:
Exception raised: HeuristicGCDFailed >> no luck
\[ \int x^4 \left (c+d \sqrt {a+b x^2}\right )^p \, dx=\int { {\left (\sqrt {b x^{2} + a} d + c\right )}^{p} x^{4} \,d x } \] Input:
integrate(x^4*(c+d*(b*x^2+a)^(1/2))^p,x, algorithm="maxima")
Output:
integrate((sqrt(b*x^2 + a)*d + c)^p*x^4, x)
\[ \int x^4 \left (c+d \sqrt {a+b x^2}\right )^p \, dx=\int { {\left (\sqrt {b x^{2} + a} d + c\right )}^{p} x^{4} \,d x } \] Input:
integrate(x^4*(c+d*(b*x^2+a)^(1/2))^p,x, algorithm="giac")
Output:
integrate((sqrt(b*x^2 + a)*d + c)^p*x^4, x)
Timed out. \[ \int x^4 \left (c+d \sqrt {a+b x^2}\right )^p \, dx=\int x^4\,{\left (c+d\,\sqrt {b\,x^2+a}\right )}^p \,d x \] Input:
int(x^4*(c + d*(a + b*x^2)^(1/2))^p,x)
Output:
int(x^4*(c + d*(a + b*x^2)^(1/2))^p, x)
\[ \int x^4 \left (c+d \sqrt {a+b x^2}\right )^p \, dx=\int x^{4} \left (c +d \sqrt {b \,x^{2}+a}\right )^{p}d x \] Input:
int(x^4*(c+d*(b*x^2+a)^(1/2))^p,x)
Output:
int(x^4*(c+d*(b*x^2+a)^(1/2))^p,x)