Integrand size = 19, antiderivative size = 350 \[ \int \frac {\left (b \sqrt [3]{x}+a x\right )^{3/2}}{x^3} \, dx=\frac {8 a^{5/2} \left (b+a x^{2/3}\right ) \sqrt [3]{x}}{5 b \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {b \sqrt [3]{x}+a x}}-\frac {4 a \sqrt {b \sqrt [3]{x}+a x}}{5 x}-\frac {8 a^2 \sqrt {b \sqrt [3]{x}+a x}}{5 b \sqrt [3]{x}}-\frac {2 \left (b \sqrt [3]{x}+a x\right )^{3/2}}{3 x^2}-\frac {8 a^{9/4} \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {\frac {b+a x^{2/3}}{\left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} E\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{5 b^{3/4} \sqrt {b \sqrt [3]{x}+a x}}+\frac {4 a^{9/4} \left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right ) \sqrt {\frac {b+a x^{2/3}}{\left (\sqrt {b}+\sqrt {a} \sqrt [3]{x}\right )^2}} \sqrt [6]{x} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{5 b^{3/4} \sqrt {b \sqrt [3]{x}+a x}} \] Output:
8/5*a^(5/2)*(b+a*x^(2/3))*x^(1/3)/b/(b^(1/2)+a^(1/2)*x^(1/3))/(b*x^(1/3)+a *x)^(1/2)-4/5*a*(b*x^(1/3)+a*x)^(1/2)/x-8/5*a^2*(b*x^(1/3)+a*x)^(1/2)/b/x^ (1/3)-2/3*(b*x^(1/3)+a*x)^(3/2)/x^2-8/5*a^(9/4)*(b^(1/2)+a^(1/2)*x^(1/3))* ((b+a*x^(2/3))/(b^(1/2)+a^(1/2)*x^(1/3))^2)^(1/2)*x^(1/6)*EllipticE(sin(2* arctan(a^(1/4)*x^(1/6)/b^(1/4))),1/2*2^(1/2))/b^(3/4)/(b*x^(1/3)+a*x)^(1/2 )+4/5*a^(9/4)*(b^(1/2)+a^(1/2)*x^(1/3))*((b+a*x^(2/3))/(b^(1/2)+a^(1/2)*x^ (1/3))^2)^(1/2)*x^(1/6)*InverseJacobiAM(2*arctan(a^(1/4)*x^(1/6)/b^(1/4)), 1/2*2^(1/2))/b^(3/4)/(b*x^(1/3)+a*x)^(1/2)
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.04 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.18 \[ \int \frac {\left (b \sqrt [3]{x}+a x\right )^{3/2}}{x^3} \, dx=-\frac {2 b \sqrt {b \sqrt [3]{x}+a x} \operatorname {Hypergeometric2F1}\left (-\frac {9}{4},-\frac {3}{2},-\frac {5}{4},-\frac {a x^{2/3}}{b}\right )}{3 \sqrt {1+\frac {a x^{2/3}}{b}} x^{5/3}} \] Input:
Integrate[(b*x^(1/3) + a*x)^(3/2)/x^3,x]
Output:
(-2*b*Sqrt[b*x^(1/3) + a*x]*Hypergeometric2F1[-9/4, -3/2, -5/4, -((a*x^(2/ 3))/b)])/(3*Sqrt[1 + (a*x^(2/3))/b]*x^(5/3))
Time = 0.84 (sec) , antiderivative size = 368, normalized size of antiderivative = 1.05, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.526, Rules used = {1924, 1926, 1926, 1931, 1938, 266, 834, 27, 761, 1510}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {\left (a x+b \sqrt [3]{x}\right )^{3/2}}{x^3} \, dx\) |
| \(\Big \downarrow \) 1924 |
| \(\displaystyle 3 \int \frac {\left (\sqrt [3]{x} b+a x\right )^{3/2}}{x^{7/3}}d\sqrt [3]{x}\) |
| \(\Big \downarrow \) 1926 |
| \(\displaystyle 3 \left (\frac {2}{3} a \int \frac {\sqrt {\sqrt [3]{x} b+a x}}{x^{4/3}}d\sqrt [3]{x}-\frac {2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{9 x^2}\right )\) |
| \(\Big \downarrow \) 1926 |
| \(\displaystyle 3 \left (\frac {2}{3} a \left (\frac {2}{5} a \int \frac {1}{\sqrt [3]{x} \sqrt {\sqrt [3]{x} b+a x}}d\sqrt [3]{x}-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{5 x}\right )-\frac {2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{9 x^2}\right )\) |
| \(\Big \downarrow \) 1931 |
| \(\displaystyle 3 \left (\frac {2}{3} a \left (\frac {2}{5} a \left (\frac {a \int \frac {\sqrt [3]{x}}{\sqrt {\sqrt [3]{x} b+a x}}d\sqrt [3]{x}}{b}-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{b \sqrt [3]{x}}\right )-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{5 x}\right )-\frac {2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{9 x^2}\right )\) |
| \(\Big \downarrow \) 1938 |
| \(\displaystyle 3 \left (\frac {2}{3} a \left (\frac {2}{5} a \left (\frac {a \sqrt [6]{x} \sqrt {a x^{2/3}+b} \int \frac {\sqrt [6]{x}}{\sqrt {x^{2/3} a+b}}d\sqrt [3]{x}}{b \sqrt {a x+b \sqrt [3]{x}}}-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{b \sqrt [3]{x}}\right )-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{5 x}\right )-\frac {2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{9 x^2}\right )\) |
| \(\Big \downarrow \) 266 |
| \(\displaystyle 3 \left (\frac {2}{3} a \left (\frac {2}{5} a \left (\frac {2 a \sqrt [6]{x} \sqrt {a x^{2/3}+b} \int \frac {x^{2/3}}{\sqrt {a x^{4/3}+b}}d\sqrt [6]{x}}{b \sqrt {a x+b \sqrt [3]{x}}}-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{b \sqrt [3]{x}}\right )-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{5 x}\right )-\frac {2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{9 x^2}\right )\) |
| \(\Big \downarrow \) 834 |
| \(\displaystyle 3 \left (\frac {2}{3} a \left (\frac {2}{5} a \left (\frac {2 a \sqrt [6]{x} \sqrt {a x^{2/3}+b} \left (\frac {\sqrt {b} \int \frac {1}{\sqrt {a x^{4/3}+b}}d\sqrt [6]{x}}{\sqrt {a}}-\frac {\sqrt {b} \int \frac {\sqrt {b}-\sqrt {a} x^{2/3}}{\sqrt {b} \sqrt {a x^{4/3}+b}}d\sqrt [6]{x}}{\sqrt {a}}\right )}{b \sqrt {a x+b \sqrt [3]{x}}}-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{b \sqrt [3]{x}}\right )-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{5 x}\right )-\frac {2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{9 x^2}\right )\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle 3 \left (\frac {2}{3} a \left (\frac {2}{5} a \left (\frac {2 a \sqrt [6]{x} \sqrt {a x^{2/3}+b} \left (\frac {\sqrt {b} \int \frac {1}{\sqrt {a x^{4/3}+b}}d\sqrt [6]{x}}{\sqrt {a}}-\frac {\int \frac {\sqrt {b}-\sqrt {a} x^{2/3}}{\sqrt {a x^{4/3}+b}}d\sqrt [6]{x}}{\sqrt {a}}\right )}{b \sqrt {a x+b \sqrt [3]{x}}}-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{b \sqrt [3]{x}}\right )-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{5 x}\right )-\frac {2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{9 x^2}\right )\) |
| \(\Big \downarrow \) 761 |
| \(\displaystyle 3 \left (\frac {2}{3} a \left (\frac {2}{5} a \left (\frac {2 a \sqrt [6]{x} \sqrt {a x^{2/3}+b} \left (\frac {\sqrt [4]{b} \left (\sqrt {a} x^{2/3}+\sqrt {b}\right ) \sqrt {\frac {a x^{4/3}+b}{\left (\sqrt {a} x^{2/3}+\sqrt {b}\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{2 a^{3/4} \sqrt {a x^{4/3}+b}}-\frac {\int \frac {\sqrt {b}-\sqrt {a} x^{2/3}}{\sqrt {a x^{4/3}+b}}d\sqrt [6]{x}}{\sqrt {a}}\right )}{b \sqrt {a x+b \sqrt [3]{x}}}-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{b \sqrt [3]{x}}\right )-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{5 x}\right )-\frac {2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{9 x^2}\right )\) |
| \(\Big \downarrow \) 1510 |
| \(\displaystyle 3 \left (\frac {2}{3} a \left (\frac {2}{5} a \left (\frac {2 a \sqrt [6]{x} \sqrt {a x^{2/3}+b} \left (\frac {\sqrt [4]{b} \left (\sqrt {a} x^{2/3}+\sqrt {b}\right ) \sqrt {\frac {a x^{4/3}+b}{\left (\sqrt {a} x^{2/3}+\sqrt {b}\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{2 a^{3/4} \sqrt {a x^{4/3}+b}}-\frac {\frac {\sqrt [4]{b} \left (\sqrt {a} x^{2/3}+\sqrt {b}\right ) \sqrt {\frac {a x^{4/3}+b}{\left (\sqrt {a} x^{2/3}+\sqrt {b}\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{a} \sqrt [6]{x}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{\sqrt [4]{a} \sqrt {a x^{4/3}+b}}-\frac {\sqrt [6]{x} \sqrt {a x^{4/3}+b}}{\sqrt {a} x^{2/3}+\sqrt {b}}}{\sqrt {a}}\right )}{b \sqrt {a x+b \sqrt [3]{x}}}-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{b \sqrt [3]{x}}\right )-\frac {2 \sqrt {a x+b \sqrt [3]{x}}}{5 x}\right )-\frac {2 \left (a x+b \sqrt [3]{x}\right )^{3/2}}{9 x^2}\right )\) |
Input:
Int[(b*x^(1/3) + a*x)^(3/2)/x^3,x]
Output:
3*((-2*(b*x^(1/3) + a*x)^(3/2))/(9*x^2) + (2*a*((-2*Sqrt[b*x^(1/3) + a*x]) /(5*x) + (2*a*((-2*Sqrt[b*x^(1/3) + a*x])/(b*x^(1/3)) + (2*a*Sqrt[b + a*x^ (2/3)]*x^(1/6)*(-((-((x^(1/6)*Sqrt[b + a*x^(4/3)])/(Sqrt[b] + Sqrt[a]*x^(2 /3))) + (b^(1/4)*(Sqrt[b] + Sqrt[a]*x^(2/3))*Sqrt[(b + a*x^(4/3))/(Sqrt[b] + Sqrt[a]*x^(2/3))^2]*EllipticE[2*ArcTan[(a^(1/4)*x^(1/6))/b^(1/4)], 1/2] )/(a^(1/4)*Sqrt[b + a*x^(4/3)]))/Sqrt[a]) + (b^(1/4)*(Sqrt[b] + Sqrt[a]*x^ (2/3))*Sqrt[(b + a*x^(4/3))/(Sqrt[b] + Sqrt[a]*x^(2/3))^2]*EllipticF[2*Arc Tan[(a^(1/4)*x^(1/6))/b^(1/4)], 1/2])/(2*a^(3/4)*Sqrt[b + a*x^(4/3)])))/(b *Sqrt[b*x^(1/3) + a*x])))/5))/3)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[( 1 + q^2*x^2)*(Sqrt[(a + b*x^4)/(a*(1 + q^2*x^2)^2)]/(2*q*Sqrt[a + b*x^4]))* EllipticF[2*ArcTan[q*x], 1/2], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]
Int[(x_)^2/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 2]}, S imp[1/q Int[1/Sqrt[a + b*x^4], x], x] - Simp[1/q Int[(1 - q*x^2)/Sqrt[a + b*x^4], x], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]
Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> With[{q = Rt[c/a, 4]}, Simp[(-d)*x*(Sqrt[a + c*x^4]/(a*(1 + q^2*x^2))), x] + Simp[d* (1 + q^2*x^2)*(Sqrt[(a + c*x^4)/(a*(1 + q^2*x^2)^2)]/(q*Sqrt[a + c*x^4]))*E llipticE[2*ArcTan[q*x], 1/2], x] /; EqQ[e + d*q^2, 0]] /; FreeQ[{a, c, d, e }, x] && PosQ[c/a]
Int[(x_)^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp [1/n Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a*x^Simplify[j/n] + b*x)^p, x ], x, x^n], x] /; FreeQ[{a, b, j, m, n, p}, x] && !IntegerQ[p] && NeQ[n, j ] && IntegerQ[Simplify[j/n]] && IntegerQ[Simplify[(m + 1)/n]] && NeQ[n^2, 1 ]
Int[((c_.)*(x_))^(m_)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Simp[(c*x)^(m + 1)*((a*x^j + b*x^n)^p/(c*(m + j*p + 1))), x] - Simp[b*p *((n - j)/(c^n*(m + j*p + 1))) Int[(c*x)^(m + n)*(a*x^j + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c}, x] && !IntegerQ[p] && LtQ[0, j, n] && (Integer sQ[j, n] || GtQ[c, 0]) && GtQ[p, 0] && LtQ[m + j*p + 1, 0]
Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol ] :> Simp[c^(j - 1)*(c*x)^(m - j + 1)*((a*x^j + b*x^n)^(p + 1)/(a*(m + j*p + 1))), x] - Simp[b*((m + n*p + n - j + 1)/(a*c^(n - j)*(m + j*p + 1))) I nt[(c*x)^(m + n - j)*(a*x^j + b*x^n)^p, x], x] /; FreeQ[{a, b, c, m, p}, x] && !IntegerQ[p] && LtQ[0, j, n] && (IntegersQ[j, n] || GtQ[c, 0]) && LtQ[ m + j*p + 1, 0]
Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol ] :> Simp[c^IntPart[m]*(c*x)^FracPart[m]*((a*x^j + b*x^n)^FracPart[p]/(x^(F racPart[m] + j*FracPart[p])*(a + b*x^(n - j))^FracPart[p])) Int[x^(m + j* p)*(a + b*x^(n - j))^p, x], x] /; FreeQ[{a, b, c, j, m, n, p}, x] && !Inte gerQ[p] && NeQ[n, j] && PosQ[n - j]
Time = 1.58 (sec) , antiderivative size = 235, normalized size of antiderivative = 0.67
| method | result | size |
| derivativedivides | \(-\frac {2 b \sqrt {b \,x^{\frac {1}{3}}+a x}}{3 x^{\frac {5}{3}}}-\frac {22 a \sqrt {b \,x^{\frac {1}{3}}+a x}}{15 x}-\frac {8 \left (b +a \,x^{\frac {2}{3}}\right ) a^{2}}{5 b \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}}+\frac {4 a^{2} \sqrt {-a b}\, \sqrt {\frac {\left (x^{\frac {1}{3}}+\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x^{\frac {1}{3}}-\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}\, \sqrt {-\frac {x^{\frac {1}{3}} a}{\sqrt {-a b}}}\, \left (-\frac {2 \sqrt {-a b}\, \operatorname {EllipticE}\left (\sqrt {\frac {\left (x^{\frac {1}{3}}+\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{a}+\frac {\sqrt {-a b}\, \operatorname {EllipticF}\left (\sqrt {\frac {\left (x^{\frac {1}{3}}+\frac {\sqrt {-a b}}{a}\right ) a}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{a}\right )}{5 b \sqrt {b \,x^{\frac {1}{3}}+a x}}\) | \(235\) |
| default | \(-\frac {2 \left (-12 a^{2} b \sqrt {\frac {x^{\frac {1}{3}} a +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x^{\frac {1}{3}} a -\sqrt {-a b}\right )}{\sqrt {-a b}}}\, \sqrt {-\frac {x^{\frac {1}{3}} a}{\sqrt {-a b}}}\, x^{\frac {8}{3}} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, \operatorname {EllipticE}\left (\sqrt {\frac {x^{\frac {1}{3}} a +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )+6 a^{2} b \sqrt {\frac {x^{\frac {1}{3}} a +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x^{\frac {1}{3}} a -\sqrt {-a b}\right )}{\sqrt {-a b}}}\, \sqrt {-\frac {x^{\frac {1}{3}} a}{\sqrt {-a b}}}\, x^{\frac {8}{3}} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, \operatorname {EllipticF}\left (\sqrt {\frac {x^{\frac {1}{3}} a +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )+12 x^{\frac {10}{3}} \sqrt {b \,x^{\frac {1}{3}}+a x}\, a^{3}+12 x^{\frac {8}{3}} \sqrt {b \,x^{\frac {1}{3}}+a x}\, a^{2} b +16 x^{2} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, a \,b^{2}+11 x^{\frac {8}{3}} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, a^{2} b +5 x^{\frac {4}{3}} \sqrt {x^{\frac {1}{3}} \left (b +a \,x^{\frac {2}{3}}\right )}\, b^{3}\right )}{15 b \,x^{3} \left (b +a \,x^{\frac {2}{3}}\right )}\) | \(339\) |
Input:
int((b*x^(1/3)+a*x)^(3/2)/x^3,x,method=_RETURNVERBOSE)
Output:
-2/3*b*(b*x^(1/3)+a*x)^(1/2)/x^(5/3)-22/15*a*(b*x^(1/3)+a*x)^(1/2)/x-8/5*( b+a*x^(2/3))*a^2/b/(x^(1/3)*(b+a*x^(2/3)))^(1/2)+4/5*a^2/b*(-a*b)^(1/2)*(( x^(1/3)+1/a*(-a*b)^(1/2))*a/(-a*b)^(1/2))^(1/2)*(-2*(x^(1/3)-1/a*(-a*b)^(1 /2))*a/(-a*b)^(1/2))^(1/2)*(-x^(1/3)/(-a*b)^(1/2)*a)^(1/2)/(b*x^(1/3)+a*x) ^(1/2)*(-2/a*(-a*b)^(1/2)*EllipticE(((x^(1/3)+1/a*(-a*b)^(1/2))*a/(-a*b)^( 1/2))^(1/2),1/2*2^(1/2))+1/a*(-a*b)^(1/2)*EllipticF(((x^(1/3)+1/a*(-a*b)^( 1/2))*a/(-a*b)^(1/2))^(1/2),1/2*2^(1/2)))
\[ \int \frac {\left (b \sqrt [3]{x}+a x\right )^{3/2}}{x^3} \, dx=\int { \frac {{\left (a x + b x^{\frac {1}{3}}\right )}^{\frac {3}{2}}}{x^{3}} \,d x } \] Input:
integrate((b*x^(1/3)+a*x)^(3/2)/x^3,x, algorithm="fricas")
Output:
integral((a*x + b*x^(1/3))^(3/2)/x^3, x)
\[ \int \frac {\left (b \sqrt [3]{x}+a x\right )^{3/2}}{x^3} \, dx=\int \frac {\left (a x + b \sqrt [3]{x}\right )^{\frac {3}{2}}}{x^{3}}\, dx \] Input:
integrate((b*x**(1/3)+a*x)**(3/2)/x**3,x)
Output:
Integral((a*x + b*x**(1/3))**(3/2)/x**3, x)
\[ \int \frac {\left (b \sqrt [3]{x}+a x\right )^{3/2}}{x^3} \, dx=\int { \frac {{\left (a x + b x^{\frac {1}{3}}\right )}^{\frac {3}{2}}}{x^{3}} \,d x } \] Input:
integrate((b*x^(1/3)+a*x)^(3/2)/x^3,x, algorithm="maxima")
Output:
integrate((a*x + b*x^(1/3))^(3/2)/x^3, x)
\[ \int \frac {\left (b \sqrt [3]{x}+a x\right )^{3/2}}{x^3} \, dx=\int { \frac {{\left (a x + b x^{\frac {1}{3}}\right )}^{\frac {3}{2}}}{x^{3}} \,d x } \] Input:
integrate((b*x^(1/3)+a*x)^(3/2)/x^3,x, algorithm="giac")
Output:
integrate((a*x + b*x^(1/3))^(3/2)/x^3, x)
Timed out. \[ \int \frac {\left (b \sqrt [3]{x}+a x\right )^{3/2}}{x^3} \, dx=\int \frac {{\left (a\,x+b\,x^{1/3}\right )}^{3/2}}{x^3} \,d x \] Input:
int((a*x + b*x^(1/3))^(3/2)/x^3,x)
Output:
int((a*x + b*x^(1/3))^(3/2)/x^3, x)
\[ \int \frac {\left (b \sqrt [3]{x}+a x\right )^{3/2}}{x^3} \, dx=\frac {-2 x^{\frac {2}{3}} \sqrt {x^{\frac {2}{3}} a +b}\, a -\frac {2 \sqrt {x^{\frac {2}{3}} a +b}\, b}{7}+\frac {4 \sqrt {x}\, \left (\int \frac {\sqrt {x^{\frac {2}{3}} a +b}}{\sqrt {x}\, b \,x^{2}+x^{\frac {19}{6}} a}d x \right ) b^{2} x}{7}}{\sqrt {x}\, x} \] Input:
int((b*x^(1/3)+a*x)^(3/2)/x^3,x)
Output:
(2*( - 7*x**(2/3)*sqrt(x**(2/3)*a + b)*a - sqrt(x**(2/3)*a + b)*b + 2*sqrt (x)*int(sqrt(x**(2/3)*a + b)/(sqrt(x)*b*x**2 + x**(1/6)*a*x**3),x)*b**2*x) )/(7*sqrt(x)*x)