Integrand size = 17, antiderivative size = 255 \[ \int x \left (b x^{2/3}+a x\right )^{3/2} \, dx=-\frac {256 b^3 \left (b x^{2/3}+a x\right )^{5/2}}{1615 a^4}+\frac {65536 b^8 \left (b x^{2/3}+a x\right )^{5/2}}{4849845 a^9 x^{5/3}}-\frac {32768 b^7 \left (b x^{2/3}+a x\right )^{5/2}}{969969 a^8 x^{4/3}}+\frac {8192 b^6 \left (b x^{2/3}+a x\right )^{5/2}}{138567 a^7 x}-\frac {4096 b^5 \left (b x^{2/3}+a x\right )^{5/2}}{46189 a^6 x^{2/3}}+\frac {512 b^4 \left (b x^{2/3}+a x\right )^{5/2}}{4199 a^5 \sqrt [3]{x}}+\frac {64 b^2 \sqrt [3]{x} \left (b x^{2/3}+a x\right )^{5/2}}{323 a^3}-\frac {32 b x^{2/3} \left (b x^{2/3}+a x\right )^{5/2}}{133 a^2}+\frac {2 x \left (b x^{2/3}+a x\right )^{5/2}}{7 a} \] Output:
-256/1615*b^3*(b*x^(2/3)+a*x)^(5/2)/a^4+65536/4849845*b^8*(b*x^(2/3)+a*x)^ (5/2)/a^9/x^(5/3)-32768/969969*b^7*(b*x^(2/3)+a*x)^(5/2)/a^8/x^(4/3)+8192/ 138567*b^6*(b*x^(2/3)+a*x)^(5/2)/a^7/x-4096/46189*b^5*(b*x^(2/3)+a*x)^(5/2 )/a^6/x^(2/3)+512/4199*b^4*(b*x^(2/3)+a*x)^(5/2)/a^5/x^(1/3)+64/323*b^2*x^ (1/3)*(b*x^(2/3)+a*x)^(5/2)/a^3-32/133*b*x^(2/3)*(b*x^(2/3)+a*x)^(5/2)/a^2 +2/7*x*(b*x^(2/3)+a*x)^(5/2)/a
Time = 5.13 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.51 \[ \int x \left (b x^{2/3}+a x\right )^{3/2} \, dx=\frac {2 \left (b+a \sqrt [3]{x}\right ) \left (b x^{2/3}+a x\right )^{3/2} \left (32768 b^8-81920 a b^7 \sqrt [3]{x}+143360 a^2 b^6 x^{2/3}-215040 a^3 b^5 x+295680 a^4 b^4 x^{4/3}-384384 a^5 b^3 x^{5/3}+480480 a^6 b^2 x^2-583440 a^7 b x^{7/3}+692835 a^8 x^{8/3}\right )}{4849845 a^9 x} \] Input:
Integrate[x*(b*x^(2/3) + a*x)^(3/2),x]
Output:
(2*(b + a*x^(1/3))*(b*x^(2/3) + a*x)^(3/2)*(32768*b^8 - 81920*a*b^7*x^(1/3 ) + 143360*a^2*b^6*x^(2/3) - 215040*a^3*b^5*x + 295680*a^4*b^4*x^(4/3) - 3 84384*a^5*b^3*x^(5/3) + 480480*a^6*b^2*x^2 - 583440*a^7*b*x^(7/3) + 692835 *a^8*x^(8/3)))/(4849845*a^9*x)
Time = 0.97 (sec) , antiderivative size = 297, normalized size of antiderivative = 1.16, number of steps used = 9, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.529, Rules used = {1922, 1922, 1922, 1908, 1922, 1922, 1922, 1922, 1920}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x \left (a x+b x^{2/3}\right )^{3/2} \, dx\) |
\(\Big \downarrow \) 1922 |
\(\displaystyle \frac {2 x \left (a x+b x^{2/3}\right )^{5/2}}{7 a}-\frac {16 b \int x^{2/3} \left (x^{2/3} b+a x\right )^{3/2}dx}{21 a}\) |
\(\Big \downarrow \) 1922 |
\(\displaystyle \frac {2 x \left (a x+b x^{2/3}\right )^{5/2}}{7 a}-\frac {16 b \left (\frac {6 x^{2/3} \left (a x+b x^{2/3}\right )^{5/2}}{19 a}-\frac {14 b \int \sqrt [3]{x} \left (x^{2/3} b+a x\right )^{3/2}dx}{19 a}\right )}{21 a}\) |
\(\Big \downarrow \) 1922 |
\(\displaystyle \frac {2 x \left (a x+b x^{2/3}\right )^{5/2}}{7 a}-\frac {16 b \left (\frac {6 x^{2/3} \left (a x+b x^{2/3}\right )^{5/2}}{19 a}-\frac {14 b \left (\frac {6 \sqrt [3]{x} \left (a x+b x^{2/3}\right )^{5/2}}{17 a}-\frac {12 b \int \left (x^{2/3} b+a x\right )^{3/2}dx}{17 a}\right )}{19 a}\right )}{21 a}\) |
\(\Big \downarrow \) 1908 |
\(\displaystyle \frac {2 x \left (a x+b x^{2/3}\right )^{5/2}}{7 a}-\frac {16 b \left (\frac {6 x^{2/3} \left (a x+b x^{2/3}\right )^{5/2}}{19 a}-\frac {14 b \left (\frac {6 \sqrt [3]{x} \left (a x+b x^{2/3}\right )^{5/2}}{17 a}-\frac {12 b \left (\frac {2 \left (a x+b x^{2/3}\right )^{5/2}}{5 a}-\frac {2 b \int \frac {\left (x^{2/3} b+a x\right )^{3/2}}{\sqrt [3]{x}}dx}{3 a}\right )}{17 a}\right )}{19 a}\right )}{21 a}\) |
\(\Big \downarrow \) 1922 |
\(\displaystyle \frac {2 x \left (a x+b x^{2/3}\right )^{5/2}}{7 a}-\frac {16 b \left (\frac {6 x^{2/3} \left (a x+b x^{2/3}\right )^{5/2}}{19 a}-\frac {14 b \left (\frac {6 \sqrt [3]{x} \left (a x+b x^{2/3}\right )^{5/2}}{17 a}-\frac {12 b \left (\frac {2 \left (a x+b x^{2/3}\right )^{5/2}}{5 a}-\frac {2 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{13 a \sqrt [3]{x}}-\frac {8 b \int \frac {\left (x^{2/3} b+a x\right )^{3/2}}{x^{2/3}}dx}{13 a}\right )}{3 a}\right )}{17 a}\right )}{19 a}\right )}{21 a}\) |
\(\Big \downarrow \) 1922 |
\(\displaystyle \frac {2 x \left (a x+b x^{2/3}\right )^{5/2}}{7 a}-\frac {16 b \left (\frac {6 x^{2/3} \left (a x+b x^{2/3}\right )^{5/2}}{19 a}-\frac {14 b \left (\frac {6 \sqrt [3]{x} \left (a x+b x^{2/3}\right )^{5/2}}{17 a}-\frac {12 b \left (\frac {2 \left (a x+b x^{2/3}\right )^{5/2}}{5 a}-\frac {2 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{13 a \sqrt [3]{x}}-\frac {8 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{11 a x^{2/3}}-\frac {6 b \int \frac {\left (x^{2/3} b+a x\right )^{3/2}}{x}dx}{11 a}\right )}{13 a}\right )}{3 a}\right )}{17 a}\right )}{19 a}\right )}{21 a}\) |
\(\Big \downarrow \) 1922 |
\(\displaystyle \frac {2 x \left (a x+b x^{2/3}\right )^{5/2}}{7 a}-\frac {16 b \left (\frac {6 x^{2/3} \left (a x+b x^{2/3}\right )^{5/2}}{19 a}-\frac {14 b \left (\frac {6 \sqrt [3]{x} \left (a x+b x^{2/3}\right )^{5/2}}{17 a}-\frac {12 b \left (\frac {2 \left (a x+b x^{2/3}\right )^{5/2}}{5 a}-\frac {2 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{13 a \sqrt [3]{x}}-\frac {8 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{11 a x^{2/3}}-\frac {6 b \left (\frac {2 \left (a x+b x^{2/3}\right )^{5/2}}{3 a x}-\frac {4 b \int \frac {\left (x^{2/3} b+a x\right )^{3/2}}{x^{4/3}}dx}{9 a}\right )}{11 a}\right )}{13 a}\right )}{3 a}\right )}{17 a}\right )}{19 a}\right )}{21 a}\) |
\(\Big \downarrow \) 1922 |
\(\displaystyle \frac {2 x \left (a x+b x^{2/3}\right )^{5/2}}{7 a}-\frac {16 b \left (\frac {6 x^{2/3} \left (a x+b x^{2/3}\right )^{5/2}}{19 a}-\frac {14 b \left (\frac {6 \sqrt [3]{x} \left (a x+b x^{2/3}\right )^{5/2}}{17 a}-\frac {12 b \left (\frac {2 \left (a x+b x^{2/3}\right )^{5/2}}{5 a}-\frac {2 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{13 a \sqrt [3]{x}}-\frac {8 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{11 a x^{2/3}}-\frac {6 b \left (\frac {2 \left (a x+b x^{2/3}\right )^{5/2}}{3 a x}-\frac {4 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{7 a x^{4/3}}-\frac {2 b \int \frac {\left (x^{2/3} b+a x\right )^{3/2}}{x^{5/3}}dx}{7 a}\right )}{9 a}\right )}{11 a}\right )}{13 a}\right )}{3 a}\right )}{17 a}\right )}{19 a}\right )}{21 a}\) |
\(\Big \downarrow \) 1920 |
\(\displaystyle \frac {2 x \left (a x+b x^{2/3}\right )^{5/2}}{7 a}-\frac {16 b \left (\frac {6 x^{2/3} \left (a x+b x^{2/3}\right )^{5/2}}{19 a}-\frac {14 b \left (\frac {6 \sqrt [3]{x} \left (a x+b x^{2/3}\right )^{5/2}}{17 a}-\frac {12 b \left (\frac {2 \left (a x+b x^{2/3}\right )^{5/2}}{5 a}-\frac {2 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{13 a \sqrt [3]{x}}-\frac {8 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{11 a x^{2/3}}-\frac {6 b \left (\frac {2 \left (a x+b x^{2/3}\right )^{5/2}}{3 a x}-\frac {4 b \left (\frac {6 \left (a x+b x^{2/3}\right )^{5/2}}{7 a x^{4/3}}-\frac {12 b \left (a x+b x^{2/3}\right )^{5/2}}{35 a^2 x^{5/3}}\right )}{9 a}\right )}{11 a}\right )}{13 a}\right )}{3 a}\right )}{17 a}\right )}{19 a}\right )}{21 a}\) |
Input:
Int[x*(b*x^(2/3) + a*x)^(3/2),x]
Output:
(2*x*(b*x^(2/3) + a*x)^(5/2))/(7*a) - (16*b*((6*x^(2/3)*(b*x^(2/3) + a*x)^ (5/2))/(19*a) - (14*b*((6*x^(1/3)*(b*x^(2/3) + a*x)^(5/2))/(17*a) - (12*b* ((2*(b*x^(2/3) + a*x)^(5/2))/(5*a) - (2*b*((6*(b*x^(2/3) + a*x)^(5/2))/(13 *a*x^(1/3)) - (8*b*((6*(b*x^(2/3) + a*x)^(5/2))/(11*a*x^(2/3)) - (6*b*((2* (b*x^(2/3) + a*x)^(5/2))/(3*a*x) - (4*b*((-12*b*(b*x^(2/3) + a*x)^(5/2))/( 35*a^2*x^(5/3)) + (6*(b*x^(2/3) + a*x)^(5/2))/(7*a*x^(4/3))))/(9*a)))/(11* a)))/(13*a)))/(3*a)))/(17*a)))/(19*a)))/(21*a)
Int[((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Simp[(a*x^j + b*x^n)^(p + 1)/(a*(j*p + 1)*x^(j - 1)), x] - Simp[b*((n*p + n - j + 1)/(a*( j*p + 1))) Int[x^(n - j)*(a*x^j + b*x^n)^p, x], x] /; FreeQ[{a, b, j, n, p}, x] && !IntegerQ[p] && NeQ[n, j] && ILtQ[Simplify[(n*p + n - j + 1)/(n - j)], 0] && NeQ[j*p + 1, 0]
Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol ] :> Simp[(-c^(j - 1))*(c*x)^(m - j + 1)*((a*x^j + b*x^n)^(p + 1)/(a*(n - j )*(p + 1))), x] /; FreeQ[{a, b, c, j, m, n, p}, x] && !IntegerQ[p] && NeQ[ n, j] && EqQ[m + n*p + n - j + 1, 0] && (IntegerQ[j] || GtQ[c, 0])
Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol ] :> Simp[c^(j - 1)*(c*x)^(m - j + 1)*((a*x^j + b*x^n)^(p + 1)/(a*(m + j*p + 1))), x] - Simp[b*((m + n*p + n - j + 1)/(a*c^(n - j)*(m + j*p + 1))) I nt[(c*x)^(m + n - j)*(a*x^j + b*x^n)^p, x], x] /; FreeQ[{a, b, c, j, m, n, p}, x] && !IntegerQ[p] && NeQ[n, j] && ILtQ[Simplify[(m + n*p + n - j + 1) /(n - j)], 0] && NeQ[m + j*p + 1, 0] && (IntegersQ[j, n] || GtQ[c, 0])
Time = 0.38 (sec) , antiderivative size = 112, normalized size of antiderivative = 0.44
method | result | size |
derivativedivides | \(\frac {2 \left (b \,x^{\frac {2}{3}}+a x \right )^{\frac {3}{2}} \left (x^{\frac {1}{3}} a +b \right ) \left (692835 a^{8} x^{\frac {8}{3}}-583440 a^{7} b \,x^{\frac {7}{3}}+480480 a^{6} b^{2} x^{2}-384384 a^{5} b^{3} x^{\frac {5}{3}}+295680 x^{\frac {4}{3}} a^{4} b^{4}-215040 a^{3} b^{5} x +143360 a^{2} b^{6} x^{\frac {2}{3}}-81920 x^{\frac {1}{3}} a \,b^{7}+32768 b^{8}\right )}{4849845 x \,a^{9}}\) | \(112\) |
default | \(\frac {2 \left (b \,x^{\frac {2}{3}}+a x \right )^{\frac {3}{2}} \left (x^{\frac {1}{3}} a +b \right ) \left (692835 a^{8} x^{\frac {8}{3}}-583440 a^{7} b \,x^{\frac {7}{3}}+480480 a^{6} b^{2} x^{2}-384384 a^{5} b^{3} x^{\frac {5}{3}}+295680 x^{\frac {4}{3}} a^{4} b^{4}-215040 a^{3} b^{5} x +143360 a^{2} b^{6} x^{\frac {2}{3}}-81920 x^{\frac {1}{3}} a \,b^{7}+32768 b^{8}\right )}{4849845 x \,a^{9}}\) | \(112\) |
Input:
int(x*(b*x^(2/3)+a*x)^(3/2),x,method=_RETURNVERBOSE)
Output:
2/4849845*(b*x^(2/3)+a*x)^(3/2)*(x^(1/3)*a+b)*(692835*a^8*x^(8/3)-583440*a ^7*b*x^(7/3)+480480*a^6*b^2*x^2-384384*a^5*b^3*x^(5/3)+295680*x^(4/3)*a^4* b^4-215040*a^3*b^5*x+143360*a^2*b^6*x^(2/3)-81920*x^(1/3)*a*b^7+32768*b^8) /x/a^9
Leaf count of result is larger than twice the leaf count of optimal. 1031 vs. \(2 (189) = 378\).
Time = 141.72 (sec) , antiderivative size = 1031, normalized size of antiderivative = 4.04 \[ \int x \left (b x^{2/3}+a x\right )^{3/2} \, dx=\text {Too large to display} \] Input:
integrate(x*(b*x^(2/3)+a*x)^(3/2),x, algorithm="fricas")
Output:
-1/4849845*((824633720832*b^16 + 171798691840*b^15 + 805306368*(64*a^3 - 3 )*b^13 - 16106127360*b^14 - 4194304*(11264*a^3 - 53)*b^12 - 8070142080*a^1 2 - 1572864*(5504*a^3 + 1)*b^11 + 49152*(3194880*a^6 - 114688*a^3 - 3)*b^1 0 + 1835008*(18816*a^6 + 103*a^3)*b^9 - 196608*(48816*a^6 + 23*a^3)*b^8 + 3072*(6575923200*a^9 + 495872*a^6 + 15*a^3)*b^7 + 28672*(146455680*a^9 - 3 439*a^6)*b^6 - 419328*(934400*a^9 - 7*a^6)*b^5 + 1584*(12166103040*a^12 - 38275840*a^9 - 21*a^6)*b^4 + 164736*(43008000*a^12 + 33737*a^9)*b^3 + 5148 0*(10838016*a^12 - 799*a^9)*b^2 - 109395*(401408*a^12 + 33*a^9)*b)*x - 2*( 692835*(16777216*a^10*b^6 + 6291456*a^10*b^5 + 196608*a^10*b^4 - 262144*a^ 13 - 114688*a^10*b^3 - 2304*a^10*b^2 + 864*a^10*b - 27*a^10)*x^4 - 6864*(1 6777216*a^7*b^9 + 6291456*a^7*b^8 + 196608*a^7*b^7 - 114688*a^7*b^6 - 2304 *a^7*b^5 + 864*a^7*b^4 - (262144*a^10 + 27*a^7)*b^3)*x^3 + 8960*(16777216* a^4*b^12 + 6291456*a^4*b^11 + 196608*a^4*b^10 - 114688*a^4*b^9 - 2304*a^4* b^8 + 864*a^4*b^7 - (262144*a^7 + 27*a^4)*b^6)*x^2 - 16384*(16777216*a*b^1 5 + 6291456*a*b^14 + 196608*a*b^13 - 114688*a*b^12 - 2304*a*b^11 + 864*a*b ^10 - (262144*a^4 + 27*a)*b^9)*x + 2*(274877906944*b^16 + 103079215104*b^1 5 + 3221225472*b^14 - 1879048192*b^13 - 37748736*b^12 - 16384*(262144*a^3 + 27)*b^10 + 14155776*b^11 + 401115*(16777216*a^9*b^7 + 6291456*a^9*b^6 + 196608*a^9*b^5 - 114688*a^9*b^4 - 2304*a^9*b^3 + 864*a^9*b^2 - (262144*a^1 2 + 27*a^9)*b)*x^3 + 3696*(16777216*a^6*b^10 + 6291456*a^6*b^9 + 196608...
\[ \int x \left (b x^{2/3}+a x\right )^{3/2} \, dx=\int x \left (a x + b x^{\frac {2}{3}}\right )^{\frac {3}{2}}\, dx \] Input:
integrate(x*(b*x**(2/3)+a*x)**(3/2),x)
Output:
Integral(x*(a*x + b*x**(2/3))**(3/2), x)
\[ \int x \left (b x^{2/3}+a x\right )^{3/2} \, dx=\int { {\left (a x + b x^{\frac {2}{3}}\right )}^{\frac {3}{2}} x \,d x } \] Input:
integrate(x*(b*x^(2/3)+a*x)^(3/2),x, algorithm="maxima")
Output:
integrate((a*x + b*x^(2/3))^(3/2)*x, x)
Leaf count of result is larger than twice the leaf count of optimal. 602 vs. \(2 (189) = 378\).
Time = 0.27 (sec) , antiderivative size = 602, normalized size of antiderivative = 2.36 \[ \int x \left (b x^{2/3}+a x\right )^{3/2} \, dx =\text {Too large to display} \] Input:
integrate(x*(b*x^(2/3)+a*x)^(3/2),x, algorithm="giac")
Output:
-2/692835*b*(32768*b^(19/2)/a^9 - (19*(6435*(a*x^(1/3) + b)^(17/2) - 58344 *(a*x^(1/3) + b)^(15/2)*b + 235620*(a*x^(1/3) + b)^(13/2)*b^2 - 556920*(a* x^(1/3) + b)^(11/2)*b^3 + 850850*(a*x^(1/3) + b)^(9/2)*b^4 - 875160*(a*x^( 1/3) + b)^(7/2)*b^5 + 612612*(a*x^(1/3) + b)^(5/2)*b^6 - 291720*(a*x^(1/3) + b)^(3/2)*b^7 + 109395*sqrt(a*x^(1/3) + b)*b^8)*b/a^8 + 9*(12155*(a*x^(1 /3) + b)^(19/2) - 122265*(a*x^(1/3) + b)^(17/2)*b + 554268*(a*x^(1/3) + b) ^(15/2)*b^2 - 1492260*(a*x^(1/3) + b)^(13/2)*b^3 + 2645370*(a*x^(1/3) + b) ^(11/2)*b^4 - 3233230*(a*x^(1/3) + b)^(9/2)*b^5 + 2771340*(a*x^(1/3) + b)^ (7/2)*b^6 - 1662804*(a*x^(1/3) + b)^(5/2)*b^7 + 692835*(a*x^(1/3) + b)^(3/ 2)*b^8 - 230945*sqrt(a*x^(1/3) + b)*b^9)/a^8)/a) + 2/1616615*a*(65536*b^(2 1/2)/a^10 + (21*(12155*(a*x^(1/3) + b)^(19/2) - 122265*(a*x^(1/3) + b)^(17 /2)*b + 554268*(a*x^(1/3) + b)^(15/2)*b^2 - 1492260*(a*x^(1/3) + b)^(13/2) *b^3 + 2645370*(a*x^(1/3) + b)^(11/2)*b^4 - 3233230*(a*x^(1/3) + b)^(9/2)* b^5 + 2771340*(a*x^(1/3) + b)^(7/2)*b^6 - 1662804*(a*x^(1/3) + b)^(5/2)*b^ 7 + 692835*(a*x^(1/3) + b)^(3/2)*b^8 - 230945*sqrt(a*x^(1/3) + b)*b^9)*b/a ^9 + 5*(46189*(a*x^(1/3) + b)^(21/2) - 510510*(a*x^(1/3) + b)^(19/2)*b + 2 567565*(a*x^(1/3) + b)^(17/2)*b^2 - 7759752*(a*x^(1/3) + b)^(15/2)*b^3 + 1 5668730*(a*x^(1/3) + b)^(13/2)*b^4 - 22221108*(a*x^(1/3) + b)^(11/2)*b^5 + 22632610*(a*x^(1/3) + b)^(9/2)*b^6 - 16628040*(a*x^(1/3) + b)^(7/2)*b^7 + 8729721*(a*x^(1/3) + b)^(5/2)*b^8 - 3233230*(a*x^(1/3) + b)^(3/2)*b^9 ...
Timed out. \[ \int x \left (b x^{2/3}+a x\right )^{3/2} \, dx=\int x\,{\left (a\,x+b\,x^{2/3}\right )}^{3/2} \,d x \] Input:
int(x*(a*x + b*x^(2/3))^(3/2),x)
Output:
int(x*(a*x + b*x^(2/3))^(3/2), x)
Time = 0.20 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.47 \[ \int x \left (b x^{2/3}+a x\right )^{3/2} \, dx=\frac {2 \sqrt {x^{\frac {1}{3}} a +b}\, \left (6435 x^{\frac {8}{3}} a^{8} b^{2}-8064 x^{\frac {5}{3}} a^{5} b^{5}+12288 x^{\frac {2}{3}} a^{2} b^{8}+692835 x^{\frac {10}{3}} a^{10}-6864 x^{\frac {7}{3}} a^{7} b^{3}+8960 x^{\frac {4}{3}} a^{4} b^{6}-16384 x^{\frac {1}{3}} a \,b^{9}+802230 a^{9} b \,x^{3}+7392 a^{6} b^{4} x^{2}-10240 a^{3} b^{7} x +32768 b^{10}\right )}{4849845 a^{9}} \] Input:
int(x*(b*x^(2/3)+a*x)^(3/2),x)
Output:
(2*sqrt(x**(1/3)*a + b)*(6435*x**(2/3)*a**8*b**2*x**2 - 8064*x**(2/3)*a**5 *b**5*x + 12288*x**(2/3)*a**2*b**8 + 692835*x**(1/3)*a**10*x**3 - 6864*x** (1/3)*a**7*b**3*x**2 + 8960*x**(1/3)*a**4*b**6*x - 16384*x**(1/3)*a*b**9 + 802230*a**9*b*x**3 + 7392*a**6*b**4*x**2 - 10240*a**3*b**7*x + 32768*b**1 0))/(4849845*a**9)