\(\int \frac {\sqrt {x} (A+B x^2)}{(b x^2+c x^4)^3} \, dx\) [152]

Optimal result

Integrand size = 26, antiderivative size = 288 \[ \int \frac {\sqrt {x} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx=-\frac {2 A}{9 b^3 x^{9/2}}-\frac {2 (b B-3 A c)}{5 b^4 x^{5/2}}+\frac {6 c (b B-2 A c)}{b^5 \sqrt {x}}+\frac {c^2 (b B-A c) x^{3/2}}{4 b^4 \left (b+c x^2\right )^2}+\frac {c^2 (21 b B-29 A c) x^{3/2}}{16 b^5 \left (b+c x^2\right )}-\frac {13 c^{5/4} (9 b B-17 A c) \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{32 \sqrt {2} b^{21/4}}+\frac {13 c^{5/4} (9 b B-17 A c) \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{32 \sqrt {2} b^{21/4}}-\frac {13 c^{5/4} (9 b B-17 A c) \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}}{\sqrt {b}+\sqrt {c} x}\right )}{32 \sqrt {2} b^{21/4}} \] Output:

-2/9*A/b^3/x^(9/2)-2/5*(-3*A*c+B*b)/b^4/x^(5/2)+6*c*(-2*A*c+B*b)/b^5/x^(1/ 
2)+1/4*c^2*(-A*c+B*b)*x^(3/2)/b^4/(c*x^2+b)^2+1/16*c^2*(-29*A*c+21*B*b)*x^ 
(3/2)/b^5/(c*x^2+b)-13/64*c^(5/4)*(-17*A*c+9*B*b)*arctan(1-2^(1/2)*c^(1/4) 
*x^(1/2)/b^(1/4))*2^(1/2)/b^(21/4)+13/64*c^(5/4)*(-17*A*c+9*B*b)*arctan(1+ 
2^(1/2)*c^(1/4)*x^(1/2)/b^(1/4))*2^(1/2)/b^(21/4)-13/64*c^(5/4)*(-17*A*c+9 
*B*b)*arctanh(2^(1/2)*b^(1/4)*c^(1/4)*x^(1/2)/(b^(1/2)+c^(1/2)*x))*2^(1/2) 
/b^(21/4)
 

Mathematica [A] (verified)

Time = 0.69 (sec) , antiderivative size = 231, normalized size of antiderivative = 0.80 \[ \int \frac {\sqrt {x} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx=\frac {-\frac {4 \sqrt [4]{b} \left (-9 b B x^2 \left (-32 b^3+416 b^2 c x^2+1053 b c^2 x^4+585 c^3 x^6\right )+A \left (160 b^4-544 b^3 c x^2+7072 b^2 c^2 x^4+17901 b c^3 x^6+9945 c^4 x^8\right )\right )}{x^{9/2} \left (b+c x^2\right )^2}+585 \sqrt {2} c^{5/4} (-9 b B+17 A c) \arctan \left (\frac {\sqrt {b}-\sqrt {c} x}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}}\right )+585 \sqrt {2} c^{5/4} (-9 b B+17 A c) \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}}{\sqrt {b}+\sqrt {c} x}\right )}{2880 b^{21/4}} \] Input:

Integrate[(Sqrt[x]*(A + B*x^2))/(b*x^2 + c*x^4)^3,x]
 

Output:

((-4*b^(1/4)*(-9*b*B*x^2*(-32*b^3 + 416*b^2*c*x^2 + 1053*b*c^2*x^4 + 585*c 
^3*x^6) + A*(160*b^4 - 544*b^3*c*x^2 + 7072*b^2*c^2*x^4 + 17901*b*c^3*x^6 
+ 9945*c^4*x^8)))/(x^(9/2)*(b + c*x^2)^2) + 585*Sqrt[2]*c^(5/4)*(-9*b*B + 
17*A*c)*ArcTan[(Sqrt[b] - Sqrt[c]*x)/(Sqrt[2]*b^(1/4)*c^(1/4)*Sqrt[x])] + 
585*Sqrt[2]*c^(5/4)*(-9*b*B + 17*A*c)*ArcTanh[(Sqrt[2]*b^(1/4)*c^(1/4)*Sqr 
t[x])/(Sqrt[b] + Sqrt[c]*x)])/(2880*b^(21/4))
 

Rubi [A] (verified)

Time = 0.95 (sec) , antiderivative size = 348, normalized size of antiderivative = 1.21, number of steps used = 16, number of rules used = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.577, Rules used = {9, 362, 253, 264, 264, 264, 266, 826, 1476, 1082, 217, 1479, 25, 27, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sqrt {x} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx\)

\(\Big \downarrow \) 9

\(\displaystyle \int \frac {A+B x^2}{x^{11/2} \left (b+c x^2\right )^3}dx\)

\(\Big \downarrow \) 362

\(\displaystyle -\frac {(9 b B-17 A c) \int \frac {1}{x^{11/2} \left (c x^2+b\right )^2}dx}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 253

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \int \frac {1}{x^{11/2} \left (c x^2+b\right )}dx}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 264

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \int \frac {1}{x^{7/2} \left (c x^2+b\right )}dx}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 264

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \int \frac {1}{x^{3/2} \left (c x^2+b\right )}dx}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 264

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {c \int \frac {\sqrt {x}}{c x^2+b}dx}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 266

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {2 c \int \frac {x}{c x^2+b}d\sqrt {x}}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 826

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {2 c \left (\frac {\int \frac {\sqrt {c} x+\sqrt {b}}{c x^2+b}d\sqrt {x}}{2 \sqrt {c}}-\frac {\int \frac {\sqrt {b}-\sqrt {c} x}{c x^2+b}d\sqrt {x}}{2 \sqrt {c}}\right )}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 1476

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {2 c \left (\frac {\frac {\int \frac {1}{x-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{c}}+\frac {\sqrt {b}}{\sqrt {c}}}d\sqrt {x}}{2 \sqrt {c}}+\frac {\int \frac {1}{x+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{c}}+\frac {\sqrt {b}}{\sqrt {c}}}d\sqrt {x}}{2 \sqrt {c}}}{2 \sqrt {c}}-\frac {\int \frac {\sqrt {b}-\sqrt {c} x}{c x^2+b}d\sqrt {x}}{2 \sqrt {c}}\right )}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 1082

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {2 c \left (\frac {\frac {\int \frac {1}{-x-1}d\left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}-\frac {\int \frac {1}{-x-1}d\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}}{2 \sqrt {c}}-\frac {\int \frac {\sqrt {b}-\sqrt {c} x}{c x^2+b}d\sqrt {x}}{2 \sqrt {c}}\right )}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 217

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {2 c \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}}{2 \sqrt {c}}-\frac {\int \frac {\sqrt {b}-\sqrt {c} x}{c x^2+b}d\sqrt {x}}{2 \sqrt {c}}\right )}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 1479

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {2 c \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}}{2 \sqrt {c}}-\frac {-\frac {\int -\frac {\sqrt {2} \sqrt [4]{b}-2 \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{c} \left (x-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{c}}+\frac {\sqrt {b}}{\sqrt {c}}\right )}d\sqrt {x}}{2 \sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {2} \sqrt [4]{c} \sqrt {x}+\sqrt [4]{b}\right )}{\sqrt [4]{c} \left (x+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{c}}+\frac {\sqrt {b}}{\sqrt {c}}\right )}d\sqrt {x}}{2 \sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}}{2 \sqrt {c}}\right )}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {2 c \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}}{2 \sqrt {c}}-\frac {\frac {\int \frac {\sqrt {2} \sqrt [4]{b}-2 \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{c} \left (x-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{c}}+\frac {\sqrt {b}}{\sqrt {c}}\right )}d\sqrt {x}}{2 \sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {2} \sqrt [4]{c} \sqrt {x}+\sqrt [4]{b}\right )}{\sqrt [4]{c} \left (x+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{c}}+\frac {\sqrt {b}}{\sqrt {c}}\right )}d\sqrt {x}}{2 \sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}}{2 \sqrt {c}}\right )}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 27

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {2 c \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}}{2 \sqrt {c}}-\frac {\frac {\int \frac {\sqrt {2} \sqrt [4]{b}-2 \sqrt [4]{c} \sqrt {x}}{x-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{c}}+\frac {\sqrt {b}}{\sqrt {c}}}d\sqrt {x}}{2 \sqrt {2} \sqrt [4]{b} \sqrt {c}}+\frac {\int \frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}+\sqrt [4]{b}}{x+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{c}}+\frac {\sqrt {b}}{\sqrt {c}}}d\sqrt {x}}{2 \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {c}}\right )}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

\(\Big \downarrow \) 1103

\(\displaystyle -\frac {(9 b B-17 A c) \left (\frac {13 \left (-\frac {c \left (-\frac {c \left (-\frac {2 c \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {x}}{\sqrt [4]{b}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}}{2 \sqrt {c}}-\frac {\frac {\log \left (\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {b}+\sqrt {c} x\right )}{2 \sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}-\frac {\log \left (-\sqrt {2} \sqrt [4]{b} \sqrt [4]{c} \sqrt {x}+\sqrt {b}+\sqrt {c} x\right )}{2 \sqrt {2} \sqrt [4]{b} \sqrt [4]{c}}}{2 \sqrt {c}}\right )}{b}-\frac {2}{b \sqrt {x}}\right )}{b}-\frac {2}{5 b x^{5/2}}\right )}{b}-\frac {2}{9 b x^{9/2}}\right )}{4 b}+\frac {1}{2 b x^{9/2} \left (b+c x^2\right )}\right )}{8 b c}-\frac {b B-A c}{4 b c x^{9/2} \left (b+c x^2\right )^2}\)

Input:

Int[(Sqrt[x]*(A + B*x^2))/(b*x^2 + c*x^4)^3,x]
 

Output:

-1/4*(b*B - A*c)/(b*c*x^(9/2)*(b + c*x^2)^2) - ((9*b*B - 17*A*c)*(1/(2*b*x 
^(9/2)*(b + c*x^2)) + (13*(-2/(9*b*x^(9/2)) - (c*(-2/(5*b*x^(5/2)) - (c*(- 
2/(b*Sqrt[x]) - (2*c*((-(ArcTan[1 - (Sqrt[2]*c^(1/4)*Sqrt[x])/b^(1/4)]/(Sq 
rt[2]*b^(1/4)*c^(1/4))) + ArcTan[1 + (Sqrt[2]*c^(1/4)*Sqrt[x])/b^(1/4)]/(S 
qrt[2]*b^(1/4)*c^(1/4)))/(2*Sqrt[c]) - (-1/2*Log[Sqrt[b] - Sqrt[2]*b^(1/4) 
*c^(1/4)*Sqrt[x] + Sqrt[c]*x]/(Sqrt[2]*b^(1/4)*c^(1/4)) + Log[Sqrt[b] + Sq 
rt[2]*b^(1/4)*c^(1/4)*Sqrt[x] + Sqrt[c]*x]/(2*Sqrt[2]*b^(1/4)*c^(1/4)))/(2 
*Sqrt[c])))/b))/b))/b))/(4*b)))/(8*b*c)
 

Defintions of rubi rules used

rule 9

Int[(u_.)*(Px_)^(p_.)*((e_.)*(x_))^(m_.), x_Symbol] :> With[{r = Expon[Px, 
x, Min]}, Simp[1/e^(p*r)   Int[u*(e*x)^(m + p*r)*ExpandToSum[Px/x^r, x]^p, 
x], x] /; IGtQ[r, 0]] /; FreeQ[{e, m}, x] && PolyQ[Px, x] && IntegerQ[p] && 
  !MonomialQ[Px, x]
 

rule 25

Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 253

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(-(c*x 
)^(m + 1))*((a + b*x^2)^(p + 1)/(2*a*c*(p + 1))), x] + Simp[(m + 2*p + 3)/( 
2*a*(p + 1))   Int[(c*x)^m*(a + b*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, m 
}, x] && LtQ[p, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
 

rule 264

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(c*x)^( 
m + 1)*((a + b*x^2)^(p + 1)/(a*c*(m + 1))), x] - Simp[b*((m + 2*p + 3)/(a*c 
^2*(m + 1)))   Int[(c*x)^(m + 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, p 
}, x] && LtQ[m, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
 

rule 266

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De 
nominator[m]}, Simp[k/c   Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) 
^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I 
ntBinomialQ[a, b, c, 2, m, p, x]
 

rule 362

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2), x 
_Symbol] :> Simp[(-(b*c - a*d))*(e*x)^(m + 1)*((a + b*x^2)^(p + 1)/(2*a*b*e 
*(p + 1))), x] - Simp[(a*d*(m + 1) - b*c*(m + 2*p + 3))/(2*a*b*(p + 1))   I 
nt[(e*x)^m*(a + b*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, m}, x] && N 
eQ[b*c - a*d, 0] && LtQ[p, -1] && (( !IntegerQ[p + 1/2] && NeQ[p, -5/4]) || 
  !RationalQ[m] || (ILtQ[p + 1/2, 0] && LeQ[-1, m, -2*(p + 1)]))
 

rule 826

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 
2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s)   Int[(r + s*x^2)/(a + b*x^ 
4), x], x] - Simp[1/(2*s)   Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ 
a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] 
 && AtomQ[SplitProduct[SumBaseQ, b]]))
 

rule 1082

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 

Maple [A] (verified)

Time = 0.44 (sec) , antiderivative size = 210, normalized size of antiderivative = 0.73

method	result	size
derivativedivides	\(-\frac {2 A}{9 b^{3} x^{\frac {9}{2}}}-\frac {2 \left (-3 A c +B b \right )}{5 b^{4} x^{\frac {5}{2}}}-\frac {6 c \left (2 A c -B b \right )}{b^{5} \sqrt {x}}-\frac {2 c^{2} \left (\frac {\frac {c \left (29 A c -21 B b \right ) x^{\frac {7}{2}}}{32}+\left (\frac {33}{32} A b c -\frac {25}{32} B \,b^{2}\right ) x^{\frac {3}{2}}}{\left (c \,x^{2}+b \right )^{2}}+\frac {\left (\frac {221 A c}{32}-\frac {117 B b}{32}\right ) \sqrt {2}\, \left (\ln \left (\frac {x -\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}{x +\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{8 c \left (\frac {b}{c}\right )^{\frac {1}{4}}}\right )}{b^{5}}\)	\(210\)
default	\(-\frac {2 A}{9 b^{3} x^{\frac {9}{2}}}-\frac {2 \left (-3 A c +B b \right )}{5 b^{4} x^{\frac {5}{2}}}-\frac {6 c \left (2 A c -B b \right )}{b^{5} \sqrt {x}}-\frac {2 c^{2} \left (\frac {\frac {c \left (29 A c -21 B b \right ) x^{\frac {7}{2}}}{32}+\left (\frac {33}{32} A b c -\frac {25}{32} B \,b^{2}\right ) x^{\frac {3}{2}}}{\left (c \,x^{2}+b \right )^{2}}+\frac {\left (\frac {221 A c}{32}-\frac {117 B b}{32}\right ) \sqrt {2}\, \left (\ln \left (\frac {x -\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}{x +\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{8 c \left (\frac {b}{c}\right )^{\frac {1}{4}}}\right )}{b^{5}}\)	\(210\)
risch	\(-\frac {2 \left (270 x^{4} A \,c^{2}-135 x^{4} B b c -27 A b c \,x^{2}+9 x^{2} B \,b^{2}+5 b^{2} A \right )}{45 b^{5} x^{\frac {9}{2}}}-\frac {c^{2} \left (\frac {\frac {c \left (29 A c -21 B b \right ) x^{\frac {7}{2}}}{16}+2 \left (\frac {33}{32} A b c -\frac {25}{32} B \,b^{2}\right ) x^{\frac {3}{2}}}{\left (c \,x^{2}+b \right )^{2}}+\frac {\left (\frac {221 A c}{32}-\frac {117 B b}{32}\right ) \sqrt {2}\, \left (\ln \left (\frac {x -\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}{x +\left (\frac {b}{c}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {b}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {b}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{4 c \left (\frac {b}{c}\right )^{\frac {1}{4}}}\right )}{b^{5}}\)	\(217\)

Input:

int(x^(1/2)*(B*x^2+A)/(c*x^4+b*x^2)^3,x,method=_RETURNVERBOSE)
 

Output:

-2/9*A/b^3/x^(9/2)-2/5*(-3*A*c+B*b)/b^4/x^(5/2)-6*c*(2*A*c-B*b)/b^5/x^(1/2 
)-2/b^5*c^2*((1/32*c*(29*A*c-21*B*b)*x^(7/2)+(33/32*A*b*c-25/32*B*b^2)*x^( 
3/2))/(c*x^2+b)^2+1/8*(221/32*A*c-117/32*B*b)/c/(b/c)^(1/4)*2^(1/2)*(ln((x 
-(b/c)^(1/4)*x^(1/2)*2^(1/2)+(b/c)^(1/2))/(x+(b/c)^(1/4)*x^(1/2)*2^(1/2)+( 
b/c)^(1/2)))+2*arctan(2^(1/2)/(b/c)^(1/4)*x^(1/2)+1)+2*arctan(2^(1/2)/(b/c 
)^(1/4)*x^(1/2)-1)))
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.10 (sec) , antiderivative size = 966, normalized size of antiderivative = 3.35 \[ \int \frac {\sqrt {x} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx =\text {Too large to display} \] Input:

integrate(x^(1/2)*(B*x^2+A)/(c*x^4+b*x^2)^3,x, algorithm="fricas")
 

Output:

-1/2880*(585*(b^5*c^2*x^9 + 2*b^6*c*x^7 + b^7*x^5)*(-(6561*B^4*b^4*c^5 - 4 
9572*A*B^3*b^3*c^6 + 140454*A^2*B^2*b^2*c^7 - 176868*A^3*B*b*c^8 + 83521*A 
^4*c^9)/b^21)^(1/4)*log(2197*b^16*(-(6561*B^4*b^4*c^5 - 49572*A*B^3*b^3*c^ 
6 + 140454*A^2*B^2*b^2*c^7 - 176868*A^3*B*b*c^8 + 83521*A^4*c^9)/b^21)^(3/ 
4) - 2197*(729*B^3*b^3*c^4 - 4131*A*B^2*b^2*c^5 + 7803*A^2*B*b*c^6 - 4913* 
A^3*c^7)*sqrt(x)) + 585*(-I*b^5*c^2*x^9 - 2*I*b^6*c*x^7 - I*b^7*x^5)*(-(65 
61*B^4*b^4*c^5 - 49572*A*B^3*b^3*c^6 + 140454*A^2*B^2*b^2*c^7 - 176868*A^3 
*B*b*c^8 + 83521*A^4*c^9)/b^21)^(1/4)*log(2197*I*b^16*(-(6561*B^4*b^4*c^5 
- 49572*A*B^3*b^3*c^6 + 140454*A^2*B^2*b^2*c^7 - 176868*A^3*B*b*c^8 + 8352 
1*A^4*c^9)/b^21)^(3/4) - 2197*(729*B^3*b^3*c^4 - 4131*A*B^2*b^2*c^5 + 7803 
*A^2*B*b*c^6 - 4913*A^3*c^7)*sqrt(x)) + 585*(I*b^5*c^2*x^9 + 2*I*b^6*c*x^7 
 + I*b^7*x^5)*(-(6561*B^4*b^4*c^5 - 49572*A*B^3*b^3*c^6 + 140454*A^2*B^2*b 
^2*c^7 - 176868*A^3*B*b*c^8 + 83521*A^4*c^9)/b^21)^(1/4)*log(-2197*I*b^16* 
(-(6561*B^4*b^4*c^5 - 49572*A*B^3*b^3*c^6 + 140454*A^2*B^2*b^2*c^7 - 17686 
8*A^3*B*b*c^8 + 83521*A^4*c^9)/b^21)^(3/4) - 2197*(729*B^3*b^3*c^4 - 4131* 
A*B^2*b^2*c^5 + 7803*A^2*B*b*c^6 - 4913*A^3*c^7)*sqrt(x)) - 585*(b^5*c^2*x 
^9 + 2*b^6*c*x^7 + b^7*x^5)*(-(6561*B^4*b^4*c^5 - 49572*A*B^3*b^3*c^6 + 14 
0454*A^2*B^2*b^2*c^7 - 176868*A^3*B*b*c^8 + 83521*A^4*c^9)/b^21)^(1/4)*log 
(-2197*b^16*(-(6561*B^4*b^4*c^5 - 49572*A*B^3*b^3*c^6 + 140454*A^2*B^2*b^2 
*c^7 - 176868*A^3*B*b*c^8 + 83521*A^4*c^9)/b^21)^(3/4) - 2197*(729*B^3*...
 

Sympy [F(-1)]

Timed out. \[ \int \frac {\sqrt {x} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx=\text {Timed out} \] Input:

integrate(x**(1/2)*(B*x**2+A)/(c*x**4+b*x**2)**3,x)
 

Output:

Timed out
 

Maxima [A] (verification not implemented)

Time = 0.13 (sec) , antiderivative size = 311, normalized size of antiderivative = 1.08 \[ \int \frac {\sqrt {x} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx=\frac {585 \, {\left (9 \, B b c^{3} - 17 \, A c^{4}\right )} x^{8} + 1053 \, {\left (9 \, B b^{2} c^{2} - 17 \, A b c^{3}\right )} x^{6} - 160 \, A b^{4} + 416 \, {\left (9 \, B b^{3} c - 17 \, A b^{2} c^{2}\right )} x^{4} - 32 \, {\left (9 \, B b^{4} - 17 \, A b^{3} c\right )} x^{2}}{720 \, {\left (b^{5} c^{2} x^{\frac {17}{2}} + 2 \, b^{6} c x^{\frac {13}{2}} + b^{7} x^{\frac {9}{2}}\right )}} + \frac {13 \, {\left (9 \, B b c^{2} - 17 \, A c^{3}\right )} {\left (\frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} b^{\frac {1}{4}} c^{\frac {1}{4}} + 2 \, \sqrt {c} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {b} \sqrt {c}}}\right )}{\sqrt {\sqrt {b} \sqrt {c}} \sqrt {c}} + \frac {2 \, \sqrt {2} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} b^{\frac {1}{4}} c^{\frac {1}{4}} - 2 \, \sqrt {c} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {b} \sqrt {c}}}\right )}{\sqrt {\sqrt {b} \sqrt {c}} \sqrt {c}} - \frac {\sqrt {2} \log \left (\sqrt {2} b^{\frac {1}{4}} c^{\frac {1}{4}} \sqrt {x} + \sqrt {c} x + \sqrt {b}\right )}{b^{\frac {1}{4}} c^{\frac {3}{4}}} + \frac {\sqrt {2} \log \left (-\sqrt {2} b^{\frac {1}{4}} c^{\frac {1}{4}} \sqrt {x} + \sqrt {c} x + \sqrt {b}\right )}{b^{\frac {1}{4}} c^{\frac {3}{4}}}\right )}}{128 \, b^{5}} \] Input:

integrate(x^(1/2)*(B*x^2+A)/(c*x^4+b*x^2)^3,x, algorithm="maxima")
 

Output:

1/720*(585*(9*B*b*c^3 - 17*A*c^4)*x^8 + 1053*(9*B*b^2*c^2 - 17*A*b*c^3)*x^ 
6 - 160*A*b^4 + 416*(9*B*b^3*c - 17*A*b^2*c^2)*x^4 - 32*(9*B*b^4 - 17*A*b^ 
3*c)*x^2)/(b^5*c^2*x^(17/2) + 2*b^6*c*x^(13/2) + b^7*x^(9/2)) + 13/128*(9* 
B*b*c^2 - 17*A*c^3)*(2*sqrt(2)*arctan(1/2*sqrt(2)*(sqrt(2)*b^(1/4)*c^(1/4) 
 + 2*sqrt(c)*sqrt(x))/sqrt(sqrt(b)*sqrt(c)))/(sqrt(sqrt(b)*sqrt(c))*sqrt(c 
)) + 2*sqrt(2)*arctan(-1/2*sqrt(2)*(sqrt(2)*b^(1/4)*c^(1/4) - 2*sqrt(c)*sq 
rt(x))/sqrt(sqrt(b)*sqrt(c)))/(sqrt(sqrt(b)*sqrt(c))*sqrt(c)) - sqrt(2)*lo 
g(sqrt(2)*b^(1/4)*c^(1/4)*sqrt(x) + sqrt(c)*x + sqrt(b))/(b^(1/4)*c^(3/4)) 
 + sqrt(2)*log(-sqrt(2)*b^(1/4)*c^(1/4)*sqrt(x) + sqrt(c)*x + sqrt(b))/(b^ 
(1/4)*c^(3/4)))/b^5
 

Giac [A] (verification not implemented)

Time = 0.21 (sec) , antiderivative size = 351, normalized size of antiderivative = 1.22 \[ \int \frac {\sqrt {x} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx=\frac {13 \, \sqrt {2} {\left (9 \, \left (b c^{3}\right )^{\frac {3}{4}} B b - 17 \, \left (b c^{3}\right )^{\frac {3}{4}} A c\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {b}{c}\right )^{\frac {1}{4}} + 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {b}{c}\right )^{\frac {1}{4}}}\right )}{64 \, b^{6} c} + \frac {13 \, \sqrt {2} {\left (9 \, \left (b c^{3}\right )^{\frac {3}{4}} B b - 17 \, \left (b c^{3}\right )^{\frac {3}{4}} A c\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {b}{c}\right )^{\frac {1}{4}} - 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {b}{c}\right )^{\frac {1}{4}}}\right )}{64 \, b^{6} c} - \frac {13 \, \sqrt {2} {\left (9 \, \left (b c^{3}\right )^{\frac {3}{4}} B b - 17 \, \left (b c^{3}\right )^{\frac {3}{4}} A c\right )} \log \left (\sqrt {2} \sqrt {x} \left (\frac {b}{c}\right )^{\frac {1}{4}} + x + \sqrt {\frac {b}{c}}\right )}{128 \, b^{6} c} + \frac {13 \, \sqrt {2} {\left (9 \, \left (b c^{3}\right )^{\frac {3}{4}} B b - 17 \, \left (b c^{3}\right )^{\frac {3}{4}} A c\right )} \log \left (-\sqrt {2} \sqrt {x} \left (\frac {b}{c}\right )^{\frac {1}{4}} + x + \sqrt {\frac {b}{c}}\right )}{128 \, b^{6} c} + \frac {21 \, B b c^{3} x^{\frac {7}{2}} - 29 \, A c^{4} x^{\frac {7}{2}} + 25 \, B b^{2} c^{2} x^{\frac {3}{2}} - 33 \, A b c^{3} x^{\frac {3}{2}}}{16 \, {\left (c x^{2} + b\right )}^{2} b^{5}} + \frac {2 \, {\left (135 \, B b c x^{4} - 270 \, A c^{2} x^{4} - 9 \, B b^{2} x^{2} + 27 \, A b c x^{2} - 5 \, A b^{2}\right )}}{45 \, b^{5} x^{\frac {9}{2}}} \] Input:

integrate(x^(1/2)*(B*x^2+A)/(c*x^4+b*x^2)^3,x, algorithm="giac")
 

Output:

13/64*sqrt(2)*(9*(b*c^3)^(3/4)*B*b - 17*(b*c^3)^(3/4)*A*c)*arctan(1/2*sqrt 
(2)*(sqrt(2)*(b/c)^(1/4) + 2*sqrt(x))/(b/c)^(1/4))/(b^6*c) + 13/64*sqrt(2) 
*(9*(b*c^3)^(3/4)*B*b - 17*(b*c^3)^(3/4)*A*c)*arctan(-1/2*sqrt(2)*(sqrt(2) 
*(b/c)^(1/4) - 2*sqrt(x))/(b/c)^(1/4))/(b^6*c) - 13/128*sqrt(2)*(9*(b*c^3) 
^(3/4)*B*b - 17*(b*c^3)^(3/4)*A*c)*log(sqrt(2)*sqrt(x)*(b/c)^(1/4) + x + s 
qrt(b/c))/(b^6*c) + 13/128*sqrt(2)*(9*(b*c^3)^(3/4)*B*b - 17*(b*c^3)^(3/4) 
*A*c)*log(-sqrt(2)*sqrt(x)*(b/c)^(1/4) + x + sqrt(b/c))/(b^6*c) + 1/16*(21 
*B*b*c^3*x^(7/2) - 29*A*c^4*x^(7/2) + 25*B*b^2*c^2*x^(3/2) - 33*A*b*c^3*x^ 
(3/2))/((c*x^2 + b)^2*b^5) + 2/45*(135*B*b*c*x^4 - 270*A*c^2*x^4 - 9*B*b^2 
*x^2 + 27*A*b*c*x^2 - 5*A*b^2)/(b^5*x^(9/2))
 

Mupad [B] (verification not implemented)

Time = 9.20 (sec) , antiderivative size = 173, normalized size of antiderivative = 0.60 \[ \int \frac {\sqrt {x} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx=\frac {13\,{\left (-c\right )}^{5/4}\,\mathrm {atan}\left (\frac {{\left (-c\right )}^{1/4}\,\sqrt {x}}{b^{1/4}}\right )\,\left (17\,A\,c-9\,B\,b\right )}{32\,b^{21/4}}-\frac {\frac {2\,A}{9\,b}-\frac {2\,x^2\,\left (17\,A\,c-9\,B\,b\right )}{45\,b^2}+\frac {117\,c^2\,x^6\,\left (17\,A\,c-9\,B\,b\right )}{80\,b^4}+\frac {13\,c^3\,x^8\,\left (17\,A\,c-9\,B\,b\right )}{16\,b^5}+\frac {26\,c\,x^4\,\left (17\,A\,c-9\,B\,b\right )}{45\,b^3}}{b^2\,x^{9/2}+c^2\,x^{17/2}+2\,b\,c\,x^{13/2}}-\frac {13\,{\left (-c\right )}^{5/4}\,\mathrm {atanh}\left (\frac {{\left (-c\right )}^{1/4}\,\sqrt {x}}{b^{1/4}}\right )\,\left (17\,A\,c-9\,B\,b\right )}{32\,b^{21/4}} \] Input:

int((x^(1/2)*(A + B*x^2))/(b*x^2 + c*x^4)^3,x)
 

Output:

(13*(-c)^(5/4)*atan(((-c)^(1/4)*x^(1/2))/b^(1/4))*(17*A*c - 9*B*b))/(32*b^ 
(21/4)) - ((2*A)/(9*b) - (2*x^2*(17*A*c - 9*B*b))/(45*b^2) + (117*c^2*x^6* 
(17*A*c - 9*B*b))/(80*b^4) + (13*c^3*x^8*(17*A*c - 9*B*b))/(16*b^5) + (26* 
c*x^4*(17*A*c - 9*B*b))/(45*b^3))/(b^2*x^(9/2) + c^2*x^(17/2) + 2*b*c*x^(1 
3/2)) - (13*(-c)^(5/4)*atanh(((-c)^(1/4)*x^(1/2))/b^(1/4))*(17*A*c - 9*B*b 
))/(32*b^(21/4))
 

Reduce [B] (verification not implemented)

Time = 0.21 (sec) , antiderivative size = 1064, normalized size of antiderivative = 3.69 \[ \int \frac {\sqrt {x} \left (A+B x^2\right )}{\left (b x^2+c x^4\right )^3} \, dx =\text {Too large to display} \] Input:

int(x^(1/2)*(B*x^2+A)/(c*x^4+b*x^2)^3,x)
 

Output:

(19890*sqrt(x)*c**(1/4)*b**(3/4)*sqrt(2)*atan((c**(1/4)*b**(1/4)*sqrt(2) - 
 2*sqrt(x)*sqrt(c))/(c**(1/4)*b**(1/4)*sqrt(2)))*a*b**2*c**2*x**4 + 39780* 
sqrt(x)*c**(1/4)*b**(3/4)*sqrt(2)*atan((c**(1/4)*b**(1/4)*sqrt(2) - 2*sqrt 
(x)*sqrt(c))/(c**(1/4)*b**(1/4)*sqrt(2)))*a*b*c**3*x**6 + 19890*sqrt(x)*c* 
*(1/4)*b**(3/4)*sqrt(2)*atan((c**(1/4)*b**(1/4)*sqrt(2) - 2*sqrt(x)*sqrt(c 
))/(c**(1/4)*b**(1/4)*sqrt(2)))*a*c**4*x**8 - 10530*sqrt(x)*c**(1/4)*b**(3 
/4)*sqrt(2)*atan((c**(1/4)*b**(1/4)*sqrt(2) - 2*sqrt(x)*sqrt(c))/(c**(1/4) 
*b**(1/4)*sqrt(2)))*b**4*c*x**4 - 21060*sqrt(x)*c**(1/4)*b**(3/4)*sqrt(2)* 
atan((c**(1/4)*b**(1/4)*sqrt(2) - 2*sqrt(x)*sqrt(c))/(c**(1/4)*b**(1/4)*sq 
rt(2)))*b**3*c**2*x**6 - 10530*sqrt(x)*c**(1/4)*b**(3/4)*sqrt(2)*atan((c** 
(1/4)*b**(1/4)*sqrt(2) - 2*sqrt(x)*sqrt(c))/(c**(1/4)*b**(1/4)*sqrt(2)))*b 
**2*c**3*x**8 - 19890*sqrt(x)*c**(1/4)*b**(3/4)*sqrt(2)*atan((c**(1/4)*b** 
(1/4)*sqrt(2) + 2*sqrt(x)*sqrt(c))/(c**(1/4)*b**(1/4)*sqrt(2)))*a*b**2*c** 
2*x**4 - 39780*sqrt(x)*c**(1/4)*b**(3/4)*sqrt(2)*atan((c**(1/4)*b**(1/4)*s 
qrt(2) + 2*sqrt(x)*sqrt(c))/(c**(1/4)*b**(1/4)*sqrt(2)))*a*b*c**3*x**6 - 1 
9890*sqrt(x)*c**(1/4)*b**(3/4)*sqrt(2)*atan((c**(1/4)*b**(1/4)*sqrt(2) + 2 
*sqrt(x)*sqrt(c))/(c**(1/4)*b**(1/4)*sqrt(2)))*a*c**4*x**8 + 10530*sqrt(x) 
*c**(1/4)*b**(3/4)*sqrt(2)*atan((c**(1/4)*b**(1/4)*sqrt(2) + 2*sqrt(x)*sqr 
t(c))/(c**(1/4)*b**(1/4)*sqrt(2)))*b**4*c*x**4 + 21060*sqrt(x)*c**(1/4)*b* 
*(3/4)*sqrt(2)*atan((c**(1/4)*b**(1/4)*sqrt(2) + 2*sqrt(x)*sqrt(c))/(c*...