Integrand size = 16, antiderivative size = 179 \[ \int \frac {1}{x^3 \left (a+b x+c x^2\right )^2} \, dx=-\frac {1}{2 a^2 x^2}+\frac {2 b}{a^3 x}+\frac {b^4-4 a b^2 c+2 a^2 c^2+b c \left (b^2-3 a c\right ) x}{a^3 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}+\frac {b \left (3 b^4-20 a b^2 c+30 a^2 c^2\right ) \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{a^4 \left (b^2-4 a c\right )^{3/2}}+\frac {\left (3 b^2-2 a c\right ) \log (x)}{a^4}-\frac {\left (3 b^2-2 a c\right ) \log \left (a+b x+c x^2\right )}{2 a^4} \] Output:
-1/2/a^2/x^2+2*b/a^3/x+(b^4-4*a*b^2*c+2*a^2*c^2+b*c*(-3*a*c+b^2)*x)/a^3/(- 4*a*c+b^2)/(c*x^2+b*x+a)+b*(30*a^2*c^2-20*a*b^2*c+3*b^4)*arctanh((2*c*x+b) /(-4*a*c+b^2)^(1/2))/a^4/(-4*a*c+b^2)^(3/2)+(-2*a*c+3*b^2)*ln(x)/a^4-1/2*( -2*a*c+3*b^2)*ln(c*x^2+b*x+a)/a^4
Time = 0.32 (sec) , antiderivative size = 175, normalized size of antiderivative = 0.98 \[ \int \frac {1}{x^3 \left (a+b x+c x^2\right )^2} \, dx=\frac {-\frac {a^2}{x^2}+\frac {4 a b}{x}+\frac {2 a \left (b^4-4 a b^2 c+2 a^2 c^2+b^3 c x-3 a b c^2 x\right )}{\left (b^2-4 a c\right ) (a+x (b+c x))}+\frac {2 b \left (3 b^4-20 a b^2 c+30 a^2 c^2\right ) \arctan \left (\frac {b+2 c x}{\sqrt {-b^2+4 a c}}\right )}{\left (-b^2+4 a c\right )^{3/2}}+2 \left (3 b^2-2 a c\right ) \log (x)+\left (-3 b^2+2 a c\right ) \log (a+x (b+c x))}{2 a^4} \] Input:
Integrate[1/(x^3*(a + b*x + c*x^2)^2),x]
Output:
(-(a^2/x^2) + (4*a*b)/x + (2*a*(b^4 - 4*a*b^2*c + 2*a^2*c^2 + b^3*c*x - 3* a*b*c^2*x))/((b^2 - 4*a*c)*(a + x*(b + c*x))) + (2*b*(3*b^4 - 20*a*b^2*c + 30*a^2*c^2)*ArcTan[(b + 2*c*x)/Sqrt[-b^2 + 4*a*c]])/(-b^2 + 4*a*c)^(3/2) + 2*(3*b^2 - 2*a*c)*Log[x] + (-3*b^2 + 2*a*c)*Log[a + x*(b + c*x)])/(2*a^4 )
Time = 0.78 (sec) , antiderivative size = 213, normalized size of antiderivative = 1.19, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {1165, 25, 1200, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{x^3 \left (a+b x+c x^2\right )^2} \, dx\) |
\(\Big \downarrow \) 1165 |
\(\displaystyle \frac {-2 a c+b^2+b c x}{a x^2 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}-\frac {\int -\frac {3 b^2+3 c x b-8 a c}{x^3 \left (c x^2+b x+a\right )}dx}{a \left (b^2-4 a c\right )}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {\int \frac {3 b^2+3 c x b-8 a c}{x^3 \left (c x^2+b x+a\right )}dx}{a \left (b^2-4 a c\right )}+\frac {-2 a c+b^2+b c x}{a x^2 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}\) |
\(\Big \downarrow \) 1200 |
\(\displaystyle \frac {\int \left (\frac {3 b^2-8 a c}{a x^3}+\frac {\left (b^2-4 a c\right ) \left (3 b^2-2 a c\right )}{a^3 x}+\frac {-b \left (3 b^4-17 a c b^2+19 a^2 c^2\right )-c \left (3 b^4-14 a c b^2+8 a^2 c^2\right ) x}{a^3 \left (c x^2+b x+a\right )}+\frac {b \left (11 a c-3 b^2\right )}{a^2 x^2}\right )dx}{a \left (b^2-4 a c\right )}+\frac {-2 a c+b^2+b c x}{a x^2 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {-\frac {\left (b^2-4 a c\right ) \left (3 b^2-2 a c\right ) \log \left (a+b x+c x^2\right )}{2 a^3}+\frac {\log (x) \left (b^2-4 a c\right ) \left (3 b^2-2 a c\right )}{a^3}+\frac {b \left (3 b^2-11 a c\right )}{a^2 x}+\frac {b \left (30 a^2 c^2-20 a b^2 c+3 b^4\right ) \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{a^3 \sqrt {b^2-4 a c}}-\frac {3 b^2-8 a c}{2 a x^2}}{a \left (b^2-4 a c\right )}+\frac {-2 a c+b^2+b c x}{a x^2 \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}\) |
Input:
Int[1/(x^3*(a + b*x + c*x^2)^2),x]
Output:
(b^2 - 2*a*c + b*c*x)/(a*(b^2 - 4*a*c)*x^2*(a + b*x + c*x^2)) + (-1/2*(3*b ^2 - 8*a*c)/(a*x^2) + (b*(3*b^2 - 11*a*c))/(a^2*x) + (b*(3*b^4 - 20*a*b^2* c + 30*a^2*c^2)*ArcTanh[(b + 2*c*x)/Sqrt[b^2 - 4*a*c]])/(a^3*Sqrt[b^2 - 4* a*c]) + ((b^2 - 4*a*c)*(3*b^2 - 2*a*c)*Log[x])/a^3 - ((b^2 - 4*a*c)*(3*b^2 - 2*a*c)*Log[a + b*x + c*x^2])/(2*a^3))/(a*(b^2 - 4*a*c))
Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_S ymbol] :> Simp[(d + e*x)^(m + 1)*(b*c*d - b^2*e + 2*a*c*e + c*(2*c*d - b*e) *x)*((a + b*x + c*x^2)^(p + 1)/((p + 1)*(b^2 - 4*a*c)*(c*d^2 - b*d*e + a*e^ 2))), x] + Simp[1/((p + 1)*(b^2 - 4*a*c)*(c*d^2 - b*d*e + a*e^2)) Int[(d + e*x)^m*Simp[b*c*d*e*(2*p - m + 2) + b^2*e^2*(m + p + 2) - 2*c^2*d^2*(2*p + 3) - 2*a*c*e^2*(m + 2*p + 3) - c*e*(2*c*d - b*e)*(m + 2*p + 4)*x, x]*(a + b*x + c*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, m}, x] && LtQ[p, -1] && IntQuadraticQ[a, b, c, d, e, m, p, x]
Int[(((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))^(n_.))/((a_.) + (b_.)* (x_) + (c_.)*(x_)^2), x_Symbol] :> Int[ExpandIntegrand[(d + e*x)^m*((f + g* x)^n/(a + b*x + c*x^2)), x], x] /; FreeQ[{a, b, c, d, e, f, g, m}, x] && In tegersQ[n]
Time = 0.76 (sec) , antiderivative size = 255, normalized size of antiderivative = 1.42
method | result | size |
default | \(-\frac {1}{2 a^{2} x^{2}}+\frac {\left (-2 a c +3 b^{2}\right ) \ln \left (x \right )}{a^{4}}+\frac {2 b}{a^{3} x}+\frac {\frac {\frac {a c b \left (3 a c -b^{2}\right ) x}{4 a c -b^{2}}-\frac {a \left (2 a^{2} c^{2}-4 c a \,b^{2}+b^{4}\right )}{4 a c -b^{2}}}{c \,x^{2}+b x +a}+\frac {\frac {\left (8 a^{2} c^{3}-14 a \,c^{2} b^{2}+3 b^{4} c \right ) \ln \left (c \,x^{2}+b x +a \right )}{2 c}+\frac {2 \left (19 a^{2} b \,c^{2}-17 a \,b^{3} c +3 b^{5}-\frac {\left (8 a^{2} c^{3}-14 a \,c^{2} b^{2}+3 b^{4} c \right ) b}{2 c}\right ) \arctan \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right )}{\sqrt {4 a c -b^{2}}}}{4 a c -b^{2}}}{a^{4}}\) | \(255\) |
risch | \(\text {Expression too large to display}\) | \(4933\) |
Input:
int(1/x^3/(c*x^2+b*x+a)^2,x,method=_RETURNVERBOSE)
Output:
-1/2/a^2/x^2+(-2*a*c+3*b^2)*ln(x)/a^4+2*b/a^3/x+1/a^4*((a*c*b*(3*a*c-b^2)/ (4*a*c-b^2)*x-a*(2*a^2*c^2-4*a*b^2*c+b^4)/(4*a*c-b^2))/(c*x^2+b*x+a)+1/(4* a*c-b^2)*(1/2*(8*a^2*c^3-14*a*b^2*c^2+3*b^4*c)/c*ln(c*x^2+b*x+a)+2*(19*a^2 *b*c^2-17*a*b^3*c+3*b^5-1/2*(8*a^2*c^3-14*a*b^2*c^2+3*b^4*c)*b/c)/(4*a*c-b ^2)^(1/2)*arctan((2*c*x+b)/(4*a*c-b^2)^(1/2))))
Leaf count of result is larger than twice the leaf count of optimal. 603 vs. \(2 (171) = 342\).
Time = 0.26 (sec) , antiderivative size = 1226, normalized size of antiderivative = 6.85 \[ \int \frac {1}{x^3 \left (a+b x+c x^2\right )^2} \, dx=\text {Too large to display} \] Input:
integrate(1/x^3/(c*x^2+b*x+a)^2,x, algorithm="fricas")
Output:
[-1/2*(a^3*b^4 - 8*a^4*b^2*c + 16*a^5*c^2 - 2*(3*a*b^5*c - 23*a^2*b^3*c^2 + 44*a^3*b*c^3)*x^3 - (6*a*b^6 - 49*a^2*b^4*c + 108*a^3*b^2*c^2 - 32*a^4*c ^3)*x^2 + ((3*b^5*c - 20*a*b^3*c^2 + 30*a^2*b*c^3)*x^4 + (3*b^6 - 20*a*b^4 *c + 30*a^2*b^2*c^2)*x^3 + (3*a*b^5 - 20*a^2*b^3*c + 30*a^3*b*c^2)*x^2)*sq rt(b^2 - 4*a*c)*log((2*c^2*x^2 + 2*b*c*x + b^2 - 2*a*c - sqrt(b^2 - 4*a*c) *(2*c*x + b))/(c*x^2 + b*x + a)) - 3*(a^2*b^5 - 8*a^3*b^3*c + 16*a^4*b*c^2 )*x + ((3*b^6*c - 26*a*b^4*c^2 + 64*a^2*b^2*c^3 - 32*a^3*c^4)*x^4 + (3*b^7 - 26*a*b^5*c + 64*a^2*b^3*c^2 - 32*a^3*b*c^3)*x^3 + (3*a*b^6 - 26*a^2*b^4 *c + 64*a^3*b^2*c^2 - 32*a^4*c^3)*x^2)*log(c*x^2 + b*x + a) - 2*((3*b^6*c - 26*a*b^4*c^2 + 64*a^2*b^2*c^3 - 32*a^3*c^4)*x^4 + (3*b^7 - 26*a*b^5*c + 64*a^2*b^3*c^2 - 32*a^3*b*c^3)*x^3 + (3*a*b^6 - 26*a^2*b^4*c + 64*a^3*b^2* c^2 - 32*a^4*c^3)*x^2)*log(x))/((a^4*b^4*c - 8*a^5*b^2*c^2 + 16*a^6*c^3)*x ^4 + (a^4*b^5 - 8*a^5*b^3*c + 16*a^6*b*c^2)*x^3 + (a^5*b^4 - 8*a^6*b^2*c + 16*a^7*c^2)*x^2), -1/2*(a^3*b^4 - 8*a^4*b^2*c + 16*a^5*c^2 - 2*(3*a*b^5*c - 23*a^2*b^3*c^2 + 44*a^3*b*c^3)*x^3 - (6*a*b^6 - 49*a^2*b^4*c + 108*a^3* b^2*c^2 - 32*a^4*c^3)*x^2 - 2*((3*b^5*c - 20*a*b^3*c^2 + 30*a^2*b*c^3)*x^4 + (3*b^6 - 20*a*b^4*c + 30*a^2*b^2*c^2)*x^3 + (3*a*b^5 - 20*a^2*b^3*c + 3 0*a^3*b*c^2)*x^2)*sqrt(-b^2 + 4*a*c)*arctan(-sqrt(-b^2 + 4*a*c)*(2*c*x + b )/(b^2 - 4*a*c)) - 3*(a^2*b^5 - 8*a^3*b^3*c + 16*a^4*b*c^2)*x + ((3*b^6*c - 26*a*b^4*c^2 + 64*a^2*b^2*c^3 - 32*a^3*c^4)*x^4 + (3*b^7 - 26*a*b^5*c...
Timed out. \[ \int \frac {1}{x^3 \left (a+b x+c x^2\right )^2} \, dx=\text {Timed out} \] Input:
integrate(1/x**3/(c*x**2+b*x+a)**2,x)
Output:
Timed out
Exception generated. \[ \int \frac {1}{x^3 \left (a+b x+c x^2\right )^2} \, dx=\text {Exception raised: ValueError} \] Input:
integrate(1/x^3/(c*x^2+b*x+a)^2,x, algorithm="maxima")
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(4*a*c-b^2>0)', see `assume?` for more deta
Time = 0.17 (sec) , antiderivative size = 229, normalized size of antiderivative = 1.28 \[ \int \frac {1}{x^3 \left (a+b x+c x^2\right )^2} \, dx=-\frac {{\left (3 \, b^{5} - 20 \, a b^{3} c + 30 \, a^{2} b c^{2}\right )} \arctan \left (\frac {2 \, c x + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{{\left (a^{4} b^{2} - 4 \, a^{5} c\right )} \sqrt {-b^{2} + 4 \, a c}} - \frac {{\left (3 \, b^{2} - 2 \, a c\right )} \log \left (c x^{2} + b x + a\right )}{2 \, a^{4}} + \frac {{\left (3 \, b^{2} - 2 \, a c\right )} \log \left ({\left | x \right |}\right )}{a^{4}} - \frac {a^{3} b^{2} - 4 \, a^{4} c - 2 \, {\left (3 \, a b^{3} c - 11 \, a^{2} b c^{2}\right )} x^{3} - {\left (6 \, a b^{4} - 25 \, a^{2} b^{2} c + 8 \, a^{3} c^{2}\right )} x^{2} - 3 \, {\left (a^{2} b^{3} - 4 \, a^{3} b c\right )} x}{2 \, {\left (c x^{2} + b x + a\right )} {\left (b^{2} - 4 \, a c\right )} a^{4} x^{2}} \] Input:
integrate(1/x^3/(c*x^2+b*x+a)^2,x, algorithm="giac")
Output:
-(3*b^5 - 20*a*b^3*c + 30*a^2*b*c^2)*arctan((2*c*x + b)/sqrt(-b^2 + 4*a*c) )/((a^4*b^2 - 4*a^5*c)*sqrt(-b^2 + 4*a*c)) - 1/2*(3*b^2 - 2*a*c)*log(c*x^2 + b*x + a)/a^4 + (3*b^2 - 2*a*c)*log(abs(x))/a^4 - 1/2*(a^3*b^2 - 4*a^4*c - 2*(3*a*b^3*c - 11*a^2*b*c^2)*x^3 - (6*a*b^4 - 25*a^2*b^2*c + 8*a^3*c^2) *x^2 - 3*(a^2*b^3 - 4*a^3*b*c)*x)/((c*x^2 + b*x + a)*(b^2 - 4*a*c)*a^4*x^2 )
Time = 9.89 (sec) , antiderivative size = 914, normalized size of antiderivative = 5.11 \[ \int \frac {1}{x^3 \left (a+b x+c x^2\right )^2} \, dx=\frac {\ln \left (6\,a\,b^8+6\,b^9\,x+192\,a^5\,c^4-6\,a\,b^5\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-73\,a^2\,b^6\,c-6\,b^6\,x\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}+307\,a^3\,b^4\,c^2-492\,a^4\,b^2\,c^3+31\,a^2\,b^3\,c\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-27\,a^3\,b\,c^2\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}+339\,a^2\,b^5\,c^2\,x-602\,a^3\,b^3\,c^3\,x+24\,a^3\,c^3\,x\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-76\,a\,b^7\,c\,x+312\,a^4\,b\,c^4\,x+40\,a\,b^4\,c\,x\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-69\,a^2\,b^2\,c^2\,x\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}\right )\,\left (3\,b^8+128\,a^4\,c^4-3\,b^5\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}+168\,a^2\,b^4\,c^2-288\,a^3\,b^2\,c^3-38\,a\,b^6\,c-30\,a^2\,b\,c^2\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}+20\,a\,b^3\,c\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}\right )}{2\,a^4\,{\left (4\,a\,c-b^2\right )}^3}-\frac {\ln \left (x\right )\,\left (2\,a\,c-3\,b^2\right )}{a^4}-\frac {\frac {1}{2\,a}-\frac {3\,b\,x}{2\,a^2}+\frac {x^2\,\left (8\,a^2\,c^2-25\,a\,b^2\,c+6\,b^4\right )}{2\,a^3\,\left (4\,a\,c-b^2\right )}-\frac {b\,c\,x^3\,\left (11\,a\,c-3\,b^2\right )}{a^3\,\left (4\,a\,c-b^2\right )}}{c\,x^4+b\,x^3+a\,x^2}+\frac {\ln \left (6\,a\,b^8+6\,b^9\,x+192\,a^5\,c^4+6\,a\,b^5\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-73\,a^2\,b^6\,c+6\,b^6\,x\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}+307\,a^3\,b^4\,c^2-492\,a^4\,b^2\,c^3-31\,a^2\,b^3\,c\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}+27\,a^3\,b\,c^2\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}+339\,a^2\,b^5\,c^2\,x-602\,a^3\,b^3\,c^3\,x-24\,a^3\,c^3\,x\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-76\,a\,b^7\,c\,x+312\,a^4\,b\,c^4\,x-40\,a\,b^4\,c\,x\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}+69\,a^2\,b^2\,c^2\,x\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}\right )\,\left (3\,b^8+128\,a^4\,c^4+3\,b^5\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}+168\,a^2\,b^4\,c^2-288\,a^3\,b^2\,c^3-38\,a\,b^6\,c+30\,a^2\,b\,c^2\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}-20\,a\,b^3\,c\,\sqrt {-{\left (4\,a\,c-b^2\right )}^3}\right )}{2\,a^4\,{\left (4\,a\,c-b^2\right )}^3} \] Input:
int(1/(x^3*(a + b*x + c*x^2)^2),x)
Output:
(log(6*a*b^8 + 6*b^9*x + 192*a^5*c^4 - 6*a*b^5*(-(4*a*c - b^2)^3)^(1/2) - 73*a^2*b^6*c - 6*b^6*x*(-(4*a*c - b^2)^3)^(1/2) + 307*a^3*b^4*c^2 - 492*a^ 4*b^2*c^3 + 31*a^2*b^3*c*(-(4*a*c - b^2)^3)^(1/2) - 27*a^3*b*c^2*(-(4*a*c - b^2)^3)^(1/2) + 339*a^2*b^5*c^2*x - 602*a^3*b^3*c^3*x + 24*a^3*c^3*x*(-( 4*a*c - b^2)^3)^(1/2) - 76*a*b^7*c*x + 312*a^4*b*c^4*x + 40*a*b^4*c*x*(-(4 *a*c - b^2)^3)^(1/2) - 69*a^2*b^2*c^2*x*(-(4*a*c - b^2)^3)^(1/2))*(3*b^8 + 128*a^4*c^4 - 3*b^5*(-(4*a*c - b^2)^3)^(1/2) + 168*a^2*b^4*c^2 - 288*a^3* b^2*c^3 - 38*a*b^6*c - 30*a^2*b*c^2*(-(4*a*c - b^2)^3)^(1/2) + 20*a*b^3*c* (-(4*a*c - b^2)^3)^(1/2)))/(2*a^4*(4*a*c - b^2)^3) - (log(x)*(2*a*c - 3*b^ 2))/a^4 - (1/(2*a) - (3*b*x)/(2*a^2) + (x^2*(6*b^4 + 8*a^2*c^2 - 25*a*b^2* c))/(2*a^3*(4*a*c - b^2)) - (b*c*x^3*(11*a*c - 3*b^2))/(a^3*(4*a*c - b^2)) )/(a*x^2 + b*x^3 + c*x^4) + (log(6*a*b^8 + 6*b^9*x + 192*a^5*c^4 + 6*a*b^5 *(-(4*a*c - b^2)^3)^(1/2) - 73*a^2*b^6*c + 6*b^6*x*(-(4*a*c - b^2)^3)^(1/2 ) + 307*a^3*b^4*c^2 - 492*a^4*b^2*c^3 - 31*a^2*b^3*c*(-(4*a*c - b^2)^3)^(1 /2) + 27*a^3*b*c^2*(-(4*a*c - b^2)^3)^(1/2) + 339*a^2*b^5*c^2*x - 602*a^3* b^3*c^3*x - 24*a^3*c^3*x*(-(4*a*c - b^2)^3)^(1/2) - 76*a*b^7*c*x + 312*a^4 *b*c^4*x - 40*a*b^4*c*x*(-(4*a*c - b^2)^3)^(1/2) + 69*a^2*b^2*c^2*x*(-(4*a *c - b^2)^3)^(1/2))*(3*b^8 + 128*a^4*c^4 + 3*b^5*(-(4*a*c - b^2)^3)^(1/2) + 168*a^2*b^4*c^2 - 288*a^3*b^2*c^3 - 38*a*b^6*c + 30*a^2*b*c^2*(-(4*a*c - b^2)^3)^(1/2) - 20*a*b^3*c*(-(4*a*c - b^2)^3)^(1/2)))/(2*a^4*(4*a*c - ...
Time = 0.25 (sec) , antiderivative size = 1039, normalized size of antiderivative = 5.80 \[ \int \frac {1}{x^3 \left (a+b x+c x^2\right )^2} \, dx =\text {Too large to display} \] Input:
int(1/x^3/(c*x^2+b*x+a)^2,x)
Output:
(60*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*a**3*b*c**2*x* *2 - 40*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*a**2*b**3* c*x**2 + 60*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*a**2*b **2*c**2*x**3 + 60*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2)) *a**2*b*c**3*x**4 + 6*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b** 2))*a*b**5*x**2 - 40*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2 ))*a*b**4*c*x**3 - 40*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b** 2))*a*b**3*c**2*x**4 + 6*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*b**6*x**3 + 6*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2 ))*b**5*c*x**4 + 32*log(a + b*x + c*x**2)*a**4*c**3*x**2 - 64*log(a + b*x + c*x**2)*a**3*b**2*c**2*x**2 + 32*log(a + b*x + c*x**2)*a**3*b*c**3*x**3 + 32*log(a + b*x + c*x**2)*a**3*c**4*x**4 + 26*log(a + b*x + c*x**2)*a**2* b**4*c*x**2 - 64*log(a + b*x + c*x**2)*a**2*b**3*c**2*x**3 - 64*log(a + b* x + c*x**2)*a**2*b**2*c**3*x**4 - 3*log(a + b*x + c*x**2)*a*b**6*x**2 + 26 *log(a + b*x + c*x**2)*a*b**5*c*x**3 + 26*log(a + b*x + c*x**2)*a*b**4*c** 2*x**4 - 3*log(a + b*x + c*x**2)*b**7*x**3 - 3*log(a + b*x + c*x**2)*b**6* c*x**4 - 64*log(x)*a**4*c**3*x**2 + 128*log(x)*a**3*b**2*c**2*x**2 - 64*lo g(x)*a**3*b*c**3*x**3 - 64*log(x)*a**3*c**4*x**4 - 52*log(x)*a**2*b**4*c*x **2 + 128*log(x)*a**2*b**3*c**2*x**3 + 128*log(x)*a**2*b**2*c**3*x**4 + 6* log(x)*a*b**6*x**2 - 52*log(x)*a*b**5*c*x**3 - 52*log(x)*a*b**4*c**2*x*...