\(\int \frac {(d+e x)^{7/2}}{(a^2+2 a b x+b^2 x^2)^{5/2}} \, dx\) [391]

Optimal result

Integrand size = 30, antiderivative size = 250 \[ \int \frac {(d+e x)^{7/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {35 e^3 \sqrt {d+e x}}{64 b^4 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {35 e^2 (d+e x)^{3/2}}{96 b^3 (a+b x) \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {7 e (d+e x)^{5/2}}{24 b^2 (a+b x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {(d+e x)^{7/2}}{4 b (a+b x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}-\frac {35 e^4 (a+b x) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{64 b^{9/2} \sqrt {b d-a e} \sqrt {a^2+2 a b x+b^2 x^2}} \] Output:

-35/64*e^3*(e*x+d)^(1/2)/b^4/((b*x+a)^2)^(1/2)-35/96*e^2*(e*x+d)^(3/2)/b^3 
/(b*x+a)/((b*x+a)^2)^(1/2)-7/24*e*(e*x+d)^(5/2)/b^2/(b*x+a)^2/((b*x+a)^2)^ 
(1/2)-1/4*(e*x+d)^(7/2)/b/(b*x+a)^3/((b*x+a)^2)^(1/2)-35/64*e^4*(b*x+a)*ar 
ctanh(b^(1/2)*(e*x+d)^(1/2)/(-a*e+b*d)^(1/2))/b^(9/2)/(-a*e+b*d)^(1/2)/((b 
*x+a)^2)^(1/2)
 

Mathematica [A] (verified)

Time = 1.02 (sec) , antiderivative size = 185, normalized size of antiderivative = 0.74 \[ \int \frac {(d+e x)^{7/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\frac {e^4 (a+b x)^5 \left (-\frac {\sqrt {b} \sqrt {d+e x} \left (105 a^3 e^3+35 a^2 b e^2 (2 d+11 e x)+7 a b^2 e \left (8 d^2+36 d e x+73 e^2 x^2\right )+b^3 \left (48 d^3+200 d^2 e x+326 d e^2 x^2+279 e^3 x^3\right )\right )}{e^4 (a+b x)^4}+\frac {105 \arctan \left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {-b d+a e}}\right )}{\sqrt {-b d+a e}}\right )}{192 b^{9/2} \left ((a+b x)^2\right )^{5/2}} \] Input:

Integrate[(d + e*x)^(7/2)/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]
 

Output:

(e^4*(a + b*x)^5*(-((Sqrt[b]*Sqrt[d + e*x]*(105*a^3*e^3 + 35*a^2*b*e^2*(2* 
d + 11*e*x) + 7*a*b^2*e*(8*d^2 + 36*d*e*x + 73*e^2*x^2) + b^3*(48*d^3 + 20 
0*d^2*e*x + 326*d*e^2*x^2 + 279*e^3*x^3)))/(e^4*(a + b*x)^4)) + (105*ArcTa 
n[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[-(b*d) + a*e]])/Sqrt[-(b*d) + a*e]))/(192*b 
^(9/2)*((a + b*x)^2)^(5/2))
 

Rubi [A] (verified)

Time = 0.50 (sec) , antiderivative size = 192, normalized size of antiderivative = 0.77, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {1102, 27, 51, 51, 51, 51, 73, 221}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(d+e x)^{7/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx\)

\(\Big \downarrow \) 1102

\(\displaystyle \frac {b^5 (a+b x) \int \frac {(d+e x)^{7/2}}{b^5 (a+b x)^5}dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {(a+b x) \int \frac {(d+e x)^{7/2}}{(a+b x)^5}dx}{\sqrt {a^2+2 a b x+b^2 x^2}}\)

\(\Big \downarrow \) 51

\(\displaystyle \frac {(a+b x) \left (\frac {7 e \int \frac {(d+e x)^{5/2}}{(a+b x)^4}dx}{8 b}-\frac {(d+e x)^{7/2}}{4 b (a+b x)^4}\right )}{\sqrt {a^2+2 a b x+b^2 x^2}}\)

\(\Big \downarrow \) 51

\(\displaystyle \frac {(a+b x) \left (\frac {7 e \left (\frac {5 e \int \frac {(d+e x)^{3/2}}{(a+b x)^3}dx}{6 b}-\frac {(d+e x)^{5/2}}{3 b (a+b x)^3}\right )}{8 b}-\frac {(d+e x)^{7/2}}{4 b (a+b x)^4}\right )}{\sqrt {a^2+2 a b x+b^2 x^2}}\)

\(\Big \downarrow \) 51

\(\displaystyle \frac {(a+b x) \left (\frac {7 e \left (\frac {5 e \left (\frac {3 e \int \frac {\sqrt {d+e x}}{(a+b x)^2}dx}{4 b}-\frac {(d+e x)^{3/2}}{2 b (a+b x)^2}\right )}{6 b}-\frac {(d+e x)^{5/2}}{3 b (a+b x)^3}\right )}{8 b}-\frac {(d+e x)^{7/2}}{4 b (a+b x)^4}\right )}{\sqrt {a^2+2 a b x+b^2 x^2}}\)

\(\Big \downarrow \) 51

\(\displaystyle \frac {(a+b x) \left (\frac {7 e \left (\frac {5 e \left (\frac {3 e \left (\frac {e \int \frac {1}{(a+b x) \sqrt {d+e x}}dx}{2 b}-\frac {\sqrt {d+e x}}{b (a+b x)}\right )}{4 b}-\frac {(d+e x)^{3/2}}{2 b (a+b x)^2}\right )}{6 b}-\frac {(d+e x)^{5/2}}{3 b (a+b x)^3}\right )}{8 b}-\frac {(d+e x)^{7/2}}{4 b (a+b x)^4}\right )}{\sqrt {a^2+2 a b x+b^2 x^2}}\)

\(\Big \downarrow \) 73

\(\displaystyle \frac {(a+b x) \left (\frac {7 e \left (\frac {5 e \left (\frac {3 e \left (\frac {\int \frac {1}{a+\frac {b (d+e x)}{e}-\frac {b d}{e}}d\sqrt {d+e x}}{b}-\frac {\sqrt {d+e x}}{b (a+b x)}\right )}{4 b}-\frac {(d+e x)^{3/2}}{2 b (a+b x)^2}\right )}{6 b}-\frac {(d+e x)^{5/2}}{3 b (a+b x)^3}\right )}{8 b}-\frac {(d+e x)^{7/2}}{4 b (a+b x)^4}\right )}{\sqrt {a^2+2 a b x+b^2 x^2}}\)

\(\Big \downarrow \) 221

\(\displaystyle \frac {(a+b x) \left (\frac {7 e \left (\frac {5 e \left (\frac {3 e \left (-\frac {e \text {arctanh}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{b^{3/2} \sqrt {b d-a e}}-\frac {\sqrt {d+e x}}{b (a+b x)}\right )}{4 b}-\frac {(d+e x)^{3/2}}{2 b (a+b x)^2}\right )}{6 b}-\frac {(d+e x)^{5/2}}{3 b (a+b x)^3}\right )}{8 b}-\frac {(d+e x)^{7/2}}{4 b (a+b x)^4}\right )}{\sqrt {a^2+2 a b x+b^2 x^2}}\)

Input:

Int[(d + e*x)^(7/2)/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]
 

Output:

((a + b*x)*(-1/4*(d + e*x)^(7/2)/(b*(a + b*x)^4) + (7*e*(-1/3*(d + e*x)^(5 
/2)/(b*(a + b*x)^3) + (5*e*(-1/2*(d + e*x)^(3/2)/(b*(a + b*x)^2) + (3*e*(- 
(Sqrt[d + e*x]/(b*(a + b*x))) - (e*ArcTanh[(Sqrt[b]*Sqrt[d + e*x])/Sqrt[b* 
d - a*e]])/(b^(3/2)*Sqrt[b*d - a*e])))/(4*b)))/(6*b)))/(8*b)))/Sqrt[a^2 + 
2*a*b*x + b^2*x^2]
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ 
(a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + 1))), x] - Simp[d*(n/(b*(m + 1))) 
Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d, n}, x 
] && ILtQ[m, -1] && FractionQ[n] && GtQ[n, 0]
 

rule 73

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ 
{p = Denominator[m]}, Simp[p/b   Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + 
 d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt 
Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL 
inearQ[a, b, c, d, m, n, x]
 

rule 221

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 1102

Int[((d_.) + (e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_S 
ymbol] :> Simp[(a + b*x + c*x^2)^FracPart[p]/(c^IntPart[p]*(b/2 + c*x)^(2*F 
racPart[p]))   Int[(d + e*x)^m*(b/2 + c*x)^(2*p), x], x] /; FreeQ[{a, b, c, 
 d, e, m, p}, x] && EqQ[b^2 - 4*a*c, 0]
 

Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(466\) vs. \(2(167)=334\).

Time = 1.61 (sec) , antiderivative size = 467, normalized size of antiderivative = 1.87

method	result	size
default	\(-\frac {\left (-105 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {b \left (a e -b d \right )}}\right ) b^{4} e^{4} x^{4}-420 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {b \left (a e -b d \right )}}\right ) a \,b^{3} e^{4} x^{3}+279 \left (e x +d \right )^{\frac {7}{2}} \sqrt {b \left (a e -b d \right )}\, b^{3}-630 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {b \left (a e -b d \right )}}\right ) a^{2} b^{2} e^{4} x^{2}+511 \left (e x +d \right )^{\frac {5}{2}} \sqrt {b \left (a e -b d \right )}\, a \,b^{2} e -511 \left (e x +d \right )^{\frac {5}{2}} \sqrt {b \left (a e -b d \right )}\, b^{3} d -420 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {b \left (a e -b d \right )}}\right ) a^{3} b \,e^{4} x +385 \left (e x +d \right )^{\frac {3}{2}} \sqrt {b \left (a e -b d \right )}\, a^{2} b \,e^{2}-770 \left (e x +d \right )^{\frac {3}{2}} \sqrt {b \left (a e -b d \right )}\, a \,b^{2} d e +385 \left (e x +d \right )^{\frac {3}{2}} \sqrt {b \left (a e -b d \right )}\, b^{3} d^{2}-105 \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {b \left (a e -b d \right )}}\right ) a^{4} e^{4}+105 \sqrt {e x +d}\, \sqrt {b \left (a e -b d \right )}\, a^{3} e^{3}-315 \sqrt {e x +d}\, a^{2} d b \,e^{2} \sqrt {b \left (a e -b d \right )}+315 \sqrt {e x +d}\, \sqrt {b \left (a e -b d \right )}\, a \,b^{2} d^{2} e -105 \sqrt {e x +d}\, \sqrt {b \left (a e -b d \right )}\, b^{3} d^{3}\right ) \left (b x +a \right )}{192 \sqrt {b \left (a e -b d \right )}\, b^{4} \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}\)	\(467\)

Input:

int((e*x+d)^(7/2)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x,method=_RETURNVERBOSE)
 

Output:

-1/192*(-105*arctan(b*(e*x+d)^(1/2)/(b*(a*e-b*d))^(1/2))*b^4*e^4*x^4-420*a 
rctan(b*(e*x+d)^(1/2)/(b*(a*e-b*d))^(1/2))*a*b^3*e^4*x^3+279*(e*x+d)^(7/2) 
*(b*(a*e-b*d))^(1/2)*b^3-630*arctan(b*(e*x+d)^(1/2)/(b*(a*e-b*d))^(1/2))*a 
^2*b^2*e^4*x^2+511*(e*x+d)^(5/2)*(b*(a*e-b*d))^(1/2)*a*b^2*e-511*(e*x+d)^( 
5/2)*(b*(a*e-b*d))^(1/2)*b^3*d-420*arctan(b*(e*x+d)^(1/2)/(b*(a*e-b*d))^(1 
/2))*a^3*b*e^4*x+385*(e*x+d)^(3/2)*(b*(a*e-b*d))^(1/2)*a^2*b*e^2-770*(e*x+ 
d)^(3/2)*(b*(a*e-b*d))^(1/2)*a*b^2*d*e+385*(e*x+d)^(3/2)*(b*(a*e-b*d))^(1/ 
2)*b^3*d^2-105*arctan(b*(e*x+d)^(1/2)/(b*(a*e-b*d))^(1/2))*a^4*e^4+105*(e* 
x+d)^(1/2)*(b*(a*e-b*d))^(1/2)*a^3*e^3-315*(e*x+d)^(1/2)*a^2*d*b*e^2*(b*(a 
*e-b*d))^(1/2)+315*(e*x+d)^(1/2)*(b*(a*e-b*d))^(1/2)*a*b^2*d^2*e-105*(e*x+ 
d)^(1/2)*(b*(a*e-b*d))^(1/2)*b^3*d^3)*(b*x+a)/(b*(a*e-b*d))^(1/2)/b^4/((b* 
x+a)^2)^(5/2)
 

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 376 vs. \(2 (167) = 334\).

Time = 0.11 (sec) , antiderivative size = 765, normalized size of antiderivative = 3.06 \[ \int \frac {(d+e x)^{7/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\left [\frac {105 \, {\left (b^{4} e^{4} x^{4} + 4 \, a b^{3} e^{4} x^{3} + 6 \, a^{2} b^{2} e^{4} x^{2} + 4 \, a^{3} b e^{4} x + a^{4} e^{4}\right )} \sqrt {b^{2} d - a b e} \log \left (\frac {b e x + 2 \, b d - a e - 2 \, \sqrt {b^{2} d - a b e} \sqrt {e x + d}}{b x + a}\right ) - 2 \, {\left (48 \, b^{5} d^{4} + 8 \, a b^{4} d^{3} e + 14 \, a^{2} b^{3} d^{2} e^{2} + 35 \, a^{3} b^{2} d e^{3} - 105 \, a^{4} b e^{4} + 279 \, {\left (b^{5} d e^{3} - a b^{4} e^{4}\right )} x^{3} + {\left (326 \, b^{5} d^{2} e^{2} + 185 \, a b^{4} d e^{3} - 511 \, a^{2} b^{3} e^{4}\right )} x^{2} + {\left (200 \, b^{5} d^{3} e + 52 \, a b^{4} d^{2} e^{2} + 133 \, a^{2} b^{3} d e^{3} - 385 \, a^{3} b^{2} e^{4}\right )} x\right )} \sqrt {e x + d}}{384 \, {\left (a^{4} b^{6} d - a^{5} b^{5} e + {\left (b^{10} d - a b^{9} e\right )} x^{4} + 4 \, {\left (a b^{9} d - a^{2} b^{8} e\right )} x^{3} + 6 \, {\left (a^{2} b^{8} d - a^{3} b^{7} e\right )} x^{2} + 4 \, {\left (a^{3} b^{7} d - a^{4} b^{6} e\right )} x\right )}}, \frac {105 \, {\left (b^{4} e^{4} x^{4} + 4 \, a b^{3} e^{4} x^{3} + 6 \, a^{2} b^{2} e^{4} x^{2} + 4 \, a^{3} b e^{4} x + a^{4} e^{4}\right )} \sqrt {-b^{2} d + a b e} \arctan \left (\frac {\sqrt {-b^{2} d + a b e} \sqrt {e x + d}}{b e x + b d}\right ) - {\left (48 \, b^{5} d^{4} + 8 \, a b^{4} d^{3} e + 14 \, a^{2} b^{3} d^{2} e^{2} + 35 \, a^{3} b^{2} d e^{3} - 105 \, a^{4} b e^{4} + 279 \, {\left (b^{5} d e^{3} - a b^{4} e^{4}\right )} x^{3} + {\left (326 \, b^{5} d^{2} e^{2} + 185 \, a b^{4} d e^{3} - 511 \, a^{2} b^{3} e^{4}\right )} x^{2} + {\left (200 \, b^{5} d^{3} e + 52 \, a b^{4} d^{2} e^{2} + 133 \, a^{2} b^{3} d e^{3} - 385 \, a^{3} b^{2} e^{4}\right )} x\right )} \sqrt {e x + d}}{192 \, {\left (a^{4} b^{6} d - a^{5} b^{5} e + {\left (b^{10} d - a b^{9} e\right )} x^{4} + 4 \, {\left (a b^{9} d - a^{2} b^{8} e\right )} x^{3} + 6 \, {\left (a^{2} b^{8} d - a^{3} b^{7} e\right )} x^{2} + 4 \, {\left (a^{3} b^{7} d - a^{4} b^{6} e\right )} x\right )}}\right ] \] Input:

integrate((e*x+d)^(7/2)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x, algorithm="fricas")
 

Output:

[1/384*(105*(b^4*e^4*x^4 + 4*a*b^3*e^4*x^3 + 6*a^2*b^2*e^4*x^2 + 4*a^3*b*e 
^4*x + a^4*e^4)*sqrt(b^2*d - a*b*e)*log((b*e*x + 2*b*d - a*e - 2*sqrt(b^2* 
d - a*b*e)*sqrt(e*x + d))/(b*x + a)) - 2*(48*b^5*d^4 + 8*a*b^4*d^3*e + 14* 
a^2*b^3*d^2*e^2 + 35*a^3*b^2*d*e^3 - 105*a^4*b*e^4 + 279*(b^5*d*e^3 - a*b^ 
4*e^4)*x^3 + (326*b^5*d^2*e^2 + 185*a*b^4*d*e^3 - 511*a^2*b^3*e^4)*x^2 + ( 
200*b^5*d^3*e + 52*a*b^4*d^2*e^2 + 133*a^2*b^3*d*e^3 - 385*a^3*b^2*e^4)*x) 
*sqrt(e*x + d))/(a^4*b^6*d - a^5*b^5*e + (b^10*d - a*b^9*e)*x^4 + 4*(a*b^9 
*d - a^2*b^8*e)*x^3 + 6*(a^2*b^8*d - a^3*b^7*e)*x^2 + 4*(a^3*b^7*d - a^4*b 
^6*e)*x), 1/192*(105*(b^4*e^4*x^4 + 4*a*b^3*e^4*x^3 + 6*a^2*b^2*e^4*x^2 + 
4*a^3*b*e^4*x + a^4*e^4)*sqrt(-b^2*d + a*b*e)*arctan(sqrt(-b^2*d + a*b*e)* 
sqrt(e*x + d)/(b*e*x + b*d)) - (48*b^5*d^4 + 8*a*b^4*d^3*e + 14*a^2*b^3*d^ 
2*e^2 + 35*a^3*b^2*d*e^3 - 105*a^4*b*e^4 + 279*(b^5*d*e^3 - a*b^4*e^4)*x^3 
 + (326*b^5*d^2*e^2 + 185*a*b^4*d*e^3 - 511*a^2*b^3*e^4)*x^2 + (200*b^5*d^ 
3*e + 52*a*b^4*d^2*e^2 + 133*a^2*b^3*d*e^3 - 385*a^3*b^2*e^4)*x)*sqrt(e*x 
+ d))/(a^4*b^6*d - a^5*b^5*e + (b^10*d - a*b^9*e)*x^4 + 4*(a*b^9*d - a^2*b 
^8*e)*x^3 + 6*(a^2*b^8*d - a^3*b^7*e)*x^2 + 4*(a^3*b^7*d - a^4*b^6*e)*x)]
 

Sympy [F(-1)]

Timed out. \[ \int \frac {(d+e x)^{7/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\text {Timed out} \] Input:

integrate((e*x+d)**(7/2)/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)
 

Output:

Timed out
 

Maxima [F]

\[ \int \frac {(d+e x)^{7/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\int { \frac {{\left (e x + d\right )}^{\frac {7}{2}}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}}} \,d x } \] Input:

integrate((e*x+d)^(7/2)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x, algorithm="maxima")
 

Output:

integrate((e*x + d)^(7/2)/(b^2*x^2 + 2*a*b*x + a^2)^(5/2), x)
 

Giac [A] (verification not implemented)

Time = 0.18 (sec) , antiderivative size = 251, normalized size of antiderivative = 1.00 \[ \int \frac {(d+e x)^{7/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\frac {35 \, e^{4} \arctan \left (\frac {\sqrt {e x + d} b}{\sqrt {-b^{2} d + a b e}}\right )}{64 \, \sqrt {-b^{2} d + a b e} b^{4} \mathrm {sgn}\left (b x + a\right )} - \frac {279 \, {\left (e x + d\right )}^{\frac {7}{2}} b^{3} e^{4} - 511 \, {\left (e x + d\right )}^{\frac {5}{2}} b^{3} d e^{4} + 385 \, {\left (e x + d\right )}^{\frac {3}{2}} b^{3} d^{2} e^{4} - 105 \, \sqrt {e x + d} b^{3} d^{3} e^{4} + 511 \, {\left (e x + d\right )}^{\frac {5}{2}} a b^{2} e^{5} - 770 \, {\left (e x + d\right )}^{\frac {3}{2}} a b^{2} d e^{5} + 315 \, \sqrt {e x + d} a b^{2} d^{2} e^{5} + 385 \, {\left (e x + d\right )}^{\frac {3}{2}} a^{2} b e^{6} - 315 \, \sqrt {e x + d} a^{2} b d e^{6} + 105 \, \sqrt {e x + d} a^{3} e^{7}}{192 \, {\left ({\left (e x + d\right )} b - b d + a e\right )}^{4} b^{4} \mathrm {sgn}\left (b x + a\right )} \] Input:

integrate((e*x+d)^(7/2)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x, algorithm="giac")
 

Output:

35/64*e^4*arctan(sqrt(e*x + d)*b/sqrt(-b^2*d + a*b*e))/(sqrt(-b^2*d + a*b* 
e)*b^4*sgn(b*x + a)) - 1/192*(279*(e*x + d)^(7/2)*b^3*e^4 - 511*(e*x + d)^ 
(5/2)*b^3*d*e^4 + 385*(e*x + d)^(3/2)*b^3*d^2*e^4 - 105*sqrt(e*x + d)*b^3* 
d^3*e^4 + 511*(e*x + d)^(5/2)*a*b^2*e^5 - 770*(e*x + d)^(3/2)*a*b^2*d*e^5 
+ 315*sqrt(e*x + d)*a*b^2*d^2*e^5 + 385*(e*x + d)^(3/2)*a^2*b*e^6 - 315*sq 
rt(e*x + d)*a^2*b*d*e^6 + 105*sqrt(e*x + d)*a^3*e^7)/(((e*x + d)*b - b*d + 
 a*e)^4*b^4*sgn(b*x + a))
 

Mupad [F(-1)]

Timed out. \[ \int \frac {(d+e x)^{7/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\int \frac {{\left (d+e\,x\right )}^{7/2}}{{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2}} \,d x \] Input:

int((d + e*x)^(7/2)/(a^2 + b^2*x^2 + 2*a*b*x)^(5/2),x)
 

Output:

int((d + e*x)^(7/2)/(a^2 + b^2*x^2 + 2*a*b*x)^(5/2), x)
 

Reduce [B] (verification not implemented)

Time = 0.23 (sec) , antiderivative size = 583, normalized size of antiderivative = 2.33 \[ \int \frac {(d+e x)^{7/2}}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\frac {105 \sqrt {b}\, \sqrt {a e -b d}\, \mathit {atan} \left (\frac {\sqrt {e x +d}\, b}{\sqrt {b}\, \sqrt {a e -b d}}\right ) a^{4} e^{4}+420 \sqrt {b}\, \sqrt {a e -b d}\, \mathit {atan} \left (\frac {\sqrt {e x +d}\, b}{\sqrt {b}\, \sqrt {a e -b d}}\right ) a^{3} b \,e^{4} x +630 \sqrt {b}\, \sqrt {a e -b d}\, \mathit {atan} \left (\frac {\sqrt {e x +d}\, b}{\sqrt {b}\, \sqrt {a e -b d}}\right ) a^{2} b^{2} e^{4} x^{2}+420 \sqrt {b}\, \sqrt {a e -b d}\, \mathit {atan} \left (\frac {\sqrt {e x +d}\, b}{\sqrt {b}\, \sqrt {a e -b d}}\right ) a \,b^{3} e^{4} x^{3}+105 \sqrt {b}\, \sqrt {a e -b d}\, \mathit {atan} \left (\frac {\sqrt {e x +d}\, b}{\sqrt {b}\, \sqrt {a e -b d}}\right ) b^{4} e^{4} x^{4}-105 \sqrt {e x +d}\, a^{4} b \,e^{4}+35 \sqrt {e x +d}\, a^{3} b^{2} d \,e^{3}-385 \sqrt {e x +d}\, a^{3} b^{2} e^{4} x +14 \sqrt {e x +d}\, a^{2} b^{3} d^{2} e^{2}+133 \sqrt {e x +d}\, a^{2} b^{3} d \,e^{3} x -511 \sqrt {e x +d}\, a^{2} b^{3} e^{4} x^{2}+8 \sqrt {e x +d}\, a \,b^{4} d^{3} e +52 \sqrt {e x +d}\, a \,b^{4} d^{2} e^{2} x +185 \sqrt {e x +d}\, a \,b^{4} d \,e^{3} x^{2}-279 \sqrt {e x +d}\, a \,b^{4} e^{4} x^{3}+48 \sqrt {e x +d}\, b^{5} d^{4}+200 \sqrt {e x +d}\, b^{5} d^{3} e x +326 \sqrt {e x +d}\, b^{5} d^{2} e^{2} x^{2}+279 \sqrt {e x +d}\, b^{5} d \,e^{3} x^{3}}{192 b^{5} \left (a \,b^{4} e \,x^{4}-b^{5} d \,x^{4}+4 a^{2} b^{3} e \,x^{3}-4 a \,b^{4} d \,x^{3}+6 a^{3} b^{2} e \,x^{2}-6 a^{2} b^{3} d \,x^{2}+4 a^{4} b e x -4 a^{3} b^{2} d x +a^{5} e -a^{4} b d \right )} \] Input:

int((e*x+d)^(7/2)/(b^2*x^2+2*a*b*x+a^2)^(5/2),x)
 

Output:

(105*sqrt(b)*sqrt(a*e - b*d)*atan((sqrt(d + e*x)*b)/(sqrt(b)*sqrt(a*e - b* 
d)))*a**4*e**4 + 420*sqrt(b)*sqrt(a*e - b*d)*atan((sqrt(d + e*x)*b)/(sqrt( 
b)*sqrt(a*e - b*d)))*a**3*b*e**4*x + 630*sqrt(b)*sqrt(a*e - b*d)*atan((sqr 
t(d + e*x)*b)/(sqrt(b)*sqrt(a*e - b*d)))*a**2*b**2*e**4*x**2 + 420*sqrt(b) 
*sqrt(a*e - b*d)*atan((sqrt(d + e*x)*b)/(sqrt(b)*sqrt(a*e - b*d)))*a*b**3* 
e**4*x**3 + 105*sqrt(b)*sqrt(a*e - b*d)*atan((sqrt(d + e*x)*b)/(sqrt(b)*sq 
rt(a*e - b*d)))*b**4*e**4*x**4 - 105*sqrt(d + e*x)*a**4*b*e**4 + 35*sqrt(d 
 + e*x)*a**3*b**2*d*e**3 - 385*sqrt(d + e*x)*a**3*b**2*e**4*x + 14*sqrt(d 
+ e*x)*a**2*b**3*d**2*e**2 + 133*sqrt(d + e*x)*a**2*b**3*d*e**3*x - 511*sq 
rt(d + e*x)*a**2*b**3*e**4*x**2 + 8*sqrt(d + e*x)*a*b**4*d**3*e + 52*sqrt( 
d + e*x)*a*b**4*d**2*e**2*x + 185*sqrt(d + e*x)*a*b**4*d*e**3*x**2 - 279*s 
qrt(d + e*x)*a*b**4*e**4*x**3 + 48*sqrt(d + e*x)*b**5*d**4 + 200*sqrt(d + 
e*x)*b**5*d**3*e*x + 326*sqrt(d + e*x)*b**5*d**2*e**2*x**2 + 279*sqrt(d + 
e*x)*b**5*d*e**3*x**3)/(192*b**5*(a**5*e - a**4*b*d + 4*a**4*b*e*x - 4*a** 
3*b**2*d*x + 6*a**3*b**2*e*x**2 - 6*a**2*b**3*d*x**2 + 4*a**2*b**3*e*x**3 
- 4*a*b**4*d*x**3 + a*b**4*e*x**4 - b**5*d*x**4))