\(\int (b d+2 c d x)^{5/2} (a+b x+c x^2)^{5/2} \, dx\) [253]

Optimal result

Integrand size = 28, antiderivative size = 373 \[ \int (b d+2 c d x)^{5/2} \left (a+b x+c x^2\right )^{5/2} \, dx=-\frac {\left (b^2-4 a c\right )^3 d (b d+2 c d x)^{3/2} \sqrt {a+b x+c x^2}}{1326 c^3}+\frac {5 \left (b^2-4 a c\right )^2 (b d+2 c d x)^{7/2} \sqrt {a+b x+c x^2}}{2652 c^3 d}-\frac {5 \left (b^2-4 a c\right ) (b d+2 c d x)^{7/2} \left (a+b x+c x^2\right )^{3/2}}{442 c^2 d}+\frac {(b d+2 c d x)^{7/2} \left (a+b x+c x^2\right )^{5/2}}{17 c d}-\frac {\left (b^2-4 a c\right )^{19/4} d^{5/2} \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} E\left (\left .\arcsin \left (\frac {\sqrt {b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right )\right |-1\right )}{884 c^4 \sqrt {a+b x+c x^2}}+\frac {\left (b^2-4 a c\right )^{19/4} d^{5/2} \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right ),-1\right )}{884 c^4 \sqrt {a+b x+c x^2}} \] Output:

-1/1326*(-4*a*c+b^2)^3*d*(2*c*d*x+b*d)^(3/2)*(c*x^2+b*x+a)^(1/2)/c^3+5/265 
2*(-4*a*c+b^2)^2*(2*c*d*x+b*d)^(7/2)*(c*x^2+b*x+a)^(1/2)/c^3/d-5/442*(-4*a 
*c+b^2)*(2*c*d*x+b*d)^(7/2)*(c*x^2+b*x+a)^(3/2)/c^2/d+1/17*(2*c*d*x+b*d)^( 
7/2)*(c*x^2+b*x+a)^(5/2)/c/d-1/884*(-4*a*c+b^2)^(19/4)*d^(5/2)*(-c*(c*x^2+ 
b*x+a)/(-4*a*c+b^2))^(1/2)*EllipticE((2*c*d*x+b*d)^(1/2)/(-4*a*c+b^2)^(1/4 
)/d^(1/2),I)/c^4/(c*x^2+b*x+a)^(1/2)+1/884*(-4*a*c+b^2)^(19/4)*d^(5/2)*(-c 
*(c*x^2+b*x+a)/(-4*a*c+b^2))^(1/2)*EllipticF((2*c*d*x+b*d)^(1/2)/(-4*a*c+b 
^2)^(1/4)/d^(1/2),I)/c^4/(c*x^2+b*x+a)^(1/2)
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.13 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.31 \[ \int (b d+2 c d x)^{5/2} \left (a+b x+c x^2\right )^{5/2} \, dx=\frac {2}{17} d (d (b+2 c x))^{3/2} \sqrt {a+x (b+c x)} \left (2 (a+x (b+c x))^3+\frac {\left (b^2-4 a c\right )^3 \operatorname {Hypergeometric2F1}\left (-\frac {5}{2},\frac {3}{4},\frac {7}{4},\frac {(b+2 c x)^2}{b^2-4 a c}\right )}{64 c^3 \sqrt {\frac {c (a+x (b+c x))}{-b^2+4 a c}}}\right ) \] Input:

Integrate[(b*d + 2*c*d*x)^(5/2)*(a + b*x + c*x^2)^(5/2),x]
 

Output:

(2*d*(d*(b + 2*c*x))^(3/2)*Sqrt[a + x*(b + c*x)]*(2*(a + x*(b + c*x))^3 + 
((b^2 - 4*a*c)^3*Hypergeometric2F1[-5/2, 3/4, 7/4, (b + 2*c*x)^2/(b^2 - 4* 
a*c)])/(64*c^3*Sqrt[(c*(a + x*(b + c*x)))/(-b^2 + 4*a*c)])))/17
 

Rubi [A] (verified)

Time = 0.71 (sec) , antiderivative size = 355, normalized size of antiderivative = 0.95, number of steps used = 12, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.393, Rules used = {1109, 1109, 1109, 1116, 1115, 1114, 836, 27, 762, 1389, 327}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{5/2} \, dx\)

\(\Big \downarrow \) 1109

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \int (b d+2 c x d)^{5/2} \left (c x^2+b x+a\right )^{3/2}dx}{34 c}\)

\(\Big \downarrow \) 1109

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \int (b d+2 c x d)^{5/2} \sqrt {c x^2+b x+a}dx}{26 c}\right )}{34 c}\)

\(\Big \downarrow \) 1109

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \left (\frac {\sqrt {a+b x+c x^2} (b d+2 c d x)^{7/2}}{9 c d}-\frac {\left (b^2-4 a c\right ) \int \frac {(b d+2 c x d)^{5/2}}{\sqrt {c x^2+b x+a}}dx}{18 c}\right )}{26 c}\right )}{34 c}\)

\(\Big \downarrow \) 1116

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \left (\frac {\sqrt {a+b x+c x^2} (b d+2 c d x)^{7/2}}{9 c d}-\frac {\left (b^2-4 a c\right ) \left (\frac {3}{5} d^2 \left (b^2-4 a c\right ) \int \frac {\sqrt {b d+2 c x d}}{\sqrt {c x^2+b x+a}}dx+\frac {4}{5} d \sqrt {a+b x+c x^2} (b d+2 c d x)^{3/2}\right )}{18 c}\right )}{26 c}\right )}{34 c}\)

\(\Big \downarrow \) 1115

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \left (\frac {\sqrt {a+b x+c x^2} (b d+2 c d x)^{7/2}}{9 c d}-\frac {\left (b^2-4 a c\right ) \left (\frac {3 d^2 \left (b^2-4 a c\right ) \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \int \frac {\sqrt {b d+2 c x d}}{\sqrt {-\frac {c^2 x^2}{b^2-4 a c}-\frac {b c x}{b^2-4 a c}-\frac {a c}{b^2-4 a c}}}dx}{5 \sqrt {a+b x+c x^2}}+\frac {4}{5} d \sqrt {a+b x+c x^2} (b d+2 c d x)^{3/2}\right )}{18 c}\right )}{26 c}\right )}{34 c}\)

\(\Big \downarrow \) 1114

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \left (\frac {\sqrt {a+b x+c x^2} (b d+2 c d x)^{7/2}}{9 c d}-\frac {\left (b^2-4 a c\right ) \left (\frac {6 d \left (b^2-4 a c\right ) \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \int \frac {b d+2 c x d}{\sqrt {1-\frac {(b d+2 c x d)^2}{\left (b^2-4 a c\right ) d^2}}}d\sqrt {b d+2 c x d}}{5 c \sqrt {a+b x+c x^2}}+\frac {4}{5} d \sqrt {a+b x+c x^2} (b d+2 c d x)^{3/2}\right )}{18 c}\right )}{26 c}\right )}{34 c}\)

\(\Big \downarrow \) 836

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \left (\frac {\sqrt {a+b x+c x^2} (b d+2 c d x)^{7/2}}{9 c d}-\frac {\left (b^2-4 a c\right ) \left (\frac {6 d \left (b^2-4 a c\right ) \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \left (d \sqrt {b^2-4 a c} \int \frac {d+\frac {b d+2 c x d}{\sqrt {b^2-4 a c}}}{d \sqrt {1-\frac {(b d+2 c x d)^2}{\left (b^2-4 a c\right ) d^2}}}d\sqrt {b d+2 c x d}-d \sqrt {b^2-4 a c} \int \frac {1}{\sqrt {1-\frac {(b d+2 c x d)^2}{\left (b^2-4 a c\right ) d^2}}}d\sqrt {b d+2 c x d}\right )}{5 c \sqrt {a+b x+c x^2}}+\frac {4}{5} d \sqrt {a+b x+c x^2} (b d+2 c d x)^{3/2}\right )}{18 c}\right )}{26 c}\right )}{34 c}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \left (\frac {\sqrt {a+b x+c x^2} (b d+2 c d x)^{7/2}}{9 c d}-\frac {\left (b^2-4 a c\right ) \left (\frac {6 d \left (b^2-4 a c\right ) \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \left (\sqrt {b^2-4 a c} \int \frac {d+\frac {b d+2 c x d}{\sqrt {b^2-4 a c}}}{\sqrt {1-\frac {(b d+2 c x d)^2}{\left (b^2-4 a c\right ) d^2}}}d\sqrt {b d+2 c x d}-d \sqrt {b^2-4 a c} \int \frac {1}{\sqrt {1-\frac {(b d+2 c x d)^2}{\left (b^2-4 a c\right ) d^2}}}d\sqrt {b d+2 c x d}\right )}{5 c \sqrt {a+b x+c x^2}}+\frac {4}{5} d \sqrt {a+b x+c x^2} (b d+2 c d x)^{3/2}\right )}{18 c}\right )}{26 c}\right )}{34 c}\)

\(\Big \downarrow \) 762

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \left (\frac {\sqrt {a+b x+c x^2} (b d+2 c d x)^{7/2}}{9 c d}-\frac {\left (b^2-4 a c\right ) \left (\frac {6 d \left (b^2-4 a c\right ) \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \left (\sqrt {b^2-4 a c} \int \frac {d+\frac {b d+2 c x d}{\sqrt {b^2-4 a c}}}{\sqrt {1-\frac {(b d+2 c x d)^2}{\left (b^2-4 a c\right ) d^2}}}d\sqrt {b d+2 c x d}-d^{3/2} \left (b^2-4 a c\right )^{3/4} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right ),-1\right )\right )}{5 c \sqrt {a+b x+c x^2}}+\frac {4}{5} d \sqrt {a+b x+c x^2} (b d+2 c d x)^{3/2}\right )}{18 c}\right )}{26 c}\right )}{34 c}\)

\(\Big \downarrow \) 1389

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \left (\frac {\sqrt {a+b x+c x^2} (b d+2 c d x)^{7/2}}{9 c d}-\frac {\left (b^2-4 a c\right ) \left (\frac {6 d \left (b^2-4 a c\right ) \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \left (d \sqrt {b^2-4 a c} \int \frac {\sqrt {\frac {b d+2 c x d}{\sqrt {b^2-4 a c} d}+1}}{\sqrt {1-\frac {b d+2 c x d}{\sqrt {b^2-4 a c} d}}}d\sqrt {b d+2 c x d}-d^{3/2} \left (b^2-4 a c\right )^{3/4} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right ),-1\right )\right )}{5 c \sqrt {a+b x+c x^2}}+\frac {4}{5} d \sqrt {a+b x+c x^2} (b d+2 c d x)^{3/2}\right )}{18 c}\right )}{26 c}\right )}{34 c}\)

\(\Big \downarrow \) 327

\(\displaystyle \frac {\left (a+b x+c x^2\right )^{5/2} (b d+2 c d x)^{7/2}}{17 c d}-\frac {5 \left (b^2-4 a c\right ) \left (\frac {\left (a+b x+c x^2\right )^{3/2} (b d+2 c d x)^{7/2}}{13 c d}-\frac {3 \left (b^2-4 a c\right ) \left (\frac {\sqrt {a+b x+c x^2} (b d+2 c d x)^{7/2}}{9 c d}-\frac {\left (b^2-4 a c\right ) \left (\frac {6 d \left (b^2-4 a c\right ) \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \left (d^{3/2} \left (b^2-4 a c\right )^{3/4} E\left (\left .\arcsin \left (\frac {\sqrt {b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right )\right |-1\right )-d^{3/2} \left (b^2-4 a c\right )^{3/4} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right ),-1\right )\right )}{5 c \sqrt {a+b x+c x^2}}+\frac {4}{5} d \sqrt {a+b x+c x^2} (b d+2 c d x)^{3/2}\right )}{18 c}\right )}{26 c}\right )}{34 c}\)

Input:

Int[(b*d + 2*c*d*x)^(5/2)*(a + b*x + c*x^2)^(5/2),x]
 

Output:

((b*d + 2*c*d*x)^(7/2)*(a + b*x + c*x^2)^(5/2))/(17*c*d) - (5*(b^2 - 4*a*c 
)*(((b*d + 2*c*d*x)^(7/2)*(a + b*x + c*x^2)^(3/2))/(13*c*d) - (3*(b^2 - 4* 
a*c)*(((b*d + 2*c*d*x)^(7/2)*Sqrt[a + b*x + c*x^2])/(9*c*d) - ((b^2 - 4*a* 
c)*((4*d*(b*d + 2*c*d*x)^(3/2)*Sqrt[a + b*x + c*x^2])/5 + (6*(b^2 - 4*a*c) 
*d*Sqrt[-((c*(a + b*x + c*x^2))/(b^2 - 4*a*c))]*((b^2 - 4*a*c)^(3/4)*d^(3/ 
2)*EllipticE[ArcSin[Sqrt[b*d + 2*c*d*x]/((b^2 - 4*a*c)^(1/4)*Sqrt[d])], -1 
] - (b^2 - 4*a*c)^(3/4)*d^(3/2)*EllipticF[ArcSin[Sqrt[b*d + 2*c*d*x]/((b^2 
 - 4*a*c)^(1/4)*Sqrt[d])], -1]))/(5*c*Sqrt[a + b*x + c*x^2])))/(18*c)))/(2 
6*c)))/(34*c)
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 327

Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[ 
(Sqrt[a]/(Sqrt[c]*Rt[-d/c, 2]))*EllipticE[ArcSin[Rt[-d/c, 2]*x], b*(c/(a*d) 
)], x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[a, 0]
 

rule 762

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[(1/(Sqrt[a]*Rt[-b/a, 4]) 
)*EllipticF[ArcSin[Rt[-b/a, 4]*x], -1], x] /; FreeQ[{a, b}, x] && NegQ[b/a] 
 && GtQ[a, 0]
 

rule 836

Int[(x_)^2/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[-b/a, 2]}, 
Simp[-q^(-1)   Int[1/Sqrt[a + b*x^4], x], x] + Simp[1/q   Int[(1 + q*x^2)/S 
qrt[a + b*x^4], x], x]] /; FreeQ[{a, b}, x] && NegQ[b/a]
 

rule 1109

Int[((d_) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_S 
ymbol] :> Simp[(d + e*x)^(m + 1)*((a + b*x + c*x^2)^p/(e*(m + 2*p + 1))), x 
] - Simp[d*p*((b^2 - 4*a*c)/(b*e*(m + 2*p + 1)))   Int[(d + e*x)^m*(a + b*x 
 + c*x^2)^(p - 1), x], x] /; FreeQ[{a, b, c, d, e, m}, x] && EqQ[2*c*d - b* 
e, 0] && NeQ[m + 2*p + 3, 0] && GtQ[p, 0] &&  !LtQ[m, -1] &&  !(IGtQ[(m - 1 
)/2, 0] && ( !IntegerQ[p] || LtQ[m, 2*p])) && RationalQ[m] && IntegerQ[2*p]
 

rule 1114

Int[Sqrt[(d_) + (e_.)*(x_)]/Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2], x_Symb 
ol] :> Simp[(4/e)*Sqrt[-c/(b^2 - 4*a*c)]   Subst[Int[x^2/Sqrt[Simp[1 - b^2* 
(x^4/(d^2*(b^2 - 4*a*c))), x]], x], x, Sqrt[d + e*x]], x] /; FreeQ[{a, b, c 
, d, e}, x] && EqQ[2*c*d - b*e, 0] && LtQ[c/(b^2 - 4*a*c), 0]
 

rule 1115

Int[((d_) + (e_.)*(x_))^(m_)/Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2], x_Sym 
bol] :> Simp[Sqrt[(-c)*((a + b*x + c*x^2)/(b^2 - 4*a*c))]/Sqrt[a + b*x + c* 
x^2]   Int[(d + e*x)^m/Sqrt[(-a)*(c/(b^2 - 4*a*c)) - b*c*(x/(b^2 - 4*a*c)) 
- c^2*(x^2/(b^2 - 4*a*c))], x], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c* 
d - b*e, 0] && EqQ[m^2, 1/4]
 

rule 1116

Int[((d_) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_S 
ymbol] :> Simp[2*d*(d + e*x)^(m - 1)*((a + b*x + c*x^2)^(p + 1)/(b*(m + 2*p 
 + 1))), x] + Simp[d^2*(m - 1)*((b^2 - 4*a*c)/(b^2*(m + 2*p + 1)))   Int[(d 
 + e*x)^(m - 2)*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] 
 && EqQ[2*c*d - b*e, 0] && NeQ[m + 2*p + 3, 0] && GtQ[m, 1] && NeQ[m + 2*p 
+ 1, 0] && (IntegerQ[2*p] || (IntegerQ[m] && RationalQ[p]) || OddQ[m])
 

rule 1389

Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (c_.)*(x_)^4], x_Symbol] :> Simp[d/Sq 
rt[a]   Int[Sqrt[1 + e*(x^2/d)]/Sqrt[1 - e*(x^2/d)], x], x] /; FreeQ[{a, c, 
 d, e}, x] && EqQ[c*d^2 + a*e^2, 0] && NegQ[c/a] && GtQ[a, 0]
 

Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(1189\) vs. \(2(317)=634\).

Time = 8.98 (sec) , antiderivative size = 1190, normalized size of antiderivative = 3.19

method	result	size
default	\(\text {Expression too large to display}\)	\(1190\)
risch	\(\text {Expression too large to display}\)	\(2706\)
elliptic	\(\text {Expression too large to display}\)	\(9950\)

Input:

int((2*c*d*x+b*d)^(5/2)*(c*x^2+b*x+a)^(5/2),x,method=_RETURNVERBOSE)
 

Output:

-1/5304*(d*(2*c*x+b))^(1/2)*(c*x^2+b*x+a)^(1/2)*d^2*(-256*a^4*b^2*c^4+3072 
*(1/(-4*a*c+b^2)^(1/2)*(2*c*x+(-4*a*c+b^2)^(1/2)+b))^(1/2)*(-(2*c*x+b)/(-4 
*a*c+b^2)^(1/2))^(1/2)*((-2*c*x+(-4*a*c+b^2)^(1/2)-b)/(-4*a*c+b^2)^(1/2))^ 
(1/2)*EllipticE(1/2*2^(1/2)*(1/(-4*a*c+b^2)^(1/2)*(2*c*x+(-4*a*c+b^2)^(1/2 
)+b))^(1/2),2^(1/2))*a^5*c^5-37368*a*b^4*c^5*x^4-24832*a^3*b*c^6*x^3-44416 
*a^2*b^3*c^5*x^3-6064*a*b^5*c^4*x^3-17600*a^3*b^2*c^5*x^2-10056*a^2*b^4*c^ 
4*x^2+160*a*b^6*c^3*x^2-1024*a^4*b*c^5*x-5184*a^3*b^3*c^4*x-456*a^2*b^5*c^ 
3*x+88*a*b^7*c^2*x-24960*b*c^9*x^9-18816*a*c^9*x^8-51456*b^2*c^8*x^8-56064 
*b^3*c^7*x^7-25216*a^2*c^8*x^6-34168*b^4*c^6*x^6-11112*b^5*c^5*x^5-12416*a 
^3*c^7*x^4-1516*b^6*c^4*x^4-1024*a^4*c^6*x^2-10*b^8*c^2*x^2-6*b^9*c*x-520* 
a^3*b^4*c^3+92*a^2*b^6*c^2-6*a*b^8*c-75264*a*b*c^8*x^7-119104*a*b^2*c^7*x^ 
6-75648*a^2*b*c^7*x^5-93888*a*b^3*c^6*x^5-85248*a^2*b^2*c^6*x^4-4992*c^10* 
x^10-3840*(1/(-4*a*c+b^2)^(1/2)*(2*c*x+(-4*a*c+b^2)^(1/2)+b))^(1/2)*(-(2*c 
*x+b)/(-4*a*c+b^2)^(1/2))^(1/2)*((-2*c*x+(-4*a*c+b^2)^(1/2)-b)/(-4*a*c+b^2 
)^(1/2))^(1/2)*EllipticE(1/2*2^(1/2)*(1/(-4*a*c+b^2)^(1/2)*(2*c*x+(-4*a*c+ 
b^2)^(1/2)+b))^(1/2),2^(1/2))*a^4*b^2*c^4+1920*(1/(-4*a*c+b^2)^(1/2)*(2*c* 
x+(-4*a*c+b^2)^(1/2)+b))^(1/2)*(-(2*c*x+b)/(-4*a*c+b^2)^(1/2))^(1/2)*((-2* 
c*x+(-4*a*c+b^2)^(1/2)-b)/(-4*a*c+b^2)^(1/2))^(1/2)*EllipticE(1/2*2^(1/2)* 
(1/(-4*a*c+b^2)^(1/2)*(2*c*x+(-4*a*c+b^2)^(1/2)+b))^(1/2),2^(1/2))*a^3*b^4 
*c^3-480*(1/(-4*a*c+b^2)^(1/2)*(2*c*x+(-4*a*c+b^2)^(1/2)+b))^(1/2)*(-(2...
 

Fricas [A] (verification not implemented)

Time = 0.11 (sec) , antiderivative size = 346, normalized size of antiderivative = 0.93 \[ \int (b d+2 c d x)^{5/2} \left (a+b x+c x^2\right )^{5/2} \, dx=\frac {3 \, \sqrt {2} {\left (b^{8} - 16 \, a b^{6} c + 96 \, a^{2} b^{4} c^{2} - 256 \, a^{3} b^{2} c^{3} + 256 \, a^{4} c^{4}\right )} \sqrt {c^{2} d} d^{2} {\rm weierstrassZeta}\left (\frac {b^{2} - 4 \, a c}{c^{2}}, 0, {\rm weierstrassPInverse}\left (\frac {b^{2} - 4 \, a c}{c^{2}}, 0, \frac {2 \, c x + b}{2 \, c}\right )\right ) + {\left (1248 \, c^{8} d^{2} x^{7} + 4368 \, b c^{7} d^{2} x^{6} + 72 \, {\left (79 \, b^{2} c^{6} + 48 \, a c^{7}\right )} d^{2} x^{5} + 60 \, {\left (55 \, b^{3} c^{5} + 144 \, a b c^{6}\right )} d^{2} x^{4} + 4 \, {\left (187 \, b^{4} c^{4} + 1804 \, a b^{2} c^{5} + 712 \, a^{2} c^{6}\right )} d^{2} x^{3} + 6 \, {\left (b^{5} c^{3} + 364 \, a b^{3} c^{4} + 712 \, a^{2} b c^{5}\right )} d^{2} x^{2} - 4 \, {\left (b^{6} c^{2} - 15 \, a b^{4} c^{3} - 486 \, a^{2} b^{2} c^{4} - 64 \, a^{3} c^{5}\right )} d^{2} x + {\left (3 \, b^{7} c - 46 \, a b^{5} c^{2} + 260 \, a^{2} b^{3} c^{3} + 128 \, a^{3} b c^{4}\right )} d^{2}\right )} \sqrt {2 \, c d x + b d} \sqrt {c x^{2} + b x + a}}{2652 \, c^{4}} \] Input:

integrate((2*c*d*x+b*d)^(5/2)*(c*x^2+b*x+a)^(5/2),x, algorithm="fricas")
 

Output:

1/2652*(3*sqrt(2)*(b^8 - 16*a*b^6*c + 96*a^2*b^4*c^2 - 256*a^3*b^2*c^3 + 2 
56*a^4*c^4)*sqrt(c^2*d)*d^2*weierstrassZeta((b^2 - 4*a*c)/c^2, 0, weierstr 
assPInverse((b^2 - 4*a*c)/c^2, 0, 1/2*(2*c*x + b)/c)) + (1248*c^8*d^2*x^7 
+ 4368*b*c^7*d^2*x^6 + 72*(79*b^2*c^6 + 48*a*c^7)*d^2*x^5 + 60*(55*b^3*c^5 
 + 144*a*b*c^6)*d^2*x^4 + 4*(187*b^4*c^4 + 1804*a*b^2*c^5 + 712*a^2*c^6)*d 
^2*x^3 + 6*(b^5*c^3 + 364*a*b^3*c^4 + 712*a^2*b*c^5)*d^2*x^2 - 4*(b^6*c^2 
- 15*a*b^4*c^3 - 486*a^2*b^2*c^4 - 64*a^3*c^5)*d^2*x + (3*b^7*c - 46*a*b^5 
*c^2 + 260*a^2*b^3*c^3 + 128*a^3*b*c^4)*d^2)*sqrt(2*c*d*x + b*d)*sqrt(c*x^ 
2 + b*x + a))/c^4
 

Sympy [F]

\[ \int (b d+2 c d x)^{5/2} \left (a+b x+c x^2\right )^{5/2} \, dx=\int \left (d \left (b + 2 c x\right )\right )^{\frac {5}{2}} \left (a + b x + c x^{2}\right )^{\frac {5}{2}}\, dx \] Input:

integrate((2*c*d*x+b*d)**(5/2)*(c*x**2+b*x+a)**(5/2),x)
 

Output:

Integral((d*(b + 2*c*x))**(5/2)*(a + b*x + c*x**2)**(5/2), x)
 

Maxima [F]

\[ \int (b d+2 c d x)^{5/2} \left (a+b x+c x^2\right )^{5/2} \, dx=\int { {\left (2 \, c d x + b d\right )}^{\frac {5}{2}} {\left (c x^{2} + b x + a\right )}^{\frac {5}{2}} \,d x } \] Input:

integrate((2*c*d*x+b*d)^(5/2)*(c*x^2+b*x+a)^(5/2),x, algorithm="maxima")
 

Output:

integrate((2*c*d*x + b*d)^(5/2)*(c*x^2 + b*x + a)^(5/2), x)
 

Giac [F]

\[ \int (b d+2 c d x)^{5/2} \left (a+b x+c x^2\right )^{5/2} \, dx=\int { {\left (2 \, c d x + b d\right )}^{\frac {5}{2}} {\left (c x^{2} + b x + a\right )}^{\frac {5}{2}} \,d x } \] Input:

integrate((2*c*d*x+b*d)^(5/2)*(c*x^2+b*x+a)^(5/2),x, algorithm="giac")
 

Output:

integrate((2*c*d*x + b*d)^(5/2)*(c*x^2 + b*x + a)^(5/2), x)
 

Mupad [F(-1)]

Timed out. \[ \int (b d+2 c d x)^{5/2} \left (a+b x+c x^2\right )^{5/2} \, dx=\int {\left (b\,d+2\,c\,d\,x\right )}^{5/2}\,{\left (c\,x^2+b\,x+a\right )}^{5/2} \,d x \] Input:

int((b*d + 2*c*d*x)^(5/2)*(a + b*x + c*x^2)^(5/2),x)
 

Output:

int((b*d + 2*c*d*x)^(5/2)*(a + b*x + c*x^2)^(5/2), x)
 

Reduce [F]

\[ \int (b d+2 c d x)^{5/2} \left (a+b x+c x^2\right )^{5/2} \, dx =\text {Too large to display} \] Input:

int((2*c*d*x+b*d)^(5/2)*(c*x^2+b*x+a)^(5/2),x)
 

Output:

(sqrt(d)*d**2*( - 256*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*a**4*c**4 + 3 
84*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*a**3*b**2*c**3 + 256*sqrt(b + 2* 
c*x)*sqrt(a + b*x + c*x**2)*a**3*b*c**4*x + 164*sqrt(b + 2*c*x)*sqrt(a + b 
*x + c*x**2)*a**2*b**4*c**2 + 1944*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)* 
a**2*b**3*c**3*x + 4272*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*a**2*b**2*c 
**4*x**2 + 2848*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*a**2*b*c**5*x**3 - 
30*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*a*b**6*c + 60*sqrt(b + 2*c*x)*sq 
rt(a + b*x + c*x**2)*a*b**5*c**2*x + 2184*sqrt(b + 2*c*x)*sqrt(a + b*x + c 
*x**2)*a*b**4*c**3*x**2 + 7216*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*a*b* 
*3*c**4*x**3 + 8640*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*a*b**2*c**5*x** 
4 + 3456*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*a*b*c**6*x**5 + 2*sqrt(b + 
 2*c*x)*sqrt(a + b*x + c*x**2)*b**8 - 4*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x 
**2)*b**7*c*x + 6*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*b**6*c**2*x**2 + 
748*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*b**5*c**3*x**3 + 3300*sqrt(b + 
2*c*x)*sqrt(a + b*x + c*x**2)*b**4*c**4*x**4 + 5688*sqrt(b + 2*c*x)*sqrt(a 
 + b*x + c*x**2)*b**3*c**5*x**5 + 4368*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x* 
*2)*b**2*c**6*x**6 + 1248*sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*b*c**7*x* 
*7 + 768*int((sqrt(b + 2*c*x)*sqrt(a + b*x + c*x**2)*x**2)/(a*b + 2*a*c*x 
+ b**2*x + 3*b*c*x**2 + 2*c**2*x**3),x)*a**4*c**6 - 768*int((sqrt(b + 2*c* 
x)*sqrt(a + b*x + c*x**2)*x**2)/(a*b + 2*a*c*x + b**2*x + 3*b*c*x**2 + ...