Integrand size = 22, antiderivative size = 210 \[ \int \frac {1}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )^2} \, dx=\frac {\sqrt {1+2 x} (37+20 x)}{217 \left (2+3 x+5 x^2\right )}-\frac {1}{217} \sqrt {\frac {2}{217} \left (32678+10325 \sqrt {35}\right )} \arctan \left (\frac {\sqrt {10 \left (2+\sqrt {35}\right )}-10 \sqrt {1+2 x}}{\sqrt {10 \left (-2+\sqrt {35}\right )}}\right )+\frac {1}{217} \sqrt {\frac {2}{217} \left (32678+10325 \sqrt {35}\right )} \arctan \left (\frac {\sqrt {10 \left (2+\sqrt {35}\right )}+10 \sqrt {1+2 x}}{\sqrt {10 \left (-2+\sqrt {35}\right )}}\right )+\frac {1}{217} \sqrt {\frac {2}{217} \left (-32678+10325 \sqrt {35}\right )} \text {arctanh}\left (\frac {\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {1+2 x}}{5+\sqrt {35}+10 x}\right ) \] Output:
(1+2*x)^(1/2)*(37+20*x)/(1085*x^2+651*x+434)-1/47089*(14182252+4481050*35^ (1/2))^(1/2)*arctan(((20+10*35^(1/2))^(1/2)-10*(1+2*x)^(1/2))/(-20+10*35^( 1/2))^(1/2))+1/47089*(14182252+4481050*35^(1/2))^(1/2)*arctan(((20+10*35^( 1/2))^(1/2)+10*(1+2*x)^(1/2))/(-20+10*35^(1/2))^(1/2))+1/47089*(-14182252+ 4481050*35^(1/2))^(1/2)*arctanh((20+10*35^(1/2))^(1/2)*(1+2*x)^(1/2)/(5+35 ^(1/2)+10*x))
Result contains complex when optimal does not.
Time = 0.78 (sec) , antiderivative size = 129, normalized size of antiderivative = 0.61 \[ \int \frac {1}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )^2} \, dx=\frac {2 \left (\frac {217 \sqrt {1+2 x} (37+20 x)}{4+6 x+10 x^2}+\sqrt {217 \left (32678+9269 i \sqrt {31}\right )} \arctan \left (\sqrt {\frac {1}{7} \left (-2-i \sqrt {31}\right )} \sqrt {1+2 x}\right )+\sqrt {217 \left (32678-9269 i \sqrt {31}\right )} \arctan \left (\sqrt {\frac {1}{7} i \left (2 i+\sqrt {31}\right )} \sqrt {1+2 x}\right )\right )}{47089} \] Input:
Integrate[1/(Sqrt[1 + 2*x]*(2 + 3*x + 5*x^2)^2),x]
Output:
(2*((217*Sqrt[1 + 2*x]*(37 + 20*x))/(4 + 6*x + 10*x^2) + Sqrt[217*(32678 + (9269*I)*Sqrt[31])]*ArcTan[Sqrt[(-2 - I*Sqrt[31])/7]*Sqrt[1 + 2*x]] + Sqr t[217*(32678 - (9269*I)*Sqrt[31])]*ArcTan[Sqrt[(I/7)*(2*I + Sqrt[31])]*Sqr t[1 + 2*x]]))/47089
Time = 0.54 (sec) , antiderivative size = 315, normalized size of antiderivative = 1.50, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.455, Rules used = {1165, 1197, 27, 1483, 27, 1142, 25, 1083, 217, 1103}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {1}{\sqrt {2 x+1} \left (5 x^2+3 x+2\right )^2} \, dx\) |
| \(\Big \downarrow \) 1165 |
| \(\displaystyle \frac {1}{217} \int \frac {20 x+107}{\sqrt {2 x+1} \left (5 x^2+3 x+2\right )}dx+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
| \(\Big \downarrow \) 1197 |
| \(\displaystyle \frac {2}{217} \int \frac {2 (10 (2 x+1)+97)}{5 (2 x+1)^2-4 (2 x+1)+7}d\sqrt {2 x+1}+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {4}{217} \int \frac {10 (2 x+1)+97}{5 (2 x+1)^2-4 (2 x+1)+7}d\sqrt {2 x+1}+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
| \(\Big \downarrow \) 1483 |
| \(\displaystyle \frac {4}{217} \left (\frac {\int \frac {5 \left (97 \sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}-\left (97-2 \sqrt {35}\right ) \sqrt {2 x+1}\right )}{5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}+\frac {\int \frac {5 \left (\left (97-2 \sqrt {35}\right ) \sqrt {2 x+1}+97 \sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}\right )}{5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}\right )+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {4}{217} \left (\frac {5 \int \frac {97 \sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}-\left (97-2 \sqrt {35}\right ) \sqrt {2 x+1}}{5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}+\frac {5 \int \frac {\left (97-2 \sqrt {35}\right ) \sqrt {2 x+1}+97 \sqrt {\frac {2}{5} \left (2+\sqrt {35}\right )}}{5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}\right )+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
| \(\Big \downarrow \) 1142 |
| \(\displaystyle \frac {4}{217} \left (\frac {5 \left (\frac {1}{10} \sqrt {326780+103250 \sqrt {35}} \int \frac {1}{5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}-\frac {1}{10} \left (97-2 \sqrt {35}\right ) \int -\frac {\sqrt {10 \left (2+\sqrt {35}\right )}-10 \sqrt {2 x+1}}{5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}+\frac {5 \left (\frac {1}{10} \sqrt {326780+103250 \sqrt {35}} \int \frac {1}{5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}+\frac {1}{10} \left (97-2 \sqrt {35}\right ) \int \frac {10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}}{5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}\right )+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle \frac {4}{217} \left (\frac {5 \left (\frac {1}{10} \sqrt {326780+103250 \sqrt {35}} \int \frac {1}{5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}+\frac {1}{10} \left (97-2 \sqrt {35}\right ) \int \frac {\sqrt {10 \left (2+\sqrt {35}\right )}-10 \sqrt {2 x+1}}{5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}+\frac {5 \left (\frac {1}{10} \sqrt {326780+103250 \sqrt {35}} \int \frac {1}{5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}+\frac {1}{10} \left (97-2 \sqrt {35}\right ) \int \frac {10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}}{5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}\right )+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
| \(\Big \downarrow \) 1083 |
| \(\displaystyle \frac {4}{217} \left (\frac {5 \left (\frac {1}{10} \left (97-2 \sqrt {35}\right ) \int \frac {\sqrt {10 \left (2+\sqrt {35}\right )}-10 \sqrt {2 x+1}}{5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}-\frac {1}{5} \sqrt {326780+103250 \sqrt {35}} \int \frac {1}{-2 x+10 \left (2-\sqrt {35}\right )-1}d\left (10 \sqrt {2 x+1}-\sqrt {10 \left (2+\sqrt {35}\right )}\right )\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}+\frac {5 \left (\frac {1}{10} \left (97-2 \sqrt {35}\right ) \int \frac {10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}}{5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}-\frac {1}{5} \sqrt {326780+103250 \sqrt {35}} \int \frac {1}{-2 x+10 \left (2-\sqrt {35}\right )-1}d\left (10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}\right )\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}\right )+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
| \(\Big \downarrow \) 217 |
| \(\displaystyle \frac {4}{217} \left (\frac {5 \left (\frac {1}{10} \left (97-2 \sqrt {35}\right ) \int \frac {\sqrt {10 \left (2+\sqrt {35}\right )}-10 \sqrt {2 x+1}}{5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}+\frac {1}{5} \sqrt {\frac {326780+103250 \sqrt {35}}{10 \left (\sqrt {35}-2\right )}} \arctan \left (\frac {10 \sqrt {2 x+1}-\sqrt {10 \left (2+\sqrt {35}\right )}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right )\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}+\frac {5 \left (\frac {1}{10} \left (97-2 \sqrt {35}\right ) \int \frac {10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}}{5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}}d\sqrt {2 x+1}+\frac {1}{5} \sqrt {\frac {326780+103250 \sqrt {35}}{10 \left (\sqrt {35}-2\right )}} \arctan \left (\frac {10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right )\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}\right )+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
| \(\Big \downarrow \) 1103 |
| \(\displaystyle \frac {4}{217} \left (\frac {5 \left (\frac {1}{5} \sqrt {\frac {326780+103250 \sqrt {35}}{10 \left (\sqrt {35}-2\right )}} \arctan \left (\frac {10 \sqrt {2 x+1}-\sqrt {10 \left (2+\sqrt {35}\right )}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right )-\frac {1}{10} \left (97-2 \sqrt {35}\right ) \log \left (5 (2 x+1)-\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}\right )\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}+\frac {5 \left (\frac {1}{5} \sqrt {\frac {326780+103250 \sqrt {35}}{10 \left (\sqrt {35}-2\right )}} \arctan \left (\frac {10 \sqrt {2 x+1}+\sqrt {10 \left (2+\sqrt {35}\right )}}{\sqrt {10 \left (\sqrt {35}-2\right )}}\right )+\frac {1}{10} \left (97-2 \sqrt {35}\right ) \log \left (5 (2 x+1)+\sqrt {10 \left (2+\sqrt {35}\right )} \sqrt {2 x+1}+\sqrt {35}\right )\right )}{2 \sqrt {14 \left (2+\sqrt {35}\right )}}\right )+\frac {\sqrt {2 x+1} (20 x+37)}{217 \left (5 x^2+3 x+2\right )}\) |
Input:
Int[1/(Sqrt[1 + 2*x]*(2 + 3*x + 5*x^2)^2),x]
Output:
(Sqrt[1 + 2*x]*(37 + 20*x))/(217*(2 + 3*x + 5*x^2)) + (4*((5*((Sqrt[(32678 0 + 103250*Sqrt[35])/(10*(-2 + Sqrt[35]))]*ArcTan[(-Sqrt[10*(2 + Sqrt[35]) ] + 10*Sqrt[1 + 2*x])/Sqrt[10*(-2 + Sqrt[35])]])/5 - ((97 - 2*Sqrt[35])*Lo g[Sqrt[35] - Sqrt[10*(2 + Sqrt[35])]*Sqrt[1 + 2*x] + 5*(1 + 2*x)])/10))/(2 *Sqrt[14*(2 + Sqrt[35])]) + (5*((Sqrt[(326780 + 103250*Sqrt[35])/(10*(-2 + Sqrt[35]))]*ArcTan[(Sqrt[10*(2 + Sqrt[35])] + 10*Sqrt[1 + 2*x])/Sqrt[10*( -2 + Sqrt[35])]])/5 + ((97 - 2*Sqrt[35])*Log[Sqrt[35] + Sqrt[10*(2 + Sqrt[ 35])]*Sqrt[1 + 2*x] + 5*(1 + 2*x)])/10))/(2*Sqrt[14*(2 + Sqrt[35])])))/217
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Simp[-2 Subst[I nt[1/Simp[b^2 - 4*a*c - x^2, x], x], x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x]
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]
Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[(2*c*d - b*e)/(2*c) Int[1/(a + b*x + c*x^2), x], x] + Simp[e/(2*c) Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x]
Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_S ymbol] :> Simp[(d + e*x)^(m + 1)*(b*c*d - b^2*e + 2*a*c*e + c*(2*c*d - b*e) *x)*((a + b*x + c*x^2)^(p + 1)/((p + 1)*(b^2 - 4*a*c)*(c*d^2 - b*d*e + a*e^ 2))), x] + Simp[1/((p + 1)*(b^2 - 4*a*c)*(c*d^2 - b*d*e + a*e^2)) Int[(d + e*x)^m*Simp[b*c*d*e*(2*p - m + 2) + b^2*e^2*(m + p + 2) - 2*c^2*d^2*(2*p + 3) - 2*a*c*e^2*(m + 2*p + 3) - c*e*(2*c*d - b*e)*(m + 2*p + 4)*x, x]*(a + b*x + c*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, m}, x] && LtQ[p, -1] && IntQuadraticQ[a, b, c, d, e, m, p, x]
Int[((f_.) + (g_.)*(x_))/(Sqrt[(d_.) + (e_.)*(x_)]*((a_.) + (b_.)*(x_) + (c _.)*(x_)^2)), x_Symbol] :> Simp[2 Subst[Int[(e*f - d*g + g*x^2)/(c*d^2 - b*d*e + a*e^2 - (2*c*d - b*e)*x^2 + c*x^4), x], x, Sqrt[d + e*x]], x] /; Fr eeQ[{a, b, c, d, e, f, g}, x]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4), x_Symbol] : > With[{q = Rt[a/c, 2]}, With[{r = Rt[2*q - b/c, 2]}, Simp[1/(2*c*q*r) In t[(d*r - (d - e*q)*x)/(q - r*x + x^2), x], x] + Simp[1/(2*c*q*r) Int[(d*r + (d - e*q)*x)/(q + r*x + x^2), x], x]]] /; FreeQ[{a, b, c, d, e}, x] && N eQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NegQ[b^2 - 4*a*c]
Time = 2.56 (sec) , antiderivative size = 249, normalized size of antiderivative = 1.19
| method | result | size |
| pseudoelliptic | \(-\frac {5 \left (-3472 \left (x +\frac {37}{20}\right ) \left (\sqrt {5}-\frac {5 \sqrt {7}}{2}\right ) \sqrt {10 \sqrt {5}\, \sqrt {7}-20}\, \sqrt {1+2 x}+\left (x^{2}+\frac {3}{5} x +\frac {2}{5}\right ) \left (\sqrt {10 \sqrt {5}\, \sqrt {7}-20}\, \left (4063 \sqrt {5}\, \sqrt {7}-16310\right ) \left (\ln \left (\sqrt {35}+5+10 x +\sqrt {1+2 x}\, \sqrt {20+10 \sqrt {35}}\right )-\ln \left (\sqrt {35}+5+10 x -\sqrt {1+2 x}\, \sqrt {20+10 \sqrt {35}}\right )\right ) \sqrt {2 \sqrt {5}\, \sqrt {7}+4}-403620 \left (\arctan \left (\frac {\sqrt {20+10 \sqrt {35}}-10 \sqrt {1+2 x}}{\sqrt {-20+10 \sqrt {35}}}\right )-\arctan \left (\frac {\sqrt {20+10 \sqrt {35}}+10 \sqrt {1+2 x}}{\sqrt {-20+10 \sqrt {35}}}\right )\right ) \left (\sqrt {5}-\frac {4 \sqrt {7}}{21}\right )\right )\right )}{94178 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}\, \left (2 \sqrt {5}-5 \sqrt {7}\right ) \left (5 x^{2}+3 x +2\right )}\) | \(249\) |
| trager | \(\frac {\sqrt {1+2 x}\, \left (37+20 x \right )}{1085 x^{2}+651 x +434}+\frac {2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+47089 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2}+3545563\right ) \ln \left (-\frac {4090016 \operatorname {RootOf}\left (\textit {\_Z}^{2}+47089 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2}+3545563\right ) \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{4} x +811021752 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2} \operatorname {RootOf}\left (\textit {\_Z}^{2}+47089 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2}+3545563\right ) x +349404224 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2} \operatorname {RootOf}\left (\textit {\_Z}^{2}+47089 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2}+3545563\right )-118853577780 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2} \sqrt {1+2 x}+39486839140 \operatorname {RootOf}\left (\textit {\_Z}^{2}+47089 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2}+3545563\right ) x +30012280480 \operatorname {RootOf}\left (\textit {\_Z}^{2}+47089 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2}+3545563\right )+54331101492115 \sqrt {1+2 x}}{868 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2} x +4871 x -37076}\right )}{47089}+\frac {2 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right ) \ln \left (-\frac {28630112 x \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{5}-1365747656 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{3} x -2445829568 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{3}+3833986380 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2} \sqrt {1+2 x}+11260542660 x \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )+25927395104 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )+2041295916625 \sqrt {1+2 x}}{868 \operatorname {RootOf}\left (107632 \textit {\_Z}^{4}+8104144 \textit {\_Z}^{2}+533028125\right )^{2} x +60485 x +37076}\right )}{217}\) | \(449\) |
| derivativedivides | \(\frac {\frac {2 \left (-3244150 \sqrt {5}\, \sqrt {7}+6488300\right ) \sqrt {5}\, \sqrt {1+2 x}}{351990275 \left (2 \sqrt {5}-5 \sqrt {7}\right )}+\frac {5 \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \left (-1946490 \sqrt {5}\, \sqrt {7}+13949845\right )}{47089 \left (14950 \sqrt {5}-37375 \sqrt {7}\right )}}{\frac {\sqrt {5}\, \sqrt {7}}{5}+1+2 x +\frac {\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}}{5}}+\frac {\frac {\left (-4063 \sqrt {2 \sqrt {35}+4}\, \sqrt {35}+16310 \sqrt {2 \sqrt {35}+4}\right ) \ln \left (\sqrt {35}+5+10 x +\sqrt {1+2 x}\, \sqrt {20+10 \sqrt {35}}\right )}{94178}+\frac {10 \left (-42098 \sqrt {5}+12028 \sqrt {7}-\frac {\left (-4063 \sqrt {2 \sqrt {35}+4}\, \sqrt {35}+16310 \sqrt {2 \sqrt {35}+4}\right ) \sqrt {20+10 \sqrt {35}}}{10}\right ) \arctan \left (\frac {\sqrt {20+10 \sqrt {35}}+10 \sqrt {1+2 x}}{\sqrt {-20+10 \sqrt {35}}}\right )}{47089 \sqrt {-20+10 \sqrt {35}}}}{2 \sqrt {5}-5 \sqrt {7}}+\frac {\frac {2 \left (-3244150 \sqrt {5}\, \sqrt {7}+6488300\right ) \sqrt {5}\, \sqrt {1+2 x}}{351990275 \left (2 \sqrt {5}-5 \sqrt {7}\right )}-\frac {\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \left (-1946490 \sqrt {5}\, \sqrt {7}+13949845\right )}{70398055 \left (2 \sqrt {5}-5 \sqrt {7}\right )}}{\frac {\sqrt {5}\, \sqrt {7}}{5}+1+2 x -\frac {\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}}{5}}+\frac {-\frac {\left (-4063 \sqrt {2 \sqrt {35}+4}\, \sqrt {35}+16310 \sqrt {2 \sqrt {35}+4}\right ) \ln \left (\sqrt {35}+5+10 x -\sqrt {1+2 x}\, \sqrt {20+10 \sqrt {35}}\right )}{94178}-\frac {10 \left (42098 \sqrt {5}-12028 \sqrt {7}+\frac {\left (-4063 \sqrt {2 \sqrt {35}+4}\, \sqrt {35}+16310 \sqrt {2 \sqrt {35}+4}\right ) \sqrt {20+10 \sqrt {35}}}{10}\right ) \arctan \left (\frac {10 \sqrt {1+2 x}-\sqrt {20+10 \sqrt {35}}}{\sqrt {-20+10 \sqrt {35}}}\right )}{47089 \sqrt {-20+10 \sqrt {35}}}}{2 \sqrt {5}-5 \sqrt {7}}\) | \(551\) |
| default | \(\frac {\frac {2 \left (-3244150 \sqrt {5}\, \sqrt {7}+6488300\right ) \sqrt {5}\, \sqrt {1+2 x}}{351990275 \left (2 \sqrt {5}-5 \sqrt {7}\right )}+\frac {5 \sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \left (-1946490 \sqrt {5}\, \sqrt {7}+13949845\right )}{47089 \left (14950 \sqrt {5}-37375 \sqrt {7}\right )}}{\frac {\sqrt {5}\, \sqrt {7}}{5}+1+2 x +\frac {\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}}{5}}+\frac {\frac {\left (-4063 \sqrt {2 \sqrt {35}+4}\, \sqrt {35}+16310 \sqrt {2 \sqrt {35}+4}\right ) \ln \left (\sqrt {35}+5+10 x +\sqrt {1+2 x}\, \sqrt {20+10 \sqrt {35}}\right )}{94178}+\frac {10 \left (-42098 \sqrt {5}+12028 \sqrt {7}-\frac {\left (-4063 \sqrt {2 \sqrt {35}+4}\, \sqrt {35}+16310 \sqrt {2 \sqrt {35}+4}\right ) \sqrt {20+10 \sqrt {35}}}{10}\right ) \arctan \left (\frac {\sqrt {20+10 \sqrt {35}}+10 \sqrt {1+2 x}}{\sqrt {-20+10 \sqrt {35}}}\right )}{47089 \sqrt {-20+10 \sqrt {35}}}}{2 \sqrt {5}-5 \sqrt {7}}+\frac {\frac {2 \left (-3244150 \sqrt {5}\, \sqrt {7}+6488300\right ) \sqrt {5}\, \sqrt {1+2 x}}{351990275 \left (2 \sqrt {5}-5 \sqrt {7}\right )}-\frac {\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \left (-1946490 \sqrt {5}\, \sqrt {7}+13949845\right )}{70398055 \left (2 \sqrt {5}-5 \sqrt {7}\right )}}{\frac {\sqrt {5}\, \sqrt {7}}{5}+1+2 x -\frac {\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}}{5}}+\frac {-\frac {\left (-4063 \sqrt {2 \sqrt {35}+4}\, \sqrt {35}+16310 \sqrt {2 \sqrt {35}+4}\right ) \ln \left (\sqrt {35}+5+10 x -\sqrt {1+2 x}\, \sqrt {20+10 \sqrt {35}}\right )}{94178}-\frac {10 \left (42098 \sqrt {5}-12028 \sqrt {7}+\frac {\left (-4063 \sqrt {2 \sqrt {35}+4}\, \sqrt {35}+16310 \sqrt {2 \sqrt {35}+4}\right ) \sqrt {20+10 \sqrt {35}}}{10}\right ) \arctan \left (\frac {10 \sqrt {1+2 x}-\sqrt {20+10 \sqrt {35}}}{\sqrt {-20+10 \sqrt {35}}}\right )}{47089 \sqrt {-20+10 \sqrt {35}}}}{2 \sqrt {5}-5 \sqrt {7}}\) | \(551\) |
| risch | \(\frac {\sqrt {1+2 x}\, \left (37+20 x \right )}{1085 x^{2}+651 x +434}-\frac {101 \ln \left (-\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+\sqrt {5}\, \sqrt {7}+5+10 x \right ) \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{13454}+\frac {132 \ln \left (-\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+\sqrt {5}\, \sqrt {7}+5+10 x \right ) \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{47089}-\frac {505 \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \left (2 \sqrt {5}\, \sqrt {7}+4\right )}{6727 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {264 \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \sqrt {5}\, \left (2 \sqrt {5}\, \sqrt {7}+4\right ) \sqrt {7}}{47089 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {388 \arctan \left (\frac {-\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \sqrt {5}\, \sqrt {7}}{1519 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {101 \ln \left (\sqrt {5}\, \sqrt {7}+\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right ) \sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{13454}-\frac {132 \ln \left (\sqrt {5}\, \sqrt {7}+\sqrt {2 \sqrt {5}\, \sqrt {7}+4}\, \sqrt {5}\, \sqrt {1+2 x}+5+10 x \right ) \sqrt {7}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}}{47089}-\frac {505 \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \left (2 \sqrt {5}\, \sqrt {7}+4\right )}{6727 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {264 \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \sqrt {5}\, \left (2 \sqrt {5}\, \sqrt {7}+4\right ) \sqrt {7}}{47089 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}+\frac {388 \arctan \left (\frac {\sqrt {5}\, \sqrt {2 \sqrt {5}\, \sqrt {7}+4}+10 \sqrt {1+2 x}}{\sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\right ) \sqrt {5}\, \sqrt {7}}{1519 \sqrt {10 \sqrt {5}\, \sqrt {7}-20}}\) | \(633\) |
Input:
int(1/(1+2*x)^(1/2)/(5*x^2+3*x+2)^2,x,method=_RETURNVERBOSE)
Output:
-5/94178*(-3472*(x+37/20)*(5^(1/2)-5/2*7^(1/2))*(10*5^(1/2)*7^(1/2)-20)^(1 /2)*(1+2*x)^(1/2)+(x^2+3/5*x+2/5)*((10*5^(1/2)*7^(1/2)-20)^(1/2)*(4063*5^( 1/2)*7^(1/2)-16310)*(ln(35^(1/2)+5+10*x+(1+2*x)^(1/2)*(20+10*35^(1/2))^(1/ 2))-ln(35^(1/2)+5+10*x-(1+2*x)^(1/2)*(20+10*35^(1/2))^(1/2)))*(2*5^(1/2)*7 ^(1/2)+4)^(1/2)-403620*(arctan(((20+10*35^(1/2))^(1/2)-10*(1+2*x)^(1/2))/( -20+10*35^(1/2))^(1/2))-arctan(((20+10*35^(1/2))^(1/2)+10*(1+2*x)^(1/2))/( -20+10*35^(1/2))^(1/2)))*(5^(1/2)-4/21*7^(1/2))))/(10*5^(1/2)*7^(1/2)-20)^ (1/2)/(2*5^(1/2)-5*7^(1/2))/(5*x^2+3*x+2)
Time = 0.09 (sec) , antiderivative size = 274, normalized size of antiderivative = 1.30 \[ \int \frac {1}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )^2} \, dx=\frac {2 \, {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} + \frac {16339}{217}} \arctan \left (\frac {14}{9269} \, {\left (\sqrt {2 \, x + 1} {\left (97 \, \sqrt {\frac {5}{7}} - 10\right )} + \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} - \frac {16339}{217}} {\left (7 \, \sqrt {\frac {5}{7}} + 2\right )}\right )} \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} + \frac {16339}{217}}\right ) - 2 \, {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} + \frac {16339}{217}} \arctan \left (-\frac {14}{9269} \, {\left (\sqrt {2 \, x + 1} {\left (97 \, \sqrt {\frac {5}{7}} - 10\right )} - \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} - \frac {16339}{217}} {\left (7 \, \sqrt {\frac {5}{7}} + 2\right )}\right )} \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} + \frac {16339}{217}}\right ) + {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} - \frac {16339}{217}} \log \left (14 \, \sqrt {2 \, x + 1} {\left (264 \, \sqrt {\frac {5}{7}} + 505\right )} \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} - \frac {16339}{217}} + 92690 \, x + 64883 \, \sqrt {\frac {5}{7}} + 46345\right ) - {\left (5 \, x^{2} + 3 \, x + 2\right )} \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} - \frac {16339}{217}} \log \left (-14 \, \sqrt {2 \, x + 1} {\left (264 \, \sqrt {\frac {5}{7}} + 505\right )} \sqrt {\frac {10325}{62} \, \sqrt {\frac {5}{7}} - \frac {16339}{217}} + 92690 \, x + 64883 \, \sqrt {\frac {5}{7}} + 46345\right ) + {\left (20 \, x + 37\right )} \sqrt {2 \, x + 1}}{217 \, {\left (5 \, x^{2} + 3 \, x + 2\right )}} \] Input:
integrate(1/(1+2*x)^(1/2)/(5*x^2+3*x+2)^2,x, algorithm="fricas")
Output:
1/217*(2*(5*x^2 + 3*x + 2)*sqrt(10325/62*sqrt(5/7) + 16339/217)*arctan(14/ 9269*(sqrt(2*x + 1)*(97*sqrt(5/7) - 10) + sqrt(10325/62*sqrt(5/7) - 16339/ 217)*(7*sqrt(5/7) + 2))*sqrt(10325/62*sqrt(5/7) + 16339/217)) - 2*(5*x^2 + 3*x + 2)*sqrt(10325/62*sqrt(5/7) + 16339/217)*arctan(-14/9269*(sqrt(2*x + 1)*(97*sqrt(5/7) - 10) - sqrt(10325/62*sqrt(5/7) - 16339/217)*(7*sqrt(5/7 ) + 2))*sqrt(10325/62*sqrt(5/7) + 16339/217)) + (5*x^2 + 3*x + 2)*sqrt(103 25/62*sqrt(5/7) - 16339/217)*log(14*sqrt(2*x + 1)*(264*sqrt(5/7) + 505)*sq rt(10325/62*sqrt(5/7) - 16339/217) + 92690*x + 64883*sqrt(5/7) + 46345) - (5*x^2 + 3*x + 2)*sqrt(10325/62*sqrt(5/7) - 16339/217)*log(-14*sqrt(2*x + 1)*(264*sqrt(5/7) + 505)*sqrt(10325/62*sqrt(5/7) - 16339/217) + 92690*x + 64883*sqrt(5/7) + 46345) + (20*x + 37)*sqrt(2*x + 1))/(5*x^2 + 3*x + 2)
\[ \int \frac {1}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )^2} \, dx=\int \frac {1}{\sqrt {2 x + 1} \left (5 x^{2} + 3 x + 2\right )^{2}}\, dx \] Input:
integrate(1/(1+2*x)**(1/2)/(5*x**2+3*x+2)**2,x)
Output:
Integral(1/(sqrt(2*x + 1)*(5*x**2 + 3*x + 2)**2), x)
\[ \int \frac {1}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )^2} \, dx=\int { \frac {1}{{\left (5 \, x^{2} + 3 \, x + 2\right )}^{2} \sqrt {2 \, x + 1}} \,d x } \] Input:
integrate(1/(1+2*x)^(1/2)/(5*x^2+3*x+2)^2,x, algorithm="maxima")
Output:
integrate(1/((5*x^2 + 3*x + 2)^2*sqrt(2*x + 1)), x)
Leaf count of result is larger than twice the leaf count of optimal. 622 vs. \(2 (151) = 302\).
Time = 0.55 (sec) , antiderivative size = 622, normalized size of antiderivative = 2.96 \[ \int \frac {1}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )^2} \, dx=\text {Too large to display} \] Input:
integrate(1/(1+2*x)^(1/2)/(5*x^2+3*x+2)^2,x, algorithm="giac")
Output:
1/807576350*sqrt(31)*(210*sqrt(31)*(7/5)^(3/4)*(2*sqrt(35) + 35)*sqrt(-140 *sqrt(35) + 2450) - sqrt(31)*(7/5)^(3/4)*(-140*sqrt(35) + 2450)^(3/2) + 2* (7/5)^(3/4)*(140*sqrt(35) + 2450)^(3/2) + 420*(7/5)^(3/4)*sqrt(140*sqrt(35 ) + 2450)*(2*sqrt(35) - 35) + 47530*sqrt(31)*(7/5)^(1/4)*sqrt(-140*sqrt(35 ) + 2450) + 95060*(7/5)^(1/4)*sqrt(140*sqrt(35) + 2450))*arctan(5/7*(7/5)^ (3/4)*((7/5)^(1/4)*sqrt(1/35*sqrt(35) + 1/2) + sqrt(2*x + 1))/sqrt(-1/35*s qrt(35) + 1/2)) + 1/807576350*sqrt(31)*(210*sqrt(31)*(7/5)^(3/4)*(2*sqrt(3 5) + 35)*sqrt(-140*sqrt(35) + 2450) - sqrt(31)*(7/5)^(3/4)*(-140*sqrt(35) + 2450)^(3/2) + 2*(7/5)^(3/4)*(140*sqrt(35) + 2450)^(3/2) + 420*(7/5)^(3/4 )*sqrt(140*sqrt(35) + 2450)*(2*sqrt(35) - 35) + 47530*sqrt(31)*(7/5)^(1/4) *sqrt(-140*sqrt(35) + 2450) + 95060*(7/5)^(1/4)*sqrt(140*sqrt(35) + 2450)) *arctan(-5/7*(7/5)^(3/4)*((7/5)^(1/4)*sqrt(1/35*sqrt(35) + 1/2) - sqrt(2*x + 1))/sqrt(-1/35*sqrt(35) + 1/2)) + 1/1615152700*sqrt(31)*(sqrt(31)*(7/5) ^(3/4)*(140*sqrt(35) + 2450)^(3/2) + 210*sqrt(31)*(7/5)^(3/4)*sqrt(140*sqr t(35) + 2450)*(2*sqrt(35) - 35) - 420*(7/5)^(3/4)*(2*sqrt(35) + 35)*sqrt(- 140*sqrt(35) + 2450) + 2*(7/5)^(3/4)*(-140*sqrt(35) + 2450)^(3/2) + 47530* sqrt(31)*(7/5)^(1/4)*sqrt(140*sqrt(35) + 2450) - 95060*(7/5)^(1/4)*sqrt(-1 40*sqrt(35) + 2450))*log(2*(7/5)^(1/4)*sqrt(2*x + 1)*sqrt(1/35*sqrt(35) + 1/2) + 2*x + sqrt(7/5) + 1) - 1/1615152700*sqrt(31)*(sqrt(31)*(7/5)^(3/4)* (140*sqrt(35) + 2450)^(3/2) + 210*sqrt(31)*(7/5)^(3/4)*sqrt(140*sqrt(35...
Time = 5.73 (sec) , antiderivative size = 207, normalized size of antiderivative = 0.99 \[ \int \frac {1}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )^2} \, dx=\frac {\frac {108\,\sqrt {2\,x+1}}{1085}+\frac {8\,{\left (2\,x+1\right )}^{3/2}}{217}}{{\left (2\,x+1\right )}^2-\frac {8\,x}{5}+\frac {3}{5}}+\frac {\sqrt {217}\,\mathrm {atan}\left (\frac {\sqrt {217}\,\sqrt {-32678-\sqrt {31}\,9269{}\mathrm {i}}\,\sqrt {2\,x+1}\,38272{}\mathrm {i}}{2018940875\,\left (\frac {10103808}{288420125}+\frac {\sqrt {31}\,3712384{}\mathrm {i}}{288420125}\right )}+\frac {76544\,\sqrt {31}\,\sqrt {217}\,\sqrt {-32678-\sqrt {31}\,9269{}\mathrm {i}}\,\sqrt {2\,x+1}}{62587167125\,\left (\frac {10103808}{288420125}+\frac {\sqrt {31}\,3712384{}\mathrm {i}}{288420125}\right )}\right )\,\sqrt {-32678-\sqrt {31}\,9269{}\mathrm {i}}\,2{}\mathrm {i}}{47089}-\frac {\sqrt {217}\,\mathrm {atan}\left (\frac {\sqrt {217}\,\sqrt {-32678+\sqrt {31}\,9269{}\mathrm {i}}\,\sqrt {2\,x+1}\,38272{}\mathrm {i}}{2018940875\,\left (-\frac {10103808}{288420125}+\frac {\sqrt {31}\,3712384{}\mathrm {i}}{288420125}\right )}-\frac {76544\,\sqrt {31}\,\sqrt {217}\,\sqrt {-32678+\sqrt {31}\,9269{}\mathrm {i}}\,\sqrt {2\,x+1}}{62587167125\,\left (-\frac {10103808}{288420125}+\frac {\sqrt {31}\,3712384{}\mathrm {i}}{288420125}\right )}\right )\,\sqrt {-32678+\sqrt {31}\,9269{}\mathrm {i}}\,2{}\mathrm {i}}{47089} \] Input:
int(1/((2*x + 1)^(1/2)*(3*x + 5*x^2 + 2)^2),x)
Output:
((108*(2*x + 1)^(1/2))/1085 + (8*(2*x + 1)^(3/2))/217)/((2*x + 1)^2 - (8*x )/5 + 3/5) + (217^(1/2)*atan((217^(1/2)*(- 31^(1/2)*9269i - 32678)^(1/2)*( 2*x + 1)^(1/2)*38272i)/(2018940875*((31^(1/2)*3712384i)/288420125 + 101038 08/288420125)) + (76544*31^(1/2)*217^(1/2)*(- 31^(1/2)*9269i - 32678)^(1/2 )*(2*x + 1)^(1/2))/(62587167125*((31^(1/2)*3712384i)/288420125 + 10103808/ 288420125)))*(- 31^(1/2)*9269i - 32678)^(1/2)*2i)/47089 - (217^(1/2)*atan( (217^(1/2)*(31^(1/2)*9269i - 32678)^(1/2)*(2*x + 1)^(1/2)*38272i)/(2018940 875*((31^(1/2)*3712384i)/288420125 - 10103808/288420125)) - (76544*31^(1/2 )*217^(1/2)*(31^(1/2)*9269i - 32678)^(1/2)*(2*x + 1)^(1/2))/(62587167125*( (31^(1/2)*3712384i)/288420125 - 10103808/288420125)))*(31^(1/2)*9269i - 32 678)^(1/2)*2i)/47089
Time = 0.22 (sec) , antiderivative size = 969, normalized size of antiderivative = 4.61 \[ \int \frac {1}{\sqrt {1+2 x} \left (2+3 x+5 x^2\right )^2} \, dx =\text {Too large to display} \] Input:
int(1/(1+2*x)^(1/2)/(5*x^2+3*x+2)^2,x)
Output:
( - 2640*sqrt(sqrt(35) - 2)*sqrt(14)*atan((sqrt(sqrt(35) + 2)*sqrt(2) - 2* sqrt(2*x + 1)*sqrt(5))/(sqrt(sqrt(35) - 2)*sqrt(2)))*x**2 - 1584*sqrt(sqrt (35) - 2)*sqrt(14)*atan((sqrt(sqrt(35) + 2)*sqrt(2) - 2*sqrt(2*x + 1)*sqrt (5))/(sqrt(sqrt(35) - 2)*sqrt(2)))*x - 1056*sqrt(sqrt(35) - 2)*sqrt(14)*at an((sqrt(sqrt(35) + 2)*sqrt(2) - 2*sqrt(2*x + 1)*sqrt(5))/(sqrt(sqrt(35) - 2)*sqrt(2))) - 7070*sqrt(sqrt(35) - 2)*sqrt(10)*atan((sqrt(sqrt(35) + 2)* sqrt(2) - 2*sqrt(2*x + 1)*sqrt(5))/(sqrt(sqrt(35) - 2)*sqrt(2)))*x**2 - 42 42*sqrt(sqrt(35) - 2)*sqrt(10)*atan((sqrt(sqrt(35) + 2)*sqrt(2) - 2*sqrt(2 *x + 1)*sqrt(5))/(sqrt(sqrt(35) - 2)*sqrt(2)))*x - 2828*sqrt(sqrt(35) - 2) *sqrt(10)*atan((sqrt(sqrt(35) + 2)*sqrt(2) - 2*sqrt(2*x + 1)*sqrt(5))/(sqr t(sqrt(35) - 2)*sqrt(2))) + 2640*sqrt(sqrt(35) - 2)*sqrt(14)*atan((sqrt(sq rt(35) + 2)*sqrt(2) + 2*sqrt(2*x + 1)*sqrt(5))/(sqrt(sqrt(35) - 2)*sqrt(2) ))*x**2 + 1584*sqrt(sqrt(35) - 2)*sqrt(14)*atan((sqrt(sqrt(35) + 2)*sqrt(2 ) + 2*sqrt(2*x + 1)*sqrt(5))/(sqrt(sqrt(35) - 2)*sqrt(2)))*x + 1056*sqrt(s qrt(35) - 2)*sqrt(14)*atan((sqrt(sqrt(35) + 2)*sqrt(2) + 2*sqrt(2*x + 1)*s qrt(5))/(sqrt(sqrt(35) - 2)*sqrt(2))) + 7070*sqrt(sqrt(35) - 2)*sqrt(10)*a tan((sqrt(sqrt(35) + 2)*sqrt(2) + 2*sqrt(2*x + 1)*sqrt(5))/(sqrt(sqrt(35) - 2)*sqrt(2)))*x**2 + 4242*sqrt(sqrt(35) - 2)*sqrt(10)*atan((sqrt(sqrt(35) + 2)*sqrt(2) + 2*sqrt(2*x + 1)*sqrt(5))/(sqrt(sqrt(35) - 2)*sqrt(2)))*x + 2828*sqrt(sqrt(35) - 2)*sqrt(10)*atan((sqrt(sqrt(35) + 2)*sqrt(2) + 2*...