Integrand size = 22, antiderivative size = 108 \[ \int \frac {1}{(2+3 x) \sqrt [3]{52-54 x+27 x^2}} \, dx=-\frac {\arctan \left (\frac {1}{\sqrt {3}}+\frac {2^{2/3} (8-3 x)}{\sqrt {3} \sqrt [3]{5} \sqrt [3]{52-54 x+27 x^2}}\right )}{3 \sqrt {3} 10^{2/3}}-\frac {\log (2+3 x)}{6\ 10^{2/3}}+\frac {\log \left (216-81 x-27 \sqrt [3]{10} \sqrt [3]{52-54 x+27 x^2}\right )}{6\ 10^{2/3}} \] Output:
1/90*arctan(-1/3*3^(1/2)-1/15*2^(2/3)*(8-3*x)*3^(1/2)*5^(2/3)/(27*x^2-54*x +52)^(1/3))*3^(1/2)*10^(1/3)-1/60*ln(2+3*x)*10^(1/3)+1/60*ln(216-81*x-27*1 0^(1/3)*(27*x^2-54*x+52)^(1/3))*10^(1/3)
Time = 0.30 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.63 \[ \int \frac {1}{(2+3 x) \sqrt [3]{52-54 x+27 x^2}} \, dx=-\frac {2 \sqrt {3} \arctan \left (\frac {8\ 10^{2/3}-3\ 10^{2/3} x+5 \sqrt [3]{52-54 x+27 x^2}}{5 \sqrt {3} \sqrt [3]{52-54 x+27 x^2}}\right )-2 \log \left (-8 10^{2/3}+3\ 10^{2/3} x+10 \sqrt [3]{52-54 x+27 x^2}\right )+\log \left (-64 \sqrt [3]{10}+48 \sqrt [3]{10} x-9 \sqrt [3]{10} x^2+10^{2/3} (-8+3 x) \sqrt [3]{52-54 x+27 x^2}-10 \left (52-54 x+27 x^2\right )^{2/3}\right )}{18\ 10^{2/3}} \] Input:
Integrate[1/((2 + 3*x)*(52 - 54*x + 27*x^2)^(1/3)),x]
Output:
-1/18*(2*Sqrt[3]*ArcTan[(8*10^(2/3) - 3*10^(2/3)*x + 5*(52 - 54*x + 27*x^2 )^(1/3))/(5*Sqrt[3]*(52 - 54*x + 27*x^2)^(1/3))] - 2*Log[-8*10^(2/3) + 3*1 0^(2/3)*x + 10*(52 - 54*x + 27*x^2)^(1/3)] + Log[-64*10^(1/3) + 48*10^(1/3 )*x - 9*10^(1/3)*x^2 + 10^(2/3)*(-8 + 3*x)*(52 - 54*x + 27*x^2)^(1/3) - 10 *(52 - 54*x + 27*x^2)^(2/3)])/10^(2/3)
Time = 0.21 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {1175}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{(3 x+2) \sqrt [3]{27 x^2-54 x+52}} \, dx\) |
\(\Big \downarrow \) 1175 |
\(\displaystyle -\frac {\arctan \left (\frac {2^{2/3} (8-3 x)}{\sqrt {3} \sqrt [3]{5} \sqrt [3]{27 x^2-54 x+52}}+\frac {1}{\sqrt {3}}\right )}{3 \sqrt {3} 10^{2/3}}+\frac {\log \left (-27 \sqrt [3]{10} \sqrt [3]{27 x^2-54 x+52}-81 x+216\right )}{6\ 10^{2/3}}-\frac {\log (3 x+2)}{6\ 10^{2/3}}\) |
Input:
Int[1/((2 + 3*x)*(52 - 54*x + 27*x^2)^(1/3)),x]
Output:
-1/3*ArcTan[1/Sqrt[3] + (2^(2/3)*(8 - 3*x))/(Sqrt[3]*5^(1/3)*(52 - 54*x + 27*x^2)^(1/3))]/(Sqrt[3]*10^(2/3)) - Log[2 + 3*x]/(6*10^(2/3)) + Log[216 - 81*x - 27*10^(1/3)*(52 - 54*x + 27*x^2)^(1/3)]/(6*10^(2/3))
Int[1/(((d_.) + (e_.)*(x_))*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(1/3)), x_Sy mbol] :> With[{q = Rt[3*c*e^2*(2*c*d - b*e), 3]}, Simp[(-Sqrt[3])*c*e*(ArcT an[1/Sqrt[3] + 2*((c*d - b*e - c*e*x)/(Sqrt[3]*q*(a + b*x + c*x^2)^(1/3)))] /q^2), x] + (-Simp[3*c*e*(Log[d + e*x]/(2*q^2)), x] + Simp[3*c*e*(Log[c*d - b*e - c*e*x - q*(a + b*x + c*x^2)^(1/3)]/(2*q^2)), x])] /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d^2 - b*c*d*e + b^2*e^2 - 3*a*c*e^2, 0] && PosQ[c*e^2 *(2*c*d - b*e)]
Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 17.14 (sec) , antiderivative size = 2201, normalized size of antiderivative = 20.38
Input:
int(1/(3*x+2)/(27*x^2-54*x+52)^(1/3),x,method=_RETURNVERBOSE)
Output:
1/3*RootOf(RootOf(_Z^3-10)^2+30*_Z*RootOf(_Z^3-10)+900*_Z^2)*ln(-(12013105 49293725*RootOf(RootOf(_Z^3-10)^2+30*_Z*RootOf(_Z^3-10)+900*_Z^2)*RootOf(_ Z^3-10)^3*x^3+321317013531015450*RootOf(RootOf(_Z^3-10)^2+30*_Z*RootOf(_Z^ 3-10)+900*_Z^2)^2*RootOf(_Z^3-10)^2*x^3+2217804091003800*RootOf(RootOf(_Z^ 3-10)^2+30*_Z*RootOf(_Z^3-10)+900*_Z^2)*RootOf(_Z^3-10)^3*x^2+593200640364 951600*RootOf(RootOf(_Z^3-10)^2+30*_Z*RootOf(_Z^3-10)+900*_Z^2)^2*RootOf(_ Z^3-10)^2*x^2+35356252380606720*(27*x^2-54*x+52)^(2/3)*RootOf(RootOf(_Z^3- 10)^2+30*_Z*RootOf(_Z^3-10)+900*_Z^2)*RootOf(_Z^3-10)^2*x+1971381414225600 *RootOf(RootOf(_Z^3-10)^2+30*_Z*RootOf(_Z^3-10)+900*_Z^2)*RootOf(_Z^3-10)^ 3*x+527289458102179200*RootOf(RootOf(_Z^3-10)^2+30*_Z*RootOf(_Z^3-10)+900* _Z^2)^2*RootOf(_Z^3-10)^2*x-94283339681617920*(27*x^2-54*x+52)^(2/3)*RootO f(RootOf(_Z^3-10)^2+30*_Z*RootOf(_Z^3-10)+900*_Z^2)*RootOf(_Z^3-10)^2-3800 74665718431*(27*x^2-54*x+52)^(1/3)*RootOf(_Z^3-10)^2*x^2-10606875714182016 0*(27*x^2-54*x+52)^(1/3)*RootOf(RootOf(_Z^3-10)^2+30*_Z*RootOf(_Z^3-10)+90 0*_Z^2)*RootOf(_Z^3-10)*x^2+2027064883831632*(27*x^2-54*x+52)^(1/3)*RootOf (_Z^3-10)^2*x+565700038089707520*(27*x^2-54*x+52)^(1/3)*RootOf(RootOf(_Z^3 -10)^2+30*_Z*RootOf(_Z^3-10)+900*_Z^2)*RootOf(_Z^3-10)*x+794713132609695*R ootOf(_Z^3-10)*x^3+212563562797440990*RootOf(RootOf(_Z^3-10)^2+30*_Z*RootO f(_Z^3-10)+900*_Z^2)*x^3-2702753178442176*(27*x^2-54*x+52)^(1/3)*RootOf(_Z ^3-10)^2-754266717452943360*(27*x^2-54*x+52)^(1/3)*RootOf(RootOf(_Z^3-1...
Leaf count of result is larger than twice the leaf count of optimal. 208 vs. \(2 (83) = 166\).
Time = 1.78 (sec) , antiderivative size = 208, normalized size of antiderivative = 1.93 \[ \int \frac {1}{(2+3 x) \sqrt [3]{52-54 x+27 x^2}} \, dx=-\frac {1}{30} \cdot 100^{\frac {1}{6}} \sqrt {\frac {1}{3}} \arctan \left (\frac {100^{\frac {1}{6}} \sqrt {\frac {1}{3}} {\left (2 \cdot 100^{\frac {2}{3}} {\left (27 \, x^{2} - 54 \, x + 52\right )}^{\frac {2}{3}} {\left (3 \, x - 8\right )} + 100^{\frac {1}{3}} {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )} + 20 \, {\left (27 \, x^{2} - 54 \, x + 52\right )}^{\frac {1}{3}} {\left (9 \, x^{2} - 48 \, x + 64\right )}\right )}}{30 \, {\left (9 \, x^{3} - 162 \, x^{2} + 372 \, x - 344\right )}}\right ) - \frac {1}{1800} \cdot 100^{\frac {2}{3}} \log \left (\frac {100^{\frac {2}{3}} {\left (27 \, x^{2} - 54 \, x + 52\right )}^{\frac {2}{3}} + 100^{\frac {1}{3}} {\left (9 \, x^{2} - 48 \, x + 64\right )} - 10 \, {\left (27 \, x^{2} - 54 \, x + 52\right )}^{\frac {1}{3}} {\left (3 \, x - 8\right )}}{9 \, x^{2} + 12 \, x + 4}\right ) + \frac {1}{900} \cdot 100^{\frac {2}{3}} \log \left (\frac {100^{\frac {1}{3}} {\left (3 \, x - 8\right )} + 10 \, {\left (27 \, x^{2} - 54 \, x + 52\right )}^{\frac {1}{3}}}{3 \, x + 2}\right ) \] Input:
integrate(1/(2+3*x)/(27*x^2-54*x+52)^(1/3),x, algorithm="fricas")
Output:
-1/30*100^(1/6)*sqrt(1/3)*arctan(1/30*100^(1/6)*sqrt(1/3)*(2*100^(2/3)*(27 *x^2 - 54*x + 52)^(2/3)*(3*x - 8) + 100^(1/3)*(27*x^3 + 54*x^2 + 36*x + 8) + 20*(27*x^2 - 54*x + 52)^(1/3)*(9*x^2 - 48*x + 64))/(9*x^3 - 162*x^2 + 3 72*x - 344)) - 1/1800*100^(2/3)*log((100^(2/3)*(27*x^2 - 54*x + 52)^(2/3) + 100^(1/3)*(9*x^2 - 48*x + 64) - 10*(27*x^2 - 54*x + 52)^(1/3)*(3*x - 8)) /(9*x^2 + 12*x + 4)) + 1/900*100^(2/3)*log((100^(1/3)*(3*x - 8) + 10*(27*x ^2 - 54*x + 52)^(1/3))/(3*x + 2))
\[ \int \frac {1}{(2+3 x) \sqrt [3]{52-54 x+27 x^2}} \, dx=\int \frac {1}{\left (3 x + 2\right ) \sqrt [3]{27 x^{2} - 54 x + 52}}\, dx \] Input:
integrate(1/(2+3*x)/(27*x**2-54*x+52)**(1/3),x)
Output:
Integral(1/((3*x + 2)*(27*x**2 - 54*x + 52)**(1/3)), x)
\[ \int \frac {1}{(2+3 x) \sqrt [3]{52-54 x+27 x^2}} \, dx=\int { \frac {1}{{\left (27 \, x^{2} - 54 \, x + 52\right )}^{\frac {1}{3}} {\left (3 \, x + 2\right )}} \,d x } \] Input:
integrate(1/(2+3*x)/(27*x^2-54*x+52)^(1/3),x, algorithm="maxima")
Output:
integrate(1/((27*x^2 - 54*x + 52)^(1/3)*(3*x + 2)), x)
\[ \int \frac {1}{(2+3 x) \sqrt [3]{52-54 x+27 x^2}} \, dx=\int { \frac {1}{{\left (27 \, x^{2} - 54 \, x + 52\right )}^{\frac {1}{3}} {\left (3 \, x + 2\right )}} \,d x } \] Input:
integrate(1/(2+3*x)/(27*x^2-54*x+52)^(1/3),x, algorithm="giac")
Output:
integrate(1/((27*x^2 - 54*x + 52)^(1/3)*(3*x + 2)), x)
Timed out. \[ \int \frac {1}{(2+3 x) \sqrt [3]{52-54 x+27 x^2}} \, dx=\int \frac {1}{\left (3\,x+2\right )\,{\left (27\,x^2-54\,x+52\right )}^{1/3}} \,d x \] Input:
int(1/((3*x + 2)*(27*x^2 - 54*x + 52)^(1/3)),x)
Output:
int(1/((3*x + 2)*(27*x^2 - 54*x + 52)^(1/3)), x)
\[ \int \frac {1}{(2+3 x) \sqrt [3]{52-54 x+27 x^2}} \, dx=\int \frac {1}{3 \left (27 x^{2}-54 x +52\right )^{\frac {1}{3}} x +2 \left (27 x^{2}-54 x +52\right )^{\frac {1}{3}}}d x \] Input:
int(1/(2+3*x)/(27*x^2-54*x+52)^(1/3),x)
Output:
int(1/(3*(27*x**2 - 54*x + 52)**(1/3)*x + 2*(27*x**2 - 54*x + 52)**(1/3)), x)