Integrand size = 28, antiderivative size = 892 \[ \int \frac {1}{(d+e x) (f+g x)^{5/2} \sqrt {a+c x^2}} \, dx=\frac {2 g^2 \sqrt {a+c x^2}}{3 (e f-d g) \left (c f^2+a g^2\right ) (f+g x)^{3/2}}+\frac {2 g^2 \left (3 a e g^2+c f (7 e f-4 d g)\right ) \sqrt {a+c x^2}}{3 (e f-d g)^2 \left (c f^2+a g^2\right )^2 \sqrt {f+g x}}+\frac {2 \sqrt [4]{c} \left (\sqrt {c} f-\sqrt {-a} g\right ) \sqrt {\sqrt {c} f+\sqrt {-a} g} \left (3 a e g^2+c f (7 e f-4 d g)\right ) \sqrt {1-\frac {\sqrt {c} (f+g x)}{\sqrt {c} f-\sqrt {-a} g}} \sqrt {1-\frac {\sqrt {c} (f+g x)}{\sqrt {c} f+\sqrt {-a} g}} E\left (\arcsin \left (\frac {\sqrt [4]{c} \sqrt {f+g x}}{\sqrt {\sqrt {c} f+\sqrt {-a} g}}\right )|\frac {\sqrt {c} f+\sqrt {-a} g}{\sqrt {c} f-\sqrt {-a} g}\right )}{3 (e f-d g)^2 \left (c f^2+a g^2\right )^2 \sqrt {a+c x^2}}-\frac {2 \sqrt [4]{c} \sqrt {\sqrt {c} f+\sqrt {-a} g} \left (3 (-a)^{3/2} e g^3-\sqrt {-a} c f g (7 e f-4 d g)+3 c^{3/2} f^2 (2 e f-d g)+a \sqrt {c} g^2 (2 e f+d g)\right ) \sqrt {1-\frac {\sqrt {c} (f+g x)}{\sqrt {c} f-\sqrt {-a} g}} \sqrt {1-\frac {\sqrt {c} (f+g x)}{\sqrt {c} f+\sqrt {-a} g}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{c} \sqrt {f+g x}}{\sqrt {\sqrt {c} f+\sqrt {-a} g}}\right ),\frac {\sqrt {c} f+\sqrt {-a} g}{\sqrt {c} f-\sqrt {-a} g}\right )}{3 (e f-d g)^2 \left (c f^2+a g^2\right )^2 \sqrt {a+c x^2}}-\frac {2 e^2 \sqrt {\sqrt {c} f+\sqrt {-a} g} \sqrt {1-\frac {\sqrt {c} (f+g x)}{\sqrt {c} f-\sqrt {-a} g}} \sqrt {1-\frac {\sqrt {c} (f+g x)}{\sqrt {c} f+\sqrt {-a} g}} \operatorname {EllipticPi}\left (\frac {e \left (f+\frac {\sqrt {-a} g}{\sqrt {c}}\right )}{e f-d g},\arcsin \left (\frac {\sqrt [4]{c} \sqrt {f+g x}}{\sqrt {\sqrt {c} f+\sqrt {-a} g}}\right ),\frac {\sqrt {c} f+\sqrt {-a} g}{\sqrt {c} f-\sqrt {-a} g}\right )}{\sqrt [4]{c} (e f-d g)^3 \sqrt {a+c x^2}} \] Output:
2/3*g^2*(c*x^2+a)^(1/2)/(-d*g+e*f)/(a*g^2+c*f^2)/(g*x+f)^(3/2)+2/3*g^2*(3* a*e*g^2+c*f*(-4*d*g+7*e*f))*(c*x^2+a)^(1/2)/(-d*g+e*f)^2/(a*g^2+c*f^2)^2/( g*x+f)^(1/2)+2/3*c^(1/4)*(c^(1/2)*f-(-a)^(1/2)*g)*(c^(1/2)*f+(-a)^(1/2)*g) ^(1/2)*(3*a*e*g^2+c*f*(-4*d*g+7*e*f))*(1-c^(1/2)*(g*x+f)/(c^(1/2)*f-(-a)^( 1/2)*g))^(1/2)*(1-c^(1/2)*(g*x+f)/(c^(1/2)*f+(-a)^(1/2)*g))^(1/2)*Elliptic E(c^(1/4)*(g*x+f)^(1/2)/(c^(1/2)*f+(-a)^(1/2)*g)^(1/2),((c^(1/2)*f+(-a)^(1 /2)*g)/(c^(1/2)*f-(-a)^(1/2)*g))^(1/2))/(-d*g+e*f)^2/(a*g^2+c*f^2)^2/(c*x^ 2+a)^(1/2)-2/3*c^(1/4)*(c^(1/2)*f+(-a)^(1/2)*g)^(1/2)*(3*(-a)^(3/2)*e*g^3- (-a)^(1/2)*c*f*g*(-4*d*g+7*e*f)+3*c^(3/2)*f^2*(-d*g+2*e*f)+a*c^(1/2)*g^2*( d*g+2*e*f))*(1-c^(1/2)*(g*x+f)/(c^(1/2)*f-(-a)^(1/2)*g))^(1/2)*(1-c^(1/2)* (g*x+f)/(c^(1/2)*f+(-a)^(1/2)*g))^(1/2)*EllipticF(c^(1/4)*(g*x+f)^(1/2)/(c ^(1/2)*f+(-a)^(1/2)*g)^(1/2),((c^(1/2)*f+(-a)^(1/2)*g)/(c^(1/2)*f-(-a)^(1/ 2)*g))^(1/2))/(-d*g+e*f)^2/(a*g^2+c*f^2)^2/(c*x^2+a)^(1/2)-2*e^2*(c^(1/2)* f+(-a)^(1/2)*g)^(1/2)*(1-c^(1/2)*(g*x+f)/(c^(1/2)*f-(-a)^(1/2)*g))^(1/2)*( 1-c^(1/2)*(g*x+f)/(c^(1/2)*f+(-a)^(1/2)*g))^(1/2)*EllipticPi(c^(1/4)*(g*x+ f)^(1/2)/(c^(1/2)*f+(-a)^(1/2)*g)^(1/2),e*(f+(-a)^(1/2)*g/c^(1/2))/(-d*g+e *f),((c^(1/2)*f+(-a)^(1/2)*g)/(c^(1/2)*f-(-a)^(1/2)*g))^(1/2))/c^(1/4)/(-d *g+e*f)^3/(c*x^2+a)^(1/2)
Result contains complex when optimal does not.
Time = 31.13 (sec) , antiderivative size = 1917, normalized size of antiderivative = 2.15 \[ \int \frac {1}{(d+e x) (f+g x)^{5/2} \sqrt {a+c x^2}} \, dx =\text {Too large to display} \] Input:
Integrate[1/((d + e*x)*(f + g*x)^(5/2)*Sqrt[a + c*x^2]),x]
Output:
(2*(g^2*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]]*(e*f - d*g)*(a + c*x^2)*(a*g^2*(4 *e*f - d*g + 3*e*g*x) + c*f*(-(d*g*(5*f + 4*g*x)) + e*f*(8*f + 7*g*x))) - (f + g*x)*(7*c^2*e^2*f^5*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]] - 11*c^2*d*e*f^4 *g*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]] + 4*c^2*d^2*f^3*g^2*Sqrt[-f - (I*Sqrt[ a]*g)/Sqrt[c]] + 10*a*c*e^2*f^3*g^2*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]] - 14* a*c*d*e*f^2*g^3*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]] + 4*a*c*d^2*f*g^4*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]] + 3*a^2*e^2*f*g^4*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c ]] - 3*a^2*d*e*g^5*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]] - 14*c^2*e^2*f^4*Sqrt[ -f - (I*Sqrt[a]*g)/Sqrt[c]]*(f + g*x) + 22*c^2*d*e*f^3*g*Sqrt[-f - (I*Sqrt [a]*g)/Sqrt[c]]*(f + g*x) - 8*c^2*d^2*f^2*g^2*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt [c]]*(f + g*x) - 6*a*c*e^2*f^2*g^2*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]]*(f + g *x) + 6*a*c*d*e*f*g^3*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]]*(f + g*x) + 7*c^2*e ^2*f^3*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]]*(f + g*x)^2 - 11*c^2*d*e*f^2*g*Sqr t[-f - (I*Sqrt[a]*g)/Sqrt[c]]*(f + g*x)^2 + 4*c^2*d^2*f*g^2*Sqrt[-f - (I*S qrt[a]*g)/Sqrt[c]]*(f + g*x)^2 + 3*a*c*e^2*f*g^2*Sqrt[-f - (I*Sqrt[a]*g)/S qrt[c]]*(f + g*x)^2 - 3*a*c*d*e*g^3*Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]]*(f + g*x)^2 + Sqrt[c]*((-I)*Sqrt[c]*f + Sqrt[a]*g)*(e*f - d*g)*(3*a*e*g^2 + c*f *(7*e*f - 4*d*g))*Sqrt[(g*((I*Sqrt[a])/Sqrt[c] + x))/(f + g*x)]*Sqrt[-(((I *Sqrt[a]*g)/Sqrt[c] - g*x)/(f + g*x))]*(f + g*x)^(3/2)*EllipticE[I*ArcSinh [Sqrt[-f - (I*Sqrt[a]*g)/Sqrt[c]]/Sqrt[f + g*x]], (Sqrt[c]*f - I*Sqrt[a...
Leaf count is larger than twice the leaf count of optimal. \(1795\) vs. \(2(892)=1784\).
Time = 7.72 (sec) , antiderivative size = 1795, normalized size of antiderivative = 2.01, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {740, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {1}{\sqrt {a+c x^2} (d+e x) (f+g x)^{5/2}} \, dx\) |
| \(\Big \downarrow \) 740 |
| \(\displaystyle \int \left (\frac {e^2}{\sqrt {a+c x^2} (d+e x) \sqrt {f+g x} (e f-d g)^2}-\frac {e g}{\sqrt {a+c x^2} (f+g x)^{3/2} (e f-d g)^2}-\frac {g}{\sqrt {a+c x^2} (f+g x)^{5/2} (e f-d g)}\right )dx\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle -\frac {\text {arctanh}\left (\frac {\sqrt {c d^2+a e^2} \sqrt {f+g x}}{\sqrt {e} \sqrt {e f-d g} \sqrt {c x^2+a}}\right ) e^{5/2}}{\sqrt {c d^2+a e^2} (e f-d g)^{5/2}}+\frac {\sqrt [4]{c} \sqrt [4]{c f^2+a g^2} \left (\sqrt {c} (e f-d g)-e \sqrt {c f^2+a g^2}\right ) \sqrt {\frac {g^2 \left (c x^2+a\right )}{\left (c f^2+a g^2\right ) \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right )^2}} \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {f+g x}}{\sqrt [4]{c f^2+a g^2}}\right ),\frac {1}{2} \left (\frac {\sqrt {c} f}{\sqrt {c f^2+a g^2}}+1\right )\right ) e^2}{g (e f-d g)^2 \left (a g e^2+c d (2 e f-d g)\right ) \sqrt {c x^2+a}}-\frac {\sqrt [4]{c f^2+a g^2} \left (\sqrt {c} (e f-d g)-e \sqrt {c f^2+a g^2}\right )^2 \sqrt {\frac {g^2 \left (c x^2+a\right )}{\left (c f^2+a g^2\right ) \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right )^2}} \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right ) \operatorname {EllipticPi}\left (\frac {\left (\sqrt {c f^2+a g^2} e+\sqrt {c} (e f-d g)\right )^2}{4 \sqrt {c} e (e f-d g) \sqrt {c f^2+a g^2}},2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {f+g x}}{\sqrt [4]{c f^2+a g^2}}\right ),\frac {1}{2} \left (\frac {\sqrt {c} f}{\sqrt {c f^2+a g^2}}+1\right )\right ) e^2}{2 \sqrt [4]{c} g (e f-d g)^3 \left (a g e^2+c d (2 e f-d g)\right ) \sqrt {c x^2+a}}+\frac {2 \sqrt [4]{c} \sqrt {\frac {g^2 \left (c x^2+a\right )}{\left (c f^2+a g^2\right ) \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right )^2}} \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right ) E\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {f+g x}}{\sqrt [4]{c f^2+a g^2}}\right )|\frac {1}{2} \left (\frac {\sqrt {c} f}{\sqrt {c f^2+a g^2}}+1\right )\right ) e}{(e f-d g)^2 \sqrt [4]{c f^2+a g^2} \sqrt {c x^2+a}}-\frac {\sqrt [4]{c} \sqrt {\frac {g^2 \left (c x^2+a\right )}{\left (c f^2+a g^2\right ) \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right )^2}} \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {f+g x}}{\sqrt [4]{c f^2+a g^2}}\right ),\frac {1}{2} \left (\frac {\sqrt {c} f}{\sqrt {c f^2+a g^2}}+1\right )\right ) e}{(e f-d g)^2 \sqrt [4]{c f^2+a g^2} \sqrt {c x^2+a}}+\frac {2 g^2 \sqrt {c x^2+a} e}{(e f-d g)^2 \left (c f^2+a g^2\right ) \sqrt {f+g x}}-\frac {2 \sqrt {c} g^2 \sqrt {f+g x} \sqrt {c x^2+a} e}{(e f-d g)^2 \left (c f^2+a g^2\right )^{3/2} \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right )}+\frac {8 c^{5/4} f \sqrt {\frac {g^2 \left (c x^2+a\right )}{\left (c f^2+a g^2\right ) \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right )^2}} \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right ) E\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {f+g x}}{\sqrt [4]{c f^2+a g^2}}\right )|\frac {1}{2} \left (\frac {\sqrt {c} f}{\sqrt {c f^2+a g^2}}+1\right )\right )}{3 (e f-d g) \left (c f^2+a g^2\right )^{5/4} \sqrt {c x^2+a}}+\frac {c^{3/4} \left (c f^2-4 \sqrt {c} \sqrt {c f^2+a g^2} f+a g^2\right ) \sqrt {\frac {g^2 \left (c x^2+a\right )}{\left (c f^2+a g^2\right ) \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right )^2}} \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} \sqrt {f+g x}}{\sqrt [4]{c f^2+a g^2}}\right ),\frac {1}{2} \left (\frac {\sqrt {c} f}{\sqrt {c f^2+a g^2}}+1\right )\right )}{3 (e f-d g) \left (c f^2+a g^2\right )^{7/4} \sqrt {c x^2+a}}+\frac {8 c f g^2 \sqrt {c x^2+a}}{3 (e f-d g) \left (c f^2+a g^2\right )^2 \sqrt {f+g x}}+\frac {2 g^2 \sqrt {c x^2+a}}{3 (e f-d g) \left (c f^2+a g^2\right ) (f+g x)^{3/2}}-\frac {8 c^{3/2} f g^2 \sqrt {f+g x} \sqrt {c x^2+a}}{3 (e f-d g) \left (c f^2+a g^2\right )^{5/2} \left (\frac {\sqrt {c} (f+g x)}{\sqrt {c f^2+a g^2}}+1\right )}\) |
Input:
Int[1/((d + e*x)*(f + g*x)^(5/2)*Sqrt[a + c*x^2]),x]
Output:
(2*g^2*Sqrt[a + c*x^2])/(3*(e*f - d*g)*(c*f^2 + a*g^2)*(f + g*x)^(3/2)) + (8*c*f*g^2*Sqrt[a + c*x^2])/(3*(e*f - d*g)*(c*f^2 + a*g^2)^2*Sqrt[f + g*x] ) + (2*e*g^2*Sqrt[a + c*x^2])/((e*f - d*g)^2*(c*f^2 + a*g^2)*Sqrt[f + g*x] ) - (8*c^(3/2)*f*g^2*Sqrt[f + g*x]*Sqrt[a + c*x^2])/(3*(e*f - d*g)*(c*f^2 + a*g^2)^(5/2)*(1 + (Sqrt[c]*(f + g*x))/Sqrt[c*f^2 + a*g^2])) - (2*Sqrt[c] *e*g^2*Sqrt[f + g*x]*Sqrt[a + c*x^2])/((e*f - d*g)^2*(c*f^2 + a*g^2)^(3/2) *(1 + (Sqrt[c]*(f + g*x))/Sqrt[c*f^2 + a*g^2])) - (e^(5/2)*ArcTanh[(Sqrt[c *d^2 + a*e^2]*Sqrt[f + g*x])/(Sqrt[e]*Sqrt[e*f - d*g]*Sqrt[a + c*x^2])])/( Sqrt[c*d^2 + a*e^2]*(e*f - d*g)^(5/2)) + (8*c^(5/4)*f*Sqrt[(g^2*(a + c*x^2 ))/((c*f^2 + a*g^2)*(1 + (Sqrt[c]*(f + g*x))/Sqrt[c*f^2 + a*g^2])^2)]*(1 + (Sqrt[c]*(f + g*x))/Sqrt[c*f^2 + a*g^2])*EllipticE[2*ArcTan[(c^(1/4)*Sqrt [f + g*x])/(c*f^2 + a*g^2)^(1/4)], (1 + (Sqrt[c]*f)/Sqrt[c*f^2 + a*g^2])/2 ])/(3*(e*f - d*g)*(c*f^2 + a*g^2)^(5/4)*Sqrt[a + c*x^2]) + (2*c^(1/4)*e*Sq rt[(g^2*(a + c*x^2))/((c*f^2 + a*g^2)*(1 + (Sqrt[c]*(f + g*x))/Sqrt[c*f^2 + a*g^2])^2)]*(1 + (Sqrt[c]*(f + g*x))/Sqrt[c*f^2 + a*g^2])*EllipticE[2*Ar cTan[(c^(1/4)*Sqrt[f + g*x])/(c*f^2 + a*g^2)^(1/4)], (1 + (Sqrt[c]*f)/Sqrt [c*f^2 + a*g^2])/2])/((e*f - d*g)^2*(c*f^2 + a*g^2)^(1/4)*Sqrt[a + c*x^2]) - (c^(1/4)*e*Sqrt[(g^2*(a + c*x^2))/((c*f^2 + a*g^2)*(1 + (Sqrt[c]*(f + g *x))/Sqrt[c*f^2 + a*g^2])^2)]*(1 + (Sqrt[c]*(f + g*x))/Sqrt[c*f^2 + a*g^2] )*EllipticF[2*ArcTan[(c^(1/4)*Sqrt[f + g*x])/(c*f^2 + a*g^2)^(1/4)], (1...
Int[((f_.) + (g_.)*(x_))^(n_)/(((d_.) + (e_.)*(x_))*Sqrt[(a_) + (c_.)*(x_)^ 2]), x_Symbol] :> Int[ExpandIntegrand[1/(Sqrt[f + g*x]*Sqrt[a + c*x^2]), (f + g*x)^(n + 1/2)/(d + e*x), x], x] /; FreeQ[{a, c, d, e, f, g}, x] && Inte gerQ[n + 1/2]
Time = 10.99 (sec) , antiderivative size = 1079, normalized size of antiderivative = 1.21
| method | result | size |
| elliptic | \(\text {Expression too large to display}\) | \(1079\) |
| default | \(\text {Expression too large to display}\) | \(9409\) |
Input:
int(1/(e*x+d)/(g*x+f)^(5/2)/(c*x^2+a)^(1/2),x,method=_RETURNVERBOSE)
Output:
((g*x+f)*(c*x^2+a))^(1/2)/(g*x+f)^(1/2)/(c*x^2+a)^(1/2)*(-2/3/(a*g^2+c*f^2 )/(d*g-e*f)*(c*g*x^3+c*f*x^2+a*g*x+a*f)^(1/2)/(x+f/g)^2+2/3*(c*g*x^2+a*g)/ (a*g^2+c*f^2)^2*g*(3*a*e*g^2-4*c*d*f*g+7*c*e*f^2)/(d*g-e*f)^2/((x+f/g)*(c* g*x^2+a*g))^(1/2)+2*(-1/3*c*g/(a*g^2+c*f^2)/(d*g-e*f)-1/3*c*f*g*(3*a*e*g^2 -4*c*d*f*g+7*c*e*f^2)/(a*g^2+c*f^2)^2/(d*g-e*f)^2)*(f/g-(-a*c)^(1/2)/c)*(( x+f/g)/(f/g-(-a*c)^(1/2)/c))^(1/2)*((x-(-a*c)^(1/2)/c)/(-f/g-(-a*c)^(1/2)/ c))^(1/2)*((x+(-a*c)^(1/2)/c)/(-f/g+(-a*c)^(1/2)/c))^(1/2)/(c*g*x^3+c*f*x^ 2+a*g*x+a*f)^(1/2)*EllipticF(((x+f/g)/(f/g-(-a*c)^(1/2)/c))^(1/2),((-f/g+( -a*c)^(1/2)/c)/(-f/g-(-a*c)^(1/2)/c))^(1/2))-2/3*c*g^2*(3*a*e*g^2-4*c*d*f* g+7*c*e*f^2)/(a*g^2+c*f^2)^2/(d*g-e*f)^2*(f/g-(-a*c)^(1/2)/c)*((x+f/g)/(f/ g-(-a*c)^(1/2)/c))^(1/2)*((x-(-a*c)^(1/2)/c)/(-f/g-(-a*c)^(1/2)/c))^(1/2)* ((x+(-a*c)^(1/2)/c)/(-f/g+(-a*c)^(1/2)/c))^(1/2)/(c*g*x^3+c*f*x^2+a*g*x+a* f)^(1/2)*((-f/g-(-a*c)^(1/2)/c)*EllipticE(((x+f/g)/(f/g-(-a*c)^(1/2)/c))^( 1/2),((-f/g+(-a*c)^(1/2)/c)/(-f/g-(-a*c)^(1/2)/c))^(1/2))+(-a*c)^(1/2)/c*E llipticF(((x+f/g)/(f/g-(-a*c)^(1/2)/c))^(1/2),((-f/g+(-a*c)^(1/2)/c)/(-f/g -(-a*c)^(1/2)/c))^(1/2)))+2*e/(d*g-e*f)^2*(f/g-(-a*c)^(1/2)/c)*((x+f/g)/(f /g-(-a*c)^(1/2)/c))^(1/2)*((x-(-a*c)^(1/2)/c)/(-f/g-(-a*c)^(1/2)/c))^(1/2) *((x+(-a*c)^(1/2)/c)/(-f/g+(-a*c)^(1/2)/c))^(1/2)/(c*g*x^3+c*f*x^2+a*g*x+a *f)^(1/2)/(-f/g+d/e)*EllipticPi(((x+f/g)/(f/g-(-a*c)^(1/2)/c))^(1/2),(-f/g +(-a*c)^(1/2)/c)/(-f/g+d/e),((-f/g+(-a*c)^(1/2)/c)/(-f/g-(-a*c)^(1/2)/c...
Timed out. \[ \int \frac {1}{(d+e x) (f+g x)^{5/2} \sqrt {a+c x^2}} \, dx=\text {Timed out} \] Input:
integrate(1/(e*x+d)/(g*x+f)^(5/2)/(c*x^2+a)^(1/2),x, algorithm="fricas")
Output:
Timed out
\[ \int \frac {1}{(d+e x) (f+g x)^{5/2} \sqrt {a+c x^2}} \, dx=\int \frac {1}{\sqrt {a + c x^{2}} \left (d + e x\right ) \left (f + g x\right )^{\frac {5}{2}}}\, dx \] Input:
integrate(1/(e*x+d)/(g*x+f)**(5/2)/(c*x**2+a)**(1/2),x)
Output:
Integral(1/(sqrt(a + c*x**2)*(d + e*x)*(f + g*x)**(5/2)), x)
\[ \int \frac {1}{(d+e x) (f+g x)^{5/2} \sqrt {a+c x^2}} \, dx=\int { \frac {1}{\sqrt {c x^{2} + a} {\left (e x + d\right )} {\left (g x + f\right )}^{\frac {5}{2}}} \,d x } \] Input:
integrate(1/(e*x+d)/(g*x+f)^(5/2)/(c*x^2+a)^(1/2),x, algorithm="maxima")
Output:
integrate(1/(sqrt(c*x^2 + a)*(e*x + d)*(g*x + f)^(5/2)), x)
\[ \int \frac {1}{(d+e x) (f+g x)^{5/2} \sqrt {a+c x^2}} \, dx=\int { \frac {1}{\sqrt {c x^{2} + a} {\left (e x + d\right )} {\left (g x + f\right )}^{\frac {5}{2}}} \,d x } \] Input:
integrate(1/(e*x+d)/(g*x+f)^(5/2)/(c*x^2+a)^(1/2),x, algorithm="giac")
Output:
integrate(1/(sqrt(c*x^2 + a)*(e*x + d)*(g*x + f)^(5/2)), x)
Timed out. \[ \int \frac {1}{(d+e x) (f+g x)^{5/2} \sqrt {a+c x^2}} \, dx=\int \frac {1}{{\left (f+g\,x\right )}^{5/2}\,\sqrt {c\,x^2+a}\,\left (d+e\,x\right )} \,d x \] Input:
int(1/((f + g*x)^(5/2)*(a + c*x^2)^(1/2)*(d + e*x)),x)
Output:
int(1/((f + g*x)^(5/2)*(a + c*x^2)^(1/2)*(d + e*x)), x)
\[ \int \frac {1}{(d+e x) (f+g x)^{5/2} \sqrt {a+c x^2}} \, dx=\int \frac {\sqrt {g x +f}\, \sqrt {c \,x^{2}+a}}{c e \,g^{3} x^{6}+c d \,g^{3} x^{5}+3 c e f \,g^{2} x^{5}+a e \,g^{3} x^{4}+3 c d f \,g^{2} x^{4}+3 c e \,f^{2} g \,x^{4}+a d \,g^{3} x^{3}+3 a e f \,g^{2} x^{3}+3 c d \,f^{2} g \,x^{3}+c e \,f^{3} x^{3}+3 a d f \,g^{2} x^{2}+3 a e \,f^{2} g \,x^{2}+c d \,f^{3} x^{2}+3 a d \,f^{2} g x +a e \,f^{3} x +a d \,f^{3}}d x \] Input:
int(1/(e*x+d)/(g*x+f)^(5/2)/(c*x^2+a)^(1/2),x)
Output:
int((sqrt(f + g*x)*sqrt(a + c*x**2))/(a*d*f**3 + 3*a*d*f**2*g*x + 3*a*d*f* g**2*x**2 + a*d*g**3*x**3 + a*e*f**3*x + 3*a*e*f**2*g*x**2 + 3*a*e*f*g**2* x**3 + a*e*g**3*x**4 + c*d*f**3*x**2 + 3*c*d*f**2*g*x**3 + 3*c*d*f*g**2*x* *4 + c*d*g**3*x**5 + c*e*f**3*x**3 + 3*c*e*f**2*g*x**4 + 3*c*e*f*g**2*x**5 + c*e*g**3*x**6),x)