Integrand size = 40, antiderivative size = 323 \[ \int \frac {x^3 (d+e x)^2}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\frac {2 a^3 e^3 (d+e x)}{c^4 d^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {\left (c d^2-3 a e^2\right ) \left (3 c d^2+19 a e^2\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{24 c^4 d^4 e^2}+\frac {\left (c d^2-11 a e^2\right ) x \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{12 c^3 d^3 e}+\frac {x^2 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 c^2 d^2}+\frac {\left (c^3 d^6+3 a c^2 d^4 e^2+15 a^2 c d^2 e^4-35 a^3 e^6\right ) \text {arctanh}\left (\frac {\sqrt {c} \sqrt {d} (d+e x)}{\sqrt {e} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}\right )}{8 c^{9/2} d^{9/2} e^{5/2}} \] Output:
2*a^3*e^3*(e*x+d)/c^4/d^4/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2)-1/24*(-3 *a*e^2+c*d^2)*(19*a*e^2+3*c*d^2)*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2)/c ^4/d^4/e^2+1/12*(-11*a*e^2+c*d^2)*x*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2 )/c^3/d^3/e+1/3*x^2*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2)/c^2/d^2+1/8*(- 35*a^3*e^6+15*a^2*c*d^2*e^4+3*a*c^2*d^4*e^2+c^3*d^6)*arctanh(c^(1/2)*d^(1/ 2)*(e*x+d)/e^(1/2)/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2))/c^(9/2)/d^(9/2 )/e^(5/2)
Time = 0.86 (sec) , antiderivative size = 243, normalized size of antiderivative = 0.75 \[ \int \frac {x^3 (d+e x)^2}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\frac {-\sqrt {c} \sqrt {d} \sqrt {e} (d+e x) \left (-105 a^3 e^5+5 a^2 c d e^3 (2 d-7 e x)+c^3 d^3 x \left (3 d^2-2 d e x-8 e^2 x^2\right )+a c^2 d^2 e \left (3 d^2+8 d e x+14 e^2 x^2\right )\right )+3 \left (c^3 d^6+3 a c^2 d^4 e^2+15 a^2 c d^2 e^4-35 a^3 e^6\right ) \sqrt {a e+c d x} \sqrt {d+e x} \text {arctanh}\left (\frac {\sqrt {c} \sqrt {d} \sqrt {d+e x}}{\sqrt {e} \sqrt {a e+c d x}}\right )}{24 c^{9/2} d^{9/2} e^{5/2} \sqrt {(a e+c d x) (d+e x)}} \] Input:
Integrate[(x^3*(d + e*x)^2)/(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2), x]
Output:
(-(Sqrt[c]*Sqrt[d]*Sqrt[e]*(d + e*x)*(-105*a^3*e^5 + 5*a^2*c*d*e^3*(2*d - 7*e*x) + c^3*d^3*x*(3*d^2 - 2*d*e*x - 8*e^2*x^2) + a*c^2*d^2*e*(3*d^2 + 8* d*e*x + 14*e^2*x^2))) + 3*(c^3*d^6 + 3*a*c^2*d^4*e^2 + 15*a^2*c*d^2*e^4 - 35*a^3*e^6)*Sqrt[a*e + c*d*x]*Sqrt[d + e*x]*ArcTanh[(Sqrt[c]*Sqrt[d]*Sqrt[ d + e*x])/(Sqrt[e]*Sqrt[a*e + c*d*x])])/(24*c^(9/2)*d^(9/2)*e^(5/2)*Sqrt[( a*e + c*d*x)*(d + e*x)])
Time = 1.65 (sec) , antiderivative size = 367, normalized size of antiderivative = 1.14, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {1211, 2192, 27, 2192, 27, 1160, 1092, 219}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^3 (d+e x)^2}{\left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}} \, dx\) |
\(\Big \downarrow \) 1211 |
\(\displaystyle \frac {\int \frac {a^2 \left (c d^2-a e^2\right ) e^7+c^3 d^3 x^3 e^6-a c d \left (c d^2-a e^2\right ) x e^6+c^2 d^2 \left (c d^2-a e^2\right ) x^2 e^5}{\sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}dx}{c^4 d^4 e^5}+\frac {2 a^3 e^3 (d+e x)}{c^4 d^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\) |
\(\Big \downarrow \) 2192 |
\(\displaystyle \frac {\frac {\int \frac {6 a^2 c d \left (c d^2-a e^2\right ) e^8-2 a c^2 d^2 \left (5 c d^2-3 a e^2\right ) x e^7+c^3 d^3 \left (c d^2-11 a e^2\right ) x^2 e^6}{2 \sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}dx}{3 c d e}+\frac {1}{3} c^2 d^2 e^5 x^2 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{c^4 d^4 e^5}+\frac {2 a^3 e^3 (d+e x)}{c^4 d^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\frac {\int \frac {6 a^2 c d \left (c d^2-a e^2\right ) e^8-2 a c^2 d^2 \left (5 c d^2-3 a e^2\right ) x e^7+c^3 d^3 \left (c d^2-11 a e^2\right ) x^2 e^6}{\sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}dx}{6 c d e}+\frac {1}{3} c^2 d^2 e^5 x^2 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{c^4 d^4 e^5}+\frac {2 a^3 e^3 (d+e x)}{c^4 d^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\) |
\(\Big \downarrow \) 2192 |
\(\displaystyle \frac {\frac {\frac {\int -\frac {c^2 d^2 e^6 \left (2 a e \left (c^2 d^4-23 a c e^2 d^2+12 a^2 e^4\right )+c d \left (c d^2-3 a e^2\right ) \left (3 c d^2+19 a e^2\right ) x\right )}{2 \sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}dx}{2 c d e}+\frac {1}{2} c^2 d^2 e^5 x \left (c d^2-11 a e^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{6 c d e}+\frac {1}{3} c^2 d^2 e^5 x^2 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{c^4 d^4 e^5}+\frac {2 a^3 e^3 (d+e x)}{c^4 d^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\frac {\frac {1}{2} c^2 d^2 e^5 x \left (c d^2-11 a e^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}-\frac {1}{4} c d e^5 \int \frac {2 a e \left (c^2 d^4-23 a c e^2 d^2+12 a^2 e^4\right )+c d \left (c d^2-3 a e^2\right ) \left (3 c d^2+19 a e^2\right ) x}{\sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}dx}{6 c d e}+\frac {1}{3} c^2 d^2 e^5 x^2 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{c^4 d^4 e^5}+\frac {2 a^3 e^3 (d+e x)}{c^4 d^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\) |
\(\Big \downarrow \) 1160 |
\(\displaystyle \frac {\frac {\frac {1}{2} c^2 d^2 e^5 x \left (c d^2-11 a e^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}-\frac {1}{4} c d e^5 \left (\frac {\left (c d^2-3 a e^2\right ) \left (19 a e^2+3 c d^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{e}-\frac {3 \left (-35 a^3 e^6+15 a^2 c d^2 e^4+3 a c^2 d^4 e^2+c^3 d^6\right ) \int \frac {1}{\sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}dx}{2 e}\right )}{6 c d e}+\frac {1}{3} c^2 d^2 e^5 x^2 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{c^4 d^4 e^5}+\frac {2 a^3 e^3 (d+e x)}{c^4 d^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\) |
\(\Big \downarrow \) 1092 |
\(\displaystyle \frac {\frac {\frac {1}{2} c^2 d^2 e^5 x \left (c d^2-11 a e^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}-\frac {1}{4} c d e^5 \left (\frac {\left (c d^2-3 a e^2\right ) \left (19 a e^2+3 c d^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{e}-\frac {3 \left (-35 a^3 e^6+15 a^2 c d^2 e^4+3 a c^2 d^4 e^2+c^3 d^6\right ) \int \frac {1}{4 c d e-\frac {\left (c d^2+2 c e x d+a e^2\right )^2}{c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}d\frac {c d^2+2 c e x d+a e^2}{\sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}}{e}\right )}{6 c d e}+\frac {1}{3} c^2 d^2 e^5 x^2 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{c^4 d^4 e^5}+\frac {2 a^3 e^3 (d+e x)}{c^4 d^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle \frac {2 a^3 e^3 (d+e x)}{c^4 d^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}+\frac {\frac {\frac {1}{2} c^2 d^2 e^5 x \left (c d^2-11 a e^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}-\frac {1}{4} c d e^5 \left (\frac {\left (c d^2-3 a e^2\right ) \left (19 a e^2+3 c d^2\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{e}-\frac {3 \left (-35 a^3 e^6+15 a^2 c d^2 e^4+3 a c^2 d^4 e^2+c^3 d^6\right ) \text {arctanh}\left (\frac {a e^2+c d^2+2 c d e x}{2 \sqrt {c} \sqrt {d} \sqrt {e} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\right )}{2 \sqrt {c} \sqrt {d} e^{3/2}}\right )}{6 c d e}+\frac {1}{3} c^2 d^2 e^5 x^2 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{c^4 d^4 e^5}\) |
Input:
Int[(x^3*(d + e*x)^2)/(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2),x]
Output:
(2*a^3*e^3*(d + e*x))/(c^4*d^4*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2] ) + ((c^2*d^2*e^5*x^2*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2])/3 + ((c ^2*d^2*e^5*(c*d^2 - 11*a*e^2)*x*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2 ])/2 - (c*d*e^5*(((c*d^2 - 3*a*e^2)*(3*c*d^2 + 19*a*e^2)*Sqrt[a*d*e + (c*d ^2 + a*e^2)*x + c*d*e*x^2])/e - (3*(c^3*d^6 + 3*a*c^2*d^4*e^2 + 15*a^2*c*d ^2*e^4 - 35*a^3*e^6)*ArcTanh[(c*d^2 + a*e^2 + 2*c*d*e*x)/(2*Sqrt[c]*Sqrt[d ]*Sqrt[e]*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2])])/(2*Sqrt[c]*Sqrt[d ]*e^(3/2))))/4)/(6*c*d*e))/(c^4*d^4*e^5)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Int[1/Sqrt[(a_) + (b_.)*(x_) + (c_.)*(x_)^2], x_Symbol] :> Simp[2 Subst[I nt[1/(4*c - x^2), x], x, (b + 2*c*x)/Sqrt[a + b*x + c*x^2]], x] /; FreeQ[{a , b, c}, x]
Int[((d_.) + (e_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol ] :> Simp[e*((a + b*x + c*x^2)^(p + 1)/(2*c*(p + 1))), x] + Simp[(2*c*d - b *e)/(2*c) Int[(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[p, -1]
Int[(((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))^(n_.))/((a_.) + (b_.)* (x_) + (c_.)*(x_)^2)^(3/2), x_Symbol] :> Simp[-2*(2*c*d - b*e)^(m - 2)*(c*( e*f + d*g) - b*e*g)^n*((d + e*x)/(c^(m + n - 1)*e^(n - 1)*Sqrt[a + b*x + c* x^2])), x] + Simp[1/(c^(m + n - 1)*e^(n - 2)) Int[ExpandToSum[((2*c*d - b *e)^(m - 1)*(c*(e*f + d*g) - b*e*g)^n - c^(m + n - 1)*e^n*(d + e*x)^(m - 1) *(f + g*x)^n)/(c*d - b*e - c*e*x), x]/Sqrt[a + b*x + c*x^2], x], x] /; Free Q[{a, b, c, d, e, f, g}, x] && EqQ[c*d^2 - b*d*e + a*e^2, 0] && IGtQ[m, 0] && IGtQ[n, 0]
Int[(Pq_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> With[{q = Expon[Pq, x], e = Coeff[Pq, x, Expon[Pq, x]]}, Simp[e*x^(q - 1)*((a + b*x + c*x^2)^(p + 1)/(c*(q + 2*p + 1))), x] + Simp[1/(c*(q + 2*p + 1)) Int[(a + b*x + c*x^2)^p*ExpandToSum[c*(q + 2*p + 1)*Pq - a*e*(q - 1)*x^(q - 2) - b *e*(q + p)*x^(q - 1) - c*e*(q + 2*p + 1)*x^q, x], x], x]] /; FreeQ[{a, b, c , p}, x] && PolyQ[Pq, x] && NeQ[b^2 - 4*a*c, 0] && !LeQ[p, -1]
Leaf count of result is larger than twice the leaf count of optimal. \(2621\) vs. \(2(293)=586\).
Time = 2.80 (sec) , antiderivative size = 2622, normalized size of antiderivative = 8.12
Input:
int(x^3*(e*x+d)^2/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(3/2),x,method=_RETURN VERBOSE)
Output:
d^2*(x^2/d/e/c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2)-3/2*(a*e^2+c*d^2)/d /e/c*(-x/d/e/c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2)-1/2*(a*e^2+c*d^2)/d /e/c*(-1/d/e/c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2)-(a*e^2+c*d^2)/d/e/c *(2*c*d*e*x+a*e^2+c*d^2)/(4*a*c*d^2*e^2-(a*e^2+c*d^2)^2)/(a*d*e+(a*e^2+c*d ^2)*x+c*d*x^2*e)^(1/2))+1/d/e/c*ln((1/2*a*e^2+1/2*c*d^2+c*d*x*e)/(d*e*c)^( 1/2)+(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2))/(d*e*c)^(1/2))-2*a/c*(-1/d/e /c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2)-(a*e^2+c*d^2)/d/e/c*(2*c*d*e*x+ a*e^2+c*d^2)/(4*a*c*d^2*e^2-(a*e^2+c*d^2)^2)/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^ 2*e)^(1/2)))+e^2*(1/3*x^4/d/e/c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2)-7/ 6*(a*e^2+c*d^2)/d/e/c*(1/2*x^3/d/e/c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/ 2)-5/4*(a*e^2+c*d^2)/d/e/c*(x^2/d/e/c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1 /2)-3/2*(a*e^2+c*d^2)/d/e/c*(-x/d/e/c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1 /2)-1/2*(a*e^2+c*d^2)/d/e/c*(-1/d/e/c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1 /2)-(a*e^2+c*d^2)/d/e/c*(2*c*d*e*x+a*e^2+c*d^2)/(4*a*c*d^2*e^2-(a*e^2+c*d^ 2)^2)/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2))+1/d/e/c*ln((1/2*a*e^2+1/2*c *d^2+c*d*x*e)/(d*e*c)^(1/2)+(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2))/(d*e* c)^(1/2))-2*a/c*(-1/d/e/c/(a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2)-(a*e^2+c *d^2)/d/e/c*(2*c*d*e*x+a*e^2+c*d^2)/(4*a*c*d^2*e^2-(a*e^2+c*d^2)^2)/(a*d*e +(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2)))-3/2*a/c*(-x/d/e/c/(a*d*e+(a*e^2+c*d^2) *x+c*d*x^2*e)^(1/2)-1/2*(a*e^2+c*d^2)/d/e/c*(-1/d/e/c/(a*d*e+(a*e^2+c*d...
Time = 0.50 (sec) , antiderivative size = 756, normalized size of antiderivative = 2.34 \[ \int \frac {x^3 (d+e x)^2}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\left [-\frac {3 \, {\left (a c^{3} d^{6} e + 3 \, a^{2} c^{2} d^{4} e^{3} + 15 \, a^{3} c d^{2} e^{5} - 35 \, a^{4} e^{7} + {\left (c^{4} d^{7} + 3 \, a c^{3} d^{5} e^{2} + 15 \, a^{2} c^{2} d^{3} e^{4} - 35 \, a^{3} c d e^{6}\right )} x\right )} \sqrt {c d e} \log \left (8 \, c^{2} d^{2} e^{2} x^{2} + c^{2} d^{4} + 6 \, a c d^{2} e^{2} + a^{2} e^{4} - 4 \, \sqrt {c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x} {\left (2 \, c d e x + c d^{2} + a e^{2}\right )} \sqrt {c d e} + 8 \, {\left (c^{2} d^{3} e + a c d e^{3}\right )} x\right ) - 4 \, {\left (8 \, c^{4} d^{4} e^{3} x^{3} - 3 \, a c^{3} d^{5} e^{2} - 10 \, a^{2} c^{2} d^{3} e^{4} + 105 \, a^{3} c d e^{6} + 2 \, {\left (c^{4} d^{5} e^{2} - 7 \, a c^{3} d^{3} e^{4}\right )} x^{2} - {\left (3 \, c^{4} d^{6} e + 8 \, a c^{3} d^{4} e^{3} - 35 \, a^{2} c^{2} d^{2} e^{5}\right )} x\right )} \sqrt {c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x}}{96 \, {\left (c^{6} d^{6} e^{3} x + a c^{5} d^{5} e^{4}\right )}}, -\frac {3 \, {\left (a c^{3} d^{6} e + 3 \, a^{2} c^{2} d^{4} e^{3} + 15 \, a^{3} c d^{2} e^{5} - 35 \, a^{4} e^{7} + {\left (c^{4} d^{7} + 3 \, a c^{3} d^{5} e^{2} + 15 \, a^{2} c^{2} d^{3} e^{4} - 35 \, a^{3} c d e^{6}\right )} x\right )} \sqrt {-c d e} \arctan \left (\frac {\sqrt {c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x} {\left (2 \, c d e x + c d^{2} + a e^{2}\right )} \sqrt {-c d e}}{2 \, {\left (c^{2} d^{2} e^{2} x^{2} + a c d^{2} e^{2} + {\left (c^{2} d^{3} e + a c d e^{3}\right )} x\right )}}\right ) - 2 \, {\left (8 \, c^{4} d^{4} e^{3} x^{3} - 3 \, a c^{3} d^{5} e^{2} - 10 \, a^{2} c^{2} d^{3} e^{4} + 105 \, a^{3} c d e^{6} + 2 \, {\left (c^{4} d^{5} e^{2} - 7 \, a c^{3} d^{3} e^{4}\right )} x^{2} - {\left (3 \, c^{4} d^{6} e + 8 \, a c^{3} d^{4} e^{3} - 35 \, a^{2} c^{2} d^{2} e^{5}\right )} x\right )} \sqrt {c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x}}{48 \, {\left (c^{6} d^{6} e^{3} x + a c^{5} d^{5} e^{4}\right )}}\right ] \] Input:
integrate(x^3*(e*x+d)^2/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2),x, algorit hm="fricas")
Output:
[-1/96*(3*(a*c^3*d^6*e + 3*a^2*c^2*d^4*e^3 + 15*a^3*c*d^2*e^5 - 35*a^4*e^7 + (c^4*d^7 + 3*a*c^3*d^5*e^2 + 15*a^2*c^2*d^3*e^4 - 35*a^3*c*d*e^6)*x)*sq rt(c*d*e)*log(8*c^2*d^2*e^2*x^2 + c^2*d^4 + 6*a*c*d^2*e^2 + a^2*e^4 - 4*sq rt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)*(2*c*d*e*x + c*d^2 + a*e^2)*sqrt (c*d*e) + 8*(c^2*d^3*e + a*c*d*e^3)*x) - 4*(8*c^4*d^4*e^3*x^3 - 3*a*c^3*d^ 5*e^2 - 10*a^2*c^2*d^3*e^4 + 105*a^3*c*d*e^6 + 2*(c^4*d^5*e^2 - 7*a*c^3*d^ 3*e^4)*x^2 - (3*c^4*d^6*e + 8*a*c^3*d^4*e^3 - 35*a^2*c^2*d^2*e^5)*x)*sqrt( c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x))/(c^6*d^6*e^3*x + a*c^5*d^5*e^4), - 1/48*(3*(a*c^3*d^6*e + 3*a^2*c^2*d^4*e^3 + 15*a^3*c*d^2*e^5 - 35*a^4*e^7 + (c^4*d^7 + 3*a*c^3*d^5*e^2 + 15*a^2*c^2*d^3*e^4 - 35*a^3*c*d*e^6)*x)*sqrt (-c*d*e)*arctan(1/2*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)*(2*c*d*e*x + c*d^2 + a*e^2)*sqrt(-c*d*e)/(c^2*d^2*e^2*x^2 + a*c*d^2*e^2 + (c^2*d^3*e + a*c*d*e^3)*x)) - 2*(8*c^4*d^4*e^3*x^3 - 3*a*c^3*d^5*e^2 - 10*a^2*c^2*d^ 3*e^4 + 105*a^3*c*d*e^6 + 2*(c^4*d^5*e^2 - 7*a*c^3*d^3*e^4)*x^2 - (3*c^4*d ^6*e + 8*a*c^3*d^4*e^3 - 35*a^2*c^2*d^2*e^5)*x)*sqrt(c*d*e*x^2 + a*d*e + ( c*d^2 + a*e^2)*x))/(c^6*d^6*e^3*x + a*c^5*d^5*e^4)]
\[ \int \frac {x^3 (d+e x)^2}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\int \frac {x^{3} \left (d + e x\right )^{2}}{\left (\left (d + e x\right ) \left (a e + c d x\right )\right )^{\frac {3}{2}}}\, dx \] Input:
integrate(x**3*(e*x+d)**2/(a*d*e+(a*e**2+c*d**2)*x+c*d*e*x**2)**(3/2),x)
Output:
Integral(x**3*(d + e*x)**2/((d + e*x)*(a*e + c*d*x))**(3/2), x)
Exception generated. \[ \int \frac {x^3 (d+e x)^2}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\text {Exception raised: ValueError} \] Input:
integrate(x^3*(e*x+d)^2/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2),x, algorit hm="maxima")
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(a*e^2-c*d^2>0)', see `assume?` f or more de
Exception generated. \[ \int \frac {x^3 (d+e x)^2}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\text {Exception raised: TypeError} \] Input:
integrate(x^3*(e*x+d)^2/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2),x, algorit hm="giac")
Output:
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:Unable to divide, perhaps due to ro unding error%%%{%%{[%%%{1,[5,5,0]%%%},0]:[1,0,%%%{-1,[1,1,1]%%%}]%%},[2,0] %%%}+%%%{
Timed out. \[ \int \frac {x^3 (d+e x)^2}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\int \frac {x^3\,{\left (d+e\,x\right )}^2}{{\left (c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e\right )}^{3/2}} \,d x \] Input:
int((x^3*(d + e*x)^2)/(x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(3/2),x)
Output:
int((x^3*(d + e*x)^2)/(x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(3/2), x)
Time = 21.45 (sec) , antiderivative size = 558, normalized size of antiderivative = 1.73 \[ \int \frac {x^3 (d+e x)^2}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx=\frac {-840 \sqrt {e}\, \sqrt {d}\, \sqrt {c}\, \sqrt {c d x +a e}\, \mathrm {log}\left (\frac {\sqrt {e}\, \sqrt {c d x +a e}+\sqrt {d}\, \sqrt {c}\, \sqrt {e x +d}}{\sqrt {a \,e^{2}-c \,d^{2}}}\right ) a^{3} e^{6}+360 \sqrt {e}\, \sqrt {d}\, \sqrt {c}\, \sqrt {c d x +a e}\, \mathrm {log}\left (\frac {\sqrt {e}\, \sqrt {c d x +a e}+\sqrt {d}\, \sqrt {c}\, \sqrt {e x +d}}{\sqrt {a \,e^{2}-c \,d^{2}}}\right ) a^{2} c \,d^{2} e^{4}+72 \sqrt {e}\, \sqrt {d}\, \sqrt {c}\, \sqrt {c d x +a e}\, \mathrm {log}\left (\frac {\sqrt {e}\, \sqrt {c d x +a e}+\sqrt {d}\, \sqrt {c}\, \sqrt {e x +d}}{\sqrt {a \,e^{2}-c \,d^{2}}}\right ) a \,c^{2} d^{4} e^{2}+24 \sqrt {e}\, \sqrt {d}\, \sqrt {c}\, \sqrt {c d x +a e}\, \mathrm {log}\left (\frac {\sqrt {e}\, \sqrt {c d x +a e}+\sqrt {d}\, \sqrt {c}\, \sqrt {e x +d}}{\sqrt {a \,e^{2}-c \,d^{2}}}\right ) c^{3} d^{6}+525 \sqrt {e}\, \sqrt {d}\, \sqrt {c}\, \sqrt {c d x +a e}\, a^{3} e^{6}-135 \sqrt {e}\, \sqrt {d}\, \sqrt {c}\, \sqrt {c d x +a e}\, a^{2} c \,d^{2} e^{4}-9 \sqrt {e}\, \sqrt {d}\, \sqrt {c}\, \sqrt {c d x +a e}\, a \,c^{2} d^{4} e^{2}+3 \sqrt {e}\, \sqrt {d}\, \sqrt {c}\, \sqrt {c d x +a e}\, c^{3} d^{6}+840 \sqrt {e x +d}\, a^{3} c d \,e^{6}-80 \sqrt {e x +d}\, a^{2} c^{2} d^{3} e^{4}+280 \sqrt {e x +d}\, a^{2} c^{2} d^{2} e^{5} x -24 \sqrt {e x +d}\, a \,c^{3} d^{5} e^{2}-64 \sqrt {e x +d}\, a \,c^{3} d^{4} e^{3} x -112 \sqrt {e x +d}\, a \,c^{3} d^{3} e^{4} x^{2}-24 \sqrt {e x +d}\, c^{4} d^{6} e x +16 \sqrt {e x +d}\, c^{4} d^{5} e^{2} x^{2}+64 \sqrt {e x +d}\, c^{4} d^{4} e^{3} x^{3}}{192 \sqrt {c d x +a e}\, c^{5} d^{5} e^{3}} \] Input:
int(x^3*(e*x+d)^2/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(3/2),x)
Output:
( - 840*sqrt(e)*sqrt(d)*sqrt(c)*sqrt(a*e + c*d*x)*log((sqrt(e)*sqrt(a*e + c*d*x) + sqrt(d)*sqrt(c)*sqrt(d + e*x))/sqrt(a*e**2 - c*d**2))*a**3*e**6 + 360*sqrt(e)*sqrt(d)*sqrt(c)*sqrt(a*e + c*d*x)*log((sqrt(e)*sqrt(a*e + c*d *x) + sqrt(d)*sqrt(c)*sqrt(d + e*x))/sqrt(a*e**2 - c*d**2))*a**2*c*d**2*e* *4 + 72*sqrt(e)*sqrt(d)*sqrt(c)*sqrt(a*e + c*d*x)*log((sqrt(e)*sqrt(a*e + c*d*x) + sqrt(d)*sqrt(c)*sqrt(d + e*x))/sqrt(a*e**2 - c*d**2))*a*c**2*d**4 *e**2 + 24*sqrt(e)*sqrt(d)*sqrt(c)*sqrt(a*e + c*d*x)*log((sqrt(e)*sqrt(a*e + c*d*x) + sqrt(d)*sqrt(c)*sqrt(d + e*x))/sqrt(a*e**2 - c*d**2))*c**3*d** 6 + 525*sqrt(e)*sqrt(d)*sqrt(c)*sqrt(a*e + c*d*x)*a**3*e**6 - 135*sqrt(e)* sqrt(d)*sqrt(c)*sqrt(a*e + c*d*x)*a**2*c*d**2*e**4 - 9*sqrt(e)*sqrt(d)*sqr t(c)*sqrt(a*e + c*d*x)*a*c**2*d**4*e**2 + 3*sqrt(e)*sqrt(d)*sqrt(c)*sqrt(a *e + c*d*x)*c**3*d**6 + 840*sqrt(d + e*x)*a**3*c*d*e**6 - 80*sqrt(d + e*x) *a**2*c**2*d**3*e**4 + 280*sqrt(d + e*x)*a**2*c**2*d**2*e**5*x - 24*sqrt(d + e*x)*a*c**3*d**5*e**2 - 64*sqrt(d + e*x)*a*c**3*d**4*e**3*x - 112*sqrt( d + e*x)*a*c**3*d**3*e**4*x**2 - 24*sqrt(d + e*x)*c**4*d**6*e*x + 16*sqrt( d + e*x)*c**4*d**5*e**2*x**2 + 64*sqrt(d + e*x)*c**4*d**4*e**3*x**3)/(192* sqrt(a*e + c*d*x)*c**5*d**5*e**3)