\(\int (d+e x)^m (f+g x) (c d^2-b d e-b e^2 x-c e^2 x^2)^{3/2} \, dx\) [250]

Optimal result

Integrand size = 44, antiderivative size = 174 \[ \int (d+e x)^m (f+g x) \left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2} \, dx=-\frac {g (d+e x)^m \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{c e^2 (5+m)}+\frac {(b e g (5+2 m)-2 c (d g m+e f (5+m))) (d+e x)^m \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2} \operatorname {Hypergeometric2F1}\left (1,5+m,\frac {7}{2},\frac {c d-b e-c e x}{2 c d-b e}\right )}{5 c e^2 (2 c d-b e) (5+m)} \] Output:

-g*(e*x+d)^m*(d*(-b*e+c*d)-b*e^2*x-c*e^2*x^2)^(5/2)/c/e^2/(5+m)+1/5*(b*e*g 
*(5+2*m)-2*c*(d*g*m+e*f*(5+m)))*(e*x+d)^m*(d*(-b*e+c*d)-b*e^2*x-c*e^2*x^2) 
^(5/2)*hypergeom([1, 5+m],[7/2],(-c*e*x-b*e+c*d)/(-b*e+2*c*d))/c/e^2/(-b*e 
+2*c*d)/(5+m)
 

Mathematica [A] (warning: unable to verify)

Time = 1.19 (sec) , antiderivative size = 170, normalized size of antiderivative = 0.98 \[ \int (d+e x)^m (f+g x) \left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2} \, dx=\frac {(d+e x)^m (-c d+b e+c e x)^2 \sqrt {(d+e x) (-b e+c (d-e x))} \left (-5 c^2 g (d+e x)^2+(-2 c d+b e) (-b e g (5+2 m)+2 c (d g m+e f (5+m))) \left (\frac {c (d+e x)}{2 c d-b e}\right )^{-\frac {1}{2}-m} \operatorname {Hypergeometric2F1}\left (\frac {5}{2},-\frac {3}{2}-m,\frac {7}{2},\frac {-c d+b e+c e x}{-2 c d+b e}\right )\right )}{5 c^3 e^2 (5+m)} \] Input:

Integrate[(d + e*x)^m*(f + g*x)*(c*d^2 - b*d*e - b*e^2*x - c*e^2*x^2)^(3/2 
),x]
 

Output:

((d + e*x)^m*(-(c*d) + b*e + c*e*x)^2*Sqrt[(d + e*x)*(-(b*e) + c*(d - e*x) 
)]*(-5*c^2*g*(d + e*x)^2 + (-2*c*d + b*e)*(-(b*e*g*(5 + 2*m)) + 2*c*(d*g*m 
 + e*f*(5 + m)))*((c*(d + e*x))/(2*c*d - b*e))^(-1/2 - m)*Hypergeometric2F 
1[5/2, -3/2 - m, 7/2, (-(c*d) + b*e + c*e*x)/(-2*c*d + b*e)]))/(5*c^3*e^2* 
(5 + m))
 

Rubi [A] (warning: unable to verify)

Time = 0.88 (sec) , antiderivative size = 226, normalized size of antiderivative = 1.30, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.114, Rules used = {1221, 1139, 1138, 80, 79}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int (f+g x) (d+e x)^m \left (-b d e-b e^2 x+c d^2-c e^2 x^2\right )^{3/2} \, dx\)

\(\Big \downarrow \) 1221

\(\displaystyle -\frac {(b e g (2 m+5)-2 c (d g m+e f (m+5))) \int (d+e x)^m \left (-c x^2 e^2-b x e^2+d (c d-b e)\right )^{3/2}dx}{2 c e (m+5)}-\frac {g (d+e x)^m \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{c e^2 (m+5)}\)

\(\Big \downarrow \) 1139

\(\displaystyle -\frac {(d+e x)^m \left (\frac {e x}{d}+1\right )^{-m} (b e g (2 m+5)-2 c (d g m+e f (m+5))) \int \left (\frac {e x}{d}+1\right )^m \left (-c x^2 e^2-b x e^2+d (c d-b e)\right )^{3/2}dx}{2 c e (m+5)}-\frac {g (d+e x)^m \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{c e^2 (m+5)}\)

\(\Big \downarrow \) 1138

\(\displaystyle -\frac {(d+e x)^m \left (\frac {e x}{d}+1\right )^{-m-\frac {1}{2}} \sqrt {d (c d-b e)-b e^2 x-c e^2 x^2} (b e g (2 m+5)-2 c (d g m+e f (m+5))) \int \left (\frac {e x}{d}+1\right )^{m+\frac {3}{2}} (d (c d-b e)-c d e x)^{3/2}dx}{2 c e (m+5) \sqrt {d (c d-b e)-c d e x}}-\frac {g (d+e x)^m \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{c e^2 (m+5)}\)

\(\Big \downarrow \) 80

\(\displaystyle -\frac {(2 c d-b e) (d+e x)^m \sqrt {d (c d-b e)-b e^2 x-c e^2 x^2} \left (\frac {c (d+e x)}{2 c d-b e}\right )^{-m-\frac {1}{2}} (b e g (2 m+5)-2 c (d g m+e f (m+5))) \int (d (c d-b e)-c d e x)^{3/2} \left (\frac {c d}{2 c d-b e}+\frac {c e x}{2 c d-b e}\right )^{m+\frac {3}{2}}dx}{2 c^2 d e (m+5) \sqrt {d (c d-b e)-c d e x}}-\frac {g (d+e x)^m \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{c e^2 (m+5)}\)

\(\Big \downarrow \) 79

\(\displaystyle \frac {(2 c d-b e) (d+e x)^m (d (c d-b e)-c d e x)^2 \sqrt {d (c d-b e)-b e^2 x-c e^2 x^2} \left (\frac {c (d+e x)}{2 c d-b e}\right )^{-m-\frac {1}{2}} (b e g (2 m+5)-2 c (d g m+e f (m+5))) \operatorname {Hypergeometric2F1}\left (\frac {5}{2},-m-\frac {3}{2},\frac {7}{2},\frac {c d-b e-c e x}{2 c d-b e}\right )}{5 c^3 d^2 e^2 (m+5)}-\frac {g (d+e x)^m \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{c e^2 (m+5)}\)

Input:

Int[(d + e*x)^m*(f + g*x)*(c*d^2 - b*d*e - b*e^2*x - c*e^2*x^2)^(3/2),x]
 

Output:

-((g*(d + e*x)^m*(d*(c*d - b*e) - b*e^2*x - c*e^2*x^2)^(5/2))/(c*e^2*(5 + 
m))) + ((2*c*d - b*e)*(b*e*g*(5 + 2*m) - 2*c*(d*g*m + e*f*(5 + m)))*(d + e 
*x)^m*((c*(d + e*x))/(2*c*d - b*e))^(-1/2 - m)*(d*(c*d - b*e) - c*d*e*x)^2 
*Sqrt[d*(c*d - b*e) - b*e^2*x - c*e^2*x^2]*Hypergeometric2F1[5/2, -3/2 - m 
, 7/2, (c*d - b*e - c*e*x)/(2*c*d - b*e)])/(5*c^3*d^2*e^2*(5 + m))
 

Defintions of rubi rules used

rule 79

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(( 
a + b*x)^(m + 1)/(b*(m + 1)*(b/(b*c - a*d))^n))*Hypergeometric2F1[-n, m + 1 
, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m, n}, x] 
&&  !IntegerQ[m] &&  !IntegerQ[n] && GtQ[b/(b*c - a*d), 0] && (RationalQ[m] 
 ||  !(RationalQ[n] && GtQ[-d/(b*c - a*d), 0]))
 

rule 80

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(c 
 + d*x)^FracPart[n]/((b/(b*c - a*d))^IntPart[n]*(b*((c + d*x)/(b*c - a*d))) 
^FracPart[n])   Int[(a + b*x)^m*Simp[b*(c/(b*c - a*d)) + b*d*(x/(b*c - a*d) 
), x]^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] &&  !IntegerQ[m] &&  !Integ 
erQ[n] && (RationalQ[m] ||  !SimplerQ[n + 1, m + 1])
 

rule 1138

Int[((d_) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Sy 
mbol] :> Simp[d^m*((a + b*x + c*x^2)^FracPart[p]/((1 + e*(x/d))^FracPart[p] 
*(a/d + (c*x)/e)^FracPart[p]))   Int[(1 + e*(x/d))^(m + p)*(a/d + (c/e)*x)^ 
p, x], x] /; FreeQ[{a, b, c, d, e, m}, x] && EqQ[c*d^2 - b*d*e + a*e^2, 0] 
&& (IntegerQ[m] || GtQ[d, 0]) &&  !(IGtQ[m, 0] && (IntegerQ[3*p] || Integer 
Q[4*p]))
 

rule 1139

Int[((d_) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Sy 
mbol] :> Simp[d^IntPart[m]*((d + e*x)^FracPart[m]/(1 + e*(x/d))^FracPart[m] 
)   Int[(1 + e*(x/d))^m*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e 
, m}, x] && EqQ[c*d^2 - b*d*e + a*e^2, 0] &&  !(IntegerQ[m] || GtQ[d, 0])
 

rule 1221

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c 
_.)*(x_)^2)^(p_), x_Symbol] :> Simp[g*(d + e*x)^m*((a + b*x + c*x^2)^(p + 1 
)/(c*(m + 2*p + 2))), x] + Simp[(m*(g*(c*d - b*e) + c*e*f) + e*(p + 1)*(2*c 
*f - b*g))/(c*e*(m + 2*p + 2))   Int[(d + e*x)^m*(a + b*x + c*x^2)^p, x], x 
] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x] && EqQ[c*d^2 - b*d*e + a*e^2, 0] 
 && NeQ[m + 2*p + 2, 0]
 

Maple [F]

\[\int \left (e x +d \right )^{m} \left (g x +f \right ) \left (-x^{2} c \,e^{2}-x b \,e^{2}-b d e +c \,d^{2}\right )^{\frac {3}{2}}d x\]

Input:

int((e*x+d)^m*(g*x+f)*(-c*e^2*x^2-b*e^2*x-b*d*e+c*d^2)^(3/2),x)
 

Output:

int((e*x+d)^m*(g*x+f)*(-c*e^2*x^2-b*e^2*x-b*d*e+c*d^2)^(3/2),x)
 

Fricas [F]

\[ \int (d+e x)^m (f+g x) \left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2} \, dx=\int { {\left (-c e^{2} x^{2} - b e^{2} x + c d^{2} - b d e\right )}^{\frac {3}{2}} {\left (g x + f\right )} {\left (e x + d\right )}^{m} \,d x } \] Input:

integrate((e*x+d)^m*(g*x+f)*(-c*e^2*x^2-b*e^2*x-b*d*e+c*d^2)^(3/2),x, algo 
rithm="fricas")
 

Output:

integral(-(c*e^2*g*x^3 + (c*e^2*f + b*e^2*g)*x^2 - (c*d^2 - b*d*e)*f + (b* 
e^2*f - (c*d^2 - b*d*e)*g)*x)*sqrt(-c*e^2*x^2 - b*e^2*x + c*d^2 - b*d*e)*( 
e*x + d)^m, x)
 

Sympy [F]

\[ \int (d+e x)^m (f+g x) \left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2} \, dx=\int \left (- \left (d + e x\right ) \left (b e - c d + c e x\right )\right )^{\frac {3}{2}} \left (d + e x\right )^{m} \left (f + g x\right )\, dx \] Input:

integrate((e*x+d)**m*(g*x+f)*(-c*e**2*x**2-b*e**2*x-b*d*e+c*d**2)**(3/2),x 
)
 

Output:

Integral((-(d + e*x)*(b*e - c*d + c*e*x))**(3/2)*(d + e*x)**m*(f + g*x), x 
)
 

Maxima [F]

\[ \int (d+e x)^m (f+g x) \left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2} \, dx=\int { {\left (-c e^{2} x^{2} - b e^{2} x + c d^{2} - b d e\right )}^{\frac {3}{2}} {\left (g x + f\right )} {\left (e x + d\right )}^{m} \,d x } \] Input:

integrate((e*x+d)^m*(g*x+f)*(-c*e^2*x^2-b*e^2*x-b*d*e+c*d^2)^(3/2),x, algo 
rithm="maxima")
 

Output:

integrate((-c*e^2*x^2 - b*e^2*x + c*d^2 - b*d*e)^(3/2)*(g*x + f)*(e*x + d) 
^m, x)
 

Giac [F]

\[ \int (d+e x)^m (f+g x) \left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2} \, dx=\int { {\left (-c e^{2} x^{2} - b e^{2} x + c d^{2} - b d e\right )}^{\frac {3}{2}} {\left (g x + f\right )} {\left (e x + d\right )}^{m} \,d x } \] Input:

integrate((e*x+d)^m*(g*x+f)*(-c*e^2*x^2-b*e^2*x-b*d*e+c*d^2)^(3/2),x, algo 
rithm="giac")
 

Output:

integrate((-c*e^2*x^2 - b*e^2*x + c*d^2 - b*d*e)^(3/2)*(g*x + f)*(e*x + d) 
^m, x)
 

Mupad [F(-1)]

Timed out. \[ \int (d+e x)^m (f+g x) \left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2} \, dx=\int \left (f+g\,x\right )\,{\left (d+e\,x\right )}^m\,{\left (c\,d^2-b\,d\,e-c\,e^2\,x^2-b\,e^2\,x\right )}^{3/2} \,d x \] Input:

int((f + g*x)*(d + e*x)^m*(c*d^2 - c*e^2*x^2 - b*d*e - b*e^2*x)^(3/2),x)
 

Output:

int((f + g*x)*(d + e*x)^m*(c*d^2 - c*e^2*x^2 - b*d*e - b*e^2*x)^(3/2), x)
 

Reduce [F]

\[ \int (d+e x)^m (f+g x) \left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2} \, dx=\int \left (e x +d \right )^{m} \left (g x +f \right ) \left (-c \,e^{2} x^{2}-b \,e^{2} x -b d e +c \,d^{2}\right )^{\frac {3}{2}}d x \] Input:

int((e*x+d)^m*(g*x+f)*(-c*e^2*x^2-b*e^2*x-b*d*e+c*d^2)^(3/2),x)
 

Output:

int((e*x+d)^m*(g*x+f)*(-c*e^2*x^2-b*e^2*x-b*d*e+c*d^2)^(3/2),x)