Integrand size = 44, antiderivative size = 258 \[ \int \frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x) (f+g x)^3} \, dx=\frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{2 (e f-d g) (f+g x)^2}-\frac {\left (3 a e^2 g-c d (2 e f+d g)\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{4 (e f-d g)^2 (c d f-a e g) (f+g x)}+\frac {\left (c d^2-a e^2\right ) \left (3 a e^2 g-c d (4 e f-d g)\right ) \text {arctanh}\left (\frac {\sqrt {c d f-a e g} (d+e x)}{\sqrt {e f-d g} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}\right )}{4 (e f-d g)^{5/2} (c d f-a e g)^{3/2}} \] Output:
1/2*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2)/(-d*g+e*f)/(g*x+f)^2-1/4*(3*a* e^2*g-c*d*(d*g+2*e*f))*(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2)/(-d*g+e*f)^ 2/(-a*e*g+c*d*f)/(g*x+f)+1/4*(-a*e^2+c*d^2)*(3*a*e^2*g-c*d*(-d*g+4*e*f))*a rctanh((-a*e*g+c*d*f)^(1/2)*(e*x+d)/(-d*g+e*f)^(1/2)/(a*d*e+(a*e^2+c*d^2)* x+c*d*e*x^2)^(1/2))/(-d*g+e*f)^(5/2)/(-a*e*g+c*d*f)^(3/2)
Time = 10.48 (sec) , antiderivative size = 235, normalized size of antiderivative = 0.91 \[ \int \frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x) (f+g x)^3} \, dx=\frac {\sqrt {(a e+c d x) (d+e x)} \left (-\frac {g (a e+c d x)}{(f+g x)^2}-\frac {\left (3 a e^2 g+c d (-4 e f+d g)\right ) \left (\frac {\sqrt {a e+c d x} \sqrt {d+e x}}{(e f-d g) (f+g x)}+\frac {\left (-c d^2+a e^2\right ) \text {arctanh}\left (\frac {\sqrt {e f-d g} \sqrt {a e+c d x}}{\sqrt {c d f-a e g} \sqrt {d+e x}}\right )}{(e f-d g)^{3/2} \sqrt {c d f-a e g}}\right )}{2 \sqrt {a e+c d x} \sqrt {d+e x}}\right )}{2 (-e f+d g) (-c d f+a e g)} \] Input:
Integrate[Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2]/((d + e*x)*(f + g*x) ^3),x]
Output:
(Sqrt[(a*e + c*d*x)*(d + e*x)]*(-((g*(a*e + c*d*x))/(f + g*x)^2) - ((3*a*e ^2*g + c*d*(-4*e*f + d*g))*((Sqrt[a*e + c*d*x]*Sqrt[d + e*x])/((e*f - d*g) *(f + g*x)) + ((-(c*d^2) + a*e^2)*ArcTanh[(Sqrt[e*f - d*g]*Sqrt[a*e + c*d* x])/(Sqrt[c*d*f - a*e*g]*Sqrt[d + e*x])])/((e*f - d*g)^(3/2)*Sqrt[c*d*f - a*e*g])))/(2*Sqrt[a*e + c*d*x]*Sqrt[d + e*x])))/(2*(-(e*f) + d*g)*(-(c*d*f ) + a*e*g))
Time = 0.62 (sec) , antiderivative size = 309, normalized size of antiderivative = 1.20, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {1215, 1237, 27, 1228, 1154, 219}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{(d+e x) (f+g x)^3} \, dx\) |
\(\Big \downarrow \) 1215 |
\(\displaystyle \int \frac {a e+c d x}{(f+g x)^3 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}dx\) |
\(\Big \downarrow \) 1237 |
\(\displaystyle \frac {\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{2 (f+g x)^2 (e f-d g)}-\frac {\int \frac {(c d f-a e g) \left (c d^2-2 c e x d-3 a e^2\right )}{2 (f+g x)^2 \sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}dx}{2 (e f-d g) (c d f-a e g)}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{2 (f+g x)^2 (e f-d g)}-\frac {\int \frac {c d^2-2 c e x d-3 a e^2}{(f+g x)^2 \sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}dx}{4 (e f-d g)}\) |
\(\Big \downarrow \) 1228 |
\(\displaystyle \frac {\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{2 (f+g x)^2 (e f-d g)}-\frac {\frac {\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (3 a e^2 g-c d (d g+2 e f)\right )}{(f+g x) (e f-d g) (c d f-a e g)}-\frac {\left (c d^2-a e^2\right ) \left (3 a e^2 g-c d (4 e f-d g)\right ) \int \frac {1}{(f+g x) \sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}dx}{2 (e f-d g) (c d f-a e g)}}{4 (e f-d g)}\) |
\(\Big \downarrow \) 1154 |
\(\displaystyle \frac {\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{2 (f+g x)^2 (e f-d g)}-\frac {\frac {\left (c d^2-a e^2\right ) \left (3 a e^2 g-c d (4 e f-d g)\right ) \int \frac {1}{4 (e f-d g) (c d f-a e g)-\frac {\left (c f d^2+a e (e f-2 d g)-\left (a e^2 g-c d (2 e f-d g)\right ) x\right )^2}{c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}d\left (-\frac {c f d^2+a e (e f-2 d g)-\left (a e^2 g-c d (2 e f-d g)\right ) x}{\sqrt {c d e x^2+\left (c d^2+a e^2\right ) x+a d e}}\right )}{(e f-d g) (c d f-a e g)}+\frac {\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (3 a e^2 g-c d (d g+2 e f)\right )}{(f+g x) (e f-d g) (c d f-a e g)}}{4 (e f-d g)}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle \frac {\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{2 (f+g x)^2 (e f-d g)}-\frac {\frac {\sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2} \left (3 a e^2 g-c d (d g+2 e f)\right )}{(f+g x) (e f-d g) (c d f-a e g)}-\frac {\left (c d^2-a e^2\right ) \left (3 a e^2 g-c d (4 e f-d g)\right ) \text {arctanh}\left (\frac {-x \left (a e^2 g-c d (2 e f-d g)\right )+a e (e f-2 d g)+c d^2 f}{2 \sqrt {e f-d g} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2} \sqrt {c d f-a e g}}\right )}{2 (e f-d g)^{3/2} (c d f-a e g)^{3/2}}}{4 (e f-d g)}\) |
Input:
Int[Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2]/((d + e*x)*(f + g*x)^3),x]
Output:
Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2]/(2*(e*f - d*g)*(f + g*x)^2) - (((3*a*e^2*g - c*d*(2*e*f + d*g))*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x ^2])/((e*f - d*g)*(c*d*f - a*e*g)*(f + g*x)) - ((c*d^2 - a*e^2)*(3*a*e^2*g - c*d*(4*e*f - d*g))*ArcTanh[(c*d^2*f + a*e*(e*f - 2*d*g) - (a*e^2*g - c* d*(2*e*f - d*g))*x)/(2*Sqrt[e*f - d*g]*Sqrt[c*d*f - a*e*g]*Sqrt[a*d*e + (c *d^2 + a*e^2)*x + c*d*e*x^2])])/(2*(e*f - d*g)^(3/2)*(c*d*f - a*e*g)^(3/2) ))/(4*(e*f - d*g))
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Int[1/(((d_.) + (e_.)*(x_))*Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2]), x_Sym bol] :> Simp[-2 Subst[Int[1/(4*c*d^2 - 4*b*d*e + 4*a*e^2 - x^2), x], x, ( 2*a*e - b*d - (2*c*d - b*e)*x)/Sqrt[a + b*x + c*x^2]], x] /; FreeQ[{a, b, c , d, e}, x]
Int[(((f_.) + (g_.)*(x_))^(n_.)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_))/( (d_) + (e_.)*(x_)), x_Symbol] :> Int[(a/d + c*(x/e))*(f + g*x)^n*(a + b*x + c*x^2)^(p - 1), x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && EqQ[c*d^2 - b*d*e + a*e^2, 0] && GtQ[p, 0]
Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c _.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(-(e*f - d*g))*(d + e*x)^(m + 1)*((a + b*x + c*x^2)^(p + 1)/(2*(p + 1)*(c*d^2 - b*d*e + a*e^2))), x] - Simp[(b*(e *f + d*g) - 2*(c*d*f + a*e*g))/(2*(c*d^2 - b*d*e + a*e^2)) Int[(d + e*x)^ (m + 1)*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x ] && EqQ[Simplify[m + 2*p + 3], 0]
Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c _.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(e*f - d*g)*(d + e*x)^(m + 1)*((a + b* x + c*x^2)^(p + 1)/((m + 1)*(c*d^2 - b*d*e + a*e^2))), x] + Simp[1/((m + 1) *(c*d^2 - b*d*e + a*e^2)) Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p*Simp[ (c*d*f - f*b*e + a*e*g)*(m + 1) + b*(d*g - e*f)*(p + 1) - c*(e*f - d*g)*(m + 2*p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && LtQ[m, -1 ] && (IntegerQ[m] || IntegerQ[p] || IntegersQ[2*m, 2*p])
Leaf count of result is larger than twice the leaf count of optimal. \(3573\) vs. \(2(238)=476\).
Time = 3.05 (sec) , antiderivative size = 3574, normalized size of antiderivative = 13.85
Input:
int((a*d*e+(a*e^2+c*d^2)*x+c*d*x^2*e)^(1/2)/(e*x+d)/(g*x+f)^3,x,method=_RE TURNVERBOSE)
Output:
1/g^2/(d*g-e*f)*(-1/2/(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)*g^2/(x+f/g )^2*(c*d*(x+f/g)^2*e+(a*e^2*g+c*d^2*g-2*c*d*e*f)/g*(x+f/g)+(a*d*e*g^2-a*e^ 2*f*g-c*d^2*f*g+c*d*e*f^2)/g^2)^(3/2)-1/4*(a*e^2*g+c*d^2*g-2*c*d*e*f)*g/(a *d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)*(-1/(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g +c*d*e*f^2)*g^2/(x+f/g)*(c*d*(x+f/g)^2*e+(a*e^2*g+c*d^2*g-2*c*d*e*f)/g*(x+ f/g)+(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)/g^2)^(3/2)+1/2*(a*e^2*g+c*d ^2*g-2*c*d*e*f)*g/(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)*((c*d*(x+f/g)^ 2*e+(a*e^2*g+c*d^2*g-2*c*d*e*f)/g*(x+f/g)+(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c *d*e*f^2)/g^2)^(1/2)+1/2*(a*e^2*g+c*d^2*g-2*c*d*e*f)/g*ln((1/2*(a*e^2*g+c* d^2*g-2*c*d*e*f)/g+d*e*c*(x+f/g))/(d*e*c)^(1/2)+(c*d*(x+f/g)^2*e+(a*e^2*g+ c*d^2*g-2*c*d*e*f)/g*(x+f/g)+(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)/g^2 )^(1/2))/(d*e*c)^(1/2)-(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)/g^2/((a*d *e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)/g^2)^(1/2)*ln((2*(a*d*e*g^2-a*e^2*f* g-c*d^2*f*g+c*d*e*f^2)/g^2+(a*e^2*g+c*d^2*g-2*c*d*e*f)/g*(x+f/g)+2*((a*d*e *g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)/g^2)^(1/2)*(c*d*(x+f/g)^2*e+(a*e^2*g+c *d^2*g-2*c*d*e*f)/g*(x+f/g)+(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)/g^2) ^(1/2))/(x+f/g)))+2*d*e*c/(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)*g^2*(1 /4*(2*d*e*c*(x+f/g)+(a*e^2*g+c*d^2*g-2*c*d*e*f)/g)/d/e/c*(c*d*(x+f/g)^2*e+ (a*e^2*g+c*d^2*g-2*c*d*e*f)/g*(x+f/g)+(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e *f^2)/g^2)^(1/2)+1/8*(4*d*e*c*(a*d*e*g^2-a*e^2*f*g-c*d^2*f*g+c*d*e*f^2)...
Leaf count of result is larger than twice the leaf count of optimal. 1192 vs. \(2 (238) = 476\).
Time = 14.73 (sec) , antiderivative size = 2441, normalized size of antiderivative = 9.46 \[ \int \frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x) (f+g x)^3} \, dx=\text {Too large to display} \] Input:
integrate((a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2)/(e*x+d)/(g*x+f)^3,x, alg orithm="fricas")
Output:
[-1/16*(sqrt(c*d*e*f^2 + a*d*e*g^2 - (c*d^2 + a*e^2)*f*g)*(4*(c^2*d^3*e - a*c*d*e^3)*f^3 - (c^2*d^4 + 2*a*c*d^2*e^2 - 3*a^2*e^4)*f^2*g + (4*(c^2*d^3 *e - a*c*d*e^3)*f*g^2 - (c^2*d^4 + 2*a*c*d^2*e^2 - 3*a^2*e^4)*g^3)*x^2 + 2 *(4*(c^2*d^3*e - a*c*d*e^3)*f^2*g - (c^2*d^4 + 2*a*c*d^2*e^2 - 3*a^2*e^4)* f*g^2)*x)*log((8*a^2*d^2*e^2*g^2 + (c^2*d^4 + 6*a*c*d^2*e^2 + a^2*e^4)*f^2 - 8*(a*c*d^3*e + a^2*d*e^3)*f*g + (8*c^2*d^2*e^2*f^2 - 8*(c^2*d^3*e + a*c *d*e^3)*f*g + (c^2*d^4 + 6*a*c*d^2*e^2 + a^2*e^4)*g^2)*x^2 - 4*sqrt(c*d*e* f^2 + a*d*e*g^2 - (c*d^2 + a*e^2)*f*g)*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a *e^2)*x)*(2*a*d*e*g - (c*d^2 + a*e^2)*f - (2*c*d*e*f - (c*d^2 + a*e^2)*g)* x) + 2*(4*(c^2*d^3*e + a*c*d*e^3)*f^2 - (3*c^2*d^4 + 10*a*c*d^2*e^2 + 3*a^ 2*e^4)*f*g + 4*(a*c*d^3*e + a^2*d*e^3)*g^2)*x)/(g^2*x^2 + 2*f*g*x + f^2)) - 4*(4*c^2*d^2*e^2*f^4 + 2*a^2*d^2*e^2*g^4 - (5*c^2*d^3*e + 9*a*c*d*e^3)*f ^3*g + (c^2*d^4 + 12*a*c*d^2*e^2 + 5*a^2*e^4)*f^2*g^2 - (3*a*c*d^3*e + 7*a ^2*d*e^3)*f*g^3 + (2*c^2*d^2*e^2*f^3*g - (c^2*d^3*e + 5*a*c*d*e^3)*f^2*g^2 - (c^2*d^4 - 4*a*c*d^2*e^2 - 3*a^2*e^4)*f*g^3 + (a*c*d^3*e - 3*a^2*d*e^3) *g^4)*x)*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x))/(c^2*d^2*e^3*f^7 - a ^2*d^3*e^2*f^2*g^5 - (3*c^2*d^3*e^2 + 2*a*c*d*e^4)*f^6*g + (3*c^2*d^4*e + 6*a*c*d^2*e^3 + a^2*e^5)*f^5*g^2 - (c^2*d^5 + 6*a*c*d^3*e^2 + 3*a^2*d*e^4) *f^4*g^3 + (2*a*c*d^4*e + 3*a^2*d^2*e^3)*f^3*g^4 + (c^2*d^2*e^3*f^5*g^2 - a^2*d^3*e^2*g^7 - (3*c^2*d^3*e^2 + 2*a*c*d*e^4)*f^4*g^3 + (3*c^2*d^4*e ...
\[ \int \frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x) (f+g x)^3} \, dx=\int \frac {\sqrt {\left (d + e x\right ) \left (a e + c d x\right )}}{\left (d + e x\right ) \left (f + g x\right )^{3}}\, dx \] Input:
integrate((a*d*e+(a*e**2+c*d**2)*x+c*d*e*x**2)**(1/2)/(e*x+d)/(g*x+f)**3,x )
Output:
Integral(sqrt((d + e*x)*(a*e + c*d*x))/((d + e*x)*(f + g*x)**3), x)
\[ \int \frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x) (f+g x)^3} \, dx=\int { \frac {\sqrt {c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x}}{{\left (e x + d\right )} {\left (g x + f\right )}^{3}} \,d x } \] Input:
integrate((a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2)/(e*x+d)/(g*x+f)^3,x, alg orithm="maxima")
Output:
integrate(sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)/((e*x + d)*(g*x + f) ^3), x)
Leaf count of result is larger than twice the leaf count of optimal. 1848 vs. \(2 (238) = 476\).
Time = 0.39 (sec) , antiderivative size = 1848, normalized size of antiderivative = 7.16 \[ \int \frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x) (f+g x)^3} \, dx=\text {Too large to display} \] Input:
integrate((a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2)/(e*x+d)/(g*x+f)^3,x, alg orithm="giac")
Output:
-1/4*(4*c^2*d^3*e*f - 4*a*c*d*e^3*f - c^2*d^4*g - 2*a*c*d^2*e^2*g + 3*a^2* e^4*g)*arctan(-((sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d* e))*g + sqrt(c*d*e)*f)/sqrt(-c*d*e*f^2 + c*d^2*f*g + a*e^2*f*g - a*d*e*g^2 ))/((c*d*e^2*f^3 - 2*c*d^2*e*f^2*g - a*e^3*f^2*g + c*d^3*f*g^2 + 2*a*d*e^2 *f*g^2 - a*d^2*e*g^3)*sqrt(-c*d*e*f^2 + c*d^2*f*g + a*e^2*f*g - a*d*e*g^2) ) + 1/4*(8*(sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))*c ^3*d^4*e^2*f^3 + 8*(sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a *d*e))*a*c^2*d^2*e^4*f^3 - 32*(sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))*a*c^2*d^3*e^3*f^2*g - 16*(sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))*a^2*c*d*e^5*f^2*g + (sqrt(c*d*e)*x - sqrt(c *d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))*c^3*d^6*f*g^2 + 7*(sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))*a*c^2*d^4*e^2*f*g^2 + 35*(sqr t(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))*a^2*c*d^2*e^4*f* g^2 + 5*(sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))*a^3* e^6*f*g^2 - (sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))* a*c^2*d^5*e*g^3 - 10*(sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))*a^2*c*d^3*e^3*g^3 - 5*(sqrt(c*d*e)*x - sqrt(c*d*e*x^2 + c*d^2*x + a*e^2*x + a*d*e))*a^3*d*e^5*g^3 + 2*sqrt(c*d*e)*c^3*d^5*e*f^3 + 4*sqrt(c* d*e)*a*c^2*d^3*e^3*f^3 + 2*sqrt(c*d*e)*a^2*c*d*e^5*f^3 + sqrt(c*d*e)*c^3*d ^6*f^2*g - 9*sqrt(c*d*e)*a*c^2*d^4*e^2*f^2*g - 13*sqrt(c*d*e)*a^2*c*d^2...
Timed out. \[ \int \frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x) (f+g x)^3} \, dx=\int \frac {\sqrt {c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e}}{{\left (f+g\,x\right )}^3\,\left (d+e\,x\right )} \,d x \] Input:
int((x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(1/2)/((f + g*x)^3*(d + e*x)), x)
Output:
int((x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(1/2)/((f + g*x)^3*(d + e*x)), x)
Time = 2.22 (sec) , antiderivative size = 11755, normalized size of antiderivative = 45.56 \[ \int \frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{(d+e x) (f+g x)^3} \, dx =\text {Too large to display} \] Input:
int((a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(1/2)/(e*x+d)/(g*x+f)^3,x)
Output:
(3*sqrt(d*g - e*f)*sqrt(a*e*g - c*d*f)*log(sqrt(g)*sqrt(e)*sqrt(a*e + c*d* x) - sqrt(2*sqrt(e)*sqrt(d)*sqrt(c)*sqrt(d*g - e*f)*sqrt(a*e*g - c*d*f) + a*e**2*g + c*d**2*g - 2*c*d*e*f) + sqrt(g)*sqrt(d)*sqrt(c)*sqrt(d + e*x))* a**3*e**6*f**2*g**3 + 6*sqrt(d*g - e*f)*sqrt(a*e*g - c*d*f)*log(sqrt(g)*sq rt(e)*sqrt(a*e + c*d*x) - sqrt(2*sqrt(e)*sqrt(d)*sqrt(c)*sqrt(d*g - e*f)*s qrt(a*e*g - c*d*f) + a*e**2*g + c*d**2*g - 2*c*d*e*f) + sqrt(g)*sqrt(d)*sq rt(c)*sqrt(d + e*x))*a**3*e**6*f*g**4*x + 3*sqrt(d*g - e*f)*sqrt(a*e*g - c *d*f)*log(sqrt(g)*sqrt(e)*sqrt(a*e + c*d*x) - sqrt(2*sqrt(e)*sqrt(d)*sqrt( c)*sqrt(d*g - e*f)*sqrt(a*e*g - c*d*f) + a*e**2*g + c*d**2*g - 2*c*d*e*f) + sqrt(g)*sqrt(d)*sqrt(c)*sqrt(d + e*x))*a**3*e**6*g**5*x**2 + sqrt(d*g - e*f)*sqrt(a*e*g - c*d*f)*log(sqrt(g)*sqrt(e)*sqrt(a*e + c*d*x) - sqrt(2*sq rt(e)*sqrt(d)*sqrt(c)*sqrt(d*g - e*f)*sqrt(a*e*g - c*d*f) + a*e**2*g + c*d **2*g - 2*c*d*e*f) + sqrt(g)*sqrt(d)*sqrt(c)*sqrt(d + e*x))*a**2*c*d**2*e* *4*f**2*g**3 + 2*sqrt(d*g - e*f)*sqrt(a*e*g - c*d*f)*log(sqrt(g)*sqrt(e)*s qrt(a*e + c*d*x) - sqrt(2*sqrt(e)*sqrt(d)*sqrt(c)*sqrt(d*g - e*f)*sqrt(a*e *g - c*d*f) + a*e**2*g + c*d**2*g - 2*c*d*e*f) + sqrt(g)*sqrt(d)*sqrt(c)*s qrt(d + e*x))*a**2*c*d**2*e**4*f*g**4*x + sqrt(d*g - e*f)*sqrt(a*e*g - c*d *f)*log(sqrt(g)*sqrt(e)*sqrt(a*e + c*d*x) - sqrt(2*sqrt(e)*sqrt(d)*sqrt(c) *sqrt(d*g - e*f)*sqrt(a*e*g - c*d*f) + a*e**2*g + c*d**2*g - 2*c*d*e*f) + sqrt(g)*sqrt(d)*sqrt(c)*sqrt(d + e*x))*a**2*c*d**2*e**4*g**5*x**2 - 10*...