\(\int \frac {(A+B x) (a+b x+c x^2)^p}{x^2} \, dx\) [245]

Optimal result

Integrand size = 21, antiderivative size = 274 \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^p}{x^2} \, dx=-\frac {A \left (a+b x+c x^2\right )^{1+p}}{a x}+\frac {2^{-1+2 p} (a B+A b p) \left (\frac {b-\sqrt {b^2-4 a c}+2 c x}{c x}\right )^{-p} \left (\frac {b+\sqrt {b^2-4 a c}+2 c x}{c x}\right )^{-p} \left (a+b x+c x^2\right )^p \operatorname {AppellF1}\left (-2 p,-p,-p,1-2 p,-\frac {b-\sqrt {b^2-4 a c}}{2 c x},-\frac {b+\sqrt {b^2-4 a c}}{2 c x}\right )}{a p}+\frac {2^{-1-2 p} A (1+2 p) (b+2 c x) \left (a+b x+c x^2\right )^p \left (-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},-p,\frac {3}{2},\frac {(b+2 c x)^2}{b^2-4 a c}\right )}{a} \] Output:

-A*(c*x^2+b*x+a)^(p+1)/a/x+2^(-1+2*p)*(A*b*p+B*a)*(c*x^2+b*x+a)^p*AppellF1 
(-2*p,-p,-p,1-2*p,-1/2*(b-(-4*a*c+b^2)^(1/2))/c/x,-1/2*(b+(-4*a*c+b^2)^(1/ 
2))/c/x)/a/p/(((b-(-4*a*c+b^2)^(1/2)+2*c*x)/c/x)^p)/(((b+(-4*a*c+b^2)^(1/2 
)+2*c*x)/c/x)^p)+2^(-1-2*p)*A*(1+2*p)*(2*c*x+b)*(c*x^2+b*x+a)^p*hypergeom( 
[1/2, -p],[3/2],(2*c*x+b)^2/(-4*a*c+b^2))/a/((-c*(c*x^2+b*x+a)/(-4*a*c+b^2 
))^p)
 

Mathematica [A] (warning: unable to verify)

Time = 0.65 (sec) , antiderivative size = 289, normalized size of antiderivative = 1.05 \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^p}{x^2} \, dx=\frac {\left (1+\frac {b-\sqrt {b^2-4 a c}}{2 c x}\right )^{-p} \left (\frac {b-\sqrt {b^2-4 a c}}{2 c}+x\right )^{-p} \left (\frac {b-\sqrt {b^2-4 a c}+2 c x}{c}\right )^p \left (\frac {b+\sqrt {b^2-4 a c}+2 c x}{c x}\right )^{-p} (a+x (b+c x))^p \left (2 A p \operatorname {AppellF1}\left (1-2 p,-p,-p,2-2 p,-\frac {b+\sqrt {b^2-4 a c}}{2 c x},\frac {-b+\sqrt {b^2-4 a c}}{2 c x}\right )+B (-1+2 p) x \operatorname {AppellF1}\left (-2 p,-p,-p,1-2 p,-\frac {b+\sqrt {b^2-4 a c}}{2 c x},\frac {-b+\sqrt {b^2-4 a c}}{2 c x}\right )\right )}{2 p (-1+2 p) x} \] Input:

Integrate[((A + B*x)*(a + b*x + c*x^2)^p)/x^2,x]
 

Output:

(((b - Sqrt[b^2 - 4*a*c] + 2*c*x)/c)^p*(a + x*(b + c*x))^p*(2*A*p*AppellF1 
[1 - 2*p, -p, -p, 2 - 2*p, -1/2*(b + Sqrt[b^2 - 4*a*c])/(c*x), (-b + Sqrt[ 
b^2 - 4*a*c])/(2*c*x)] + B*(-1 + 2*p)*x*AppellF1[-2*p, -p, -p, 1 - 2*p, -1 
/2*(b + Sqrt[b^2 - 4*a*c])/(c*x), (-b + Sqrt[b^2 - 4*a*c])/(2*c*x)]))/(2*p 
*(-1 + 2*p)*(1 + (b - Sqrt[b^2 - 4*a*c])/(2*c*x))^p*x*((b - Sqrt[b^2 - 4*a 
*c])/(2*c) + x)^p*((b + Sqrt[b^2 - 4*a*c] + 2*c*x)/(c*x))^p)
 

Rubi [A] (warning: unable to verify)

Time = 0.48 (sec) , antiderivative size = 314, normalized size of antiderivative = 1.15, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {1237, 25, 1269, 1096, 1178, 150}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(A+B x) \left (a+b x+c x^2\right )^p}{x^2} \, dx\)

\(\Big \downarrow \) 1237

\(\displaystyle -\frac {\int -\frac {(a B+A b p+A c (2 p+1) x) \left (c x^2+b x+a\right )^p}{x}dx}{a}-\frac {A \left (a+b x+c x^2\right )^{p+1}}{a x}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {\int \frac {(a B+A b p+A c (2 p+1) x) \left (c x^2+b x+a\right )^p}{x}dx}{a}-\frac {A \left (a+b x+c x^2\right )^{p+1}}{a x}\)

\(\Big \downarrow \) 1269

\(\displaystyle \frac {(a B+A b p) \int \frac {\left (c x^2+b x+a\right )^p}{x}dx+A c (2 p+1) \int \left (c x^2+b x+a\right )^pdx}{a}-\frac {A \left (a+b x+c x^2\right )^{p+1}}{a x}\)

\(\Big \downarrow \) 1096

\(\displaystyle \frac {(a B+A b p) \int \frac {\left (c x^2+b x+a\right )^p}{x}dx-\frac {A c 2^{p+1} (2 p+1) \left (-\frac {-\sqrt {b^2-4 a c}+b+2 c x}{\sqrt {b^2-4 a c}}\right )^{-p-1} \left (a+b x+c x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (-p,p+1,p+2,\frac {b+2 c x+\sqrt {b^2-4 a c}}{2 \sqrt {b^2-4 a c}}\right )}{(p+1) \sqrt {b^2-4 a c}}}{a}-\frac {A \left (a+b x+c x^2\right )^{p+1}}{a x}\)

\(\Big \downarrow \) 1178

\(\displaystyle \frac {-4^p \left (\frac {1}{x}\right )^{2 p} (a B+A b p) \left (\frac {-\sqrt {b^2-4 a c}+b+2 c x}{c x}\right )^{-p} \left (\frac {\sqrt {b^2-4 a c}+b+2 c x}{c x}\right )^{-p} \left (a+b x+c x^2\right )^p \int \left (\frac {b-\sqrt {b^2-4 a c}}{2 c x}+1\right )^p \left (\frac {b+\sqrt {b^2-4 a c}}{2 c x}+1\right )^p \left (\frac {1}{x}\right )^{-2 p-1}d\frac {1}{x}-\frac {A c 2^{p+1} (2 p+1) \left (a+b x+c x^2\right )^{p+1} \left (-\frac {-\sqrt {b^2-4 a c}+b+2 c x}{\sqrt {b^2-4 a c}}\right )^{-p-1} \operatorname {Hypergeometric2F1}\left (-p,p+1,p+2,\frac {b+2 c x+\sqrt {b^2-4 a c}}{2 \sqrt {b^2-4 a c}}\right )}{(p+1) \sqrt {b^2-4 a c}}}{a}-\frac {A \left (a+b x+c x^2\right )^{p+1}}{a x}\)

\(\Big \downarrow \) 150

\(\displaystyle \frac {\frac {2^{2 p-1} (a B+A b p) \left (\frac {-\sqrt {b^2-4 a c}+b+2 c x}{c x}\right )^{-p} \left (\frac {\sqrt {b^2-4 a c}+b+2 c x}{c x}\right )^{-p} \left (a+b x+c x^2\right )^p \operatorname {AppellF1}\left (-2 p,-p,-p,1-2 p,-\frac {b-\sqrt {b^2-4 a c}}{2 c x},-\frac {b+\sqrt {b^2-4 a c}}{2 c x}\right )}{p}-\frac {A c 2^{p+1} (2 p+1) \left (-\frac {-\sqrt {b^2-4 a c}+b+2 c x}{\sqrt {b^2-4 a c}}\right )^{-p-1} \left (a+b x+c x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (-p,p+1,p+2,\frac {b+2 c x+\sqrt {b^2-4 a c}}{2 \sqrt {b^2-4 a c}}\right )}{(p+1) \sqrt {b^2-4 a c}}}{a}-\frac {A \left (a+b x+c x^2\right )^{p+1}}{a x}\)

Input:

Int[((A + B*x)*(a + b*x + c*x^2)^p)/x^2,x]
 

Output:

-((A*(a + b*x + c*x^2)^(1 + p))/(a*x)) + ((2^(-1 + 2*p)*(a*B + A*b*p)*(a + 
 b*x + c*x^2)^p*AppellF1[-2*p, -p, -p, 1 - 2*p, -1/2*(b - Sqrt[b^2 - 4*a*c 
])/(c*x), -1/2*(b + Sqrt[b^2 - 4*a*c])/(c*x)])/(p*((b - Sqrt[b^2 - 4*a*c] 
+ 2*c*x)/(c*x))^p*((b + Sqrt[b^2 - 4*a*c] + 2*c*x)/(c*x))^p) - (2^(1 + p)* 
A*c*(1 + 2*p)*(-((b - Sqrt[b^2 - 4*a*c] + 2*c*x)/Sqrt[b^2 - 4*a*c]))^(-1 - 
 p)*(a + b*x + c*x^2)^(1 + p)*Hypergeometric2F1[-p, 1 + p, 2 + p, (b + Sqr 
t[b^2 - 4*a*c] + 2*c*x)/(2*Sqrt[b^2 - 4*a*c])])/(Sqrt[b^2 - 4*a*c]*(1 + p) 
))/a
 

Defintions of rubi rules used

rule 25

Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 150

Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_)*((e_) + (f_.)*(x_))^(p_), x_ 
] :> Simp[c^n*e^p*((b*x)^(m + 1)/(b*(m + 1)))*AppellF1[m + 1, -n, -p, m + 2 
, (-d)*(x/c), (-f)*(x/e)], x] /; FreeQ[{b, c, d, e, f, m, n, p}, x] &&  !In 
tegerQ[m] &&  !IntegerQ[n] && GtQ[c, 0] && (IntegerQ[p] || GtQ[e, 0])
 

rule 1096

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> With[{q = Rt[b^2 
 - 4*a*c, 2]}, Simp[(-(a + b*x + c*x^2)^(p + 1)/(q*(p + 1)*((q - b - 2*c*x) 
/(2*q))^(p + 1)))*Hypergeometric2F1[-p, p + 1, p + 2, (b + q + 2*c*x)/(2*q) 
], x]] /; FreeQ[{a, b, c, p}, x] &&  !IntegerQ[4*p] &&  !IntegerQ[3*p]
 

rule 1178

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_S 
ymbol] :> With[{q = Rt[b^2 - 4*a*c, 2]}, Simp[(-(1/(d + e*x))^(2*p))*((a + 
b*x + c*x^2)^p/(e*(e*((b - q + 2*c*x)/(2*c*(d + e*x))))^p*(e*((b + q + 2*c* 
x)/(2*c*(d + e*x))))^p))   Subst[Int[x^(-m - 2*(p + 1))*Simp[1 - (d - e*((b 
 - q)/(2*c)))*x, x]^p*Simp[1 - (d - e*((b + q)/(2*c)))*x, x]^p, x], x, 1/(d 
 + e*x)], x]] /; FreeQ[{a, b, c, d, e, p}, x] && ILtQ[m, 0]
 

rule 1237

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c 
_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(e*f - d*g)*(d + e*x)^(m + 1)*((a + b* 
x + c*x^2)^(p + 1)/((m + 1)*(c*d^2 - b*d*e + a*e^2))), x] + Simp[1/((m + 1) 
*(c*d^2 - b*d*e + a*e^2))   Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p*Simp[ 
(c*d*f - f*b*e + a*e*g)*(m + 1) + b*(d*g - e*f)*(p + 1) - c*(e*f - d*g)*(m 
+ 2*p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && LtQ[m, -1 
] && (IntegerQ[m] || IntegerQ[p] || IntegersQ[2*m, 2*p])
 

rule 1269

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c 
_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[g/e   Int[(d + e*x)^(m + 1)*(a + b*x + 
 c*x^2)^p, x], x] + Simp[(e*f - d*g)/e   Int[(d + e*x)^m*(a + b*x + c*x^2)^ 
p, x], x] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x] &&  !IGtQ[m, 0]
 

Maple [F]

\[\int \frac {\left (B x +A \right ) \left (c \,x^{2}+b x +a \right )^{p}}{x^{2}}d x\]

Input:

int((B*x+A)*(c*x^2+b*x+a)^p/x^2,x)
 

Output:

int((B*x+A)*(c*x^2+b*x+a)^p/x^2,x)
 

Fricas [F]

\[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^p}{x^2} \, dx=\int { \frac {{\left (B x + A\right )} {\left (c x^{2} + b x + a\right )}^{p}}{x^{2}} \,d x } \] Input:

integrate((B*x+A)*(c*x^2+b*x+a)^p/x^2,x, algorithm="fricas")
 

Output:

integral((B*x + A)*(c*x^2 + b*x + a)^p/x^2, x)
 

Sympy [F]

\[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^p}{x^2} \, dx=\int \frac {\left (A + B x\right ) \left (a + b x + c x^{2}\right )^{p}}{x^{2}}\, dx \] Input:

integrate((B*x+A)*(c*x**2+b*x+a)**p/x**2,x)
 

Output:

Integral((A + B*x)*(a + b*x + c*x**2)**p/x**2, x)
 

Maxima [F]

\[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^p}{x^2} \, dx=\int { \frac {{\left (B x + A\right )} {\left (c x^{2} + b x + a\right )}^{p}}{x^{2}} \,d x } \] Input:

integrate((B*x+A)*(c*x^2+b*x+a)^p/x^2,x, algorithm="maxima")
 

Output:

integrate((B*x + A)*(c*x^2 + b*x + a)^p/x^2, x)
 

Giac [F]

\[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^p}{x^2} \, dx=\int { \frac {{\left (B x + A\right )} {\left (c x^{2} + b x + a\right )}^{p}}{x^{2}} \,d x } \] Input:

integrate((B*x+A)*(c*x^2+b*x+a)^p/x^2,x, algorithm="giac")
 

Output:

integrate((B*x + A)*(c*x^2 + b*x + a)^p/x^2, x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^p}{x^2} \, dx=\int \frac {\left (A+B\,x\right )\,{\left (c\,x^2+b\,x+a\right )}^p}{x^2} \,d x \] Input:

int(((A + B*x)*(a + b*x + c*x^2)^p)/x^2,x)
 

Output:

int(((A + B*x)*(a + b*x + c*x^2)^p)/x^2, x)
 

Reduce [F]

\[ \int \frac {(A+B x) \left (a+b x+c x^2\right )^p}{x^2} \, dx =\text {Too large to display} \] Input:

int((B*x+A)*(c*x^2+b*x+a)^p/x^2,x)
                                                                                    
                                                                                    
 

Output:

( - (a + b*x + c*x**2)**p*a*b*p**2 + (a + b*x + c*x**2)**p*a*b*p - 3*(a + 
b*x + c*x**2)**p*a*c*p*x + (a + b*x + c*x**2)**p*a*c*x + (a + b*x + c*x**2 
)**p*b**2*p*x - (a + b*x + c*x**2)**p*b**2*x + int((a + b*x + c*x**2)**p/( 
a*p*x - a*x + b*p*x**2 - b*x**2 + c*p*x**3 - c*x**3),x)*a*b**2*p**4*x - in 
t((a + b*x + c*x**2)**p/(a*p*x - a*x + b*p*x**2 - b*x**2 + c*p*x**3 - c*x* 
*3),x)*a*b**2*p**3*x - int((a + b*x + c*x**2)**p/(a*p*x - a*x + b*p*x**2 - 
 b*x**2 + c*p*x**3 - c*x**3),x)*a*b**2*p**2*x + int((a + b*x + c*x**2)**p/ 
(a*p*x - a*x + b*p*x**2 - b*x**2 + c*p*x**3 - c*x**3),x)*a*b**2*p*x + 2*in 
t((a + b*x + c*x**2)**p/(a*p - a + b*p*x - b*x + c*p*x**2 - c*x**2),x)*a*b 
*c*p**4*x - int((a + b*x + c*x**2)**p/(a*p - a + b*p*x - b*x + c*p*x**2 - 
c*x**2),x)*a*b*c*p**3*x - 2*int((a + b*x + c*x**2)**p/(a*p - a + b*p*x - b 
*x + c*p*x**2 - c*x**2),x)*a*b*c*p**2*x + int((a + b*x + c*x**2)**p/(a*p - 
 a + b*p*x - b*x + c*p*x**2 - c*x**2),x)*a*b*c*p*x + 6*int(((a + b*x + c*x 
**2)**p*x)/(a*p - a + b*p*x - b*x + c*p*x**2 - c*x**2),x)*a*c**2*p**3*x - 
8*int(((a + b*x + c*x**2)**p*x)/(a*p - a + b*p*x - b*x + c*p*x**2 - c*x**2 
),x)*a*c**2*p**2*x + 2*int(((a + b*x + c*x**2)**p*x)/(a*p - a + b*p*x - b* 
x + c*p*x**2 - c*x**2),x)*a*c**2*p*x - int(((a + b*x + c*x**2)**p*x)/(a*p 
- a + b*p*x - b*x + c*p*x**2 - c*x**2),x)*b**2*c*p**3*x + 2*int(((a + b*x 
+ c*x**2)**p*x)/(a*p - a + b*p*x - b*x + c*p*x**2 - c*x**2),x)*b**2*c*p**2 
*x - int(((a + b*x + c*x**2)**p*x)/(a*p - a + b*p*x - b*x + c*p*x**2 - ...