Integrand size = 19, antiderivative size = 87 \[ \int \frac {x (d+e x)}{\left (a+b x+c x^2\right )^2} \, dx=-\frac {x (b d-2 a e+(2 c d-b e) x)}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}-\frac {2 (b d-2 a e) \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{3/2}} \] Output:
-x*(b*d-2*a*e+(-b*e+2*c*d)*x)/(-4*a*c+b^2)/(c*x^2+b*x+a)-2*(-2*a*e+b*d)*ar ctanh((2*c*x+b)/(-4*a*c+b^2)^(1/2))/(-4*a*c+b^2)^(3/2)
Time = 0.08 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.14 \[ \int \frac {x (d+e x)}{\left (a+b x+c x^2\right )^2} \, dx=\frac {a b e+b (-c d+b e) x-2 a c (d+e x)}{c \left (-b^2+4 a c\right ) (a+x (b+c x))}-\frac {2 (b d-2 a e) \arctan \left (\frac {b+2 c x}{\sqrt {-b^2+4 a c}}\right )}{\left (-b^2+4 a c\right )^{3/2}} \] Input:
Integrate[(x*(d + e*x))/(a + b*x + c*x^2)^2,x]
Output:
(a*b*e + b*(-(c*d) + b*e)*x - 2*a*c*(d + e*x))/(c*(-b^2 + 4*a*c)*(a + x*(b + c*x))) - (2*(b*d - 2*a*e)*ArcTan[(b + 2*c*x)/Sqrt[-b^2 + 4*a*c]])/(-b^2 + 4*a*c)^(3/2)
Time = 0.25 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.14, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {1224, 1083, 219}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x (d+e x)}{\left (a+b x+c x^2\right )^2} \, dx\) |
\(\Big \downarrow \) 1224 |
\(\displaystyle \frac {(b d-2 a e) \int \frac {1}{c x^2+b x+a}dx}{b^2-4 a c}+\frac {x \left (2 a c e+b^2 (-e)+b c d\right )+a (2 c d-b e)}{c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}\) |
\(\Big \downarrow \) 1083 |
\(\displaystyle \frac {x \left (2 a c e+b^2 (-e)+b c d\right )+a (2 c d-b e)}{c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}-\frac {2 (b d-2 a e) \int \frac {1}{b^2-(b+2 c x)^2-4 a c}d(b+2 c x)}{b^2-4 a c}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle \frac {x \left (2 a c e+b^2 (-e)+b c d\right )+a (2 c d-b e)}{c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )}-\frac {2 (b d-2 a e) \text {arctanh}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{3/2}}\) |
Input:
Int[(x*(d + e*x))/(a + b*x + c*x^2)^2,x]
Output:
(a*(2*c*d - b*e) + (b*c*d - b^2*e + 2*a*c*e)*x)/(c*(b^2 - 4*a*c)*(a + b*x + c*x^2)) - (2*(b*d - 2*a*e)*ArcTanh[(b + 2*c*x)/Sqrt[b^2 - 4*a*c]])/(b^2 - 4*a*c)^(3/2)
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Simp[-2 Subst[I nt[1/Simp[b^2 - 4*a*c - x^2, x], x], x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x]
Int[((d_.) + (e_.)*(x_))*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*( x_)^2)^(p_), x_Symbol] :> Simp[(-(2*a*c*(e*f + d*g) - b*(c*d*f + a*e*g) - ( b^2*e*g - b*c*(e*f + d*g) + 2*c*(c*d*f - a*e*g))*x))*((a + b*x + c*x^2)^(p + 1)/(c*(p + 1)*(b^2 - 4*a*c))), x] - Simp[(b^2*e*g*(p + 2) - 2*a*c*e*g + c *(2*c*d*f - b*(e*f + d*g))*(2*p + 3))/(c*(p + 1)*(b^2 - 4*a*c)) Int[(a + b*x + c*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && LtQ[p, - 1] && !(IntegerQ[p] && NeQ[a, 0] && NiceSqrtQ[b^2 - 4*a*c])
Time = 1.20 (sec) , antiderivative size = 118, normalized size of antiderivative = 1.36
method | result | size |
default | \(\frac {-\frac {\left (2 a c e -e \,b^{2}+d b c \right ) x}{\left (4 a c -b^{2}\right ) c}+\frac {a \left (b e -2 c d \right )}{c \left (4 a c -b^{2}\right )}}{c \,x^{2}+b x +a}+\frac {2 \left (2 a e -b d \right ) \arctan \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right )}{\left (4 a c -b^{2}\right )^{\frac {3}{2}}}\) | \(118\) |
risch | \(\frac {-\frac {\left (2 a c e -e \,b^{2}+d b c \right ) x}{\left (4 a c -b^{2}\right ) c}+\frac {a \left (b e -2 c d \right )}{c \left (4 a c -b^{2}\right )}}{c \,x^{2}+b x +a}+\frac {2 \ln \left (\left (-8 a \,c^{2}+2 b^{2} c \right ) x +\left (-4 a c +b^{2}\right )^{\frac {3}{2}}-4 a b c +b^{3}\right ) a e}{\left (-4 a c +b^{2}\right )^{\frac {3}{2}}}-\frac {\ln \left (\left (-8 a \,c^{2}+2 b^{2} c \right ) x +\left (-4 a c +b^{2}\right )^{\frac {3}{2}}-4 a b c +b^{3}\right ) b d}{\left (-4 a c +b^{2}\right )^{\frac {3}{2}}}-\frac {2 \ln \left (\left (8 a \,c^{2}-2 b^{2} c \right ) x +\left (-4 a c +b^{2}\right )^{\frac {3}{2}}+4 a b c -b^{3}\right ) a e}{\left (-4 a c +b^{2}\right )^{\frac {3}{2}}}+\frac {\ln \left (\left (8 a \,c^{2}-2 b^{2} c \right ) x +\left (-4 a c +b^{2}\right )^{\frac {3}{2}}+4 a b c -b^{3}\right ) b d}{\left (-4 a c +b^{2}\right )^{\frac {3}{2}}}\) | \(274\) |
Input:
int(x*(e*x+d)/(c*x^2+b*x+a)^2,x,method=_RETURNVERBOSE)
Output:
(-(2*a*c*e-b^2*e+b*c*d)/(4*a*c-b^2)/c*x+a*(b*e-2*c*d)/c/(4*a*c-b^2))/(c*x^ 2+b*x+a)+2*(2*a*e-b*d)/(4*a*c-b^2)^(3/2)*arctan((2*c*x+b)/(4*a*c-b^2)^(1/2 ))
Leaf count of result is larger than twice the leaf count of optimal. 251 vs. \(2 (83) = 166\).
Time = 0.08 (sec) , antiderivative size = 521, normalized size of antiderivative = 5.99 \[ \int \frac {x (d+e x)}{\left (a+b x+c x^2\right )^2} \, dx=\left [\frac {{\left (a b c d - 2 \, a^{2} c e + {\left (b c^{2} d - 2 \, a c^{2} e\right )} x^{2} + {\left (b^{2} c d - 2 \, a b c e\right )} x\right )} \sqrt {b^{2} - 4 \, a c} \log \left (\frac {2 \, c^{2} x^{2} + 2 \, b c x + b^{2} - 2 \, a c - \sqrt {b^{2} - 4 \, a c} {\left (2 \, c x + b\right )}}{c x^{2} + b x + a}\right ) + 2 \, {\left (a b^{2} c - 4 \, a^{2} c^{2}\right )} d - {\left (a b^{3} - 4 \, a^{2} b c\right )} e + {\left ({\left (b^{3} c - 4 \, a b c^{2}\right )} d - {\left (b^{4} - 6 \, a b^{2} c + 8 \, a^{2} c^{2}\right )} e\right )} x}{a b^{4} c - 8 \, a^{2} b^{2} c^{2} + 16 \, a^{3} c^{3} + {\left (b^{4} c^{2} - 8 \, a b^{2} c^{3} + 16 \, a^{2} c^{4}\right )} x^{2} + {\left (b^{5} c - 8 \, a b^{3} c^{2} + 16 \, a^{2} b c^{3}\right )} x}, -\frac {2 \, {\left (a b c d - 2 \, a^{2} c e + {\left (b c^{2} d - 2 \, a c^{2} e\right )} x^{2} + {\left (b^{2} c d - 2 \, a b c e\right )} x\right )} \sqrt {-b^{2} + 4 \, a c} \arctan \left (-\frac {\sqrt {-b^{2} + 4 \, a c} {\left (2 \, c x + b\right )}}{b^{2} - 4 \, a c}\right ) - 2 \, {\left (a b^{2} c - 4 \, a^{2} c^{2}\right )} d + {\left (a b^{3} - 4 \, a^{2} b c\right )} e - {\left ({\left (b^{3} c - 4 \, a b c^{2}\right )} d - {\left (b^{4} - 6 \, a b^{2} c + 8 \, a^{2} c^{2}\right )} e\right )} x}{a b^{4} c - 8 \, a^{2} b^{2} c^{2} + 16 \, a^{3} c^{3} + {\left (b^{4} c^{2} - 8 \, a b^{2} c^{3} + 16 \, a^{2} c^{4}\right )} x^{2} + {\left (b^{5} c - 8 \, a b^{3} c^{2} + 16 \, a^{2} b c^{3}\right )} x}\right ] \] Input:
integrate(x*(e*x+d)/(c*x^2+b*x+a)^2,x, algorithm="fricas")
Output:
[((a*b*c*d - 2*a^2*c*e + (b*c^2*d - 2*a*c^2*e)*x^2 + (b^2*c*d - 2*a*b*c*e) *x)*sqrt(b^2 - 4*a*c)*log((2*c^2*x^2 + 2*b*c*x + b^2 - 2*a*c - sqrt(b^2 - 4*a*c)*(2*c*x + b))/(c*x^2 + b*x + a)) + 2*(a*b^2*c - 4*a^2*c^2)*d - (a*b^ 3 - 4*a^2*b*c)*e + ((b^3*c - 4*a*b*c^2)*d - (b^4 - 6*a*b^2*c + 8*a^2*c^2)* e)*x)/(a*b^4*c - 8*a^2*b^2*c^2 + 16*a^3*c^3 + (b^4*c^2 - 8*a*b^2*c^3 + 16* a^2*c^4)*x^2 + (b^5*c - 8*a*b^3*c^2 + 16*a^2*b*c^3)*x), -(2*(a*b*c*d - 2*a ^2*c*e + (b*c^2*d - 2*a*c^2*e)*x^2 + (b^2*c*d - 2*a*b*c*e)*x)*sqrt(-b^2 + 4*a*c)*arctan(-sqrt(-b^2 + 4*a*c)*(2*c*x + b)/(b^2 - 4*a*c)) - 2*(a*b^2*c - 4*a^2*c^2)*d + (a*b^3 - 4*a^2*b*c)*e - ((b^3*c - 4*a*b*c^2)*d - (b^4 - 6 *a*b^2*c + 8*a^2*c^2)*e)*x)/(a*b^4*c - 8*a^2*b^2*c^2 + 16*a^3*c^3 + (b^4*c ^2 - 8*a*b^2*c^3 + 16*a^2*c^4)*x^2 + (b^5*c - 8*a*b^3*c^2 + 16*a^2*b*c^3)* x)]
Leaf count of result is larger than twice the leaf count of optimal. 379 vs. \(2 (82) = 164\).
Time = 0.68 (sec) , antiderivative size = 379, normalized size of antiderivative = 4.36 \[ \int \frac {x (d+e x)}{\left (a+b x+c x^2\right )^2} \, dx=- \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \cdot \left (2 a e - b d\right ) \log {\left (x + \frac {- 16 a^{2} c^{2} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \cdot \left (2 a e - b d\right ) + 8 a b^{2} c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \cdot \left (2 a e - b d\right ) + 2 a b e - b^{4} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \cdot \left (2 a e - b d\right ) - b^{2} d}{4 a c e - 2 b c d} \right )} + \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \cdot \left (2 a e - b d\right ) \log {\left (x + \frac {16 a^{2} c^{2} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \cdot \left (2 a e - b d\right ) - 8 a b^{2} c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \cdot \left (2 a e - b d\right ) + 2 a b e + b^{4} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{3}}} \cdot \left (2 a e - b d\right ) - b^{2} d}{4 a c e - 2 b c d} \right )} + \frac {a b e - 2 a c d + x \left (- 2 a c e + b^{2} e - b c d\right )}{4 a^{2} c^{2} - a b^{2} c + x^{2} \cdot \left (4 a c^{3} - b^{2} c^{2}\right ) + x \left (4 a b c^{2} - b^{3} c\right )} \] Input:
integrate(x*(e*x+d)/(c*x**2+b*x+a)**2,x)
Output:
-sqrt(-1/(4*a*c - b**2)**3)*(2*a*e - b*d)*log(x + (-16*a**2*c**2*sqrt(-1/( 4*a*c - b**2)**3)*(2*a*e - b*d) + 8*a*b**2*c*sqrt(-1/(4*a*c - b**2)**3)*(2 *a*e - b*d) + 2*a*b*e - b**4*sqrt(-1/(4*a*c - b**2)**3)*(2*a*e - b*d) - b* *2*d)/(4*a*c*e - 2*b*c*d)) + sqrt(-1/(4*a*c - b**2)**3)*(2*a*e - b*d)*log( x + (16*a**2*c**2*sqrt(-1/(4*a*c - b**2)**3)*(2*a*e - b*d) - 8*a*b**2*c*sq rt(-1/(4*a*c - b**2)**3)*(2*a*e - b*d) + 2*a*b*e + b**4*sqrt(-1/(4*a*c - b **2)**3)*(2*a*e - b*d) - b**2*d)/(4*a*c*e - 2*b*c*d)) + (a*b*e - 2*a*c*d + x*(-2*a*c*e + b**2*e - b*c*d))/(4*a**2*c**2 - a*b**2*c + x**2*(4*a*c**3 - b**2*c**2) + x*(4*a*b*c**2 - b**3*c))
Exception generated. \[ \int \frac {x (d+e x)}{\left (a+b x+c x^2\right )^2} \, dx=\text {Exception raised: ValueError} \] Input:
integrate(x*(e*x+d)/(c*x^2+b*x+a)^2,x, algorithm="maxima")
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(4*a*c-b^2>0)', see `assume?` for more deta
Time = 0.19 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.25 \[ \int \frac {x (d+e x)}{\left (a+b x+c x^2\right )^2} \, dx=\frac {2 \, {\left (b d - 2 \, a e\right )} \arctan \left (\frac {2 \, c x + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{{\left (b^{2} - 4 \, a c\right )} \sqrt {-b^{2} + 4 \, a c}} + \frac {b c d x - b^{2} e x + 2 \, a c e x + 2 \, a c d - a b e}{{\left (b^{2} c - 4 \, a c^{2}\right )} {\left (c x^{2} + b x + a\right )}} \] Input:
integrate(x*(e*x+d)/(c*x^2+b*x+a)^2,x, algorithm="giac")
Output:
2*(b*d - 2*a*e)*arctan((2*c*x + b)/sqrt(-b^2 + 4*a*c))/((b^2 - 4*a*c)*sqrt (-b^2 + 4*a*c)) + (b*c*d*x - b^2*e*x + 2*a*c*e*x + 2*a*c*d - a*b*e)/((b^2* c - 4*a*c^2)*(c*x^2 + b*x + a))
Time = 10.89 (sec) , antiderivative size = 177, normalized size of antiderivative = 2.03 \[ \int \frac {x (d+e x)}{\left (a+b x+c x^2\right )^2} \, dx=\frac {\frac {a\,\left (b\,e-2\,c\,d\right )}{c\,\left (4\,a\,c-b^2\right )}-\frac {x\,\left (-e\,b^2+c\,d\,b+2\,a\,c\,e\right )}{c\,\left (4\,a\,c-b^2\right )}}{c\,x^2+b\,x+a}-\frac {2\,\mathrm {atan}\left (\frac {\left (4\,a\,c-b^2\right )\,\left (\frac {\left (b^3-4\,a\,b\,c\right )\,\left (2\,a\,e-b\,d\right )}{{\left (4\,a\,c-b^2\right )}^{5/2}}-\frac {2\,c\,x\,\left (2\,a\,e-b\,d\right )}{{\left (4\,a\,c-b^2\right )}^{3/2}}\right )}{2\,a\,e-b\,d}\right )\,\left (2\,a\,e-b\,d\right )}{{\left (4\,a\,c-b^2\right )}^{3/2}} \] Input:
int((x*(d + e*x))/(a + b*x + c*x^2)^2,x)
Output:
((a*(b*e - 2*c*d))/(c*(4*a*c - b^2)) - (x*(2*a*c*e - b^2*e + b*c*d))/(c*(4 *a*c - b^2)))/(a + b*x + c*x^2) - (2*atan(((4*a*c - b^2)*(((b^3 - 4*a*b*c) *(2*a*e - b*d))/(4*a*c - b^2)^(5/2) - (2*c*x*(2*a*e - b*d))/(4*a*c - b^2)^ (3/2)))/(2*a*e - b*d))*(2*a*e - b*d))/(4*a*c - b^2)^(3/2)
Time = 0.22 (sec) , antiderivative size = 406, normalized size of antiderivative = 4.67 \[ \int \frac {x (d+e x)}{\left (a+b x+c x^2\right )^2} \, dx=\frac {4 \sqrt {4 a c -b^{2}}\, \mathit {atan} \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right ) a^{2} b e -2 \sqrt {4 a c -b^{2}}\, \mathit {atan} \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right ) a \,b^{2} d +4 \sqrt {4 a c -b^{2}}\, \mathit {atan} \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right ) a \,b^{2} e x +4 \sqrt {4 a c -b^{2}}\, \mathit {atan} \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right ) a b c e \,x^{2}-2 \sqrt {4 a c -b^{2}}\, \mathit {atan} \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right ) b^{3} d x -2 \sqrt {4 a c -b^{2}}\, \mathit {atan} \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right ) b^{2} c d \,x^{2}+8 a^{3} c e -2 a^{2} b^{2} e -4 a^{2} b c d +8 a^{2} c^{2} e \,x^{2}+a \,b^{3} d -6 a \,b^{2} c e \,x^{2}+4 a b \,c^{2} d \,x^{2}+b^{4} e \,x^{2}-b^{3} c d \,x^{2}}{b \left (16 a^{2} c^{3} x^{2}-8 a \,b^{2} c^{2} x^{2}+b^{4} c \,x^{2}+16 a^{2} b \,c^{2} x -8 a \,b^{3} c x +b^{5} x +16 a^{3} c^{2}-8 a^{2} b^{2} c +a \,b^{4}\right )} \] Input:
int(x*(e*x+d)/(c*x^2+b*x+a)^2,x)
Output:
(4*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*a**2*b*e - 2*sq rt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*a*b**2*d + 4*sqrt(4* a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*a*b**2*e*x + 4*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*a*b*c*e*x**2 - 2*sqrt(4*a*c - b**2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*b**3*d*x - 2*sqrt(4*a*c - b** 2)*atan((b + 2*c*x)/sqrt(4*a*c - b**2))*b**2*c*d*x**2 + 8*a**3*c*e - 2*a** 2*b**2*e - 4*a**2*b*c*d + 8*a**2*c**2*e*x**2 + a*b**3*d - 6*a*b**2*c*e*x** 2 + 4*a*b*c**2*d*x**2 + b**4*e*x**2 - b**3*c*d*x**2)/(b*(16*a**3*c**2 - 8* a**2*b**2*c + 16*a**2*b*c**2*x + 16*a**2*c**3*x**2 + a*b**4 - 8*a*b**3*c*x - 8*a*b**2*c**2*x**2 + b**5*x + b**4*c*x**2))