Integrand size = 24, antiderivative size = 201 \[ \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx=\frac {2 f x \left (1+\frac {c x}{b}\right )^{-p} \left (b x+c x^2\right )^p \operatorname {AppellF1}\left (1+p,-p,1,2+p,-\frac {c x}{b},-\frac {2 f x}{e-\sqrt {e^2-4 d f}}\right )}{\sqrt {e^2-4 d f} \left (e-\sqrt {e^2-4 d f}\right ) (1+p)}-\frac {2 f x \left (1+\frac {c x}{b}\right )^{-p} \left (b x+c x^2\right )^p \operatorname {AppellF1}\left (1+p,-p,1,2+p,-\frac {c x}{b},-\frac {2 f x}{e+\sqrt {e^2-4 d f}}\right )}{\sqrt {e^2-4 d f} \left (e+\sqrt {e^2-4 d f}\right ) (1+p)} \] Output:
2*f*x*(c*x^2+b*x)^p*AppellF1(p+1,-p,1,2+p,-c*x/b,-2*f*x/(e-(-4*d*f+e^2)^(1 /2)))/(-4*d*f+e^2)^(1/2)/(e-(-4*d*f+e^2)^(1/2))/(p+1)/((1+c*x/b)^p)-2*f*x* (c*x^2+b*x)^p*AppellF1(p+1,-p,1,2+p,-c*x/b,-2*f*x/(e+(-4*d*f+e^2)^(1/2)))/ (-4*d*f+e^2)^(1/2)/(e+(-4*d*f+e^2)^(1/2))/(p+1)/((1+c*x/b)^p)
\[ \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx=\int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx \] Input:
Integrate[(b*x + c*x^2)^p/(d + e*x + f*x^2),x]
Output:
Integrate[(b*x + c*x^2)^p/(d + e*x + f*x^2), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx\) |
\(\Big \downarrow \) 1325 |
\(\displaystyle \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2}dx\) |
Input:
Int[(b*x + c*x^2)^p/(d + e*x + f*x^2),x]
Output:
$Aborted
Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_)*((d_.) + (e_.)*(x_) + (f_.)*(x _)^2)^(q_), x_Symbol] :> Unintegrable[(a + b*x + c*x^2)^p*(d + e*x + f*x^2) ^q, x] /; FreeQ[{a, b, c, d, e, f, p, q}, x] && !IGtQ[p, 0] && !IGtQ[q, 0 ]
\[\int \frac {\left (c \,x^{2}+b x \right )^{p}}{f \,x^{2}+e x +d}d x\]
Input:
int((c*x^2+b*x)^p/(f*x^2+e*x+d),x)
Output:
int((c*x^2+b*x)^p/(f*x^2+e*x+d),x)
\[ \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx=\int { \frac {{\left (c x^{2} + b x\right )}^{p}}{f x^{2} + e x + d} \,d x } \] Input:
integrate((c*x^2+b*x)^p/(f*x^2+e*x+d),x, algorithm="fricas")
Output:
integral((c*x^2 + b*x)^p/(f*x^2 + e*x + d), x)
Timed out. \[ \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx=\text {Timed out} \] Input:
integrate((c*x**2+b*x)**p/(f*x**2+e*x+d),x)
Output:
Timed out
\[ \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx=\int { \frac {{\left (c x^{2} + b x\right )}^{p}}{f x^{2} + e x + d} \,d x } \] Input:
integrate((c*x^2+b*x)^p/(f*x^2+e*x+d),x, algorithm="maxima")
Output:
integrate((c*x^2 + b*x)^p/(f*x^2 + e*x + d), x)
\[ \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx=\int { \frac {{\left (c x^{2} + b x\right )}^{p}}{f x^{2} + e x + d} \,d x } \] Input:
integrate((c*x^2+b*x)^p/(f*x^2+e*x+d),x, algorithm="giac")
Output:
integrate((c*x^2 + b*x)^p/(f*x^2 + e*x + d), x)
Timed out. \[ \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx=\int \frac {{\left (c\,x^2+b\,x\right )}^p}{f\,x^2+e\,x+d} \,d x \] Input:
int((b*x + c*x^2)^p/(d + e*x + f*x^2),x)
Output:
int((b*x + c*x^2)^p/(d + e*x + f*x^2), x)
\[ \int \frac {\left (b x+c x^2\right )^p}{d+e x+f x^2} \, dx=\int \frac {\left (c \,x^{2}+b x \right )^{p}}{f \,x^{2}+e x +d}d x \] Input:
int((c*x^2+b*x)^p/(f*x^2+e*x+d),x)
Output:
int((b*x + c*x**2)**p/(d + e*x + f*x**2),x)