\(\int \frac {\sqrt {a+c x^2}}{x^3 (d+e x+f x^2)} \, dx\) [24]

Optimal result

Integrand size = 27, antiderivative size = 485 \[ \int \frac {\sqrt {a+c x^2}}{x^3 \left (d+e x+f x^2\right )} \, dx=-\frac {\sqrt {a+c x^2}}{2 d x^2}+\frac {e \sqrt {a+c x^2}}{d^2 x}+\frac {f \left (2 e \left (c d^2+a \left (e^2-2 d f\right )\right )-\left (e-\sqrt {e^2-4 d f}\right ) \left (c d^2+a \left (e^2-d f\right )\right )\right ) \text {arctanh}\left (\frac {2 a f-c \left (e-\sqrt {e^2-4 d f}\right ) x}{\sqrt {2} \sqrt {2 a f^2+c \left (e^2-2 d f-e \sqrt {e^2-4 d f}\right )} \sqrt {a+c x^2}}\right )}{\sqrt {2} d^3 \sqrt {e^2-4 d f} \sqrt {2 a f^2+c \left (e^2-2 d f-e \sqrt {e^2-4 d f}\right )}}-\frac {f \left (2 e \left (c d^2+a \left (e^2-2 d f\right )\right )-\left (e+\sqrt {e^2-4 d f}\right ) \left (c d^2+a \left (e^2-d f\right )\right )\right ) \text {arctanh}\left (\frac {2 a f-c \left (e+\sqrt {e^2-4 d f}\right ) x}{\sqrt {2} \sqrt {2 a f^2+c \left (e^2-2 d f+e \sqrt {e^2-4 d f}\right )} \sqrt {a+c x^2}}\right )}{\sqrt {2} d^3 \sqrt {e^2-4 d f} \sqrt {2 a f^2+c \left (e^2-2 d f+e \sqrt {e^2-4 d f}\right )}}-\frac {c \text {arctanh}\left (\frac {\sqrt {a+c x^2}}{\sqrt {a}}\right )}{2 \sqrt {a} d}-\frac {\sqrt {a} \left (e^2-d f\right ) \text {arctanh}\left (\frac {\sqrt {a+c x^2}}{\sqrt {a}}\right )}{d^3} \] Output:

-1/2*(c*x^2+a)^(1/2)/d/x^2+e*(c*x^2+a)^(1/2)/d^2/x+1/2*f*(2*e*(c*d^2+a*(-2 
*d*f+e^2))-(e-(-4*d*f+e^2)^(1/2))*(c*d^2+a*(-d*f+e^2)))*arctanh(1/2*(2*a*f 
-c*(e-(-4*d*f+e^2)^(1/2))*x)*2^(1/2)/(2*a*f^2+c*(e^2-2*d*f-e*(-4*d*f+e^2)^ 
(1/2)))^(1/2)/(c*x^2+a)^(1/2))*2^(1/2)/d^3/(-4*d*f+e^2)^(1/2)/(2*a*f^2+c*( 
e^2-2*d*f-e*(-4*d*f+e^2)^(1/2)))^(1/2)-1/2*f*(2*e*(c*d^2+a*(-2*d*f+e^2))-( 
e+(-4*d*f+e^2)^(1/2))*(c*d^2+a*(-d*f+e^2)))*arctanh(1/2*(2*a*f-c*(e+(-4*d* 
f+e^2)^(1/2))*x)*2^(1/2)/(2*a*f^2+c*(e^2-2*d*f+e*(-4*d*f+e^2)^(1/2)))^(1/2 
)/(c*x^2+a)^(1/2))*2^(1/2)/d^3/(-4*d*f+e^2)^(1/2)/(2*a*f^2+c*(e^2-2*d*f+e* 
(-4*d*f+e^2)^(1/2)))^(1/2)-1/2*c*arctanh((c*x^2+a)^(1/2)/a^(1/2))/a^(1/2)/ 
d-a^(1/2)*(-d*f+e^2)*arctanh((c*x^2+a)^(1/2)/a^(1/2))/d^3
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.

Time = 1.10 (sec) , antiderivative size = 533, normalized size of antiderivative = 1.10 \[ \int \frac {\sqrt {a+c x^2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\frac {\frac {d (-d+2 e x) \sqrt {a+c x^2}}{x^2}+\frac {2 c d^2 \text {arctanh}\left (\frac {\sqrt {c} x-\sqrt {a+c x^2}}{\sqrt {a}}\right )}{\sqrt {a}}-4 \sqrt {a} \left (e^2-d f\right ) \text {arctanh}\left (\frac {-\sqrt {c} x+\sqrt {a+c x^2}}{\sqrt {a}}\right )-2 \text {RootSum}\left [a^2 f+2 a \sqrt {c} e \text {$\#$1}+4 c d \text {$\#$1}^2-2 a f \text {$\#$1}^2-2 \sqrt {c} e \text {$\#$1}^3+f \text {$\#$1}^4\&,\frac {-a c d^2 f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right )-a^2 e^2 f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right )+a^2 d f^2 \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right )-2 c^{3/2} d^2 e \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}-2 a \sqrt {c} e^3 \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}+4 a \sqrt {c} d e f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}+c d^2 f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}^2+a e^2 f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}^2-a d f^2 \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}^2}{a \sqrt {c} e+4 c d \text {$\#$1}-2 a f \text {$\#$1}-3 \sqrt {c} e \text {$\#$1}^2+2 f \text {$\#$1}^3}\&\right ]}{2 d^3} \] Input:

Integrate[Sqrt[a + c*x^2]/(x^3*(d + e*x + f*x^2)),x]
 

Output:

((d*(-d + 2*e*x)*Sqrt[a + c*x^2])/x^2 + (2*c*d^2*ArcTanh[(Sqrt[c]*x - Sqrt 
[a + c*x^2])/Sqrt[a]])/Sqrt[a] - 4*Sqrt[a]*(e^2 - d*f)*ArcTanh[(-(Sqrt[c]* 
x) + Sqrt[a + c*x^2])/Sqrt[a]] - 2*RootSum[a^2*f + 2*a*Sqrt[c]*e*#1 + 4*c* 
d*#1^2 - 2*a*f*#1^2 - 2*Sqrt[c]*e*#1^3 + f*#1^4 & , (-(a*c*d^2*f*Log[-(Sqr 
t[c]*x) + Sqrt[a + c*x^2] - #1]) - a^2*e^2*f*Log[-(Sqrt[c]*x) + Sqrt[a + c 
*x^2] - #1] + a^2*d*f^2*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1] - 2*c^(3/ 
2)*d^2*e*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1 - 2*a*Sqrt[c]*e^3*Log 
[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1 + 4*a*Sqrt[c]*d*e*f*Log[-(Sqrt[c] 
*x) + Sqrt[a + c*x^2] - #1]*#1 + c*d^2*f*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2 
] - #1]*#1^2 + a*e^2*f*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1^2 - a*d 
*f^2*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1^2)/(a*Sqrt[c]*e + 4*c*d*# 
1 - 2*a*f*#1 - 3*Sqrt[c]*e*#1^2 + 2*f*#1^3) & ])/(2*d^3)
 

Rubi [A] (verified)

Time = 1.80 (sec) , antiderivative size = 507, normalized size of antiderivative = 1.05, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.074, Rules used = {7279, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sqrt {a+c x^2}}{x^3 \left (d+e x+f x^2\right )} \, dx\)

\(\Big \downarrow \) 7279

\(\displaystyle \int \left (\frac {\sqrt {a+c x^2} \left (e^2-d f\right )}{d^3 x}+\frac {\sqrt {a+c x^2} \left (-f x \left (e^2-d f\right )-e \left (e^2-2 d f\right )\right )}{d^3 \left (d+e x+f x^2\right )}-\frac {e \sqrt {a+c x^2}}{d^2 x^2}+\frac {\sqrt {a+c x^2}}{d x^3}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {\sqrt {a} \left (e^2-d f\right ) \text {arctanh}\left (\frac {\sqrt {a+c x^2}}{\sqrt {a}}\right )}{d^3}+\frac {f \left (a \left (e^2 \sqrt {e^2-4 d f}-d f \sqrt {e^2-4 d f}-3 d e f+e^3\right )+c d^2 \left (\sqrt {e^2-4 d f}+e\right )\right ) \text {arctanh}\left (\frac {2 a f-c x \left (e-\sqrt {e^2-4 d f}\right )}{\sqrt {2} \sqrt {a+c x^2} \sqrt {2 a f^2+c \left (-e \sqrt {e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt {2} d^3 \sqrt {e^2-4 d f} \sqrt {2 a f^2+c \left (-e \sqrt {e^2-4 d f}-2 d f+e^2\right )}}-\frac {f \left (a \left (-e^2 \sqrt {e^2-4 d f}+d f \sqrt {e^2-4 d f}-3 d e f+e^3\right )+c d^2 \left (e-\sqrt {e^2-4 d f}\right )\right ) \text {arctanh}\left (\frac {2 a f-c x \left (\sqrt {e^2-4 d f}+e\right )}{\sqrt {2} \sqrt {a+c x^2} \sqrt {2 a f^2+c \left (e \sqrt {e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt {2} d^3 \sqrt {e^2-4 d f} \sqrt {2 a f^2+c \left (e \sqrt {e^2-4 d f}-2 d f+e^2\right )}}-\frac {c \text {arctanh}\left (\frac {\sqrt {a+c x^2}}{\sqrt {a}}\right )}{2 \sqrt {a} d}+\frac {e \sqrt {a+c x^2}}{d^2 x}-\frac {\sqrt {a+c x^2}}{2 d x^2}\)

Input:

Int[Sqrt[a + c*x^2]/(x^3*(d + e*x + f*x^2)),x]
 

Output:

-1/2*Sqrt[a + c*x^2]/(d*x^2) + (e*Sqrt[a + c*x^2])/(d^2*x) + (f*(c*d^2*(e 
+ Sqrt[e^2 - 4*d*f]) + a*(e^3 - 3*d*e*f + e^2*Sqrt[e^2 - 4*d*f] - d*f*Sqrt 
[e^2 - 4*d*f]))*ArcTanh[(2*a*f - c*(e - Sqrt[e^2 - 4*d*f])*x)/(Sqrt[2]*Sqr 
t[2*a*f^2 + c*(e^2 - 2*d*f - e*Sqrt[e^2 - 4*d*f])]*Sqrt[a + c*x^2])])/(Sqr 
t[2]*d^3*Sqrt[e^2 - 4*d*f]*Sqrt[2*a*f^2 + c*(e^2 - 2*d*f - e*Sqrt[e^2 - 4* 
d*f])]) - (f*(c*d^2*(e - Sqrt[e^2 - 4*d*f]) + a*(e^3 - 3*d*e*f - e^2*Sqrt[ 
e^2 - 4*d*f] + d*f*Sqrt[e^2 - 4*d*f]))*ArcTanh[(2*a*f - c*(e + Sqrt[e^2 - 
4*d*f])*x)/(Sqrt[2]*Sqrt[2*a*f^2 + c*(e^2 - 2*d*f + e*Sqrt[e^2 - 4*d*f])]* 
Sqrt[a + c*x^2])])/(Sqrt[2]*d^3*Sqrt[e^2 - 4*d*f]*Sqrt[2*a*f^2 + c*(e^2 - 
2*d*f + e*Sqrt[e^2 - 4*d*f])]) - (c*ArcTanh[Sqrt[a + c*x^2]/Sqrt[a]])/(2*S 
qrt[a]*d) - (Sqrt[a]*(e^2 - d*f)*ArcTanh[Sqrt[a + c*x^2]/Sqrt[a]])/d^3
 

Defintions of rubi rules used

rule 2009

Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 7279

Int[(u_)/((a_.) + (b_.)*(x_)^(n_.) + (c_.)*(x_)^(n2_.)), x_Symbol] :> With[ 
{v = RationalFunctionExpand[u/(a + b*x^n + c*x^(2*n)), x]}, Int[v, x] /; Su 
mQ[v]] /; FreeQ[{a, b, c}, x] && EqQ[n2, 2*n] && IGtQ[n, 0]
 

Maple [A] (verified)

Time = 2.26 (sec) , antiderivative size = 789, normalized size of antiderivative = 1.63

method	result	size
risch	\(-\frac {\sqrt {c \,x^{2}+a}\, \left (-2 e x +d \right )}{2 d^{2} x^{2}}-\frac {\frac {4 f \left (2 a d f -2 a \,e^{2}-c \,d^{2}\right ) \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {c \,x^{2}+a}}{x}\right )}{\left (-e +\sqrt {-4 d f +e^{2}}\right ) \left (e +\sqrt {-4 d f +e^{2}}\right ) \sqrt {a}}+\frac {2 f \left (\sqrt {-4 d f +e^{2}}\, a e -2 a d f +a \,e^{2}+2 c \,d^{2}\right ) \sqrt {2}\, \ln \left (\frac {\frac {-\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}-\frac {c \left (e -\sqrt {-4 d f +e^{2}}\right ) \left (x -\frac {-e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}{f}+\frac {\sqrt {2}\, \sqrt {\frac {-\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}}\, \sqrt {4 c {\left (x -\frac {-e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}^{2}-\frac {4 c \left (e -\sqrt {-4 d f +e^{2}}\right ) \left (x -\frac {-e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}{f}+\frac {-2 \sqrt {-4 d f +e^{2}}\, c e +4 a \,f^{2}-4 d f c +2 c \,e^{2}}{f^{2}}}}{2}}{x -\frac {-e +\sqrt {-4 d f +e^{2}}}{2 f}}\right )}{\sqrt {-4 d f +e^{2}}\, \left (-e +\sqrt {-4 d f +e^{2}}\right ) \sqrt {\frac {-\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}}}-\frac {2 f \left (\sqrt {-4 d f +e^{2}}\, a e +2 a d f -a \,e^{2}-2 c \,d^{2}\right ) \sqrt {2}\, \ln \left (\frac {\frac {\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}-\frac {c \left (e +\sqrt {-4 d f +e^{2}}\right ) \left (x +\frac {e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}{f}+\frac {\sqrt {2}\, \sqrt {\frac {\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}}\, \sqrt {4 c {\left (x +\frac {e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}^{2}-\frac {4 c \left (e +\sqrt {-4 d f +e^{2}}\right ) \left (x +\frac {e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}{f}+\frac {2 \sqrt {-4 d f +e^{2}}\, c e +4 a \,f^{2}-4 d f c +2 c \,e^{2}}{f^{2}}}}{2}}{x +\frac {e +\sqrt {-4 d f +e^{2}}}{2 f}}\right )}{\sqrt {-4 d f +e^{2}}\, \left (e +\sqrt {-4 d f +e^{2}}\right ) \sqrt {\frac {\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}}}}{2 d^{2}}\)	\(789\)
default	\(\text {Expression too large to display}\)	\(1521\)

Input:

int((c*x^2+a)^(1/2)/x^3/(f*x^2+e*x+d),x,method=_RETURNVERBOSE)
 

Output:

-1/2*(c*x^2+a)^(1/2)*(-2*e*x+d)/d^2/x^2-1/2/d^2*(4*f*(2*a*d*f-2*a*e^2-c*d^ 
2)/(-e+(-4*d*f+e^2)^(1/2))/(e+(-4*d*f+e^2)^(1/2))/a^(1/2)*ln((2*a+2*a^(1/2 
)*(c*x^2+a)^(1/2))/x)+2*f*((-4*d*f+e^2)^(1/2)*a*e-2*a*d*f+a*e^2+2*c*d^2)/( 
-4*d*f+e^2)^(1/2)/(-e+(-4*d*f+e^2)^(1/2))*2^(1/2)/((-(-4*d*f+e^2)^(1/2)*c* 
e+2*a*f^2-2*d*f*c+c*e^2)/f^2)^(1/2)*ln(((-(-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2 
*d*f*c+c*e^2)/f^2-c*(e-(-4*d*f+e^2)^(1/2))/f*(x-1/2/f*(-e+(-4*d*f+e^2)^(1/ 
2)))+1/2*2^(1/2)*((-(-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2)/f^2)^(1/ 
2)*(4*c*(x-1/2/f*(-e+(-4*d*f+e^2)^(1/2)))^2-4*c*(e-(-4*d*f+e^2)^(1/2))/f*( 
x-1/2/f*(-e+(-4*d*f+e^2)^(1/2)))+2*(-(-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2*d*f* 
c+c*e^2)/f^2)^(1/2))/(x-1/2/f*(-e+(-4*d*f+e^2)^(1/2))))-2*f*((-4*d*f+e^2)^ 
(1/2)*a*e+2*a*d*f-a*e^2-2*c*d^2)/(-4*d*f+e^2)^(1/2)/(e+(-4*d*f+e^2)^(1/2)) 
*2^(1/2)/(((-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2)/f^2)^(1/2)*ln(((( 
-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2)/f^2-c*(e+(-4*d*f+e^2)^(1/2))/ 
f*(x+1/2*(e+(-4*d*f+e^2)^(1/2))/f)+1/2*2^(1/2)*(((-4*d*f+e^2)^(1/2)*c*e+2* 
a*f^2-2*d*f*c+c*e^2)/f^2)^(1/2)*(4*c*(x+1/2*(e+(-4*d*f+e^2)^(1/2))/f)^2-4* 
c*(e+(-4*d*f+e^2)^(1/2))/f*(x+1/2*(e+(-4*d*f+e^2)^(1/2))/f)+2*((-4*d*f+e^2 
)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2)/f^2)^(1/2))/(x+1/2*(e+(-4*d*f+e^2)^(1/2 
))/f)))
 

Fricas [F(-1)]

Timed out. \[ \int \frac {\sqrt {a+c x^2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\text {Timed out} \] Input:

integrate((c*x^2+a)^(1/2)/x^3/(f*x^2+e*x+d),x, algorithm="fricas")
 

Output:

Timed out
 

Sympy [F]

\[ \int \frac {\sqrt {a+c x^2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\int \frac {\sqrt {a + c x^{2}}}{x^{3} \left (d + e x + f x^{2}\right )}\, dx \] Input:

integrate((c*x**2+a)**(1/2)/x**3/(f*x**2+e*x+d),x)
 

Output:

Integral(sqrt(a + c*x**2)/(x**3*(d + e*x + f*x**2)), x)
 

Maxima [F]

\[ \int \frac {\sqrt {a+c x^2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\int { \frac {\sqrt {c x^{2} + a}}{{\left (f x^{2} + e x + d\right )} x^{3}} \,d x } \] Input:

integrate((c*x^2+a)^(1/2)/x^3/(f*x^2+e*x+d),x, algorithm="maxima")
 

Output:

integrate(sqrt(c*x^2 + a)/((f*x^2 + e*x + d)*x^3), x)
 

Giac [F(-1)]

Timed out. \[ \int \frac {\sqrt {a+c x^2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\text {Timed out} \] Input:

integrate((c*x^2+a)^(1/2)/x^3/(f*x^2+e*x+d),x, algorithm="giac")
 

Output:

Timed out
 

Mupad [F(-1)]

Timed out. \[ \int \frac {\sqrt {a+c x^2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\int \frac {\sqrt {c\,x^2+a}}{x^3\,\left (f\,x^2+e\,x+d\right )} \,d x \] Input:

int((a + c*x^2)^(1/2)/(x^3*(d + e*x + f*x^2)),x)
 

Output:

int((a + c*x^2)^(1/2)/(x^3*(d + e*x + f*x^2)), x)
 

Reduce [F]

\[ \int \frac {\sqrt {a+c x^2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\text {too large to display} \] Input:

int((c*x^2+a)^(1/2)/x^3/(f*x^2+e*x+d),x)
 

Output:

(8*sqrt(a + c*x**2)*a**3*d**2*f**2 - 16*sqrt(a + c*x**2)*a**3*d*e**2*f + 8 
*sqrt(a + c*x**2)*a**3*e**4 - 8*sqrt(a + c*x**2)*a**2*c*d**3*f + 8*sqrt(a 
+ c*x**2)*a**2*c*d**2*e**2 + 8*sqrt(a + c*x**2)*a**2*c*d**2*e*f*x - 8*sqrt 
(a + c*x**2)*a**2*c*d*e**3*x - 2*sqrt(a + c*x**2)*a*c**2*d**4 - 4*sqrt(a + 
 c*x**2)*a*c**2*d**3*e*x - 2*sqrt(a)*log(sqrt(a + c*x**2) - sqrt(a))*a*c** 
2*d**3*f*x**2 + 2*sqrt(a)*log(sqrt(a + c*x**2) - sqrt(a))*a*c**2*d**2*e**2 
*x**2 + sqrt(a)*log(sqrt(a + c*x**2) - sqrt(a))*c**3*d**4*x**2 + 2*sqrt(a) 
*log(sqrt(a + c*x**2) + sqrt(a))*a*c**2*d**3*f*x**2 - 2*sqrt(a)*log(sqrt(a 
 + c*x**2) + sqrt(a))*a*c**2*d**2*e**2*x**2 - sqrt(a)*log(sqrt(a + c*x**2) 
 + sqrt(a))*c**3*d**4*x**2 + 16*int(sqrt(a + c*x**2)/(a*d*x**3 + a*e*x**4 
+ a*f*x**5 + c*d*x**5 + c*e*x**6 + c*f*x**7),x)*a**4*d**3*f**2*x**2 - 32*i 
nt(sqrt(a + c*x**2)/(a*d*x**3 + a*e*x**4 + a*f*x**5 + c*d*x**5 + c*e*x**6 
+ c*f*x**7),x)*a**4*d**2*e**2*f*x**2 + 16*int(sqrt(a + c*x**2)/(a*d*x**3 + 
 a*e*x**4 + a*f*x**5 + c*d*x**5 + c*e*x**6 + c*f*x**7),x)*a**4*d*e**4*x**2 
 - 16*int(sqrt(a + c*x**2)/(a*d*x**3 + a*e*x**4 + a*f*x**5 + c*d*x**5 + c* 
e*x**6 + c*f*x**7),x)*a**3*c*d**4*f*x**2 + 16*int(sqrt(a + c*x**2)/(a*d*x* 
*3 + a*e*x**4 + a*f*x**5 + c*d*x**5 + c*e*x**6 + c*f*x**7),x)*a**3*c*d**3* 
e**2*x**2 + 16*int(sqrt(a + c*x**2)/(a*d*x**2 + a*e*x**3 + a*f*x**4 + c*d* 
x**4 + c*e*x**5 + c*f*x**6),x)*a**4*d**2*e*f**2*x**2 - 32*int(sqrt(a + c*x 
**2)/(a*d*x**2 + a*e*x**3 + a*f*x**4 + c*d*x**4 + c*e*x**5 + c*f*x**6),...