Integrand size = 27, antiderivative size = 589 \[ \int \frac {\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\frac {c \sqrt {a+c x^2}}{d}+\frac {a \left (e^2-d f\right ) \sqrt {a+c x^2}}{d^3}-\frac {\left (c d^2+a \left (e^2-d f\right )\right ) \sqrt {a+c x^2}}{d^3}-\frac {a \sqrt {a+c x^2}}{2 d x^2}+\frac {a e \sqrt {a+c x^2}}{d^2 x}+\frac {\left (2 a e f \left (2 c d^2+a \left (e^2-2 d f\right )\right )+\left (e-\sqrt {e^2-4 d f}\right ) \left (c^2 d^3-2 a c d^2 f-a^2 f \left (e^2-d f\right )\right )\right ) \text {arctanh}\left (\frac {2 a f-c \left (e-\sqrt {e^2-4 d f}\right ) x}{\sqrt {2} \sqrt {2 a f^2+c \left (e^2-2 d f-e \sqrt {e^2-4 d f}\right )} \sqrt {a+c x^2}}\right )}{\sqrt {2} d^3 \sqrt {e^2-4 d f} \sqrt {2 a f^2+c \left (e^2-2 d f-e \sqrt {e^2-4 d f}\right )}}-\frac {\left (2 a e f \left (2 c d^2+a \left (e^2-2 d f\right )\right )+\left (e+\sqrt {e^2-4 d f}\right ) \left (c^2 d^3-2 a c d^2 f-a^2 f \left (e^2-d f\right )\right )\right ) \text {arctanh}\left (\frac {2 a f-c \left (e+\sqrt {e^2-4 d f}\right ) x}{\sqrt {2} \sqrt {2 a f^2+c \left (e^2-2 d f+e \sqrt {e^2-4 d f}\right )} \sqrt {a+c x^2}}\right )}{\sqrt {2} d^3 \sqrt {e^2-4 d f} \sqrt {2 a f^2+c \left (e^2-2 d f+e \sqrt {e^2-4 d f}\right )}}-\frac {3 \sqrt {a} c \text {arctanh}\left (\frac {\sqrt {a+c x^2}}{\sqrt {a}}\right )}{2 d}-\frac {a^{3/2} \left (e^2-d f\right ) \text {arctanh}\left (\frac {\sqrt {a+c x^2}}{\sqrt {a}}\right )}{d^3} \] Output:
c*(c*x^2+a)^(1/2)/d+a*(-d*f+e^2)*(c*x^2+a)^(1/2)/d^3-(c*d^2+a*(-d*f+e^2))* (c*x^2+a)^(1/2)/d^3-1/2*a*(c*x^2+a)^(1/2)/d/x^2+a*e*(c*x^2+a)^(1/2)/d^2/x+ 1/2*(2*a*e*f*(2*c*d^2+a*(-2*d*f+e^2))+(e-(-4*d*f+e^2)^(1/2))*(c^2*d^3-2*a* c*d^2*f-a^2*f*(-d*f+e^2)))*arctanh(1/2*(2*a*f-c*(e-(-4*d*f+e^2)^(1/2))*x)* 2^(1/2)/(2*a*f^2+c*(e^2-2*d*f-e*(-4*d*f+e^2)^(1/2)))^(1/2)/(c*x^2+a)^(1/2) )*2^(1/2)/d^3/(-4*d*f+e^2)^(1/2)/(2*a*f^2+c*(e^2-2*d*f-e*(-4*d*f+e^2)^(1/2 )))^(1/2)-1/2*(2*a*e*f*(2*c*d^2+a*(-2*d*f+e^2))+(e+(-4*d*f+e^2)^(1/2))*(c^ 2*d^3-2*a*c*d^2*f-a^2*f*(-d*f+e^2)))*arctanh(1/2*(2*a*f-c*(e+(-4*d*f+e^2)^ (1/2))*x)*2^(1/2)/(2*a*f^2+c*(e^2-2*d*f+e*(-4*d*f+e^2)^(1/2)))^(1/2)/(c*x^ 2+a)^(1/2))*2^(1/2)/d^3/(-4*d*f+e^2)^(1/2)/(2*a*f^2+c*(e^2-2*d*f+e*(-4*d*f +e^2)^(1/2)))^(1/2)-3/2*a^(1/2)*c*arctanh((c*x^2+a)^(1/2)/a^(1/2))/d-a^(3/ 2)*(-d*f+e^2)*arctanh((c*x^2+a)^(1/2)/a^(1/2))/d^3
Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
Time = 1.10 (sec) , antiderivative size = 617, normalized size of antiderivative = 1.05 \[ \int \frac {\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\frac {\frac {a d (-d+2 e x) \sqrt {a+c x^2}}{x^2}+6 \sqrt {a} c d^2 \text {arctanh}\left (\frac {\sqrt {c} x-\sqrt {a+c x^2}}{\sqrt {a}}\right )-4 a^{3/2} \left (e^2-d f\right ) \text {arctanh}\left (\frac {-\sqrt {c} x+\sqrt {a+c x^2}}{\sqrt {a}}\right )-2 \text {RootSum}\left [a^2 f+2 a \sqrt {c} e \text {$\#$1}+4 c d \text {$\#$1}^2-2 a f \text {$\#$1}^2-2 \sqrt {c} e \text {$\#$1}^3+f \text {$\#$1}^4\&,\frac {a c^2 d^3 \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right )-2 a^2 c d^2 f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right )-a^3 e^2 f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right )+a^3 d f^2 \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right )-4 a c^{3/2} d^2 e \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}-2 a^2 \sqrt {c} e^3 \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}+4 a^2 \sqrt {c} d e f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}-c^2 d^3 \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}^2+2 a c d^2 f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}^2+a^2 e^2 f \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}^2-a^2 d f^2 \log \left (-\sqrt {c} x+\sqrt {a+c x^2}-\text {$\#$1}\right ) \text {$\#$1}^2}{a \sqrt {c} e+4 c d \text {$\#$1}-2 a f \text {$\#$1}-3 \sqrt {c} e \text {$\#$1}^2+2 f \text {$\#$1}^3}\&\right ]}{2 d^3} \] Input:
Integrate[(a + c*x^2)^(3/2)/(x^3*(d + e*x + f*x^2)),x]
Output:
((a*d*(-d + 2*e*x)*Sqrt[a + c*x^2])/x^2 + 6*Sqrt[a]*c*d^2*ArcTanh[(Sqrt[c] *x - Sqrt[a + c*x^2])/Sqrt[a]] - 4*a^(3/2)*(e^2 - d*f)*ArcTanh[(-(Sqrt[c]* x) + Sqrt[a + c*x^2])/Sqrt[a]] - 2*RootSum[a^2*f + 2*a*Sqrt[c]*e*#1 + 4*c* d*#1^2 - 2*a*f*#1^2 - 2*Sqrt[c]*e*#1^3 + f*#1^4 & , (a*c^2*d^3*Log[-(Sqrt[ c]*x) + Sqrt[a + c*x^2] - #1] - 2*a^2*c*d^2*f*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1] - a^3*e^2*f*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1] + a^3*d* f^2*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1] - 4*a*c^(3/2)*d^2*e*Log[-(Sqr t[c]*x) + Sqrt[a + c*x^2] - #1]*#1 - 2*a^2*Sqrt[c]*e^3*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1 + 4*a^2*Sqrt[c]*d*e*f*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1 - c^2*d^3*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1^2 + 2*a*c*d^2*f*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1^2 + a^2*e^2*f*Log [-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1^2 - a^2*d*f^2*Log[-(Sqrt[c]*x) + Sqrt[a + c*x^2] - #1]*#1^2)/(a*Sqrt[c]*e + 4*c*d*#1 - 2*a*f*#1 - 3*Sqrt[c] *e*#1^2 + 2*f*#1^3) & ])/(2*d^3)
Time = 3.16 (sec) , antiderivative size = 668, normalized size of antiderivative = 1.13, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.074, Rules used = {7279, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx\) |
| \(\Big \downarrow \) 7279 |
| \(\displaystyle \int \left (\frac {\left (a+c x^2\right )^{3/2} \left (e^2-d f\right )}{d^3 x}+\frac {\left (a+c x^2\right )^{3/2} \left (-f x \left (e^2-d f\right )-e \left (e^2-2 d f\right )\right )}{d^3 \left (d+e x+f x^2\right )}-\frac {e \left (a+c x^2\right )^{3/2}}{d^2 x^2}+\frac {\left (a+c x^2\right )^{3/2}}{d x^3}\right )dx\) |
| \(\Big \downarrow \) 2009 |
| \(\displaystyle -\frac {a^{3/2} \left (e^2-d f\right ) \text {arctanh}\left (\frac {\sqrt {a+c x^2}}{\sqrt {a}}\right )}{d^3}+\frac {\left (a^2 f \left (e^2 \sqrt {e^2-4 d f}-d f \sqrt {e^2-4 d f}-3 d e f+e^3\right )+2 a c d^2 f \left (\sqrt {e^2-4 d f}+e\right )+c^2 d^3 \left (e-\sqrt {e^2-4 d f}\right )\right ) \text {arctanh}\left (\frac {2 a f-c x \left (e-\sqrt {e^2-4 d f}\right )}{\sqrt {2} \sqrt {a+c x^2} \sqrt {2 a f^2+c \left (-e \sqrt {e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt {2} d^3 \sqrt {e^2-4 d f} \sqrt {2 a f^2+c \left (-e \sqrt {e^2-4 d f}-2 d f+e^2\right )}}-\frac {\left (a^2 f \left (-e^2 \sqrt {e^2-4 d f}+d f \sqrt {e^2-4 d f}-3 d e f+e^3\right )+2 a c d^2 f \left (e-\sqrt {e^2-4 d f}\right )+c^2 d^3 \left (\sqrt {e^2-4 d f}+e\right )\right ) \text {arctanh}\left (\frac {2 a f-c x \left (\sqrt {e^2-4 d f}+e\right )}{\sqrt {2} \sqrt {a+c x^2} \sqrt {2 a f^2+c \left (e \sqrt {e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt {2} d^3 \sqrt {e^2-4 d f} \sqrt {2 a f^2+c \left (e \sqrt {e^2-4 d f}-2 d f+e^2\right )}}-\frac {3 \sqrt {a} c \text {arctanh}\left (\frac {\sqrt {a+c x^2}}{\sqrt {a}}\right )}{2 d}+\frac {a \sqrt {a+c x^2} \left (e^2-d f\right )}{d^3}+\frac {e \left (a+c x^2\right )^{3/2}}{d^2 x}-\frac {3 c e x \sqrt {a+c x^2}}{2 d^2}-\frac {\sqrt {a+c x^2} \left (2 \left (a \left (e^2-d f\right )+c d^2\right )-c d e x\right )}{2 d^3}-\frac {\left (a+c x^2\right )^{3/2}}{2 d x^2}+\frac {3 c \sqrt {a+c x^2}}{2 d}\) |
Input:
Int[(a + c*x^2)^(3/2)/(x^3*(d + e*x + f*x^2)),x]
Output:
(3*c*Sqrt[a + c*x^2])/(2*d) + (a*(e^2 - d*f)*Sqrt[a + c*x^2])/d^3 - (3*c*e *x*Sqrt[a + c*x^2])/(2*d^2) - ((2*(c*d^2 + a*(e^2 - d*f)) - c*d*e*x)*Sqrt[ a + c*x^2])/(2*d^3) - (a + c*x^2)^(3/2)/(2*d*x^2) + (e*(a + c*x^2)^(3/2))/ (d^2*x) + ((c^2*d^3*(e - Sqrt[e^2 - 4*d*f]) + 2*a*c*d^2*f*(e + Sqrt[e^2 - 4*d*f]) + a^2*f*(e^3 - 3*d*e*f + e^2*Sqrt[e^2 - 4*d*f] - d*f*Sqrt[e^2 - 4* d*f]))*ArcTanh[(2*a*f - c*(e - Sqrt[e^2 - 4*d*f])*x)/(Sqrt[2]*Sqrt[2*a*f^2 + c*(e^2 - 2*d*f - e*Sqrt[e^2 - 4*d*f])]*Sqrt[a + c*x^2])])/(Sqrt[2]*d^3* Sqrt[e^2 - 4*d*f]*Sqrt[2*a*f^2 + c*(e^2 - 2*d*f - e*Sqrt[e^2 - 4*d*f])]) - ((2*a*c*d^2*f*(e - Sqrt[e^2 - 4*d*f]) + c^2*d^3*(e + Sqrt[e^2 - 4*d*f]) + a^2*f*(e^3 - 3*d*e*f - e^2*Sqrt[e^2 - 4*d*f] + d*f*Sqrt[e^2 - 4*d*f]))*Ar cTanh[(2*a*f - c*(e + Sqrt[e^2 - 4*d*f])*x)/(Sqrt[2]*Sqrt[2*a*f^2 + c*(e^2 - 2*d*f + e*Sqrt[e^2 - 4*d*f])]*Sqrt[a + c*x^2])])/(Sqrt[2]*d^3*Sqrt[e^2 - 4*d*f]*Sqrt[2*a*f^2 + c*(e^2 - 2*d*f + e*Sqrt[e^2 - 4*d*f])]) - (3*Sqrt[ a]*c*ArcTanh[Sqrt[a + c*x^2]/Sqrt[a]])/(2*d) - (a^(3/2)*(e^2 - d*f)*ArcTan h[Sqrt[a + c*x^2]/Sqrt[a]])/d^3
Int[(u_)/((a_.) + (b_.)*(x_)^(n_.) + (c_.)*(x_)^(n2_.)), x_Symbol] :> With[ {v = RationalFunctionExpand[u/(a + b*x^n + c*x^(2*n)), x]}, Int[v, x] /; Su mQ[v]] /; FreeQ[{a, b, c}, x] && EqQ[n2, 2*n] && IGtQ[n, 0]
Time = 2.47 (sec) , antiderivative size = 907, normalized size of antiderivative = 1.54
| method | result | size |
| risch | \(-\frac {a \sqrt {c \,x^{2}+a}\, \left (-2 e x +d \right )}{2 d^{2} x^{2}}-\frac {\frac {2 \left (a^{2} e \,f^{2} \sqrt {-4 d f +e^{2}}-\sqrt {-4 d f +e^{2}}\, c^{2} d^{2} e -2 a^{2} d \,f^{3}+a^{2} e^{2} f^{2}+4 a c \,d^{2} f^{2}-2 d^{3} f \,c^{2}+d^{2} e^{2} c^{2}\right ) \sqrt {2}\, \ln \left (\frac {\frac {-\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}-\frac {c \left (e -\sqrt {-4 d f +e^{2}}\right ) \left (x -\frac {-e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}{f}+\frac {\sqrt {2}\, \sqrt {\frac {-\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}}\, \sqrt {4 c {\left (x -\frac {-e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}^{2}-\frac {4 c \left (e -\sqrt {-4 d f +e^{2}}\right ) \left (x -\frac {-e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}{f}+\frac {-2 \sqrt {-4 d f +e^{2}}\, c e +4 a \,f^{2}-4 d f c +2 c \,e^{2}}{f^{2}}}}{2}}{x -\frac {-e +\sqrt {-4 d f +e^{2}}}{2 f}}\right )}{\sqrt {-4 d f +e^{2}}\, \left (-e +\sqrt {-4 d f +e^{2}}\right ) f \sqrt {\frac {-\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}}}-\frac {2 \left (a^{2} e \,f^{2} \sqrt {-4 d f +e^{2}}-\sqrt {-4 d f +e^{2}}\, c^{2} d^{2} e +2 a^{2} d \,f^{3}-a^{2} e^{2} f^{2}-4 a c \,d^{2} f^{2}+2 d^{3} f \,c^{2}-d^{2} e^{2} c^{2}\right ) \sqrt {2}\, \ln \left (\frac {\frac {\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}-\frac {c \left (e +\sqrt {-4 d f +e^{2}}\right ) \left (x +\frac {e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}{f}+\frac {\sqrt {2}\, \sqrt {\frac {\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}}\, \sqrt {4 c {\left (x +\frac {e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}^{2}-\frac {4 c \left (e +\sqrt {-4 d f +e^{2}}\right ) \left (x +\frac {e +\sqrt {-4 d f +e^{2}}}{2 f}\right )}{f}+\frac {2 \sqrt {-4 d f +e^{2}}\, c e +4 a \,f^{2}-4 d f c +2 c \,e^{2}}{f^{2}}}}{2}}{x +\frac {e +\sqrt {-4 d f +e^{2}}}{2 f}}\right )}{\sqrt {-4 d f +e^{2}}\, \left (e +\sqrt {-4 d f +e^{2}}\right ) f \sqrt {\frac {\sqrt {-4 d f +e^{2}}\, c e +2 a \,f^{2}-2 d f c +c \,e^{2}}{f^{2}}}}+\frac {4 f \sqrt {a}\, \left (2 a d f -2 a \,e^{2}-3 c \,d^{2}\right ) \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {c \,x^{2}+a}}{x}\right )}{\left (-e +\sqrt {-4 d f +e^{2}}\right ) \left (e +\sqrt {-4 d f +e^{2}}\right )}}{2 d^{2}}\) | \(907\) |
| default | \(\text {Expression too large to display}\) | \(2614\) |
Input:
int((c*x^2+a)^(3/2)/x^3/(f*x^2+e*x+d),x,method=_RETURNVERBOSE)
Output:
-1/2*a*(c*x^2+a)^(1/2)*(-2*e*x+d)/d^2/x^2-1/2/d^2*(2*(a^2*e*f^2*(-4*d*f+e^ 2)^(1/2)-(-4*d*f+e^2)^(1/2)*c^2*d^2*e-2*a^2*d*f^3+a^2*e^2*f^2+4*a*c*d^2*f^ 2-2*d^3*f*c^2+d^2*e^2*c^2)/(-4*d*f+e^2)^(1/2)/(-e+(-4*d*f+e^2)^(1/2))/f*2^ (1/2)/((-(-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2)/f^2)^(1/2)*ln(((-(- 4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2)/f^2-c*(e-(-4*d*f+e^2)^(1/2))/f *(x-1/2/f*(-e+(-4*d*f+e^2)^(1/2)))+1/2*2^(1/2)*((-(-4*d*f+e^2)^(1/2)*c*e+2 *a*f^2-2*d*f*c+c*e^2)/f^2)^(1/2)*(4*c*(x-1/2/f*(-e+(-4*d*f+e^2)^(1/2)))^2- 4*c*(e-(-4*d*f+e^2)^(1/2))/f*(x-1/2/f*(-e+(-4*d*f+e^2)^(1/2)))+2*(-(-4*d*f +e^2)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2)/f^2)^(1/2))/(x-1/2/f*(-e+(-4*d*f+e^ 2)^(1/2))))-2*(a^2*e*f^2*(-4*d*f+e^2)^(1/2)-(-4*d*f+e^2)^(1/2)*c^2*d^2*e+2 *a^2*d*f^3-a^2*e^2*f^2-4*a*c*d^2*f^2+2*d^3*f*c^2-d^2*e^2*c^2)/(-4*d*f+e^2) ^(1/2)/(e+(-4*d*f+e^2)^(1/2))/f*2^(1/2)/(((-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2 *d*f*c+c*e^2)/f^2)^(1/2)*ln((((-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2 )/f^2-c*(e+(-4*d*f+e^2)^(1/2))/f*(x+1/2*(e+(-4*d*f+e^2)^(1/2))/f)+1/2*2^(1 /2)*(((-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2)/f^2)^(1/2)*(4*c*(x+1/2 *(e+(-4*d*f+e^2)^(1/2))/f)^2-4*c*(e+(-4*d*f+e^2)^(1/2))/f*(x+1/2*(e+(-4*d* f+e^2)^(1/2))/f)+2*((-4*d*f+e^2)^(1/2)*c*e+2*a*f^2-2*d*f*c+c*e^2)/f^2)^(1/ 2))/(x+1/2*(e+(-4*d*f+e^2)^(1/2))/f))+4*f*a^(1/2)*(2*a*d*f-2*a*e^2-3*c*d^2 )/(-e+(-4*d*f+e^2)^(1/2))/(e+(-4*d*f+e^2)^(1/2))*ln((2*a+2*a^(1/2)*(c*x^2+ a)^(1/2))/x))
Timed out. \[ \int \frac {\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\text {Timed out} \] Input:
integrate((c*x^2+a)^(3/2)/x^3/(f*x^2+e*x+d),x, algorithm="fricas")
Output:
Timed out
Timed out. \[ \int \frac {\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\text {Timed out} \] Input:
integrate((c*x**2+a)**(3/2)/x**3/(f*x**2+e*x+d),x)
Output:
Timed out
\[ \int \frac {\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{\frac {3}{2}}}{{\left (f x^{2} + e x + d\right )} x^{3}} \,d x } \] Input:
integrate((c*x^2+a)^(3/2)/x^3/(f*x^2+e*x+d),x, algorithm="maxima")
Output:
integrate((c*x^2 + a)^(3/2)/((f*x^2 + e*x + d)*x^3), x)
Timed out. \[ \int \frac {\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\text {Timed out} \] Input:
integrate((c*x^2+a)^(3/2)/x^3/(f*x^2+e*x+d),x, algorithm="giac")
Output:
Timed out
Timed out. \[ \int \frac {\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\int \frac {{\left (c\,x^2+a\right )}^{3/2}}{x^3\,\left (f\,x^2+e\,x+d\right )} \,d x \] Input:
int((a + c*x^2)^(3/2)/(x^3*(d + e*x + f*x^2)),x)
Output:
int((a + c*x^2)^(3/2)/(x^3*(d + e*x + f*x^2)), x)
\[ \int \frac {\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx=\text {too large to display} \] Input:
int((c*x^2+a)^(3/2)/x^3/(f*x^2+e*x+d),x)
Output:
(8*sqrt(a + c*x**2)*a**3*d**2*f**3 - 16*sqrt(a + c*x**2)*a**3*d*e**2*f**2 + 8*sqrt(a + c*x**2)*a**3*e**4*f - 16*sqrt(a + c*x**2)*a**2*c*d**3*f**2 + 16*sqrt(a + c*x**2)*a**2*c*d**2*e**2*f + 8*sqrt(a + c*x**2)*a**2*c*d**2*e* f**2*x - 8*sqrt(a + c*x**2)*a**2*c*d*e**3*f*x + 6*sqrt(a + c*x**2)*a*c**2* d**4*f - 8*sqrt(a + c*x**2)*a*c**2*d**3*e**2 - 12*sqrt(a + c*x**2)*a*c**2* d**3*e*f*x + 8*sqrt(a + c*x**2)*c**3*d**4*e*x - 2*sqrt(a)*log(sqrt(a + c*x **2) - sqrt(a))*a*c**2*d**3*f**2*x**2 + 2*sqrt(a)*log(sqrt(a + c*x**2) - s qrt(a))*a*c**2*d**2*e**2*f*x**2 + 3*sqrt(a)*log(sqrt(a + c*x**2) - sqrt(a) )*c**3*d**4*f*x**2 + 2*sqrt(a)*log(sqrt(a + c*x**2) + sqrt(a))*a*c**2*d**3 *f**2*x**2 - 2*sqrt(a)*log(sqrt(a + c*x**2) + sqrt(a))*a*c**2*d**2*e**2*f* x**2 - 3*sqrt(a)*log(sqrt(a + c*x**2) + sqrt(a))*c**3*d**4*f*x**2 + 16*int (sqrt(a + c*x**2)/(a*d*x**3 + a*e*x**4 + a*f*x**5 + c*d*x**5 + c*e*x**6 + c*f*x**7),x)*a**4*d**3*f**3*x**2 - 32*int(sqrt(a + c*x**2)/(a*d*x**3 + a*e *x**4 + a*f*x**5 + c*d*x**5 + c*e*x**6 + c*f*x**7),x)*a**4*d**2*e**2*f**2* x**2 + 16*int(sqrt(a + c*x**2)/(a*d*x**3 + a*e*x**4 + a*f*x**5 + c*d*x**5 + c*e*x**6 + c*f*x**7),x)*a**4*d*e**4*f*x**2 - 32*int(sqrt(a + c*x**2)/(a* d*x**3 + a*e*x**4 + a*f*x**5 + c*d*x**5 + c*e*x**6 + c*f*x**7),x)*a**3*c*d **4*f**2*x**2 + 32*int(sqrt(a + c*x**2)/(a*d*x**3 + a*e*x**4 + a*f*x**5 + c*d*x**5 + c*e*x**6 + c*f*x**7),x)*a**3*c*d**3*e**2*f*x**2 + 16*int(sqrt(a + c*x**2)/(a*d*x**3 + a*e*x**4 + a*f*x**5 + c*d*x**5 + c*e*x**6 + c*f*...