Integrand size = 14, antiderivative size = 21 \[ \int \frac {1}{\left (3+4 x+2 x^2\right )^{4/3}} \, dx=(1+x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {4}{3},\frac {3}{2},-2 (1+x)^2\right ) \] Output:
(1+x)*hypergeom([1/2, 4/3],[3/2],-2*(1+x)^2)
Leaf count is larger than twice the leaf count of optimal. \(55\) vs. \(2(21)=42\).
Time = 5.86 (sec) , antiderivative size = 55, normalized size of antiderivative = 2.62 \[ \int \frac {1}{\left (3+4 x+2 x^2\right )^{4/3}} \, dx=-\frac {(1+x) \left (-3+\sqrt [3]{3+4 x+2 x^2} \operatorname {Hypergeometric2F1}\left (\frac {1}{3},\frac {1}{2},\frac {3}{2},-2 (1+x)^2\right )\right )}{2 \sqrt [3]{3+4 x+2 x^2}} \] Input:
Integrate[(3 + 4*x + 2*x^2)^(-4/3),x]
Output:
-1/2*((1 + x)*(-3 + (3 + 4*x + 2*x^2)^(1/3)*Hypergeometric2F1[1/3, 1/2, 3/ 2, -2*(1 + x)^2]))/(3 + 4*x + 2*x^2)^(1/3)
Leaf count is larger than twice the leaf count of optimal. \(367\) vs. \(2(21)=42\).
Time = 0.74 (sec) , antiderivative size = 367, normalized size of antiderivative = 17.48, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {1089, 1090, 233, 833, 760, 2418}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{\left (2 x^2+4 x+3\right )^{4/3}} \, dx\) |
\(\Big \downarrow \) 1089 |
\(\displaystyle \frac {3 (x+1)}{2 \sqrt [3]{2 x^2+4 x+3}}-\frac {1}{2} \int \frac {1}{\sqrt [3]{2 x^2+4 x+3}}dx\) |
\(\Big \downarrow \) 1090 |
\(\displaystyle \frac {3 (x+1)}{2 \sqrt [3]{2 x^2+4 x+3}}-\frac {1}{8} \int \frac {1}{\sqrt [3]{\frac {1}{8} (4 x+4)^2+1}}d(4 x+4)\) |
\(\Big \downarrow \) 233 |
\(\displaystyle \frac {3 (x+1)}{2 \sqrt [3]{2 x^2+4 x+3}}-\frac {3 \sqrt {(4 x+4)^2} \int \frac {2 \sqrt {2} \sqrt [3]{\frac {1}{8} (4 x+4)^2+1}}{\sqrt {(4 x+4)^2}}d\sqrt [3]{\frac {1}{8} (4 x+4)^2+1}}{4 \sqrt {2} (4 x+4)}\) |
\(\Big \downarrow \) 833 |
\(\displaystyle \frac {3 (x+1)}{2 \sqrt [3]{2 x^2+4 x+3}}-\frac {3 \sqrt {(4 x+4)^2} \left (\left (1+\sqrt {3}\right ) \int \frac {2 \sqrt {2}}{\sqrt {(4 x+4)^2}}d\sqrt [3]{\frac {1}{8} (4 x+4)^2+1}-\int \frac {2 \sqrt {2} \left (-4 x+\sqrt {3}-3\right )}{\sqrt {(4 x+4)^2}}d\sqrt [3]{\frac {1}{8} (4 x+4)^2+1}\right )}{4 \sqrt {2} (4 x+4)}\) |
\(\Big \downarrow \) 760 |
\(\displaystyle \frac {3 (x+1)}{2 \sqrt [3]{2 x^2+4 x+3}}-\frac {3 \sqrt {(4 x+4)^2} \left (-\int \frac {2 \sqrt {2} \left (-4 x+\sqrt {3}-3\right )}{\sqrt {(4 x+4)^2}}d\sqrt [3]{\frac {1}{8} (4 x+4)^2+1}-\frac {4 \sqrt {2 \left (2-\sqrt {3}\right )} \left (1+\sqrt {3}\right ) (-4 x-3) \sqrt {\frac {4 x+\left (\frac {1}{8} (4 x+4)^2+1\right )^{2/3}+5}{\left (-4 x-\sqrt {3}-3\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {-4 x+\sqrt {3}-3}{-4 x-\sqrt {3}-3}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {-\frac {-4 x-3}{\left (-4 x-\sqrt {3}-3\right )^2}} \sqrt {(4 x+4)^2}}\right )}{4 \sqrt {2} (4 x+4)}\) |
\(\Big \downarrow \) 2418 |
\(\displaystyle \frac {3 (x+1)}{2 \sqrt [3]{2 x^2+4 x+3}}-\frac {3 \sqrt {(4 x+4)^2} \left (-\frac {4 \sqrt {2 \left (2-\sqrt {3}\right )} \left (1+\sqrt {3}\right ) (-4 x-3) \sqrt {\frac {4 x+\left (\frac {1}{8} (4 x+4)^2+1\right )^{2/3}+5}{\left (-4 x-\sqrt {3}-3\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {-4 x+\sqrt {3}-3}{-4 x-\sqrt {3}-3}\right ),-7+4 \sqrt {3}\right )}{\sqrt [4]{3} \sqrt {-\frac {-4 x-3}{\left (-4 x-\sqrt {3}-3\right )^2}} \sqrt {(4 x+4)^2}}+\frac {2 \sqrt [4]{3} \sqrt {2 \left (2+\sqrt {3}\right )} (-4 x-3) \sqrt {\frac {4 x+\left (\frac {1}{8} (4 x+4)^2+1\right )^{2/3}+5}{\left (-4 x-\sqrt {3}-3\right )^2}} E\left (\arcsin \left (\frac {-4 x+\sqrt {3}-3}{-4 x-\sqrt {3}-3}\right )|-7+4 \sqrt {3}\right )}{\sqrt {-\frac {-4 x-3}{\left (-4 x-\sqrt {3}-3\right )^2}} \sqrt {(4 x+4)^2}}-\frac {\sqrt {(4 x+4)^2}}{\sqrt {2} \left (-4 x-\sqrt {3}-3\right )}\right )}{4 \sqrt {2} (4 x+4)}\) |
Input:
Int[(3 + 4*x + 2*x^2)^(-4/3),x]
Output:
(3*(1 + x))/(2*(3 + 4*x + 2*x^2)^(1/3)) - (3*Sqrt[(4 + 4*x)^2]*(-(Sqrt[(4 + 4*x)^2]/(Sqrt[2]*(-3 - Sqrt[3] - 4*x))) + (2*3^(1/4)*Sqrt[2*(2 + Sqrt[3] )]*(-3 - 4*x)*Sqrt[(5 + 4*x + (1 + (4 + 4*x)^2/8)^(2/3))/(-3 - Sqrt[3] - 4 *x)^2]*EllipticE[ArcSin[(-3 + Sqrt[3] - 4*x)/(-3 - Sqrt[3] - 4*x)], -7 + 4 *Sqrt[3]])/(Sqrt[-((-3 - 4*x)/(-3 - Sqrt[3] - 4*x)^2)]*Sqrt[(4 + 4*x)^2]) - (4*Sqrt[2*(2 - Sqrt[3])]*(1 + Sqrt[3])*(-3 - 4*x)*Sqrt[(5 + 4*x + (1 + ( 4 + 4*x)^2/8)^(2/3))/(-3 - Sqrt[3] - 4*x)^2]*EllipticF[ArcSin[(-3 + Sqrt[3 ] - 4*x)/(-3 - Sqrt[3] - 4*x)], -7 + 4*Sqrt[3]])/(3^(1/4)*Sqrt[-((-3 - 4*x )/(-3 - Sqrt[3] - 4*x)^2)]*Sqrt[(4 + 4*x)^2])))/(4*Sqrt[2]*(4 + 4*x))
Int[((a_) + (b_.)*(x_)^2)^(-1/3), x_Symbol] :> Simp[3*(Sqrt[b*x^2]/(2*b*x)) Subst[Int[x/Sqrt[-a + x^3], x], x, (a + b*x^2)^(1/3)], x] /; FreeQ[{a, b }, x]
Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[2*Sqrt[2 - Sqrt[3]]*(s + r*x)*(Sqrt[(s^2 - r*s *x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[(- s)*((s + r*x)/((1 - Sqrt[3])*s + r*x)^2)]))*EllipticF[ArcSin[((1 + Sqrt[3]) *s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b}, x ] && NegQ[a]
Int[(x_)/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3] ], s = Denom[Rt[b/a, 3]]}, Simp[(-(1 + Sqrt[3]))*(s/r) Int[1/Sqrt[a + b*x ^3], x], x] + Simp[1/r Int[((1 + Sqrt[3])*s + r*x)/Sqrt[a + b*x^3], x], x ]] /; FreeQ[{a, b}, x] && NegQ[a]
Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(b + 2*c*x) *((a + b*x + c*x^2)^(p + 1)/((p + 1)*(b^2 - 4*a*c))), x] - Simp[2*c*((2*p + 3)/((p + 1)*(b^2 - 4*a*c))) Int[(a + b*x + c*x^2)^(p + 1), x], x] /; Fre eQ[{a, b, c}, x] && LtQ[p, -1] && (IntegerQ[4*p] || IntegerQ[3*p])
Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[1/(2*c*(-4* (c/(b^2 - 4*a*c)))^p) Subst[Int[Simp[1 - x^2/(b^2 - 4*a*c), x]^p, x], x, b + 2*c*x], x] /; FreeQ[{a, b, c, p}, x] && GtQ[4*a - b^2/c, 0]
Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = N umer[Simplify[(1 + Sqrt[3])*(d/c)]], s = Denom[Simplify[(1 + Sqrt[3])*(d/c) ]]}, Simp[2*d*s^3*(Sqrt[a + b*x^3]/(a*r^2*((1 - Sqrt[3])*s + r*x))), x] + S imp[3^(1/4)*Sqrt[2 + Sqrt[3]]*d*s*(s + r*x)*(Sqrt[(s^2 - r*s*x + r^2*x^2)/( (1 - Sqrt[3])*s + r*x)^2]/(r^2*Sqrt[a + b*x^3]*Sqrt[(-s)*((s + r*x)/((1 - S qrt[3])*s + r*x)^2)]))*EllipticE[ArcSin[((1 + Sqrt[3])*s + r*x)/((1 - Sqrt[ 3])*s + r*x)], -7 + 4*Sqrt[3]], x]] /; FreeQ[{a, b, c, d}, x] && NegQ[a] && EqQ[b*c^3 - 2*(5 + 3*Sqrt[3])*a*d^3, 0]
\[\int \frac {1}{\left (2 x^{2}+4 x +3\right )^{\frac {4}{3}}}d x\]
Input:
int(1/(2*x^2+4*x+3)^(4/3),x)
Output:
int(1/(2*x^2+4*x+3)^(4/3),x)
\[ \int \frac {1}{\left (3+4 x+2 x^2\right )^{4/3}} \, dx=\int { \frac {1}{{\left (2 \, x^{2} + 4 \, x + 3\right )}^{\frac {4}{3}}} \,d x } \] Input:
integrate(1/(2*x^2+4*x+3)^(4/3),x, algorithm="fricas")
Output:
integral((2*x^2 + 4*x + 3)^(2/3)/(4*x^4 + 16*x^3 + 28*x^2 + 24*x + 9), x)
\[ \int \frac {1}{\left (3+4 x+2 x^2\right )^{4/3}} \, dx=\int \frac {1}{\left (2 x^{2} + 4 x + 3\right )^{\frac {4}{3}}}\, dx \] Input:
integrate(1/(2*x**2+4*x+3)**(4/3),x)
Output:
Integral((2*x**2 + 4*x + 3)**(-4/3), x)
\[ \int \frac {1}{\left (3+4 x+2 x^2\right )^{4/3}} \, dx=\int { \frac {1}{{\left (2 \, x^{2} + 4 \, x + 3\right )}^{\frac {4}{3}}} \,d x } \] Input:
integrate(1/(2*x^2+4*x+3)^(4/3),x, algorithm="maxima")
Output:
integrate((2*x^2 + 4*x + 3)^(-4/3), x)
\[ \int \frac {1}{\left (3+4 x+2 x^2\right )^{4/3}} \, dx=\int { \frac {1}{{\left (2 \, x^{2} + 4 \, x + 3\right )}^{\frac {4}{3}}} \,d x } \] Input:
integrate(1/(2*x^2+4*x+3)^(4/3),x, algorithm="giac")
Output:
integrate((2*x^2 + 4*x + 3)^(-4/3), x)
Timed out. \[ \int \frac {1}{\left (3+4 x+2 x^2\right )^{4/3}} \, dx=\int \frac {1}{{\left (2\,x^2+4\,x+3\right )}^{4/3}} \,d x \] Input:
int(1/(4*x + 2*x^2 + 3)^(4/3),x)
Output:
int(1/(4*x + 2*x^2 + 3)^(4/3), x)
\[ \int \frac {1}{\left (3+4 x+2 x^2\right )^{4/3}} \, dx=\int \frac {1}{2 \left (2 x^{2}+4 x +3\right )^{\frac {1}{3}} x^{2}+4 \left (2 x^{2}+4 x +3\right )^{\frac {1}{3}} x +3 \left (2 x^{2}+4 x +3\right )^{\frac {1}{3}}}d x \] Input:
int(1/(2*x^2+4*x+3)^(4/3),x)
Output:
int(1/(2*(2*x**2 + 4*x + 3)**(1/3)*x**2 + 4*(2*x**2 + 4*x + 3)**(1/3)*x + 3*(2*x**2 + 4*x + 3)**(1/3)),x)