\(\int \frac {1}{(-a-b x^2-c x^4)^{3/2}} \, dx\) [314]

Optimal result

Integrand size = 20, antiderivative size = 371 \[ \int \frac {1}{\left (-a-b x^2-c x^4\right )^{3/2}} \, dx=-\frac {x \left (b^2-2 a c+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {-a-b x^2-c x^4}}-\frac {b \sqrt {c} x \sqrt {-a-b x^2-c x^4}}{a \left (b^2-4 a c\right ) \left (\sqrt {a}+\sqrt {c} x^2\right )}-\frac {b \sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{a^{3/4} \left (b^2-4 a c\right ) \sqrt {-a-b x^2-c x^4}}+\frac {\sqrt [4]{c} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{2 a^{3/4} \left (b-2 \sqrt {a} \sqrt {c}\right ) \sqrt {-a-b x^2-c x^4}} \] Output:

-x*(b*c*x^2-2*a*c+b^2)/a/(-4*a*c+b^2)/(-c*x^4-b*x^2-a)^(1/2)-b*c^(1/2)*x*( 
-c*x^4-b*x^2-a)^(1/2)/a/(-4*a*c+b^2)/(a^(1/2)+c^(1/2)*x^2)-b*c^(1/4)*(a^(1 
/2)+c^(1/2)*x^2)*((c*x^4+b*x^2+a)/(a^(1/2)+c^(1/2)*x^2)^2)^(1/2)*EllipticE 
(sin(2*arctan(c^(1/4)*x/a^(1/4))),1/2*(2-b/a^(1/2)/c^(1/2))^(1/2))/a^(3/4) 
/(-4*a*c+b^2)/(-c*x^4-b*x^2-a)^(1/2)+1/2*c^(1/4)*(a^(1/2)+c^(1/2)*x^2)*((c 
*x^4+b*x^2+a)/(a^(1/2)+c^(1/2)*x^2)^2)^(1/2)*InverseJacobiAM(2*arctan(c^(1 
/4)*x/a^(1/4)),1/2*(2-b/a^(1/2)/c^(1/2))^(1/2))/a^(3/4)/(b-2*a^(1/2)*c^(1/ 
2))/(-c*x^4-b*x^2-a)^(1/2)
 

Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 10.65 (sec) , antiderivative size = 464, normalized size of antiderivative = 1.25 \[ \int \frac {1}{\left (-a-b x^2-c x^4\right )^{3/2}} \, dx=-\frac {4 \sqrt {\frac {c}{b-\sqrt {b^2-4 a c}}} x \left (b^2-2 a c+b c x^2\right )+i b \left (b+\sqrt {b^2-4 a c}\right ) \sqrt {\frac {b+\sqrt {b^2-4 a c}+2 c x^2}{b+\sqrt {b^2-4 a c}}} \sqrt {\frac {2 b-2 \sqrt {b^2-4 a c}+4 c x^2}{b-\sqrt {b^2-4 a c}}} E\left (i \text {arcsinh}\left (\sqrt {2} \sqrt {\frac {c}{b-\sqrt {b^2-4 a c}}} x\right )|\frac {b-\sqrt {b^2-4 a c}}{b+\sqrt {b^2-4 a c}}\right )-i \left (b^2-4 a c+b \sqrt {b^2-4 a c}\right ) \sqrt {\frac {b+\sqrt {b^2-4 a c}+2 c x^2}{b+\sqrt {b^2-4 a c}}} \sqrt {\frac {2 b-2 \sqrt {b^2-4 a c}+4 c x^2}{b-\sqrt {b^2-4 a c}}} \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {2} \sqrt {\frac {c}{b-\sqrt {b^2-4 a c}}} x\right ),\frac {b-\sqrt {b^2-4 a c}}{b+\sqrt {b^2-4 a c}}\right )}{4 a \left (b^2-4 a c\right ) \sqrt {\frac {c}{b-\sqrt {b^2-4 a c}}} \sqrt {-a-x^2 \left (b+c x^2\right )}} \] Input:

Integrate[(-a - b*x^2 - c*x^4)^(-3/2),x]
 

Output:

-1/4*(4*Sqrt[c/(b - Sqrt[b^2 - 4*a*c])]*x*(b^2 - 2*a*c + b*c*x^2) + I*b*(b 
 + Sqrt[b^2 - 4*a*c])*Sqrt[(b + Sqrt[b^2 - 4*a*c] + 2*c*x^2)/(b + Sqrt[b^2 
 - 4*a*c])]*Sqrt[(2*b - 2*Sqrt[b^2 - 4*a*c] + 4*c*x^2)/(b - Sqrt[b^2 - 4*a 
*c])]*EllipticE[I*ArcSinh[Sqrt[2]*Sqrt[c/(b - Sqrt[b^2 - 4*a*c])]*x], (b - 
 Sqrt[b^2 - 4*a*c])/(b + Sqrt[b^2 - 4*a*c])] - I*(b^2 - 4*a*c + b*Sqrt[b^2 
 - 4*a*c])*Sqrt[(b + Sqrt[b^2 - 4*a*c] + 2*c*x^2)/(b + Sqrt[b^2 - 4*a*c])] 
*Sqrt[(2*b - 2*Sqrt[b^2 - 4*a*c] + 4*c*x^2)/(b - Sqrt[b^2 - 4*a*c])]*Ellip 
ticF[I*ArcSinh[Sqrt[2]*Sqrt[c/(b - Sqrt[b^2 - 4*a*c])]*x], (b - Sqrt[b^2 - 
 4*a*c])/(b + Sqrt[b^2 - 4*a*c])])/(a*(b^2 - 4*a*c)*Sqrt[c/(b - Sqrt[b^2 - 
 4*a*c])]*Sqrt[-a - x^2*(b + c*x^2)])
 

Rubi [A] (verified)

Time = 0.72 (sec) , antiderivative size = 363, normalized size of antiderivative = 0.98, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {1405, 27, 1511, 27, 1416, 1509}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{\left (-a-b x^2-c x^4\right )^{3/2}} \, dx\)

\(\Big \downarrow \) 1405

\(\displaystyle \frac {\int \frac {c \left (b x^2+2 a\right )}{\sqrt {-c x^4-b x^2-a}}dx}{a \left (b^2-4 a c\right )}-\frac {x \left (-2 a c+b^2+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {-a-b x^2-c x^4}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {c \int \frac {b x^2+2 a}{\sqrt {-c x^4-b x^2-a}}dx}{a \left (b^2-4 a c\right )}-\frac {x \left (-2 a c+b^2+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {-a-b x^2-c x^4}}\)

\(\Big \downarrow \) 1511

\(\displaystyle \frac {c \left (\sqrt {a} \left (2 \sqrt {a}+\frac {b}{\sqrt {c}}\right ) \int \frac {1}{\sqrt {-c x^4-b x^2-a}}dx-\frac {\sqrt {a} b \int \frac {\sqrt {a}-\sqrt {c} x^2}{\sqrt {a} \sqrt {-c x^4-b x^2-a}}dx}{\sqrt {c}}\right )}{a \left (b^2-4 a c\right )}-\frac {x \left (-2 a c+b^2+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {-a-b x^2-c x^4}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {c \left (\sqrt {a} \left (2 \sqrt {a}+\frac {b}{\sqrt {c}}\right ) \int \frac {1}{\sqrt {-c x^4-b x^2-a}}dx-\frac {b \int \frac {\sqrt {a}-\sqrt {c} x^2}{\sqrt {-c x^4-b x^2-a}}dx}{\sqrt {c}}\right )}{a \left (b^2-4 a c\right )}-\frac {x \left (-2 a c+b^2+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {-a-b x^2-c x^4}}\)

\(\Big \downarrow \) 1416

\(\displaystyle \frac {c \left (\frac {\sqrt [4]{a} \left (2 \sqrt {a}+\frac {b}{\sqrt {c}}\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{2 \sqrt [4]{c} \sqrt {-a-b x^2-c x^4}}-\frac {b \int \frac {\sqrt {a}-\sqrt {c} x^2}{\sqrt {-c x^4-b x^2-a}}dx}{\sqrt {c}}\right )}{a \left (b^2-4 a c\right )}-\frac {x \left (-2 a c+b^2+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {-a-b x^2-c x^4}}\)

\(\Big \downarrow \) 1509

\(\displaystyle \frac {c \left (\frac {\sqrt [4]{a} \left (2 \sqrt {a}+\frac {b}{\sqrt {c}}\right ) \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right ),\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{2 \sqrt [4]{c} \sqrt {-a-b x^2-c x^4}}-\frac {b \left (\frac {\sqrt [4]{a} \left (\sqrt {a}+\sqrt {c} x^2\right ) \sqrt {\frac {a+b x^2+c x^4}{\left (\sqrt {a}+\sqrt {c} x^2\right )^2}} E\left (2 \arctan \left (\frac {\sqrt [4]{c} x}{\sqrt [4]{a}}\right )|\frac {1}{4} \left (2-\frac {b}{\sqrt {a} \sqrt {c}}\right )\right )}{\sqrt [4]{c} \sqrt {-a-b x^2-c x^4}}+\frac {x \sqrt {-a-b x^2-c x^4}}{\sqrt {a}+\sqrt {c} x^2}\right )}{\sqrt {c}}\right )}{a \left (b^2-4 a c\right )}-\frac {x \left (-2 a c+b^2+b c x^2\right )}{a \left (b^2-4 a c\right ) \sqrt {-a-b x^2-c x^4}}\)

Input:

Int[(-a - b*x^2 - c*x^4)^(-3/2),x]
 

Output:

-((x*(b^2 - 2*a*c + b*c*x^2))/(a*(b^2 - 4*a*c)*Sqrt[-a - b*x^2 - c*x^4])) 
+ (c*(-((b*((x*Sqrt[-a - b*x^2 - c*x^4])/(Sqrt[a] + Sqrt[c]*x^2) + (a^(1/4 
)*(Sqrt[a] + Sqrt[c]*x^2)*Sqrt[(a + b*x^2 + c*x^4)/(Sqrt[a] + Sqrt[c]*x^2) 
^2]*EllipticE[2*ArcTan[(c^(1/4)*x)/a^(1/4)], (2 - b/(Sqrt[a]*Sqrt[c]))/4]) 
/(c^(1/4)*Sqrt[-a - b*x^2 - c*x^4])))/Sqrt[c]) + (a^(1/4)*(2*Sqrt[a] + b/S 
qrt[c])*(Sqrt[a] + Sqrt[c]*x^2)*Sqrt[(a + b*x^2 + c*x^4)/(Sqrt[a] + Sqrt[c 
]*x^2)^2]*EllipticF[2*ArcTan[(c^(1/4)*x)/a^(1/4)], (2 - b/(Sqrt[a]*Sqrt[c] 
))/4])/(2*c^(1/4)*Sqrt[-a - b*x^2 - c*x^4])))/(a*(b^2 - 4*a*c))
 

Defintions of rubi rules used

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 1405

Int[((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_), x_Symbol] :> Simp[(-x)*(b^2 
- 2*a*c + b*c*x^2)*((a + b*x^2 + c*x^4)^(p + 1)/(2*a*(p + 1)*(b^2 - 4*a*c)) 
), x] + Simp[1/(2*a*(p + 1)*(b^2 - 4*a*c))   Int[(b^2 - 2*a*c + 2*(p + 1)*( 
b^2 - 4*a*c) + b*c*(4*p + 7)*x^2)*(a + b*x^2 + c*x^4)^(p + 1), x], x] /; Fr 
eeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0] && LtQ[p, -1] && IntegerQ[2*p]
 

rule 1416

Int[1/Sqrt[(a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4], x_Symbol] :> With[{q = Rt[c 
/a, 4]}, Simp[(1 + q^2*x^2)*(Sqrt[(a + b*x^2 + c*x^4)/(a*(1 + q^2*x^2)^2)]/ 
(2*q*Sqrt[a + b*x^2 + c*x^4]))*EllipticF[2*ArcTan[q*x], 1/2 - b*(q^2/(4*c)) 
], x]] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0] && PosQ[c/a]
 

rule 1509

Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4], x_Symbo 
l] :> With[{q = Rt[c/a, 4]}, Simp[(-d)*x*(Sqrt[a + b*x^2 + c*x^4]/(a*(1 + q 
^2*x^2))), x] + Simp[d*(1 + q^2*x^2)*(Sqrt[(a + b*x^2 + c*x^4)/(a*(1 + q^2* 
x^2)^2)]/(q*Sqrt[a + b*x^2 + c*x^4]))*EllipticE[2*ArcTan[q*x], 1/2 - b*(q^2 
/(4*c))], x] /; EqQ[e + d*q^2, 0]] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^2 
- 4*a*c, 0] && PosQ[c/a]
 

rule 1511

Int[((d_) + (e_.)*(x_)^2)/Sqrt[(a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4], x_Symbo 
l] :> With[{q = Rt[c/a, 2]}, Simp[(e + d*q)/q   Int[1/Sqrt[a + b*x^2 + c*x^ 
4], x], x] - Simp[e/q   Int[(1 - q*x^2)/Sqrt[a + b*x^2 + c*x^4], x], x] /; 
NeQ[e + d*q, 0]] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && Pos 
Q[c/a]
 

Maple [A] (verified)

Time = 0.54 (sec) , antiderivative size = 479, normalized size of antiderivative = 1.29

method	result	size
default	\(\frac {2 c \left (\frac {b \,x^{3}}{2 a \left (4 a c -b^{2}\right )}-\frac {\left (2 a c -b^{2}\right ) x}{2 a \left (4 a c -b^{2}\right ) c}\right )}{\sqrt {-\left (x^{4}+\frac {b \,x^{2}}{c}+\frac {a}{c}\right ) c}}+\frac {\left (-\frac {1}{a}+\frac {2 a c -b^{2}}{a \left (4 a c -b^{2}\right )}\right ) \sqrt {4+\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right ) x^{2}}{a}}\, \sqrt {4-\frac {2 \left (-b +\sqrt {-4 a c +b^{2}}\right ) x^{2}}{a}}\, \operatorname {EllipticF}\left (\frac {x \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}}{2}, \frac {\sqrt {-4-\frac {2 b \left (-b +\sqrt {-4 a c +b^{2}}\right )}{a c}}}{2}\right )}{2 \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}\, \sqrt {-c \,x^{4}-b \,x^{2}-a}}-\frac {b c \sqrt {4+\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right ) x^{2}}{a}}\, \sqrt {4-\frac {2 \left (-b +\sqrt {-4 a c +b^{2}}\right ) x^{2}}{a}}\, \left (\operatorname {EllipticF}\left (\frac {x \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}}{2}, \frac {\sqrt {-4-\frac {2 b \left (-b +\sqrt {-4 a c +b^{2}}\right )}{a c}}}{2}\right )-\operatorname {EllipticE}\left (\frac {x \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}}{2}, \frac {\sqrt {-4-\frac {2 b \left (-b +\sqrt {-4 a c +b^{2}}\right )}{a c}}}{2}\right )\right )}{\left (4 a c -b^{2}\right ) \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}\, \sqrt {-c \,x^{4}-b \,x^{2}-a}\, \left (-b +\sqrt {-4 a c +b^{2}}\right )}\)	\(479\)
elliptic	\(\frac {2 c \left (\frac {b \,x^{3}}{2 a \left (4 a c -b^{2}\right )}-\frac {\left (2 a c -b^{2}\right ) x}{2 a \left (4 a c -b^{2}\right ) c}\right )}{\sqrt {-\left (x^{4}+\frac {b \,x^{2}}{c}+\frac {a}{c}\right ) c}}+\frac {\left (-\frac {1}{a}+\frac {2 a c -b^{2}}{a \left (4 a c -b^{2}\right )}\right ) \sqrt {4+\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right ) x^{2}}{a}}\, \sqrt {4-\frac {2 \left (-b +\sqrt {-4 a c +b^{2}}\right ) x^{2}}{a}}\, \operatorname {EllipticF}\left (\frac {x \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}}{2}, \frac {\sqrt {-4-\frac {2 b \left (-b +\sqrt {-4 a c +b^{2}}\right )}{a c}}}{2}\right )}{2 \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}\, \sqrt {-c \,x^{4}-b \,x^{2}-a}}-\frac {b c \sqrt {4+\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right ) x^{2}}{a}}\, \sqrt {4-\frac {2 \left (-b +\sqrt {-4 a c +b^{2}}\right ) x^{2}}{a}}\, \left (\operatorname {EllipticF}\left (\frac {x \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}}{2}, \frac {\sqrt {-4-\frac {2 b \left (-b +\sqrt {-4 a c +b^{2}}\right )}{a c}}}{2}\right )-\operatorname {EllipticE}\left (\frac {x \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}}{2}, \frac {\sqrt {-4-\frac {2 b \left (-b +\sqrt {-4 a c +b^{2}}\right )}{a c}}}{2}\right )\right )}{\left (4 a c -b^{2}\right ) \sqrt {-\frac {2 \left (b +\sqrt {-4 a c +b^{2}}\right )}{a}}\, \sqrt {-c \,x^{4}-b \,x^{2}-a}\, \left (-b +\sqrt {-4 a c +b^{2}}\right )}\)	\(479\)

Input:

int(1/(-c*x^4-b*x^2-a)^(3/2),x,method=_RETURNVERBOSE)
 

Output:

2*c*(1/2*b/a/(4*a*c-b^2)*x^3-1/2*(2*a*c-b^2)/a/(4*a*c-b^2)/c*x)/(-(x^4+1/c 
*b*x^2+1/c*a)*c)^(1/2)+1/2*(-1/a+(2*a*c-b^2)/a/(4*a*c-b^2))/(-2*(b+(-4*a*c 
+b^2)^(1/2))/a)^(1/2)*(4+2*(b+(-4*a*c+b^2)^(1/2))/a*x^2)^(1/2)*(4-2*(-b+(- 
4*a*c+b^2)^(1/2))/a*x^2)^(1/2)/(-c*x^4-b*x^2-a)^(1/2)*EllipticF(1/2*x*(-2* 
(b+(-4*a*c+b^2)^(1/2))/a)^(1/2),1/2*(-4-2*b*(-b+(-4*a*c+b^2)^(1/2))/a/c)^( 
1/2))-b/(4*a*c-b^2)*c/(-2*(b+(-4*a*c+b^2)^(1/2))/a)^(1/2)*(4+2*(b+(-4*a*c+ 
b^2)^(1/2))/a*x^2)^(1/2)*(4-2*(-b+(-4*a*c+b^2)^(1/2))/a*x^2)^(1/2)/(-c*x^4 
-b*x^2-a)^(1/2)/(-b+(-4*a*c+b^2)^(1/2))*(EllipticF(1/2*x*(-2*(b+(-4*a*c+b^ 
2)^(1/2))/a)^(1/2),1/2*(-4-2*b*(-b+(-4*a*c+b^2)^(1/2))/a/c)^(1/2))-Ellipti 
cE(1/2*x*(-2*(b+(-4*a*c+b^2)^(1/2))/a)^(1/2),1/2*(-4-2*b*(-b+(-4*a*c+b^2)^ 
(1/2))/a/c)^(1/2)))
 

Fricas [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 460, normalized size of antiderivative = 1.24 \[ \int \frac {1}{\left (-a-b x^2-c x^4\right )^{3/2}} \, dx=-\frac {\sqrt {\frac {1}{2}} {\left (b^{2} c x^{4} + b^{3} x^{2} + a b^{2} - {\left (a b c x^{4} + a b^{2} x^{2} + a^{2} b\right )} \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}}\right )} \sqrt {-a} \sqrt {\frac {a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} - b}{a}} E(\arcsin \left (\sqrt {\frac {1}{2}} x \sqrt {\frac {a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} - b}{a}}\right )\,|\,\frac {a b \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} + b^{2} - 2 \, a c}{2 \, a c}) - \sqrt {\frac {1}{2}} {\left ({\left (2 \, a b + b^{2}\right )} c x^{4} + 2 \, a^{2} b + a b^{2} + {\left (2 \, a b^{2} + b^{3}\right )} x^{2} + {\left ({\left (2 \, a^{2} - a b\right )} c x^{4} + 2 \, a^{3} - a^{2} b + {\left (2 \, a^{2} b - a b^{2}\right )} x^{2}\right )} \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}}\right )} \sqrt {-a} \sqrt {\frac {a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} - b}{a}} F(\arcsin \left (\sqrt {\frac {1}{2}} x \sqrt {\frac {a \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} - b}{a}}\right )\,|\,\frac {a b \sqrt {\frac {b^{2} - 4 \, a c}{a^{2}}} + b^{2} - 2 \, a c}{2 \, a c}) - 2 \, {\left (a b c x^{3} + {\left (a b^{2} - 2 \, a^{2} c\right )} x\right )} \sqrt {-c x^{4} - b x^{2} - a}}{2 \, {\left (a^{3} b^{2} - 4 \, a^{4} c + {\left (a^{2} b^{2} c - 4 \, a^{3} c^{2}\right )} x^{4} + {\left (a^{2} b^{3} - 4 \, a^{3} b c\right )} x^{2}\right )}} \] Input:

integrate(1/(-c*x^4-b*x^2-a)^(3/2),x, algorithm="fricas")
 

Output:

-1/2*(sqrt(1/2)*(b^2*c*x^4 + b^3*x^2 + a*b^2 - (a*b*c*x^4 + a*b^2*x^2 + a^ 
2*b)*sqrt((b^2 - 4*a*c)/a^2))*sqrt(-a)*sqrt((a*sqrt((b^2 - 4*a*c)/a^2) - b 
)/a)*elliptic_e(arcsin(sqrt(1/2)*x*sqrt((a*sqrt((b^2 - 4*a*c)/a^2) - b)/a) 
), 1/2*(a*b*sqrt((b^2 - 4*a*c)/a^2) + b^2 - 2*a*c)/(a*c)) - sqrt(1/2)*((2* 
a*b + b^2)*c*x^4 + 2*a^2*b + a*b^2 + (2*a*b^2 + b^3)*x^2 + ((2*a^2 - a*b)* 
c*x^4 + 2*a^3 - a^2*b + (2*a^2*b - a*b^2)*x^2)*sqrt((b^2 - 4*a*c)/a^2))*sq 
rt(-a)*sqrt((a*sqrt((b^2 - 4*a*c)/a^2) - b)/a)*elliptic_f(arcsin(sqrt(1/2) 
*x*sqrt((a*sqrt((b^2 - 4*a*c)/a^2) - b)/a)), 1/2*(a*b*sqrt((b^2 - 4*a*c)/a 
^2) + b^2 - 2*a*c)/(a*c)) - 2*(a*b*c*x^3 + (a*b^2 - 2*a^2*c)*x)*sqrt(-c*x^ 
4 - b*x^2 - a))/(a^3*b^2 - 4*a^4*c + (a^2*b^2*c - 4*a^3*c^2)*x^4 + (a^2*b^ 
3 - 4*a^3*b*c)*x^2)
 

Sympy [F]

\[ \int \frac {1}{\left (-a-b x^2-c x^4\right )^{3/2}} \, dx=\int \frac {1}{\left (- a - b x^{2} - c x^{4}\right )^{\frac {3}{2}}}\, dx \] Input:

integrate(1/(-c*x**4-b*x**2-a)**(3/2),x)
 

Output:

Integral((-a - b*x**2 - c*x**4)**(-3/2), x)
 

Maxima [F]

\[ \int \frac {1}{\left (-a-b x^2-c x^4\right )^{3/2}} \, dx=\int { \frac {1}{{\left (-c x^{4} - b x^{2} - a\right )}^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/(-c*x^4-b*x^2-a)^(3/2),x, algorithm="maxima")
 

Output:

integrate((-c*x^4 - b*x^2 - a)^(-3/2), x)
 

Giac [F]

\[ \int \frac {1}{\left (-a-b x^2-c x^4\right )^{3/2}} \, dx=\int { \frac {1}{{\left (-c x^{4} - b x^{2} - a\right )}^{\frac {3}{2}}} \,d x } \] Input:

integrate(1/(-c*x^4-b*x^2-a)^(3/2),x, algorithm="giac")
 

Output:

integrate((-c*x^4 - b*x^2 - a)^(-3/2), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{\left (-a-b x^2-c x^4\right )^{3/2}} \, dx=\int \frac {1}{{\left (-c\,x^4-b\,x^2-a\right )}^{3/2}} \,d x \] Input:

int(1/(- a - b*x^2 - c*x^4)^(3/2),x)
 

Output:

int(1/(- a - b*x^2 - c*x^4)^(3/2), x)
 

Reduce [F]

\[ \int \frac {1}{\left (-a-b x^2-c x^4\right )^{3/2}} \, dx=\left (\int \frac {\sqrt {c \,x^{4}+b \,x^{2}+a}}{c^{2} x^{8}+2 b c \,x^{6}+2 a c \,x^{4}+b^{2} x^{4}+2 a b \,x^{2}+a^{2}}d x \right ) i \] Input:

int(1/(-c*x^4-b*x^2-a)^(3/2),x)
 

Output:

int(sqrt(a + b*x**2 + c*x**4)/(a**2 + 2*a*b*x**2 + 2*a*c*x**4 + b**2*x**4 
+ 2*b*c*x**6 + c**2*x**8),x)*i