\(\int \frac {(d x)^{19/2}}{(a^2+2 a b x^2+b^2 x^4)^2} \, dx\) [456]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [C] (verification not implemented)
Sympy [F]
Maxima [A] (verification not implemented)
Giac [A] (verification not implemented)
Mupad [B] (verification not implemented)
Reduce [B] (verification not implemented)

Optimal result

Integrand size = 28, antiderivative size = 291 \[ \int \frac {(d x)^{19/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=-\frac {663 a d^9 \sqrt {d x}}{64 b^5}+\frac {663 d^7 (d x)^{5/2}}{320 b^4}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}-\frac {17 d^3 (d x)^{13/2}}{48 b^2 \left (a+b x^2\right )^2}-\frac {221 d^5 (d x)^{9/2}}{192 b^3 \left (a+b x^2\right )}-\frac {663 a^{5/4} d^{19/2} \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} b^{21/4}}+\frac {663 a^{5/4} d^{19/2} \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} b^{21/4}}+\frac {663 a^{5/4} d^{19/2} \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}}{\sqrt {d} \left (\sqrt {a}+\sqrt {b} x\right )}\right )}{128 \sqrt {2} b^{21/4}} \] Output:

-663/64*a*d^9*(d*x)^(1/2)/b^5+663/320*d^7*(d*x)^(5/2)/b^4-1/6*d*(d*x)^(17/ 
2)/b/(b*x^2+a)^3-17/48*d^3*(d*x)^(13/2)/b^2/(b*x^2+a)^2-221/192*d^5*(d*x)^ 
(9/2)/b^3/(b*x^2+a)-663/256*a^(5/4)*d^(19/2)*arctan(1-2^(1/2)*b^(1/4)*(d*x 
)^(1/2)/a^(1/4)/d^(1/2))*2^(1/2)/b^(21/4)+663/256*a^(5/4)*d^(19/2)*arctan( 
1+2^(1/2)*b^(1/4)*(d*x)^(1/2)/a^(1/4)/d^(1/2))*2^(1/2)/b^(21/4)+663/256*a^ 
(5/4)*d^(19/2)*arctanh(2^(1/2)*a^(1/4)*b^(1/4)*(d*x)^(1/2)/d^(1/2)/(a^(1/2 
)+b^(1/2)*x))*2^(1/2)/b^(21/4)
 

Mathematica [A] (verified)

Time = 0.61 (sec) , antiderivative size = 205, normalized size of antiderivative = 0.70 \[ \int \frac {(d x)^{19/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=\frac {d^9 \sqrt {d x} \left (4 \sqrt [4]{b} \sqrt {x} \left (-9945 a^4-27846 a^3 b x^2-24973 a^2 b^2 x^4-6528 a b^3 x^6+384 b^4 x^8\right )+9945 \sqrt {2} a^{5/4} \left (a+b x^2\right )^3 \arctan \left (\frac {-\sqrt {a}+\sqrt {b} x}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}\right )+9945 \sqrt {2} a^{5/4} \left (a+b x^2\right )^3 \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}{\sqrt {a}+\sqrt {b} x}\right )\right )}{3840 b^{21/4} \sqrt {x} \left (a+b x^2\right )^3} \] Input:

Integrate[(d*x)^(19/2)/(a^2 + 2*a*b*x^2 + b^2*x^4)^2,x]
 

Output:

(d^9*Sqrt[d*x]*(4*b^(1/4)*Sqrt[x]*(-9945*a^4 - 27846*a^3*b*x^2 - 24973*a^2 
*b^2*x^4 - 6528*a*b^3*x^6 + 384*b^4*x^8) + 9945*Sqrt[2]*a^(5/4)*(a + b*x^2 
)^3*ArcTan[(-Sqrt[a] + Sqrt[b]*x)/(Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[x])] + 994 
5*Sqrt[2]*a^(5/4)*(a + b*x^2)^3*ArcTanh[(Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[x])/ 
(Sqrt[a] + Sqrt[b]*x)]))/(3840*b^(21/4)*Sqrt[x]*(a + b*x^2)^3)
 

Rubi [A] (verified)

Time = 1.07 (sec) , antiderivative size = 419, normalized size of antiderivative = 1.44, number of steps used = 18, number of rules used = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.607, Rules used = {1380, 27, 252, 252, 252, 262, 262, 266, 755, 27, 1476, 1082, 217, 1479, 25, 27, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(d x)^{19/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx\)

\(\Big \downarrow \) 1380

\(\displaystyle b^4 \int \frac {(d x)^{19/2}}{b^4 \left (b x^2+a\right )^4}dx\)

\(\Big \downarrow \) 27

\(\displaystyle \int \frac {(d x)^{19/2}}{\left (a+b x^2\right )^4}dx\)

\(\Big \downarrow \) 252

\(\displaystyle \frac {17 d^2 \int \frac {(d x)^{15/2}}{\left (b x^2+a\right )^3}dx}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 252

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \int \frac {(d x)^{11/2}}{\left (b x^2+a\right )^2}dx}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 252

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \int \frac {(d x)^{7/2}}{b x^2+a}dx}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 262

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \int \frac {(d x)^{3/2}}{b x^2+a}dx}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 262

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {a d^2 \int \frac {1}{\sqrt {d x} \left (b x^2+a\right )}dx}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 266

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \int \frac {1}{b x^2+a}d\sqrt {d x}}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 755

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \left (\frac {\int \frac {d^2 \left (\sqrt {a} d-\sqrt {b} d x\right )}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {a} d}+\frac {\int \frac {d^2 \left (\sqrt {b} x d+\sqrt {a} d\right )}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {a} d}\right )}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \left (\frac {d \int \frac {\sqrt {a} d-\sqrt {b} d x}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {a}}+\frac {d \int \frac {\sqrt {b} x d+\sqrt {a} d}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {a}}\right )}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 1476

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \left (\frac {d \int \frac {\sqrt {a} d-\sqrt {b} d x}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {a}}+\frac {d \left (\frac {\int \frac {1}{x d+\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}}d\sqrt {d x}}{2 \sqrt {b}}+\frac {\int \frac {1}{x d+\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}}d\sqrt {d x}}{2 \sqrt {b}}\right )}{2 \sqrt {a}}\right )}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 1082

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \left (\frac {d \int \frac {\sqrt {a} d-\sqrt {b} d x}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {a}}+\frac {d \left (\frac {\int \frac {1}{-d x-1}d\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\int \frac {1}{-d x-1}d\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}\right )}{2 \sqrt {a}}\right )}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \left (\frac {d \int \frac {\sqrt {a} d-\sqrt {b} d x}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {a}}+\frac {d \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}\right )}{2 \sqrt {a}}\right )}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 1479

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \left (\frac {d \left (-\frac {\int -\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}-2 \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{b} \left (x d+\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt [4]{a} \sqrt {d}+\sqrt {2} \sqrt [4]{b} \sqrt {d x}\right )}{\sqrt [4]{b} \left (x d+\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}\right )}{2 \sqrt {a}}+\frac {d \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}\right )}{2 \sqrt {a}}\right )}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \left (\frac {d \left (\frac {\int \frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}-2 \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{b} \left (x d+\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}+\frac {\int \frac {\sqrt {2} \left (\sqrt [4]{a} \sqrt {d}+\sqrt {2} \sqrt [4]{b} \sqrt {d x}\right )}{\sqrt [4]{b} \left (x d+\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}\right )}{2 \sqrt {a}}+\frac {d \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}\right )}{2 \sqrt {a}}\right )}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \left (\frac {d \left (\frac {\int \frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}-2 \sqrt [4]{b} \sqrt {d x}}{x d+\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt {b} \sqrt {d}}+\frac {\int \frac {\sqrt [4]{a} \sqrt {d}+\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{x d+\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}}d\sqrt {d x}}{2 \sqrt [4]{a} \sqrt {b} \sqrt {d}}\right )}{2 \sqrt {a}}+\frac {d \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}\right )}{2 \sqrt {a}}\right )}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {17 d^2 \left (\frac {13 d^2 \left (\frac {9 d^2 \left (\frac {2 d (d x)^{5/2}}{5 b}-\frac {a d^2 \left (\frac {2 d \sqrt {d x}}{b}-\frac {2 a d \left (\frac {d \left (\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}\right )}{2 \sqrt {a}}+\frac {d \left (\frac {\log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d} \sqrt {d x}+\sqrt {a} d+\sqrt {b} d x\right )}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d} \sqrt {d x}+\sqrt {a} d+\sqrt {b} d x\right )}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}\right )}{2 \sqrt {a}}\right )}{b}\right )}{b}\right )}{4 b}-\frac {d (d x)^{9/2}}{2 b \left (a+b x^2\right )}\right )}{8 b}-\frac {d (d x)^{13/2}}{4 b \left (a+b x^2\right )^2}\right )}{12 b}-\frac {d (d x)^{17/2}}{6 b \left (a+b x^2\right )^3}\)

Input:

Int[(d*x)^(19/2)/(a^2 + 2*a*b*x^2 + b^2*x^4)^2,x]
 

Output:

-1/6*(d*(d*x)^(17/2))/(b*(a + b*x^2)^3) + (17*d^2*(-1/4*(d*(d*x)^(13/2))/( 
b*(a + b*x^2)^2) + (13*d^2*(-1/2*(d*(d*x)^(9/2))/(b*(a + b*x^2)) + (9*d^2* 
((2*d*(d*x)^(5/2))/(5*b) - (a*d^2*((2*d*Sqrt[d*x])/b - (2*a*d*((d*(-(ArcTa 
n[1 - (Sqrt[2]*b^(1/4)*Sqrt[d*x])/(a^(1/4)*Sqrt[d])]/(Sqrt[2]*a^(1/4)*b^(1 
/4)*Sqrt[d])) + ArcTan[1 + (Sqrt[2]*b^(1/4)*Sqrt[d*x])/(a^(1/4)*Sqrt[d])]/ 
(Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[d])))/(2*Sqrt[a]) + (d*(-1/2*Log[Sqrt[a]*d + 
 Sqrt[b]*d*x - Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[d]*Sqrt[d*x]]/(Sqrt[2]*a^(1/4) 
*b^(1/4)*Sqrt[d]) + Log[Sqrt[a]*d + Sqrt[b]*d*x + Sqrt[2]*a^(1/4)*b^(1/4)* 
Sqrt[d]*Sqrt[d*x]]/(2*Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[d])))/(2*Sqrt[a])))/b)) 
/b))/(4*b)))/(8*b)))/(12*b)
 

Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 252
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[c*(c*x 
)^(m - 1)*((a + b*x^2)^(p + 1)/(2*b*(p + 1))), x] - Simp[c^2*((m - 1)/(2*b* 
(p + 1)))   Int[(c*x)^(m - 2)*(a + b*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c 
}, x] && LtQ[p, -1] && GtQ[m, 1] &&  !ILtQ[(m + 2*p + 3)/2, 0] && IntBinomi 
alQ[a, b, c, 2, m, p, x]
 

rule 262
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[c*(c*x) 
^(m - 1)*((a + b*x^2)^(p + 1)/(b*(m + 2*p + 1))), x] - Simp[a*c^2*((m - 1)/ 
(b*(m + 2*p + 1)))   Int[(c*x)^(m - 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b 
, c, p}, x] && GtQ[m, 2 - 1] && NeQ[m + 2*p + 1, 0] && IntBinomialQ[a, b, c 
, 2, m, p, x]
 

rule 266
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De 
nominator[m]}, Simp[k/c   Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) 
^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I 
ntBinomialQ[a, b, c, 2, m, p, x]
 

rule 755
Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2] 
], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*r)   Int[(r - s*x^2)/(a + b*x^4) 
, x], x] + Simp[1/(2*r)   Int[(r + s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{a, 
 b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] & 
& AtomQ[SplitProduct[SumBaseQ, b]]))
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1380
Int[(u_)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> S 
imp[1/c^p   Int[u*(b/2 + c*x^n)^(2*p), x], x] /; FreeQ[{a, b, c, n, p}, x] 
&& EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]
 

rule 1476
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 
Maple [A] (verified)

Time = 2.52 (sec) , antiderivative size = 232, normalized size of antiderivative = 0.80

method result size
risch \(-\frac {2 \left (-b \,x^{2}+20 a \right ) x \,d^{10}}{5 b^{5} \sqrt {d x}}+\frac {2 a^{2} d^{11} \left (\frac {-\frac {617 b^{2} \left (d x \right )^{\frac {9}{2}}}{384}-\frac {173 a b \,d^{2} \left (d x \right )^{\frac {5}{2}}}{64}-\frac {151 \sqrt {d x}\, a^{2} d^{4}}{128}}{\left (b \,d^{2} x^{2}+a \,d^{2}\right )^{3}}+\frac {663 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{1024 a \,d^{2}}\right )}{b^{5}}\) \(232\)
derivativedivides \(2 d^{7} \left (-\frac {-\frac {b \left (d x \right )^{\frac {5}{2}}}{5}+4 \sqrt {d x}\, a \,d^{2}}{b^{5}}+\frac {a^{2} d^{4} \left (\frac {-\frac {617 b^{2} \left (d x \right )^{\frac {9}{2}}}{384}-\frac {173 a b \,d^{2} \left (d x \right )^{\frac {5}{2}}}{64}-\frac {151 \sqrt {d x}\, a^{2} d^{4}}{128}}{\left (b \,d^{2} x^{2}+a \,d^{2}\right )^{3}}+\frac {663 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{1024 a \,d^{2}}\right )}{b^{5}}\right )\) \(237\)
default \(2 d^{7} \left (-\frac {-\frac {b \left (d x \right )^{\frac {5}{2}}}{5}+4 \sqrt {d x}\, a \,d^{2}}{b^{5}}+\frac {a^{2} d^{4} \left (\frac {-\frac {617 b^{2} \left (d x \right )^{\frac {9}{2}}}{384}-\frac {173 a b \,d^{2} \left (d x \right )^{\frac {5}{2}}}{64}-\frac {151 \sqrt {d x}\, a^{2} d^{4}}{128}}{\left (b \,d^{2} x^{2}+a \,d^{2}\right )^{3}}+\frac {663 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{1024 a \,d^{2}}\right )}{b^{5}}\right )\) \(237\)
pseudoelliptic \(\frac {663 d^{5} \left (\frac {\ln \left (\frac {d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right ) \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} a \,d^{4} \sqrt {2}\, \left (b \,x^{2}+a \right )^{3}}{2}+\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, a \,d^{4} \left (b \,x^{2}+a \right )^{3} \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )+\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, a \,d^{4} \left (b \,x^{2}+a \right )^{3} \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )-\frac {1384 a^{3} \left (d x \right )^{\frac {5}{2}} b \,d^{2}}{663}-\frac {2468 \left (d x \right )^{\frac {9}{2}} a^{2} b^{2}}{1989}-4 d^{4} \sqrt {d x}\, \left (-\frac {128}{3315} b^{4} x^{8}+\frac {128}{195} a \,b^{3} x^{6}+\frac {2432}{1105} a^{2} b^{2} x^{4}+\frac {7552}{3315} a^{3} b \,x^{2}+a^{4}\right )\right )}{256 b^{5} \left (b \,x^{2}+a \right )^{3}}\) \(294\)

Input:

int((d*x)^(19/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x,method=_RETURNVERBOSE)
 

Output:

-2/5*(-b*x^2+20*a)*x/b^5/(d*x)^(1/2)*d^10+2*a^2/b^5*d^11*((-617/384*b^2*(d 
*x)^(9/2)-173/64*a*b*d^2*(d*x)^(5/2)-151/128*(d*x)^(1/2)*a^2*d^4)/(b*d^2*x 
^2+a*d^2)^3+663/1024*(a*d^2/b)^(1/4)/a/d^2*2^(1/2)*(ln((d*x+(a*d^2/b)^(1/4 
)*(d*x)^(1/2)*2^(1/2)+(a*d^2/b)^(1/2))/(d*x-(a*d^2/b)^(1/4)*(d*x)^(1/2)*2^ 
(1/2)+(a*d^2/b)^(1/2)))+2*arctan(2^(1/2)/(a*d^2/b)^(1/4)*(d*x)^(1/2)+1)+2* 
arctan(2^(1/2)/(a*d^2/b)^(1/4)*(d*x)^(1/2)-1)))
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.17 (sec) , antiderivative size = 433, normalized size of antiderivative = 1.49 \[ \int \frac {(d x)^{19/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=\frac {9945 \, \left (-\frac {a^{5} d^{38}}{b^{21}}\right )^{\frac {1}{4}} {\left (b^{8} x^{6} + 3 \, a b^{7} x^{4} + 3 \, a^{2} b^{6} x^{2} + a^{3} b^{5}\right )} \log \left (663 \, \sqrt {d x} a d^{9} + 663 \, \left (-\frac {a^{5} d^{38}}{b^{21}}\right )^{\frac {1}{4}} b^{5}\right ) - 9945 \, \left (-\frac {a^{5} d^{38}}{b^{21}}\right )^{\frac {1}{4}} {\left (-i \, b^{8} x^{6} - 3 i \, a b^{7} x^{4} - 3 i \, a^{2} b^{6} x^{2} - i \, a^{3} b^{5}\right )} \log \left (663 \, \sqrt {d x} a d^{9} + 663 i \, \left (-\frac {a^{5} d^{38}}{b^{21}}\right )^{\frac {1}{4}} b^{5}\right ) - 9945 \, \left (-\frac {a^{5} d^{38}}{b^{21}}\right )^{\frac {1}{4}} {\left (i \, b^{8} x^{6} + 3 i \, a b^{7} x^{4} + 3 i \, a^{2} b^{6} x^{2} + i \, a^{3} b^{5}\right )} \log \left (663 \, \sqrt {d x} a d^{9} - 663 i \, \left (-\frac {a^{5} d^{38}}{b^{21}}\right )^{\frac {1}{4}} b^{5}\right ) - 9945 \, \left (-\frac {a^{5} d^{38}}{b^{21}}\right )^{\frac {1}{4}} {\left (b^{8} x^{6} + 3 \, a b^{7} x^{4} + 3 \, a^{2} b^{6} x^{2} + a^{3} b^{5}\right )} \log \left (663 \, \sqrt {d x} a d^{9} - 663 \, \left (-\frac {a^{5} d^{38}}{b^{21}}\right )^{\frac {1}{4}} b^{5}\right ) + 4 \, {\left (384 \, b^{4} d^{9} x^{8} - 6528 \, a b^{3} d^{9} x^{6} - 24973 \, a^{2} b^{2} d^{9} x^{4} - 27846 \, a^{3} b d^{9} x^{2} - 9945 \, a^{4} d^{9}\right )} \sqrt {d x}}{3840 \, {\left (b^{8} x^{6} + 3 \, a b^{7} x^{4} + 3 \, a^{2} b^{6} x^{2} + a^{3} b^{5}\right )}} \] Input:

integrate((d*x)^(19/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x, algorithm="fricas")
 

Output:

1/3840*(9945*(-a^5*d^38/b^21)^(1/4)*(b^8*x^6 + 3*a*b^7*x^4 + 3*a^2*b^6*x^2 
 + a^3*b^5)*log(663*sqrt(d*x)*a*d^9 + 663*(-a^5*d^38/b^21)^(1/4)*b^5) - 99 
45*(-a^5*d^38/b^21)^(1/4)*(-I*b^8*x^6 - 3*I*a*b^7*x^4 - 3*I*a^2*b^6*x^2 - 
I*a^3*b^5)*log(663*sqrt(d*x)*a*d^9 + 663*I*(-a^5*d^38/b^21)^(1/4)*b^5) - 9 
945*(-a^5*d^38/b^21)^(1/4)*(I*b^8*x^6 + 3*I*a*b^7*x^4 + 3*I*a^2*b^6*x^2 + 
I*a^3*b^5)*log(663*sqrt(d*x)*a*d^9 - 663*I*(-a^5*d^38/b^21)^(1/4)*b^5) - 9 
945*(-a^5*d^38/b^21)^(1/4)*(b^8*x^6 + 3*a*b^7*x^4 + 3*a^2*b^6*x^2 + a^3*b^ 
5)*log(663*sqrt(d*x)*a*d^9 - 663*(-a^5*d^38/b^21)^(1/4)*b^5) + 4*(384*b^4* 
d^9*x^8 - 6528*a*b^3*d^9*x^6 - 24973*a^2*b^2*d^9*x^4 - 27846*a^3*b*d^9*x^2 
 - 9945*a^4*d^9)*sqrt(d*x))/(b^8*x^6 + 3*a*b^7*x^4 + 3*a^2*b^6*x^2 + a^3*b 
^5)
 

Sympy [F]

\[ \int \frac {(d x)^{19/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=\int \frac {\left (d x\right )^{\frac {19}{2}}}{\left (a + b x^{2}\right )^{4}}\, dx \] Input:

integrate((d*x)**(19/2)/(b**2*x**4+2*a*b*x**2+a**2)**2,x)
 

Output:

Integral((d*x)**(19/2)/(a + b*x**2)**4, x)
 

Maxima [A] (verification not implemented)

Time = 0.12 (sec) , antiderivative size = 361, normalized size of antiderivative = 1.24 \[ \int \frac {(d x)^{19/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=-\frac {\frac {40 \, {\left (617 \, \left (d x\right )^{\frac {9}{2}} a^{2} b^{2} d^{12} + 1038 \, \left (d x\right )^{\frac {5}{2}} a^{3} b d^{14} + 453 \, \sqrt {d x} a^{4} d^{16}\right )}}{b^{8} d^{6} x^{6} + 3 \, a b^{7} d^{6} x^{4} + 3 \, a^{2} b^{6} d^{6} x^{2} + a^{3} b^{5} d^{6}} - \frac {9945 \, {\left (\frac {\sqrt {2} d^{12} \log \left (\sqrt {b} d x + \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {3}{4}} b^{\frac {1}{4}}} - \frac {\sqrt {2} d^{12} \log \left (\sqrt {b} d x - \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {3}{4}} b^{\frac {1}{4}}} + \frac {2 \, \sqrt {2} d^{11} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} + 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {a}} + \frac {2 \, \sqrt {2} d^{11} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} - 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {a}}\right )} a^{2}}{b^{5}} - \frac {3072 \, {\left (\left (d x\right )^{\frac {5}{2}} b d^{8} - 20 \, \sqrt {d x} a d^{10}\right )}}{b^{5}}}{7680 \, d} \] Input:

integrate((d*x)^(19/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x, algorithm="maxima")
 

Output:

-1/7680*(40*(617*(d*x)^(9/2)*a^2*b^2*d^12 + 1038*(d*x)^(5/2)*a^3*b*d^14 + 
453*sqrt(d*x)*a^4*d^16)/(b^8*d^6*x^6 + 3*a*b^7*d^6*x^4 + 3*a^2*b^6*d^6*x^2 
 + a^3*b^5*d^6) - 9945*(sqrt(2)*d^12*log(sqrt(b)*d*x + sqrt(2)*(a*d^2)^(1/ 
4)*sqrt(d*x)*b^(1/4) + sqrt(a)*d)/((a*d^2)^(3/4)*b^(1/4)) - sqrt(2)*d^12*l 
og(sqrt(b)*d*x - sqrt(2)*(a*d^2)^(1/4)*sqrt(d*x)*b^(1/4) + sqrt(a)*d)/((a* 
d^2)^(3/4)*b^(1/4)) + 2*sqrt(2)*d^11*arctan(1/2*sqrt(2)*(sqrt(2)*(a*d^2)^( 
1/4)*b^(1/4) + 2*sqrt(d*x)*sqrt(b))/sqrt(sqrt(a)*sqrt(b)*d))/(sqrt(sqrt(a) 
*sqrt(b)*d)*sqrt(a)) + 2*sqrt(2)*d^11*arctan(-1/2*sqrt(2)*(sqrt(2)*(a*d^2) 
^(1/4)*b^(1/4) - 2*sqrt(d*x)*sqrt(b))/sqrt(sqrt(a)*sqrt(b)*d))/(sqrt(sqrt( 
a)*sqrt(b)*d)*sqrt(a)))*a^2/b^5 - 3072*((d*x)^(5/2)*b*d^8 - 20*sqrt(d*x)*a 
*d^10)/b^5)/d
 

Giac [A] (verification not implemented)

Time = 0.16 (sec) , antiderivative size = 345, normalized size of antiderivative = 1.19 \[ \int \frac {(d x)^{19/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=\frac {\frac {19890 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} a d^{10} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} + 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{b^{6}} + \frac {19890 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} a d^{10} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} - 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{b^{6}} + \frac {9945 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} a d^{10} \log \left (d x + \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{b^{6}} - \frac {9945 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} a d^{10} \log \left (d x - \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{b^{6}} - \frac {40 \, {\left (617 \, \sqrt {d x} a^{2} b^{2} d^{16} x^{4} + 1038 \, \sqrt {d x} a^{3} b d^{16} x^{2} + 453 \, \sqrt {d x} a^{4} d^{16}\right )}}{{\left (b d^{2} x^{2} + a d^{2}\right )}^{3} b^{5}} + \frac {3072 \, {\left (\sqrt {d x} b^{16} d^{10} x^{2} - 20 \, \sqrt {d x} a b^{15} d^{10}\right )}}{b^{20}}}{7680 \, d} \] Input:

integrate((d*x)^(19/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x, algorithm="giac")
 

Output:

1/7680*(19890*sqrt(2)*(a*b^3*d^2)^(1/4)*a*d^10*arctan(1/2*sqrt(2)*(sqrt(2) 
*(a*d^2/b)^(1/4) + 2*sqrt(d*x))/(a*d^2/b)^(1/4))/b^6 + 19890*sqrt(2)*(a*b^ 
3*d^2)^(1/4)*a*d^10*arctan(-1/2*sqrt(2)*(sqrt(2)*(a*d^2/b)^(1/4) - 2*sqrt( 
d*x))/(a*d^2/b)^(1/4))/b^6 + 9945*sqrt(2)*(a*b^3*d^2)^(1/4)*a*d^10*log(d*x 
 + sqrt(2)*(a*d^2/b)^(1/4)*sqrt(d*x) + sqrt(a*d^2/b))/b^6 - 9945*sqrt(2)*( 
a*b^3*d^2)^(1/4)*a*d^10*log(d*x - sqrt(2)*(a*d^2/b)^(1/4)*sqrt(d*x) + sqrt 
(a*d^2/b))/b^6 - 40*(617*sqrt(d*x)*a^2*b^2*d^16*x^4 + 1038*sqrt(d*x)*a^3*b 
*d^16*x^2 + 453*sqrt(d*x)*a^4*d^16)/((b*d^2*x^2 + a*d^2)^3*b^5) + 3072*(sq 
rt(d*x)*b^16*d^10*x^2 - 20*sqrt(d*x)*a*b^15*d^10)/b^20)/d
 

Mupad [B] (verification not implemented)

Time = 0.14 (sec) , antiderivative size = 188, normalized size of antiderivative = 0.65 \[ \int \frac {(d x)^{19/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=\frac {2\,d^7\,{\left (d\,x\right )}^{5/2}}{5\,b^4}-\frac {\frac {151\,a^4\,d^{15}\,\sqrt {d\,x}}{64}+\frac {617\,a^2\,b^2\,d^{11}\,{\left (d\,x\right )}^{9/2}}{192}+\frac {173\,a^3\,b\,d^{13}\,{\left (d\,x\right )}^{5/2}}{32}}{a^3\,b^5\,d^6+3\,a^2\,b^6\,d^6\,x^2+3\,a\,b^7\,d^6\,x^4+b^8\,d^6\,x^6}-\frac {663\,{\left (-a\right )}^{5/4}\,d^{19/2}\,\mathrm {atan}\left (\frac {b^{1/4}\,\sqrt {d\,x}}{{\left (-a\right )}^{1/4}\,\sqrt {d}}\right )}{128\,b^{21/4}}-\frac {8\,a\,d^9\,\sqrt {d\,x}}{b^5}+\frac {{\left (-a\right )}^{5/4}\,d^{19/2}\,\mathrm {atan}\left (\frac {b^{1/4}\,\sqrt {d\,x}\,1{}\mathrm {i}}{{\left (-a\right )}^{1/4}\,\sqrt {d}}\right )\,663{}\mathrm {i}}{128\,b^{21/4}} \] Input:

int((d*x)^(19/2)/(a^2 + b^2*x^4 + 2*a*b*x^2)^2,x)
 

Output:

(2*d^7*(d*x)^(5/2))/(5*b^4) - ((151*a^4*d^15*(d*x)^(1/2))/64 + (617*a^2*b^ 
2*d^11*(d*x)^(9/2))/192 + (173*a^3*b*d^13*(d*x)^(5/2))/32)/(a^3*b^5*d^6 + 
b^8*d^6*x^6 + 3*a*b^7*d^6*x^4 + 3*a^2*b^6*d^6*x^2) - (663*(-a)^(5/4)*d^(19 
/2)*atan((b^(1/4)*(d*x)^(1/2))/((-a)^(1/4)*d^(1/2))))/(128*b^(21/4)) + ((- 
a)^(5/4)*d^(19/2)*atan((b^(1/4)*(d*x)^(1/2)*1i)/((-a)^(1/4)*d^(1/2)))*663i 
)/(128*b^(21/4)) - (8*a*d^9*(d*x)^(1/2))/b^5
 

Reduce [B] (verification not implemented)

Time = 0.18 (sec) , antiderivative size = 673, normalized size of antiderivative = 2.31 \[ \int \frac {(d x)^{19/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx =\text {Too large to display} \] Input:

int((d*x)^(19/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x)
 

Output:

(sqrt(d)*d**9*( - 19890*b**(3/4)*a**(1/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)* 
sqrt(2) - 2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4)*sqrt(2)))*a**4 - 59670*b** 
(3/4)*a**(1/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)*sqrt(2) - 2*sqrt(x)*sqrt(b) 
)/(b**(1/4)*a**(1/4)*sqrt(2)))*a**3*b*x**2 - 59670*b**(3/4)*a**(1/4)*sqrt( 
2)*atan((b**(1/4)*a**(1/4)*sqrt(2) - 2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4) 
*sqrt(2)))*a**2*b**2*x**4 - 19890*b**(3/4)*a**(1/4)*sqrt(2)*atan((b**(1/4) 
*a**(1/4)*sqrt(2) - 2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4)*sqrt(2)))*a*b**3 
*x**6 + 19890*b**(3/4)*a**(1/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)*sqrt(2) + 
2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4)*sqrt(2)))*a**4 + 59670*b**(3/4)*a**( 
1/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)*sqrt(2) + 2*sqrt(x)*sqrt(b))/(b**(1/4 
)*a**(1/4)*sqrt(2)))*a**3*b*x**2 + 59670*b**(3/4)*a**(1/4)*sqrt(2)*atan((b 
**(1/4)*a**(1/4)*sqrt(2) + 2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4)*sqrt(2))) 
*a**2*b**2*x**4 + 19890*b**(3/4)*a**(1/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)* 
sqrt(2) + 2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4)*sqrt(2)))*a*b**3*x**6 - 99 
45*b**(3/4)*a**(1/4)*sqrt(2)*log( - sqrt(x)*b**(1/4)*a**(1/4)*sqrt(2) + sq 
rt(a) + sqrt(b)*x)*a**4 - 29835*b**(3/4)*a**(1/4)*sqrt(2)*log( - sqrt(x)*b 
**(1/4)*a**(1/4)*sqrt(2) + sqrt(a) + sqrt(b)*x)*a**3*b*x**2 - 29835*b**(3/ 
4)*a**(1/4)*sqrt(2)*log( - sqrt(x)*b**(1/4)*a**(1/4)*sqrt(2) + sqrt(a) + s 
qrt(b)*x)*a**2*b**2*x**4 - 9945*b**(3/4)*a**(1/4)*sqrt(2)*log( - sqrt(x)*b 
**(1/4)*a**(1/4)*sqrt(2) + sqrt(a) + sqrt(b)*x)*a*b**3*x**6 + 9945*b**(...