Integrand size = 28, antiderivative size = 275 \[ \int \frac {1}{(d x)^{3/2} \left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=-\frac {195}{64 a^4 d \sqrt {d x}}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}+\frac {13}{48 a^2 d \sqrt {d x} \left (a+b x^2\right )^2}+\frac {39}{64 a^3 d \sqrt {d x} \left (a+b x^2\right )}+\frac {195 \sqrt [4]{b} \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{17/4} d^{3/2}}-\frac {195 \sqrt [4]{b} \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{17/4} d^{3/2}}+\frac {195 \sqrt [4]{b} \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}}{\sqrt {d} \left (\sqrt {a}+\sqrt {b} x\right )}\right )}{128 \sqrt {2} a^{17/4} d^{3/2}} \] Output:
-195/64/a^4/d/(d*x)^(1/2)+1/6/a/d/(d*x)^(1/2)/(b*x^2+a)^3+13/48/a^2/d/(d*x )^(1/2)/(b*x^2+a)^2+39/64/a^3/d/(d*x)^(1/2)/(b*x^2+a)+195/256*b^(1/4)*arct an(1-2^(1/2)*b^(1/4)*(d*x)^(1/2)/a^(1/4)/d^(1/2))*2^(1/2)/a^(17/4)/d^(3/2) -195/256*b^(1/4)*arctan(1+2^(1/2)*b^(1/4)*(d*x)^(1/2)/a^(1/4)/d^(1/2))*2^( 1/2)/a^(17/4)/d^(3/2)+195/256*b^(1/4)*arctanh(2^(1/2)*a^(1/4)*b^(1/4)*(d*x )^(1/2)/d^(1/2)/(a^(1/2)+b^(1/2)*x))*2^(1/2)/a^(17/4)/d^(3/2)
Time = 0.52 (sec) , antiderivative size = 173, normalized size of antiderivative = 0.63 \[ \int \frac {1}{(d x)^{3/2} \left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=\frac {x \left (-\frac {4 \sqrt [4]{a} \left (384 a^3+1469 a^2 b x^2+1638 a b^2 x^4+585 b^3 x^6\right )}{\left (a+b x^2\right )^3}+585 \sqrt {2} \sqrt [4]{b} \sqrt {x} \arctan \left (\frac {\sqrt {a}-\sqrt {b} x}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}\right )+585 \sqrt {2} \sqrt [4]{b} \sqrt {x} \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}{\sqrt {a}+\sqrt {b} x}\right )\right )}{768 a^{17/4} (d x)^{3/2}} \] Input:
Integrate[1/((d*x)^(3/2)*(a^2 + 2*a*b*x^2 + b^2*x^4)^2),x]
Output:
(x*((-4*a^(1/4)*(384*a^3 + 1469*a^2*b*x^2 + 1638*a*b^2*x^4 + 585*b^3*x^6)) /(a + b*x^2)^3 + 585*Sqrt[2]*b^(1/4)*Sqrt[x]*ArcTan[(Sqrt[a] - Sqrt[b]*x)/ (Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[x])] + 585*Sqrt[2]*b^(1/4)*Sqrt[x]*ArcTanh[( Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[x])/(Sqrt[a] + Sqrt[b]*x)]))/(768*a^(17/4)*(d *x)^(3/2))
Time = 1.00 (sec) , antiderivative size = 393, normalized size of antiderivative = 1.43, number of steps used = 17, number of rules used = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.571, Rules used = {1380, 27, 253, 253, 253, 264, 266, 27, 826, 1476, 1082, 217, 1479, 25, 27, 1103}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{(d x)^{3/2} \left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx\) |
\(\Big \downarrow \) 1380 |
\(\displaystyle b^4 \int \frac {1}{b^4 (d x)^{3/2} \left (b x^2+a\right )^4}dx\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \int \frac {1}{(d x)^{3/2} \left (a+b x^2\right )^4}dx\) |
\(\Big \downarrow \) 253 |
\(\displaystyle \frac {13 \int \frac {1}{(d x)^{3/2} \left (b x^2+a\right )^3}dx}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 253 |
\(\displaystyle \frac {13 \left (\frac {9 \int \frac {1}{(d x)^{3/2} \left (b x^2+a\right )^2}dx}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 253 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \int \frac {1}{(d x)^{3/2} \left (b x^2+a\right )}dx}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 264 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {b \int \frac {\sqrt {d x}}{b x^2+a}dx}{a d^2}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 266 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \int \frac {d^3 x}{b x^2 d^2+a d^2}d\sqrt {d x}}{a d^3}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \int \frac {d x}{b x^2 d^2+a d^2}d\sqrt {d x}}{a d}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 826 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \left (\frac {\int \frac {\sqrt {b} x d+\sqrt {a} d}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {b}}-\frac {\int \frac {\sqrt {a} d-\sqrt {b} d x}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {b}}\right )}{a d}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 1476 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \left (\frac {\frac {\int \frac {1}{x d+\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}}d\sqrt {d x}}{2 \sqrt {b}}+\frac {\int \frac {1}{x d+\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}}d\sqrt {d x}}{2 \sqrt {b}}}{2 \sqrt {b}}-\frac {\int \frac {\sqrt {a} d-\sqrt {b} d x}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {b}}\right )}{a d}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 1082 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \left (\frac {\frac {\int \frac {1}{-d x-1}d\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\int \frac {1}{-d x-1}d\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}}{2 \sqrt {b}}-\frac {\int \frac {\sqrt {a} d-\sqrt {b} d x}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {b}}\right )}{a d}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}}{2 \sqrt {b}}-\frac {\int \frac {\sqrt {a} d-\sqrt {b} d x}{b x^2 d^2+a d^2}d\sqrt {d x}}{2 \sqrt {b}}\right )}{a d}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 1479 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}}{2 \sqrt {b}}-\frac {-\frac {\int -\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}-2 \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{b} \left (x d+\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt [4]{a} \sqrt {d}+\sqrt {2} \sqrt [4]{b} \sqrt {d x}\right )}{\sqrt [4]{b} \left (x d+\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}}{2 \sqrt {b}}\right )}{a d}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}}{2 \sqrt {b}}-\frac {\frac {\int \frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}-2 \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{b} \left (x d+\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}+\frac {\int \frac {\sqrt {2} \left (\sqrt [4]{a} \sqrt {d}+\sqrt {2} \sqrt [4]{b} \sqrt {d x}\right )}{\sqrt [4]{b} \left (x d+\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}}{2 \sqrt {b}}\right )}{a d}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}}{2 \sqrt {b}}-\frac {\frac {\int \frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}-2 \sqrt [4]{b} \sqrt {d x}}{x d+\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{a} \sqrt {b} \sqrt {d}}+\frac {\int \frac {\sqrt [4]{a} \sqrt {d}+\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{x d+\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d x} \sqrt {d}}{\sqrt [4]{b}}}d\sqrt {d x}}{2 \sqrt [4]{a} \sqrt {b} \sqrt {d}}}{2 \sqrt {b}}\right )}{a d}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
\(\Big \downarrow \) 1103 |
\(\displaystyle \frac {13 \left (\frac {9 \left (\frac {5 \left (-\frac {2 b \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}}{2 \sqrt {b}}-\frac {\frac {\log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d} \sqrt {d x}+\sqrt {a} d+\sqrt {b} d x\right )}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}-\frac {\log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d} \sqrt {d x}+\sqrt {a} d+\sqrt {b} d x\right )}{2 \sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d}}}{2 \sqrt {b}}\right )}{a d}-\frac {2}{a d \sqrt {d x}}\right )}{4 a}+\frac {1}{2 a d \sqrt {d x} \left (a+b x^2\right )}\right )}{8 a}+\frac {1}{4 a d \sqrt {d x} \left (a+b x^2\right )^2}\right )}{12 a}+\frac {1}{6 a d \sqrt {d x} \left (a+b x^2\right )^3}\) |
Input:
Int[1/((d*x)^(3/2)*(a^2 + 2*a*b*x^2 + b^2*x^4)^2),x]
Output:
1/(6*a*d*Sqrt[d*x]*(a + b*x^2)^3) + (13*(1/(4*a*d*Sqrt[d*x]*(a + b*x^2)^2) + (9*(1/(2*a*d*Sqrt[d*x]*(a + b*x^2)) + (5*(-2/(a*d*Sqrt[d*x]) - (2*b*((- (ArcTan[1 - (Sqrt[2]*b^(1/4)*Sqrt[d*x])/(a^(1/4)*Sqrt[d])]/(Sqrt[2]*a^(1/4 )*b^(1/4)*Sqrt[d])) + ArcTan[1 + (Sqrt[2]*b^(1/4)*Sqrt[d*x])/(a^(1/4)*Sqrt [d])]/(Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[d]))/(2*Sqrt[b]) - (-1/2*Log[Sqrt[a]*d + Sqrt[b]*d*x - Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[d]*Sqrt[d*x]]/(Sqrt[2]*a^(1/ 4)*b^(1/4)*Sqrt[d]) + Log[Sqrt[a]*d + Sqrt[b]*d*x + Sqrt[2]*a^(1/4)*b^(1/4 )*Sqrt[d]*Sqrt[d*x]]/(2*Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[d]))/(2*Sqrt[b])))/(a *d)))/(4*a)))/(8*a)))/(12*a)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(-(c*x )^(m + 1))*((a + b*x^2)^(p + 1)/(2*a*c*(p + 1))), x] + Simp[(m + 2*p + 3)/( 2*a*(p + 1)) Int[(c*x)^m*(a + b*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, m }, x] && LtQ[p, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(c*x)^( m + 1)*((a + b*x^2)^(p + 1)/(a*c*(m + 1))), x] - Simp[b*((m + 2*p + 3)/(a*c ^2*(m + 1))) Int[(c*x)^(m + 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, p }, x] && LtQ[m, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s) Int[(r + s*x^2)/(a + b*x^ 4), x], x] - Simp[1/(2*s) Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ, b]]))
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S implify[a*(c/b^2)]}, Simp[-2/b Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b )], x] /; RationalQ[q] && (EqQ[q^2, 1] || !RationalQ[b^2 - 4*a*c])] /; Fre eQ[{a, b, c}, x]
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]
Int[(u_)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> S imp[1/c^p Int[u*(b/2 + c*x^n)^(2*p), x], x] /; FreeQ[{a, b, c, n, p}, x] && EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 2*(d/e), 2]}, Simp[e/(2*c) Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ e/(2*c) Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ -2*(d/e), 2]}, Simp[e/(2*c*q) Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Simp[e/(2*c*q) Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
Time = 0.60 (sec) , antiderivative size = 217, normalized size of antiderivative = 0.79
method | result | size |
risch | \(-\frac {2}{a^{4} d \sqrt {d x}}-\frac {b \left (\frac {\frac {67 b^{2} \left (d x \right )^{\frac {11}{2}}}{64}+\frac {81 a b \,d^{2} \left (d x \right )^{\frac {7}{2}}}{32}+\frac {317 a^{2} d^{4} \left (d x \right )^{\frac {3}{2}}}{192}}{\left (b \,d^{2} x^{2}+a \,d^{2}\right )^{3}}+\frac {195 \sqrt {2}\, \left (\ln \left (\frac {d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{512 b \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{4} d}\) | \(217\) |
derivativedivides | \(2 d^{7} \left (-\frac {1}{a^{4} d^{8} \sqrt {d x}}-\frac {b \left (\frac {\frac {67 b^{2} \left (d x \right )^{\frac {11}{2}}}{128}+\frac {81 a b \,d^{2} \left (d x \right )^{\frac {7}{2}}}{64}+\frac {317 a^{2} d^{4} \left (d x \right )^{\frac {3}{2}}}{384}}{\left (b \,d^{2} x^{2}+a \,d^{2}\right )^{3}}+\frac {195 \sqrt {2}\, \left (\ln \left (\frac {d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{1024 b \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{4} d^{8}}\right )\) | \(221\) |
default | \(2 d^{7} \left (-\frac {1}{a^{4} d^{8} \sqrt {d x}}-\frac {b \left (\frac {\frac {67 b^{2} \left (d x \right )^{\frac {11}{2}}}{128}+\frac {81 a b \,d^{2} \left (d x \right )^{\frac {7}{2}}}{64}+\frac {317 a^{2} d^{4} \left (d x \right )^{\frac {3}{2}}}{384}}{\left (b \,d^{2} x^{2}+a \,d^{2}\right )^{3}}+\frac {195 \sqrt {2}\, \left (\ln \left (\frac {d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{1024 b \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{4} d^{8}}\right )\) | \(221\) |
pseudoelliptic | \(-\frac {2 \left (\frac {195 \sqrt {2}\, \left (b \,x^{2}+a \right )^{3} \left (\ln \left (\frac {d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}-\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}+\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}\right )\right ) \sqrt {d x}}{1024}+\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \left (\frac {195}{128} b^{3} x^{6}+\frac {273}{64} b^{2} x^{4} a +\frac {1469}{384} a^{2} b \,x^{2}+a^{3}\right )\right )}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, d \,a^{4} \left (b \,x^{2}+a \right )^{3}}\) | \(236\) |
Input:
int(1/(d*x)^(3/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x,method=_RETURNVERBOSE)
Output:
-2/a^4/d/(d*x)^(1/2)-b/a^4*(2*(67/128*b^2*(d*x)^(11/2)+81/64*a*b*d^2*(d*x) ^(7/2)+317/384*a^2*d^4*(d*x)^(3/2))/(b*d^2*x^2+a*d^2)^3+195/512/b/(a*d^2/b )^(1/4)*2^(1/2)*(ln((d*x-(a*d^2/b)^(1/4)*(d*x)^(1/2)*2^(1/2)+(a*d^2/b)^(1/ 2))/(d*x+(a*d^2/b)^(1/4)*(d*x)^(1/2)*2^(1/2)+(a*d^2/b)^(1/2)))+2*arctan(2^ (1/2)/(a*d^2/b)^(1/4)*(d*x)^(1/2)+1)+2*arctan(2^(1/2)/(a*d^2/b)^(1/4)*(d*x )^(1/2)-1)))/d
Result contains complex when optimal does not.
Time = 0.16 (sec) , antiderivative size = 456, normalized size of antiderivative = 1.66 \[ \int \frac {1}{(d x)^{3/2} \left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=-\frac {585 \, {\left (a^{4} b^{3} d^{2} x^{7} + 3 \, a^{5} b^{2} d^{2} x^{5} + 3 \, a^{6} b d^{2} x^{3} + a^{7} d^{2} x\right )} \left (-\frac {b}{a^{17} d^{6}}\right )^{\frac {1}{4}} \log \left (7414875 \, a^{13} d^{5} \left (-\frac {b}{a^{17} d^{6}}\right )^{\frac {3}{4}} + 7414875 \, \sqrt {d x} b\right ) + 585 \, {\left (-i \, a^{4} b^{3} d^{2} x^{7} - 3 i \, a^{5} b^{2} d^{2} x^{5} - 3 i \, a^{6} b d^{2} x^{3} - i \, a^{7} d^{2} x\right )} \left (-\frac {b}{a^{17} d^{6}}\right )^{\frac {1}{4}} \log \left (7414875 i \, a^{13} d^{5} \left (-\frac {b}{a^{17} d^{6}}\right )^{\frac {3}{4}} + 7414875 \, \sqrt {d x} b\right ) + 585 \, {\left (i \, a^{4} b^{3} d^{2} x^{7} + 3 i \, a^{5} b^{2} d^{2} x^{5} + 3 i \, a^{6} b d^{2} x^{3} + i \, a^{7} d^{2} x\right )} \left (-\frac {b}{a^{17} d^{6}}\right )^{\frac {1}{4}} \log \left (-7414875 i \, a^{13} d^{5} \left (-\frac {b}{a^{17} d^{6}}\right )^{\frac {3}{4}} + 7414875 \, \sqrt {d x} b\right ) - 585 \, {\left (a^{4} b^{3} d^{2} x^{7} + 3 \, a^{5} b^{2} d^{2} x^{5} + 3 \, a^{6} b d^{2} x^{3} + a^{7} d^{2} x\right )} \left (-\frac {b}{a^{17} d^{6}}\right )^{\frac {1}{4}} \log \left (-7414875 \, a^{13} d^{5} \left (-\frac {b}{a^{17} d^{6}}\right )^{\frac {3}{4}} + 7414875 \, \sqrt {d x} b\right ) + 4 \, {\left (585 \, b^{3} x^{6} + 1638 \, a b^{2} x^{4} + 1469 \, a^{2} b x^{2} + 384 \, a^{3}\right )} \sqrt {d x}}{768 \, {\left (a^{4} b^{3} d^{2} x^{7} + 3 \, a^{5} b^{2} d^{2} x^{5} + 3 \, a^{6} b d^{2} x^{3} + a^{7} d^{2} x\right )}} \] Input:
integrate(1/(d*x)^(3/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x, algorithm="fricas")
Output:
-1/768*(585*(a^4*b^3*d^2*x^7 + 3*a^5*b^2*d^2*x^5 + 3*a^6*b*d^2*x^3 + a^7*d ^2*x)*(-b/(a^17*d^6))^(1/4)*log(7414875*a^13*d^5*(-b/(a^17*d^6))^(3/4) + 7 414875*sqrt(d*x)*b) + 585*(-I*a^4*b^3*d^2*x^7 - 3*I*a^5*b^2*d^2*x^5 - 3*I* a^6*b*d^2*x^3 - I*a^7*d^2*x)*(-b/(a^17*d^6))^(1/4)*log(7414875*I*a^13*d^5* (-b/(a^17*d^6))^(3/4) + 7414875*sqrt(d*x)*b) + 585*(I*a^4*b^3*d^2*x^7 + 3* I*a^5*b^2*d^2*x^5 + 3*I*a^6*b*d^2*x^3 + I*a^7*d^2*x)*(-b/(a^17*d^6))^(1/4) *log(-7414875*I*a^13*d^5*(-b/(a^17*d^6))^(3/4) + 7414875*sqrt(d*x)*b) - 58 5*(a^4*b^3*d^2*x^7 + 3*a^5*b^2*d^2*x^5 + 3*a^6*b*d^2*x^3 + a^7*d^2*x)*(-b/ (a^17*d^6))^(1/4)*log(-7414875*a^13*d^5*(-b/(a^17*d^6))^(3/4) + 7414875*sq rt(d*x)*b) + 4*(585*b^3*x^6 + 1638*a*b^2*x^4 + 1469*a^2*b*x^2 + 384*a^3)*s qrt(d*x))/(a^4*b^3*d^2*x^7 + 3*a^5*b^2*d^2*x^5 + 3*a^6*b*d^2*x^3 + a^7*d^2 *x)
\[ \int \frac {1}{(d x)^{3/2} \left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=\int \frac {1}{\left (d x\right )^{\frac {3}{2}} \left (a + b x^{2}\right )^{4}}\, dx \] Input:
integrate(1/(d*x)**(3/2)/(b**2*x**4+2*a*b*x**2+a**2)**2,x)
Output:
Integral(1/((d*x)**(3/2)*(a + b*x**2)**4), x)
Time = 0.12 (sec) , antiderivative size = 328, normalized size of antiderivative = 1.19 \[ \int \frac {1}{(d x)^{3/2} \left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=-\frac {\frac {8 \, {\left (585 \, b^{3} d^{6} x^{6} + 1638 \, a b^{2} d^{6} x^{4} + 1469 \, a^{2} b d^{6} x^{2} + 384 \, a^{3} d^{6}\right )}}{\left (d x\right )^{\frac {13}{2}} a^{4} b^{3} + 3 \, \left (d x\right )^{\frac {9}{2}} a^{5} b^{2} d^{2} + 3 \, \left (d x\right )^{\frac {5}{2}} a^{6} b d^{4} + \sqrt {d x} a^{7} d^{6}} + \frac {585 \, b {\left (\frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} + 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {b}} + \frac {2 \, \sqrt {2} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} - 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {b}} - \frac {\sqrt {2} \log \left (\sqrt {b} d x + \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {3}{4}}} + \frac {\sqrt {2} \log \left (\sqrt {b} d x - \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {3}{4}}}\right )}}{a^{4}}}{1536 \, d} \] Input:
integrate(1/(d*x)^(3/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x, algorithm="maxima")
Output:
-1/1536*(8*(585*b^3*d^6*x^6 + 1638*a*b^2*d^6*x^4 + 1469*a^2*b*d^6*x^2 + 38 4*a^3*d^6)/((d*x)^(13/2)*a^4*b^3 + 3*(d*x)^(9/2)*a^5*b^2*d^2 + 3*(d*x)^(5/ 2)*a^6*b*d^4 + sqrt(d*x)*a^7*d^6) + 585*b*(2*sqrt(2)*arctan(1/2*sqrt(2)*(s qrt(2)*(a*d^2)^(1/4)*b^(1/4) + 2*sqrt(d*x)*sqrt(b))/sqrt(sqrt(a)*sqrt(b)*d ))/(sqrt(sqrt(a)*sqrt(b)*d)*sqrt(b)) + 2*sqrt(2)*arctan(-1/2*sqrt(2)*(sqrt (2)*(a*d^2)^(1/4)*b^(1/4) - 2*sqrt(d*x)*sqrt(b))/sqrt(sqrt(a)*sqrt(b)*d))/ (sqrt(sqrt(a)*sqrt(b)*d)*sqrt(b)) - sqrt(2)*log(sqrt(b)*d*x + sqrt(2)*(a*d ^2)^(1/4)*sqrt(d*x)*b^(1/4) + sqrt(a)*d)/((a*d^2)^(1/4)*b^(3/4)) + sqrt(2) *log(sqrt(b)*d*x - sqrt(2)*(a*d^2)^(1/4)*sqrt(d*x)*b^(1/4) + sqrt(a)*d)/(( a*d^2)^(1/4)*b^(3/4)))/a^4)/d
Time = 0.15 (sec) , antiderivative size = 327, normalized size of antiderivative = 1.19 \[ \int \frac {1}{(d x)^{3/2} \left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=-\frac {\frac {3072}{\sqrt {d x} a^{4}} + \frac {8 \, {\left (201 \, \sqrt {d x} b^{3} d^{5} x^{5} + 486 \, \sqrt {d x} a b^{2} d^{5} x^{3} + 317 \, \sqrt {d x} a^{2} b d^{5} x\right )}}{{\left (b d^{2} x^{2} + a d^{2}\right )}^{3} a^{4}} + \frac {1170 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {3}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} + 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{5} b^{2} d^{2}} + \frac {1170 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {3}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} - 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{5} b^{2} d^{2}} - \frac {585 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {3}{4}} \log \left (d x + \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{a^{5} b^{2} d^{2}} + \frac {585 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {3}{4}} \log \left (d x - \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{a^{5} b^{2} d^{2}}}{1536 \, d} \] Input:
integrate(1/(d*x)^(3/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x, algorithm="giac")
Output:
-1/1536*(3072/(sqrt(d*x)*a^4) + 8*(201*sqrt(d*x)*b^3*d^5*x^5 + 486*sqrt(d* x)*a*b^2*d^5*x^3 + 317*sqrt(d*x)*a^2*b*d^5*x)/((b*d^2*x^2 + a*d^2)^3*a^4) + 1170*sqrt(2)*(a*b^3*d^2)^(3/4)*arctan(1/2*sqrt(2)*(sqrt(2)*(a*d^2/b)^(1/ 4) + 2*sqrt(d*x))/(a*d^2/b)^(1/4))/(a^5*b^2*d^2) + 1170*sqrt(2)*(a*b^3*d^2 )^(3/4)*arctan(-1/2*sqrt(2)*(sqrt(2)*(a*d^2/b)^(1/4) - 2*sqrt(d*x))/(a*d^2 /b)^(1/4))/(a^5*b^2*d^2) - 585*sqrt(2)*(a*b^3*d^2)^(3/4)*log(d*x + sqrt(2) *(a*d^2/b)^(1/4)*sqrt(d*x) + sqrt(a*d^2/b))/(a^5*b^2*d^2) + 585*sqrt(2)*(a *b^3*d^2)^(3/4)*log(d*x - sqrt(2)*(a*d^2/b)^(1/4)*sqrt(d*x) + sqrt(a*d^2/b ))/(a^5*b^2*d^2))/d
Time = 0.14 (sec) , antiderivative size = 166, normalized size of antiderivative = 0.60 \[ \int \frac {1}{(d x)^{3/2} \left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx=\frac {195\,{\left (-b\right )}^{1/4}\,\mathrm {atanh}\left (\frac {{\left (-b\right )}^{1/4}\,\sqrt {d\,x}}{a^{1/4}\,\sqrt {d}}\right )}{128\,a^{17/4}\,d^{3/2}}-\frac {195\,{\left (-b\right )}^{1/4}\,\mathrm {atan}\left (\frac {{\left (-b\right )}^{1/4}\,\sqrt {d\,x}}{a^{1/4}\,\sqrt {d}}\right )}{128\,a^{17/4}\,d^{3/2}}-\frac {\frac {2\,d^5}{a}+\frac {1469\,b\,d^5\,x^2}{192\,a^2}+\frac {273\,b^2\,d^5\,x^4}{32\,a^3}+\frac {195\,b^3\,d^5\,x^6}{64\,a^4}}{b^3\,{\left (d\,x\right )}^{13/2}+a^3\,d^6\,\sqrt {d\,x}+3\,a^2\,b\,d^4\,{\left (d\,x\right )}^{5/2}+3\,a\,b^2\,d^2\,{\left (d\,x\right )}^{9/2}} \] Input:
int(1/((d*x)^(3/2)*(a^2 + b^2*x^4 + 2*a*b*x^2)^2),x)
Output:
(195*(-b)^(1/4)*atanh(((-b)^(1/4)*(d*x)^(1/2))/(a^(1/4)*d^(1/2))))/(128*a^ (17/4)*d^(3/2)) - (195*(-b)^(1/4)*atan(((-b)^(1/4)*(d*x)^(1/2))/(a^(1/4)*d ^(1/2))))/(128*a^(17/4)*d^(3/2)) - ((2*d^5)/a + (1469*b*d^5*x^2)/(192*a^2) + (273*b^2*d^5*x^4)/(32*a^3) + (195*b^3*d^5*x^6)/(64*a^4))/(b^3*(d*x)^(13 /2) + a^3*d^6*(d*x)^(1/2) + 3*a^2*b*d^4*(d*x)^(5/2) + 3*a*b^2*d^2*(d*x)^(9 /2))
Time = 0.18 (sec) , antiderivative size = 688, normalized size of antiderivative = 2.50 \[ \int \frac {1}{(d x)^{3/2} \left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx =\text {Too large to display} \] Input:
int(1/(d*x)^(3/2)/(b^2*x^4+2*a*b*x^2+a^2)^2,x)
Output:
(sqrt(d)*(1170*sqrt(x)*b**(1/4)*a**(3/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)*s qrt(2) - 2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4)*sqrt(2)))*a**3 + 3510*sqrt( x)*b**(1/4)*a**(3/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)*sqrt(2) - 2*sqrt(x)*s qrt(b))/(b**(1/4)*a**(1/4)*sqrt(2)))*a**2*b*x**2 + 3510*sqrt(x)*b**(1/4)*a **(3/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)*sqrt(2) - 2*sqrt(x)*sqrt(b))/(b**( 1/4)*a**(1/4)*sqrt(2)))*a*b**2*x**4 + 1170*sqrt(x)*b**(1/4)*a**(3/4)*sqrt( 2)*atan((b**(1/4)*a**(1/4)*sqrt(2) - 2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4) *sqrt(2)))*b**3*x**6 - 1170*sqrt(x)*b**(1/4)*a**(3/4)*sqrt(2)*atan((b**(1/ 4)*a**(1/4)*sqrt(2) + 2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4)*sqrt(2)))*a**3 - 3510*sqrt(x)*b**(1/4)*a**(3/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)*sqrt(2) + 2*sqrt(x)*sqrt(b))/(b**(1/4)*a**(1/4)*sqrt(2)))*a**2*b*x**2 - 3510*sqrt( x)*b**(1/4)*a**(3/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)*sqrt(2) + 2*sqrt(x)*s qrt(b))/(b**(1/4)*a**(1/4)*sqrt(2)))*a*b**2*x**4 - 1170*sqrt(x)*b**(1/4)*a **(3/4)*sqrt(2)*atan((b**(1/4)*a**(1/4)*sqrt(2) + 2*sqrt(x)*sqrt(b))/(b**( 1/4)*a**(1/4)*sqrt(2)))*b**3*x**6 - 585*sqrt(x)*b**(1/4)*a**(3/4)*sqrt(2)* log( - sqrt(x)*b**(1/4)*a**(1/4)*sqrt(2) + sqrt(a) + sqrt(b)*x)*a**3 - 175 5*sqrt(x)*b**(1/4)*a**(3/4)*sqrt(2)*log( - sqrt(x)*b**(1/4)*a**(1/4)*sqrt( 2) + sqrt(a) + sqrt(b)*x)*a**2*b*x**2 - 1755*sqrt(x)*b**(1/4)*a**(3/4)*sqr t(2)*log( - sqrt(x)*b**(1/4)*a**(1/4)*sqrt(2) + sqrt(a) + sqrt(b)*x)*a*b** 2*x**4 - 585*sqrt(x)*b**(1/4)*a**(3/4)*sqrt(2)*log( - sqrt(x)*b**(1/4)*...