Integrand size = 26, antiderivative size = 255 \[ \int x^{12} \left (a^2+2 a b x^2+b^2 x^4\right )^{5/2} \, dx=\frac {a^5 x^{13} \sqrt {a^2+2 a b x^2+b^2 x^4}}{13 \left (a+b x^2\right )}+\frac {a^4 b x^{15} \sqrt {a^2+2 a b x^2+b^2 x^4}}{3 \left (a+b x^2\right )}+\frac {10 a^3 b^2 x^{17} \sqrt {a^2+2 a b x^2+b^2 x^4}}{17 \left (a+b x^2\right )}+\frac {10 a^2 b^3 x^{19} \sqrt {a^2+2 a b x^2+b^2 x^4}}{19 \left (a+b x^2\right )}+\frac {5 a b^4 x^{21} \sqrt {a^2+2 a b x^2+b^2 x^4}}{21 \left (a+b x^2\right )}+\frac {b^5 x^{23} \sqrt {a^2+2 a b x^2+b^2 x^4}}{23 \left (a+b x^2\right )} \] Output:
a^5*x^13*((b*x^2+a)^2)^(1/2)/(13*b*x^2+13*a)+a^4*b*x^15*((b*x^2+a)^2)^(1/2 )/(3*b*x^2+3*a)+10*a^3*b^2*x^17*((b*x^2+a)^2)^(1/2)/(17*b*x^2+17*a)+10*a^2 *b^3*x^19*((b*x^2+a)^2)^(1/2)/(19*b*x^2+19*a)+5*a*b^4*x^21*((b*x^2+a)^2)^( 1/2)/(21*b*x^2+21*a)+b^5*x^23*((b*x^2+a)^2)^(1/2)/(23*b*x^2+23*a)
Time = 1.02 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.33 \[ \int x^{12} \left (a^2+2 a b x^2+b^2 x^4\right )^{5/2} \, dx=\frac {x^{13} \sqrt {\left (a+b x^2\right )^2} \left (156009 a^5+676039 a^4 b x^2+1193010 a^3 b^2 x^4+1067430 a^2 b^3 x^6+482885 a b^4 x^8+88179 b^5 x^{10}\right )}{2028117 \left (a+b x^2\right )} \] Input:
Integrate[x^12*(a^2 + 2*a*b*x^2 + b^2*x^4)^(5/2),x]
Output:
(x^13*Sqrt[(a + b*x^2)^2]*(156009*a^5 + 676039*a^4*b*x^2 + 1193010*a^3*b^2 *x^4 + 1067430*a^2*b^3*x^6 + 482885*a*b^4*x^8 + 88179*b^5*x^10))/(2028117* (a + b*x^2))
Time = 0.41 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.40, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {1384, 27, 244, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^{12} \left (a^2+2 a b x^2+b^2 x^4\right )^{5/2} \, dx\) |
\(\Big \downarrow \) 1384 |
\(\displaystyle \frac {\sqrt {a^2+2 a b x^2+b^2 x^4} \int b^5 x^{12} \left (b x^2+a\right )^5dx}{b^5 \left (a+b x^2\right )}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\sqrt {a^2+2 a b x^2+b^2 x^4} \int x^{12} \left (b x^2+a\right )^5dx}{a+b x^2}\) |
\(\Big \downarrow \) 244 |
\(\displaystyle \frac {\sqrt {a^2+2 a b x^2+b^2 x^4} \int \left (b^5 x^{22}+5 a b^4 x^{20}+10 a^2 b^3 x^{18}+10 a^3 b^2 x^{16}+5 a^4 b x^{14}+a^5 x^{12}\right )dx}{a+b x^2}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {\sqrt {a^2+2 a b x^2+b^2 x^4} \left (\frac {a^5 x^{13}}{13}+\frac {1}{3} a^4 b x^{15}+\frac {10}{17} a^3 b^2 x^{17}+\frac {10}{19} a^2 b^3 x^{19}+\frac {5}{21} a b^4 x^{21}+\frac {b^5 x^{23}}{23}\right )}{a+b x^2}\) |
Input:
Int[x^12*(a^2 + 2*a*b*x^2 + b^2*x^4)^(5/2),x]
Output:
(Sqrt[a^2 + 2*a*b*x^2 + b^2*x^4]*((a^5*x^13)/13 + (a^4*b*x^15)/3 + (10*a^3 *b^2*x^17)/17 + (10*a^2*b^3*x^19)/19 + (5*a*b^4*x^21)/21 + (b^5*x^23)/23)) /(a + b*x^2)
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Int[Expand Integrand[(c*x)^m*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, m}, x] && IGtQ[p , 0]
Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> S imp[(a + b*x^n + c*x^(2*n))^FracPart[p]/(c^IntPart[p]*(b/2 + c*x^n)^(2*Frac Part[p])) Int[u*(b/2 + c*x^n)^(2*p), x], x] /; FreeQ[{a, b, c, n, p}, x] && EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p - 1/2] && NeQ[u, x^(n - 1)] && NeQ[u, x^(2*n - 1)] && !(EqQ[p, 1/2] && EqQ[u, x^(-2*n - 1)])
Time = 5.99 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.31
method | result | size |
gosper | \(\frac {x^{13} \left (88179 x^{10} b^{5}+482885 a \,x^{8} b^{4}+1067430 a^{2} x^{6} b^{3}+1193010 a^{3} x^{4} b^{2}+676039 x^{2} a^{4} b +156009 a^{5}\right ) {\left (\left (b \,x^{2}+a \right )^{2}\right )}^{\frac {5}{2}}}{2028117 \left (b \,x^{2}+a \right )^{5}}\) | \(80\) |
default | \(\frac {x^{13} \left (88179 x^{10} b^{5}+482885 a \,x^{8} b^{4}+1067430 a^{2} x^{6} b^{3}+1193010 a^{3} x^{4} b^{2}+676039 x^{2} a^{4} b +156009 a^{5}\right ) {\left (\left (b \,x^{2}+a \right )^{2}\right )}^{\frac {5}{2}}}{2028117 \left (b \,x^{2}+a \right )^{5}}\) | \(80\) |
orering | \(\frac {x^{13} \left (88179 x^{10} b^{5}+482885 a \,x^{8} b^{4}+1067430 a^{2} x^{6} b^{3}+1193010 a^{3} x^{4} b^{2}+676039 x^{2} a^{4} b +156009 a^{5}\right ) \left (b^{2} x^{4}+2 a b \,x^{2}+a^{2}\right )^{\frac {5}{2}}}{2028117 \left (b \,x^{2}+a \right )^{5}}\) | \(89\) |
risch | \(\frac {a^{5} x^{13} \sqrt {\left (b \,x^{2}+a \right )^{2}}}{13 b \,x^{2}+13 a}+\frac {a^{4} b \,x^{15} \sqrt {\left (b \,x^{2}+a \right )^{2}}}{3 b \,x^{2}+3 a}+\frac {10 \sqrt {\left (b \,x^{2}+a \right )^{2}}\, a^{3} b^{2} x^{17}}{17 \left (b \,x^{2}+a \right )}+\frac {10 \sqrt {\left (b \,x^{2}+a \right )^{2}}\, a^{2} b^{3} x^{19}}{19 \left (b \,x^{2}+a \right )}+\frac {5 \sqrt {\left (b \,x^{2}+a \right )^{2}}\, b^{4} a \,x^{21}}{21 \left (b \,x^{2}+a \right )}+\frac {b^{5} x^{23} \sqrt {\left (b \,x^{2}+a \right )^{2}}}{23 b \,x^{2}+23 a}\) | \(178\) |
Input:
int(x^12*(b^2*x^4+2*a*b*x^2+a^2)^(5/2),x,method=_RETURNVERBOSE)
Output:
1/2028117*x^13*(88179*b^5*x^10+482885*a*b^4*x^8+1067430*a^2*b^3*x^6+119301 0*a^3*b^2*x^4+676039*a^4*b*x^2+156009*a^5)*((b*x^2+a)^2)^(5/2)/(b*x^2+a)^5
Time = 0.08 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.22 \[ \int x^{12} \left (a^2+2 a b x^2+b^2 x^4\right )^{5/2} \, dx=\frac {1}{23} \, b^{5} x^{23} + \frac {5}{21} \, a b^{4} x^{21} + \frac {10}{19} \, a^{2} b^{3} x^{19} + \frac {10}{17} \, a^{3} b^{2} x^{17} + \frac {1}{3} \, a^{4} b x^{15} + \frac {1}{13} \, a^{5} x^{13} \] Input:
integrate(x^12*(b^2*x^4+2*a*b*x^2+a^2)^(5/2),x, algorithm="fricas")
Output:
1/23*b^5*x^23 + 5/21*a*b^4*x^21 + 10/19*a^2*b^3*x^19 + 10/17*a^3*b^2*x^17 + 1/3*a^4*b*x^15 + 1/13*a^5*x^13
\[ \int x^{12} \left (a^2+2 a b x^2+b^2 x^4\right )^{5/2} \, dx=\int x^{12} \left (\left (a + b x^{2}\right )^{2}\right )^{\frac {5}{2}}\, dx \] Input:
integrate(x**12*(b**2*x**4+2*a*b*x**2+a**2)**(5/2),x)
Output:
Integral(x**12*((a + b*x**2)**2)**(5/2), x)
Time = 0.04 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.22 \[ \int x^{12} \left (a^2+2 a b x^2+b^2 x^4\right )^{5/2} \, dx=\frac {1}{23} \, b^{5} x^{23} + \frac {5}{21} \, a b^{4} x^{21} + \frac {10}{19} \, a^{2} b^{3} x^{19} + \frac {10}{17} \, a^{3} b^{2} x^{17} + \frac {1}{3} \, a^{4} b x^{15} + \frac {1}{13} \, a^{5} x^{13} \] Input:
integrate(x^12*(b^2*x^4+2*a*b*x^2+a^2)^(5/2),x, algorithm="maxima")
Output:
1/23*b^5*x^23 + 5/21*a*b^4*x^21 + 10/19*a^2*b^3*x^19 + 10/17*a^3*b^2*x^17 + 1/3*a^4*b*x^15 + 1/13*a^5*x^13
Time = 0.11 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.41 \[ \int x^{12} \left (a^2+2 a b x^2+b^2 x^4\right )^{5/2} \, dx=\frac {1}{23} \, b^{5} x^{23} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {5}{21} \, a b^{4} x^{21} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {10}{19} \, a^{2} b^{3} x^{19} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {10}{17} \, a^{3} b^{2} x^{17} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {1}{3} \, a^{4} b x^{15} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {1}{13} \, a^{5} x^{13} \mathrm {sgn}\left (b x^{2} + a\right ) \] Input:
integrate(x^12*(b^2*x^4+2*a*b*x^2+a^2)^(5/2),x, algorithm="giac")
Output:
1/23*b^5*x^23*sgn(b*x^2 + a) + 5/21*a*b^4*x^21*sgn(b*x^2 + a) + 10/19*a^2* b^3*x^19*sgn(b*x^2 + a) + 10/17*a^3*b^2*x^17*sgn(b*x^2 + a) + 1/3*a^4*b*x^ 15*sgn(b*x^2 + a) + 1/13*a^5*x^13*sgn(b*x^2 + a)
Timed out. \[ \int x^{12} \left (a^2+2 a b x^2+b^2 x^4\right )^{5/2} \, dx=\int x^{12}\,{\left (a^2+2\,a\,b\,x^2+b^2\,x^4\right )}^{5/2} \,d x \] Input:
int(x^12*(a^2 + b^2*x^4 + 2*a*b*x^2)^(5/2),x)
Output:
int(x^12*(a^2 + b^2*x^4 + 2*a*b*x^2)^(5/2), x)
Time = 0.17 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.23 \[ \int x^{12} \left (a^2+2 a b x^2+b^2 x^4\right )^{5/2} \, dx=\frac {x^{13} \left (88179 b^{5} x^{10}+482885 a \,b^{4} x^{8}+1067430 a^{2} b^{3} x^{6}+1193010 a^{3} b^{2} x^{4}+676039 a^{4} b \,x^{2}+156009 a^{5}\right )}{2028117} \] Input:
int(x^12*(b^2*x^4+2*a*b*x^2+a^2)^(5/2),x)
Output:
(x**13*(156009*a**5 + 676039*a**4*b*x**2 + 1193010*a**3*b**2*x**4 + 106743 0*a**2*b**3*x**6 + 482885*a*b**4*x**8 + 88179*b**5*x**10))/2028117