Integrand size = 22, antiderivative size = 179 \[ \int \frac {1}{\left (d+e x^2\right )^{3/2} \left (a-c x^4\right )} \, dx=-\frac {e^2 x}{d \left (c d^2-a e^2\right ) \sqrt {d+e x^2}}+\frac {\sqrt {c} \arctan \left (\frac {\sqrt {\sqrt {c} d-\sqrt {a} e} x}{\sqrt [4]{a} \sqrt {d+e x^2}}\right )}{2 a^{3/4} \left (\sqrt {c} d-\sqrt {a} e\right )^{3/2}}+\frac {\sqrt {c} \text {arctanh}\left (\frac {\sqrt {\sqrt {c} d+\sqrt {a} e} x}{\sqrt [4]{a} \sqrt {d+e x^2}}\right )}{2 a^{3/4} \left (\sqrt {c} d+\sqrt {a} e\right )^{3/2}} \] Output:
-e^2*x/d/(-a*e^2+c*d^2)/(e*x^2+d)^(1/2)+1/2*c^(1/2)*arctan((c^(1/2)*d-a^(1 /2)*e)^(1/2)*x/a^(1/4)/(e*x^2+d)^(1/2))/a^(3/4)/(c^(1/2)*d-a^(1/2)*e)^(3/2 )+1/2*c^(1/2)*arctanh((c^(1/2)*d+a^(1/2)*e)^(1/2)*x/a^(1/4)/(e*x^2+d)^(1/2 ))/a^(3/4)/(c^(1/2)*d+a^(1/2)*e)^(3/2)
Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
Time = 0.21 (sec) , antiderivative size = 247, normalized size of antiderivative = 1.38 \[ \int \frac {1}{\left (d+e x^2\right )^{3/2} \left (a-c x^4\right )} \, dx=-\frac {\frac {2 e^2 x}{\sqrt {d+e x^2}}-c d e^{3/2} \text {RootSum}\left [c d^4-4 c d^3 \text {$\#$1}+6 c d^2 \text {$\#$1}^2-16 a e^2 \text {$\#$1}^2-4 c d \text {$\#$1}^3+c \text {$\#$1}^4\&,\frac {d^2 \log \left (d+2 e x^2-2 \sqrt {e} x \sqrt {d+e x^2}-\text {$\#$1}\right )-6 d \log \left (d+2 e x^2-2 \sqrt {e} x \sqrt {d+e x^2}-\text {$\#$1}\right ) \text {$\#$1}+\log \left (d+2 e x^2-2 \sqrt {e} x \sqrt {d+e x^2}-\text {$\#$1}\right ) \text {$\#$1}^2}{c d^3-3 c d^2 \text {$\#$1}+8 a e^2 \text {$\#$1}+3 c d \text {$\#$1}^2-c \text {$\#$1}^3}\&\right ]}{2 c d^3-2 a d e^2} \] Input:
Integrate[1/((d + e*x^2)^(3/2)*(a - c*x^4)),x]
Output:
-(((2*e^2*x)/Sqrt[d + e*x^2] - c*d*e^(3/2)*RootSum[c*d^4 - 4*c*d^3*#1 + 6* c*d^2*#1^2 - 16*a*e^2*#1^2 - 4*c*d*#1^3 + c*#1^4 & , (d^2*Log[d + 2*e*x^2 - 2*Sqrt[e]*x*Sqrt[d + e*x^2] - #1] - 6*d*Log[d + 2*e*x^2 - 2*Sqrt[e]*x*Sq rt[d + e*x^2] - #1]*#1 + Log[d + 2*e*x^2 - 2*Sqrt[e]*x*Sqrt[d + e*x^2] - # 1]*#1^2)/(c*d^3 - 3*c*d^2*#1 + 8*a*e^2*#1 + 3*c*d*#1^2 - c*#1^3) & ])/(2*c *d^3 - 2*a*d*e^2))
Time = 0.81 (sec) , antiderivative size = 227, normalized size of antiderivative = 1.27, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {1487, 208, 2257, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{\left (a-c x^4\right ) \left (d+e x^2\right )^{3/2}} \, dx\) |
\(\Big \downarrow \) 1487 |
\(\displaystyle \frac {c \int \frac {d-e x^2}{\sqrt {e x^2+d} \left (a-c x^4\right )}dx}{c d^2-a e^2}-\frac {e^2 \int \frac {1}{\left (e x^2+d\right )^{3/2}}dx}{c d^2-a e^2}\) |
\(\Big \downarrow \) 208 |
\(\displaystyle \frac {c \int \frac {d-e x^2}{\sqrt {e x^2+d} \left (a-c x^4\right )}dx}{c d^2-a e^2}-\frac {e^2 x}{d \sqrt {d+e x^2} \left (c d^2-a e^2\right )}\) |
\(\Big \downarrow \) 2257 |
\(\displaystyle \frac {c \int \left (\frac {\sqrt {c} d-\sqrt {a} e}{2 \sqrt {a} \sqrt {c} \left (\sqrt {a}-\sqrt {c} x^2\right ) \sqrt {e x^2+d}}-\frac {-\sqrt {c} d-\sqrt {a} e}{2 \sqrt {a} \sqrt {c} \left (\sqrt {c} x^2+\sqrt {a}\right ) \sqrt {e x^2+d}}\right )dx}{c d^2-a e^2}-\frac {e^2 x}{d \sqrt {d+e x^2} \left (c d^2-a e^2\right )}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {c \left (\frac {\left (\sqrt {a} e+\sqrt {c} d\right ) \arctan \left (\frac {x \sqrt {\sqrt {c} d-\sqrt {a} e}}{\sqrt [4]{a} \sqrt {d+e x^2}}\right )}{2 a^{3/4} \sqrt {c} \sqrt {\sqrt {c} d-\sqrt {a} e}}+\frac {\left (\sqrt {c} d-\sqrt {a} e\right ) \text {arctanh}\left (\frac {x \sqrt {\sqrt {a} e+\sqrt {c} d}}{\sqrt [4]{a} \sqrt {d+e x^2}}\right )}{2 a^{3/4} \sqrt {c} \sqrt {\sqrt {a} e+\sqrt {c} d}}\right )}{c d^2-a e^2}-\frac {e^2 x}{d \sqrt {d+e x^2} \left (c d^2-a e^2\right )}\) |
Input:
Int[1/((d + e*x^2)^(3/2)*(a - c*x^4)),x]
Output:
-((e^2*x)/(d*(c*d^2 - a*e^2)*Sqrt[d + e*x^2])) + (c*(((Sqrt[c]*d + Sqrt[a] *e)*ArcTan[(Sqrt[Sqrt[c]*d - Sqrt[a]*e]*x)/(a^(1/4)*Sqrt[d + e*x^2])])/(2* a^(3/4)*Sqrt[c]*Sqrt[Sqrt[c]*d - Sqrt[a]*e]) + ((Sqrt[c]*d - Sqrt[a]*e)*Ar cTanh[(Sqrt[Sqrt[c]*d + Sqrt[a]*e]*x)/(a^(1/4)*Sqrt[d + e*x^2])])/(2*a^(3/ 4)*Sqrt[c]*Sqrt[Sqrt[c]*d + Sqrt[a]*e])))/(c*d^2 - a*e^2)
Int[((a_) + (b_.)*(x_)^2)^(-3/2), x_Symbol] :> Simp[x/(a*Sqrt[a + b*x^2]), x] /; FreeQ[{a, b}, x]
Int[((d_) + (e_.)*(x_)^2)^(q_)/((a_) + (c_.)*(x_)^4), x_Symbol] :> Simp[e^2 /(c*d^2 + a*e^2) Int[(d + e*x^2)^q, x], x] + Simp[c/(c*d^2 + a*e^2) Int [(d + e*x^2)^(q + 1)*((d - e*x^2)/(a + c*x^4)), x], x] /; FreeQ[{a, c, d, e }, x] && NeQ[c*d^2 + a*e^2, 0] && !IntegerQ[q] && LtQ[q, -1]
Int[(Px_)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (c_.)*(x_)^4)^(p_.), x_Symbol ] :> Int[ExpandIntegrand[Px*(d + e*x^2)^q*(a + c*x^4)^p, x], x] /; FreeQ[{a , c, d, e, q}, x] && PolyQ[Px, x] && IntegerQ[p]
Time = 0.50 (sec) , antiderivative size = 253, normalized size of antiderivative = 1.41
method | result | size |
pseudoelliptic | \(\frac {\frac {\left (a e +\sqrt {d^{2} a c}\right ) d^{2} \sqrt {\left (a e +\sqrt {d^{2} a c}\right ) a}\, c \sqrt {e \,x^{2}+d}\, \arctan \left (\frac {\sqrt {e \,x^{2}+d}\, a}{x \sqrt {\left (-a e +\sqrt {d^{2} a c}\right ) a}}\right )}{2}+\sqrt {\left (-a e +\sqrt {d^{2} a c}\right ) a}\, \left (\frac {c \,d^{2} \sqrt {e \,x^{2}+d}\, \left (a e -\sqrt {d^{2} a c}\right ) \operatorname {arctanh}\left (\frac {\sqrt {e \,x^{2}+d}\, a}{x \sqrt {\left (a e +\sqrt {d^{2} a c}\right ) a}}\right )}{2}+\sqrt {\left (a e +\sqrt {d^{2} a c}\right ) a}\, \sqrt {d^{2} a c}\, e^{2} x \right )}{\sqrt {\left (a e +\sqrt {d^{2} a c}\right ) a}\, \sqrt {e \,x^{2}+d}\, \sqrt {d^{2} a c}\, \sqrt {\left (-a e +\sqrt {d^{2} a c}\right ) a}\, \left (a \,e^{2}-c \,d^{2}\right ) d}\) | \(253\) |
default | \(\text {Expression too large to display}\) | \(1852\) |
Input:
int(1/(e*x^2+d)^(3/2)/(-c*x^4+a),x,method=_RETURNVERBOSE)
Output:
1/((a*e+(d^2*a*c)^(1/2))*a)^(1/2)/(e*x^2+d)^(1/2)/(d^2*a*c)^(1/2)*(1/2*(a* e+(d^2*a*c)^(1/2))*d^2*((a*e+(d^2*a*c)^(1/2))*a)^(1/2)*c*(e*x^2+d)^(1/2)*a rctan((e*x^2+d)^(1/2)/x*a/((-a*e+(d^2*a*c)^(1/2))*a)^(1/2))+((-a*e+(d^2*a* c)^(1/2))*a)^(1/2)*(1/2*c*d^2*(e*x^2+d)^(1/2)*(a*e-(d^2*a*c)^(1/2))*arctan h((e*x^2+d)^(1/2)/x*a/((a*e+(d^2*a*c)^(1/2))*a)^(1/2))+((a*e+(d^2*a*c)^(1/ 2))*a)^(1/2)*(d^2*a*c)^(1/2)*e^2*x))/((-a*e+(d^2*a*c)^(1/2))*a)^(1/2)/(a*e ^2-c*d^2)/d
Leaf count of result is larger than twice the leaf count of optimal. 3813 vs. \(2 (133) = 266\).
Time = 11.03 (sec) , antiderivative size = 3813, normalized size of antiderivative = 21.30 \[ \int \frac {1}{\left (d+e x^2\right )^{3/2} \left (a-c x^4\right )} \, dx=\text {Too large to display} \] Input:
integrate(1/(e*x^2+d)^(3/2)/(-c*x^4+a),x, algorithm="fricas")
Output:
Too large to include
\[ \int \frac {1}{\left (d+e x^2\right )^{3/2} \left (a-c x^4\right )} \, dx=- \int \frac {1}{- a d \sqrt {d + e x^{2}} - a e x^{2} \sqrt {d + e x^{2}} + c d x^{4} \sqrt {d + e x^{2}} + c e x^{6} \sqrt {d + e x^{2}}}\, dx \] Input:
integrate(1/(e*x**2+d)**(3/2)/(-c*x**4+a),x)
Output:
-Integral(1/(-a*d*sqrt(d + e*x**2) - a*e*x**2*sqrt(d + e*x**2) + c*d*x**4* sqrt(d + e*x**2) + c*e*x**6*sqrt(d + e*x**2)), x)
\[ \int \frac {1}{\left (d+e x^2\right )^{3/2} \left (a-c x^4\right )} \, dx=\int { -\frac {1}{{\left (c x^{4} - a\right )} {\left (e x^{2} + d\right )}^{\frac {3}{2}}} \,d x } \] Input:
integrate(1/(e*x^2+d)^(3/2)/(-c*x^4+a),x, algorithm="maxima")
Output:
-integrate(1/((c*x^4 - a)*(e*x^2 + d)^(3/2)), x)
Timed out. \[ \int \frac {1}{\left (d+e x^2\right )^{3/2} \left (a-c x^4\right )} \, dx=\text {Timed out} \] Input:
integrate(1/(e*x^2+d)^(3/2)/(-c*x^4+a),x, algorithm="giac")
Output:
Timed out
Timed out. \[ \int \frac {1}{\left (d+e x^2\right )^{3/2} \left (a-c x^4\right )} \, dx=\int \frac {1}{\left (a-c\,x^4\right )\,{\left (e\,x^2+d\right )}^{3/2}} \,d x \] Input:
int(1/((a - c*x^4)*(d + e*x^2)^(3/2)),x)
Output:
int(1/((a - c*x^4)*(d + e*x^2)^(3/2)), x)
\[ \int \frac {1}{\left (d+e x^2\right )^{3/2} \left (a-c x^4\right )} \, dx=\int \frac {1}{\sqrt {e \,x^{2}+d}\, a d +\sqrt {e \,x^{2}+d}\, a e \,x^{2}-\sqrt {e \,x^{2}+d}\, c d \,x^{4}-\sqrt {e \,x^{2}+d}\, c e \,x^{6}}d x \] Input:
int(1/(e*x^2+d)^(3/2)/(-c*x^4+a),x)
Output:
int(1/(sqrt(d + e*x**2)*a*d + sqrt(d + e*x**2)*a*e*x**2 - sqrt(d + e*x**2) *c*d*x**4 - sqrt(d + e*x**2)*c*e*x**6),x)