Integrand size = 24, antiderivative size = 623 \[ \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx=\frac {x \sqrt {a-c x^4}}{7 d \left (d+e x^2\right )^{7/2}}+\frac {2 \left (2 c d^2-3 a e^2\right ) x \sqrt {a-c x^4}}{35 d^2 \left (c d^2-a e^2\right ) \left (d+e x^2\right )^{5/2}}+\frac {8 \left (c^2 d^4-6 a c d^2 e^2+3 a^2 e^4\right ) x \sqrt {a-c x^4}}{105 d^3 \left (c d^2-a e^2\right )^2 \left (d+e x^2\right )^{3/2}}+\frac {2 a e \left (77 c^2 d^4-69 a c d^2 e^2+24 a^2 e^4\right ) \sqrt {a-c x^4}}{105 d^3 \left (c d^2-a e^2\right )^3 x \sqrt {d+e x^2}}+\frac {2 a \sqrt {c} e \left (77 c^2 d^4-69 a c d^2 e^2+24 a^2 e^4\right ) \sqrt {1-\frac {a}{c x^4}} x^3 \sqrt {\frac {\sqrt {a} \left (d+e x^2\right )}{\left (\sqrt {c} d+\sqrt {a} e\right ) x^2}} E\left (\arcsin \left (\frac {\sqrt {1-\frac {\sqrt {a}}{\sqrt {c} x^2}}}{\sqrt {2}}\right )|\frac {2 d}{d+\frac {\sqrt {a} e}{\sqrt {c}}}\right )}{105 d^4 \left (\sqrt {c} d-\sqrt {a} e\right )^3 \left (\sqrt {c} d+\sqrt {a} e\right )^2 \sqrt {d+e x^2} \sqrt {a-c x^4}}+\frac {2 \sqrt {a} \sqrt {c} \left (35 c^2 d^4-51 a c d^2 e^2+24 a^2 e^4\right ) \sqrt {1-\frac {a}{c x^4}} x^3 \sqrt {\frac {\sqrt {a} \left (d+e x^2\right )}{\left (\sqrt {c} d+\sqrt {a} e\right ) x^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {1-\frac {\sqrt {a}}{\sqrt {c} x^2}}}{\sqrt {2}}\right ),\frac {2 d}{d+\frac {\sqrt {a} e}{\sqrt {c}}}\right )}{105 d^4 \left (c d^2-a e^2\right )^2 \sqrt {d+e x^2} \sqrt {a-c x^4}} \] Output:
1/7*x*(-c*x^4+a)^(1/2)/d/(e*x^2+d)^(7/2)+2/35*(-3*a*e^2+2*c*d^2)*x*(-c*x^4 +a)^(1/2)/d^2/(-a*e^2+c*d^2)/(e*x^2+d)^(5/2)+8/105*(3*a^2*e^4-6*a*c*d^2*e^ 2+c^2*d^4)*x*(-c*x^4+a)^(1/2)/d^3/(-a*e^2+c*d^2)^2/(e*x^2+d)^(3/2)+2/105*a *e*(24*a^2*e^4-69*a*c*d^2*e^2+77*c^2*d^4)*(-c*x^4+a)^(1/2)/d^3/(-a*e^2+c*d ^2)^3/x/(e*x^2+d)^(1/2)+2/105*a*c^(1/2)*e*(24*a^2*e^4-69*a*c*d^2*e^2+77*c^ 2*d^4)*(1-a/c/x^4)^(1/2)*x^3*(a^(1/2)*(e*x^2+d)/(c^(1/2)*d+a^(1/2)*e)/x^2) ^(1/2)*EllipticE(1/2*(1-a^(1/2)/c^(1/2)/x^2)^(1/2)*2^(1/2),2^(1/2)*(d/(d+a ^(1/2)*e/c^(1/2)))^(1/2))/d^4/(c^(1/2)*d-a^(1/2)*e)^3/(c^(1/2)*d+a^(1/2)*e )^2/(e*x^2+d)^(1/2)/(-c*x^4+a)^(1/2)+2/105*a^(1/2)*c^(1/2)*(24*a^2*e^4-51* a*c*d^2*e^2+35*c^2*d^4)*(1-a/c/x^4)^(1/2)*x^3*(a^(1/2)*(e*x^2+d)/(c^(1/2)* d+a^(1/2)*e)/x^2)^(1/2)*EllipticF(1/2*(1-a^(1/2)/c^(1/2)/x^2)^(1/2)*2^(1/2 ),2^(1/2)*(d/(d+a^(1/2)*e/c^(1/2)))^(1/2))/d^4/(-a*e^2+c*d^2)^2/(e*x^2+d)^ (1/2)/(-c*x^4+a)^(1/2)
\[ \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx=\int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx \] Input:
Integrate[Sqrt[a - c*x^4]/(d + e*x^2)^(9/2),x]
Output:
Integrate[Sqrt[a - c*x^4]/(d + e*x^2)^(9/2), x]
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx\) |
\(\Big \downarrow \) 1571 |
\(\displaystyle \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}}dx\) |
Input:
Int[Sqrt[a - c*x^4]/(d + e*x^2)^(9/2),x]
Output:
$Aborted
Int[((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (c_.)*(x_)^4)^(p_.), x_Symbol] :> U nintegrable[(d + e*x^2)^q*(a + c*x^4)^p, x] /; FreeQ[{a, c, d, e, p, q}, x]
\[\int \frac {\sqrt {-c \,x^{4}+a}}{\left (e \,x^{2}+d \right )^{\frac {9}{2}}}d x\]
Input:
int((-c*x^4+a)^(1/2)/(e*x^2+d)^(9/2),x)
Output:
int((-c*x^4+a)^(1/2)/(e*x^2+d)^(9/2),x)
\[ \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx=\int { \frac {\sqrt {-c x^{4} + a}}{{\left (e x^{2} + d\right )}^{\frac {9}{2}}} \,d x } \] Input:
integrate((-c*x^4+a)^(1/2)/(e*x^2+d)^(9/2),x, algorithm="fricas")
Output:
integral(sqrt(-c*x^4 + a)*sqrt(e*x^2 + d)/(e^5*x^10 + 5*d*e^4*x^8 + 10*d^2 *e^3*x^6 + 10*d^3*e^2*x^4 + 5*d^4*e*x^2 + d^5), x)
\[ \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx=\int \frac {\sqrt {a - c x^{4}}}{\left (d + e x^{2}\right )^{\frac {9}{2}}}\, dx \] Input:
integrate((-c*x**4+a)**(1/2)/(e*x**2+d)**(9/2),x)
Output:
Integral(sqrt(a - c*x**4)/(d + e*x**2)**(9/2), x)
\[ \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx=\int { \frac {\sqrt {-c x^{4} + a}}{{\left (e x^{2} + d\right )}^{\frac {9}{2}}} \,d x } \] Input:
integrate((-c*x^4+a)^(1/2)/(e*x^2+d)^(9/2),x, algorithm="maxima")
Output:
integrate(sqrt(-c*x^4 + a)/(e*x^2 + d)^(9/2), x)
\[ \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx=\int { \frac {\sqrt {-c x^{4} + a}}{{\left (e x^{2} + d\right )}^{\frac {9}{2}}} \,d x } \] Input:
integrate((-c*x^4+a)^(1/2)/(e*x^2+d)^(9/2),x, algorithm="giac")
Output:
integrate(sqrt(-c*x^4 + a)/(e*x^2 + d)^(9/2), x)
Timed out. \[ \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx=\int \frac {\sqrt {a-c\,x^4}}{{\left (e\,x^2+d\right )}^{9/2}} \,d x \] Input:
int((a - c*x^4)^(1/2)/(d + e*x^2)^(9/2),x)
Output:
int((a - c*x^4)^(1/2)/(d + e*x^2)^(9/2), x)
\[ \int \frac {\sqrt {a-c x^4}}{\left (d+e x^2\right )^{9/2}} \, dx=\int \frac {\sqrt {e \,x^{2}+d}\, \sqrt {-c \,x^{4}+a}}{e^{5} x^{10}+5 d \,e^{4} x^{8}+10 d^{2} e^{3} x^{6}+10 d^{3} e^{2} x^{4}+5 d^{4} e \,x^{2}+d^{5}}d x \] Input:
int((-c*x^4+a)^(1/2)/(e*x^2+d)^(9/2),x)
Output:
int((sqrt(d + e*x**2)*sqrt(a - c*x**4))/(d**5 + 5*d**4*e*x**2 + 10*d**3*e* *2*x**4 + 10*d**2*e**3*x**6 + 5*d*e**4*x**8 + e**5*x**10),x)