Integrand size = 26, antiderivative size = 224 \[ \int \frac {1}{\left (d+e x^2\right )^3 \sqrt {d^2-e^2 x^4}} \, dx=\frac {x \sqrt {d^2-e^2 x^4}}{10 d^2 \left (d+e x^2\right )^3}+\frac {x \sqrt {d^2-e^2 x^4}}{5 d^3 \left (d+e x^2\right )^2}+\frac {9 x \sqrt {d^2-e^2 x^4}}{20 d^4 \left (d+e x^2\right )}+\frac {9 \sqrt {1-\frac {e^2 x^4}{d^2}} E\left (\left .\arcsin \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )\right |-1\right )}{20 d^{5/2} \sqrt {e} \sqrt {d^2-e^2 x^4}}-\frac {\sqrt {1-\frac {e^2 x^4}{d^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {e} x}{\sqrt {d}}\right ),-1\right )}{5 d^{5/2} \sqrt {e} \sqrt {d^2-e^2 x^4}} \] Output:
1/10*x*(-e^2*x^4+d^2)^(1/2)/d^2/(e*x^2+d)^3+1/5*x*(-e^2*x^4+d^2)^(1/2)/d^3 /(e*x^2+d)^2+9/20*x*(-e^2*x^4+d^2)^(1/2)/d^4/(e*x^2+d)+9/20*(1-e^2*x^4/d^2 )^(1/2)*EllipticE(e^(1/2)*x/d^(1/2),I)/d^(5/2)/e^(1/2)/(-e^2*x^4+d^2)^(1/2 )-1/5*(1-e^2*x^4/d^2)^(1/2)*EllipticF(e^(1/2)*x/d^(1/2),I)/d^(5/2)/e^(1/2) /(-e^2*x^4+d^2)^(1/2)
Result contains complex when optimal does not.
Time = 10.78 (sec) , antiderivative size = 187, normalized size of antiderivative = 0.83 \[ \int \frac {1}{\left (d+e x^2\right )^3 \sqrt {d^2-e^2 x^4}} \, dx=\frac {\sqrt {-\frac {e}{d}} x \left (15 d^3+7 d^2 e x^2-13 d e^2 x^4-9 e^3 x^6\right )-9 i d \left (d+e x^2\right )^2 \sqrt {1-\frac {e^2 x^4}{d^2}} E\left (\left .i \text {arcsinh}\left (\sqrt {-\frac {e}{d}} x\right )\right |-1\right )+4 i d \left (d+e x^2\right )^2 \sqrt {1-\frac {e^2 x^4}{d^2}} \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {-\frac {e}{d}} x\right ),-1\right )}{20 d^4 \sqrt {-\frac {e}{d}} \left (d+e x^2\right )^2 \sqrt {d^2-e^2 x^4}} \] Input:
Integrate[1/((d + e*x^2)^3*Sqrt[d^2 - e^2*x^4]),x]
Output:
(Sqrt[-(e/d)]*x*(15*d^3 + 7*d^2*e*x^2 - 13*d*e^2*x^4 - 9*e^3*x^6) - (9*I)* d*(d + e*x^2)^2*Sqrt[1 - (e^2*x^4)/d^2]*EllipticE[I*ArcSinh[Sqrt[-(e/d)]*x ], -1] + (4*I)*d*(d + e*x^2)^2*Sqrt[1 - (e^2*x^4)/d^2]*EllipticF[I*ArcSinh [Sqrt[-(e/d)]*x], -1])/(20*d^4*Sqrt[-(e/d)]*(d + e*x^2)^2*Sqrt[d^2 - e^2*x ^4])
Time = 0.78 (sec) , antiderivative size = 292, normalized size of antiderivative = 1.30, number of steps used = 14, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.538, Rules used = {1396, 316, 27, 402, 27, 402, 25, 27, 399, 289, 329, 327, 765, 762}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {1}{\left (d+e x^2\right )^3 \sqrt {d^2-e^2 x^4}} \, dx\) |
\(\Big \downarrow \) 1396 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \int \frac {1}{\sqrt {d-e x^2} \left (e x^2+d\right )^{7/2}}dx}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 316 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}-\frac {\int -\frac {3 e \left (3 d-e x^2\right )}{\sqrt {d-e x^2} \left (e x^2+d\right )^{5/2}}dx}{10 d^2 e}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \int \frac {3 d-e x^2}{\sqrt {d-e x^2} \left (e x^2+d\right )^{5/2}}dx}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 402 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}-\frac {\int -\frac {2 d e \left (7 d-2 e x^2\right )}{\sqrt {d-e x^2} \left (e x^2+d\right )^{3/2}}dx}{6 d^2 e}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\int \frac {7 d-2 e x^2}{\sqrt {d-e x^2} \left (e x^2+d\right )^{3/2}}dx}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 402 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\frac {9 x \sqrt {d-e x^2}}{2 d \sqrt {d+e x^2}}-\frac {\int -\frac {d e \left (9 e x^2+5 d\right )}{\sqrt {d-e x^2} \sqrt {e x^2+d}}dx}{2 d^2 e}}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\frac {\int \frac {d e \left (9 e x^2+5 d\right )}{\sqrt {d-e x^2} \sqrt {e x^2+d}}dx}{2 d^2 e}+\frac {9 x \sqrt {d-e x^2}}{2 d \sqrt {d+e x^2}}}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\frac {\int \frac {9 e x^2+5 d}{\sqrt {d-e x^2} \sqrt {e x^2+d}}dx}{2 d}+\frac {9 x \sqrt {d-e x^2}}{2 d \sqrt {d+e x^2}}}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 399 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\frac {9 \int \frac {\sqrt {e x^2+d}}{\sqrt {d-e x^2}}dx-4 d \int \frac {1}{\sqrt {d-e x^2} \sqrt {e x^2+d}}dx}{2 d}+\frac {9 x \sqrt {d-e x^2}}{2 d \sqrt {d+e x^2}}}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 289 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\frac {9 \int \frac {\sqrt {e x^2+d}}{\sqrt {d-e x^2}}dx-\frac {4 d \sqrt {d^2-e^2 x^4} \int \frac {1}{\sqrt {d^2-e^2 x^4}}dx}{\sqrt {d-e x^2} \sqrt {d+e x^2}}}{2 d}+\frac {9 x \sqrt {d-e x^2}}{2 d \sqrt {d+e x^2}}}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 329 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\frac {\frac {9 d \sqrt {1-\frac {e^2 x^4}{d^2}} \int \frac {\sqrt {\frac {e x^2}{d}+1}}{\sqrt {1-\frac {e x^2}{d}}}dx}{\sqrt {d-e x^2} \sqrt {d+e x^2}}-\frac {4 d \sqrt {d^2-e^2 x^4} \int \frac {1}{\sqrt {d^2-e^2 x^4}}dx}{\sqrt {d-e x^2} \sqrt {d+e x^2}}}{2 d}+\frac {9 x \sqrt {d-e x^2}}{2 d \sqrt {d+e x^2}}}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 327 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\frac {\frac {9 d^{3/2} \sqrt {1-\frac {e^2 x^4}{d^2}} E\left (\left .\arcsin \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )\right |-1\right )}{\sqrt {e} \sqrt {d-e x^2} \sqrt {d+e x^2}}-\frac {4 d \sqrt {d^2-e^2 x^4} \int \frac {1}{\sqrt {d^2-e^2 x^4}}dx}{\sqrt {d-e x^2} \sqrt {d+e x^2}}}{2 d}+\frac {9 x \sqrt {d-e x^2}}{2 d \sqrt {d+e x^2}}}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 765 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\frac {\frac {9 d^{3/2} \sqrt {1-\frac {e^2 x^4}{d^2}} E\left (\left .\arcsin \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )\right |-1\right )}{\sqrt {e} \sqrt {d-e x^2} \sqrt {d+e x^2}}-\frac {4 d \sqrt {1-\frac {e^2 x^4}{d^2}} \int \frac {1}{\sqrt {1-\frac {e^2 x^4}{d^2}}}dx}{\sqrt {d-e x^2} \sqrt {d+e x^2}}}{2 d}+\frac {9 x \sqrt {d-e x^2}}{2 d \sqrt {d+e x^2}}}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
\(\Big \downarrow \) 762 |
\(\displaystyle \frac {\sqrt {d-e x^2} \sqrt {d+e x^2} \left (\frac {3 \left (\frac {\frac {\frac {9 d^{3/2} \sqrt {1-\frac {e^2 x^4}{d^2}} E\left (\left .\arcsin \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )\right |-1\right )}{\sqrt {e} \sqrt {d-e x^2} \sqrt {d+e x^2}}-\frac {4 d^{3/2} \sqrt {1-\frac {e^2 x^4}{d^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt {e} x}{\sqrt {d}}\right ),-1\right )}{\sqrt {e} \sqrt {d-e x^2} \sqrt {d+e x^2}}}{2 d}+\frac {9 x \sqrt {d-e x^2}}{2 d \sqrt {d+e x^2}}}{3 d}+\frac {2 x \sqrt {d-e x^2}}{3 d \left (d+e x^2\right )^{3/2}}\right )}{10 d^2}+\frac {x \sqrt {d-e x^2}}{10 d^2 \left (d+e x^2\right )^{5/2}}\right )}{\sqrt {d^2-e^2 x^4}}\) |
Input:
Int[1/((d + e*x^2)^3*Sqrt[d^2 - e^2*x^4]),x]
Output:
(Sqrt[d - e*x^2]*Sqrt[d + e*x^2]*((x*Sqrt[d - e*x^2])/(10*d^2*(d + e*x^2)^ (5/2)) + (3*((2*x*Sqrt[d - e*x^2])/(3*d*(d + e*x^2)^(3/2)) + ((9*x*Sqrt[d - e*x^2])/(2*d*Sqrt[d + e*x^2]) + ((9*d^(3/2)*Sqrt[1 - (e^2*x^4)/d^2]*Elli pticE[ArcSin[(Sqrt[e]*x)/Sqrt[d]], -1])/(Sqrt[e]*Sqrt[d - e*x^2]*Sqrt[d + e*x^2]) - (4*d^(3/2)*Sqrt[1 - (e^2*x^4)/d^2]*EllipticF[ArcSin[(Sqrt[e]*x)/ Sqrt[d]], -1])/(Sqrt[e]*Sqrt[d - e*x^2]*Sqrt[d + e*x^2]))/(2*d))/(3*d)))/( 10*d^2)))/Sqrt[d^2 - e^2*x^4]
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2)^(p_), x_Symbol] :> Sim p[(a + b*x^2)^FracPart[p]*((c + d*x^2)^FracPart[p]/(a*c + b*d*x^4)^FracPart [p]) Int[(a*c + b*d*x^4)^p, x], x] /; FreeQ[{a, b, c, d, p}, x] && EqQ[b* c + a*d, 0] && !IntegerQ[p]
Int[((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2)^(q_), x_Symbol] :> Sim p[(-b)*x*(a + b*x^2)^(p + 1)*((c + d*x^2)^(q + 1)/(2*a*(p + 1)*(b*c - a*d)) ), x] + Simp[1/(2*a*(p + 1)*(b*c - a*d)) Int[(a + b*x^2)^(p + 1)*(c + d*x ^2)^q*Simp[b*c + 2*(p + 1)*(b*c - a*d) + d*b*(2*(p + q + 2) + 1)*x^2, x], x ], x] /; FreeQ[{a, b, c, d, q}, x] && NeQ[b*c - a*d, 0] && LtQ[p, -1] && ! ( !IntegerQ[p] && IntegerQ[q] && LtQ[q, -1]) && IntBinomialQ[a, b, c, d, 2, p, q, x]
Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[ (Sqrt[a]/(Sqrt[c]*Rt[-d/c, 2]))*EllipticE[ArcSin[Rt[-d/c, 2]*x], b*(c/(a*d) )], x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[a, 0]
Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[ a*(Sqrt[1 - b^2*(x^4/a^2)]/(Sqrt[a + b*x^2]*Sqrt[c + d*x^2])) Int[Sqrt[1 + b*(x^2/a)]/Sqrt[1 - b*(x^2/a)], x], x] /; FreeQ[{a, b, c, d}, x] && EqQ[b *c + a*d, 0] && !(LtQ[a*c, 0] && GtQ[a*b, 0])
Int[((e_) + (f_.)*(x_)^2)/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_) ^2]), x_Symbol] :> Simp[f/b Int[Sqrt[a + b*x^2]/Sqrt[c + d*x^2], x], x] + Simp[(b*e - a*f)/b Int[1/(Sqrt[a + b*x^2]*Sqrt[c + d*x^2]), x], x] /; Fr eeQ[{a, b, c, d, e, f}, x] && !((PosQ[b/a] && PosQ[d/c]) || (NegQ[b/a] && (PosQ[d/c] || (GtQ[a, 0] && ( !GtQ[c, 0] || SimplerSqrtQ[-b/a, -d/c])))))
Int[((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2)^(q_.)*((e_) + (f_.)*(x _)^2), x_Symbol] :> Simp[(-(b*e - a*f))*x*(a + b*x^2)^(p + 1)*((c + d*x^2)^ (q + 1)/(a*2*(b*c - a*d)*(p + 1))), x] + Simp[1/(a*2*(b*c - a*d)*(p + 1)) Int[(a + b*x^2)^(p + 1)*(c + d*x^2)^q*Simp[c*(b*e - a*f) + e*2*(b*c - a*d) *(p + 1) + d*(b*e - a*f)*(2*(p + q + 2) + 1)*x^2, x], x], x] /; FreeQ[{a, b , c, d, e, f, q}, x] && LtQ[p, -1]
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[(1/(Sqrt[a]*Rt[-b/a, 4]) )*EllipticF[ArcSin[Rt[-b/a, 4]*x], -1], x] /; FreeQ[{a, b}, x] && NegQ[b/a] && GtQ[a, 0]
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[Sqrt[1 + b*(x^4/a)]/Sqrt [a + b*x^4] Int[1/Sqrt[1 + b*(x^4/a)], x], x] /; FreeQ[{a, b}, x] && NegQ [b/a] && !GtQ[a, 0]
Int[(u_.)*((a_) + (c_.)*(x_)^(n2_.))^(p_)*((d_) + (e_.)*(x_)^(n_))^(q_.), x _Symbol] :> Simp[(a + c*x^(2*n))^FracPart[p]/((d + e*x^n)^FracPart[p]*(a/d + c*(x^n/e))^FracPart[p]) Int[u*(d + e*x^n)^(p + q)*(a/d + (c/e)*x^n)^p, x], x] /; FreeQ[{a, c, d, e, n, p, q}, x] && EqQ[n2, 2*n] && EqQ[c*d^2 + a* e^2, 0] && !IntegerQ[p] && !(EqQ[q, 1] && EqQ[n, 2])
Time = 2.34 (sec) , antiderivative size = 256, normalized size of antiderivative = 1.14
method | result | size |
default | \(\frac {x \sqrt {-e^{2} x^{4}+d^{2}}}{10 d^{2} e^{3} \left (x^{2}+\frac {d}{e}\right )^{3}}+\frac {x \sqrt {-e^{2} x^{4}+d^{2}}}{5 d^{3} e^{2} \left (x^{2}+\frac {d}{e}\right )^{2}}+\frac {9 \left (-e^{2} x^{2}+d e \right ) x}{20 e \,d^{4} \sqrt {\left (x^{2}+\frac {d}{e}\right ) \left (-e^{2} x^{2}+d e \right )}}+\frac {\sqrt {1-\frac {e \,x^{2}}{d}}\, \sqrt {1+\frac {e \,x^{2}}{d}}\, \operatorname {EllipticF}\left (x \sqrt {\frac {e}{d}}, i\right )}{4 d^{3} \sqrt {\frac {e}{d}}\, \sqrt {-e^{2} x^{4}+d^{2}}}-\frac {9 \sqrt {1-\frac {e \,x^{2}}{d}}\, \sqrt {1+\frac {e \,x^{2}}{d}}\, \left (\operatorname {EllipticF}\left (x \sqrt {\frac {e}{d}}, i\right )-\operatorname {EllipticE}\left (x \sqrt {\frac {e}{d}}, i\right )\right )}{20 d^{3} \sqrt {\frac {e}{d}}\, \sqrt {-e^{2} x^{4}+d^{2}}}\) | \(256\) |
elliptic | \(\frac {x \sqrt {-e^{2} x^{4}+d^{2}}}{10 d^{2} e^{3} \left (x^{2}+\frac {d}{e}\right )^{3}}+\frac {x \sqrt {-e^{2} x^{4}+d^{2}}}{5 d^{3} e^{2} \left (x^{2}+\frac {d}{e}\right )^{2}}+\frac {9 \left (-e^{2} x^{2}+d e \right ) x}{20 e \,d^{4} \sqrt {\left (x^{2}+\frac {d}{e}\right ) \left (-e^{2} x^{2}+d e \right )}}+\frac {\sqrt {1-\frac {e \,x^{2}}{d}}\, \sqrt {1+\frac {e \,x^{2}}{d}}\, \operatorname {EllipticF}\left (x \sqrt {\frac {e}{d}}, i\right )}{4 d^{3} \sqrt {\frac {e}{d}}\, \sqrt {-e^{2} x^{4}+d^{2}}}-\frac {9 \sqrt {1-\frac {e \,x^{2}}{d}}\, \sqrt {1+\frac {e \,x^{2}}{d}}\, \left (\operatorname {EllipticF}\left (x \sqrt {\frac {e}{d}}, i\right )-\operatorname {EllipticE}\left (x \sqrt {\frac {e}{d}}, i\right )\right )}{20 d^{3} \sqrt {\frac {e}{d}}\, \sqrt {-e^{2} x^{4}+d^{2}}}\) | \(256\) |
Input:
int(1/(e*x^2+d)^3/(-e^2*x^4+d^2)^(1/2),x,method=_RETURNVERBOSE)
Output:
1/10/d^2/e^3*x*(-e^2*x^4+d^2)^(1/2)/(x^2+d/e)^3+1/5/d^3/e^2*x*(-e^2*x^4+d^ 2)^(1/2)/(x^2+d/e)^2+9/20*(-e^2*x^2+d*e)/e/d^4*x/((x^2+d/e)*(-e^2*x^2+d*e) )^(1/2)+1/4/d^3/(e/d)^(1/2)*(1-e*x^2/d)^(1/2)*(1+e*x^2/d)^(1/2)/(-e^2*x^4+ d^2)^(1/2)*EllipticF(x*(e/d)^(1/2),I)-9/20/d^3/(e/d)^(1/2)*(1-e*x^2/d)^(1/ 2)*(1+e*x^2/d)^(1/2)/(-e^2*x^4+d^2)^(1/2)*(EllipticF(x*(e/d)^(1/2),I)-Elli pticE(x*(e/d)^(1/2),I))
Time = 0.08 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.00 \[ \int \frac {1}{\left (d+e x^2\right )^3 \sqrt {d^2-e^2 x^4}} \, dx=\frac {9 \, {\left (e^{4} x^{6} + 3 \, d e^{3} x^{4} + 3 \, d^{2} e^{2} x^{2} + d^{3} e\right )} \sqrt {\frac {e}{d}} E(\arcsin \left (x \sqrt {\frac {e}{d}}\right )\,|\,-1) + {\left ({\left (5 \, d e^{3} - 9 \, e^{4}\right )} x^{6} + 3 \, {\left (5 \, d^{2} e^{2} - 9 \, d e^{3}\right )} x^{4} + 5 \, d^{4} - 9 \, d^{3} e + 3 \, {\left (5 \, d^{3} e - 9 \, d^{2} e^{2}\right )} x^{2}\right )} \sqrt {\frac {e}{d}} F(\arcsin \left (x \sqrt {\frac {e}{d}}\right )\,|\,-1) + {\left (9 \, e^{3} x^{5} + 22 \, d e^{2} x^{3} + 15 \, d^{2} e x\right )} \sqrt {-e^{2} x^{4} + d^{2}}}{20 \, {\left (d^{4} e^{4} x^{6} + 3 \, d^{5} e^{3} x^{4} + 3 \, d^{6} e^{2} x^{2} + d^{7} e\right )}} \] Input:
integrate(1/(e*x^2+d)^3/(-e^2*x^4+d^2)^(1/2),x, algorithm="fricas")
Output:
1/20*(9*(e^4*x^6 + 3*d*e^3*x^4 + 3*d^2*e^2*x^2 + d^3*e)*sqrt(e/d)*elliptic _e(arcsin(x*sqrt(e/d)), -1) + ((5*d*e^3 - 9*e^4)*x^6 + 3*(5*d^2*e^2 - 9*d* e^3)*x^4 + 5*d^4 - 9*d^3*e + 3*(5*d^3*e - 9*d^2*e^2)*x^2)*sqrt(e/d)*ellipt ic_f(arcsin(x*sqrt(e/d)), -1) + (9*e^3*x^5 + 22*d*e^2*x^3 + 15*d^2*e*x)*sq rt(-e^2*x^4 + d^2))/(d^4*e^4*x^6 + 3*d^5*e^3*x^4 + 3*d^6*e^2*x^2 + d^7*e)
\[ \int \frac {1}{\left (d+e x^2\right )^3 \sqrt {d^2-e^2 x^4}} \, dx=\int \frac {1}{\sqrt {- \left (- d + e x^{2}\right ) \left (d + e x^{2}\right )} \left (d + e x^{2}\right )^{3}}\, dx \] Input:
integrate(1/(e*x**2+d)**3/(-e**2*x**4+d**2)**(1/2),x)
Output:
Integral(1/(sqrt(-(-d + e*x**2)*(d + e*x**2))*(d + e*x**2)**3), x)
\[ \int \frac {1}{\left (d+e x^2\right )^3 \sqrt {d^2-e^2 x^4}} \, dx=\int { \frac {1}{\sqrt {-e^{2} x^{4} + d^{2}} {\left (e x^{2} + d\right )}^{3}} \,d x } \] Input:
integrate(1/(e*x^2+d)^3/(-e^2*x^4+d^2)^(1/2),x, algorithm="maxima")
Output:
integrate(1/(sqrt(-e^2*x^4 + d^2)*(e*x^2 + d)^3), x)
\[ \int \frac {1}{\left (d+e x^2\right )^3 \sqrt {d^2-e^2 x^4}} \, dx=\int { \frac {1}{\sqrt {-e^{2} x^{4} + d^{2}} {\left (e x^{2} + d\right )}^{3}} \,d x } \] Input:
integrate(1/(e*x^2+d)^3/(-e^2*x^4+d^2)^(1/2),x, algorithm="giac")
Output:
integrate(1/(sqrt(-e^2*x^4 + d^2)*(e*x^2 + d)^3), x)
Timed out. \[ \int \frac {1}{\left (d+e x^2\right )^3 \sqrt {d^2-e^2 x^4}} \, dx=\int \frac {1}{\sqrt {d^2-e^2\,x^4}\,{\left (e\,x^2+d\right )}^3} \,d x \] Input:
int(1/((d^2 - e^2*x^4)^(1/2)*(d + e*x^2)^3),x)
Output:
int(1/((d^2 - e^2*x^4)^(1/2)*(d + e*x^2)^3), x)
\[ \int \frac {1}{\left (d+e x^2\right )^3 \sqrt {d^2-e^2 x^4}} \, dx=\int \frac {\sqrt {-e^{2} x^{4}+d^{2}}}{-e^{5} x^{10}-3 d \,e^{4} x^{8}-2 d^{2} e^{3} x^{6}+2 d^{3} e^{2} x^{4}+3 d^{4} e \,x^{2}+d^{5}}d x \] Input:
int(1/(e*x^2+d)^3/(-e^2*x^4+d^2)^(1/2),x)
Output:
int(sqrt(d**2 - e**2*x**4)/(d**5 + 3*d**4*e*x**2 + 2*d**3*e**2*x**4 - 2*d* *2*e**3*x**6 - 3*d*e**4*x**8 - e**5*x**10),x)